The gradual and uniform cooling of glass that has been heated in order to relieve random internal stresses is... Group of answer choices annealing tempering quenching heat treating

A) 473 horsepower rating on the bmw m3 in north america.

BMW's S58 twin-turbo 3.0-liter inline-six, which in standard form generates 473 horsepower and 406 lb-ft of torque, powers the M3. It is connected to either a six-speed manual transmission or an eight-speed automatic transmission that only drives the rear wheels. According to BMW, the M3 will reach 60 mph in 4.1 seconds and reach a top speed of 180 mph.

Engine output increases to 503 horsepower and 479 lb-ft of torque in the M3 Competition. BMW's xDrive AWD technology is now provided, whilst the Competition is only offered with an automatic transmission. Considering the car's capabilities, fuel economy isn't too poor; regardless of the transmission selected, it receives an EPA rating of 16/23 mpg city/highway.

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Answer:

Here are three examples of Dutch gable roof designs:

Answer:

hello some part of your question is missing ( The table ) attached below is the missing detail related to your question

answer: cumulative infiltration after 30 mins = 6.7

Explanation:

Calculate the cumulative infiltration after 30 min

formula for calculating  cumulative infiltration

= 11( t - tp + t' ) = F - 34.3 In ( 1 + 0.0291 * F )

Attached below is a detailed solution to the problem

Answer:

When are resistors in series? Resistors are in series whenever the flow of charge, called the current, must flow through devices sequentially. For example, if current flows through a person holding a screwdriver and into the Earth, then  

R

1

 in Figure 1(a) could be the resistance of the screwdriver’s shaft,  

R

2

 the resistance of its handle,  

R

3

 the person’s body resistance, and  

R

4

 the resistance of her shoes.

Figure 2 shows resistors in series connected to a voltage source. It seems reasonable that the total resistance is the sum of the individual resistances, considering that the current has to pass through each resistor in sequence. (This fact would be an advantage to a person wishing to avoid an electrical shock, who could reduce the current by wearing high-resistance rubber-soled shoes. It could be a disadvantage if one of the resistances were a faulty high-resistance cord to an appliance that would reduce the operating current.)

Two electrical circuits are compared. The first one has three resistors, R sub one, R sub two, and R sub three, connected in series with a voltage source V to form a closed circuit. The first circuit is equivalent to the second circuit, which has a single resistor R sub s connected to a voltage source V. Both circuits carry a current I, which starts from the positive end of the voltage source and moves in a clockwise direction around the circuit.

Figure 2. Three resistors connected in series to a battery (left) and the equivalent single or series resistance (right).

To verify that resistances in series do indeed add, let us consider the loss of electrical power, called a voltage drop, in each resistor in Figure 2.

According to Ohm’s law, the voltage drop,  

V

, across a resistor when a current flows through it is calculated using the equation  

V

=

I

R

, where  

I

 equals the current in amps (A) and  

R

 is the resistance in ohms  

(

Ω

)

. Another way to think of this is that  

V

 is the voltage necessary to make a current  

I

 flow through a resistance  

R

.

So the voltage drop across  

R

1

 is  

V

1

=

I

R

1

, that across  

R

2

 is  

V

2

=

I

R

2

, and that across  

R

3

 is  

V

3

=

I

R

3

. The sum of these voltages equals the voltage output of the source; that is,

V

=

V

1

+

V

2

+

V

3

.

This equation is based on the conservation of energy and conservation of charge. Electrical potential energy can be described by the equation  

P

E

=

q

V

, where  

q

 is the electric charge and  

V

 is the voltage. Thus the energy supplied by the source is  

q

V

, while that dissipated by the resistors is

q

V

1

+

q

V

2

+

q

V

3

.

Explanation:

Answer:

Do not use I me my we. Less exclamation points, bigger words like "Pompous" Lots of uptight language, as if you are at an interview. structure should be precise and sharp, sharper than Angelina Jolie's cheekbones

Explanation:

Answer:

sorry im answering questions for the points cuz im built dfferent

Explanation:

Answer: That happens to me too sometimes. I hate when people give the wrong answers...like if u don't know the answer, then don't respond

The temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

It should be noted that temperature simply means the measure of hotness and coldness in a body

From the given information, H is the enthalpy of gas on the constant pressure line, m is the mass flow rate and U is the internal energy of gas.

Here, the temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

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The limited approach boundary distance for an exposed fixed circuit part on a 480y/277-volt distribution panel is 3'6".

An exposed Fixed Circuit part is, a bare conductor or another circuit component that is stationary and will not move. This is the most often used Limited Approach Boundary value. Exposed Movable Conductor - A bare conductor that can move (e.g., an overhead transmission line conductor).

