Answer:
10%
Explanation:
It's the famous "10 percent rule" that limits how much energy is transferred b/w trophic levels.
So if we started with 1000 kJ of energy then on average, only 10%, which is about 100 kJ of energy is passed onto the next trophic level.
Answer:
10%
Explanation:
On average, only 10% of energy stored as biomass in a trophic level is passed from one level to the next. This is known as 10% rule.
What should you do if...
3. You are in doubt about any procedure?
4. Your clothes catch on fire?
5. You broke a glass?
6. Chemical splashes in your eyes?
7. To prevent chemical splashes into an eye or a foreign object gets stuck in one?
8. You injure yourself or lab partner?
9. You use hot plate in the experiment?
Answer:
3. you need to ask your available lab instructors what to do.
4. You immediately have to drop down your cloth and roll it to extinguish the fire or move to the emergency shower if available
5. You have too keep calm and report to the lab instructor but do no shout.
6. Move immediately to the eye rinse basin if available and wash your eyes gently and thoroughly
A man is driving through his neighborhood
when a boy on a bike comes out of a driveway.
The driver skids to a stop in an attempt to avoid
hitting the biker, but ends up knocking the boy
off of his bike. The biker has minor injuries and
his parents file a lawsuit against the driver,
claiming that the car was going over the speed
limit at the time. The drag of the road is 0. 75
You might need to slow down because, generally speaking, a bicycle moves more slowly than other vehicles.
What sort of vehicle can a driver encounter on a slow-moving road? You might need to slow down because, generally speaking, a bicycle moves more slowly than other vehicles.Before overtaking a bicycle in a lane that is too small to share, wait until there is a clear section of the road.Before opening your automobile door into a traffic lane or a cycling lane, look out for passing bicycles.I'd like to outline three fundamental ideas that, in my opinion, form the basis of this skill set, despite the fact that defensive and professional driving entail many specific techniques:1) fault vs. avoidability; 2) following distance; and 3) detachment from other driversYour following distance should be extended.The interior and outside mirrors, as well as a head check, can be used to assess the mirror blind spots by the driver.
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which lineweaver–burk plot most accurately depicts the kinetic data of gk and gk-p?
The most accurate Lineweaver-Burk plot that depicts the kinetic data of GK and GK-P can be determined by comparing the reciprocal plots of the enzyme-catalyzed reaction rates.
Lineweaver-Burk plots are graphical representations of the Michaelis-Menten equation, displaying the inverse of substrate concentration (1/[S]) on the x-axis and the inverse of reaction velocity (1/V) on the y-axis. In order to find the most accurate plot for GK and GK-P, it is necessary to obtain experimental data for both enzymes. Once you have the initial reaction velocities (V) for various substrate concentrations ([S]), you can create a series of data points for both GK and GK-P by calculating the corresponding 1/[S] and 1/V values.
Next, plot these reciprocal data points on a graph and draw the best-fit lines for each enzyme. The slopes and intercepts of these lines can be used to derive the kinetic parameters, such as Km (substrate affinity) and Vmax (maximum reaction velocity), for both GK and GK-P. So therefore by comparing the Lineweaver-Burk plots for GK and GK-P, you can determine which one most accurately represents their respective kinetic data. This will allow you to understand their enzymatic differences and potential functional implications in metabolic pathways.
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A 1000 kg go-kart is moving at a constant speed of 23 m/s. How much kinetic energy does it have?
The kinetic energy possesed by a 1000kg go-cart that is moving at a constant speed of 23 m/s is 264,500J.
How to calculate kinetic energy?Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.
Kinetic energy of a body can be calculated using the following formula;
K.E = ½mv²
According to this question, a 1000kg go-cart is moving at a constant speed of 23m/s. The kinetic energy of the cart can be calculated as follows:
K.E. = ½ × 1000 × 23²
K.E. = 500 × 529
K.E. = 264,500J
Therefore, 264,500J is the kinetic energy of the go-cart.
