The work done against friction as the mass slides is 8 J.
The given parameters:
sliding mass, m = 5.0 kgdistance traveled by the mass, s = 9.0 mheight of incline, h = 2.0 mtime of motion, t = 3.0 skinetic energy of the object, K.E = 90 JThe work done against friction as the mass slides can be determined by applying work-energy theorem.
\(\Delta E= W\\\\P.E - K.E = W\)
the change in mechanical energy of the sliding mass, is equal to energy lost to friction.
\(W = P.E - K.E\\\\W = mgh - K.E\\\\W = (5 \times 9.8 \times 2) - 90\\\\W = 98 - 90\\\\W = 8 \ J\)
Thus, the work done against friction as the mass slides is 8 J.
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An object that can push
or pull on iron without
touching it is called a:
Answer:
A magnet
Explanation:
is an object that can attract some metals like iron
Describe three tasks performed by a sound engineering technician.
Answer:
Operate, monitor, and adjust audio, video, lighting, and broadcast equipment to ensure consistent quality. Set up and take down equipment for events and live performances.
Explain what radiation is in 1-2 paragraphs please, thank you
Answer:
Explanation:
Radiation is often categorized as either ionizing or non-ionizing depending on the energy of the radiated particles. Ionizing radiation carries more than 10 eV, which is enough to ionize atoms and molecules and break chemical bonds. This is an important distinction due to the large difference in harmfulness to living organisms. A common source of ionizing radiation is radioactive materials that emit α, β, or γ radiation, consisting of helium nuclei, electrons or positrons, and photons, respectively. Other sources include X-rays from medical radiography examinations and muons, mesons, positrons, neutrons and other particles that constitute the secondary cosmic rays that are produced after primary cosmic rays interact with Earth's atmosphere.
imagine rigel, a star, rises at 6pm today. what time will it rise tomorrow and a month from now?
Assuming a constant rate of Earth's rotation and neglecting any axial tilt effects, Rigel, a star, would rise approximately 4 minutes earlier each day. Therefore, if Rigel rises at 6 PM today, it would rise at around 5:56 PM tomorrow. In one month, comprising roughly 30 days, Rigel would rise approximately 2 hours earlier, at around 4 PM. These calculations are based on the assumption that the observer's location on Earth remains constant, and no other factors, such as atmospheric conditions or the star's own motion, significantly affect the timing of Rigel's rise.
The Earth rotates approximately once every 24 hours, causing the stars to appear to rise and set each day. This rotation rate is relatively constant over short timescales. Therefore, if a star rises at a specific time on a given day, it will rise approximately 4 minutes earlier the following day, as 24 hours divided by 60 minutes gives an average of 4 minutes per minute of Earth rotation. Multiplying this by the number of days in a month (30) results in approximately 2 hours earlier for the star's rise time.
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hellllp me please anyone help Light travels from a region of air into a region of air, making an angle of incidence of 60 degrees. Which of the following best describes the path of the light as it moves into the air? A) The light will bend toward the normal B) The light will bend away from the normal C)The light will continue without bending D)The light will move in some manner not determined by the information here.
Answer:
(B)
Explanation:
Because what ever angle the surface is, the light will reflect of of it perpendicular.
A car travels a distance of 150 m in the direction of a constant force of 50 N. The work done on the car is
Answer:
the work done on the car is 7,500 J.
Explanation:
Given;
distance traveled by the car, d = 150 m
applied force, F = 50 N
The work done on the car is calculated as;
W = F x d
W = 50 N x 150 m
W = 7,500 J
Therefore, the work done on the car is 7,500 J.
How many types of joints are there in the human body? A. 4 B. 2 C. 12 D. 6
Answer:
there are six types of joints in the human body
Answer: The answer is D. 6
Explanation: Learned in health class a while ago.
Please Help Quick ASAP Hurry This is Physical Science
Which statements best describe magnetic fields?
A. Magnetic fields need a conductor.
B. Magnetic fields must have only positive charges.
C. Magnetic fields have north and south magnetic poles.
D. Magnetic fields are always found in insulators.
Answer:
Think it is C
Explanation:
Not sure!!!
a triangular hiking trail is being planned. at an average walking speed of 2 m/s, how many minutes will it take a hiker to make a complete circuit around the trail? round to the nearest minute
The time taken by hiker is L/60 minutes (L = length of trail)
However, we can show the steps to find the answer if we have the length of the trail.
Let's assume that the length of the hiking trail is L meters. To make a complete circuit around the trail, the hiker needs to cover a distance of 2L meters (going up and coming back down).
