The diameter of a circle is 6 m. What is the area of the circle to the nearest square meter?

Answer:

a) 201s / 1000

b) 7s / 125 + s / 10 + 7s / 5 + s / 30 + s / 2

Step-by-step explanation:

Total de miembros de la familia = 4

Ganancia de la madre = s / 1000 por mes

Ganancia del papa = s / 40 por semana

Ganancia por venta de huevos = s / 10

Ganancia total por mes = s / 1000 + s / 40 * 4 + s / 10 = s / 1000 + s / 10 + s / 10 = 201s / 1000  

Gasto-

Servicio - S / 250 * 4 = 4s / 250

ropa - 4S / 40

servicios de agua - 4S / 30

Electricidad - 4S / 100

paquete de teléfono, internet y cable - S / 120

gas - S / 40

alimento para pollos - S / 15 cada mes

higiene personal 4S / 20

4 mascarillas de tela - 4S / 10

4 litros de alcohol - 4 S / 8

3 litros de lejía - 3S / 5

Gastos totales = 2s / 125 + s / 10 + 2s / 15 + s / 25 + s / 120 + s / 40 + s / 15 + s / 5 + 2s / 5 + s / 2 + 3S / 5

Gasto total = 7s / 125 + s / 10 + 7s / 5 + s / 30 + s / 2

The percentage of the original area of wetlands currently left in the United States is approximately 50%. So, the correct

option is 50% (option 3).

Percentages are a way of expressing a proportion or a fraction as a part of 100. It is denoted by the symbol "%".

According to the United States Environmental Protection Agency (EPA), it is estimated that about 50% of the original

wetlands in the contiguous United States have been lost since the 1600s due to human activities such as agriculture,

development, and urbanization. Therefore, the correct answer to the question is 50%.

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The percentage of the original area of wetlands currently left in the United States is approximately 50%.

Wetlands are regions of land where the soil is continually or intermittently soaked with water. Wetlands have a particular hydrology, soil, and vegetation mix that results in specialised ecosystems that offer a variety of ecological functions.

There are many different types of habitats where wetlands can be found, such as coastal locations, interior regions, and high-altitude mountain regions. They come in a variety of shapes, such as marshes, swamps, bogs, fens, and estuaries, and can be freshwater, brackish, or saline.

Wetlands are significant for several reasons. For species, such as migrating birds, amphibians, and fish, they offer crucial habitats. They also aid in removing contaminants from water, lessen the effects of flooding, and give people access to recreational activities. Wetlands are crucial for carbon sequestration as well.
Based on the information provided, the question is asking for the approximate percentage of the original area of wetlands currently left in the United States. The answer is approximately 50%.

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Answer:

44.821869662

Step-by-step explanation:

The integral evaluates to `4z`.

Given that region D is bounded by the line y=1 and the parabola y²=22+6 (or y²=6x). We need to evaluate `∬ D f(x,y) dA`, where `f(x,y)=zy`. The region D can be sketched as follows: Find the bounds of integration: Since the integral is from left to right, the variable y goes from y=1 to y=±sqrt(6x).

The variable x goes from x=0 to x=4. So, the limits of integration are: `0 ≤ x ≤ 4, 1 ≤ y ≤ √(6x)`Using these bounds of integration, we get the following double integral:`∬ D f(x,y) dA = ∫₀⁴ ∫₁^√(6x) zy dy dx`Evaluating the inner integral:`∫₁^√(6x) zy dy = [z(y²/2)]₁^√(6x) = z(3x-x²/2)`Substituting this in the original integral,

we get:`∬ D f(x,y) dA = ∫₀⁴ z(3x-x²/2) dx`Evaluating the integral:`∫₀⁴ z(3x-x²/2) dx = z[3(x²/2)-x³/6]₀⁴= z(24/6) = 4z`Hence, `∬ D f(x,y) dA = 4z`.

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The percentage of sites with either purple loosestrife or common reed present is 67%.

Write down the formula to calculate the probability of the union (or) of two events:

P(A or B) = P(A) + P(B) - P(A and B)

This formula says that to find the probability of A or B occurring, you need to add the probability of A occurring, the probability of B occurring, and then subtract the probability of both A and B occurring at the same time.

This is because if you simply add the probabilities of A and B, you would be double-counting the cases where A and B both occur.

