. The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth


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Answer:

I think 32

Explanation:

Answer:

c

Explanation:

The law of conservation of momentum states that in an isolated system, the total momentum of two or more bodies acting on each other remains constant unless an external force acts on them. Therefore, it cannot create or destroy momentum.

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Answer:

439.6 THz

Explanation:

When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².

Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.

Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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It struck him with 60 W of power. when a 10 kg rock hits a guy after falling from a height of 18 m and landing on him after around 3 s.

Power is the rate of production of work. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit for power. Power is a measure of how quickly energy is used up since power is the transfer of energy. An example would be a 60-W light bulb, which uses 60 J of energy every second.

Power= mass. velocity + power=10*18/3*10 = 60 W,

resulting in the power of a falling rock being 60W.

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According to the question, the height of the cliff is 49.67 m, the final velocity of the stone before it strikes A is  1636 m/s, and the maximum height reached by the stone is 149 m.

In physics, projection may be defined as the process or technique of reproducing a spatial object upon a plane or curved surface, or a line by projecting its points. It involves the angle formed by the initial velocity of a body and the horizontal plane through which the body is thrown.

According to the question:

The initial velocity of an object, v₀ = 47.0 m/s

The angle of projection, θ = 51.0°

The time of the motion, t = 5.31 s.

y = y₀ + v₀ᵧ t + ½ gt²

0 = h + (47.0 sin 51.0) (5.31) + ½ (-9.8) (5.31)²

h = 49.67 m.

vᵧ = gt + v₀ᵧ

vᵧ = (-9.8)(5.31) + (47.0 sin 51.0)

vᵧ = -20.49 m/s

vₓ = 47.0 cos 51.0

vₓ = 34.88 m/s

v² = vₓ² + vᵧ²

v = 1636 m/sec.

vᵧ² = v₀ᵧ² + 2g(y - y₀)

0² = (47.0)² + 2(-9.8)(H - 51.8)

H = 149 m.

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Answer:

humerus and all hand bones

Explanation:

not skull bones

in axial skel.

The force required to stop the car of mass 3250 kg is -12195.12 N.

Force is the product of mass and acceleration.

To calculate the force required to stop the car, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

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The spring constant of the spring is determined as 2,647.7 N/m.

The spring constant of the spring is calculated by applying the following equation.

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv² / x²

where;

F = kx

ma = kx

k = ma / x

where;

ma / x = mv² / x²

a / x = v² / x²

ax = v²

x = v² / a

The spring constant of the spring is calculated as;

k = ma / x

k = (ma / v² / a)

k = ( ma² / v² )

k = (1200 x 39.2²) / (26.39²)

k = 2,647.7 N/m

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Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

\(f_s = \mu_s N\) --- (1)

where;

\(f_s =\) static friction force

\(\mu_s =\) coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

\(N = ma_{min}\)

From equation (1)

\(f_s = \mu_s ma_{min}\)

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

\(F = f_s\)

\(mg = \mu_s ma_{min}\)

\(a_{min} = \dfrac{mg }{ \mu_s m}\)

\(a_{min} = \dfrac{g }{ \mu_s }\)

where;

\(\mu_s = 0.383\) and g = 9.8 m/s²

\(a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }\)

\(\mathbf{a_{min}= 25.59 \ m/s^2}\)

Answer:

Initial height

Answer:

A: the hardness of the sidewalk where the mug landed

Explanation:

did the quick check

An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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Answer:

Drift velocity in m/s is \(1.84 \times 10^{-8}\ m/s\).

Explanation:

Formula for Drift Velocity is:

\(u = \dfrac{I}{nAq}\)

Where I is the current

n is the number of electrons in 1 \(m^3\) or the electron density

A is the area of cross section and

q is the charge of one electron.

We are given the following:

n = \(8.49 \times 10^{28}\ electrons/m^3\)

I = 1 A

A = 0.40 \(cm^2\) = 40 \(\times 10^{-4}\) \(m^{2}\)

We know that q = \(1.6\times10^{-19} C\)

Putting all the values to find drift velocity:

\(u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s\)

So, drift velocity in m/s is \(1.84 \times 10^{-8}\ m/s\).

The number of times times larger is the United States water consumption PER PERSON compared to the World water consumption PER PERSON is 100 to 175 gallons of water

Every day, the average American uses 100 to 175 gallons of water. We use almost 4 trillion cubic meters of freshwater annually on a global scale! In some areas, agriculture can use up to 90% of the available freshwater.

Although the water resources in the United States are enormous, they are not limitless. Given that the average American's water footprint, or the total amount of water consumed directly and indirectly, is about twice that of the rest of the world, it is extremely important to save and safeguard this water.