If the hiker's average walking speed is 2 m/s, then the time taken to cover a distance of 2L meters can be calculated using the formula:time = distance / speed
Plugging in the values, we get:time = (2L meters) / (2 m/s) = L seconds
To convert seconds to minutes, we divide by 60:time in minutes = L seconds / 60
If we knew the length of the trail in meters, we could calculate the time taken in minutes using this formula.
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When you have enough resources for one or two (or more) hosts failovers, but still, you get
If you have enough resources for one or two (or more) hosts failovers, you can build a highly available system by setting up multiple servers and configuring them to act as a cluster.
This will allow the system to keep running even if one of the hosts fails. You can also configure a load balancing system to distribute traffic across the cluster for better performance. You can also use a system like keepalived to manage the failover of IP addresses and other resources. Additionally, you can use a system like Pacemaker or Corosync to manage the cluster and control the failover process.
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Body of an earthworm is divided into rings/ metamers. It moves with the help of two muscles: longitudinal and circular muscles. Which of the following activity is done by earthworm during its movement?
(OPTIONs)
→ Swallow the soil it moves
→ Grip the soil firmly at one end
→ Make the soil moist and slippery
→ Break the soil into smaller particles
Swallow the soil it moves and Break the soil into smaller particles.
What is movement in earthworm?They don't have bones or other fixed features that might restrict their movement. The body of an earthworm is segmented. Earthworms use the setae, or tiny bristles, that are present on each segment, to assist them hold the dirt as they travel.
An earthworm uses two distinct sets of muscles to move. Longitudinal muscles run the length of the body, while circular muscles loop around each segment. The earthworm extends as a result of the circular muscles contracting, growing longer and thinner.
The earthworm embeds the front of its body in the dirt using its setae. The earthworm now contracts its longitudinal muscles, either making it shorter and wider.
Therefore, Swallow the soil it moves and Break the soil into smaller particles.
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A car, of mass 2.1 X 10^3 kg, travels in the horizontal plane around an unbanked curve of a radius of 275 m at a speed of 26 m/s, without sliding.
a) Determine the minimum coefficient of static friction between the tires and the road.
b) How would your answer in part a) be affected if the mass of the vehicle were greater because of the presence of heavy cargo?
c) How would your answer in part a) be affected if the curve were sharper, i.e., if its radius were smaller?
Answer:
Centripetal force is perpendicular to velocity and causes uniform circular motion. ... force exerted on a 900.0-kg car that negotiates a 500.0-m radius curve at 25.00 m/s. ... A car moving at 96.8 km/h travels around a circular curve of radius 182.9 m ... Because the car does not leave the surface of the road, the net vertical force ...
Explanation:
HE monda
question 1: Ethanol has a specific latent heat of evaporation of 855kJ/kg. Calculate the energy required to boil 0.60kg of ethanol.
question 2:A piece of gold has a volume of 2.00 x 10-5m3 and a mass of 0.386kh. Calculate the density of gold
1. The energy required is 513 kJ to boil 0.60kg of ethanol.
2. The density of gold is 19,300 kg/\(m^3\) if it has a volume of 2.00 x \(10^-^5\)\(m^3\) and a mass of 0.386kh.
Question 1: The energy required to boil a substance can be calculated by multiplying the mass of the substance by its specific latent heat of evaporation. In this case, the specific latent heat of evaporation for ethanol is given as 855 kJ/kg, and the mass of ethanol to be boiled is 0.60 kg.
Energy required = Mass × Specific latent heat of evaporation
Energy required = 0.60 kg × 855 kJ/kg
Energy required = 513 kJ
Therefore, the energy required to boil 0.60 kg of ethanol is 513 kJ.
Question 2: The density of a substance is calculated by dividing its mass by its volume. In this case, the volume of the gold is given as 2.00 x\(10^-^5\) \(m^3\) and the mass of the gold is 0.386 kg.
Density = Mass / Volume
Density = 0.386 kg / 2.00 x \(10^-^5\) \(m^3\)
Density = 19300 kg/\(m^3\)
Therefore, the density of gold is 19300 kg/\(m^3\).
In summary, the energy required to boil 0.60 kg of ethanol is 513 kJ, and the density of gold is 19300 kg/m^3.
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A wave is traveling at the speed of light. If it has a frequency of 4 x 10^15 Hz, what is its wavelength?
