The correct option is D, The amount of linear expansion of a long rod does depend on the coefficient of linear expansion.
Linear expansion refers to the physical phenomenon where a material changes its dimensions in response to changes in temperature. When a material is heated, its atoms and molecules start to vibrate faster, which increases the space between them, causing the material to expand in length, width, or height, depending on its orientation.
The extent of linear expansion depends on the coefficient of linear expansion (α) of the material, which is a measure of how much the material will expand per unit length per unit temperature change. The coefficient of linear expansion varies from material to material, and can be determined experimentally.
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Complete Question:
The amount of linear expansion of a long rod does not depend on
A). The original length of the rod
B). The specific heat of the rod
C). The change in the absolute temperature of the rod
D). The coefficient of linear expansion
E). The material out of which the rod is made
a 1500-nfnf capacitor with circular parallel plates 2.0 cmcm in diameter is accumulating charge at the rate of 39.0 mc/smc/s at some instant in time. part a what will be the induced magnetic field strength 9.5 cmcm radially outward from the center of the plates?
The induced magnetic field strength 9.5cm radially outward from the center of the plates is 821.052 Tesla.
We know very well that when a charge is moving with some speed in particular direction then, it will induce a magnetic field around its environment. Only moving charge is able to produce magnetic field, stationary charge only produce electric field.
We know that magnetic field is given by=(μ/2πr)×(q/t) where
μ is called as magnetic field constant,
q is the induced charge in the capacitor,
and r is the distance between the two plates
So, we have r=9.5cm=0.095m,(q/t) =39C/sec and μ=4π×10⁻⁷Tesla-m/A.
So, on putting the above values, we get
=>B=(4π×10⁻⁷ × 39)/2π×0.095
=>B=2×39/ 0.095
=>B=78/0.095
=>B=821.052Tesla.
Hence, induced magnetic field is 821.052Tesla.
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Which of the following is an example of uniform circular motion?
A. A meteoroid falling to Earth
B. A comet orbiting the Sun in an elliptical orbit
C. A rocket traveling to the Moon
D. A satellite making a circular orbit around Earth
please help
Newton’s first law of motion is often called the law of?
Answer:
Newton's first law is often called the law of inertia.
searched it up to verify
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according to the most recent data from satellites making precise measurements of the properties of the cosmic background radiation (cbr) the dark energy makes?
According to the most recent data from satellites making precise measurements of the properties of the cosmic background radiation (CBR), it has been determined that dark energy makes up approximately 68% of the total energy density of the universe.
This means that dark energy is the dominant force driving the acceleration of the expansion of the universe.
The CBR is the afterglow of the Big Bang, and by analyzing its properties, scientists can learn more about the structure and evolution of the universe. The Planck satellite, launched in 2009, has been instrumental in providing high-precision measurements of the CBR and contributing to our understanding of dark energy.
Despite being the dominant force in the universe, dark energy remains a mystery. Its nature and properties are still largely unknown, but it is thought to be a property of space itself rather than a type of matter or energy. Ongoing research and observations will continue to shed light on this elusive phenomenon and deepen our understanding of the universe as a whole.
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Density differences in different materials are able to change the _____________ of a wave.
Amplitude
Crest
Speed
Trough
Answer:
speed
Explanation:
why is a layer of pollution in the air more visible in winter than summer
Answer:
During winters the planetary boundary layer is thinner as the cooler air near the earth's surface is dense. The cooler air is trapped under the warm air above that forms a kind of atmospheric 'lid'. This phenomenon is called winter inversion
Explanation:
What is an ideal gas
Answer:
Is a natural gas source manufactured
What are the chances that radio transmissions from Earth or messages sent on distant space probes will ever be received by living beings
Answer:
Very low
Explanation:
It is fair to say to a reasonable extent that there are very low chances that radio transmissions from Earth or messages sent on distant space probes will ever be received by living beings .
Bear in mind that for years some scientists have believed without any substantial evidence that there are other living beings in distant space.
Refer to the diagram and use the drop-down menus to answer each question
How much energy is reflected by the Earth system?
How much energy is absorbed by the Earth system?
Answer:
first 31 second 69
Explanation:
Answer:
Refer to the diagram and use the drop-down menus to answer each question. How much energy is reflected by the Earth system? How much energy is absorbed ...
Explanation:
they delted our page
Which electromagnetic radiation wavelength is efficiently observed using ground based telescopes?