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A 55.0-kg person consumes a small order of french fries
(241.0 Cal)
and
wishes to
"work off"
the
energy by climbing a
11.0 m
stairway.
How many vertical climbs are needed to use all the
energy?
To use all the energy from consuming a small order of french fries, the person would need to climb the 11.0 m stairway approximately 17.0 times.
The energy content of the small order of french fries is given as 241.0 Cal. We can convert this value to joules since the unit of energy in the metric system is the joule (J). 1 calorie (Cal) is equal to 4.184 joules (J). To use all the energy from consuming a small order of french fries, the person would need to climb the 11.0 m stairway approximately 57 times.
Energy content of the small order of french fries:
241.0 Cal × 4.184 J/Cal = 1007.144 J
Work done to climb the stairway:
(55.0 kg) × (11.0 m) × (9.8 m/s²) = 59294 J
Number of climbs needed to use all the energy:
1007.144 J ÷ 59294 J ≈ 17.0
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Kumar rides his bicycle such that the back wheel rotates 10 times in 5 s. Determine the angular velocity of the wheel in a) degrees per second b) radians per second.
(a) Angular velocity in Degrees per second = \(720^0\) per second
(b) Angular velocity in radians per second = 4\(\Pi\) radians per second.
Number of rotations = 10
Total time = 5
So, the value of frequency will be =(Number of rotations)/Total time
That will be = (10/5) = 2
Angular velocity is defined as the speed at which an item rotates or revolves around an axis.
The Greek letter omega (occasionally ω, sometimes Ω) stands for angular velocity.
The SI unit for angular velocity is radians per second because it is expressed as an angle per unit of time.
(a) Angular velocity in Degrees per second
\($=360^{\circ} \mathrm{f}=720^{\circ}$\) degree per second.
(b) Angular velocity in radians per second
\($\omega =2 \pi f=2 \pi(2)=4 \pi$\) radians per second.
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two objects, each with a charge of 1 nc, are sitting alone in space. if we measure the magnitude of the electric field at a location given by , which is equidistant from both objects, what result would we get?
According to question, result would we between E=0 and E=(1/4piepsilon naught) (2nC/r^2) .
The presence of an electric charge results in a modification of space known as the electric field. Between a source charge and a test charge, the electric field mediates the electric force. A vector by definition points away from positive charges and toward negative charges, which is what the field does.
Always pointing away from a positive charge and in the direction of a negative point are electric field lines. Field lines never cross one another, too.
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how much radius of earth
HELP MEEEEE HURRRYYYY EASYY
What best describes the greatest height a ball will bounce off the ground after being dropped from a height of 50 centimeters?
A. Less than 50 centimeters, as the ball transforms some of its thermal energy into sound energy
B. Less than 50 centimeters, as the ball transforms some of its potential energy into sound energy
C. Greater than 50 centimeters, as the ball transforms some of its thermal energy into potential energy
D. Greater than 50 centimeters, as the ball transforms some of its potential energy into thermal energ
Answer:
C
Explanation:
thats what i think it depends on the amount of force someone dropped the ball with.
Answer: A) "Less than 60 centimeters, as the ball transforms a part of its potential energy into heat energy"
Explanation:
I took the test
what is the value of acceleration due to gravity at the pole, equator and the centre of the earth
Answer:
In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.
3. in adlerian therapy, clients learn how core beliefs that have been helpful in the past might not work well now and then to put that understanding to use in the real world. what therapeutic process is referred to jim to overcome his core beliefs and move forward? as a counselor, how do you make him understand?
Adlerian therapy is a method in which a therapist collaborates with a client to pinpoint challenges and develop successful solutions for achieving their objectives.
Key Takeaways: Adlerian Therapy
Individual therapy, often known as Adlerian therapy, places an emphasis on the patient's capacity to effect good change in his or her own life.
Adlerian therapy consists of four stages: engagement, assessment, insight, and reorientation.
In Adler’s theory, individuals work to overcome feelings of inferiority and to act in ways that benefit the social interest.
