The number of birds at the Bronx Zoo is 139. There are 139 birds at the Bronx Zoo, based on the information provided by Maggie's animal count and leg count.
Let's use algebraic equations to solve for the number of birds at the Bronx Zoo.
Let's assume that the number of mammals is represented by the variable "m" and the number of birds is represented by the variable "b."
From the given information, we know that the total number of animals counted, whether mammals or birds, is 200. This can be expressed as:
m + b = 200 (Equation 1)
Additionally, we know that the total number of legs counted is 522. Mammals have 4 legs each, while birds have 2 legs each. Therefore, the total number of legs can be calculated as:
4m + 2b = 522 (Equation 2)
To solve this system of equations, we can use substitution or elimination method.
Let's solve using the elimination method:
Multiply Equation 1 by 2 to make the coefficients of "b" in both equations the same:
2m + 2b = 400 (Equation 3)
Now subtract Equation 3 from Equation 2:
4m + 2b - (2m + 2b) = 522 - 400
Simplifying:
2m = 122
Divide both sides by 2:
m = 61
Now substitute the value of "m" back into Equation 1 to solve for "b":
61 + b = 200
Subtract 61 from both sides:
b = 200 - 61
b = 139
Therefore, the number of birds at the Bronx Zoo is 139.
By solving the given algebraic equation, we determined that there are 139 birds at the Bronx Zoo, based on the information provided by Maggie's animal count and leg count.
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Around ball that has a volume of 10 milliliters was found to have a density of 1
gram/milliliter. What is the mass of the round ball?
(Mass is measure in grams, volume is measured in milliliters and density is measured in
grams/milliliter.)
Density = Mass/Volume
Answer:
\( \boxed{\sf Mass \ (M) \ of \ the \ round \ ball = 10 \ grams} \)
Given:
Volume (V) = 10 millilitres
Density (\( \sf \rho \)) = 1 gram/millilitre
To Find:
Mass (M) of the round ball
Step-by-step explanation:
Formula:
\( \boxed{ \bold{Density \: ( \rho) = \frac{Mass \ (M)}{Volume \ (V)} }}\)
\( \sf \implies Mass \ (M) = Density \ (\rho) \times Volume \ (V)\)
Substituting value of density (\( \sf \rho \)) & volume (V) in the equation:
\( \sf \implies M = 1 \times 10 \\ \\ \sf \implies M = 10 \: grams\)
\( \therefore\)
Mass (M) of the round ball = 10 grams
Help me solve this problem please
Answer:
A 2,3,6 :)
Step-by-step explanation:
thats answer corect me if im wrong hope it help
41- 3/4 x < 53
please help!
Answer:
x > - 16
Step-by-step explanation:
41- 3/4 x < 53
Subtract 41 from each side
41-41- 3/4 x < 53-41
-3/4x < 12
Multiply each side by -4/3, remembering to flip the inequality
-4/3 * -3/4x > 12 * -4/3
x > - 16
Find the length, L, of the curve given below. y= x∫1√9t ⁴−1dt, 1≤x≤3
L=
The given function is y = x ∫₁^(√9) (t⁴ - 1) dt. Here, we need to find the length of the curve between x = 1 and x = 3.
Let us differentiate the function y = x ∫₁^(√9) (t⁴ - 1) dt with respect to x using the Leibnitz rule:dy/dx = ∫₁^(√9) (t⁴ - 1) dt + x d/dx (∫₁^(√9) (t⁴ - 1) dt)Here, the first term is simply the given function. Let us evaluate the second term separately. Let u = ∫₁^(√9) (t⁴ - 1) dt, then we have u = [t⁵/5 - t] from 1 to √9 which gives u = 16/5. Hence, d/dx (∫₁^(√9) (t⁴ - 1) dt) = d/dx u = 0. Therefore, dy/dx = ∫₁^(√9) (t⁴ - 1) dt.Length of curve between x = 1 and x = 3 is given byL = ∫₁³ √(1 + (dy/dx)²) dx= ∫₁³ √(1 + (∫₁^(√9) (t⁴ - 1) dt)²) dx.
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Two employees Maggie and Rachel earn $18 per hour. Maggie receives 1.00 raise each 6 months and Rachel receives a 6% raise each year. Write an equation to represent Maggie pay over x years
What is the rate of change of y with respect to x for this function
Answer:
-0.2
Step-by-step explanation:
Between the left marked point and the right one, the y-value changes by ...
Δy = 2 -3.6 = -1.6
and the x-value changes by ...
Δx = 5 -(-3) = 8
The rate of change of y with respect to x is the ratio of these:
Δy/Δx = -1.6/8 = -0.2
The rate of change of y with respect to x is -0.2.