The majority of electromagnetic energy from space cannot reach the Earth's surface. The only light that reaches sea level is radio waves, visible light, and some ultraviolet light.
Some infrared wavelengths can be observed by astronomers by mounting telescopes on mountain peaks. The majority of space-derived electromagnetic radiation cannot reach the surface of the Earth due to the atmosphere. This diagram demonstrates how deep into the atmosphere various EM spectrum wavelengths can go before being absorbed. Radio and visible light only partially make it to the surface.A typical natural eye can detect frequencies between 380 and 750 nanometers. This contrasts with a band nearby 400-790 terahertz in terms of repetition. These restrictions are not specifically stated and may vary from person to person. These limits of human insight can extend to wavelengths of 310 nm (bright) and 1100 nm under perfect conditions (close to infrared).To know more about electromagnetic energy
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During a protostar's T Tauri phase, it
a. begins a period of reduced activity.
b. expands dramatically.
c. may develop very strong winds.
d. changes its spin direction.
e. lies on the main sequence.
c
During a protostar's T Tauri phase it may develop strong winds.
Adolescence typically consists of four stages for a rising star. First, it starts as a protostar still shrouded in its natal molecular cloud. A very young star still gaining mass from its parent molecular cloud is known as a protostar.
The proto-stellar phase is the earliest stage of stellar evolution. As it accretes new material and a protoplanetary disc forms. The third stage, when the surrounding envelope has cleared, is called the T-Tauri phase. This is due to the gradual removal of the surrounding shell of gas and dust by stellar winds and radiation. T-Tauri stars are relatively young, less than ten million years old (the class is named after the first star of this type to be identified).
The correct option is c.
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on a try by a–1, the ball is bouncing directly above the ring, when b–1 touches the net. the official rules this basket interference. is the official correct?
Yes, the official is correct. Basket interference occurs when a player touches the ball or the net while it is in the cylinder above the basket.
What is interference?
Interference in physics is a phenomenon where two waves combine besides adding their displacements at each and every point in space and time to produce a new wave that has a higher, lower, or identical amplitude. The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference. All types of waves, including light, radio, acoustic, groundwater waves, gravity waves, and matter waves, can exhibit interference effects.
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from cathode ray experiments, j. j. thomson estimated that the mass of an electron was "about a thousandth" of the mass of a proton. how accurate is that estimate? calculate the ratio of the mass of an electron to the mass of a proton.
A rock is thrown horizontally from a 65 meter high cliff with an initial velocity of 8 m/s. What is the vertical component of the velocity of the rock
when it hits the ground?
Answer:
Projectile motion is a combination of horizontal and vertical motion. - The horizontal ... What are the horizontal and vertical components of the initial velocity? Round your ... A rock is thrown horizontally at a speed of 5.0 m/s from the top of a cliff 64.7 m high. The rock hits the ground 18.0 m from the base of the cliff.
Explanation:
Quickly...
A/An _____ is described as a type of circuit in which there are several current paths.
Options:
parallel circuit
series circuit
short circuit
voltage divider
A parallel circuit is described as a type of circuit in which there are several current paths.
A parallel circuit is a type of electrical circuit where two or more components are connected in parallel, and each component has its path for electric current flow. The path is separate from all other parts, and each has the same voltage level. The current divides among each path according to the resistance value of the components in the circuit. Parallel circuits are used in various applications, including lighting in households, street lights, and other electronic devices. In a parallel circuit, the voltage across each component is the same, and the total current in the circuit is equal to the sum of the current flowing in each branch.
A parallel circuit is used in the household and other applications to prevent other electrical devices from overloading and cutting off electrical supply, for example, when several devices are plugged into a power source. In a parallel circuit, the voltage divider circuit can be used to divide the voltage among resistors. This is because the voltage across each component in a parallel circuit is the same, and we can use the equation V = IR to calculate the voltage divider.
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The figure above shows a nephron. Filtration takes place in the structure labeled _____.
A) a
B) b
C) c
D) d
Filtration takes place in the structure labeled B) b, the Bowman's capsule, because it is the location where the blood is filtered through the glomerulus, allowing the nephron to process the filtrate into urine.
1. The nephron is the functional unit of the kidney and is responsible for filtering blood and forming urine.
2. The labeled structure 'b' in the figure is the Bowman's capsule (also known as the glomerular capsule).
3. Filtration takes place in the Bowman's capsule because it surrounds the glomerulus, which is a network of capillaries.
