The following four waves are sent along strings with the same
linear densities (x is in meters and t is in seconds). Rank the waves according to (a) their wave speed and (b) the tension in the strings along which they travel, greatest first:
1 $$y_1 = (3 mm) sin(x - 3t)$$, (1) $$y_2 = (6 mm) sin(2x - t)$$, (3) $$y_3 = (1 mm) sin(4x - t)$$, (4) $$y_4 = (2 mm) sin(x - 2t)$$,

Answer:

U = 25J

Explanation:

In order to calculate the potential energy of the projectile-Earth system, when the projectile is at its maximum height, you use the following formula for the potential energy:

\(U=Mgh_{max}\)           (1)

M: mass of the projectile = 2.0kg

g: gravitational acceleration =  9.8m/s²

hmax: maximum height reached by the projectile.

The maximum height is given by the following formula:

\(h_{max}=\frac{v_o^2sin^2\theta}{2g}\)          (2)

vo: initial speed of the projectile = 10 m/s

θ: angle at which projectile was fires = 30°

You replace the expression (2) into the equation (1) and replace the values of all parameters:

\(U=Mg(\frac{v_o^2sin^2\theta}{2g})=\frac{1}{2}Mv_o^2sin^2\theta\\\\U=\frac{1}{2}(2.0kg)(10m/s)^2(sin30\°)^2=25J\)

Hence, the potential energy of the projectile-Earth system is 25J

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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The speed of the ball if a 55 kg student running at 2 m/s runs into it is 0.73m/s.

Momentum is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.

The momentum of bodies can be calculated using the following formula:

m¹v¹ = m²v²

Where;

According to this question, 150kg ball is sitting on the floor. A 55kg student running at 2 m/s runs into. The speed of the ball is calculated as follows::

150 × v = 55 × 2

150v = 110

v = 110/150

v = 0.73m/s

Therefore, 0.73m/s is the speed of the ball.

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Answer:

Gravity

Explanation:

Answer:

magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Explanation:

Given the data in the question;

Speed of carousel N = 24 rpm

From the diagram below, selected path direction defines the Axis of slip.

Hence, The Coriolis is acting along the axis of transmission

Now, we determine the angular speed ω of the carousel.

ω = 2πN / 60

we substitute in the value of N

ω = (2π × 24) / 60

ω = 2.5133 rad/s

Next, we convert the given velocity from mph to ft/s

we know that; 1 mph = 1.4667 ft/s

so

\(V_{slip\) = 6 mph = ( 6 × 1.4667 ) = 8.8002 ft/s

Now, we determine the magnitude of the Coriolis acceleration

\(a_c\) = 2( \(V_{slip\) × ω )

we substitute

\(a_c\) = 2( 8.8002 ft/s × 2.5133 rad/s )

\(a_c\) = 44.235 ft/s²

Hence, magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Specific resistance is also known as the resistivity of a material. It is defined as the resistance of a material that has unit length and has a unit cross-sectional area. Resistivity is the fundamental property of a material.

Resistivity is a measure of how strongly the material resists the flow of the current through it. A lower resistivity means the material easily allows the current to flow through it.

This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

According to Newton's Law of Gravitation:

\(F=\frac{Gm_1m_2}{r^2}\)

where,

Therefore,

\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)

F = 1355.78 N = 1.356 KN

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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,

The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

\(\rm F= \frac{Gm_1m_2}{r^2}\)  , Where

\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)

Putting values in the above formula:

\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

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Answer:

Games such as Patintero, Tumbang Preso, Piko, Sipa, Turumpo, and many others, are still played daily in neighborhoods.

Explanation:

Hope this helps... Maybe

Answer:

Answer:

Larger, cooler, and more luminous.

Betelgeuse is red in color, and that means that the surface of it is cooler than the sun (bluish white is hottest, and red is lowest). It is also common knowledge that it is larger,

According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.

According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.

On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.

Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.

Note: This question is incomplete. Here is the complete information:
Attached image

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Answer:

Contact forces are those types of forces that result when the two interacting objects are perceived to be physically contacting each other. Examples of contact forces include frictional forces, tensional forces, normal forces, air resistance forces, and applied forces.

Explanation:

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

Explanation:

A disc of mass 3kg and radius 50cm rotate on a horizontal plane zcity of 40rad if it is brought to rest in 5sec calculate it's angular acceleration

Answer:

True

Explanation:

Answer:

b is called the power of base 10.

Explanation:

In the scientific notation form  

\(a\,\,10^b\)

the exponent b is called the power of the base 10.

Answer:

Explanation:

That is an amazing fact.