Answer:
7.5x10-^8m
Explanation:
the formulae is v=fh ,where f is frequency
h is wavelength
hence wavelength=v/f
since the speed of light is 3x10^8
then the wavelength =3 x 10^8/4 x 10^15
=7.5x10^-8m
a ball is tossed up into the air, reaches its highest point and returns to its original position. which of the following is true about the balls velocity and acceleration at its highest point? IF YOU CAN CAN YOU PLS EXPLAIN
a) it’s velocity and acceleration are both zero
b) it’s velocity is up and non zero constant and acceleration is zero
c) it’s velocity is down and non zero constant and acceleration is zero
d) it’s velocity is zero and acceleration is up and non zero constant
e) it’s velocity is zero and acceleration is down and non constant zero
Answer:
) At the top v =0 and there will be a acceleration due to gravity (g) acting downward.
an electric lamp is marked 240 volt 60 watt what is the resistor when it is operated at the correct voltage.b A. 1/960. B. 1/4 C. 4. D. 960. E. 14.400
The resistor of the electric lamp is marked at 240 volts and 60 watts is 960 ohms. Thus, option D is correct.
The resistance is a property that gives obstruction the current flow. It blocks the current flow in the circuit. The unit of resistance is the ohm.
From the given,
The voltage of the electric lamp (E) = 240 volt
Power in the circuit (P) = 60 watt
Resistance =?
Power (P) = E² / R
R = E²/P
= 240×240/60
= 960 Ω
The resistance of the electric lamp with a given voltage and power is 960 Ω. Thus, the ideal solution is D.
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At Earth's surface, a flux of about 70 billion solar neutrinos flow through every square centimeter every second. Using that information and a version of the L = 4πr2 F luminosity-flux equation, calculate how many neutrinos are produced in the Sun every second.
Approximately 5.95 x \(10^1^8\)neutrinos are produced in the Sun every second.
What is the rate of neutrino production in the Sun per second?The number of neutrinos produced in the Sun every second can calculated by using luminosity-flux equation:
L = 4πr²F
where L is the luminosity, r is the distance from the source (in this case, the Sun), and F is the flux.
Given that the flux at Earth's surface is approximately 70 billion solar neutrinos per square centimeter per second, we can substitute this value into the equation:
L = 4π(1 AU)²(70 billion neutrinos/cm²/s)
Note that 1 astronomical unit (AU) is the average distance from the Earth to the Sun, which is approximately 149.6 million kilometers or 93 million miles.
Now, we need to convert the area from square centimeters to square meters, which is 1 cm²= 0.0001 m²:
L = 4π(1 AU)²(70 billion neutrinos/cm²/s)(0.0001 m²/cm²)
Simplifying the equation:
L = 4π(1 AU)²(7 million neutrinos/m²/s)
Now we can calculate the number of neutrinos produced in the Sun every second by multiplying the luminosity (L) of the Sun by the flux (F) at Earth's surface:
Number of neutrinos produced in the Sun per second = L * F
Number of neutrinos produced in the Sun per second = 4π(1 AU)²(7 million neutrinos/m²/s) * (1.496 x \(10^1^1\)meters)²
Calculating the expression:
Number of neutrinos produced in the Sun per second ≈ 5.95 x \(10^1^8\)neutrinos
Therefore, approximately 5.95 x \(10^1^8\) neutrinos are produced in the Sun every second.
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Which one!!!!!!!!!!!!
Answer:
3N to the right
Explanation:
can someone help me for this question?
Answer:
A, 0.050 Hz
Explanation:
1) Frequency = speed divided by wavelength
time is 2* 60 = 120 seconds
distance = 6 wave lengths
speed = distance divided by time
speed = 6 wave lengths divided by 120
Hope this helps!
PLEASE ANSWER!! WILL GIVE A LOT POINTS AND MARK AS BRAINLIESY IF YOU ANSWER ALL QUESTIONS!!!!
LAB: MOTION
1. What is the purpose of the lab, the importance of the topic, and the question you are trying to answer?
2. What is your hypothesis (or hypotheses) for this experiment?
3. What methods are you using to test this (or each) hypothesis?
4. Locate the data and observations collected in your lab guide. Eat are the key results? How would you vest summarize the data to relate your findings?
5.Do you have quantitative data (numerical results or calculations)? Do you have qualitative data (written observations and descriptions)? How can you recognize this data for your report?
6. What do the key results indicate?
7. If you constructed graphs, what trends do they indicate in your data?
8. Were there any problems with the experiment or the methods? Did you have any surprising results?
9. What do the results tell you about your hypothesis(es)?
10. How do the data support your claim above?
11. If you could repeat the experiment and make it better, what would you do differently and why?
hm..
