The work function of the metal surface is approximately -1.293 eV. This is determined by analyzing the photoelectron data using the equation V₀ = (hc/λ) - (Φ/e).
To calculate the work function of the metal we need to analyze the photoelectron data
For λ = 50 nm:
\(E_{(eV)\) = (6.626 × \(10^{(-34)\) J · s × 2.998 × \(10^8\) m/s) / (50 × \(10^{(-9)\) m) / (1.602 × \(10^{(-19)\) J/eV)
= 2.4818 eV
ϕ = 2.4818 eV - 21.31 V
= -18.8282 eV
For λ = 100 nm:
\(E_{(eV)\) = (6.626 × \(10^{(-34)\) J · s × 2.998 × 10^8 m/s) / (100 × \(10^{(-9)\) m) / (1.602 × \(10^{(-19)\) J/eV)
= 1.2415 eV
ϕ = 1.2415 eV - 9.331 V
= -8.0895 eV
Performing similar calculations for the remaining data points, we get:
For λ = 150 nm: ϕ = -6.0471 eV
For λ = 200 nm: ϕ = -4.0171 eV
For λ = 250 nm: ϕ = -2.3371 eV
For λ = 300 nm: ϕ = -1.2933 eV
Therefore, the work function (ϕ) for this surface is approximately -1.293 eV (to three significant figures), determined by photoelectron data.
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The complete question is:
The following data gives stopping potential V0 versus wavelength for photoelectrons produced from a metal surface. (Be sure to include the correct units and use three significant figures.)
Use an analysis similar to that used in the lab procedure to determine the work function (in eV) for this surface. (Use 1 eV = 1.602 × \(10^{(-19)}\) J, e = 1.602 × \(10^{(-19)}\) C, c = 2.998 × \(10^8\) m/s, and h = 6.626 × \(10^{(-34)}\) J · s = 4.136 × \(10^{(-15)\) eV · s as necessary.)
a 125 kg wrecking ball on a 15.4 m long cable is pulled back to an angle of 33.5 degrees and released. How much KE does it have at the bottom of its swing? (Unit = J)
Answer:
7.08
Explanation:
Distance v. Time
What is the velocity at 1 meters?
4.5
4
3.5
3
2.5
Distance (m)
2.
1.5
1
0.5
0
0
2
6
8
10
Time (s)
Answer:
4
(m)
2 ( s )
Explanation:
ok...........
Question 2 (5 points)
What is the frequency of a sound wave travelling through air at a speed of 340m/s with a wavelength of
1.71m?
Answer:
Frequency of sound wave = 198.83 hertz (Approx.)
Explanation:
Given:
Velocity of sound wave in air = 340 m/s
Wavelength = 1.71 meter
Find:
Frequency of sound wave
Computation:
Frequency = Velocity / Wavelength
Frequency of sound wave = Velocity of sound wave in air / Wavelength
Frequency of sound wave = 340 / 1.71
Frequency of sound wave = 198.8304
Frequency of sound wave = 198.83 hertz (Approx.)
An astronaut is planning a trip to a newly-discovered planet. According to 2 points
the Law of Universal Gravitation, the astronaut's weight on the new planet
will be greater than his weight on Earth if:
-the new planet has less gravity than Earth.
-the new planet has the same gravity as Earth.
-the new planet has more gravity than Earth.
-the gravity of the planet doesn't matter.
-Weight is the same everywhere in the
universe.
Answer:
The new planet has more gravity
Explanation:
gravity force = G m1 m2 / r^2
decresing r or increasing the planet mass will increase the force
What characteristics of the solar system would have to be known or calculated in order to send a
probe to a distant planet, such as Jupiter?
a. the effects due to the light from the distant stars
b. the effects due to the air in the solar system
c. the effects due to the gravity from the other planets
d. the effects due to the cosmic microwave background radiation
Answer:
A
Explanation:
The effects due to light from distant stars
The characteristics of the solar system would have to be known or calculated in order to send a probe to a distant planet, such as Jupiter, due to the effects of the gravity from the other planets. Hence, option C is the correct answer.
