Let the intensity of light from the first polarizing filter is I_1.
The intensity of the light from the second polarizing filter is,
\(I_2=I_1\cos ^2(\theta)\)where,
\(\theta\text{ is the angle betw}een\text{ the polarizing filter's axes}\)Thus, the intensity of light through the passes through two polarizing filter depends on the angle between their polarizing axes.
Hence, the given statement is true.
A string is attached to the rear-view mirror of a car. A ball is hanging at the other end of the string. The car is driving around in a circle, at a constant speed. Which of the following lists gives all of the forces directly acting on the ball?
a. tension
b. tension and gravity
c. tension, gravity, and the centripetal force
d. tension, gravity, the centripetal force, and friction
Answer:
c. tension, gravity, and the centripetal force
Explanation:
The ball experiences a variety of force as explained below.
Gravity force acts on the body due to its mass and the acceleration due to gravity. The gravity force on every object on earth due to its mass keeps all object on the surface of the earth.
Although the car moves around in circle, centripetal towards the center of the radius of turn exists on the ball. This centripetal force is due to the constantly changing direction of the circular motion, resulting in a force away from the center. The centripetal force keeps the ball from swinging off away from the center of turn.
Tension force on the string holds the ball against falling towards the earth under its own weight, and also from swinging away from the center of turn of the car. Tension force holds the ball relatively fixed in its vertical position in the car.
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
a kayaker moves 26 meters southward, then 18 meters northward, and finally 12 meters southward.
What is the magnitude and direction of the displacement?
Answer:
Explanation:
26 - 18 + 12 = 20 m south
What is true about the foci of a planet in elliptical orbit?
A:The sun is located at one focus.
B: Earth is located at one focus.
C: Earth is located in the center of the orbit.
D: The sun is located in the center of the orbit
Statement A. The sun is located at one focus is true about the foci of a planet in an elliptical orbit (option A).
What is an elliptical orbit?An elliptical orbit can be defined as any movement of a celestial body in which the attained object (for example a planet around its star) moves in an eccentric manner or oval-shaped way, which is a feature of the planets in the solar systems including the Earth planet.
The movement of a planet in an elliptical orbit is called an ellipse, while two points that are selected chosen at the start site are known as foci in such orbits.
Therefore, with this data, we can see that an elliptical orbit is an excentric movement of a celestial body such as the earth's planet around the sun, and foci are called to fixed points located inside this orbit.
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What factors affect the speed of a wave? Check all that apply.
the amplitude of the wave
the energy of the wave
the temperature of the medium
the type of wave
the type of medium
Answer: Correct answer is C. The temperature of the medium. D. The type of wave. F. The type of medium
Explanation:
A and B is wrong
Answer: The correct choices are:
C. the temperature of the medium
D. the type of wave
E. the type of medium
The other person who answered the question is right :)
Explanation:
Got it right on the quiz, Edge 2022
A car traveled to the right 4.2 km and made a 90 degree turn and traveled straight for
another 2.6 km. What is the total displacement of the car? Be sure to show your work.
Answer:
4.9 km
Explanation:
\(\sqrt{4.2^2+2.6^2}=4.9 km\)
A wholesale club sells eggs by the dozen .Does the table show a proportional relationship between the number of dozen of eggs cost?
Answer:
12 dozen
Explanation:
Answer:
The table is proportional.
Explanation:
You would do 21/6 to get 3.5. Then 28/8 to get 3.5. After 35/10 to get 3.5. Finally 49/14 to get 3.5. If each answer (3.5) is the same than it is proportional.
hope i helped
Describe briefy the production of soud in of the following instruments. √ Trumpet
To produce its distinct sound a trumpet relies on the dynamic interplay between airflow, vibration, and resonance.
What are the process by which produces it sound?To create sound on a trumpet, one must blow air into its mouthpiece which generates a high-speed airstream causing changes in both volume and pitch. The airstream then meets with vibrating lips on the mouthpiece that function either as reeds or double reeds per player preference.
