Therefore, the tomato hits the ground with a speed of 80 ft/sec (feet per second). Thus, the final answer is 80 ft/sec.
The acceleration due to gravity on earth is 32 ft/sec2. A tomato is dropped from 100 feet above the ground. To find at what speed does the tomato hit the ground, the final velocity of the tomato is required, which can be calculated by applying the formula as follows:v² = u² + 2asWherev is the final velocityu is the initial velocity . a is the acceleration du to gravity on earths is the distance covered by the tomato .
So, in this case, the tomato is dropped from a height of 100 feet above the ground, therefore, u=0.The acceleration due to gravity on earth is 32 ft/sec2, therefore, a = 32 ft/sec².
The distance covered by the tomato, s = 100 feet. Substituting the given values in the formula:v² = 0 + 2 × 32 × 100v² = 6400v = √6400v = 80 ft/sec . Therefore, the tomato hits the ground with a speed of 80 ft/sec (feet per second). Thus, the final answer is 80 ft/sec.
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a satellite with a mass of 2190 kg is placed at an altitude of 465650 km above the surface of sun. what is the strength of the gravitational force on the satellite?
The gravitational force of the satellite can be determined using universal gravitational law. The force of gravitation on the satellite is 6.73 × 10⁻²⁵ N.
What is gravitational force?Gravitational force is a kind of force by which an object attracts other objects into its centre of mass. Earth gravitationally pull every objects into its centre and that's why every one is standing on the ground.
According to Universal Gravitational law, the force of gravitation g is written as:
g = G m/r²
where, G is the universal gravitational constant and r be the distance from the surface and m be the mass.
The mass of the satellite = 2190 Kg
r = 465650 × 10³ m
G = 6.67 × 10⁻¹¹ m³/ Kg s⁻²
then g = 6.67 × 10⁻¹¹ m³/ Kg s⁻² × 2190 Kg/ (465650 × 10³ m)²
= 6.73 × 10⁻²⁵ N.
Therefore, the gravitational force on the satellite is 6.73 × 10⁻²⁵ N.
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pls help me!! 100 points!!!
"type a definition for each of the following words in YOUR own words."
1) Constants (also called Controls or Control Variables) –
2) Independent variable –
3) Dependent variable –
Answer:
1) Constants are variables that are kept the same throughout an experiment.
2) An independent variable is a variable that is manipulated by the experimenter.
3) A dependent variable is a variable that is measured by the experimenter.
Explanation:
ping pong ball and bowling ball are dropped from the same height at the same time, which ball will land the ground first? (neglect air resistance)
Assuming that air resistance is neglected, both the ping pong ball and the bowling ball will hit the ground at the same time.
This is because, according to the laws of physics, the acceleration of an object due to gravity is independent of its mass. Both the ping pong ball and the bowling ball will experience the same acceleration due to gravity as they fall, which is approximately 9.8 meters per second squared (9.8 m/s^2) near the surface of the Earth.
Since the acceleration due to gravity is the same for both balls, they will both accelerate at the same rate and therefore reach the ground at the same time, neglecting air resistance.
It's worth noting that in the presence of air resistance, the balls would experience a drag force that would slow them down and cause them to fall at different rates. However, if air resistance is neglected as stated in the question, then both balls will hit the ground at the same time.
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two point charges -5 uc and 4 uc charge are 21 cm apart. what is the magnitude of the electric field at a point half-way between the two charges?
The electric field at a point halfway is 18.37 x 10⁵ N/C.
We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
E = k.Q/r²
where E is the electric field, Q is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 = -5μC = -5 x 10¯⁶ C
Q2 = 4μC = 4 x 10¯⁶ C
x = 21 cm = 0.21 m
from midpoint (r = 0.105 m)
The electric field directly outward from Q2 to Q1 so that the total electric field between the charges will be added up.
Etotal = E1 + E2
Etotal = k.Q1/r² + k.Q2/r²
Etotal = k/r² x (Q1 + Q2)
Etotal = 9 x 10⁹/(0.21)² x (5 x 10¯⁶ + 4 x 10¯⁶)
Etotal = 18.37 x 10⁵ N/C
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A kid walks 500 m North and then 300 m south.
a. What is the distance of his walk?
b. What is the displacement of his walk?