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Answer:

The viscosity of the fluid is 1.16 N-s/m²

Explanation:

Given that,

Area = 0.6 m²

Angle = 30°

Velocity = 0.36 m/s

Thickness = 1.8 mm

Weight = 280 N

We need to calculate the viscosity of the fluid

Using balance equation

\(w\sin\theta=\dfrac{\mu\times v}{t}\times A\)

Put the value in the equation

\(280\sin30=\dfrac{\mu\times0.36}{1.8\times10^{-3}}\times(0.6)\)

\(140=\mu\times120\)

\(\mu=1.16\ N-s/m^2\)

Hence. The viscosity of the fluid is 1.16 N-s/m².

Answer:

i got u

Explanation:

The iron will have the higher final temperature. This is because the specific heat capacity of iron is much lower than the specific heat capacity of ice. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance by a certain amount, and it varies from substance to substance. Since the specific heat capacity of iron is lower, it means that it takes less heat energy to raise the temperature of iron than it does to raise the temperature of ice by the same amount. Therefore, when equal amounts of heat are added to equal masses of ice and iron at the same initial temperature, the iron will have a higher final temperature than the ice.

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.

Curved mirrors are used by the majority of telescopes nowadays to collect light from the night sky. Light is focused by a telescope's mirror or lens' shape.

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky.

The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light. The "optics" of a telescope are the mirrors or lenses. Strong telescopes may view objects that are extremely faint and incredibly far away.

Therefore, Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.

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Answer:

jnfal4u4ryhfsbjls5

Explanation:

duehdakjweyedufkbshegygfr

Answer:

The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.

Answer:

Explanation:

The mass is essentially "how much stuff" is in an object. ... Weight: There is a gravitational interaction between objects that have mass. If you consider an object interacting with the Earth, this force is called the weight. The unit for weight is the Newton (same as for any other force).

Answer:

The correct answer is C) Force. If the total force on an object is not zero, its motion will change according to the second law of motion by Isaac Newton.

Answer:

B is the best answer for this

Answer:

(Total initial linear momentum = total final linear momentum.)

Momentum = mass × velocity

180×4 + 120×0 = 180×0 + 120×V

(180 ×4)/120 = V

The distance travelled during the given time can be found out by using the equations of motion.

The distance traveled during the time interval is "13810.8 m".

First, we will find the deceleration of the motorcycle by using the first equation of motion:

\(v_f=v_it+at\\\\\)

where,

vi = initial velocity = (518 km/h)\((\frac{1\ h}{3600\ s})(\frac{1000\ m}{1\ km})\) = 143.89 m/s

vf = final veocity = 60 % of 143.89 m/s = (0.6)(143.89 m/s) = 86.33 m/s

a = deceleration = ?

t =time interval = 2 min = 120 s

Therefore,

\(86.33\ m/s = 143.89\ m/s + a(120\ s)\\\\a = \frac{86.33\ m/s - 143.89\ m/s}{120\ s}\)

a = -0.48 m/s²

Now, we will use the second equation of motion to find out the distance traveled (s):

\(s = v_it+\frac{1}{2}at^2\\\\s = (143.89\ m/s)(120\ s)+\frac{1}{2}(-0.48\ m/s^2)(120\ s)^2\\\\s = 17266.8\ m - 3456\ m\)

s = 13810.8 m = 13.81 km

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The attached picture shows the equations of motion.

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  \(F = 25 \ N\)

   The frequency is   \(f = 1 \ Hz\)

   The mass of the bridge per unit length is  \(\mu = 2000 \ kg /m\)

    The length of the central span is  \(d = 144 m\)

     The oscillation amplitude of the section  considered at the time considered is  \(A = 75 \ mm = 0.075 \ m\)

      The time taken for the undriven oscillation to decay to \(\frac{1}{e}\)  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            \(m = \mu * d\)

=>        \(m = 2000 * 144\)

=>        \(m = 288000 \ kg\)

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 \(A(t) = A_o e^{-\frac{bt}{2m} }\)

Here b is the damping constant and the \(A_o\) is the amplitude of the section when it was undriven

So from the question  

               \(\frac{A_o}{e} = A_o e^{-\frac{b6T}{2m} }\)

=>            \(\frac{1}{e} =e^{-\frac{b6T}{2m} }\)

=>          \(e^{-1} =e^{-\frac{b6T}{2m} }\)

=>           \(-\frac{3T b}{m} = -1\)

=>         \(b = \frac{m}{3T}\)

Generally the amplitude of the section considered is mathematically represented as

           \(A = \frac{n * F }{ b * 2 \pi }\)

=>       \(A = \frac{n * F }{ \frac{m}{3T} * 2 \pi }\)

=>       \(n = A * \frac{m}{3} * \frac{2\pi}{25}\)

=>       \(n = 0.075 * \frac{288000}{3} * \frac{2* 3.142 }{25}\)

=>       \(n = 1810 \ people\)