26,062, 26,064, __
2,898, 322, 324, 36
What is the missing number in the pattern above?
Auto saved at 12
What is the equation of a line that passes through the point (-5, 2) and has a slope of zero?
(Hint: Substitute the slope and point into the point slope formula and then solve for y!)
Answer:
Slope intercept: y = 0x + 2
Point slope: y - 2 = 0(x + 5)
Standard: 0x - y = 2
A triangle has vertices at A (−2, −2), B (−1, 1), and C (3, 2). Which of the following transformations produces an image with vertices A′ (−2, 2), B′ (−1, −1), and C′ (3, −2)?
2n+3 5n-4 work out 2 terms that are in both
Answer:
(2n 2+5n−4)⋅(n+1)
Step-by-step explanation:
STEP
1:Equation at the end of step 1
(((4•(n2))+3n)+((2•(n3))-4))+(3n2-2n)
STEP 2:Equation at the end of step 2
(((4•(n2))+3n)+(2n3-4))+(3n2-2n)
STEP 3:Equation at the end of step 3:
((22n2 + 3n) + (2n3 - 4)) + (3n2 - 2n)
STEP 4:Checking for a perfect cube
4.1 2n3+7n2+n-4 is not a perfect cube
30% of the mass of an object is 24 kilograms. Use this fact to find 60% of the mass
Answer:
total mass is 80
60% of 80 = 48
aka 24 (30%) x2
Write an equation for the line that goes through (-2,6) and is parallel to the line y=1/2x+9
Answer:
y = 1/2x + 7
Step-by-step explanation:
Parallel lines have the same slope.
Therefore the new equation will have a slope(m) = 1/2
Substitute m = 1/2 and point (-2, 6) into y = mx + b to solve for "b"
y = mx + b
6 = 1/2(-2) + b
6 = -1 + b
7 = b
The new equation: y = mx + b
y = 1/2x + 7
(12 points) The product of 2 consecutive odd integers is 399. What are the integers?
Let's assume the first odd integer is x. Since the next odd integer would be consecutive, we can represent it as x + 2.
According to the problem, the product of these two consecutive odd integers is 399:
x * (x + 2) = 399
Expanding the equation:
x^2 + 2x = 399
Rearranging the equation into a quadratic form:
x^2 + 2x - 399 = 0
To solve this quadratic equation, we can either factor it or use the quadratic formula. Let's use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 1, b = 2, and c = -399.
x = (-2 ± √(2^2 - 4 * 1 * -399)) / (2 * 1)
Simplifying:
x = (-2 ± √(4 + 1596)) / 2
x = (-2 ± √1600) / 2
x = (-2 ± 40) / 2
Now, we can calculate the two possible values for x:
x = (-2 + 40) / 2 = 38 / 2 = 19
x = (-2 - 40) / 2 = -42 / 2 = -21
Since we are looking for consecutive odd integers, we take the positive value of x, which is 19. The next consecutive odd integer would be 19 + 2 = 21.
Therefore, the two consecutive odd integers whose product is 399 are 19 and 21.
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I need help with this
(This is 8th grade math btw)
Answer:
Just do 12x+7 and 5x-1 divide that answer by 57 that seems easy and i am in 6th grade
Step-by-step explanation:
if this is not right i dont know what is
Answer:
Angle WST = 91°
Step-by-step explanation:
The first step in this situation is to find Angle TSU. Then find x, which is 7, which can be put into the equation shown for Angle WST.
pls help asap
Twenty-seven minus 3/2 of a number (x) is not more than 36. What is the number? A. x > 42 B. x ≥ -6 C. x < 3 D. x ≤ -6
Answer: B.) x ≥ -6
Step-by-step explanation:
minimize f(x) = |x+3| + x^3 S.t. x sum [-2, 6]
Minimization of f(x) = |x+3| + x^3 at the endpoints (-2 and 6) the minimum value of the function is approximately 3.84, which occurs at x= \sqrt{1/3}
within the given interval.
To minimize the function subject to the constraint f(x) = |x+3| + x^3 that x lies in the interval [-2, 6], we need to find the value of x that minimizes f(x) within that interval.
First, let's analyze the function f(x). The absolute value term |x+3| can be rewritten as:
|x+3| =
x+3 if x+3 >= 0
-(x+3) if x+3 < 0
Since the interval [-2, 6] includes both positive and negative values of x+3, we need to consider both cases.