The limited approach boundary distance for an exposed fixed circuit part on a 480y/277-volt distribution panel is 3 feet 6 inches, which indicates that persons and objects should not go any closer to live electrical parts than this distance in order to avoid electrical shock or another injury.

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Answer:

gift cards like subscribe channel comment on this is new to the same time as I will send it in the blanks with past and different problems with the day I will send it by clicking the link to and from the day of a place to stay in touch with you tube dash board and my family is greenhouse gases and different songs of a

Answer:

No what was in the past is the past but present is in the present unless it has it's own law/rule

Explanation:

Answer:

it's not included

Explanation:

plz exact ur explain

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

Answer:

Following are the solution to this question:

Explanation:

In point a:

This takes me six weeks for both the took ideas that I was searching for but it continued for 3 years (12 weeks) as it's an intern.  

In point b:

Finding job:

\(\to f = \frac{1}{6} = 0.166\) jobs weekly  

Separation of jobs:

\(\to \frac{ 1}{12}=0.083\) employment per week.  

In point c:

Its natural rate of unemployment is:  \(\frac{U}{L} = s+(s \times f)\).  

The normal level of employment for that community I represent, once we add up from that preceding section, is as follows:

\(\to \frac{U}{L} = 0.083+ (0.083\times 0.166) = 0.096\)

If on average, it requires six weeks to find another job or the work lasted 12 weeks, the group's unemployment level is \(0.096 \ \%\).

Given Information:C1 is Transacting Customer and C2 are Enquiring Customer.There is 1 vending machine with delay type constant 3 seconds.There is only 1 Teller in the counter whose processing speed is Triangular with minimum 3, most likely 5 and maximum is 12 Minutes.

The bank also employs 1 receptionist whose working speed is uniform with minimum 2 minutes and a maximum of 8 minutes.20% customers also do transactions with the bank.There is a single manager who works with processing delay as Triangular minimum 5, average 10 and Maximum 30.

Replication length = 14 hoursWe are supposed to design a simulation for a bank where two types of customers arrive. We need to determine the number of customers served by the Teller and the number of customers served by the Receptionist, respectively.Simulation Design:The first step of the simulation is to create the flowchart. A flowchart represents the sequence of activities carried out by the bank and the possible events that may occur during the simulation.

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Answer:

Therefore the value of the line currents IR, IY, and IB are

\(I_{R}=I_{1}=83\angle 6.87^{o}A\\I_{B}=-I_{2}=-71.88\angle-23.13^{o}A\\I_{Y}=I_{2}-I_{1}\\I_{Y}=-I_{2}=41.50\angle113.3^{o}A\)

Explanation:

Apply KVL for loop 1  

\(415\angle 120^{o}=\left ( 3+j4+3+j4 \right )I_{1}-\left ( 3+j4 \right )I_{2}\\415\angle 120^{o}=\left ( 6+j8 \right )I_{1}-\left ( 3+j4 \right )I_{2}\\415\angle 120^{o}=\left ( 10\angle 53.13^{o} \right )I_{1}-\left ( 5\angle 53.13^{o}\right )I_{2} \rightarrow \left ( 1 \right )\)

Apply KVL for loop 2

\(415\angle 0^{o}=\left ( 3+j4+3+j4 \right )I_{2}-\left ( 3+j4 \right )I_{1}\\415\angle 0^{o}=\left ( 6+j8 \right )I_{2}-\left ( 3+j4 \right )I_{1}\\415\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{2}-\left ( 5\angle 53.13^{o}\right )I_{1} \rightarrow \left ( 2 \right )\)

Solving the above equations,

\(415\angle 120^{o}+830\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{1}-\left ( 5\angle 53.13^{o}\right )I_{2} +\left ( 20\angle 53.13^{o}\right )I_{2}- \left ( 10\angle 53.13^{o} \right )I_{1}\\415\angle 120^{o}+830\angle 0^{o}=\left ( 20\angle 53.13^{o}\right )I_{2}- \left ( 10\angle 53.13^{o} \right )I_{2}\\415\angle 120^{o}+830\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{2}\\I_{2}= 71.88\angle -23.13^{o}A\)&

\(415\angle 0^{o}=\left ( 10\angle 53.13^{o} \right ) \times 71.88\angle -23.13^{o}-\left ( 5\angle 53.13^{o} \right )I_{1}\\415\angle 0^{o}=718.8\angle 30^{o}-\left ( 5\angle 53.13^{o} \right )I_{1}\\\left ( 5\angle 53.13^{o} \right )I_{1}=415\angle 60^{o}\\I_{1}= 83\angle 6.87^{o}A\)

Hence,

\(I_{R}=I_{1}=83\angle 6.87^{o}A\\I_{B}=-I_{2}=-71.88\angle-23.13^{o}A\\I_{Y}=I_{2}-I_{1}\\I_{Y}=-I_{2}=41.50\angle113.3^{o}A\)

To determine the power used by the calculator, we can use the formula P = V x I, where P is power, V is voltage, and I is current. Plugging in the values, we get P = 8 x 0.1 = 0.8 watts.