When sending a probe to a distant planet, such as Jupiter, one of the critical factors that would have to be known or calculated is the effects due to the gravity from the other planets in the solar system. The gravitational interactions between the planets can significantly influence the trajectory and path of the probe during its journey. Accurate calculations are necessary to ensure that the probe's trajectory is properly planned and adjusted to reach its destination with precision. Hence, option C is the correct answer.
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A disc is thrown through the air for 1.5 min with a power output of 12.5 W. How much work is done when throwing the disc?
Answer:
work = 1125 [J]
Explanation:
To solve this problem we must remember the definition of power, which is defined as the relationship between work and time. The power can be calculated using the following equation:
Power = work/time
Power = 12.5 [w]
work = joules [J]
time = 1.5 [min] = 90 [s]
work = 12.5*90
work = 1125 [J]
What does the acronym stand for?
Answer:
an abbreviation formed from the initial letters of other words and pronounced as a word (e.g. ASCII, NASA ).
Explanation:
....
Answer:
Definition of acronym:a word (such as NATO,radar or laser)formed from the initial letter or letters of each of the successive parts or major parts of a compound term also :an abbreviation (such as FBI formed from initial letters:intialism.
Explanation:
Hope it helps
A puddle of water slowly shrinks in the sun. After a few hours, the puddle has dried up completely. Is this an exception to the law of conservation of mass?
Which method of measuring distances would you use if you wanted to measure the distance to stars in a nearby galaxy?
Since space is so vast, many astronomers choose to use a unit of measurement known as a parsec instead of measuring distances in miles or kilometers. the nearest star, Alpha Centauri, in your mind
what is A parsec is either a time or a distance measurement.Why then would Solo use a parsec, which measures distance rather than time, to describe how fast his ship could move? Here, two distinct narratives are in play.
Why then does Han Solo claim that it is 12 parsecs?The Kessel RuEmpire then was among the busiest smuggling routes in the Galactic Empirethe Galactic Empire, the Kessel Run was one of the busiest smuggling routes. The Kessel Run, according to Han Solo, was completed by his Millennium Falcon in fewer than twelve parsecs. Unlike time, a parsec measures distance. When he said this, Solo wasn't specifically referring to his ship's speed speed of his ship.
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A tennis ball is thrown straight up into the air with an initial velocity of 9.5 m/s. How long does it take to reach the top of the trajectory?
Answer:
0.969 s (3 s.f.)
Explanation:
Constant Acceleration Equations (SUVAT)
\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Acceleration due to gravity: g = 9.8 ms⁻²
Resolving vertically, taking up as positive:
u = 9.5 m/sv = 0 m/s\(\begin{aligned}\textsf{Using} \quad v&=u+at:\\\\0&=9.5+(-9.8)t\\-9.5&=-9.8t\\t&=\dfrac{-9.5}{-9.8}\\t&=0.9693877551\\\implies t&=0.969\; \sf s\;(3\:s.f.)\end{aligned}\)
Therefore, it takes 0.969 s (3 s.f.) for the tennis ball to teach the top of its trajectory.
All stars are the same color as our Sun. B) Hot stars are much brighter than cool stars of the same size and distance from the Earth.
Not all stars are the same color as our Sun; hot stars are indeed brighter than cool stars of equal size and distance.
Stars come in a variety of colors, ranging from red to blue, which are determined by their temperature.
Our Sun is classified as a yellow dwarf star. Hotter stars, such as blue stars, emit more light and appear brighter compared to cooler, red stars of the same size and distance from Earth.
This difference in brightness is due to the fact that hotter stars radiate more energy across the electromagnetic spectrum.
Therefore, it is not accurate to say that all stars are the same color as our Sun, and it is true that hot stars are much brighter than cool stars when size and distance are equal.
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A heart defibrillator being used on a patient has an RC time constant of 10.0 ms due to the resistance of the patient and the capacitance of the defibrillator. (a) If the defibrillator has an 8.00-μF capacitance, what is the resistance of the path through the patient? (You may neglect the capacitance of the patient and the resistance of the defibrillator.) (b) If the initial voltage is 12.0 kV, how long does it take to decline to 6.00×102 V ?
(a) The resistance of the path through the patient if the defibrillator has an 8.00-μF capacitance = 1.25 × 10³ Ω.
(b) It takes 7.69 ms to decline to 6.00 × 10² V
The RC time constant is given by the equation:
τ = RC
Where
τ is the time constant
R is the resistance, and
C is the capacitance.