Explanation:
for the walking distance it did not matter in what direction the kid walked.
a. the distance of the walk is 500 + 300 = 800 m
b. the kid ended up 500-300=200 m north of the original point.
At what point does a rubber band have the most elastic potential energy? Explain.
Answer:
You input potential (stored) energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this kind of potential energy is specifically called elastic potential energy. ... When the rubber band is released, the potential energy is quickly converted to kinetic (motion) energy.
Explanation:
True or False
1. Scientists have complete knowledge of atoms and this knowledge can never change?
1. What is the voltage across each resistor?
2. What is the current in each branch?
3. What is the total current provided by the batteries?
For top and bottom picture.
For top picture, I also need to know: Use the total current and the total voltage to calculate the total resistance of the circuit.
The current provided in each branch for 12V circuit are 6 A and 4 A.
The total current provided for the 12 V circuit is 10 A.
The current provided in each branch for 9V circuit are 4.5 A, 3 A and 9 A.
The total current provided for the 12 V circuit is 16.5 A.
What is the current in each branch?The current provided in each branch of the parallel circuit is calculated as follows;
For the 12V circuit;
I = V/R
where;
V is voltageR is the resistancebranch 1 = 12/2 = 6 A
branch 2 = 12/3 = 4 A
Total resistance;
1/Rt = 1/2 + 1/3
1/Rt = 5/6
Rt = 6/5 = 1.2 ohm
Total current is calculated as;
I_t = 12 V/1.2 ohm = 10 A
For the 9 V circuit:
branch 1 = 9/2 = 4.5 A
branch 2 = 9/3 = 3 A
branch 3 = 9/1 = 9 A
Total resistance;
1/Rt = 1/2 + 1/3 + 1/1
1/Rt = 11/6
Rt = 6/11 = 0.545 ohms
Total current is calculated as;
I_t = 9 V/0.545 ohm = 16.5 A
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The relative frequency of people who strongly disagree with the statement is __________.
a. 40.3%
b. 68%
c. 22.7%
d. 10.7%
The relative frequency of people who strongly disagree with the statement is 10.7%. This means that out of all the people surveyed or considered, 10.7% of them strongly disagree with the statement.
To calculate the relative frequency, we need to know the total number of people surveyed or considered and the number of people who strongly disagree. Let's say that out of 1000 people surveyed, 107 of them strongly disagree with the statement.
To calculate the relative frequency, we divide the number of people who strongly disagree by the total number of people surveyed and multiply by 100. In this case, (107 / 1000) * 100 = 10.7%.
The answer is d. 10.7%, which represents the relative frequency of people who strongly disagree with the statement.
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What type of energy is described above? A. sound energy B. light energy C. heat energy D. kinetic energy
Kinetic energy is the kind of energy mentioned. The energy an object has as a result of its motion is known as kinetic energy.
What kind of energy are light and sound?Sound is a pressure density wave, whereas light is an electromagnetic wave. Sound must pass through a medium in order to be heard, but light does not. Sound energy is a continuous stream of energy on the scale while light energy is quantized into packets of energy called photons.
Why is energy in the form of sound?Sound is the longitudinal (compression or rarefaction) wave-based transfer of energy through materials. When a force causes an object or substance to vibrate, sound is created. That is to say, the substance serves as a conduit for the energy.
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The type of energy mentioned is kinetic energy. Kinetic energy is the energy that an object has as a result of motion.
Light and sound both include what kind of energy?Light is an electromagnetic wave, whereas sound is a pressure density wave. Light does not require a medium for transmission, but sound must. On the scale, sound energy flows continuously, whereas light energy is quantized into units of energy called photons.
What causes energy to manifest as sound?The longitudinal wave-based transport of energy through materials is known as sound. Sound is produced when a force causes an item or substance to vibrate. In other words, the substance acts as a conduit.
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____________ energy the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have this energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of this energy at work.