Case 1: x+3 >= 0
In this case, f(x) = (x+3) + x^3 = 2x + x^3 + 3
Case 2: x+3 < 0
In this case, f(x) = -(x+3) + x^3 = -2x + x^3 - 3
Now, we can find the minimum of f(x) within the given interval by evaluating the function at the endpoints (-2 and 6) and at any critical points within the interval.
Calculating the values of f(x) at x = -2, 6, and the critical points, we can determine the minimum value of f(x) and the corresponding value of x.
Since the equation involves both absolute value and a cubic term, it is not possible to find a closed-form solution or an exact minimum value without numerical methods or approximation techniques.
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Which of the following angles are supplementary to _1?
Plsss Help
find an equation of the curve that passes through the point (0, 1) and whose slope at (x, y) is 5xy. (note: start your answer with y
The equation of the curve that passes through the point (0, 1) and has a slope of 5xy at any point (x, y) is y = (5/2) * x^2y + 1. This equation represents a curve where the y-coordinate is a function of the x-coordinate, satisfying the conditions.
To determine an equation of the curve that satisfies the conditions, we can integrate the slope function with respect to x to obtain the equation of the curve. Let's proceed with the calculations:
We have:
Point: (0, 1)
Slope: 5xy
We can start by integrating the slope function to find the equation of the curve:
∫(dy/dx) dx = ∫(5xy) dx
Integrating both sides:
∫dy = ∫(5xy) dx
Integrating with respect to y on the left side gives us:
y = ∫(5xy) dx
To solve this integral, we treat y as a constant and integrate with respect to x:
y = 5∫(xy) dx
Using the power rule of integration, where the integral of x^n dx is (1/(n+1)) * x^(n+1), we integrate x with respect to x and get:
y = 5 * (1/2) * x^2y + C
Applying the initial condition (0, 1), we substitute x = 0 and y = 1 into the equation to find the value of the constant C:
1 = 5 * (1/2) * (0)^2 * 1 + C
1 = C
Therefore, the equation of the curve that passes through the point (0, 1) and has a slope of 5xy at any point (x, y) is:
y = 5 * (1/2) * x^2y + 1
Simplifying further, we have:
y = (5/2) * x^2y + 1
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list from least to greatest
Kennedy walks 2miles in 15 minutes she want to walk 3 more miles at the rate of speed. Which equation represents how many minutes it would take her to walk 5 miled
Answer:
We know that the equation for the speed is:
Speed = Distance/time.
First, we know that he walks 2 miles in 15 minutes.
distance = 2miles
time = 15 minutes
Then his speed in that interval is:
Speed = (2 mi)/(15 min) = (2/15) miles per minute.
Now, at this same speed, he wants to walk 3 more miles. And we want to find the equation that represents how much time she needs to walk 5 miles (the 2 first miles plus the other 3 miles)
We use again the equation:
Speed = Distance/Time
But we isolate Time, to get:
Time = Distance/Speed
Where:
Distance = 5 miles
Speed = (2/15) miles per min
Time = (5 miles)/((2/15) miles per min) = 37.5 minutes
She needs 37.5 minutes to walk the 5 miles.
Write rhe set of decimals in order from least to greatest. A) 9.3,3.09,3.9,3.011
Answer:
The digits arranged in order from least to largest is 3.011, 3.09, 3.9, 9.3
Step-by-step explanation:
The arrangement of decimals in order from smallest to largest can be done by taking note of the digit in the unit portion, the tenths, hundredths and thousandths.
The numbers are;
9.3
3.09
3.9
3.011
The largest number is the 9.3
Of the three numbers with 3 as unit, the lowest hundredths is 0.011, therefore, we have;
Therefore, the least (lowest) number = 3.011
The next is the 3.09 as 0.09 is larger than 0.011
Then the second number is 3.9
The digits arranged in order from least to largest is then 3.011, 3.09, 3.9, 9.3.
I don’t know the answer and I’m doing a text I need help!
Answer:
your answer will be A
Step-by-step explanation:
^_^
A dinner cost $28.50 and a 15% tip was added, how much was your bill?
(SHOW ALL WORK)
Find the volume of this triangular prism.
Be sure to include the correct unit in your answer.
Answer:
189in²
Step-by-step explanation:
first you multiple the triangle width(6) time the triangle height(7).
Then you divide that by 2
and times that times the prism length(9)
Written as the product of its prime factors, 2250=2x3²x5³. Two integers, A and B, can be written as products of prime factors. A=2xpxq¹ B=2xp² xq² The lowest common multiple (LCM) of A and B is 2250. Write down the values of p, q and r.
The values of p, q, and r are p = 2, q = 5, and r = 3, respectively.