Four Stages of Adlerian Therapy :
Engagement
Assessment
Insight
Reorientation
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You are moving a chair by sliding it across the ground. The maximum force you can give the chair before it slides is 150 N. If you push the chair with 250 N of force and the chair begins to slide, what will the frictional force be?
Answer:
Frictional force will be 150N
What is speed? Please respond in 1-2 complete sentences using your best
grammar.
A physical concept called speed explains how quickly an object is moving.
The distance covered in a given amount of time is its definition. In the International System of Units, the measurement of speed is measured in metres per second (m/s). (SI).
The following algorithm can be used to determine speed:
Distance travelled times speed
For instance, if a car goes 100 kilometres in two hours, its speed can be determined as follows:
50 km/hour is equal to 100 km/two hours of speed.
Speed can also be expressed in different measures, including feet per second (ft/s), kilometres per hour (km/h), and miles per hour (mph). An object's velocity, acceleration, and direction of motion are just a few examples of variables that can affect speed.
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an astronomical telescope, having an objective of focal length 100cm and eyepiece of focal length 10cm, is used in normal adjustment. calculate the separation of the lenses
The separation of the lenses is 110 cm.
The separation of the lenses in an astronomical telescope can be calculated using the lens formula, which states that:
1/f = 1/v - 1/u,
where f is the focal length of the lens, v is the image distance, and u is the object distance.
In this case, the objective lens has a focal length of 100 cm, and the eyepiece lens has a focal length of 10 cm.
For the objective lens, u1 is the distance between the object being observed and the lens, and v1 is the distance between the lens and the image formed by the objective lens.
For the eyepiece lens, u2 is the distance between the image formed by the objective lens and the eyepiece lens, and v2 is the distance between the eyepiece lens and the final image formed.
Since the telescope is in normal adjustment, the final image is formed at infinity, so v2 is equal to infinity.
Using the lens formula for the objective lens, we can write:
1/f1 = 1/v1 - 1/u1.
Using the lens formula for the eyepiece lens, we can write:
1/f2 = 1/v2 - 1/u2.
Substituting v2 = infinity, the equation becomes:
1/f2 = 0 - 1/u2.
1/f2 = -1/u2.
Since the telescope is in normal adjustment, the final image formed is at infinity. Therefore, u2 is equal to the distance between the eyepiece lens and the image formed by the objective lens, which is equal to v1.
So, u2 = v1.
1/f2 = -1/v1.
1/10 = -1/v1.
v1 = -10 cm.
Since the distance between the object and the objective lens is equal to the distance between the objective lens and the image formed (u1 = v1), the separation between the lenses is the sum of the focal lengths of the two lenses:
separation = focal length of objective lens + focal length of eyepiece lens.
Substituting the values:
separation = 100 cm + 10 cm = 110 cm.
Therefore, the separation of the lenses in the astronomical telescope is 110 cm.
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While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. how much time does it take?
While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. The time taken by the car will be 4 seconds. the correct answer is option(c).
When acceleration is constant, the rate of change in velocity is also constant. In the absence of any acceleration, velocity remains constant. When acceleration is positive, velocity becomes more significant.
Let a denote acceleration, u denote initial velocity, v denote final velocity, and t denote time.
The equation of motion is stated as,
v = u + at
v² = u² + 2as
A car travels across a distance of 60.0 m while accelerating constantly from 12.0 m/s to 18.0 m/s.
Then the time taken by the car will be,
u = 12 m/s
v = 18 m/s
s = 60 m
Put these in the equation v² = u² + 2as.
18² = 12² + 2 x a x 60
a = 1.5
Then the time will be
18 = 12 + 1.5t
1.5t = 6
t = 4 seconds
Hence, the time taken is 4 s.
The complete question is:
While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?
1.00 s
2.50 s
4.00 s
4.50 s
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A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15 ∘
to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, find the minimum speed at which she can travel without slipping.
A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15° to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, the minimum speed at which she can travel without slipping is 13.64 m/s.
To find the minimum speed at which the girl can travel without slipping, we need to consider the forces acting on her and her cycle as they move in a circular track.