What type of energy is described above? A. sound energy B. light energy C. heat energy D. kinetic energy
Protons are______
charged particles.
Answer: Protons are positively charged particles
Explanation:
A centrifuge rotor rotating at 10,300 rpm is shut off and is eventually brought uniformly to rest by a frictional torque of 1.2 m*N. If the mass of the rotor is 4.8 kg and it can be approximated as a solid cylinder of radius .0710 m, through how many revolutions will the rotor turn before coming to rest, and how long will it take?
Upon calculations, the solution was found to be that the centrifuge rotor will make approximately 5,579 revolutions before coming to rest, and it will take about 32.4 seconds for it to do so.
The centrifuge rotor, with a mass of 4.8 kg and approximated as a solid cylinder of radius 0.0710 m, is initially rotating at 10,300 rpm. It comes to rest due to a frictional torque of 1.2 m*N acting on it.
To determine the number of revolutions the rotor will make before coming to rest and the time it will take, we can use the principles of rotational dynamics.
The initial angular velocity of the rotor can be calculated by converting the given 10,300 rpm to rad/s: 10,300 rpm = (10,300 rev/min) * (2π rad/rev) * (1 min/60 s) ≈ 1,080 rad/s.
The frictional torque acting on the rotor can be related to the angular acceleration through the equation τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
In this case, the torque is 1.2 m*N, and the moment of inertia for a solid cylinder is given by I = ½ * m * r^2, where m is the mass and r is the radius.
Rearranging the equation τ = Iα, we can solve for α: α = τ / I. Substituting the given values, we find α = 1.2 m*N / (½ * 4.8 kg * (0.0710 m)^2) ≈ 33.3 rad/s^2.
The final angular velocity of the rotor is zero since it comes to rest.
Using the equation ω = ω₀ + αt, where ω is the final angular velocity, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time, we can solve for t: 0 = 1,080 rad/s + (-33.3 rad/s^2) * t.
Rearranging the equation, we find t ≈ 32.4 s.
The number of revolutions can be calculated by dividing the initial angular displacement by 2π.
The initial angular displacement can be obtained by multiplying the initial angular velocity by the time: θ = ω₀ * t. Substituting the given values, we have θ = 1,080 rad/s * 32.4 s ≈ 35,088 rad.
Finally, the number of revolutions is given by the equation N = θ / (2π), where N is the number of revolutions: N ≈ 35,088 rad / (2π rad/rev) ≈ 5,579 revolutions.
Therefore, the centrifuge rotor will make approximately 5,579 revolutions before coming to rest, and it will take about 32.4 seconds for it to do so.
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A 5n solution is diluted 1:4. the resulting solution is diluted 4:15. what is the concentration in normality of the final solution?
A 5N solution is first diluted at a ratio of 1:4, and then the resulting solution is further diluted at a ratio of 4:15. The question asks for the concentration in normality of the final solution.
Normality (N) is a measure of the concentration of a solution and is defined as the number of gram equivalents of solute per liter of solution. To determine the concentration in normality of the final solution, we need to calculate the gram equivalents of solute in the solution.
In the first dilution, the 5N solution is diluted at a ratio of 1:4. This means that for every 1 part of the original solution, 4 parts of the diluent (usually water) are added. As a result, the concentration of the solution is reduced by a factor of 4.
Next, the resulting solution is diluted at a ratio of 4:15. This means that for every 4 parts of the solution, 15 parts of the diluent are added. This further reduces the concentration of the solution.
The final concentration in normality, we need to determine the gram equivalents of solute in the final solution. This can be done by multiplying the initial concentration (5N) by the dilution factors (1/4 and 4/15) and dividing by the final volume of the solution.
Therefore, by considering the dilution ratios and using the concept of normality, we can calculate the concentration in normality of the final solution.
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The final solution, after two-step dilution, has a concentration of 0.04n.
