m= 2.4 kg
Amplitude = maximum displacement = 3 cm
period = time to complet 1 cycle = T = 0.8 s
frequency = 1/T = 1 /0.8 = 1.25 hz
angular frequency = ω= 2 pi f = 2 pi x 1.25 = 7.85 rad/s
Constant of the spring:k
ω = √k/m
k = ω^2 m = (7.85)^2 * 2.4 = 147.894 N/m
Answers:
A) Period = 0.8 s
B) Frequency = 1.25 hz
C) Angular Frequency= 7.85 rad/s
D) Amplitude =3cm
E) Spring Constant = 147.894 N/m
What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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1. A student walks first 70m in the direction 37° north of east, and then walks 82m in the direction 20° south of east, and finally walks 28m in the direction 30° west of north. a. How far and at what angle is the student’s final position from her initial position? b. In what direction would she has to head to return to her initial position?
a. The student's final position is 100.5 meters at an angle of 25.2° north of east from her initial position and b. The student would have to head in the direction of 334.8° south of east to return to her initial position.
a. To find the student's final position, we can use vector addition. We can start by breaking each displacement vector into its x- and y-components. First displacement (70 m at 37° north of east),
x-component = 70 cos(37°) = 56.02 m
y-component = 70 sin(37°) = 42.49 m
Second displacement (82 m at 20° south of east),
x-component = 82 cos(-20°) = 78.72 m
y-component = 82 sin(-20°) = -28.12 m
Third displacement (28 m at 30° west of north),
x-component = 28 sin(30°) = 14 m
y-component = 28 cos(30°) = 24.24 m
We can add the x-components and y-components separately to get the total displacement,
x-displacement = 56.02 m + 78.72 m - 14 m = 120.74 m
y-displacement = 42.49 m - 28.12 m + 24.24 m = 38.61 m
The magnitude of the total displacement is,
|d| = √(x-displacement² + y-displacement²)
|d| = √(120.74² + 38.61²)
|d| = 126.0 m.
The direction of the total displacement can be found using the inverse tangent function,
θ = atan(y-displacement/x-displacement)
θ = atan(38.61/120.74)
θ = 17.4° north of east. Therefore, the student's final position is 126.0 m at 17.4° north of east.
b. To return to her initial position, the student would need to walk the same distance and direction as her total displacement but in the opposite direction. The opposite direction of 17.4° north of east is 162.6° south of west. Therefore, she would need to walk 126.0 m at 162.6° south of west to return to her initial position.
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Where can you find most of earths freshwater
Answer:
HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!
Explanation:
HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!
Icecaps and Glaciers
Explanation:
Icecaps and Glaciers hold 68 percent of fresh water on earth :)
A roller coaster pushes a 27 kg person upward with a force of 432 N. What is the acceleration?
Given:
• Mass of person, m = 27 kg
,• Force = 432 N
Let's find the acceleration.
To find the acceleration, apply Newton's Second Law:
\(F=m*a\)Where:
F is the Force
m is the mass
a is the acceleration.
Rewrite the formula for a, plug in the values of m and F, the solve:
\(\begin{gathered} a=\frac{F}{m} \\ \\ a=\frac{432\text{ N}}{27\text{ kg}} \\ \\ a=16\text{ m/s}^2 \end{gathered}\)Therefore, the acceleration is 16 m/s².
ANSWER:
16 m/s²
How much work would it take to push two protons very slowly from a separation of 2e-10 m. (a typical atomic distance) to 3e-15 m. (a typical nuclear distance)?
If the protons are both released from rest at the closer distance, how fast are they moving when they reach their original separation?
The amount of work done to push the protons is 7.67 X 10⁻¹⁴ J. If the protons are both released from rest at the closer distance, then the speed at which they reach their original separation is 6.77 X 10⁶ m/s.