The minus sign is what you have to pay attention to. The earth has a mass of 100 times that of Saturn. As someone on here once noted, Saturn has such a low density that it would float in water.

The answer is D

Answer:

Newton's third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects. However much you push your fork in the food, that much a dent it will cause.

Explanation:

Answer:

¡I hope it helps you! :) .................

Answer:

Data

Explanation:

Data is factual information not subject to bias.

This ultimately implies that, data connotes fact, thus, it is an information that is credible, accurate, a statement of truth, evidential and proven.

In Computer programming, a data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.

In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.

This ultimately implies that, a data dictionary found in a computer database system typically contains the records about all the data elements (objects) such as data relationships with other elements, ownership, type, size, primary keys etc. This records are stored and communicated to other data when required or needed.

Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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Answer:

The skier will be moving at 13.31 m/s.

Explanation:

To calculate the velocity of the skier we need to find the acceleration, as follows:

\( \Sigma F = ma \)

\( F_{r} - F_{f} = ma \)

Where:

\( F_{r}\): is the force due to the rope = 365 N

\( F_{f}\): is the combined average frictional force = 190 N

m: is the mass = 75.0 kg

\( a = \frac{365 N - 190 N}{75.0 kg} = 2.33 m/s^{2} \)

Now, we can calculate the velocity of the skier by using the following kinematic equation:

\( v_{f}^{2} = v_{0}^{2} + 2ad \)

Where:

\( v_{f}\): is the final velocity =?

\( v_{0}\): is the initial velocity = 0 (the skier is initially at rest)

d: is the distance = 38.0 m

\( v_{f} = \sqrt{2*2.33 m/s^{2}*38.0 m} = 13.31 m/s \)

Therefore, the skier will be moving at 13.31 m/s.

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Answer:

To calculate the work done by a force, we can use the formula:

Work = ∫F dx

In this case, the force is given by Fx = (2x + 7) N, and the particle moves along the X-axis from X1 = 1 m to X2 = 5 m. Let's calculate the work done.

Work = ∫(2x + 7) dx

Integrating the function (2x + 7) with respect to x, we get:

Work = (x^2 + 7x) evaluated from X1 to X2

Plugging in the values X2 = 5 and X1 = 1 into the expression, we have:

Work = (5^2 + 7 * 5) - (1^2 + 7 * 1)

= (25 + 35) - (1 + 7)

= 60 - 8

= 52

Therefore, the work done by the force is 52 Joules (J).

Explanation:

Answer:

The correct answer is "12 rad/s"

Explanation:

The given values are,

Mass of rod,

M = 140 g

i.e.,

   = 0.14 kg

Length,

L = 57 cm

i.e.,

  = 0.57 m

Mass of beads,

M = 30 g

i.e.,

   = 0.03 kg

Angular speed,

r = 11 cm

i.e.,

 = 0.11 m

Now,

The inertia of rods will be:

=  \(\frac{1}{12}ML ^2\)

On substituting the values, we get

=  \(\frac{1}{12}\times 0.14\times (0.57)^2\)

=  \(0.0037905 \ kg-m^2\)

The inertia of beads will be:

=  \(mr^2\)

On substituting the values, we get

=  \(0.03\times (0.11)^2\)

=  \(0.000726 \ kg-m^2\)

The total inertia will be:

=  \(Inertia \ of \ rods+Inertia \ of \ beads\)

=  \(0.0037905 + 0.000726\)

=  \(0.0045165 \ kg-m^2\)

now,

The angular speed of the system will be:

⇒ \(L_1w_1=L_2w_2\)

On substituting the values in the above equation, we get

⇒ \(0.0045165\times 23 = (0.0037905 + (0.03\times 0.285^2)\times 2 )\times w_2\)

⇒ \(0.1038795 = 0.0037905 + (0.00243675\times 2 )\times w_2\)

⇒             \(w_2 = 12 \ rad/s\)

For signs of such collisions on the moons of the outer planets, look for craters, ray systems, fissures and fractures, melted or evaporated material, and changes in the moon's surface composition.

Huge fragments of the newly discovered comet Shoemaker-Levy 9 (SL9) collided with Jupiter over a period of days from July 16 to 22, 1994, leaving vast, dark scars in the planet's atmosphere and lofting superheated plumes into its stratosphere.

Dust was also left floating on top of Jupiter's clouds after the collision. The movement of the planet's dust allowed researchers to trace Jupiter's high-altitude winds for the first time.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

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(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.

The acceleration of the car and trailer system is given as 2.15 m/s².

Using Newton's second law:

Net force = mass × acceleration

Net force = 1,300 kg × 2.15 m/s²

Net force ≈ 2,795 N

Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.

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