The directions of horizontal forces is crucial in analyzing the motion of objects on different surfaces, as it helps determine the net force acting on an object and its resulting acceleration.
Based on the figure, there are two horizontal forces acting on crate 2. One is the force applied by the truck in the forward direction, and the other is the force of friction acting in the opposite direction due to the rough surface of the road.
The force applied by the truck is directed towards the right, while the force of friction is directed towards the left. Therefore, the directions of all the horizontal forces acting on crate 2 are to the right and to the left.
It is important to note that horizontal forces are forces that act parallel to the ground or the surface on which an object rests. These forces can either be balanced or unbalanced, depending on whether they cancel each other out or not. In this case, the two horizontal forces acting on crate 2 are unbalanced, as the force of friction is opposing the motion caused by the force applied by the truck.
Overall, understanding the directions of horizontal forces is crucial in analyzing the motion of objects on different surfaces, as it helps determine the net force acting on an object and its resulting acceleration.
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You cause a particle to move from point A, where the electric potential is 18.7 V, to point B, where the electric potential is −24.1 V. Calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, a proton, a neutral hydrogen atom, and a singly ionized helium atom (i.e., lacking one electron from its neutral state). electron: J proton: neutral hydrogen atom: J singly ionized helium atom:
The changes in electrostatic potential energy are approximately:
Electron: +6.88 × 10^(-18) J
Proton: -6.88 × 10^(-18) J
Neutral hydrogen atom: 0 J
Singly ionized helium atom: -6.88 × 10^(-18) J
To calculate the change in electrostatic potential energy, we can use the formula:
ΔPE = q * ΔV
where ΔPE is the change in electrostatic potential energy, q is the charge of the particle, and ΔV is the change in electric potential.
Given the electric potential at point A (18.7 V) and point B (-24.1 V), we can calculate the change in electric potential (ΔV) as:
ΔV = VB - VA
ΔV = (-24.1 V) - (18.7 V)
Now, let's calculate the change in electrostatic potential energy for each particle:
For an electron:
q = \(-1.6 *10^(-19)\) C (charge of an electron)
ΔPE (electron) =\((-1.6 * 10^(-19) C)\)* ΔV
For a proton:
q = +1.6 ×\(10^(-19)\)C (charge of a proton)
ΔPE (proton) = (+1.6 × \(10^(-19)\)C) * ΔV
For a neutral hydrogen atom:
q = 0 (charge of a neutral atom)
ΔPE (neutral hydrogen atom) = 0 * ΔV = 0
For a singly ionized helium atom:
q = +1.6 × 10^(-19) C (charge of a singly ionized helium atom)
ΔPE (singly ionized helium atom) = (+1.6 × 10^(-19) C) * ΔV
Now we can calculate the numerical values
ΔV = (-24.1 V) - (18.7 V) = -42.8 V
ΔPE (electron) = (-1.6 × \(10^(-19) \\\)C) * (-42.8 V) = 6.88 ×\(10^(-18)\)J
ΔPE (proton) = (+1.6 × \(10^(-19) \\\) C) * (-42.8 V) = -6.88 × \(10^(-18)\)J
ΔPE (neutral hydrogen atom) = 0
ΔPE (singly ionized helium atom) =\((+1.6 * 10^(-19) C) * (-42.8 V) = -6.88 * 10^(-18) J\)
Therefore, the changes in electrostatic potential energy are:
electron\(: 6.88 *10^(-18) J\)
proton: \(-6.88 * 10^(-18) J\)
neutral hydrogen atom: 0
singly ionized helium atom: \(-6.88 * 10^(-18) J\)
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Describe a situation in which the velocity of a particle is perpendicular to the position vector ?
Answer:
"Velocity always perpendicular to position vector" means that the distance from the particle of interest to the origin never changes. The question is whether such motion always traces out a circle. Counterexample: consider a plane pendulum with its pivot at the origin.
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles
traveled in a straight line and some were deflected at different angles.
Which statement best describes what Rutherford concluded from the motion of the particles?