Initial distance = d = 2 X 10⁻¹⁰ m
Final distance = d' = 3 X 10⁻¹⁵ m
Mass of both protons = 1.6 X 10⁻²⁷ Kg each
Charge of both protons = q = 1.6 X 10⁻¹⁹ C each
The constant for proton energy = 1/(4πε) = 9 X 10⁹ Nm²/C²
The potential change changes when their is a change in the work done, thus, potential energy initially = U =
= U = 1/(4πε) X (q₁q₂ / d)
= U = ( 9 X 10⁹ X 1.6 X 10⁻¹⁹ X 1.6 X 10⁻¹⁹ ) / 2 X 10⁻¹⁰
= U = 11.52 X 10⁻¹⁹ J
Now, finial potential energy = U' =
= U' = 1/(4πε) X (q₁q₂ / d')
= U' = ( 9 X 10⁹ X 1.6 X 10⁻¹⁹ X 1.6 X 10⁻¹⁹ ) / 3 X 10⁻¹⁵
= U' = 7.68 X 10⁻¹⁴ J
Thus, the work done to push the two protons is the different between final potential energy and the initial potential energy = W =
= W = U' - U
= W =11.52 X 10⁻¹⁹ - 7.68 X 10⁻¹⁴
= W = 7.67 X 10⁻¹⁴ J
Now, the speed of protons while coming back to the original positions = V;
Work done is also equal to the sum of kinetic energy's, hence,
= W = KE + KE'
= W = (1/2)mv² + (1/2)mv'²
= W = 2 X (1/2)mV²
= V = √ (W / m)
= V = √ (7.67 X 10⁻¹⁴ / 1.6 X 10⁻²⁷)
= V = 6.77 X 10⁶ m/s
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Someone says, “The sun seems brighter because it is bigger than other stars.” What would you say?
Answer:The sun is not a particularly large star. It appears brighter because it is only 93 to 95 million miles away or about 8 light minutes. Whereas the next closest star is 4.5 light years away.
Explanation: does this need an explanation? no, exactly.
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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You hear the sound of the firing of a canon 5.0 seconds after seeing the flash. How far are you from the cannon?
Phrases in this set (10) 5.0 seconds after observing the flash, You should be 2.7 kilometers away. In an unidentified medium, the wavelength of a sound wave at 2280 Hz is 0.655 m.
What does wavelength actually mean?The distance between two identical locations (adjacent crests) as in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted across wires or space. In wireless systems, its length is commonly specified in meters (m), centimetres (cm), or micrometer (mm) (mm).
What does a wavelength look like?illustrations of wavelengths. All visible light has a wavelength between 400 and 700 nanometers (nm). Yellow light has a wavelength of about 570 nanometers. Infrared energy is defined as being "redder than red" but having a wavelength that's too long to be seen.
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What equation relates mechanical energy, thermal energy, and total energy when there is friction present in a system?
While driving south on hwy 400, Jim gets stuck travelling at 1.9 m/s behind a slow truck. He finally gets into a passing lane, hits the gas and speeds up with a constant acceleration of 0.060 m/s2. What is his velocity (m/s) after accelerating for 8.5 km?
Final velocity
\(vf\approx\text{ 31.99 m/s}\)Data & Formula:
. final velocity: vf = ?
. initial velocity : vi = 1.9 m/s
. acceleration : a = 0.060m/s^2
. distance : d = 8.5 km
\(vf\text{ = }\sqrt[]{vi^2+2ad}\)\(vf\text{ = }\sqrt[]{1.9^2\text{ + 2 }\cdot\text{ 0.060 }\cdot\text{ 8.5}}\)A 5 kg object is dropped from the top of a 40 m tall building. What is its initial potential energy? What is its velocity the instant it hits the ground? What is its velocity after it has fallen 25 m?
Answer:
GPE = mgh = 5.00 kg .
2.20 + 0.30 m = 122.5 J
Explanation:
A cat pushes a porcelain statue off a bookshelf with a speed of 0.5 m/s and it smashed on the floor 0.85 sec later.
Answer:
167?