To calculate the energy used, we can use the formula E = P x t, where E is energy, P is power, and t is time. In this case, if the calculator is used for one hour, we get E = 0.8 x 1 = 0.8 watt-hours (Wh).
It is important to note that this is a small amount of energy, as calculators are designed to be low-power devices. However, over time, the cumulative energy usage of many small devices like calculators can add up, which is why energy conservation is important.

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Answer:

9 1/2

Explanation:

3 4/5 is 3.8

2/5 is 0.4

divide 3.8 by 0.4 you get 9.5 which is 9 1/2 in a fraction

Both Technician A and Technician B can be correct depending on the specific situation and the design of the cylinder head.

In general, when performing valve seat work, it is common practice to repair or replace the valve guides before machining the valve seats. Valve guides provide guidance and support to the valves, and if they are worn or damaged, it can affect the valve's performance and seating.

Technician A is correct in emphasizing the importance of repairing the valve guides before machining the valve seats. This ensures that the valves are properly guided and aligned during the machining process, resulting in accurate and precise valve seat work.

However, Technician B is also correct in stating that on certain cylinder heads, the valve seats can be removed and replaced. Some cylinder heads are designed with removable valve seats, which allows for easier replacement when the seats are worn or damaged. This process involves removing the old valve seats and installing new ones, ensuring a proper sealing surface for the valves.

Ultimately, the correct approach depends on the specific cylinder head design and the condition of the valve guides and seats. It is essential to assess the condition of the valve guides and seats before determining the appropriate course of action, whether it involves repairing the valve guides or replacing the valve seats.

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Answer:

It's to ensure a driver's safety.

Answer:

They both have the same efficiency.

Explanation:

The simple ideal Rankine cycle and an ideal regenerative Rankine cycle with one open feedwater heater would both have the same efficiency because the extraction steam would just create a mini cycle that recirculates. The energy given to the feedwater heater is proportional to the added heat in the boiler to the feedwater in the simple cycle to raise its temperature to the same boiler inlet condition.

Therefore in comparison, the efficiency is the same for both.

Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

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Answer:

D) All of the above.

The opcode of the instruction MOV AX, BX is neither AX nor BX, but rather the binary code 10001011. This instruction moves the contents of register BX into register AX in the x86 assembly language.

This can be explained as follows:Opcode is the hexadecimal value of the operation code (op code) used to specify the instruction to be executed in a computer's central processing unit (CPU).It tells the processor what to do with the operands of the instruction (such as AX, BX in this case). The opcode is used to assemble machine code, which the CPU can then execute. In general, opcodes are used to specify operations that can be performed by a processor, such as moving data between registers (MOV), adding numbers (ADD), and comparing data (CMP).The opcode of MOV AX, BX is a two-byte instruction in which the first byte specifies the opcode (8B in hexadecimal) and the second byte specifies the registers involved in the instruction (C3 in hexadecimal). The instruction is encoded as follows: 8B C3. Hence, we can say that the answer is false.

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From the given information, we have the voltage across the circuit element as v(t) = 5te^(-100t) + cos(1000t) V and the current through the element as i(t) = 2.5te^(-100t)cos(1000t) μA.

To determine the element, its value, and initial condition, we can compare the form of the voltage and current equations with the general expressions for a circuit element.

The general expression for a circuit element voltage is v(t) = V0e^(-αt)cos(ωt + φ), where V0 represents the element value, α is the decay constant, ω is the angular frequency, and φ is the phase angle.

Comparing the given voltage equation with the general expression, we can identify the following values:

Element: It is not specified in the given information, so we cannot determine the specific element.

Element value (V0): The coefficient of the exponential term represents the element value. In this case, V0 = 5 V.

Initial condition: The initial condition of the element refers to the voltage or current value at t = 0. In this case, the initial condition is 0 since there is no constant term in the voltage equation.

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Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Answer:

building a bridge

Explanation:

you would have to sketch ideas to see what the bridge would look like and you need to know what to add to it to enhance the percentage of it working. if you sketch it you would have an idea of the process also

Building a bridge is an occasion in which an explanatory sketch would be used.