Explanation:The student is asked to find the concentration in normality of a solution after a two-step dilution. First, a 5n solution is diluted 1:4, meaning one part solution and four parts diluent, resulting in a solution of 1n. Then, this solution is diluted again 4:15, implying four parts of the initial solution and 15 parts diluent. Dividing the 1n by 5 (the sum of 4 and 1), we obtain 0.2n. This new concentration is then diluted by a factor of 5 (sum of 4 and 15 divided by 4), calculating to 0.2n / 5 = 0.04n. Thus, the final concentration of the solution is 0.04n.
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how long ago (in seconds) was that galaxy right next door to our own galaxy if it has always been receding at its present rate? since the universe began when all galaxies were very close together, this number is a rough estimate for the age of the universe.
According to the Statement it always was receding at its current rate, that galaxy was just next to our own galaxy, moving at 8000 km/s.
Which galaxy contains Earth?Astronomy The Universe The Nebula Galaxy. Did you know that, in conjunction to our light, the Sun, the Milky Way Cluster, a large expanse of space, includes millions and billions of other stars? Its Milky Way is distinguished by a phenomenal number of stars, infinitesimal particles, and gas.
Briefing :Since V = H x d, the velocity of a galaxy at a distance of 400 x 10⁶ light-years = 8000 km/s
For H = 20 km/s per million light-years. The time required to travel
4 x 10⁸ light - years at 8000 km/s is given by :
T = (4x10⁸ light - years ) (9.46 x 10¹² km /light-year) ÷ 8 x 10³
= 4.7 x 10¹⁷ = 15 billion year
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Complete question : Consider a galaxy at a distance of 400 million light-years receding from us at a velocity, v. If the Hubble constant is 20 km/s per million light-years, what is its velocity? How long ago was that galaxy right next door to our own Galaxy if it has always been receding at its present rate?
the drawing shows an exaggerated view of a rifle that has been"sighted in" for a 91.4-meter target. If the muzzle speed of thebullet is v0 = 427 m/s, what are the two possible anglesθ1 and θ2 between the rifle barreland the horizontal such that the bullet will hit the target? One ofthese angles is so large that it is never used in target shooting.(HInt: the following trigonometric identity may be useful: 2 sinθ cos θ = sin 2 θ.)
The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.
Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.
It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).
Here, t is the time of flight of the bullet and g is the acceleration due to gravity.
As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.
On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.
Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.
Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.
Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.
Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.
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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.
Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.
It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).
Here, t is the time of flight of the bullet and g is the acceleration due to gravity.
As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.
On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.
Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.
Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.
Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.
Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.
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Answer:
child i dont even know the answer for this question
Explanation:
Mining would be classified as a _____ human activity for the environment. Negative or positive
Answer: negative
Explanation:
rue or False a) For a symmetric laminate, the uniform temperature change will not produce thermal moment resultants
The statement "For a symmetric laminate, the uniform temperature change will not produce thermal moment resultants" is true.
A laminate is symmetric when its layer stacking sequence is such that the layers on one side of the laminate are a mirror image of the layers on the other side. When a symmetric laminate is subjected to a uniform temperature change, the layers on both sides of the laminate experience the same amount of thermal expansion or contraction. As a result, the laminate does not undergo any twisting or warping, and there is no tendency for the laminate to rotate or move due to thermal expansion.
This means that the thermal moment resultants, which are the moments that arise due to the thermal expansion or contraction of a material, are zero for a symmetric laminate subjected to a uniform temperature change. The absence of thermal moment resultants is a desirable property for many engineering applications, as it reduces the risk of distortion or failure due to temperature changes.
In summary, a symmetric laminate subjected to a uniform temperature change does not produce thermal moment resultants, making this statement true.
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What quantities can be calculated from the bohr equation for the energy levels of the hydrogen atom?
e = â2.18 Ã 10â18 j (1n2)
We can find the energy needed to ionize the hydrogen atom.
We can find the wavelength of a spectral line.
We can find the energy change of the electron moving between two levels.
The first atomic model to adequately explain the radiation spectra of atomic hydrogen was Bohr's model of the hydrogen atom. The atomic Hydrogen model was first presented by Niels Bohr in 1913. Rutherford's model of the hydrogen atom leaves several holes, which Bohr's model of the hydrogen atom tries to fill in.