Answer:
C
Explanation:
I just took the quiz
Q4. a 5.0-kg bowling ball rolls down a frictionless 2.5 m tall ramp and strikes a
stationary mass at the bottom of the ramp in a pertectly elastic collision.
to what
height back up the ramp does the first bowling travel after the collision if
a) the stationary mass is also 5.0 kg
b) the stationary mass is 10.0 kg
c) the stationary mass is 500.00kg
If the stationary mass is also 5 kg, then the bowling travel upto 2.5 m. If it is 10 kg the height it travel after the collision will be 1.25 m and if the stationary mass is 500 then the height will be 0.025 m.
What is elastic collision?An elastic collision is the short term force acting between two objects make them move apart or to one direction where, the total kinetic energy and momentum of the objects are conserved.
Here, the kinetic energy of the moving ball is equal to the work done by its weight and displacement.
hence Ke = f.ds
f = mg. ds = 5 kg × 9.8 m/s² × 2.5 m = 122.5 J
Then this work done is equal to the potential energy of the stationary mass and:
122.5 J = mgh.
then for a mass of 5 kg , h = 122.5 / (5 × 9.8 ) = 2.5 m
If the mass is 10 kg, h = 122.5 / (10× 9.8 ) = 1.25 m
If the mass is 500 kg, h = 122.5 / (500 × 9.8 ) = 0.025 m.
Therefore the height that the bowling travel back after collision varies with the mass of the stationary object.
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critically discuss three negative reasons why some people join protest actions
Answer:
1. Peer Pressure: One of the negative reasons why some people join protest actions is peer pressure. This is the pressure exerted on an individual by their peers or social group to participate in a protest or rally even if they do not fully understand the cause or issues behind it. In such cases, these individuals might feel compelled to participate because of the fear of being seen as outcasts or not being accepted by their group.
2. The Desire for Attention: Another reason why some people might join a protest action is the desire for attention or recognition. For some individuals, participating in a protest offers them the opportunity to be seen on social media or in the news, which can give them a sense of importance or relevance. Often, such individuals might not even care about the cause but are only interested in gaining attention.
3. Ideological Manipulation: A third negative reason why some people join protest actions is ideological manipulation. In some cases, individuals might be manipulated or brainwashed by an extremist group or political party to join a protest or rally. These individuals might be given false information or propaganda to believe that they are fighting for a noble or just cause when, in reality, they are being used as pawns for political or personal gains.
In conclusion, while protest actions are a legitimate form of expressing dissent and demanding change, these actions can also be hijacked by individuals who have negative motives for joining. Therefore, it is essential to critically evaluate the reasons behind one's participation in a protest action and ensure that it aligns with the genuine cause or issue at hand.
A playground 82 ft long and 54 ft wide is to be resurfaced at a cost of $2.75 per sq ft. What will the resurfacing cost?Round to nearest integer or decimal
ANSWER:
$ 12177
STEP-BY-STEP EXPLANATION:
We must calculate the area of the playground, knowing that the area is equal to length times width, like this:
\(\begin{gathered} A=82\cdot54 \\ A=4428ft^2 \end{gathered}\)Now, knowing the area, we can calculate the total cost, like this:
\(\begin{gathered} C=2.75\cdot4428 \\ C=12177 \end{gathered}\)The resurfacing cost is $ 12177
2. Why is CO2 important?
how much work is required to increase a velocity of 4kg object by 8m/s?
Answer:
4kg=4000,8m=60 times 8 =480
4000 times 480 over 100 =19200
28.2 km equal how many meters
Answer:exactly 28200 meters
Explanation:
A burst of sound takes 0.4 seconds to reach the seabed and return, if speed of sound in water is 1400m/s. what is the depth of water?
Explanation:
Given:
Speed of sound = 1400 m/s
Total time taken = 0.4 seconds
To find:
The depth of water
Solution:
As it take 0.4 seconds for the burst to reach the seabed and return (both ways), we can deduce that it takes 0.2 seconds to reach the seabed (one way).
This is because the speed of sound is a constant.
Now, to find the depth, we use the equation
Speed = Distance/Time
Here, we know the values of speed (1400 m/s) and time (0.2 seconds). Distance is the depth of the water, which we need to find. Let the distance be x.
Therefore
1400 = x/0.2
x = 1400 * 0.2
x = 280 m
We get the depth as 280 metres.
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Three point charges are arranged at the corners of a square of side L as shown in the figure. What is the potential at the fourth corner (point A), taking V =0 at a great distance?
