Given
AB stage
v_o = initial velocity
v_o = 0 m/s
a = 0.40 m/s2
d = 20m
BC stage
v = constant
t = 10s
Procedure
To calculate the average speed we need to calculate the total distance and total travel time. To do this, let us calculate the final velocity at point B
\(\begin{gathered} v_B^2=v_o^2+2ax \\ v_B=\sqrt{2ax} \\ v_B=\sqrt{2*0.4*20} \\ v_B=4m/s \end{gathered}\)Therefore, we can calculate the time on path AB as follows
\(\begin{gathered} v_B=at \\ t=\frac{v_B}{a} \\ t=\frac{4}{0.4} \\ t=10s \end{gathered}\)An electron moving in the y direction, at right angles to a magnetic field, experiences a magnetic force in the -x direction. The direction of the magnetic field is in the
Answer:
The direction of magnetic field is along + Z axis.
Explanation:
The direction of motion of electron is along y axis.
The magnetic force is along - X axis.
The force on the charged particle moving in the magnetic field is
\(\overrightarrow{F} = q (\overrightarrow{v}\times \overrightarrow{B})\\\\- F \widehat{i} = - q (v \widehat{j}\times \overrightarrow{B})\\\)
So, the direction of the magnetic field is along + Z axis.
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Please answer these questions correctly (photo is attached) I’ll give brainliest
a student standing on the ground throws a ball straight up. the ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground.you may want to review (page) .for help with math skills, you may want to review:quadratic equationsfor general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of time in the air for a tossed ball.
Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionThe equations apply in uniformly accelerated straight motion in vertical dimension are
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + ½ gt²
Where
v₀ = initial velocityv₁ = final velocityg = acceleration due to gravityt = timeh = height of objectA student standing on the ground throws a ball straight up with
Initial height, h₁ = 2.5 mSpeed of the ball at h₁, v₀ = 13.0 m/sFind the time it takes for the ball to reach the ground!
We use g = 9.8 m/s². See the illustration picture in the attachment!
The ball will go upward and stop at a certain height with v₁ = 0. The time needed is
v₁ = v₀ - gt₁
0 = 13.0 - 9.8t
13.0 = 9.8t
t₁ = 13.0/9.8
t₁ = 1.3 s
The height above the hand when the ball stops is
v₁² = v₀² - 2gh₂
0 = 13.0² - 2(9.8)h₂
13.0² = 2(9.8)h₂
169 = 19.6h₂
h₂ = 8,62 m
The ball stops at a height of
h₃ = h₁ + h₂
h₃ = 2.50 + 8.62
h₃ = 11.12 m
The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is
h₃ = v₁t + ½ gt₂²
11.12 = 0 + ½ (9.8)t₂²
11.12 = 4.9t²
t₂² = 2.27
t₂ ≈ 1.5 s
The time that the ball in the air is
t = t₁ + t₂
t = 1.3 + 1.5
t = 2.8 s
Hence, the ball is in the air for 2.8 seconds.
Your question is incomplete, but most probably your full question was
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).
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a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
The block comes to a rest from 12 m/s with acceleration 3 m/s^2, which is carried out over a distance x such that
(12 m/s)^2 - 0^2 = 2 (3 m/s^2) x
=> x = (12 m/s)^2 / (2 (3 m/s^2)) = 24 m
The force itself has a magnitude F such that
F = (4 kg) (3 m/s^2)
=> F = 12 N
This force is pointing opposite the direction in which the block is moving, so the work it's performing is negative, and the work done is
W = - (12 N) (24 m) = -288 Nm = -288 J
which makes C the answer.
A pendulum made of a uniform rod with a length of 50.0 cm is set into simple harmonic motion about one end on Earth's surface. Calculate the period of its motion.
The period of the motion made by a simple pendulum of length 50 cm is 1.42 seconds.
What is Period?Period can be defined as the time taken for a body to complete one revolution.
To calculate the length of the period of the motion, we use the formula below.
