The graph below represents the relationship between speed and time for an object moving along a straight line. What is the total distance traveled by the object during the first 4 seconds

When two blocks are on a frictionless surface and have the same mass m, the system's ultimate speed is closest to 2v.

Friction is the force that prevents solid surfaces, fluid layers, and material components from sliding against each other. There are several kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in touch solid surfaces. When the surface of one item comes into contact with the surface of another, friction occurs. Friction reduces a machine's mechanical advantage, or in other words, friction reduces the output to input ratio.

Here,

When two blocks collide perfectly inelastically, their final speed is equal to the common speed of the two blocks, which is equal to the total momentum of the system divided by the total mass.

Let's consider two blocks of the same mass m, with block 1 moving to the left with speed 4v and block 2 initially at rest. The initial momentum of block 1 is given by:

p1 = m * 4v

After the collision, the final momentum of the system of two blocks is equal to the initial momentum of block 1:

p_final = p1 = m * 4v

The final speed of the system can be found by dividing the final momentum by the total mass:

v_final = p_final / (2m) = 2v

So, the final speed of the system is closest to 2v when two blocks are on a frictionless surface and have the same mass m.

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Answer:

825 km/hr

Explanation:

To find the average speed, you simply have to divide the distance by the time taken.

Distance travelled = 6600 km

Time Taken: 8 hours

Average speed = 6600 ÷ 8 or 6600/8 = 825 km/hr

Your final answer would be the plane travelled at an average speed of 825 kilometres per hour.

The anticipated time when he will appear again is 5:17 pm

The given parameters;

your speed, \(V_a\) = 3 m/s

the runner's speed, \(V_b\) = 14 m/s

the diameter of the lake, d = 2 miles = 3218.69 meters

The circumference of the lake is calculated as;

\(C = \pi d\\\\C = 3.142 \times 3218.69 = 10,113.12 \ m\)

Apply concept of relative velocity to determine the time, in which he will appear again.

By the time he appears again;

the distance you moved + distance he moved = circumference of the circle

\(V_at + V_bt = 10, 113.12\\\\(V_a + V_b)t = 10,113.12\\\\(3 + 14) t = 10,113.12\\\\17t = 10,113.12\\\\t = \frac{10,113.12}{17} \\\\t = 594.89 \ s = 9.92 \ \min \ \approx 10 \ \min\)

\(t\ \approx \ \ 5:17 \ pm\)

Thus, the anticipated time when he will appear again is 5:17 pm

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Answer:

Near the Earth's surface, the acceleration due to gravity is approximately constant. ... Its value is = 6.673 x 10-11 N·m2/kg2. ... The mass of the moon is 7.35 x 1022 kg. ... moon, the distance to the center of mass is the same as the radius: r = 1.74 x ... Handwriting · Spanish · Facts · Examples · Formulas · Difference Between ...

Explanation:

The acceleration of gravity on the Moon is 1.62 m/s2. The mass of the Moon is 7.35 x 10^22 kg. From this information, then the radius of the Moon is 3 * 10¹² m.

The sole natural satellite of Earth is the Moon. With a diameter around one-quarter that of Earth (equivalent to the breadth of Australia), it is the largest and most massive compared to its home planet and the fifth largest satellite in the Solar System. The Moon is bigger than any known dwarf planets of the Solar System and is a planetary-mass object with a distinct rocky body, making it a satellite planet according to geophysical definitions of the word. There isn't much of an atmosphere, hydrosphere, or magnetic field there. With a surface gravity of 0.1654 g, it has a gravity that is around one-sixth that of Earth. Jupiter's moon Io is the only satellite in the Solar System that is known to have a greater gravity and density.

The Moon travels an average distance around Earth.

Given,

g = 1.62 m/s²

m = 7.35*10²² kg

according to formula,

g = GM/r²

1.62 = 6.67× 10⁻¹¹ m³ kg⁻¹ s⁻²*7.35*10²² kg/r²

solving this for r we get

r = 1.7 * 10⁶ m

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Answer:

He needs clay gravel and rocks with cracks

At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

Assuming that the two charges are of equal magnitude and opposite sign and that the distance between them is d, the electric field at the point indicated by the dot can be found using Coulomb's law:

\(E = kq/r^2\)

where k is Coulomb's constant (\(8.99 *10^9 N m^2/C^2\)), q is the magnitude of the charge, and r is the distance between the charges.