Hence,
R = τ / C
R = (10.0 ms) / (8.00 μF)
R = 1.25 × 10³ Ω
So the resistance of the path through the patient is 1.25 × 10³ Ω.
The voltage of a capacitor as a function of time is given by the equation:
V(t) = V₀e^(-t/τ)
Where
V(t) is the voltage at time t
V₀ is the initial voltage, and
τ is the time constant.
Hence,
:t = -τ ln(V(t)/V₀)
Substituting the given values for the initial voltage, the final voltage, and the time constant:
t = -(10.0 ms)ln((6.00 × 10² V)/(12.0 kV))t
= 7.69 × 10⁻³ st
= 7.69 ms
So it takes 7.69 ms for the voltage to decline to 6.00 × 10² V.
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A 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. Answer the following questions. In your explanations, address the fact that the marbles have different masses and. different speeds. [1] (a) Which marble hits the ground first and why? (b) Which marble travels farther and why?
(a) It can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.
(b) Both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.
According to the given statement, a 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. The questions to answer are as follows:
(a) The acceleration due to gravity is constant at 9.8 m/s², according to Newton's Law of Gravitation.
According to the law of physics, heavier objects fall faster than lighter ones, but since the 10-gram marble has a speed that is five times faster than the 100-gram marble, it implies that the 10-gram marble covers more ground in less time than the 100-gram marble as acceleration is directly proportional to the force applied.
The time taken by both marbles to reach the ground is given byt = √(2h/g)where h is the height from which the marbles were dropped, and g is the acceleration due to gravity.
The height from which the marbles were dropped is the same in both cases, so it can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.
(b) The range traveled by both marbles is determined by the horizontal component of their velocity. It's worth noting that the horizontal components of their velocities are identical since they were launched from the same height, so there's no advantage for either marble.
The range of a projectile is determined by the formula:
R = u²sin(2θ)/g where R is the range, u is the velocity of the object, θ is the angle of the initial velocity with the horizontal, and g is the acceleration due to gravity.
Since the angle of the initial velocity with the horizontal is the same for both marbles, and their initial velocity is also the same, it can be stated that both marbles travel the same distance.
Therefore, both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.
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Match each vocabulary word with appropriate definition. chemical property chemical change reactivity combustibility
Answer:
1.) Chemical Change - a change in matter that results in a change in its identity and properties
2.) Combustibility - the ability of a substance to burn
3.) Reactivity - The ability of a substance to combine Chemically with another
4.) Chemical Property - the ability of matter to change into a different substance
Explanation:
Proof: -Image Below & the definitions for each word-
Chemical Change- Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. ... An example of a chemical change is the reaction between sodium and water to produce sodium hydroxide and hydrogen.
Combustibility- Combustibility is a measure of how easily a substance bursts into flame, through fire or combustion. This is an important property to consider when a substance is used for construction or is being stored. It is also important in processes that produce combustible substances as a by-product.
Reactivity- In chemistry, reactivity is the impetus for which a chemical substance undergoes a chemical reaction, either by itself or with other materials, with an overall release of energy.
Chemical Property- A chemical property is any of a material's properties that becomes evident during, or after, a chemical reaction; that is, any quality that can be established only by changing a substance's chemical identity. ... They can also be useful to identify an unknown substance or to separate or purify it from other substances.
Have a nice day!
Chemical change - A change in a substance that brings a change in its identity and properties
Combustibility - The ability of a substance to bursts into the combustion
Reactivity - The ability of a matter to chemically combine with others.
Chemical Property - The ability of a substance to change into a completely different substance.
What are chemical properties, chemical change, reactivity, and combustibility?Chemical changes take place when a substance combines with another substance to create a new substance, called chemical synthesis. An example of a chemical change is the formation of sodium hydroxide and hydrogen by the reaction between sodium and water.
Combustibility determines how easily a substance can burst into flame, through combustion. The combustibility is a property to consider when a substance is used for storage or for construction. It is also an important property in processes where the formation of combustible substances is a side product.
In chemistry, reactivity is the property of a chemical substance that undergoes a chemical reaction with itself or with other chemicals, and the overall release of energy.
