the equation of motion of a particle is s = t3 − 27t, where s is measured in meters and t is in seconds. (assume t ≥ 0.)

Answer:

cohesive properties

Explanation:

The property of cohesion allows liquid water to have no tension on the surface.

Answer:

Cohesive properties

Explanation:

Answer:

It's A & C

Explanation:

:p

Knowing the surface tension of isopropanol in air and surface tension of water in air we can say that:

Isopropyl alcohol (IPA) at various concentration levels is considered a disinfectant (not for bacterial spores), virucide, fungicide and an effective waste removal agent widely used in cleanrooms and other contamination controlled environments.

So compare the surface tension of isopropanol and the water we can say that Isopropanol will have a flatter meniscus than water because the forces between the molecules are smaller and Isopropanol will have a lower boiling point than water because the forces between the molecules are smaller.

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Complete cancellation will occur for a path difference equal to an odd multiple of half the wavelength.

The phenomenon of cancellation occurs in wave interference when two waves with the same frequency and amplitude are out of phase by 180 degrees, meaning that the crests of one wave coincide with the troughs of the other wave.

The path difference between the two waves determines whether or not complete cancellation will occur. When the path difference is equal to an odd multiple of half the wavelength (λ/2, 3λ/2, 5λ/2, etc.), the waves will be out of phase by 180 degrees and complete cancellation will occur.

Mathematically, we can express this condition as:

path difference = (m + 1/2) λ

where;

For example, if the wavelength of the waves is 1 meter and the path difference is 1/2 meter (m = 0), the waves will be in phase and constructive interference will occur. However, if the path difference is 1 meter (m = 1), the waves will be out of phase by 180 degrees and complete cancellation will occur.

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Answer:

the exact center of its mass

Answer:

800J

Explanation:

Given data

Force= 100N

Distance moved= 8m

The expression for the work done is

WD= Force* distance

substitute

WD= 100*8

WD= 800Joules

Hence the work done is 800J

Answer:

I HAD THE SAME QUESTION AND SEARCHED IT UP AND GOT THE ANSWERS.

Explanation:

Structural engineering is the other course that are increasingly becoming relevant to space science careers

Investigating how gravity affects the human body, building the telescopes of the future. providing accessible explanations of solar system discoveries. These are just a few examples of the projects that people involved in space exploration employment work on.

Learning how to repair space stations, aircraft, or even make space shuttles or items you'll need in space requires knowledge in civil engineering, which is the notion of designing large transportation projects.

Structural engineering is the other course that are increasingly becoming relevant to space science careers

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Explanation:

The length of the shortest pipe closed on one end and open at the other end that will have a fundamental frequency of 0.060 kHz on a day when the speed of sound is 340 m/s is approximately 283.3 cm.

This can be determined using the formula:

frequency = (n x speed of sound) / (2 x length)

where: n = 1 (fundamental frequency)

frequency = 0.060 kHz (60 Hz)

speed of sound = 340 m/s.

Plugging these values into the formula gives:

0.060 x 10³ Hz = (1 x 340 m/s) / (2 x length)

0.06 x 10³ Hz = 170 m/s / length

0.06 x 10³ Hz x length = 170 m/s

Dividing both sides by 0.06 x 10³ Hz:

length = 170 m/s / (0.06 x 10³ Hz)

length = 283.3 cm (rounded to one decimal place)

Therefore, the length of the shortest pipe closed on one end and open at the other end that will have a fundamental frequency of 0.060 kHz on a day when the speed of sound is 340 m/s is approximately 283.3 cm.

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The gravitational torque on your arm in this position around the shoulder joint  is  mgL/2.

The force that can cause an object to rotate along an axis is measured as torque. An object acquires angular acceleration due to torque.

A vector quantity is a torque. The force acting on the axis determines the direction of the torque vector.

Let the mass of your arm = m.

Length of your arm = L.

If the hand has uniform mass, the position of its center of gravity during it is horizontal is = L/2.

Hence, the torque on your arm in this position around the shoulder joint be =

weight of your hand × the position of its center of gravity with respect to shoulder

= mgL/2

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Given:

Pressure, P = 300 kPa

Volume, V = 100 cm³

Temperature, T = 30°C

Let's fin the pressure of the gas inside the container if it is heated to 100°C.

Apply the Gay-Lussac's law:

Where:

P1 = 300 kPa

T1 = 30 + 273 = 303 K

T2 = 100 + 273 = 373 K

V1 = V2 (since the container is sealed).

Let's solve for P2.

Rewrite the formula for P2:

Therefore, the pressure if the container is heated to 100°C is 369.31 kPa.