Since the charges are of equal magnitude, the net charge at the point indicated by the dot is zero, so we only need to consider the electric field due to one of the charges. Let's assume that we want to find the electric field due to the positive charge.

The distance between the positive charge and the point indicated by the dot is r = d/2. Therefore, the electric field at that point is:

\(E = kq/(d/2)^2 = 4kq/d^2\)

The direction of the electric field is radial, pointing away from the positive charge and toward the negative charge. At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

deceleration is the opposite of acceleration

Explanation:

We know that acceleration is the increase of speed with respect to time. So deceleration must be represented on the graph as a decrease in speed over time.a

Answer:

A) A negative charge of value Q is induced on sphere B

B) there is an attraction between sphere

C) The charge of sphere A is distributed between the two spheres,

Explanation:

This is an electrostatic problem, in general charges of the same sign attract and repel each other.

with this principle let's analyze the different situations

A) The sphere A that is insulating has a charge on its surface and zero charge is its interior

   The conducting sphere B has zero charge, but the sphere A creates an attraction in the electrons, therefore a negative charge of the same value as the charge of the sphere A is induced in the part closest and in the part farther away than one that a positive charge.

A negative charge of value Q is induced on sphere B

B) In this case there is an attraction between sphere A with positive charge and sphere B with negative induced charge

C) When the two spheres come into contact, the charge of sphere A is distributed between the two spheres, therefore each one has a positive charge of value half of the initial charge, as now we have net positive charges in the two spheres charges of the same sign repel each other so the spheres separate

The initial velocity of the lander, at t = 0 and just before it reaches the lunar surface, is 64 m/s. This is because the velocity of the lander is given by c = 64 m/s.

Velocity is a vector quantity that describes the rate of change of an object's position with respect to time. It is the magnitude of an object's displacement per unit of time, expressed as a speed in a specific direction.

Velocity is calculated by dividing the change in position (displacement) by the time interval in which the displacement occurs. It has units of distance per time (e.g. meters per second). The direction of velocity is the same as the direction of displacement, and its magnitude represents the speed of an object's motion.

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On the apple, we apply "antigravitational force."

The apple exerts "gravitational force" on us.

The gravitational attraction, an attractive force whose magnitude is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another, draws all mass-containing things together.

You can never decrease the gravitational pull produced by adding mass. It is possible for gravitational forces acting in opposition to one another to cancel one another out and leave no net force. It would be conceivable for gravity to push objects instead of always dragging them if it weren't always additive.

A place or thing being free from the pull of gravity is the goal of the hypothetical phenomena known as anti-gravity. It doesn't mean balancing the force of gravity with another force, like electromagnetism or aerodynamic lift, or the lack of weight under gravity felt in free fall or orbit.

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Answer:

Chemical energy to sound energy to heat energy

Answer:

55.56

Explanation:

5000N * 50 = 250000/4500= 55.55555555 or 55.56

Answer: In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

Explanation: SI unit: watt (W)

In SI base units: kg⋅m2⋅s−3

Derivations from other quantities: P = E/t; P = F...

Answer:

P = ρ g H     pkgressure due to liquid (gas) of height H

H = 1.00E5 N/m^2 / (1.3 kg / m^3 * 10 N/kg) = 7,700 m

A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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Atom A has 10 protons, 12 neutrons, and 10 electrons, while Atom B has 10 protons, 10 neutrons, and 12 electrons.

Atom A and Atom B are not isotopes of each other. Isotopes are atoms of the same element that differ in the number of neutrons but have the same number of protons. In this case, Atom A and Atom B have different numbers of protons, which means they are not isotopes of each other.

The number of protons determines the element, and since Atom A and Atom B have different numbers of protons, they belong to different elements.

Isotopes, on the other hand, have the same number of protons but differ in the number of neutrons.

This variation in the number of neutrons gives isotopes different atomic masses while retaining the same chemical properties.

However, Atom A and Atom B do not fulfill this criterion, so they cannot be considered isotopes of each other.

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Answer: 10 m/s

Explanation: Velocity/Time

50/5= 10

:)

Answer:

B

Explanation:

on edge

The illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side demonstrates the phenomenon of absorption, so, option B is correct.

Absorption, in wave motion, is the process by which a wave's energy is transferred to matter when the wave travels through it. The energy of an electromagnetic, acoustic, or other wave is related to the square of its amplitude, which is the maximum displacement or movement of a point on the wave.