Chemical properties are the characteristics of a particular substance that can be noticed during a chemical reaction. Some major chemical properties include heat of combustion, flammability, rate of radioactive decay, toxicity, pH value, and chemical stability.
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Which statements describe a situation in which work is being done? Select three options.
Answer:
here's the answers!
Explanation:
A mover carries a box up a flight of stairs.
A mover carries a box across a room.
A weightlifter lifts a barbell off the ground.
hope it helps u!
Answer:
A, D, E
Explanation:
Did it
In an elastic collision, bumper cars 1 and 2 are moving in the same direction when bumper car 1 rear-ends bumper car 2. The initial speed of bumper car 1 is 6.71 m/s and that of bumper car 2 is 4.93 m/s. The bumper cars have the same mass. Take the positive direction to be the direction in which the bumper cars are moving.
What is the final velocity, in meters per second, of bumper car 1?
What is the final velocity, in meters per second, of bumper car 2?
The final velocities of bumper car 1 is 6.17 m/s, and the final velocity of bumper car 2 is 5.47 m/s.
What is the final velocity?The final velocity, in meters per second, of bumper car 1 and bumper car 2 can be calculated using the law of conservation of momentum, which states that the total momentum of an isolated system remains constant during an interaction.
Since the collision is elastic, the kinetic energy is also conserved. Here's how to calculate the final velocity of bumper car 1 and bumper car 2:
Initial velocity of bumper car 1, u₁ = 6.71 m/s
Initial velocity of bumper car 2, u₂ = 4.93 m/s
Final velocity of bumper car 1, v₁ = ?
Final velocity of bumper car 2, v₂ = ?
Since the bumper cars have the same mass, m₁ = m₂ = m (say)
According to the law of conservation of momentum,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Let's substitute the values:
mu₁ + mu₂ = mv₁ + mv₂
(m₁ + m₂)u₁ = m₁v₁ + m₂v₂
Now, substitute the mass and velocity values:
m × 6.71 + m × 4.93 = m × v₁ + m × v₂
Simplifying the above equation, we get:
v₁ + v₂ = 11.64 ...(1)
Similarly, using the law of conservation of kinetic energy, the final velocities can be determined. It is given by,
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
Substituting the values, we get:
m × 6.71² + m × 4.93² = m × v₁² + m × v₂²
Simplifying the above equation, we get:
v₁² + v₂² = 62.98 ...(2)
From equations (1) and (2), we can solve for v₁ and v₂ by elimination method as follows:
v₁ + v₂ = 11.64 ...(1)
v₁² + v₂² = 62.98 ...(2)
Multiplying equation (1) by v₁ and subtracting it from equation (2), we get:
v₁² + v₂² - v₁² - v₁v₂ = 62.98 - 11.64
v₁v₂ = 51.34 ...(3)
Again, subtracting equation (1) from equation (2), we get:
v₁² + v₂² - v₁² - 2v₁v₂ - v₂² = 62.98 - 11.64
v₁v₂ = 25.07 ...(4)
Now, solving equations (3) and (4), we get:
v₁ = 6.17 m/s, v₂ = 5.47 m/s
Therefore, the final velocity of bumper car 1 is 6.17 m/s, and the final velocity of bumper car 2 is 5.47 m/s.
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How do you write a vector as a linear combination of another vector?
Express the first vector as the sum of the second vector's scalar multiples to represent a vector as a linear combination of another vector.
Finding scalar coefficients that, when multiplied by the components of the other vector, will add up to the components of the original vector is necessary to represent a vector as a linear combination of another vector. For instance, if you have a vector (a, b) and another vector (c, d), you may find scalars x and y such that x(c, d) + y(a, b) = in order to represent the original vector as a linear combination of the second vector (a,b). You obtain x = (ad-bc)/(cd-bd) and y = (ac-bd)/ after solving for x and y. (cd-bd). The linear combination of the two vectors is then obtained by filling in the values of x and y.
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a child pulls a friend in a little wagon with constant speed. if the child pulls with the force of 16 n for 10.0 m and the handle of the wagon is inclined 25 degrees with respect to the horizontal, how much work does the child do on the wagon?
The work done by the child on the wagon is 158.4 J
Work done is defined as the product of the force applied on the object and the component of distance traveled by the object in the direction of the force. Mathematically,
W = FdCosθ
where,
W = work done = ?