The forces acting on the girl and her cycle are the gravitational force (mg), the normal force (N), and the frictional force (f). The frictional force provides the centripetal force necessary to keep the girl moving in a circular path.
The normal force can be resolved into two components: the vertical component (N⊥) and the horizontal component (N∥). The vertical component balances the gravitational force, while the horizontal component provides the centripetal force.
Mass of the girl and cycle (m) = 60 kg
Diameter of the circular track (d) = 60 m
Bank angle (θ) = 15 degrees
Coefficient of friction (μ) = 0.25
Find the normal force components:
N⊥ = mg cos(θ)
N∥ = mg sin(θ)
The frictional force:
f = μN⊥
The frictional force (f) provides the centripetal force required for circular motion:
f = m(v² / r)
Here, v is the velocity and r is the radius of the circular track. The radius is:
r = d / 2
Combining the equations, we have:
μN⊥ = m(v² / r)
Substituting the values we have:
μmg cos(θ) = m(v² / (d / 2))
v² = (μmg cos(θ) / m) * (d / 2)
v² = (μg cos(θ)) * (d / 2)
v = √((μg cos(θ)) * (d / 2))
v = √((0.25 * 9.8 * cos(15)) * (60 / 2))
v ≈ 13.64 m/s
Therefore, the minimum speed at which the girl can travel without slipping is approximately 13.64 m/s.
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2. Provide a definition of a measuring unit. Give an example of a
unit of length, mass, and volume.
Impulsive vs. Long-Duration Flare The X-ray flux from an X5 impulsive flare can be approximated as 5x10-4e-2 W/m², t (hours) > 0 The X-ray flux from an X1 long-duration flare can be approximated as 1x10-4 e-t/3 W/m², t (hours) > 0 Calculate the total X-ray flux in J/m² for each flare. If the total fluxes are similar, which flare is more likely to signal the beginning of a significant space weather event? Why?
The X₅ impulsive flare has a total X-ray flux that is four times greater than the X1 long-duration flare.
How to calculate the valueThe total X-ray flux for the X5 impulsive flare is:
5x10-4e⁻² W/m² * 3600 s/hour * 1 hour
= 5.4 J/m²
The total X-ray flux for the X1 long-duration flare is:
1x10⁻⁴ e-t/3 W/m² * 3600 s/hour * 1 hour
= 1.2 J/m²
As you can see, the X₅ impulsive flare has a total X-ray flux that is four times greater than the X1 long-duration flare. Therefore, the X impulsive flare is more likely to signal the beginning of a significant space weather event.
The reason for this is that the X₅ impulsive flare is a much more powerful event. It releases a much larger amount of energy in a much shorter period of time.
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Use the energy method to determine the deflected shape of a rectangular plate a x b, simply supported along
each edge and carrying a concentrated load F at a position (r1, y) . The deflected shape of the plate can be
represented by the series DO MAT nay Amn sin sin b TIL
The energy method is a technique used to determine the deflected shape of a rectangular plate subjected to a concentrated load. In this case, the plate is simply supported along each edge and carries a concentrated load F at a position (r1, y).
To find the deflected shape of the plate, we can use the series representation DO MAT nay Amn sin sin b TIL.
Now, let's break down the steps to determine the deflected shape using the energy method:
1. First, we need to calculate the bending moment caused by the concentrated load F. The bending moment can be given by the formula M = F * (b - r1),
where b is the width of the plate and r1 is the distance of the concentrated load from one edge.
2. Next, we need to find the deflection function, which represents the shape of the plate when it is deflected.
The deflection function can be represented by the series DO MAT nay Amn sin sin b TIL, where DO is the maximum deflection, A is a constant, m and n are positive integers, and a and b are the dimensions of the plate.
3. Now, we substitute the deflection function into the plate's governing equation. The governing equation for a rectangular plate simply supported along each edge is given by the biharmonic equation:
∇^4w = 0,
where ∇^4 represents the Laplacian operator.