E4 = kQ.[2/a2 + 1/a2] appears to reflect the electric field at the fourth corner as a result.
What makes it a "electric field"?A characteristic of matter called an electric discharge generates multiple objects to either attract or repel each other depending on how it is charged (positive or negative). A region of space surrounding a static electricity particle or object known as an electrostatic potential is one in which an electricity would experience force.
Why is the electric field crucial?A personality electromagnetic field like light also requires a grasp of the electric field idea. We now have a mechanism to explain how starlight traverses enormous stretches of vacant desert in order to reach our eyes thanks to the electric field notion.
Briefing:Number of point charges = 3
E4 = E1 + E2 + E3
E4 = kQ/a2 + kQ/√(2a2) + kQ/a2
E4 = kQ.[ 1/a2 + 1/√(2a2) + 1/a2 ]
E4 = kQ.[ 2/a2 + 1/a√2 ]
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much like a battery these generate electricity from chemical events
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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Una ballena nada con una rapidez lineal de 50 km/h. ¿Cuántos metros habrá recorrido al cabo de 2 horas y media?
The linear speed of a swimming whale is 50 km/h. and it will have traveled approximately 138.9 km after 2 and a half hours.
First, we need to convert the linear speed into m/s:
1 km/h = 1000/3600 m/s= 5/18 m/s
Therefore,50 km/h = 50 × 5/18 m/s = 125/9 m/s
Now, the distance traveled by the whale can be found using the formula:
Distance = speed × time
Since the time is 2.5 hours, we have that convert it to seconds:
2.5 hours = 2.5 × 60 × 60 seconds = 9000 seconds
Therefore, the distance traveled is:
Distance = (125/9) m/s × 9000 s= 1250000/9 m ≈ 138888.89 m≈ 138.9 km
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Can someone explain E=mc2
In FULL detail please
Einstein's Big Idea homepage. E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.
A charge of +4.0 C is moved a distance of 0.50 m in a uniform electric field of magnitude 30 N/C. Calculate the work done on this charge by the electric field.
Answer:
+60 J
Explanation:
Work done by the field on the charge is given by W = qEd where q = charge = +4.0 C, E= electric field strength = 30 N/C and d = distance moved by charge = 0.50 m
So, substituting the values of the variables into the equation, we have
W = qEd
= +4.0 C × 30 N/C × 0.50 m
= +60 Nm
= +60 J
The work done on the charge will be given by \(W=60\ J\)
What will be the work done on the charge?It is given that
Charge q= +4C
The distance D= 0.50 m
Electric field \(E=30 \ \frac{N}{C}\)
Now the work done will be given by
\(W= q\times E\times d\)
\(W=4\times 30\times 0.5\)
\(W=60J\)
Thus the work done on the charge will be given by \(W=60\ J\)
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7
How should an Ammeter be connected into a circuit?
(1 Point)
In parallel with the wire
In parallel with the battery
In series
Answer:
In series
Explanation:
Ammeter is used in electric circuits to measure the amount electric current that passes through the circuit.
Now, as a rule, this ammeter is always connected in series with the wires in the circuit where the current is being measured so that sufficient current can pass through it.
what is the difference between speed and velocity in physics
The primary difference between speed and velocity is that speed is a scalar quantity that describes how fast an object is moving, while velocity is a vector quantity that describes how fast an object is moving in a particular direction
Speed and velocity are two critical concepts in physics. They are used to describe the motion of an object. While both describe how fast an object is moving, there are some fundamental differences between the two. Let's explore these differences.
What is speed?
Speed is a scalar quantity that describes how quickly an object moves. It is measured in meters per second (m/s) or kilometers per hour (km/h).
Speed can be calculated using the following formula:
speed = distance ÷ time
For example,
if an object covers a distance of 150 meters in 10 seconds, its speed can be calculated as follows:
Speed = distance ÷ time= 150 meters ÷ 10 seconds= 15 meters per second (m/s)
What is velocity?
Velocity, on the other hand, is a vector quantity that describes how fast an object is moving in a particular direction. It is measured in meters per second (m/s) or kilometers per hour (km/h).