When these parted lips vibrate against each other due to passing airflow, they produce sound waves inside the long tube of Trumpet with bell widening towards downstream direction at play's end. This reverberates with vibrating lips' oscillations resulting in shaping and amplifying unique tone and timbre of Trumpet notes. Players can get different pitches by utilizing three valves located on their Trumpet.
As an accomplished trumpeter, one can utilize various valve combinations and modify their embouchure to produce a diverse range of notes and melodies.
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condition necessary for thermodynamic equilibrium
Answer:
For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.
Explanation:
hope it helps :)
Answer: For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.
Explanation:
a man of height 1.8 meters walks away from a 5-meter lamppost at a speed pf 1.2 m/sec. find the rate at which his shadow is increasing in length diagram
The rate at which the shadow of the man changing is 0.675
The height of the man = 1.8 m
The height of the tower = 5 m
The speed of the man = 1.2 m/s
The rate at which the length of the man's shadow increases is dy/dt
We know that the speed is nothing but a rate of change of distance, Thus
dx/dt = 1.2 m/s
The increase in shadow due to the lamp = the shadow of the man
5 / (x + y) = 1.8 / y
5y = 1.8x + 1.8y
3.2y = 1.8x
Let us differentiate the equation with respect to time,
3.2 dy/dt = 1.8 dx/dt
Let us substitute the known values in the above equation, we get
3.2 dy/dt = 1.8 x 1.2
dy/dt = 2.16 / 3.2
dy/dt = 0.675
Therefore, the rate of change of the shadow is 0.675
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How does the release of energy during fusion provide evidence of mass-energy equivalence?
The release of energy during fusion because the mass of the resulting single nucleus is smaller than the combined mass of the two initial nuclei, the process produces energy. Remaining mass is converted to energy.
what is Nuclear fusion?
A reaction known as nuclear fusion occurs when two or more atomic nuclei fuse to create new atomic and subatomic particles.
Mass energy equivalence describes the relation between mass and energy when system is in rest frame. According to Einstein's equation, mass and energy can be transformed into one another (E=mc2).
when energy is lost the mass of the system will also decrease in proportion. The energy and mass can be discharged into the environment as heat energy or radiant energy like light.
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This means that the release of energy from a nuclear reaction creates enough of a mass difference to be measured.
Mass-Energy EquivalenceAccording to mass-energy equivalence, mass is merely concentrated energy. The formula E=mc2 was created by Albert Einstein for his special relativity theory. Mass contains a huge quantity of energy. The energy in a 20g marble is equivalent to a 500 kiloton hydrogen bomb, but it is incredibly difficult to unleash. When matter and antimatter come together, a process known as matter-antimatter annihilation, it can be liberated. Because of the changes in mass, it is evident why nuclear processes produce so much more energy than chemical ones.To learn more about Mass-Energy Equivalence refer:
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Explain the light detection technique of photovoltaic detection
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
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Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader
Answer:
7.55 g
Explanation:
Heat of fusion = 333kj/kg
Heat capacity, c = 4190 j/kg /k
Heat capacity in j/g /k = 0.4190
Let the Number of grams of ice that will melt = n
Number of grams * heat of fusion = heat capacity * temperature change
n * 0.333 = 0.419 * (6-0)
0.333n = 2.514
n = 2.514 / 0.333
n = 7.5495
n = 7.55 gram
Hence, the number of gram of ice that will melt is 7.55 grams
provides some pertinent background for this problem. A pendulum is constructed from a thin, rigid, and uniform rod with a small sphere attached to the end opposite the pivot. This arrangement is a good approximation to a simple pendulum (period = 0.61 s), because the mass of the sphere (lead) is much greater than the mass of the rod (aluminum). When the sphere is removed, the pendulum no longer is a simple pendulum, but is then a physical pendulum. What is the period of the physical pendulum?