ANSWER:

369.31 kPa

The amplitude of oscillations of the automobile can be calculated using the formula: A = (m * g * h) / (k + m * w^2)

where:

m = 1000 kg (mass of the automobile including passengers)

g = 9.8 m/s^2 (acceleration due to gravity)

h = 5 cm = 0.05 m (amplitude of the sinusoidal bumps)

k = effective spring constant of the suspension system

w = 2 * pi * f

= 2 * pi * v / lambda

= 2 * pi * 20 / 20

= 2 * pi (frequency of the bumps, v is the speed of the car, lambda is the wavelength)

We don't have the value for k,

so we can assume it to be a constant value for all cars.

Therefore, the amplitude of oscillations can be calculated as:

A = (1000 kg * 9.8 m/s^2 * 0.05 m) / (k + 1000 kg * (2 * pi)^2)

This value will give us the maximum vertical displacement of the car from its mean position.

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Answer:

B is directed from N to S     (upwards at the open end)

Let the magnet be oriented with the open end at the north

F = q * v X B

A positive charge would be deflected towards the East using v X B

This is the direction of the "conventional" current which is B to A

Actual charges flow from A to B but the sign of the charge is -q

The work done by the rock climber when she climbs 12 m in 10 sec with a backpack weighing 600 N is option (d)  7200 J

The distance climbed is 12 meters, and the time taken is 10 seconds. Therefore, the average speed of the climber is:

Average speed = Distance / Time = 12 m / 10 s = 1.2 m/s

The work done is given by the formula:

Work = Force x Distance x cos(theta)

where theta is the angle between the force and the displacement. In this case, the climber is moving vertically upwards, and the force is also vertically upwards, so theta is 0 degrees, and cos(theta) = 1.

Therefore, the work done is:

Work = Force x Distance x cos(theta) = 600 N x 12 m x 1 = 7200 J

Therefore, the correct option is (d) 7200 J

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Answer:

if positioned at height

Explanation:

just search it online

Answer: 1st, 4th, and 6th choice

A bow is drawn back from its equilibrium position.

A spring toy dart gun is loaded with a dart.

A bungee cord is stretched with a person at the end.

Explanation:

If these are the choices...

A bow is drawn back from its equilibrium position.

An arrow rests on a bow.

A spring toy dart gun is unloaded.

A spring toy dart gun is loaded with a dart.

A bungee cord is connected to a tall tower.

A bungee cord is stretched with a person at the end.

Edge 2021

Answer:

The wheel and axle is another simple machine. It uses a wheel with a rod attached in the middle as an axle to help it to lift or move loads. In some cases this machine works like a lever to multiply force (like with a doorknob or a fishing reel).

Even though you did not take any measurements, (2m/s2, 3N) is another data point that would be fair to provide.

To determine if there is another reasonable data point that can be added, we can plot the force and acceleration data to see if there is a clear relationship between the two variables.

From the plot, we can find that there is a clear linear relationship between the force and acceleration data. We can also calculate the slope of the line using the formula:

slope = Δa / ΔF

where Δa is the change in acceleration and ΔF is the change in force. From the given data, we can use the first and last data points to calculate the slope:

slope = (1.8 m/\(s^2\) - 0.5 m/\(s^2\)) / (1 N - 0.25 N) = 3.6 m/\(s^2\)/N

Now, we can use the slope to predict the acceleration for another force value. For example, we can predict the acceleration for a force of 2 N:

a = slope * F = 3.6 m/\(s^2\)/N * 2 N = 7.2 m/\(s^2\)

Data point to add to the plot is (2 N, 7.2 m/\(s^2\))

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False is the proper response. The magnitude of velocity is constant in a uniform circular motion. Therefore, the assertion is true.

How does the frequency or number of revolutions change when the washer's bulk rises?

The frequency increased with increasing bulk. The second formula can also be used to describe this relationship. The equation demonstrates the direct connection between acceleration and mass in the presence of constant load and diameter. The outcome is that an increase in mass causes an increase in velocity.

A uniformly moving item has a centripetal force that is constantly directed toward the center of the circle it is traveling in. When the applied circular path force is released, the item will travel on a single direction parallel to the curving route at a certain location.

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The new gravitational force between the two heavenly bodies is six times the original gravitational force.

The gravitational force between two heavenly bodies can be calculated using Newton's law of universal gravitation;

F1 = G × (m1 × m2) / r²...eq (1)

gravitational constant = G

mass 1 = m1

mass 2 = m2

radius = r

distance between them constant,

we can calculate the new gravitational force F2 using the formula:

F2 = G × (m1 × m2) / r²; where

gravitational constant = G

mass 1 = 2m1 (doubled)

mass 2 = 3m2 (tripled)

radius = r

on substitution,

F2 = G × (2m1 × 3m2) / r²

= G × (6m1m2) / r²

= 6 × G × (m1m2) / r²

⇒ (G × (m1 × m2) / r² = F1 )...from eq. (1)

= 6 × F1

⇒ F2 = 6F1

Therefore, the new gravitational force will be six times the original gravitational force when one mass is doubled and the other mass is tripled.