Velocity can be calculated using the following formula:
velocity = displacement ÷ time
For example, if an object travels a displacement of 150 meters in 10 seconds in a specific direction, its velocity can be calculated as follows:
Velocity = displacement ÷ time= 150 meters ÷ 10 seconds= 15 meters per second (m/s) in a specific direction.
In conclusion, the primary difference between speed and velocity is that speed is a scalar quantity that describes how fast an object is moving, while velocity is a vector quantity that describes how fast an object is moving in a particular direction.
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If the force shown in the diagram below does 1,110J of work while acting throughout the
10.0m distance, what is the magnitude of the force?
a. F = 139N
b. F = 111N
c. F = 8,860N
d. F = 904N
The force that is acting on the object is 139N. Option A
What is the magnitude of the force?Let us know that we can only say that there is work done if we have a force that has been applied in such a way that it can be able to move an object in the direction of the force.
As such, we are going to have that;
W = Fcosθ
W = work done
F = force applied
θ = angle turned
1110 = F cos 37 * 10
F = 1110/cos 37 * 10
F = 139N
There is the application of a force of about 139N on the object as have been shown here.
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In a certain telemetry system, there are four analog signals mi(t), m₂(1), m(t) and m4(1). The 1st signal has the bandwidth of 3.6 kHz and rests have the bandwidth of 1.4 kHz each. Design a multiplexing scheme for the signals.
By assigning non-overlapping frequency ranges to each signal, we ensure that they can be transmitted simultaneously without interfering with each other.
To design a multiplexing scheme for the given signals, we need to allocate suitable frequency ranges for each signal to avoid interference and enable their simultaneous transmission.
Given bandwidths:
m₁(t): 3.6 kHz
m₂(1): 1.4 kHz
m₃(t): 1.4 kHz
m₄(1): 1.4 kHz
One common approach is to use frequency-division multiplexing (FDM), where each signal is assigned a unique frequency range within the overall available bandwidth.
In this case, we can allocate frequency ranges as follows:
m₁(t): 0 Hz - 3.6 kHz
m₂(1): 3.6 kHz - 5 kHz (using 1.4 kHz bandwidth)
m₃(t): 5 kHz - 6.4 kHz (using 1.4 kHz bandwidth)
m₄(1): 6.4 kHz - 7.8 kHz (using 1.4 kHz bandwidth)
By assigning non-overlapping frequency ranges to each signal, we ensure that they can be transmitted simultaneously without interfering with each other. This multiplexing scheme allows for the efficient transmission of all four analog signals within the available bandwidth.
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Studies of the spectra of stars have revealed that the element that makes up the majority of the stars (75% by mass) is
Studies of the spectra of stars have revealed that the element that makes up the majority of the stars (75% by mass) is hydrogen.
Spectra refer to the range of wavelengths of electromagnetic radiation emitted or absorbed by an object. In the case of stars, their spectra provide crucial information about their composition, temperature, and motion. Astronomers analyze these spectra to determine the presence of various elements within a star.
Elements are substances made up of only one type of atom, such as hydrogen, helium, and carbon. In stars, elements undergo nuclear fusion reactions, producing energy and light.
When observing the spectra of stars, astronomers noticed that the majority of the spectral lines corresponded to the element hydrogen. This observation led to the conclusion that hydrogen is the most abundant element in stars, making up about 75% of their mass. The remaining mass is primarily composed of helium (about 24%), with trace amounts of heavier elements.
In summary, through the analysis of stellar spectra, it has been discovered that hydrogen is the predominant element in stars, accounting for approximately 75% of their mass. This finding is essential to our understanding of the processes taking place within stars, such as nuclear fusion and energy production.
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A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror?
–5.0 cm
7.5 cm
-7.5 cm
5.0 cm
Answer:
-7.5
Explanation:
edge 2021
Identifying Video Ports and Connectors
On the Ports and Connectors tab, select the connector names and video ports from the lists.
By selecting the appropriate connector names and video ports from the lists, you'll be able to identify and understand the different types of video ports and connectors used in various devices.
Step 1: Open the Ports and Connectors tab, where you will find lists of connector names and video ports.
Step 2: Carefully review the lists and identify the most common video ports and connectors, such as HDMI, VGA, DVI, and DisplayPort.
Step 3: Select the appropriate connector names and video ports from the lists.