Answer:
the period of the physical pendulum is 0.498 s
Explanation:
Given the data in the question;
\(T_{simple\) = 0.61 s
we know that, the relationship between T and angular frequency is;
T = 2π/ω ---------- let this be equation 1
Also, the angular frequency of physical pendulum is;
ω = √(mgL / \(I\) ) ------ let this equation 2
where m is mass of pendulum, L is distance between axis of rotation and the center of gravity of rod and \(I\) is moment of inertia of rod.
Now, moment of inertia of thin uniform rod D is;
\(I\) = \(\frac{1}{3}\)mD²
since we were not given the length of the rod but rather the period of the simple pendulum, lets combine this three equations.
we substitute equation 2 into equation 1
we have;
T = 2π/ω OR T = 2π/√(mgL/\(I\)) OR T = 2π√(\(I\)/mgL)
so we can use \(I\) = \(\frac{1}{3}\)mD² for moment of inertia of the rod
Since center of gravity of the uniform rod lies at the center of rod
so that L = \(\frac{1}{2}\)D.
now, substituting these equations, the period becomes;
T = 2π/√(\(I\)/mgL) OR T = \(2\pi \sqrt{\frac{\frac{1}{3}mD^2 }{mg(\frac{1}{2})D } }\) OR T = 2π√(2D/3g ) ----- equation 3
length of rod D is still unknown, so from equation 1 and 2 ( period of pendulum ),
we have;
ω\(_{simple\) = 2π/\(T_{simple\) OR ω\(_{simple\) = √(g/D) OR ω\(_{simple\) = 2π√( D/g )
so we simple solve for D/g and insert into equation 3
so we have;
T = √(2/3) × \(T_{simple\)
we substitute in value of \(T_{simple\)
T = √(2/3) × 0.61 s
T = 0.498 s
Therefore, the period of the physical pendulum is 0.498 s
What is the average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s
Answer:
The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \(\frac{m}{s}\).
Explanation:
Velocity is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.
\(velocity=\frac{displacement}{time}\)
Velocity considers the direction in which an object moves, so it is considered a vector magnitude.
In this case, the displacement is 192 m and the time period is 8 s. Replacing:
\(velocity=\frac{192 m}{8 s}\)
Solving:
velocity= 24 \(\frac{m}{s}\)
The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \(\frac{m}{s}\).
Two passenger cars, car A and car B, of the same weight are put to a 30 mph head-on crash test. In the test, cars are pulled forward by a cable at 30 mph speed into a flat concrete wall. After the crash test, the length of the cars became shorter because the frontal part of the cars got crumbled at the crash. If car A's length got shortened much more than car B's,
(A) the impact force on car A was much less than on car B during the collision.
(B) the impulse on the car A was much more than on car B during the collision.
(C) the impulse on the car A was much less than on car B during the collision.
(D) the impact force on car A was much more than on car B during the collision.
Answer:
the statements the correct one is A
Explanation:
Let's analyze this exercise, vehicles have the same mass and speed, so we can use the momentum impulse ratio
I = ∫ F dt = Δp
the Δp is the same for both cars since they have the same mass and the same speeds, so the momentum is the same in both vehicles
When they indicate that vehicle A was reduced more than vehicle B, this implies that the force acted for a longer time, to have the largest reduction in size, therefore the impact force was less in car A than in car B
Resisting the statements the correct one is A
1. Two small, identical conducting spheres A and B are a distance R apart; each carries the same charge Q. What is the force sphere B is exerting on sphere A? (2 marks) b. An identical sphere with zero charge, sphere C, makes contact with sphere A and is then moved very far away. What is the net force now acting on sphere A? (3 marks) c. Sphere C next makes contact with sphere A and is then moved far away. What is the force on sphere A in this third case? (2 marks)
Answer:
the same question I want to know
a. Spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:
\(\rm \[ F = \frac{k Q^2}{R^2} \]\), b. The net force on sphere A now is the force due to sphere B, which is: \(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\), c. The magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.