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If one of the masses in a gravitational system is doubled and the other mass is tripled while keeping the distance between the bodies constant, then the new gravitational force will increase by a multiple of:

6 (2 x 3 = 6)

We know from Newton's Law of Gravitation that the gravitational force between two objects is:

F = G * (m1 * m2) / r^2

Where:

F = Gravitational force

G = Universal gravitational constant

m1 = Mass of first object

m2 = Mass of second object

r = Distance between the objects

Since the distance (r) between the two bodies remains constant in the given scenario, it drops out when calculating the change in force.

We are only concerned with how the change in masses affects the force.

Based on the equation, we can see that the gravitational force is directly proportional to the product of the two masses (m1 * m2).

If one mass doubles and the other mass triples, their product will increase by a multiple of 2 x 3 = 6.

Therefore, the new gravitational force between the two heavenly bodies will increase by a factor of 6, compared to the original gravitational force when only one mass was doubled and the other mass tripled, while keeping the distance constant between them.

In his comprehensive response, Vardhan Thigle explains how the absence of zero point energy would be inconsistent with the uncertainty principle. I'd want to present a heuristic argument that also holds true for other systems where a particle is bound.

The mass's potential to be at rest at equilibrium is a factor in the classical harmonic oscillator problem. The formal solution to the quantum harmonic oscillator puzzle has a non-zero ground state energy. In other words, the permitted energy levels are determined by:

h*v(n+1/2), where n=0 is the ground state.

However, the uncertainty principle argument asserts that a harmonic oscillator would need to be at rest at its equilibrium position in order for it to have zero energy. However, doing so would need precise knowledge of both the position and momentum, which would go against the uncertainty principle. The lowest energy is therefore not zero. It has implications for why helium does not solidify until under very high pressures when absolute zero is approached. This has to do with the zero-point energy theory. In other words, even as liquid helium is cooled below 4.2K and toward the lowest temperatures that can be reached, the atoms are still oscillating loudly enough to prevent them from becoming a solid with the predicted hcp crystal structure.

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Correct Question:

How would you analyze the Heisenberg uncertainty principle for a harmonic oscillator, explain the existence of zero point (i.e., g) energy in harmonic oscillator?

Answer:

  1.343 atm

Explanation:

The mass of water above 1 square meter of swimming pool bottom is ...

  M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2

Then the force exerted by the water on the pool bottom is ...

  F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa

Compared with atmospheric pressure, this is ...

  34,300/10^5 = 0.343 . . . . atmospheres

Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.

The current through the long straight wire is 45.7 A.

The magnetic field produced by a long straight wire carrying a current is given by the formula B = (μ0I)/(2πr), where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. Rearranging the formula to solve for I, we get I = (2πrB)/μ0.

Substituting the given values, we have B = 1.70 T and r = 0.0370 m. The permeability of free space μ0 is a constant equal to 4π × 10⁻⁷ T·m/A. Thus, we can calculate the current I as I = (2π0.0370 m1.70 T)/(4π × 10⁻⁷ T·m/A) = 45.7 A.

Therefore, the current through the long straight wire is 45.7 A.

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The density of matter in a lead nucleus is 2.82 x 10¹⁷ kg/m³.

Lead nucleus is composed of protons and neutrons. The density of a nucleus is the mass of a nucleus divided by the volume occupied by the nucleus. The volume of a nucleus can be determined using the formula

(4/3)πr³,

where r is the radius of the nucleus. As the diameter of a lead nucleus is given as 14.2 fm, the radius of a nucleus can be calculated as follows:

radius = diameter/2

= 14.2 fm/2

= 7.1 fm

Hence, the volume of a lead nucleus can be calculated as:

(4/3)πr³ = (4/3)π(7.1 fm)³

= 1.57 x 10⁻⁴ fm³

As the mass of a lead nucleus is 3.15 x 10⁻²⁵ kg, the density of matter in a lead nucleus can be calculated as follows:

Density = Mass/Volume

= 3.15 x 10⁻²⁵ kg/1.57 x 10⁻⁴ fm³

= 2.82 x 10¹⁷ kg/m³

The density of matter in a lead nucleus is 2.82 x 10¹⁷ kg/m³.

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The minimum length of the curve for the required sight distance is 338.12 feet.

Locate the station point of the highest point on the curve.