4. As blood flows through the glomerulus, high pressure forces water and small molecules (like glucose, amino acids, and waste products) to move from the blood vessels into the Bowman's capsule. This process is called filtration.
5. Larger molecules (like proteins) and blood cells are not filtered, remaining in the blood vessels within the glomerulus.
6. The filtrate (fluid with small molecules) collected in the Bowman's capsule then continues through the rest of the nephron, where reabsorption and secretion occur to form urine.
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(c) Identify the forces acting on your hand. (Select all that apply.) book on hand hand on book floor on hand earth on hand'
Both the force of "Hand on the book" and the force of "Earth on the book" are directed upward. The ground and the book are being drawn in toward the hand. As a result, the forces pulling on the hands are "Book on hand" and "Earth on hand."
Gravity, usually referred to as gravitation, is the unchanging force of attraction that binds everything together in physics. Being the weakest known force in nature, it has minimal effect on defining the inherent properties of everyday objects.
The force "Hand on the book" is directed upward, and the force "Earth on the book" is directed downward. The hand is being pulled toward the book and the earth.
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What is the instantaneous velocity of the sloth at time t = 8s?
The calculated value is AO=3.2sec.
The limit of average velocity as elapsed time approaches zero, or the derivative of x with respect to t: v (t) = d d t x (t), is the instantaneous velocity of an object. v (t) equals d d t x (t). Instantaneous velocity is a vector having a dimension of length per time, similar to average velocity.
In contrast to instantaneous velocity, which is determined by the slope of the tangent line, average velocity is defined as the change in position (or displacement) during the course of transit.
So, we obtain
cosθ= 5/4
= 4AO
So, we obtain AO=3.2sec.
The complete question is- Position-time graph is shown, which is a semicircle from t=2 to t=8 sec. Find time t at which the instantaneous velocity, is equal to average velocity over first t seconds.
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The position of a particle in millimeters is given by s=102−23t+t ^2 where t is in seconds. Plot the s-t and v-t relationships for the first 17 seconds. Determine the net displacement Δs during that interval and the total distance D traveled. By inspection of the s-t relationship, what conclusion can you reach regarding the acceleration? Answers: Δ5= mm D= mm
The given position equation of a particle is, s=102−23t+t2Here, t is in seconds.The first derivative of s is its velocity: v = ds/dt - 23 + 2tThe second derivative of s is the particle's acceleration:
The total distance traveled is the sum of all distance travelled in each interval of time: D = ∫|v|dt + ∫|v|dt + ... (From t 0 s to t = 17 s)From the graph of the velocity, the particle is moving to the left and toward the right side. The velocity-time graph is linear, which means that the acceleration is constant and uniform. Hence, the conclusion we can draw is that the particle is moving with uniform acceleration. a = dv/dt = 2The given equations are: s=102−23t+t2v
=−23+2ta
=2Plot of s-t and v-t graphs:
Net displacement (Δs) during the interval of 17 seconds can be calculated as:Δs = s(17) - s(0)Δs
= 102 - (2 × 3² / 2) - (23 × 3) + (17² / 2) - 102Δs
= -4 mmThe particle moves to the left side.
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A burst of sound takes 0.4 seconds to reach the seabed and return, if speed of sound in water is 1400m/s. what is the depth of water?
Explanation:
Given:
Speed of sound = 1400 m/s
Total time taken = 0.4 seconds
To find:
The depth of water
Solution:
As it take 0.4 seconds for the burst to reach the seabed and return (both ways), we can deduce that it takes 0.2 seconds to reach the seabed (one way).
This is because the speed of sound is a constant.
Now, to find the depth, we use the equation
Speed = Distance/Time
Here, we know the values of speed (1400 m/s) and time (0.2 seconds). Distance is the depth of the water, which we need to find. Let the distance be x.
Therefore
1400 = x/0.2
x = 1400 * 0.2
x = 280 m
We get the depth as 280 metres.
Feel free to ask me if you didn't understand any part.
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The sun produces energy from matter in its core through the process of
Answer here
Answer:
Explanation:
nuclear fusion?
5. Imagine you're an astronomer who discovers a blue supergiant star that emits high-intensity light with a wavelength of 400 nm. How would the temperature of this star compare to the sun? How do you know?
The temperature of the blue supergiant star would be hotter than the Sun.