a) The magnitude of the force (F) sphere B exerts on sphere A can be calculated using Coulomb's law:
\(\rm \[ F = \frac{k Q_1 Q_2}{R^2} \]\)
where:
k is Coulomb's constant \(\rm \( k = \frac{1}{4\pi\epsilon_0} \)\) where \(\rm \( \epsilon_0 \)\) is the vacuum permittivity constant),
\(\rm \( Q_1 \)\) and \(\rm \( Q_2 \)\) are the charges on spheres A and B respectively, and
\(\rm \( R \)\) is the distance between the two spheres.
Since both spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:
\(\rm \[ F = \frac{k Q^2}{R^2} \]\)
b) When an identical sphere C makes contact with sphere B, they share the charge equally. Sphere B now carries \(\rm \( \frac{Q}{2} \)\) charge, and sphere C carries \(\rm \( \frac{Q}{2} \)\) charge.
When sphere C is moved far away, it exerts no force on sphere A. So, the net force on sphere A now is the force due to sphere B, which is:
\(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\)
c) When sphere C makes contact with sphere A, they both share the charge equally. Each sphere now carries \(\rm \( \frac{Q}{2} \)\) charge.
When sphere C is moved far away, the net force on sphere A now is the force due to the charge on sphere A itself, which is:
\(\rm \[ F = \frac{k \frac{Q}{2} \cdot \frac{Q}{2}}{R^2} \\\\\rm = \frac{3}{8} \frac{k Q^2}{R^2} \]\)
So, the magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.
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A spherical ball of lead (density 11.3 g/cm 3) is placed in a tub of mercury (density 13.6 g/cm 3). Which answer best describes the result
The lead ball will float with about 17% of its volume above the surface of the mercury.
We know that density is defined as mass per unit volume of a substance. The density of a substance is an intrinsic property which can be used to identify a substance.
Given that Lead is less dense that mercury, we know that lead will float on mercury. Since the density of mercury is 13.6 g/cm3 and that of lead is 11.3 g/cm3, lead ball will float with about 17% of its volume above the surface of the mercury.
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Missing parts;
A spherical ball of lead (density 11.3 g/cm3) is placed in a tub of mercury (density 13.6 g/cm3). Which answer best describes the result?
A.The lead ball will float with about 83% of its volume above the surface of the mercury.
B.The lead ball will float with about 17% of its volume above the surface of the mercury.
C.The lead ball will float with its top exactly even with the surface of the mercury.
D.The lead will sink to the bottom of the mercury.
E.none of the above
What happens to make electrical current flow in a generator?
Each of the following figures shows a person (not to scale) located on Earth at either 40°N or 40°S latitude. Rank the figures based on how much time the person spends in daylight during each 24-hour period, from most to least. To rank items as equivalent, overlap them.
The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.
The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.
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If the net work done on a particle is zero, which of the following statements must be true?
A. The speed is unchanged.
B. The velocity is zero.
C. The velocity is unchanged.
D. More information is needed.
E. The velocity is decreased.
Answer:
A. The speed is unchanged.
Explanation:
In the case when the work is to be done on a particle i.e. zero so the change made in KE of the particle would be zero. This represent the work energy theroem. But when the KE remains same or does not change so it should be the same and the particle speed would also the same
Therefore as per the given statement, the first option is correct
And rest of the options are wrong
Assume you are going to race the three objects (hollow sphere, disk and ring used in Experiment 8.2) by releasing them from rest at the top of an inclined plane.Which object do you expect to reach the bottom of the inclined plan first? Why?
Answer:
a. The disk
b. Because it has the smallest rotational inertia
Explanation:
a. Which object do you expect to reach the bottom of the inclined plan first?
I would expect the disk to reach the bottom first.
b. Why?
This is because the disk has the smallest rotational inertia.