Given that the lowest common multiple (LCM) of A and B is 2250, and the prime factorization of A is A = 2 × p × q¹, and the prime factorization of B is B = 2 × p² × q², we can compare the prime factorizations to determine the values of p, q, and r.
From the prime factorization of 2250 (2 × 3² × 5³), we can observe the following:
The prime factor 2 appears in both A and B.
The prime factor 3 appears in A.
The prime factor 5 appears in A.
Comparing this with the prime factorizations of A and B, we can deduce the following:
The prime factor p appears in both A and B, as it is present in the common factors 2 × p.
The prime factor q appears in both A and B, as it is present in the common factors q¹ × q² = q³.
From the above analysis, we can conclude:
p = 2
q = 5
r = 3.
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in a one-tailed hypothesis test (lower tail), the z test statistic is determined to be -1.9. the p-value for this test is
The p-value for this z test statistic is equal to 0.0287.
What is a null hypothesis?A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.
How to calculate value of the z test statistic?The z test statistic can be calculated by using this formula:
\(t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }\)
Where:
x represents the sample mean.μ represents the mean.σ represents the standard deviation.n represents the number of hours.In this scenario, the z test statistic for a one-tailed hypothesis test (lower tail) is equal to -1.9. Therefore, by using a t-distribution and z-score calculator for a normal distribution, the p-value for this test is given by:
P-value = P(t > -1.9)
P-value = 0.0287.
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Choose the limit to which L'Hôpital's rule may be applied:
a. lim x approaches 0 (1/x)
b. lim x approaches 0 ((2x^2) -1)/3x-1
c. lim x approaches 0 (1-cosx)/x
d. lim x approaches 0 (cos2x)/2
which one is right?
The solution is Option C.
The L'Hopital's rule is applied to the equation lim x approaches 0 (1-cosx)/x
What is L'Hopital's rule?L'Hopital's rule then states that the slope of the curve when t = c is the limit of the slope of the tangent to the curve as the curve approaches the origin, provided that this is defined. The limit of a quotient of functions (i.e., an algebraic fraction) is equal to the limit of their derivatives.The tangent to the curve at the point [g(t), f(t)] is given by [g′(t), f′(t)]
And , lim x approches c [ f ( x ) / g ( x ) ] = lim x approches c [ f' ( x ) / g' ( x ) ]
Given data ,
Let the equation be represented as A
Now , the value of A is
a)
The equation is A = lim x approaches 0 (1/x)
On simplifying the equation , we get
The limit diverges as the function diverges and limit does not exist
And , lim x approaches 0₊ (1/x) ≠ lim x approaches 0₋ (1/x) = ∞
b)
The equation is A = lim x approaches 0 ( 2x² - 1 ) / ( 3x - 1 )
On simplifying the equation , we get
when x = 0 ,
Substitute the value of x = 0 in the limit , we get
A = ( 2 ( 0 )² - 1 ) / ( 3 ( 0 ) - 1 )
A = ( 0 - 1 ) / ( 0 - 1 )
A = 1
c)
The equation is A = lim x approaches 0 ( 1 - cosx ) / x
On simplifying the equation , we get
Applying L'Hopital's rule , we get
lim x approches c [ f ( x ) / g ( x ) ] = lim x approches c [ f' ( x ) / g' ( x ) ]
f ( x ) = ( 1 - cos x )
g ( x ) = x
f' ( x ) = sin x
g' ( x ) = 1
So ,
lim x approches 0 [ f' ( x ) / g' ( x ) ] = lim x approches 0 ( sin x / 1 )
when x = 0
sin ( 0 ) = 0
Therefore , the value of lim x approaches 0 (1-cosx)/x = 0
d)
The equation is A = lim x approaches 0 ( cos 2x ) / 2
On simplifying the equation , we get
when x = 0 ,
A = cos ( 2 ( 0 ) / 2
A = cos ( 0 ) / 2
A = 1/2
Hence , the L'Hopital's rule is applied to lim x approaches 0 ( 1 - cosx ) / x
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Kevin is 4 times as old as Daniel and Kevin is
also 6 years older than Daniel
Step-by-step explanation:
let kevein be x and daniel be y
x=4y (equation i)
x=6+y(equationii)
putting the value of x in equationii
4y=6+y
3x=6
x=2
Which pair of triangles can be proven congruent by SAS?
Answer:
i don't know
Step-by-step explanation:
i am lower grade srry
What is the value of a 2 + 3 b + c − 2 d , w h e n a = 3 , b = 8 , c = 2 , a n d d = 5 ?
Answer:
Step-by-step explanation:
3*2+3*8+2-2*5=6+24-10+2=22