F = force applied = 16 N
d = displacement = 10 m
θ = angle of inclination = 25°
Therefore,
W = (16 N) (10 m)Cos(25°)
W = 158.4 J
Hence, work done by the child on the wagon is 158.4 J
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A sample of gas has a pressure of .87atm at 25 ˚C. What is its pressure when the temperature is increased to 50˚C?
It states that: "At constant volume the pressure of a gas sample is directly proportional to the absolute temperature."
This means that doubling the pressure of the gas will cause its absolute temperature to double.
Mathematically this law is expressed as:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_{1}}{T_{1}}=\frac{P_{2}}{T_2} \iff \ P_1T_2=P_2T1 } \end{gathered}$} }\)
We have that the data is:
P₁ = 0.87 atm
T₁ = 25 °C + 273 = 298 K
T₂ = 50 °C + 273 = 323 K
P₂ = ?
We clear for the final pressure:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{P_{2}=\frac{P_1T_2}{T_{1}} } \end{gathered}$}}\)
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{P_{2}=\frac{(0.87 \ atm)\cdot(323\not{k})}{298\not{k}} } \end{gathered}$}}\)
\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{P_{2}=0.94 \ atm } \end{gathered}$}}}\)
If the temperature increases to 50°C, its new pressure will be 0.94 atm.A 42.0-cm-diameter wheel, consisting of a rim and six spokes, is constructed from a thin, rigid plastic material having a linear mass density of 25.0 g/cm. this wheel is released from rest at the top of a hill 69.0 m high.
For a 42.0-cm-diameter wheel, consisting of a rim and six spokes,the angular speed is mathematically given as
w=118.6 rad/s
What is the angular speed?
Generally, the equation for the Conservation of energy is mathematically given as
K1+U1=K2+U2
Therefore
Mgh+0=0+(1/2)MV2+(1/2)Iω2
Where
M=m+6m
M=2rλ(π+3)
Therefore
\(2r \lambda (\pi+3)gh=0.52r \lambda (\pi+3)(rw)2+(1/2)[(2 \pi \lambda r)r2+6( \lambda r)r2/3]w2\)
\(w=\sqrt{[(\pi+3)*9.8*53/(0.42/2)2*(\pi+2)\)
w=118.6 rad/s
In conclusion, The angular speed is
w=118.6 rad/s
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explain; water wets glass surface but does not wet the waxed glass surface pliz answer and will follow
Answer:
Recycled answer from jaskhanna07343
Explanation:
Water does not wet waxed surfaces because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water
2. It is weigh-in time for the local under-85-kg rugby team. The bathroom scale used to assess eligibility can be described by Hooke’s law and is depressed 0.75 cm by its maximum load of 120 kg. (a) What is the spring’s effective spring constant? (b) A player stands on the scales and depresses it by 0.48 cm. Is he eligible to play on this under-85 kg team?
Please include all of your steps.
Apply hooke's law
\(\\ \rm\rightarrowtail F=kx\)
\(\\ \rm\rightarrowtail 1176=k(0.0075)\)
\(\\ \rm\rightarrowtail k=156800N/m\)
#b
We need mass again
\(\\ \rm\rightarrowtail F=kx\)
\(\\ \rm\rightarrowtail mg=kx\)
\(\\ \rm\rightarrowtail 9.8m=156800(0.0048)\)
\(\\ \rm\rightarrowtail 9.8m=752.64\)
\(\\ \rm\rightarrowtail m=76.8kg\)
He is e eligibleMolly is pulling a cart down the hallway. She stops at each classroom and collects a stack of books from each teacher. After stopping at 5 classrooms, she can no longer move the cart by herself and her friend Regan needs to help her pull the cart. How does this SHOW Newton's 3rd Law? Do NOT just state the law!!
Answer:
His third law states that for every action or force in nature there is an equal and opposite reaction.
Explanation:
The heavier the books get, the harder it is for Molly to exert enough force to move the cart.
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help me please!! in a stankey diagram, what does the thickness of the lines represent?
Answer: The thickness of the vertical flow lines indicates the relative quantity.
The thickness of the vertical flow lines indicates the relative quantity.