Explanation:
i added both
if you have 34 pounds of meat at 200F and you immerse it in 15 liters of water at 25C what is the final temp of the water? ( specific heat of water= 4 184 J/kgC and the specific heat of meat= 3.42 KL/kg. K, Kelvin=C+273)
Answer:
The specific heat capacity is the heat or energy required to change one unit mass of a substance of a constant volume by 1 °C. The formula is Cv = Q / (ΔT ⨉ m)
a car accelerate uniformly from rest to a speed of 20m/s in 8seconds.the mass of the car is 1200kg. calculate the acceleration of the car
Answer:3000
Explanation:
given:u=0v=20m/st= 8sec
thereforea=v-u/t=20-0/8=20/8=5/2 m/som=1200 kg
thereforef=ma=1200*5/2=600*5=3000N
Kinematics Exercises[1] The acceleration of a particle in 1-D varies with time as: a(t) = pt² −qt³.Assuming that its initial position and velocity are zero:Find an expressions for the velocity v(t) and the position x(t).
From the acceleration yo can find the rest of the expressions by integrating the initial equations
\(\begin{gathered} a(t)=pt^2-qt^3 \\ v(t)=\int a(t)dt=\frac{pt^3}{3}-\frac{qt^4}{4}+c \\ d(t)=\int\int a(t)dtdt=\frac{pt^4}{12}-\frac{qt^5}{20}+ct+b \end{gathered}\)Is important to put the constants when you integrate, they can affect the result when you solve the system
\(\begin{gathered} v(0)=0=\frac{p(0)^3}{3}-\frac{q(0)^4}{4}+c \\ 0=c \\ d(0)=\frac{p(0)^4}{12}-\frac{q(0)^5}{20}+b=0 \\ 0=b \end{gathered}\)After having the expressions, you replace the assumptions, in this case, v and d are 0, when time t is 0
2) A 45-kg person steps on a scale in an elevator. The scale reads 460 N. What is the elevator doing?
Answer:
The elevator is stationary
For both circuits: Determine the potential difference on and the current through each resistor. Show your work and then check your answer with PhET
Answer:
Answer is explained in the explanation section below.
Explanation:
Note: This question is incomplete and lacks the necessary diagram of the circuits to solve for this question. However, I have found similar question on the internet and dragged the diagrams out of it. I have attached the diagrams of the circuits for your ease. It has two circuits to be solved. Attachment 1 refers to first circuit and Attachment 2 refers to second circuit.
Solution:
We are asked to find the potential difference and current through each resistor.
So,
Calculations for Circuit 1: Please refer to Attachment 1
First we need to find the Resistance:
Req = \(\frac{9 . 6}{9+6} +3\)
R = 6.6 Ohm
Now, we know that:
V = IR
So,
I = V/R
V = 12 V
I = 12 V/ 6.6 ohm
I = 1.82 Amperes.
Now,
The Potential Difference through 3 ohm resistor:
P.D = \(V_{3}\) = 1.82 x 3
\(V_{3}\) = 5.45 V
Now,
The Potential Difference through 6 ohm and 9 ohm resistor:
\(V_{6/9}\) = 12V - 5.45V
\(V_{6/9}\) = 6.545V
Now,
The current through 6 ohm is:
\(I_{6}\) = \(\frac{6.545}{6}\)
\(I_{6}\) = 1.09 A
Now,
The Current through 9 ohm is:
\(I_{9}\) = \(\frac{6.545}{9}\)
\(I_{9}\) = 0.72 A
Similarly,
Calculations for Circuit 2: Please refer to attachment 2:
Req = \(\frac{(30+50).90}{90+(30+50)} +20\)
Req = 62.35 ohm
I = V/R
I = 12 V/ 62.35ohm
I = 0.192 Amperes.