Explanation:
this would be quite hard to answer because no one has actually experienced the lab so maybe I can help better if you give more information on the lab you did:)
Answer: To figure the motion of the object or thing and the purpose i to learn off it
Explanation:
for 1.
A string of 35 miniature decorative lights is wired in series. If it draws
0.20 A of current when it is connected to a 120.0 V emf source, what is the
resistance of each miniature bulb?
The resistance of each miniature bulb is 17.14 \(\Omega\).
According to the question:
35 miniature decorative lights are wires in series
Current drawn(I) = 0.20 A
e.m.f(Volatge) = 120.0 V
To find:
Resistance(r) of each bulb
We know that by Ohm's law:
R = Voltage/current
R = Total resistance of the circuit
By substituting the values given to us in the above equation we can find the total resistance of the circuit.
R = 120.0/0.20
R = 600 \(\Omega\)
This is the total resistance of the circuit.
Since the light bulbs are connected in series the total resistance of the bulbs is the sum of the individual resistances of the bulbs.
⇒ R = Number of light bulbs × resistance of each bulb(r)
r = R/(Number of light bulbs)
r = 600/35
r = 17.14 \(\Omega\)
Therefore, the resistance of each individual light bulb is 17.14 \(\Omega\).
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Using the data in the Reagents and Properties table below, please calculate the theoretical yield of
methoxybenzaldehyde in grams, assuming you start with 1.50 g of the alcohol. (Assume the
alcohol is the limiting reactant). Please, show your work.
substance quantity molar mass (g/mole) bp (°C)
bleach (NaOCl) 20 mL
dichloromethane 18 mL 84.93 40°C
ethyl acetate 40 mL 88.11 76—77°C
magnesium sulfate,
anhydrous 1 g 120.37
methoxybenzaldehyde
(reaction product) 136.15 248°C
p-methoxybenzyl alcohol 1.5 g 138.15
sodium chloride,
saturated solution 20—30 mL
sodium hydroxide,5% 20 mL
tetrabutylammonium
hydrogen sulfate 0.15—0.2 g 339.54
To calculate the theoretical yield of methoxy benzaldehyde, we need to find the amount of p-methoxybenzyl alcohol consumed in the reaction.
Since p-methoxybenzyl alcohol is the limiting reactant, the amount of methoxy benzaldehyde produced will be equal to the amount of p-methoxybenzyl alcohol used in the reaction.
1.5 g of p-methoxybenzyl alcohol has a molar mass of 138.15 g/mol, so its moles can be calculated as:
moles of p-methoxybenzyl alcohol = 1.5 g / 138.15 g/mol = 0.0108 mol
The theoretical yield of methoxy benzaldehyde can be calculated as:
theoretical yield (g) = moles of p-methoxybenzyl alcohol x molar mass of methoxy benzaldehyde (g/mol) = 0.0108 mol x 136.15 g/mol = 1.47 g
So, the theoretical yield of methoxy benzaldehyde is 1.47 g.
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A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 96 ft/s. How high will it go? Use -32 ft/s? forthe acceleration caused by gravity. Ignore air resistance.
Given,
The initial height of the soccer ball, h₁=6 ft
The initial velocity of the ball, u=96 ft/s
The acceleration due to gravity, g=-32 ft/s
When the ball reaches the maximum height, its velocity will reduce to zero.
Thus the velocity of the ball when it is at its maximum height is v=0 ft/s
From the equation of motion,
\(v^2-u^2=2gh_2\)Where h₂ is the total height covered by the ball from its initial height to reach its maximum height.
On substituting the known values,
\(\begin{gathered} 0-96^2=2\times-32\times h_2 \\ \Rightarrow h_2=\frac{-96^2}{2\times-32} \\ =144\text{ ft} \end{gathered}\)Thus the maximum height reached by the ball is,
\(\begin{gathered} H=h_1+h_2 \\ =6+144 \\ =150\text{ ft} \end{gathered}\)Thus the maximum height reached by the ball is 150 ft.
What are the factors that change the pattern observed on a screen during Young’s double-slit experiment?
The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.
The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:
1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.
2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.
3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.
4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.
5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.
When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.
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The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy. For example, if your automobile gets 30 miles per gallon at 55mph, the fuel consumption is 21 miles per gallon at 70mph. If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, what is the extra cost of fuel if gasoline costs $3.26 per gallon? Your car gets 30 miles per gallon (mpg) at 63mph.