For example, some selections you might make include:
- HDMI: This connector is commonly used for high-definition video and audio, and can be found on many devices such as computers, TVs, and gaming consoles.
- VGA: This connector is an older analog video standard, commonly used for connecting monitors to computers. It is gradually being replaced by digital interfaces like HDMI and DisplayPort.
- DVI: This connector is used for digital video connections between computers and monitors. There are different types of DVI, such as DVI-A, DVI-D, and DVI-I.
- DisplayPort: This connector is a newer digital video and audio interface, used for connecting computers, monitors, and other devices. It supports high-resolution displays and multiple display setups.
By selecting the appropriate connector names and video ports from the lists, you'll be able to identify and understand the different types of video ports and connectors used in various devices.
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What is one characteristic of the convection inside the sun?
- Cells of circulating gasses called granules
- Thick clouds of dust and gasses
- Large cells of rising and sinking gasses
- Nuclear reactions between hydrogen atoms
Answer: 3- Large cells of rising and sinking gasses
Explanation: Hotter gas coming from the radiative zone expands and rises through the convective zone. It can do this because the convective zone is cooler than the radiative zone and therefore less dense. As the gas rises, it cools and begins to sink again. As it falls down to the top of the radiative zone, it heats up and starts to rise. This process repeats, creating convection currents and the visual effect of boiling on the Sun's surface.
For the circuit in the figure
Find the rate of conversion of internal (chemical) energy toelectrical energy within the battery.
Find the rate of dissipation of electrical energy in thebattery.
Find the rate of dissipation of electrical energy in the externalresistor.
The rates of conversion and dissipation of energy can be found using the following equations:
Power = Voltage x Current
Power = Current^2 x Resistance
where power is the rate of energy conversion or dissipation in watts (W), voltage is the potential difference in volts (V), current is the flow of electric charge in amperes (A), and resistance is the opposition to the flow of current in ohms (Ω).
Assuming a battery of voltage V and internal resistance R is connected to an external resistor of resistance r, with a current I flowing through the circuit, we can use the following expressions to calculate the rates of energy conversion and dissipation:
Rate of conversion of internal energy to electrical energy in the battery:
P1 = VI
Rate of dissipation of electrical energy in the battery:
P2 = I^2R
Rate of dissipation of electrical energy in the external resistor:
P3 = I^2r
Note that the total power supplied by the battery must equal the total power dissipated in the circuit, according to the principle of conservation of energy.
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A debt ratio of 0.5 indicates: A) The balance on the mortgage equals 50 percent of the value of the home. B) For every dollar of net worth, debt equals $0.50. C) For every dollar of debt, net worth equals $0.50. D) For every dollar of take-home pay, monthly credit payments equal $0.50. E) For every dollar of assets, monthly credit payments equal $0.50.
A debt ratio of 0.5 indicates: For every dollar of net worth, debt equals $0.50. The correct answer is B.
A debt ratio is a financial metric that measures the proportion of debt in relation to the net worth or equity of an individual or company. It helps evaluate the level of financial leverage or the extent to which an entity relies on borrowed funds.
In the context of the given options, a debt ratio of 0.5 means that for every dollar of net worth, there is $0.50 of debt. This implies that 50 percent of the net worth is financed through debt. This ratio indicates the proportion of debt relative to the equity or ownership in an entity.
Option B correctly states that for every dollar of net worth, debt equals $0.50. This interpretation aligns with the definition of the debt ratio, as it reflects the relationship between net worth and debt.
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Give your opinion regarding behavioral modeling in Verilog HDL which could give the most effective way of describing the digital circuits. (2 marks) (b) Give the difference between using the general-purpose processor and digital design in developing an electronic application. (2 marks) (c) There are four principals to effectively and quickly achieve the design. With an example, explain the regularity principle using your own words. (4 marks) (d) Discuss how a two-input LUT in the FPGA implements a logic f = a b + ab
The two-input LUT is a very versatile logic element that can be used to implement a wide variety of functions.
a) Behavioral modeling in Verilog HDL is a high-level language that allows you to describe the behavior of a digital circuit without worrying about the underlying hardware implementation. This makes it a very effective way of describing digital circuits, as it allows you to focus on the functionality of the circuit without getting bogged down in the details of how it will be implemented.
b) The main difference between using a general-purpose processor and digital design in developing an electronic application is that a general-purpose processor is designed to be able to execute a wide variety of instructions, while digital design is specifically designed to implement a particular function. This means that a general-purpose processor may not be the most efficient way to implement a specific function, as it may require more hardware resources than a custom-designed digital circuit.
c) The four principles for effectively and quickly achieving the design are:
Regularity: The design should be as regular as possible. This means that the design should be made up of a small number of repeated units, rather than a large number of unique units.