Formula:
T = 2π√(L/g)............... Equation 1Where:
T = Period of the simple pendulumL = Length of the simple pendulumg = Acceleration due to gravityFrom the question,
Given:
L = 50 cm = 0.5 mg = 9.8 m/s²π = 3.14Substitute these values into equation 1
T = 2×3.14×√(0.5/9.8)T = 1.42 secondsHence, the period of the motion is 1.42 seconds.
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How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?
Hi there!
We know that:
I = mΔv = F · t
We are given that:
Δv = 2 m/s
m = 1,500 kg
F = 600 N
Solve for t:
mΔv = Ft
mΔv/F = t
Plug in values:
(1,500)(2)/600 = 5 sec
Two lenses, one converging with focal length 10.0 cm and one diverging with focal length -5.0 cm, are placed 13.0 cm apart. An object is placed 30.0 cm in front of the converging lens. Determine the position of the final image formed.
Two lenses, one converging with a focal length of 10.0 cm and one diverging with a focal length of -5.0 cm, are placed 13.0 cm apart, the position of the final image formed is mathematically given as
u=70.645
What is the position of the final image formed.?Generally, the equation for the convex lens is mathematically given as
I/f=1/u-1/v
Therefore
1/20=1/u-(1/-61)
u=29.76cm
In conclusion, For concave lens
1/-10=1/u-1/8.76
u=87.6/1.2
u=70.645
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Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with the ground what is the horizontal component of Barney’s velocity
Answer:
Explanation:
The horizontal velocity is 1.61.
The
is located 12 to 50 kilometers from Earth’s surface.
Both the
get colder as altitude increases.
The ozone in the
protects people from ultraviolet (UV) radiation.
The
has the highest temperature of any layer in Earth’s atmosphere.
The thermosphere has the highest temperature of any layer in Earth’s atmosphere.
What is the atmosphere?The term troposphere is the region that is found 12 to 50 kilometers from Earth’s surface. This region is found to be the region where you can find a lot of gases.
Both the Troposphere and the stratosphere get colder as altitude increases. However, the ozone in the stratosphere protects people from ultraviolet (UV) radiation.
The thermosphere has the highest temperature of any layer in Earth’s atmosphere.
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An object has mass M (uppercase) and is located at the origin of the coordinate system. A second object has mass m (lowercase) and is located at a distance r from the origin. This exercise explores the potential energy of the two-mass system. A spherical coordinate system is appropriate, but only the radial direction, r^, needs to be considered.
Enter a vector expression for the force, F⃗ , acting on mass m . The expression must be valid for all values of the radial coordinate, 0 0, and the zero of potential energy is taken as limr→∞UG=0.
Mass of the second object located at a distance r from the origin, r^ is the unit vector in the radial direction, and the negative sign indicates that the force
What is a system ?The System can refer to a set of interacting or interdependent components forming an integrated whole. The term can be applied to various fields, including physics, engineering, biology, and social sciences, among others. In physics, a system typically refers to a collection of objects or particles that are studied together, often with the goal of understanding the behavior of the system as a whole. In engineering, a system can refer to a group of components that work together to perform a specific function, such as an electrical power grid or an automobile engine. In biology, a system can refer to an organism or group of organisms that interact with their environment, such as an ecosystem or the human body.
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An electric iron is Mark 120 volts and 500 Watts to units consumed by it in using it for 24 hours will be
An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I
Using the above formula, we can find the current drawn by the electric iron as follows:I = P/VI = 500/120I = 4.17 ATherefore, the power consumed by the electric iron in 24 hours is:P = VI x tP = 120 x 4.17 x 24P = 120 x 100.08P = 12010.56 watt-hoursTo convert watt-hours to kilowatt-hours, we divide by 1000: Energy consumed = 12010.56 / 1000Energy consumed = 12.01 kWhHence, the units consumed by the electric iron in 24 hours is 12.01 kilowatt-hours.For such more question on Voltage
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1. (a) Show that the rate of change of mechanical energy for a damped harmonic oscillator dE is given by -by, and hence it is always negative. dt
(b) A 0.40 kg mass attached to the free end of a spring with force constant k = 300 N m¹ is moving and is acted on by a damping force F = -bv.
i. If the constant b = 9.0 kg s¹, what is the frequency of oscillation of the mass? ii. For what value of the constant b will be the motion be critically damped?