4. By substituting the deflection function into the biharmonic equation and solving for the unknown coefficients, we can determine the specific form of the deflection function that satisfies the boundary conditions.
5. Finally, with the determined coefficients, we can calculate the deflected shape of the plate by evaluating the deflection function at different points on the plate.
It's important to note that the exact determination of the coefficients Amn requires solving an infinite series of equations.
However, in practical applications, only a few terms of the series are usually considered, resulting in an approximation of the deflected shape.
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A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is
Answer:
0.02N
Explanation:
According to Newton's 3rd Law of motion, the bee exerts the same force on the bowling ball as the bowling ball exerts the force on the bee.
We have that for the Question "A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is" it can be said that The force the bee exerts is
F=0.02N
From the question we are told
A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is
Generally the Newtons equation for Motion is mathematically given as
This law perceives two bodies who collide as having forces which are equal as the magnitudes in opposite directions
Therefore
V^2= 2as
Hence
The force the bee exerts is
F=0.02N
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as the stapes vibrates the oval window, pressure waves first begin
As the stapes bone vibrates against the oval window, it creates pressure waves that propagate through the fluid-filled cochlea of the inner ear.
These pressure waves are the initial stimulus for the process of hearing. The oval window is connected to the cochlea, which is a spiral-shaped structure responsible for converting sound waves into electrical signals that can be interpreted by the brain.
When the oval window moves in response to the vibrations of the stapes, it creates a pressure disturbance in the fluid within the cochlea. This disturbance travels through the cochlear fluid, causing the basilar membrane (a thin membrane running along the length of the cochlea) to vibrate. The basilar membrane has different mechanical properties along its length, so different regions of the membrane vibrate preferentially in response to specific frequencies of sound.
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4. Once the child in the sample problem reaches the bottom of the hill,
she continues sliding along flat; snow-covered ground until she comes
to a stop. If her acceleration during this time is -0.392 m/s², how long
does it take her to travel from the bottom of the hill to her stopping
point?
Answer:
8.04 seconds
Explanation:
Assuming that the child starts from rest at the bottom of the hill and travels until she comes to a stop, we can use the following kinematic equation:
v_f^2 = v_i^2 + 2ad
where v_f is the final velocity (which is zero since the child comes to a stop), v_i is the initial velocity (which is the velocity at the bottom of the hill), a is the acceleration (-0.392 m/s²), and d is the distance traveled.
We can solve for d:
d = (v_f^2 - v_i^2) / (2a)
= (0 - v_i^2) / (2-0.392)
= v_i^2 / 0.784
Since the child is sliding along flat snow-covered ground, there is no change in elevation, so we can use the distance traveled from the bottom of the hill to the stopping point as the distance d.
To find the time it takes for the child to travel this distance, we can use the following kinematic equation:
d = v_it + 0.5a*t^2
where t is the time and all other variables are as previously defined.
Substituting the expression for d obtained above, we get:
v_i^2 / 0.784 = v_it + 0.5(-0.392)*t^2
Solving for t, we get:
t = (2 * v_i) / 0.392
We still need to find the value of v_i, the initial velocity of the child at the bottom of the hill. To do so, we can use conservation of energy. The child starts at rest at the top of the hill, so all the initial energy is potential energy. At the bottom of the hill, all the potential energy has been converted to kinetic energy. Assuming no energy is lost to friction, we can equate these two energies:
mgh = 0.5mv_i^2
where m is the mass of the child, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the hill.
Solving for v_i, we get:
v_i = √(2gh)
Substituting this expression for v_i into the expression for t obtained earlier, we get:
t = (2 * √(2gh)) / 0.392
Plugging in the values of g, h, and a, we get:
t = (2 * √(29.820)) / 0.392 = 8.04 seconds
You may have seen ambulances on the street with the letters of the word AMBULANCE written on the front of them, in such a way as to appear correctly when viewed in your car's rear-view mirror. (See the figure.) How do the letters appear when you look directly at the ambulance (not through the mirror)?
When you look directly at an ambulance, the letters of the word "AMBULANCE" will appear reversed, or mirrored.