The rotational inertial of the hollow sphere, disk and ring are 2/3MR², 1/2MR² and MR² respectively.
Since the three objects are rolling from the same height, they have the same mechanical energy.
But, since the disk has the smallest rotational inertia, it would have the smallest rotational kinetic energy and largest translational kinetic energy. The disk's smaller rotational kinetic energy will cause to rotate less but translate more than the other objects and thus reach the bottom first.
The object which is expected to reach the bottom of the inclined plan first is the disk, as it has the lowest rotational inertia.
What is a moment of inertia?Moment of inertia is the force which acts in the opposite direction of the force of angular acceleration acting on the body.
There are three objects, hollow sphere, disk and ring.
The moment of inertia of the hollow sphere object is given as,\(I=\dfrac{2}{3}mr^2\)
The moment of inertia of the ring is,\(I=mr^2\)
The moment of inertia of the disk is,\(I=\dfrac{1}{2}mr^2\)Here, (m) is the mass and (r) is the radius of the object.
These three objects are going to race by releasing from rest at the top of an inclined plane to the bottom of the plane.
As moment of inertia is the force which acts in the opposite direction of the force of angular acceleration acting on the body.
Thus the less the value of inertia will result in less the time required to reach at the bottom of the inclined plane.
Hence, the object which is expected to reach the bottom of the inclined plan first is the disk, as it has the lowest rotational inertia.
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an ideal gas at 20centigree In a press 1.5×10pa and compress,a.isothamally,b.adaibatically until it volume in 1/3 in each case reversible.calculate in each case the final pressure and temperature of d gas (the ratio all specific capacity=Cp/Cv=1.4
a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.
a. Isothermal compression:
For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.
Since the process is isothermal, we can write:
\(P_1V_1 = P_2V_2\)
where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.
We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:
\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)
To find the final temperature, we can use the ideal gas law again:
PV = nRT
Rearranging, we get:
T = PV/(nR)
Substituting the values we know, we get:
T = (\(1.5*10^5\)Pa)(V1)/(nR)
Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:
T2 = T1 = 293 K
b. Adiabatic compression:
For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:
PV^γ = constant
where γ = Cp/Cv is the ratio of specific heats.
Since the process is adiabatic and reversible, we can write:
\(P_1V_1\)^γ = \(P_2V_2\)^γ
We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:
\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)
To find the final temperature, we can use the adiabatic equation again:
\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K
Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.
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This type of material magnetizes when a magnetic field is applied, but quickly demagnetizes after removal of the magnetic field.
a soft ferromagnetic material
a hard ferromagnetic material
an antiferromagnetic material
a hard ferrimagnetic material
a paramagnetic material
The material that quickly gets magnetized when applied to the magnetic field is called soft ferromagnetic material.
Soft ferromagnet, these materials are characterized by high magnetic permeability, low coercive force, easy magnetization/demagnetization, and small hysteresis. Some examples are iron, nickel, aluminum, tungsten, and cobalt. Soft ferromagnet. High relative permeability, low coercive force, easy magnetization/demagnetization, and extremely small hysteresis. Soft ferromagnetic materials are iron and various alloys including materials such as nickel, cobalt, tungsten, and aluminum. Ferromagnetism is a rare property found only in a very small number of materials. The most common are the transition metals iron, nickel, and cobalt, and their alloys, as well as alloys of rare earth metals.
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A ball is suspended from two cords as illustrated belowA) determine the magnitude of the tension in the angled cordB) what is the magnitude of the tension in the vertical cord attached to the ballC) calculate the mass of ball
a)
Since the ball is in equilibrium, the sum of horizontal forces are equal zero.