2. A steady force of 120 N is required to push a 700 kg boat through water at a constant speed of 1.0 m/s. Assume that the damping force exerted by water is given by FD=-bv.
a) Determine the value of b.
b) The boat is fastened by springs on two posts as
shown in the figure and held at 2.0 m from its
equilibrium position by 450 N horizontal force
and released from rest at t=0. Determine
i. the spring constant of two springs, and
ii. how long it will take its amplitude to be decreases by a factor of 100.
3. A 1000 kg car carrying four 80 kg people travels over a rough dirt road with corrugations (bumps) 4.0 m apart, which cause the car to bounce on its spring suspensions. The car bounces with maximum amplitude when its speed is 16 km/h. The car now stops, and the four people get out. By how much does the car body rise on its suspensions due to this decrease in mass?
Rate of change of mechanical energy of damped oscillation, dE/dt = -bv² is proven.
What is meant by damped oscillation ?Damped oscillation is the type of oscillation during which the amplitude of the oscillation decreases with time. Damped oscillation occurs due to dissipating forces like resistance, viscosity, etc
Here,
1. (a) Total energy for a damped oscillation is,
E = 1/2 mv² + 1/2 kx²
Taking derivatives with respect to time,
dE/dt = 1/2m 2v(dv/dt) + 1/2k 2x(dx/dt)
dE/dt =mav + kxv
dE/dt = v(ma + kx)
We know, for a damped oscillation, the restoring force, F = -bv
So, dE/dt = v(-bv)
Therefore, dE/dt = -bv²
(b) m = 0.4 kg
k = 300 N/m
i) Frequency, f = (1/2\(\pi\)) [√(k/m) - (b²/2m)]
f = 4.056 s⁻¹
ii) For critically damped oscillation,
b = √4mk = √4x 0.4x 300
b = 21.9 kg/s
2. F = 120 N
m = 700 kg
v = 1 m/s
(a) F = -bv
b = F/v = 120/1
b = 120 kg/s
(b) x = 2 m
F = 450 N
i) F = kx
k = F/x = 450/2
k = 225 N/m
ii) A = A₀ e⁻λt where λ = b/2m
A = A₀/100
A₀/100 = A₀ e⁻λt
e⁻λt = 10⁻²
λt = 2
t = 2/λ = 4m/b = 4x 700/120
t = 23.3 s
(3) λ = 4m
v = 16 km/h = 4.44 m/s
f = v/λ = 4.44/4
f = 1.11 s⁻¹
We know that, f = 1/\(2\pi\) √(k/m)
On squaring,
k = mf²4\(\pi\)²
k = 1000x 1.11²x 4\(\pi\)²
k = 48.56x 10³
We know,
F = kx
mg = kx
x = k/mg = 48.56x 10³/(1200 + 320)9.8
x = 3.26 m
After unloading,
x' = 48.56x 10³/(1200x 9.8)
x' = 4.13 m
So,
ΔX = x' -x = 0.87 m
Hence,
Rate of change of mechanical energy of damped oscillation, dE/dt = -bv² is proven.
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817 cm3 at 80.8 kPa to 101.3 kPa: __________ cm3 (No temp. change)
The final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law can be represented by the equation: P₁V₁ = P₂V₂
Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
Given:
Initial volume, V₁ = 817 cm³
Initial pressure, P₁ = 80.8 kPa
Final pressure, P₂ = 101.3 kPa
We need to find the final volume, V₂.