Identify the probabilities given in the problem statement:

P(Purple loosestrife) = 0.35

P(Common reed) = 0.55

P(Purple loosestrife and Common reed) = 0.23

Substitute the probabilities into the formula for P(A or B):

P(Purple loosestrife or Common reed) = P(Purple loosestrife) + P(Common reed) - P(Purple loosestrife and Common reed)

P(Purple loosestrife or Common reed) = 0.35 + 0.55 - 0.23

Simplify the expression:

P(Purple loosestrife or Common reed) = 0.67

Convert the probability to a percentage by multiplying by 100:

P(Purple loosestrife or Common reed) = 67%

Therefore, the percentage of sites with either purple loosestrife or common reed present is 67%.

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Answer:

108g

Explanation:

Weight of the atom of an element = 1.792x10-22 (Given)

Let the atomic mass of the atom be = x

x ms of the element contains Avogadro number of atoms = 6 × 10^23 atoms

Weight of one mole of atoms = atomic weight  

Where one mole = 6.022 × 10^23 atoms  

Weight of one atom = x/(6 × 10^23)

= 1.8 × 10^-22

Thus, the atomic weight will be -

x = 6 × 10^23 × 1.8 × 10^-22​ = 107.9 = 108 g

/mole

Therefore, the atomic mass of the element is 108 g/mole.

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Approximate sum of the lengths of the two sidewalks, shown as dotted lines in the figure of rectangle garden is 38.2 meters.

Pythagoras theorem says that in a right angle triangle the square of hypotenuse side is equal to the sum of square of other two legs of right angle triangle.

A 15-meter by 23-meter garden is divided into two sections. In this rectangle,

Here, a vertical line is drawn from the top to bottom side to split the shape into a square and a rectangle. The length of the left side of the square will be 15 long. Thus, the lenght of its diagonal is,

\(d_1=15\sqrt{2}\\d_1=21.213\rm\; m\)

The length of the sidewalk in smaller rectangle in the right side of figure is,

\(d_2=\sqrt{15^2+8^2}\\d_2=17\rm\; m\)

Sum of the lengths of the two sidewalks using the pythagoras theorem is,

\(S=21.2+17\\S=38.2\rm\;m\)

Thus, approximate sum of the lengths of the two sidewalks, shown as dotted lines in the figure of rectangle garden is 38.2 meters.

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Answer:

D 38.2

Step-by-step explanation:

E2020

Answer:

D is the answers for the question

Step-by-step explanation:

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The distance traveled to reach the boxcar is 54.4 m.

Part A: How long does it take him to catch up to the empty boxcar

A fugitive hops on a freight train that travels at a constant speed of 5.2 m/s, and just as an empty boxcar passes him, the fugitive starts from rest and accelerates to his maximum speed of 6.2 m/s, with an acceleration of a = 1.4 m/s2. We need to determine how long it would take him to catch up to the empty boxcar.

The distance traveled by the boxcar is equal to the distance traveled by the fugitive when he caught up with the boxcar. Therefore, we can use this equation:

distance = 1/2(a)t² + vt

where, v is the initial velocity, a is the acceleration, t is time, and distance is the distance traveled by the fugitive to catch up with the empty boxcar.

Substituting the given values:

v = 0 m/s (because he started from rest)

a = 1.4 m/s²t =  (what we are solving for)

distance = nee to find

We know that the boxcar has already traveled a certain distance before the fugitive starts accelerating. So the total distance traveled by the fugitive is the distance traveled by the boxcar plus the distance traveled by the fugitive after he started accelerating.

t = (6.2 m/s - 0 m/s)/1.4 m/s²t

 = 4.43 s (to two significant figures)

Therefore, it takes the fugitive 4.43 seconds to catch up with the empty boxcar.

Part B:

What is the distance traveled to reach the boxcar

To find the distance traveled by the fugitive, we use the same equation:

distance = 1/2(a)t² + vt

distance = 1/2(1.4 m/s²)(4.43 s)² + (5.2 m/s)(4.43 s)

distance = 54.4 m (to two significant figures)

The distance traveled to reach the boxcar is 54.4 m.

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96 inch

V

=

64

c

u

b

i

c

i

n

c

h

e

s

Let us suppose

a

is the side length of the given cube:

a

3

=

64

c

u

b

i

c

i

n

c

h

e

s

a

=

(

64

)

1

3

a

=

4

i

n

c

h

e

s

Now the surface area of the cube:

S

=

6

a

2

=

6

(

4

)

2

=

6

(

16

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=

96

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Answer:

Their is a different question in the pic then the writing?

a) Activity that should be crashed first to reduce the project duration by 1 day is B.

b) Activity that should be crashed next to reduce the project duration by one additional day is C.

c) Total cost of crashing the project by 2 days = $10,000.