We can determine this based on the concept of Wien's displacement law, which states that the wavelength of peak intensity emitted by a black body is inversely proportional to its temperature. The Sun, with its characteristic yellow-white light, has a temperature of approximately 5,500 degrees Celsius (5,773 Kelvin), which corresponds to a peak wavelength of around 500 nm. In comparison, the blue supergiant star emits high-intensity light with a wavelength of 400 nm, which is shorter than the Sun's peak wavelength. Since shorter wavelengths correspond to higher temperatures, the blue supergiant star must have a higher temperature than the Sun. These stars have surface temperatures typically exceeding 10,000 degrees Celsius (10,273 Kelvin) and can reach even higher temperatures, up to tens of thousands of degrees Celsius.
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HELP I NEED THIS QUICK PLEASE
First let's see what the funny letters in the equation they gave us means.
F = Gravitational Force
G = Gravitational Constant
m1 = Mass of one of the spheres
m2 = Mass of the other sphere
r = Distance between the two spheres
Ok, now implement it.
\(\frac{9.8 x 10^{2} 1.96 x 10^{2} }{4^{2} }\)
To make it simpler
F = 980 x 196 = 192,080
192,080 ÷ 4²
192,080 ÷ 16
= 12005
F = 12,005N
It is because of following reasons - For keeping the box in motion , we have to continuously apply the energy i.e., force as opposite frictional force is always present - for starting the box we have to apply force only one time such that force applied will be more than friction at starting. Aftet some time box will be halted as applied force will be dessipated.
To keep an object in motion, continuous application of force is required due to the presence of opposing frictional force. Starting the object requires an initial force greater than the frictional force, and once in motion, the force applied needs to counteract the dissipative effects of friction to maintain the object's motion.
When an object is at rest or stationary, static friction opposes any applied force. To start the motion of the object, we need to apply a force greater than the static friction. Once the object is in motion, the friction that acts on it changes to kinetic friction, which is generally lower than static friction. However, kinetic friction still opposes the motion and acts as a dissipative force.
To keep the object in motion, a continuous force needs to be applied to overcome the dissipative effects of kinetic friction. This force compensates for the energy lost due to friction and ensures that the object remains in motion. If the applied force is insufficient to counteract the frictional force, the object will eventually come to a halt due to the dissipation of energy through friction.
In summary, continuous application of force is necessary to keep an object in motion as it counteracts the opposing force of friction, which dissipates energy. Without this continuous force, the dissipative effects of friction would cause the object to slow down and eventually stop.
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If you start with 100 grams of a radioactive isotope, how much DAUGHTER would you expect to have after 3 half-lives? 100 g 25 g 87.5 g 50 g 12.5 g 75 g
After three half-lives of a radioactive isotope, you would expect to have 12.5 grams of the daughter isotope.
The concept of half-life refers to the time it takes for half of the radioactive substance to decay. During each half-life, the amount of the original radioactive isotope decreases by half, while the amount of the daughter isotope increases.
Since we start with 100 grams of the radioactive isotope, after one half-life, we would have 50 grams of the original isotope remaining, and 50 grams would have decayed into the daughter isotope.
After the second half-life, half of the remaining 50 grams would decay, leaving us with 25 grams of the original isotope and 75 grams of the daughter isotope.
After the third half-life, half of the remaining 25 grams would decay, resulting in 12.5 grams of the original isotope and 87.5 grams of the daughter isotope.
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INEGRATED SCIENCE-8th grade science
report cards due dec.18
Please Help ASSSAAAAPPPP! PLEASEEEEEEE
Answer:
I do drink bottled water but not to often, I live about 2.8 miles away from its water source and if i did'nt drink bottled water and I had to found out how my drinking water is treated I would go ask the people that are taking care of the water.
Explanation:
hope this helps
describe how a diffraction grating affects the light from a hydrogen lamp.
The diffraction grating affects the light from a hydrogen lamp as it produces the separation of the colors of the white light. The spectrum can be viewed through the grating,
how much work must you do to push a 12 kg k g block of steel across a steel table at a steady speed of 1.3 m/s m / s for 6.1 s s ? the coefficient of kinetic friction for steel on steel is 0.60.
To determine the work necessary to drive a 12 kilogram block of steel over a steel table at a constant speed of 1.3 m/s for 6.1 seconds, we must take into account the force required to overcome friction.