Using Boyle's Law equation, we can rearrange it to solve for V₂:
V₂ = (P₁V₁) / P₂
Plugging in the given values:
V₂ = (80.8 kPa * 817 cm³) / 101.3 kPa
Simplifying the expression:
V₂ ≈ 652.9 cm³
Therefore, the final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.
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How are magnetic field lines different from electric field lines and why is there a difference? If you break in half a metal rod with a positive charge on one end and a negative charge on the other, what do you end up with? What do you end up with if you break a bar magnet in half? What does this tell us about electric and magnetic monopoles?
The magnetic field lines forms closed loops where as electric lines won't form closed loops. This is because for magnetic poles source and Sink lies at lame point means we cannot able to Separate Nortn and South poles. where as positive & negative charges can be separated
If we break a rod with half with one positive and other negative side charge is allow two magneted where as if we have magnet & if it is broken, then is forms two magnets. This is because magnetic poles cannot be seperated where as electric charges can be separated.Magnet always exists in dipole but charge can exists as mono as well as bi.To know more about magnetic field lines visit : https://brainly.com/question/17011493
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You have a parallel‑plate 5.13×10−6 F capacitor that is charged to 0.00967 C. While the capacitor is isolated, you change the plate separation so that the capacitance becomes 1.27×10−6 F. How much work do you perform in this process?
The work done to separate the plates of the parallel plate capacitor that's charged to a 0.00967 C is 2864.5 J
U = 1 / 2 C V²
U = Initial energy
C = Capacitance
V = Electric Potential
Q = Charge
C\(_{i}\) = 5.13 μ F
Q\(_{i}\) = 9.67 m C
C\(_{f}\) = 1.27 μ F
As the capacitor is isolated, there'll be no further current flow and charge will remain constant.
Q\(_{f}\) = Q\(_{i}\) = 9.67 m C
Q = C V
Q² = ( C V )²
U\(_{i}\) = 1 / 2 * C\(_{i}\) * V\(_{i}\)²
U\(_{i}\) = 0.5 * ( C\(_{i}\) * \(V_{i}\) )² / C\(_{i}\)
U\(_{i}\) = 0.5 * Q\(_{i}\)² / C\(_{i}\)
U\(_{i}\) = 0.5 * ( 9.67 * \(10^{-3}\) / 5.13 * \(10^{-6}\) )
U\(_{i}\) = 942.5 J
U\(_{f}\) = 1 / 2 * C\(_{f}\) * \(V_{f}\)²
U\(_{f}\) = 0.5 * ( C\(_{f}\) * \(V_{f}\) )² / C\(_{f}\)
U\(_{f}\) = 0.5 * Q\(_{f}\)² / C\(_{f}\)
U\(_{f}\) = 0.5 * ( 9.67 * \(10^{-3}\) / 1.27 * \(10^{-6}\) )
U\(_{f}\) = 3807 J
W = U\(_{f}\) - U\(_{i}\)
W = 3807 - 942.5
W = 2864.5 J
Therefore, the work done to separate the plates of the parallel plate capacitor is 2864.5 J
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Usually, we do a
when a population is hard to study, for some reason.
Usually, we use sampling when a population is hard to study, for some reason.
Sampling is a technique commonly employed in research and statistics when it is impractical or impossible to study an entire population directly. It involves selecting a subset, or sample, from the population and using the information gathered from the sample to make inferences about the entire population. This is done with the assumption that the sample is representative of the population and that the findings from the sample can be generalized to the larger population.
There are several reasons why a population might be difficult to study comprehensively. One reason is the size of the population. For example, if the population of interest is the entire world or a country, it would be practically impossible to study each individual in the population due to logistical constraints and limited resources. In such cases, sampling allows researchers to gather information from a smaller, manageable subset of the population.
Another reason for using sampling is when the population is dispersed or geographically scattered. If the population is spread out across a wide area, it can be challenging and costly to reach and collect data from every individual. Sampling allows researchers to select representative individuals or clusters from different regions, making data collection more feasible.