To determine the activities that should be crashed first and next, we need to consider the critical path method (CPM). The critical path is the longest sequence of activities that determines the total project duration. Crashing activities on the critical path will reduce the project duration.

Let's calculate the project duration and costs for each activity:

Activity A:

Normal Time: 7 days

Crash Time: 6 days

Normal Cost: $5000

Total Cost with Crashing: $5600

Activity B:

Normal Time: 4 days

Crash Time: 2 days

Normal Cost: $1500

Total Cost with Crashing: $3400

Immediate Predecessor(s): A

Activity C:

Normal Time: 11 days

Crash Time: 9 days

Normal Cost: $4200

Total Cost with Crashing: $6600

Immediate Predecessor(s): B

To find the critical path, we add the normal times of each activity:

Critical Path: A -> B -> C

a) Activity that should be crashed first to reduce the project duration by 1 day:

Since the critical path includes activities A, B, and C, we need to identify which activity's crash time can reduce the project duration by 1 day. The activity that can achieve this is B since its crash time is 2 days compared to activity A's crash time of 6 days. Therefore, activity B should be crashed first.

b) Activity that should be crashed next to reduce the project duration by one additional day:

After crashing activity B, the project duration will be reduced by 1 day. To further reduce the duration by an additional day, we need to determine which activity's crash time can achieve this. The activity that can achieve this is C since its crash time is 9 days compared to activity A's crash time of 6 days. Therefore, activity C should be crashed next.

c) Total cost of crashing the project by 2 days:

The total cost of crashing the project by 2 days is the sum of the total costs for the crashed activities:

Total cost of crashing = Total cost of crashing activity B + Total cost of crashing activity C

                   = $3400 + $6600

                   = $10,000

Therefore, the total cost of crashing the project by 2 days is $10,000.

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Complete Question:

Three activities are candidates for crashing on a project network for a large computer installation (all are, of course, critical). Activity details are in the following table.

a) Activity that should be crashed first to reduce the project duration by 1 day is

b) Activity that should be crashed next to reduce the project duration by one additional day is

c) Total cost of crashing the project by 2 days =

The work best fits the art movement of abstract. Abstract art is characterized by the use of shapes, forms, colors, and gestural marks that are not meant to represent specific objects or subjects in a realistic manner.

It emphasizes the visual elements of art, such as line, color, and composition, and often focuses on expressing emotions or conveying abstract concepts. The work in question likely displays non-representational elements, with emphasis on the arrangement of shapes, colors, and forms to create a visual impact that is not tied to recognizable objects or scenes.

In the given work, the absence of identifiable objects or subjects suggests a departure from realistic representation. Instead, the emphasis is placed on the arrangement of abstract elements, such as bold colors, dynamic lines, and geometric shapes. These elements are likely employed to evoke emotions, convey concepts, or explore the purely visual aspects of art. The use of abstraction allows for subjective interpretation and encourages viewers to engage with the work on a more personal and imaginative level. Therefore, the work aligns most closely with the abstract art style or movement.

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To maximize profits, the firm should produce a quantity of goods x = 5 and y = 10, based on the cost function and price constraints.

To maximize profits, the firm needs to find the quantities of goods x and y that will yield the highest profit. The profit function can be defined as the revenue minus the cost. Revenue is calculated by multiplying the quantity of each good produced with their respective prices, while the cost function is given as C(x, y) = 10x + xy + 10y.

The firm is committed to delivering a total of 15 units, which can be expressed as x + y = 15. To determine the optimal production quantities, we need to maximize the profit function subject to this constraint.

By substituting the price expressions Ps = 50 - x + y and Py = 50 - x + y into the profit function, we obtain the profit equation. To find the maximum profit, we can take the partial derivatives of the profit equation with respect to x and y, set them equal to zero, and solve the resulting system of equations.

Solving the equations, we find that the optimal production quantities are x = 5 and y = 10, which maximize the firm's profits.

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Using the normal distribution, it is found that there is a 0.0013 = 0.13% probability that the mean weight of 25 pods of coffee is less than 42.035 grams.