Simplicity: The design should be as simple as possible. This means that the design should be easy to understand and implement.
Efficiency: The design should be as efficient as possible. This means that the design should use the minimum amount of hardware resources.
Verifiability: The design should be verifiable. This means that the design should be able to be checked to ensure that it meets its specifications.
The regularity principle can be explained by the following example. If you are designing a digital circuit to add two numbers, you could use a design that is made up of a small number of repeated units, such as adders and registers. This would be a more regular design than a design that used a large number of unique units, such as a custom-designed adder. A more regular design is easier to understand and implement, and it is also more likely to be efficient.
d) A two-input LUT in the FPGA implements a logic f = a b + ab by storing the truth table for the function in its memory. When the inputs to the LUT are applied, the LUT will output the corresponding value from its memory.
For example, if the inputs to the LUT are a = 0 and b = 1, the LUT will output the value 1, because the truth table for f shows that the output is 1 when a = 0 and b = 1.
The two-input LUT is a very versatile logic element that can be used to implement a wide variety of functions. It is a key building block in many FPGA designs.
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A hot-air balloon with a mass of 400 kilograms moves across the sky with 3,200 joules of kinetic energy. The velocity of the balloon is meters/second.
Answer:
4 m/s
Explanation:
KE =
Velocity of balloon will be 4 m/s.
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When you are playing pool and a moving ball hits a stationary ball and the moving ball stops what happens to the momentum of the moving ball?
When a moving pool ball hits a stationary ball, some kinetic energy from the moving pool ball is transferred to the stationary ball and it attains momentum.
Both in the case of elastic and inelastic collisions, momentum is preserved. That means the total momentum will always be the same.
Momentum (ρ) is defined as "mass in motion". There are two factors affecting the momentum. Mass(m) and velocity(v).
ρ = m×v
So for a stationary object momentum will be 0. When the moving ball hits the stationary ball, it starts moving, because it gets kinetic energy from the moving ball. The total momentum before and after the collision will always be equal.
mₐ₁× vₐ₁ = mₐ₂×vₐ₂ + m₂ v₂
mₐ₁× vₐ₁ is the momentum of ball A before the collision
mₐ₂×vₐ₂ is the momentum of ball A after collision
m₂ v₂ is the momentum of ball B after collision.
So the stationary ball begins to move after the collision due to increased kinetic energy and attains some momentum. The total momentum of the system remains the same.
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It is possible to change the priority of an OCR job in Workspace Mode. True or false
True. In Workspace Mode, it is possible to change the priority of an OCR (Optical Character Recognition) job.
OCR is a process that converts scanned images or printed text into machine-readable text that can be edited and searched. Depending on the size and complexity of the document, OCR jobs can take longer to process than other tasks in Workspace Mode. By changing the priority of the OCR job, users can ensure that it is given higher processing power and completed faster. To change the priority of an OCR job, users can navigate to the "Processing" tab in Workspace Mode and select the OCR job they want to modify. From there, they can adjust the priority level and save the changes. It is important to note that changing the priority of an OCR job may impact the processing of other tasks in Workspace Mode, so users should consider their overall workload before making any adjustments.
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A car moves along a curved road of diameter 2 km. If the maximum velocity for safe driving on this path is 30 m/s, at what angle has the road been banked? (Ignore friction. )
A)11°
B)22. 6°
C)45. 2°
D)5. 26°
Answer:
b
Explanation:
θ = tan^-1(v^2/rg)
where θ is the angle of banking, v is the maximum velocity for safe driving, r is the radius of the curve (half the diameter), and g is the acceleration due to gravity.
Plugging in the values, we get:
θ = tan^-1((30 m/s)^2 / (1000 m * 9.8 m/s^2))
θ ≈ 22.6°
Therefore, the answer is (B) 22.6°.