(dy)/(dx) = 0

(dy)/(dx) = - 0.19 × 2x + 1.2 = 0

x = 3.1579stations

The elevation of the very best point at the curve is

y = - 0.19 × 3.1579² + 1.2 × 3.1579 + 1094.8

= 1096.69ft

Deceleration rate a is 11.2ft / (s² ). Reaction time t is 2.5seconds

The necessary SSD for the design speed of 60mph is

V 1 ^ 2/ 2g(( a / g ) pm G) +V 1 × t

,= (60 * 5280ft)² /(60 × 60s)) ² /(2 × 32.2((112/322))) + ((60 * 5280f)/(60 * 60s)) * 2.5

= 565.71pi

Lm= (|G1 - G2| × SSD² )/2158  = (|1.2 + 1.08| × 565.71²) /2158

= 338.12ft

speed in physics is a scalar amount that refers back to the fee at which an item moves, typically expressed in units of meters in line with seconds (m/s) or kilometers in step with the hour (km/h). it is defined as the distance an item travels in line with a unit of time, which means that it only takes into consideration the value of the item's motion and not its path.

Immediate speed refers to the speed of an item at any given second, at the same time as average speed is calculated over a period of time. the velocity of an object may be inspired by means of several elements, which include the forces appearing upon it and the medium through which it is transferring.

Further to hurry, there are different associated standards in physics, along with speed, which incorporates each the rate and course of an item's movement and acceleration, which describes the rate at which an object's velocity changes over the years.

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Answer:

The answer(s) for this question are as followed: A, C, & D

Explanation:

I hope this helped, let me know if i missed any.

16.92 meter far can the turtle travel in an hour.

What is the formula for Speed, Distance & Time?

Speed (or rate, r) is a scalar quantity that measures the distance travelled (d) over the change in time (Δt), represented by the equation r = d/Δt

Given, 12 mile in 19 hours so we require to convert in SI unit.

12 mile = 19312.1 meters

19 Hour = 68400 sec

Applying in formula, speed = Distance / Time

Distance / Time = 19312.1 / 68400 = 0.282 m/ sec ²

Speed = 0.282 m / sec ²

1 hour = 60 second

Putting the above value in the below formula

speed = Distance / Time

Distance = Speed x Time = 0.282 x 60 = 16.92 meter

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Answer:

where are the choices i think 100% that is my opinion

The time for a steel ball to hit the ground when shot horizontally off a table is independent of the initial velocity, and the formula is \(d = v_i*t + (1/2)at^2\).

To decide the time it takes for a steel ball to stir things up around town when shot evenly off a table, we can utilize the conditions of movement, explicitly the kinematic condition:

\(d = v_i*t + (1/2)at^2\)

where:

d is the distance voyaged

v_i is the underlying speed

an is the speed increase

t is the time

We can expect that the speed increase is because of gravity, which is steady and equivalent to \(9.81 m/s^2.\)

Since the ball is shot on a level plane, its underlying vertical speed is zero. Accordingly, we can work on the situation to:

\(d = (1/2)at^2\)

Settling for t, we get:

t = sqrt(2*d/a)

To decide the distance voyaged, we can utilize the way that the ball will follow an explanatory direction and will stir things up around town simultaneously it would have taken to fall upward from a similar level. Hence, we can involve the condition for the time it takes for an item to in an upward direction fall:

t = sqrt(2*h/g)

where h is the level of the table and g is the speed increase because of gravity.

Utilizing the trial information, we can decide the level of the table and the distance the ball goes prior to stirring things up around town for every speed setting of the launcher. Then, we can work out the time it takes for the ball to stir things up around town involving the condition for t.

The time it takes for the ball to stir things up around town will be the equivalent no matter what the speed setting of the launcher, as long as the ball is shot evenly with a similar starting level. This is on the grounds that the underlying speed in the level bearing doesn't influence the time it takes for the ball to upward fall.

This outcome is steady with the way that the time it takes for an item to fall upward just relies upon the level and speed increase because of gravity. Hence, failing upward from the table top to the floor beneath would bring about a similar time it takes for the ball to raise a ruckus around town when shot evenly off the table.

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The complete question is:

If the steel ball is shot horizontally off the table, how much time would it take the ball to hit the ground for each of the velocity settings of the launcher? Explain your answer using the equations of motion and your experimental data. How does this relate to the ball being dropped vertically from the table top to the floor below.

The number of customer complaints received each day is a discrete variable. This is because it is a count of a specific number of complaints and cannot be measured as a fraction or percentage. the measures of central tendency, variance, or regression models.

The number of complaints can only take on specific whole numbers, and there is no possibility of a "fractional" or "in-between" value. For example, if a business receives 5 customer complaints in a day, it cannot receive 5.5 or 5.25 complaints - it is simply 5. Therefore, the number of complaints is considered to be a discrete variable. It is important to identify whether a variable is discrete or continuous as it can impact how the data is analyzed and interpreted. Discrete variables are typically analyzed using counts, percentages, or statistical tests such as chi-square tests or Poisson regression, whereas continuous variables are analyzed using measures of central tendency, variance, or regression models.

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