We can decompose the tension in the angled cord in horizontal and vertical components, and then calculate the sum of horizontal forces in the diagram:
\(\begin{gathered} T_{2x}=T_2\cdot\cos (57\degree) \\ T_{2x}=T_2\cdot0.545 \\ \\ T=T_{2x} \\ 250=T_2\cdot0.545 \\ T_2=\frac{250}{0.545} \\ T_2=458.7\text{ N} \end{gathered}\)So the tension in the angled cord is 458.7 N
b)
To find the tension in the vertical cord, we can find the vertical component of the tension in the angled cord, since these two forces are equal because the ball is at equilibrium:
\(\begin{gathered} T_{2y}=T_2\cdot\sin (57\degree) \\ T_{2y}=458.7\cdot0.839 \\ T_{2y}=384.85\text{ N} \\ \\ W=T_{2y} \\ W=384.85\text{ N} \end{gathered}\)So the tension in the vertical cord is 384.85 N
c)
To calculate the mass of the ball, let's use the weight formula:
\(\begin{gathered} W=m\cdot g \\ 384.85=m\cdot9.8 \\ m=\frac{384.85}{9.8} \\ m=39.27\text{ kg} \end{gathered}\)So the mass of the ball is 39.27 kg
Answer #49 please and thank you
when Force (N) is 10.0 Length (m) is 0.60
when Force (N) is 8.0 Length (m) is 0.40
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 2.0 Length (m) is 0.10
chatgpt
49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:
Period (T) = 2π√(Length (L) / g)
Substituting the given values:
2.3 = 2π√(L / 1.6)
To solve for L, we can rearrange the formula:
L = (2.3 / (2π))^2 * 1.6
L ≈ 0.781 meters (or 78.1 centimeters)
So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.
50. Ranking Task:
To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.
Ranking from least to greatest period:
1. A: 10 cm long, mass = 0.25 kg
2. C: 20 cm long, mass = 0.25 kg
3. B: 10 cm long, mass = 0.35 kg
There is a tie between pendulums A and C, as they have the same length but different masses.
a camera employs _lens to form_images
Answer:
a camera employs camera lens to firm some images.
Explanation:
hope this helps.
A cable raises a mass of 120.0 kg with a constant speed. What
force of tension is in the cable
NEW
1
The mass is rising with a constant speed.
=> So it has no vertical acceleration.
=> So there is no net vertical force acting on it.
=> So the sum of the vertical forces on it is zero.
There are two vertical forces acting on the mass.
=> the force of gravity, pulling it down
=> the tension in the cable, pulling it up.
The force of gravity acting on the mass (its weight) is (mass) x (gravity).
=> That's (120 kg) x (9.8 m/s²) downward.
=> That's 1,176 newtons downward.
If the vertical forces add up to zero, the other force ... the tension in the cable ... must be the same magnitude in the opposite direction.
=> The force of tension in the cable is 1,176 newtons upward.
An 11 kg toddler is running at a speed of 8 m/s. How much energy does he have?
Please help
Answer:g
Explanation:jqjqksk
The frequency of the middle B note on a piano is 493.88 Hz. What is the wavelength of this note in centimeters? The speed of sound in air is 343.06 m/s. quizle
Explanation:
using
v = f × lambda
lambda = v/f
v = 343.06m/s to cm/s
343.06 × 100
34306.00cm/s
f = 493.88 Hz
lambda = (34306/493.88) cm/s÷Hz
lambda = 69.46cm
Here we know a frequency, and from this we want to find the wavelength of a soundwave with that frequency.
We will see that the solution is: Wavelength = 69.46cm
The equation we need to use is:
v = λ*fWhere:v = velocityλ = wavelengthf = frequency.In this particular case we know that the frequency is:
f = 493.88 Hz
And the velocity of the wave is:
v = 343.06 m/s
We can replace these in the general equation:
343.06 m/s = λ*(493.88 Hz)
(343.06 m/s)/(493.88 Hz) = λ
0.6946 m = λ
And we want to write this in centimeters, remember that:
1m = 100cm
Then:
λ = 0.6946 m = 0.6946*(100cm) = 69.46cm
If you want to learn more, you can read:
https://brainly.com/question/12924624