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The parameters are given as follows:

\(\mu = 42.05, \sigma = 0.025, n = 25, s = \frac{0.025}{\sqrt{25}} = 0.005\)

The probability that the mean weight of 25 pods of coffee is less than 42.035 grams is the p-value of Z when X = 42.035, hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{42.035 - 42.05}{0.005}\)

Z = -3

Z = -3 has a p-value of 0.0013.

0.0013 = 0.13% probability that the mean weight of 25 pods of coffee is less than 42.035 grams.

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Answer:

put a dot on -5 on the y axis

Step-by-step explanation:

Answer:

It is a horizontal line across the y-axis, at the value of -five.

Step-by-step explanation:

Like this black line

Answer:

y = -3(x + 2)^2 + 10.

Step-by-step explanation:

y = –3x2 – 12x – 2

Divide first 2 terms by -3:

y = -3(x^2 + 4x) - 2            Now complete the square on x^2 + 4x:-

y = -3(x^2 + 4x + 4 - 4) - 2

y = -3[(x + 2)^2 - 4] - 2

y = -3(x + 2)^2 + 12 - 2

y = -3(x + 2)^2 + 10.

Inferential Statistics is discussed below.

We have the following statement -

Statistical techniques that allow us to study samples and then make generalizations about the populations from which they were selected.

We have to determine what kind of techniques are these.

It is a part of mathematics that deals with the collection, analysis, interpretation, and presentation of numerical data.

According to the question -

The techniques that allow us to study samples and then make generalizations about the populations from which they were selected are part of the inferential statistics.

Inferential statistics helps us to make predictions from the data described by descriptive statistics. It has two main areas -

1 -   Estimating Parameters

2 -  Hypothesis tests

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Therefore, the correct answer to the question "The following are ALL common quantitative forecasting models EXCEPT?" is B. Delphi Method, as it is not a mathematical model but rather a consensus-based method.

Quantitative forecasting models are statistical methods used to forecast future values or trends based on historical data, mathematical formulas, and other numerical data. These models are used to predict future demand, sales, production, inventory levels, and other quantitative variables. Some common quantitative forecasting models include time series analysis, regression analysis, exponential smoothing, and artificial neural networks. These models are useful for businesses and organizations to make informed decisions about their future operations and strategies.

Here,

Quantitative forecasting models are mathematical models that use historical data to predict future events or trends. There are several common types of quantitative forecasting models, including:

A. Simple Linear Regression: This model uses a linear equation to predict future values based on a single independent variable. It assumes a linear relationship between the independent and dependent variables.

B. Delphi Method: This model is a consensus-based forecasting method that uses expert opinions to make predictions. It involves a group of experts who provide their opinions on a given topic, which are then compiled and analyzed to make a forecast.

C. Exponential Smoothing: This model uses a weighted average of past observations to predict future values. It assigns more weight to recent observations and less weight to older observations.

D. Naïve Forecasting: This model predicts that future values will be equal to the most recent observed value. It is a simple and easy-to-use forecasting method, but it does not account for any trends or patterns in the data.

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Answer:

3/4 is the answer to ur question

Triangle xyz, z=61 degree, its nearest length If leg an is the missing side and xz=17.3 cm and xy=15.2 cm,

then change the equation to its original form when an is on one side and calculate the square root: a = √(c² - b²)

Leg b is undetermined if. For a missing hypotenuse c, the formula is b = (c2 - a2). c = √(a² + b²)

How do you calculate a triangle's third side?

Different Methods to Determine a Triangle's Third Side?

Use the Pythagorean Theorem while forming a right triangle. Use the isosceles triangle area formula to determine the area of a triangle. Use the law of cosines or the law of sines if you are familiar with some of the angles and other side lengths.

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A leaking faucet in the S&E building lab, dripping at a rate of one drop per second, will result in a water loss of approximately 4,725 liters in one year.

To calculate the amount of water lost in one year, we need to determine the number of drops per year and then convert it to liters. Since the faucet drips at a rate of one drop per second, there are 60 drops in a minute (60 seconds), which totals to 3,600 drops in an hour (60 minutes).

In a day, there would be 86,400 drops (24 hours * 3,600 drops). Considering a year of 365 days, the total number of drops would be approximately 31,536,000 drops (86,400 drops * 365 days). To convert the number of drops to liters, we need to multiply the total number of drops by the volume of each drop.