It has a particular place in history since it introduced the quantum theory, which led to the development of quantum mechanics. Bohr proposed that electrons moved in predetermined orbits or shells with defined radii around the nucleus. It was impossible for electrons to reside between any shells other than those having a radius given by the equation below.
\(r (n) =n^{2} * r(1)\)
\(E (n) = \frac{1}{n^{2} } 13.6eV\)
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pls help
Problem 1:
The 2022 Tesla Model S Plaid can accelerate from 0-60 mph in 2.28 seconds. How many g’s does the
driver experience during this acceleration? How far does the car travel to hit 60 mph?
The driver experiences about 0.835 g, g-force during the acceleration. and the car travels about 49.8 meters (163 feet) to hit 60 mph.
What is g-force?
To calculate the g-force experienced by the driver during the acceleration, we need to use the formula:
g-force = acceleration due to gravity / acceleration of the car
The acceleration due to gravity is approximately 9.81 m/s², or 32.2 ft/s².
The acceleration of the car can be calculated by converting the acceleration from 0-60 mph to meters per second squared (m/s²). We can use the following formula to convert:
a = (v_f - v_i) / t
where:
a = acceleration
v_f = final velocity (60 mph in this case, which is 26.8 m/s)
v_i = initial velocity (0 mph in this case, which is 0 m/s)
t = time taken to reach final velocity (2.28 seconds in this case)
Plugging in the values, we get:
a = (26.8 m/s - 0 m/s) / 2.28 s
a ≈ 11.75 m/s²
Now we can calculate the g-force experienced by the driver:
g-force = 9.81 m/s² / 11.75 m/s²
g-force ≈ 0.835 g
Therefore, the driver experiences about 0.835 g during the acceleration.
To calculate the distance traveled by the car to hit 60 mph, we can use the following formula:
d = v_i * t + 0.5 * a * t²
where:
d = distance traveled
v_i = initial velocity (0 mph in this case, which is 0 m/s)
t = time taken to reach final velocity (2.28 seconds in this case)
a = acceleration (11.75 m/s²)
Plugging in the values, we get:
d = 0 m/s * 2.28 s + 0.5 * 11.75 m/s² * (2.28 s)²
d ≈ 49.8 m
Therefore, the car travels about 49.8 meters (163 feet) to hit 60 mph.
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Complete question is: The 2022 Tesla Model S Plaid can accelerate from 0-60 mph in 2.28 seconds. The driver experiences about 0.835 g, g-force during the acceleration. and the car travels about 49.8 meters (163 feet) to hit 60 mph.
Angela has a bucket of mass 2 kg tied to a string. She places a drinking glass of mass 0.5 kg in the bucket. She spins the bucket in a vertical circle of radius 1.5 m. You want to find out how fast she must swing the bucket to keep the glass from falling out.
a. Draw the free-body diagram for the glass when it is at the top of the circle.
b. What is the equation for the net force on the glass at the top of the circle in terms of w, FN, m, v, and r?
c. The glass will fall out of the bucket if the normal force between the glass and bucket equals zero. How fast must she spin the bucket to prevent this from happening?
d. The string will break if the tension on it is more than 100 N. Over what range of speeds can she keep the glass in the bucket and prevent the string from breaking?
a. The free-body diagram for the glass when it is at the top of the circle is attached below.
b. The equation for the net force on the glass at the top of the circle in terms of w, Fn, m, v, and r is mg x g + N - mg x Vtop² /R =0
c. The glass will fall out of the bucket if the normal force between the glass and bucket equals zero. The speed with which she spin the bucket to prevent this from happening is 3.83 m/s.
d. The string will break if the tension on it is more than 100 N. The range of speeds can prevent the string from breaking is 3.83< Vtop<4.99 m/s
What is Net force?When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
Given, Angela has a bucket of mass 2 kg tied to a string. She places a drinking glass of mass 0.5 kg in the bucket. She spins the bucket in a vertical circle of radius 1.5 m. She must swing the bucket to keep the glass from falling out.
a. The free body diagram of the bucket and glass is attached below.