The extra cost of fuel for driving 83 mph instead of 73 mph is $3.7671.
The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy.
If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, then the extra cost of the fuel is calculated as:
* **Fuel consumption at 83 mph:** 30 mpg * (1 - 2% * (83 - 55)) = 27.6 mpg
* **Fuel consumption at 73 mph:** 30 mpg * (1 - 2% * (73 - 55)) = 29 mpg
* **Extra fuel used:** 400 miles / 27.6 mpg - 400 miles / 29 mpg = 2.4 gallons
* **Extra cost of fuel:** $3.26/gallon * 2.4 gallons = $3.7671
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A student walks 3 km in 30 minutes. What is the student's average speed in km/h?
Answer:
6km/hr
Explanation:
3km = 30mins
x(km) = 1hr
1hr = 60 x 60 = 3600secs
30min = 30 x 60 = 1800secs
3 x 3,600/x X 1,800
x = 10,800/1,800
x = 6km/hr
To solve the problem we must know about speed, distance, and time.
What is the relationship between Speed, distance, and Time?
We know that speed, distance, and time all are in a relationship with each other. this relationship can be given as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
Given to us
A student walks 3 km in 30 minutes.
We know distance can be written as the product of speed and time, therefore,
\(\rm Distance = \rm speed \times \rm Time\)
Substituting the values we get,
\(\rm 3\ km = Speed \times 0.5\ hour\)
\(\rm speed = \dfrac{3\ km}{0.5\ hour}\)
speed = 15 km\h
Hence, the speed of the student is 15 km\hour.
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a farsighted woman has a near point of 70.0 cm. what power contact lens (when on the eye) will allow her to see objects 27.3 cm away clearly?
A contact lens with a +3.014 diopters power will enable a farsighted woman with a near point of 70.0 cm to see objects clearly at a distance of 27.3 cm.
We have do = 23cm and di = -75cm
So 1/f = 1/do + 1/di = 1/23 + 1/(-75) = .03014
So f = 1/.03014=33.17
So power = 1/0.3317 = +3.014Diopters (converging lens)
In optics, a diopter represents the magnifying power of a lens or lens system. The power of a lens is proportional to unity (one) divided by the focal length (see lens), so the power of a lens in diopters is mathematically equal to 1 meter is divided by the focal length. A healthy human eye can concentrate on an object or picture that is 1/40 of a meter away with an optical power of roughly 40 diopters. A average young person's eye has an additional 20 diopters of adjustment.
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no object can travel faster than the speed of light, so it would appear evident that the uncertainty in the speed of any object is at most . (a) what is the minimum uncertainty in the position of an electron, given that we know nothing about its speed except that it is slower than the speed of light?
The minimum uncertainty in the position of an electron is given by Δx ≥ h/4πc. Note that this calculation is a simplified representation of the uncertainty principle and does not take into account other factors that may affect the electron's position uncertainty.
The uncertainty principle, proposed by Werner Heisenberg, states that there is a fundamental limit to the precision with which certain pairs of physical properties of a particle can be known simultaneously. One such pair is the position and momentum (or speed) of an object.
According to the principle, if we have perfect knowledge of an object's speed, then the uncertainty in its position is at most zero. However, if we have no information about the speed of an object except that it is slower than the speed of light, we can determine the minimum uncertainty in its position.
The minimum uncertainty in position (Δx) can be calculated using the uncertainty principle equation:
Δx * Δp ≥ h/4π
where, Δp represents the uncertainty in momentum.
Since we know nothing about the electron's speed except that it is slower than the speed of light, we can consider its momentum to be very small. As a result, we can assume that Δp is at most equal to a small value, such as Planck's constant (h) divided by the speed of light (c).
Therefore, the minimum uncertainty in the position of an electron is given by Δx ≥ h/4πc.
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A tennis ball and a solid steel ball of the same diameter are dropped at the same time. Ignoring the air resistance effects, which ball has the greatest acceleration?
why are the most common stars among the most difficult to observe
The most common stars, known as red dwarfs, are difficult to observe because of their low luminosity, small size, and cool surface temperatures.
The most common stars in our universe are red dwarfs, which are small and dim compared to other types of stars. They emit most of their light in the infrared spectrum, making them difficult to observe with visible-light telescopes. Additionally, these stars are often surrounded by dust and gas that further obstructs our view of them. Red dwarfs also have long lifespans, so their evolution and behavior occur over much longer timescales than larger, more luminous stars. All of these factors make it challenging to study red dwarfs and understand their properties, despite their abundance in the universe.
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