Sketches of explanations are created to demonstrate form, structure, and function. They accurately and objectively communicate a design, placing more emphasis on explanation than pitch. Outside of the design team, explanation sketches must be understandable.

Exploratory sketches, often referred to as thinking drawings, are a type of personal communication that frequently serve as the starting point for brand-new product concepts.

During a brainstorming session or for personal usage in a design notebook, these quick sketches are meant to quickly capture ideas. Exploratory research aims to study the important aspects of a topic that hasn't gotten much attention.

Thus, it is Building a bridge.

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The flow rate in an ideal fluid is directly proportional to the square of the radius. Flow rate is directly proportional to the fourth power of the radius of a viscous fluid. When blood is assumed to be a non-viscous fluid, the flow rate is determined to be decreased by 25% because the radius is decreased by 50%.

However, if the blood is considered a viscous fluid, the flow rate is reduced by 94.6%.Explanation:The rate of flow of fluid is defined as the volume of fluid flowing through a given cross-section of the tube in unit time. In a pipe, the rate of flow is inversely proportional to the length of the pipe, whereas it is directly proportional to the cross-sectional area of the pipe.The formula for flow rate in an ideal fluid is given by:Q = Av where,Q= flow rateA= cross-sectional areav= velocity of fluidThus, if the cross-sectional area of the tube is reduced, the flow rate will also decrease. However, in a viscous fluid, the formula changes, and the flow rate becomes:Q = (π r^4∆P) / (8ηl)where,Q= flow rateA= cross-sectional area∆P= pressure gradientη= viscosity of fluidl= length of the pipeWhen a tube is 50% blocked, the radius decreases to half of its initial value. Thus, the cross-sectional area decreases to one-fourth of the initial value because the cross-sectional area is inversely proportional to the square of the radius.If the blood is non-viscous, the flow rate decreases by 25% because the radius decreases by 50%, which is half the initial value. If the blood is considered a viscous fluid, the flow rate decreases by 94.6% because the flow rate is directly proportional to the fourth power of the radius.

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Wi-Fi is not a building automation and control protocol.Building automation and control protocols are a group of technologies that are used in buildings to automate the building's control and energy management systems. They are designed to allow for the integration of different systems in a building, such as HVAC, lighting, security, and other systems, into a single, centralized system that can be controlled and monitored from a central location.

There are many different building automation and control protocols that are in use today. Some of the most common ones include BACnet, LonWorks, Modbus, and KNX. Each of these protocols has its own strengths and weaknesses, and each is best suited for different types of buildings and different types of control systems.Wi-Fi, on the other hand, is not a building automation and control protocol. It is a wireless networking technology that is used to connect devices to the Internet and to each other. While Wi-Fi can be used to connect building automation and control systems, it is not specifically designed for this purpose, and there are other protocols that are better suited for building automation and control applications.Wi-Fi is a common wireless network technology that allows devices to connect to the Internet and to each other. However, Wi-Fi is not a building automation and control protocol. Building automation and control protocols are specifically designed for the automation and control of building systems, and they are better suited for this purpose than Wi-Fi.

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The following sketch for Arduino Uno generates a PWM output on pin 9 based on the voltage reading from AN5.

The voltage on AN5 is compared with predefined thresholds to determine the duty cycle of the PWM signal. A reference voltage of 5V is used for the ADC.

To generate the desired PWM output on pin 9, we need to measure the voltage on AN5 and map it to the corresponding duty cycle. The Arduino Uno has a built-in analog-to-digital converter (ADC) that can read voltages from 0V to the reference voltage (in this case, 5V). We will use this capability to read the voltage on AN5.

First, we need to set up the ADC by configuring the reference voltage and enabling the ADC module. We set the reference voltage to the external 5V source using the analogReference() function.

Next, we read the voltage on AN5 using the analogRead() function. This function returns a value between 0 and 1023, representing the voltage as a fraction of the reference voltage. To convert this value to a voltage, we multiply it by the reference voltage and divide by 1023.

Once we have the voltage reading, we can map it to the corresponding duty cycle for the PWM signal. We define four voltage thresholds (1.25V, 2.5V, 3.75V, and 5V) and their corresponding duty cycles (100%, 50%, 25%, and 0%). We use if-else statements to compare the voltage reading with these thresholds and set the duty cycle accordingly.

Finally, we use the analogWrite() function to generate the PWM signal on pin 9 with the calculated duty cycle. The analogWrite() function takes values from 0 to 255, representing the duty cycle as a fraction of the PWM period (255 being 100%).

By implementing this sketch on the Arduino Uno, the PWM output on pin 9 will vary based on the voltage reading on AN5, following the specified duty cycle mapping.

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hospital, school, streets