Now,
The The Potential Difference through 20 ohm resistor:
\(V_{20}\) = 20 x 0.192
\(V_{20}\) = 3.849 V
Now,
The The Potential Difference through 90 ohm resistor:
\(V_{90/(30+50)}\) = 12 - 3.849
\(V_{90/(30+50)}\) = 8.150
Now,
The Current through 90 ohm is:
\(I_{90}\) = 8.1509/90
\(I_{90}\) = 0.0905 Amperes
Now,
The Current through 30 and 50 ohm is:
\(I_{30/50}\) = 0.192 - 0.0905
\(I_{30/50}\) = 0.101 A
Now,
The Potential Difference through 50 ohm resistor:
\(V_{50}\) = 50 x 0.101
\(V_{50}\) = 5.094 V
The Potential Difference through 30 ohm resistor:
\(V_{30}\) = 30 x 0.101
\(V_{30}\) = 3.0566 V
A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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lectric Charges
The glass is attracting the pieces of paper. What does
this tell you about the charges on the glass and the
paper?
The glass and the paper have the same charge.
O The glass and the paper have different charges.
ONeither the glass nor the paper has a charge.
assignment questions
Answer:
which on a is the question
A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.
When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e
Answer:
e
Explanation:
It is noticed that one of the natural frequencies of NaCl crystal is 5.3x10¹⁵ Hz. If placed under pressure, the frequency is increased by a factor of 0.11 due to the compression of the atomic lattice changing the atomic spring constant. What is the relative change in the spring constant (∆k/k) Select one:
a. 0.11
b. 5.3×10-13
c. 0.33
d. 0.23
The relative change in the spring constant (∆k/k) is approximately 0.11. Option A
To find the relative change in the spring constant (∆k/k) of the NaCl crystal under pressure, we can use the equation :
Δf/f = -Δk/k
where Δf is the change in frequency, f is the initial frequency, Δk is the change in the spring constant, and k is the initial spring constant.
Given that the initial frequency is f = 5.3x10^15 Hz and the change in frequency is Δf/f = 0.11, we can rearrange the equation to solve for Δk/k:
0.11 = -Δk/k
Now we can solve for Δk/k:
Δk/k = -0.11
Since the value is negative, we can consider the absolute value to obtain the relative change in the spring constant:
Δk/k ≈ 0.11.
Option A is correct.
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Consider a fusion reaction in which a proton fuses with a neutron to form a deuterium nucleus. How much energy is released in this reaction?(The mass of the deuterium nucleus is 2.01355u). Answer in Me
The difference in mass is then 2.01649u - 2.01355u = 0.00294u. This means that the energy released in this reaction is equal to 0.00294u × (c^2) = 4.621 x 10^-12 J.
What is mass?
Mass is a measure of the amount of matter an object contains. It is different from weight, which is a measure of the force gravity exerts on an object. Mass is typically measured in kilograms (kg) or grams (g).
The energy released in this reaction is equal to the mass difference between the products and the reactants multiplied by the speed of light squared. In this reaction, the mass of the reactants (1 proton and 1 neutron) is equal to 1.007825u + 1.008665u = 2.01649u.
The mass of the product (deuterium nucleus) is 2.01355u.
This means that the energy released in this reaction is equal to 0.00294u × (c^2) = 4.621 x 10^-12 J.
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A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid. If the diameter of the rod is doubled, by how much would the rate of heat removal change
Complete question is;
A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid. If the diameter of the rod is doubled, by how much would the rate of heat removal change?
Answer:
182.84 %
Explanation:
Formula for rate of heat transfer of an infinite log fin is given as;
q_f1 = (π/2) × (hk)^(½)) × D^(3/2)) × (T_b - T_∞)
Where D is diameter.
Now, if the diameter of the rod is doubled, it means Diameter is now 2D.
Thus;
q_f2 = (π/2) × (hk)^(½)) × (2D^(3/2)) × (T_b - T_∞)
To find how much the rate of heat removal will change, we will calculate as follows;
((q_f2/q_f1) - 1) × 100
Plugging in the relevant expressions, we have;
([[(π/2) × (hk)^(½)) × ((2D)^(3/2)) × (T_b - T_∞)]/[(π/2) × (hk)^(½)) × (D^(3/2)) × (T_b - T_∞)]] - 1) × 100
Upon simplifying, we have;
(((2D)^(3/2))/(D^(3/2)) - 1) × 100
((2^(3/2)) - 1) × 100
This gives;
182.84 %
What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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A man is whirling a 0.25 kg ball on a 1.5 m long string at 3 m/s. Find the centripetal acceleration of this ball.