Additionally, there are cases where the population is inaccessible or hard to reach due to privacy concerns or ethical considerations. For example, if the population consists of individuals with certain medical conditions or sensitive personal information, it may be challenging to obtain consent or access to the entire population. In such cases, researchers can use sampling methods to obtain data from a subset of individuals who are willing to participate and meet the necessary criteria.
In summary, sampling is a valuable tool when studying populations that are hard to access, too large, or dispersed. It allows researchers to gather relevant data from a representative subset of the population and make valid inferences about the larger population, despite the challenges posed by studying the population as a whole.
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The question probable may be:
Usually, we use when a population is hard to study, for some reason.
How much power does the athlete produce if he has 28,056J of work over 45s?
Explanation:
Power = Work done ÷ Time
P = 28056 ÷ 45 Watt
P = 623.46 Watt
If an object accelerates at 40 m/s^2 in four minutes ("careful this is in minutes),
what will be the final velocity? (assume the object started from rest) *
Change in speed = (acceleration) x (time)
4 minutes = 240 seconds
Change in speed = (40 m/s²) x (240 seconds)
Change in speed = 9,600 m/s
What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.
The driver would definitely NOT get a speeding ticket, because nobody could catch him.
Also, his car would heat up and shoot flames from atmospheric friction.
(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)
Actually, I hope there's nobody in the car. His experience wouldn't be pretty.
magnetism/ magnetic field ana magnetic forces
Answer:
Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.
1) How psychology is a science?
Psychology is a science because it makes use of scientific method such as observation, asking question, making prediction, etc to study the mind and behavior.
What is Psychology?
Psychology is the scientific study of mind and behavior.
The different types of Psychology include;
Abnormal PsychologyBiopsychologySocial PsychologyCognitive PsychologyDevelopmental PsychologyPersonality PsychologyForensic PsychologyIndustrial-Organizational PsychologySo we can conclude that Psychology is science because it uses scientific method to study the mind and behavior.
Scientific method entails the process of observing, asking questions, and seeking answers through tests and experiments is not unique to any one field of science.
The characteristics of scientific method include;
Making observation.Asking question.Forming a hypothesis, or testable explanation.Making a prediction based on the hypothesis.Testing the prediction.Iterate or repeating the processPsychology applies such scientific method to arrive to a conclusion, hence we can conclude that Psychology is a science.
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A person takes a trip, driving with a constant speed of 98.5 km/h, except for a 20.0-min rest stop. The person's average speed is 68.8 km/h. (a) How much time is spent on the trip? h (b) How far does the person travel? km
Answer:
Total time taken(T) = 1.1 hour
Distance = 75.68 km
Explanation:
Given:
Average speed = 68.8 km/h
Constant speed = 98.5 km/h
Rest time = 20 min = 20 / 60 = 0.3333 hour
Find:
Total time taken(T)
Total distance (D)
Computation:
Distance = speed × time
D = 68.8 × t.........Eq1
and
D = 98.5 × [t-0.33]
D = 98.5 t - 32.8333.........Eq2
From Eq1 and Eq2
68.8 t = 98.5 t - 32.83333
29.7 t = 32.83333
t = 1.1
Total time taken(T) = 1.1 hour
Distance = speed × time
Distance = 68.8 × 1.1
Distance = 75.68 km
1. Explain why Solids have a definite shape and liquids flow?
Explanation:
solid have a definite shape because molecules are compact and vibrate around a fixed position but liquids flow because because molecules are loose and move about freely or without restrain
Answer:
here is my theory
Explanation:
solids have molecules which are totally intact and can't be taken apart unless it's done by hand or by tool on the other hand liquids are not intact at all and has no molecule's together.
5. A man has a weight of 100 Newtons. How much work is done if he climbs 4 meters up a ladder? Plug numbers under the equation. Solve and circle your answer. Include the proper units.
Answer:
400 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 4
We have the final answer as
400 JHope this helps you
a ball tied to a string is rotating in a horizontal circle with a radius 1.5 m and angular speed 3.5rad/s.calculate it's centripetal acceleration?