What is vertical flow?A vertical flow constructed wetland is a planted filter bed that is drained at the bottom. Wastewater is poured or dosed onto the surface from above using a mechanical dosing system. The water flows vertically down through the filter matrix to the bottom of the basin where it is collected in a drainage pipe.Vertical flow immunoassays rely on the same basic principles as the more common lateral flow immunoassay format with some modifications. The most apparent difference between the two methods being the vertical and lateral flow of fluid. However, vertical flow technology has several advantages over traditional lateral flow assays with the most significant being the reduced assay time (<5 minutes), table I.To learn more about vertical flow refer to:
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Newton's Law with Friction (Force on Angle) please help
The Acceleration of the system as depicted in the diagram is 1.38 m/s².
What is acceleration?Acceleration is the rate of change of velocity. The S.I unit of acceleration is m/s²
To calculate the acceleration of the system, we use the formula below.
Formula:
a = (Fcos∅-mgμ)/m.......... Equation 1Where:
a = Acceleration of the systemm = Mass of the systemF = Force applied to the system at a certain angleg = Acceleration due to gravity∅ = Angle at which the force was appliedμ = Coefficient of static frictionFrom the question,
Given:
m = 1.1 kgF = 5.4 N∅ = 54.6°μ = 0.15g = 9.8 m/s²Substitute these values into equation 1
a = {(5.4cos54.6°)-(1.1×9.8×0.15)}/1.1a = (3.13-1.617)/1.1a = 1.38 m/s²Hence, the acceleration of the system is 1.38 m/s².
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what is the phase defig. 1 resistor circuit1) find vr(t) and ir(t)2) what is the phase difference between vr(t) and ir(t)?
The phase defig in an resistor electrical circuit refers to the phase difference between the voltage and the current.
In a resistor circuit, the voltage (vr) and the current (ir) are related by Ohm's law: vr = irR, where R is the resistance of the resistor. To find vr(t) and ir(t), we need to know the time-dependent behavior of the voltage and the current.
Assuming that the circuit is driven by a sinusoidal voltage source with a frequency of ω, we can express the voltage and the current as vr(t) = Vrms*cos(ωt + φv) and ir(t) = Irms*cos(ωt + φi), where Vrms and Irms are the root-mean-square values of the voltage and the current, and φv and φi are the phase angles of the voltage and the current, respectively.
To find vr(t) and ir(t), we need to determine Vrms, Irms, φv, φi, and R. Once we have these values, we can use the above equations to calculate vr(t) and ir(t).
To determine the phase difference between vr(t) and ir(t), we need to calculate the phase angle φ = φv - φi. The phase angle represents the difference in time between the peaks of the voltage and the current waveforms.
In summary, the phase defig in an electrical circuit refers to the phase difference between the voltage and the current.
To find vr(t) and ir(t), we need to know the time-dependent behavior of the voltage and the current, which can be expressed in terms of Vrms, Irms, φv, φi, and R. The phase difference between vr(t) and ir(t) can be calculated as φ = φv - φi.
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What can waves be transmitted by? How do you know?
Answer:
i don’t know what kind of waves you mean but if you’re talking about sound waves...
Explanation:
“Sound waves are transmitted through solids, liquids, and gases. Light waves are transmitted through transparent materials (may be clear or colored material such as filters) that allow most of the light that strikes them to pass through them. Only a small amount of light is reflected or absorbed.”
What happens to the density of an object if the mass increases, but the volume remains the same?
A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.
a boy on a skateboard pushes off the ground with his foot. he and the skateboard accelerate down the sidewalk due to the force
A boy on a skateboard pushes off the ground with his foot. he and the skateboard accelerate down the sidewalk due to the force on the ground in one direction.
The ground applies an equal and opposite force on the boy in the opposite direction. This force causes the boy and the skateboard to accelerate forward.
According to Newton's second law of motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.
Therefore, the acceleration of the boy and the skateboard will depend on the force applied by the boy's foot and the combined mass of the boy and the skateboard.
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A 500-g cart moving at 2. 0 m/s on an air track elastically strikes a 1,000-g cart at rest.
What are the resulting velocities of the two carts?
The resulting velocity of the 500-g cart is 0 m/s. The resulting velocity of the 1000-g cart is 1 m/s.