Steel against steel has a coefficient of kinetic friction of 0.60.Then, we must compute the force of friction opposing the block's motion. F friction = coefficient of friction x F normal, where F normal is the normal force applied by the table to the block. We know that the net force applied on the block is zero since it is travelling at a constant pace. As a result, the force of friction must be equal to the force we are exerting.to move the block ahead. Applying the aforementioned equation, we can calculate the friction force to be 70.56 N. As a result, the effort required to push the block for 6.1 seconds is equal to the friction force multiplied by the distance the block moves during that time, which is given by distance = speed x time = 1.3 m/s x 6.1 seconds = 7.93 m. Hence, W = force x distance = 70.56 N x 7.93 m = 560.3 J is the labor necessary to push the block (Joules).
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A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the y-component of the ball'sfinal velocity?y-component (m/s)Enter
let the bowling ball initially is moving along the x-axis,
The whole process can be represented as,
Before the collision the net kinetic energy of the balls is,
\(K_{iy}=\frac{1}{2}\times m_1\times(v_1\cos (90^o))^2+\frac{1}{2}\times m_2\times(0)^2\)where the values of the variables are given as,
\(\begin{gathered} m_1=7.5\text{ kg} \\ v_1=6.42ms^{-1} \\ m_2=1.6\text{ kg} \end{gathered}\)As the value of cos(90) is zero.
Substituting the known values,
The value of the net kinetic energy with the velocity along the y-axis before the collision is,
\(K_{iy}=0\)The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.
After the collision of the balls, the net kinetic energy is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times m_1\times(v^{\prime}_1\sin (\alpha))^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \\ K_{fy}=\frac{1}{2}\times m_1\times(v_{1fy})^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \end{gathered}\)Negative sign here indicating the direction of the final balls motion will be opposite to the each other.
The values of the variables are given as,
\(v^{\prime}_2=14.8ms^{-1}\)Substituting the known values,
The value final kinetic enegry of the balls with velocity along the y-axis is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times7.5\times(v_{1fy})^2+\frac{1}{2}\times1.6\times(14.8\times\sin (360^o-47^o)^2 \\ K_{fy}=3.75\times(v_{1fy})^2-93.72 \end{gathered}\)Here 360 degree is used because the pin ball direction is downward of the positive x-axis.
Then by the law of conservation of energy along the y-axis,
\(\begin{gathered} K_{iy}=K_{fy} \\ 0=3.75\times(v_{1fy})^2-93.72 \\ (v_{1fy})^2=\frac{93.72}{3.75} \\ (v_{1fy})^2=25 \\ v_{1fy}=5ms^{-1} \end{gathered}\)Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.
The Moon and the Earth both orbit the center of mass of the Earth-Moon system. Earth is 81 times more massive than the Moon. Assume that the center-to-center distance between the Earth and the Moon is 384,400.0 km. Determine the distance of the center of mass of the Earth- Moon system from the center of the Earth. Does it lie inside or outside the Earth with the radius of 6,371.0 km
The distance of the center of mass of the Earth-Moon system from the center of the Earth is approximately 4,670 km. It lies outside the Earth, but it is still very close to it (only about 73% of the Earth's radius).
To determine the distance of the center of mass of the Earth- Moon system from the center of the Earth, we can use the formula of Center of mass, given by:
Center of Mass = (m1x1 + m2x2)/(m1 + m2)
Where, m1 = mass of the Earth, m2 = mass of the Moon
x1 = position of the Earth
x2 = position of the Moon
We can assume that the center of mass of the Earth-Moon system lies on the line joining the centers of the Earth and the Moon and it will be closer to the Earth.
Let the distance of the center of mass from the Earth be 'x'. Then, the distance of the center of mass from the Moon will be (384,400 - x).
Now, we can use the concept of torque to find the value of 'x'.
Torque due to the Moon = Torque due to the Earth(384,400 - x) x m2 x g = x x m1 x g x r
Where, g = acceleration due to gravity
r = radius of the Earth
We have to use the values of m1, m2, g and r, given by:m1 = 81 x m2
g = 9.81 m/s^2r = 6,371 km = 6,371,000 m
Substituting the values, we get:
(384,400 - x) x m2 x g = x x m1 x g x r
(384,400 - x) x m2 = x x m1 x r
384,400 x m2 - x x m2 = x x m1 x r
384,400 x m2 = x x (m1 x r + m2)x = (384,400 x m2)/(m1 + m2) + r
Putting the values, we get:
x = [(384,400 x 7.34 x 10^22)/(5.97 x 10^24 + 7.34 x 10^22)] + 6,371,000x = 4,670 km (approx)
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