Answer:
ac = ω²R = 3.5²(1.5) = 18.375 ≈ 18 m/s²
Which best describes the introduction to Imperial March, heard in this excerpt?
Repeated rhythmic pattern best describes the introduction to Imperial March, heard in this excerpt.
The Imperial March was initially featured in which film?It first appeared in the second movie, The Empire Strikes Back, also is known as the leitmotiv, a recurring motif connected to certain people or incidents in a play. The Imperial Motif, a motif for the Empire that appeared in the previous movie, is replaced by the Imperial March in the sequel.
Why is The Imperial March so terrifying?The influx of minor chords, especially those that nearly sound normal, conveys the idea of a deeply deviant, malevolent worldview. For fun, I transposed these warped chords in the song down a semitone so you could hear how the march will sound with the more traditional chords.
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John walks 10 meters North, 8 meters East, 3 meters South, and then 8
West. What is Johns displacement?
4.24 meters is the Johns displacement.
What does displacement mean in its simplest form?The modification of an object's position is referred to as displacement. It is a vector quantity with a direction and magnitude. It is depicted as an arrow that moves from the starting point to the ending. For instance, if an object moves from position A to position B, its position changes.
(8m west) + (3m south) + (8m east) + (10m north) =
[ (2m west)+(8m east) ] + [ (3m south)+(10m north) ] =
[ (-2m east)+(4m east) ] + [ (-3m south)+(10m south) ] =
(2m east) + (7m south)
The North/South component and the East/West component are the orthogonal (perpendicular) components of the displacement that we currently have.
To combine these, it's time for Pythagoras:
Displacement = √[ (2m)² + (7m)² ]
Displacement = √ (4m² + 14m²)
Displacement = √18m²
Displacement = 4.24 meters Southeast.
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1.) Consider the graph shown to the right. The two lines denote the motion of two different objects which move in the x direction only.
2.) Five vectors, A, B, C, D, E are shown at the right. Which of the combinations below has the largest magnitude ?
Graph is shown in the picture, please help!
The change in position of an object over time is known as velocity. The thing in question is traveling correctly. Vector c has the largest magnitude of all the vectors. And as demonstrated, a half-arrow can be used to represent this vector.
What are some types of objects?Everything that is readily apparent or palpable and has a stable form. An object of study in medicine is anything, anyone, or anything to which action or thinking is focused.
What is a kid-friendly object?A person or thing that the verb directs its action toward is called an object. A noun, pronoun, or noun phrase that is impacted by the action verb is referred to as an object. A sentence is also finished by it.
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Help anyone
Please I don’t understand it at alll
Answer:
a) 24525 Newtons
b)240590.25 Joules
c)4009.8375 Watt
d)294300 Joules
Explanation:
a) Weight is a force, and can be calculated by multiplying mass by acceleration due to gravity. Earth's acceleration due to gravity is 9.81m/s/s. To find the water's weight, we multiply its mass (2500) by acceleration due to gravity.
W=mg
=(2500)(9.81)
=24525 Newtons
b) Work is calculated by multiplying force by distance. In this case, the force is the weight (as found in part a) and the distance is 16m.
W=fd
=(24525)(9.81)
=240590.25 Joules
c) Power is calculated by dividing the work by the time. In this case the work is our answer for part b and the time is sixty seconds.
P=w/t
=240590.25/60
=4009.8375 Watt
d) The first bit of part d tells us that (the waters potential energy)(0.75)=(electric energy). To find potential energy, multiply mass by acceleration due to gravity by height.
PE=mgh
=2500*9.81*16
=392400 Joules
Multiply by 0.75 to find electric energy: 294300 Joules
a squirrel with a mass of 4.5 kg sits on a branch that is 13 m off the ground. what is the gravitational potential energy? The acceleration of gravity is 9.8 m/squared
Answer:
573.3J
Explanation:
P.E=mgh
P.E=4.5x9.8x13
P.E=573.3J