b. Bucket will undergo centrifugal force
Fb = mVtop² /R
From the equilibrium of forces, we have
For bucket,
T +mb xg - N = mb x Vtop² /R..............(1)
For glass,
mg x g + N = mg x Vtop² /R..............(2)
Thus, this is the net force equation on the glass.
c. On adding both the equations. we have
T + (mb + mg) xg = (mb + mg) Vtop² /R
Substituting the values, T = 0 and from the question, we get
0 + (2+0.5) 9.81 = (2+0.5)(Vtop²/0.5)
Vtop = 3.83 m/s
Thus, the speed of spin to prevent glass from falling out is 3.83 m/s
d. The string will break if the tension on it is more than 100 N
100 + (2+0.5) 9.81 = (2+0.5)(Vtop²/0.5)
Vtop = 4.99 m/s
Thus, the range of velocity is 3.83< Vtop<4.99 m/s
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Un móvil viaja inicialmente con una velocidad de 55 m/s, al cabo de cierto tiempo, su velocidad es de 115 m/s, de repente frena bruscamente con una desaceleración de 14, 500 m/s2. ¿qué distancia recorrerá antes de frenar?
Answer:
Distancia, S = 2.84 metros
Explanation:
Dados los siguientes datos;
Velocidad inicial = 55 m/s
Velocidad final = 115 m/s
Deceleración = 14500 m/s²
Para encontrar qué tan lejos viajaría el automóvil, usaríamos la tercera ecuación de movimiento;
V² = U² + 2aS
115² = 55² + 2*14500*S
13225 = 3025 + 29000S
29000S = 13225 - 3025
29000S = 10200
S = 29000/10200
Distancia, S = 2.84 metros
A rock is thrown downwards from the edge of the Grand Canyon. With what velocity will it hit the donkey-riding tourist who is 40 m below?
if 20 boys can sweep the school compound in 8 minutes, how many boys can sweep it in 10minutes
Answer:
So this is just a ratio/proportion problem
so lets say its in boys:minutes
so in the first scenario
20:8
and we want to find
x:10
So proportion really
20/8=x/10
cross multiply
25
25 boys can sweep it in 10 minutes
Calculate Vector component in Y if the hypotenuse is 32 and angle is 45
Answer:
The correct option is;
c. 22.6
Explanation:
The given parameters are;
The hypotenuse of the vector = 32
The angle of the vector = 45°
Therefore, the vector component in the y-axis is given as follows;
\(v_y = v \times sin(\theta)\)
Substituting the values from the question gives;
\(v_y = 32 \times sin(45^{\circ}) \approx 22.6\)
The vector component in the y-axis, \(v_y\), is approximately 22.6.
if the diameter of a wire were decreased it's electrical resistance would
Would the numerical values of the thermal coefficients would have been the same if the temperatures had been measured in Fahrenheit instead of Celsius
The numerical values of the thermal coefficients would change if the temperatures had been measured in Fahrenheit instead of Celsius.
Why would the numerical values of thermal coefficients change if the temperature is measured in Fahrenheit instead of Celsius?The amount it expands is, of course, a property of the material and cannot be altered. When we use alternative units of measurement, though, we communicate this differently. It will therefore be 9/5 of its value in "per degree C" if it is stated as "per degree F".For example:Saying the speed of light is 299792458 m/s, or 186282.397 miles per second, is equivalent. The representation alters but not the speed of light.What is the Coefficient of thermal expansion?The rate at which a material expands as temperature rises is known as the coefficient of thermal expansion (CTE). The material is assumed to still be in its solid or fluid form as this coefficient is calculated at constant pressure and without a phase transition.A material will expand more in response to heat if its coefficient of thermal expansion is higher.T o learn more about thermal coefficients visit:
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Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
The upward force acting on the wing of an airplane ir flight is called?
Answer:
Lift is the upward force on the wing acting perpendicular to the relative wind and perpendicular to the aircraft's lateral axis. Lift is required to counteract the aircraft's weight.
Explanation:
Answer: The upward force acting on the wing of an airplane in flight is called Lift
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is