The amplitude of a wave continuously diminishes as it travels through a substance. The medium is described as being transparent to a specific type of radiation if just a tiny portion of the energy is absorbed, whereas it is described as opaque if all the energy is lost.

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Use the kinetic energy formula:

KE = 1/2 m v^2

m= mass = 49 kg

v = speed

and the potential energy formula:

PE = m g h

g = 9.8 N

h= height = 6 m

PE = 49 x 9.8 x 6 = 2,881.2 J

Since PE = KE

2,881.2 J = KE

2,881.2 = 1/2 x 49 x v^2

2,881.2 = 24.5 x v^2

2,881.2 / 24.5 = v^2

117.6 = v^2

√117.6 = v

v= 10.84 m/s

The original two light bulbs will appear brighter when the third resistor is added in parallel.

When a third resistor is added in parallel to the other two resistors in a circuit, it will have an impact on the overall brightness of the original two light bulbs.

In a parallel circuit, each resistor has its own branch connected to the power source. The current flowing through each branch is inversely proportional to the resistance of that branch. Adding a third resistor in parallel means an additional path for current to flow.

The introduction of the third resistor reduces the total resistance of the circuit. As a result, the total current drawn from the power source increases, as per Ohm's Law (I = V/R). The increased current is distributed among the parallel branches, including the original two light bulbs.

Since the current through the bulbs is now greater, their brightness will also increase. This is because the brightness of an incandescent light bulb is directly proportional to the current passing through it.

It's worth noting that the specific effect on brightness depends on the resistance values of the resistors and the characteristics of the light bulbs. However, in general, adding a resistor in parallel reduces the overall resistance, increases the current, and subsequently enhances the brightness of the light bulbs in the circuit.

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The responses that we have from the question are;

a) The initial velocity is 21.7 m/s

b) he highest altitude is  24 m

c) The time elapsed is 2.2 s

d) The total time spent in air is 4.4s

We know that we can be able to obtain the parameters that are requested in the question by the use of the equations of kinematics.

We can be able to obtain the initial speed by the use of the formula;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height attained

u^2 = v^2 + 2gh

u = √(14)^2 + 2 * 2 * 9.8 * 14

u = 21.7 m/s

b) Using;

v^2 = u^2 - 2gh

At maximum height v = 0 m/s

u^2 = 2gh

h = u^2/2g

h = (21.7)^2 / 2 * 9.8

h = 24 m

c) Time elapsed

v = u - gt

At maximum height v = 0 m/s

u =gt

t = u/g

t = 21.7/9.8

t = 2.2 s

d) The time taken to reach the ground again is 2(2.2) = 4.4s

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When a block is launched with initial speed 2.2 m/s up a 35° frictionless ramp then ramp slides up to 0.43m.

The work-energy theorem explains that net work done by the forces on an object is equal to change in its kinetic energy.

We can also say that work done on a body is equal to the net change in its energy.

Given angle = 35°

initial speed = 2.2m/s

Applying work - energy theorem,

Wgravity = KE

-m *g *sin ∅ * S =1/2* (0- 2.2²)

-9.81*sin 35° *S= 1/2 *(0- 2.2² )

S= 0.43m

Ramp slides up to 0.43m.

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(a) The area of the leaf is  0.064 m².

(b) The length of the fiber is 10,359.2 m.

The area of the leaf is calculated from the volume of the leaf, while the volume of the leaf is calculated from the density and mass of the leaf.

V = m / ρ

where;

V = ( 4.295 g ) / ( 19.32 g/cm³ )

V = 0.22 cm³ = 0.22 x 10⁻⁶ m³

Ah = V

A = V / h

where;

A = ( 0.22 x 10⁻⁶ m³ ) / ( 3.449 x 10⁻⁶ m )

A = 0.064 m²

The length of the fiber is calculated as follows;

V = πr²h

h = V / πr²

h = ( 0.22 x 10⁻⁶ m³ ) / ( π x 2.6 x 10⁻⁶ m x 2.6  x 10⁻⁶ m )

h = 10,359.2 m

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Answer:

Q / Q₀ = 3.4 ,      ΔQ = 31.14 10⁻⁶ C

Explanation:

For this exercise we will calculate the charge of the capacitor with and without dielectric

the capacitance is given by

          C = Q /ΔV

we also use the ratio of capacitances

          C = k C₀

           Q /ΔV = kQ₀ /ΔV

           Q = k Q₀

            Q / Q₀ = k

            Q / Q₀ = 3.4

If we want a numerical value

           C = k Q / DV

           Q = C ΔV / k

            Q = 2.5 10⁻⁶ 60 / 3.4

            Q = 44.12 10⁻⁶ C

whereby the charge without dielectric is

          Q₀ = Q / 3.4

          Q₀ = 44.12 / 3.4 10⁻⁶

          Q₀ = 12.98 10⁻⁶ C

therefore the charge when removing the dielectric is reduced, the amount of charge that flows is

          ΔQ = Q - Q₀

          ΔQ = (44.12 - 12.98) 10⁻⁶

          ΔQ = 31.14 10⁻⁶ C

The amount of charge should be Q / Q₀ = 3.4 ,    ΔQ = 31.14 10⁻⁶ C

For this given situation,  we will determine the charge of the capacitor with and without dielectric

We know that

the capacitance is given by

         C = Q /ΔV

Now here we can applied the ratio of capacitances

So,

         C = k C₀

          Q /ΔV = kQ₀ /ΔV

          Q = k Q₀

           Q / Q₀ = k

           Q / Q₀ = 3.4

In case of numerical value

          C = k Q / DV

          Q = C ΔV / k

           Q = 2.5 10⁻⁶ 60 / 3.4

           Q = 44.12 10⁻⁶ C

whereby the charge without dielectric is

         Q₀ = Q / 3.4

         Q₀ = 44.12 / 3.4 10⁻⁶

         Q₀ = 12.98 10⁻⁶ C

Thus the charge at the time when removing the dielectric is decreased , the amount of charge that flows is

         ΔQ = Q - Q₀

         ΔQ = (44.12 - 12.98) 10⁻⁶

         ΔQ = 31.14 10⁻⁶ C

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Answer:

\(a_c=0.016 \ m/s^2\)

Explanation:

Centripetal acceleration: Is the acceleration experienced by an object while in a uniform circular motion. It points toward the center of rotation and is perpendicular to the linear velocity v and has the magnitude:

\(\displaystyle a_c=\frac{v^2}{r}\)

Where v is the linear velocity and r is the radius of the circle.

It's given a hurricane with a radius r=70 Km = 70,000 m has a tangential wind velocity of v=33 m/s. The acceleration of a particle lying on the edge of the hurricane is:

\(\displaystyle a_c=\frac{33^2}{70,000}\)

\(\boxed{a_c=0.016 \ m/s^2}\)

Answer:

Explanation:

for a.;

Kinetic molecular theory assumes the collision of particles with each other and walls of container as perfectly elastic, that is why no particle loses energy.

for b.;

Kinetic molecular theory assumes that particles are of very small size incomparison with the size of container and far apart from each other that is why their density is very low. because density is described as

Density = Mass/Volume

So, one can imagine that in a big container, entire mass of all gas particles is very low as compared to the volume of container. So the gas have very low density

For c.;

Gases assume shape of their container because they are freely moving with in a container

For d.;

For statement in "b", one can easily understand that because according to kinetic molecular theory, particles are very small and at great distances, so they are compressible against any external pressure applied

Answer:

24 mph

Explanation:

Speed = Distance / Time

Speed = 20 ÷ 5/6

Speed = 24 mph

NOTE: 5/6 is a fraction in this case and is equivalent to 50/60 and 60 minutes = 1 hour of course.

Hope this helped!

Answer:

\(\textsf {speed = 24 mph}\)

Explanation:

\(\textsf {Formula used :}\\\implies \textsf {speed = distance/time}\)

\(\mathsf {Given :}\)

\(\implies \textsf {distance = 20 miles}\)

\(\implies \textsf {time = 50 minutes = 5/6 hour}\)

\(\textsf {Solving :}\)

\(\implies \mathsf {speed = 20 \div 5/6 }\)

\(\implies \mathsf {speed = 20 \times 6/5}\)

\(\implies \mathsf {speed = 4 \times 6}\)

\(\implies \textsf {speed = 24 mph}\)

the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is  6,000 J. Option C is correct answer.

The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:

K.E = 1/2 mv²

Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object

Putting the given values in the above formula:

K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules

The correct answer is C.

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