Given that each drop contains 0.150 milliliters, we convert it to liters by dividing by 1,000, resulting in 0.00015 liters per drop. Multiplying the total number of drops by the volume per drop, we find that the total water loss is approximately 4,725 liters (31,536,000 drops * 0.00015 liters/drop).

Therefore, in one year, the leaking faucet in the S&E building lab would result in a water loss of approximately 4,725 liters.

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Answer:

Letter B

Step-by-step explanation:

The independent is the one that is changed on purpose which is what the "if" is talking about

The dependent is the one that is changed based on the "if" meaning it's dependent

Order: Independent, Dependent

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The p-value accurate to 4 decimal places is approximately 0.2628.

To find the p-value for a two-tailed test with a test statistic of z = 1.113, we need to calculate the probability of observing a test statistic as extreme or more extreme than the one obtained, assuming the null hypothesis is true.

Since it is a two-tailed test, we need to consider both tails of the standard normal distribution.

The p-value is the probability of obtaining a test statistic as extreme as 1.113 or more extreme in both tails. To calculate this, we find the area under the curve beyond 1.113 in the right tail and beyond -1.113 in the left tail.

Using a standard normal distribution table or a statistical calculator, we can find the cumulative probability associated with the test statistic:

For the right tail:

P(Z > 1.113) = 1 - P(Z ≤ 1.113)

Using a standard normal distribution table or calculator, we find that P(Z ≤ 1.113) ≈ 0.8686.

Therefore, P(Z > 1.113) = 1 - 0.8686 ≈ 0.1314.

For the left tail:

P(Z < -1.113) ≈ P(Z ≤ -1.113)

Using symmetry of the standard normal distribution, we know that P(Z ≤ -1.113) is the same as P(Z > 1.113).

Therefore, P(Z < -1.113) ≈ P(Z > 1.113) ≈ 0.1314.

Since this is a two-tailed test, we need to combine the probabilities of both tails.

p-value = 2 * P(Z > 1.113) ≈ 2 * 0.1314 ≈ 0.2628.

Thus, the p-value accurate to 4 decimal places is approximately 0.2628.

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Answer:

  x = 1/2 or 3

Step-by-step explanation:

Compare the given equation to the standard form equation to identify the values of the variables in the formula. Then put those values in the formula and do the arithmetic.

  \(ax^2+bx+c=0\\\\2x^2-7x+3=0\\\\a=2;\ b=-7;\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)}}{2(2)}=\dfrac{7\pm\sqrt{25}}{4}=\dfrac{7\pm 5}{4}\\\\x=\left\{\dfrac{1}{2},3\right\}\)

Answer:

Step-by-step explanation:

\(2x^2-7x+3=0\\\\x_1 ,2 =\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=2\\\:b=-7\\,\:c=3\\:\quad x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\times\:2\times\:3}}{2\times\:2}\\\\=\frac{7+\sqrt{\left(-7\right)^2-4\times\:2\times\:3}}{2\times\:2}\\\\7+\sqrt{\left(-7\right)^2-4\times\:2\times\:3}=7+\sqrt{25}\\\\=\frac{7+\sqrt{25}}{2\times\:2}\\\\=\frac{7+\sqrt{25}}{4}\\\\\sqrt{25}=5\\\\=\frac{7+5}{4}\\\\=\frac{12}{4}\\\\=3 \\\)

\(x=\frac{-\left(-7\right)-\sqrt{\left(-7\right)^2-4\times\:2\times\:3}}{2\times\:2}\\\\=\frac{7-\sqrt{\left(-7\right)^2-4\times\:2\cdot \:3}}{2\times\:2}\\\\7-\sqrt{\left(-7\right)^2-4\times \:2\times\:3}=7-\sqrt{25}\\\\=\frac{7-\sqrt{25}}{2\times \:2}\\\\=\frac{7-\sqrt{25}}{4}\\\sqrt{25}=5\\\\=\frac{7-5}{4}\\=\frac{2}{4}\\\\=\frac{1}{2}\)

Answer: First, we need to convert feet to meters, using the conversion factor of 1ft ≈ 0.3m:

2055 feet * 0.3 meters/foot = 616.5 meters

Next, we need to convert meters to centimeters, using the conversion factor of 1m = 100cm:

616.5 meters * 100 centimeters/meter = 61,650 centimeters

Therefore, the perimeter of Elliot's property is 61,650 centimeters.

Step-by-step explanation:

Answer:

(2,-3)

Step-by-step explanation:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and the signs are changed.

(-2, 3)

Hope it helps.

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