This is because the letters on the front of the ambulance are intentionally designed to be read in reverse when viewed in a rare-view mirror, so that drivers can quickly and easily identify the vehicle as an ambulance and make way for it to pass.
1) Here's how the letters appear when viewed directly, step by step:
2) The first letter, "A", will appear as a normal "A" when viewed directly, as there is no mirror involved.
3) The second letter, "M", will appear reversed, as the left side of the letter will appear on the right, and vice versa.
4) The third letter, "B", will also appear reversed, with the left side of the letter appearing on the right and the right side appearing on the left.
5) The fourth letter, "U", will appear normal, as it is symmetrical and looks the same from both sides.
6) The fifth letter, "L", will appear reversed, with the left side appearing on the right and the right side appearing on the left.
7) The sixth letter, "A", will again appear normal.
8) The seventh letter, "N", will appear reversed, with the left side appearing on the right and the right side appearing on the left.
9) The eighth letter, "C", will also appear reversed, with the left side appearing on the right and the right side appearing on the left.
The ninth letter, "E", will appear normal, as it is symmetrical and looks the same from both sides.
So, when you look directly at an ambulance, the letters will appear reversed for the second, third, fifth, seventh, and eighth letters.
This is because these letters are not symmetrical and have different shapes on the left and right sides, so they appear differently when viewed in reverse.
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A device that converts electrical energy into kinetic energy to turn an axle?
Write the following number in scientific notation. 0.00000341
Answer:
3.41 × 10^-6
It is because 341 has to be a decimal and the zeros you see there...always count them if the zero has the decimal after it it will be a negative. Why 10 to the power of Negative 6? Count the 6 zeros
PLEASE HELP!!!
Photons with an energy of 5 electron volts strike a photoemissive surface causing the emission of 2 electron-volt photoelectrons. If photons with 10 electron volts of energy strike the same photoemissive surface, what will be the energy of the emitted photoelectrons?
Answer:
Easy.The energy of the emitted photoelectrons can be determined using the concept of the photoelectric effect. According to the photoelectric effect, the energy of the emitted photoelectrons is equal to the difference between the energy of the incident photons and the work function of the material.
In this case, we are given that the incident photons have an energy of 10 electron volts (eV). Let's assume the work function of the material is represented by W (in eV).
The energy of the emitted photoelectrons (Ee) can be calculated as:
Ee = incident photon energy - work function
Ee = 10 eV - W
We are also given that when photons with an energy of 5 eV strike the same surface, the emitted photoelectrons have an energy of 2 eV. Using this information, we can set up another equation:
2 eV = 5 eV - W
Solving this equation for W, the work function:
W = 5 eV - 2 eV
W = 3 eV
Now, we can substitute the value of the work function into the equation for the energy of the emitted photoelectrons:
Ee = 10 eV - W
Ee = 10 eV - 3 eV
Ee = 7 eV
Therefore, when photons with 10 electron volts of energy strike the photoemissive surface, the energy of the emitted photoelectrons will be 7 electron volts.
a rod of zinc has a mass of 5kg. in water it weighs 25 N. what is the buoyant force on it when it is submerged in water?
Answer:
If it has a mass of 5 kg its weight is 5 kg * 9.8 m/s^2 = 49 N
Weight in air = 49 N
Weight in water = 25 N
Buoyant force provided by water = 49 - 25 = 24 N
Choose the picture of how the Earth would move if you "turned off the gravity forces
Answer:
I think the answer is d; as the object is revolving around the earth in a circular motion due to centripetal force provided by gravity and if you "turned off" the gravity then it would tend to continue away from the planet but in the same direction.
please help im failing this class and i have to get these answers right for my test.
You can see the planets at night because
A. they produce their own light.
B. they reflect light from each other.
C. nuclear fusion takes place in their cores.
D. sunlight reflects from their surfaces.
Answer:
hope this helps at least a little it's either b or d but I would say d!
What are the three components of the equation for the second law of motion?
force= mass × acceleration