Question 2 options:
0.5 m/s2
13.5 m/s2
6 m/s2
2 m/s2
The centripetal acceleration of this ball is equal to 12 \(m/s^2\)
Given the following data:
Diameter = 1.5 mSpeed, V = 3 m/s.Mass = 0.25 kgRadius = \(\frac{Diameter}{2} = \frac{1.5}{2} = 0.75 \;meters\)
To find the centripetal acceleration of this ball:
The acceleration of an object along a circular track is referred to as centripetal acceleration.
Mathematically, the centripetal acceleration of an object is given by the formula:
\(A_c = \frac{V^2}{r}\)
Where:
Ac is the centripetal acceleration.r is the radius of the circular track.V is the velocity of an object.
Substituting the given parameters into the formula, we have;
\(A_c = \frac{3^2}{0.75}\\\\A_c = \frac{9}{0.75}\\\\A_c = \frac{9}{0.75}\)
Centripetal acceleration = 12 \(m/s^2\)
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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Question 43
In order for an open switch to cause a short circuit, what must be connected to the rest of the circuit ?
Answer:
a break in the circuit can also cause this problem
Refer to the picture!
(a) The work done by the donkey on the cart is 59,721.9 J.
(b) The work done by the force of gravity on the cart is -48,434.87 J.
(c) The work done on the cart by friction during this time is 11,315.12 J.
What is the work done by the donkey on the cart?(a) The work done by the donkey on the cart is calculated as follows;
Wd = Fd cosθ
where;
F is the applied force by the donkeyd is the displacementθ is the angle of inclinationWd = 375 N x 163 m x cos(12.3)
Wd = 59,721.9 J
(b) The work done by the force of gravity on the cart is calculated as;
Wg = Fg x d x cosθ
Where;
Fg is the force of gravityd is the displacementθ is the angle between the force of gravity and displacementθ = 90⁰ + 4.03⁰ = 94.03⁰
Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)
Wg = -48,434.87 J
(c) The work done on the cart by friction during this time is calculated as;
Wf = Ff x d x cosθ
where;
Ff is the force of friction;Ff = μmg cosθ
Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)
Ff = 69.59 N
Wf = 69.59 x 163 x cos (4.03)
Wf = 11,315.12 J
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Which of the following statements about random assignment is true?
•It works best with a larger number of participants because there is more opportunity for extraneous variables to be equally distributed to each group.
• It works best with a smaller number of participants because fewer participants means there will be fewer opportunities for extraneous variables to confound the results of a study.
• It is the only control technique that explicitly controls for extraneous variables.
• It is the only control technique that produces a sample that is representative of the population.
The following statements about random assignment is true:
It works best with a larger number of participants because there is more opportunity for extraneous variables to be equally distributed to each group.
Random assignment is a technique used in research studies to assign participants to different groups or conditions. Its purpose is to create equivalent groups, ensuring that any differences in the outcomes can be attributed to the treatment or intervention being studied rather than other factors. The statement that is true about random assignment is that it works best with a larger number of participants because there is more opportunity for extraneous variables to be equally distributed to each group.When the number of participants is larger, the random assignment process becomes more effective in creating groups that are balanced and representative of the population. This is because with a larger sample size, there is a greater chance that random assignment will distribute extraneous variables evenly across the groups. As a result, the groups are more likely to be comparable in terms of their characteristics and any potential confounding variablesOn the other hand, when the number of participants is smaller, there is a higher risk that random assignment may not effectively distribute the extraneous variables equally across the groups. This increases the potential for confounding variables to influence the outcomes of the study, limiting the validity and reliability of the results.While random assignment is an important control technique in research, it is not the only technique available. There are other control techniques such as matching, blocking, and stratification that can also be used to control for extraneous variables. Additionally, random assignment does not guarantee a sample that is representative of the population as it is focused on creating equivalent groups rather than representing the entire population.For more such questions on Random assignment, click on:
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