The hot and neutral wires supplying DC power to a light-rail commuter train carry 700 A and are separated by 70.0 cm. What is the magnitude (in N) of the force between 30.0 m of these wires?

Based on the image provided and the location of deposition and erosion, it seems that the longshore current is moving towards the right.

Based on the image provided, it appears that the longshore current is traveling towards the right. This can be determined by looking at where deposition and erosion are occurring. Deposition is happening on the right side of the image, where sand is building up and forming a beach. Erosion, on the other hand, is happening on the left side of the image, where the waves are breaking against the cliff face and wearing it away. Longshore currents are generated by waves hitting the shore at an angle, causing the water to move parallel to the shore. In this case, the waves are coming in from the top left of the image and hitting the shore at an angle, which creates a longshore current that moves towards the right. As the water moves along the shore, it picks up sand and sediment and carries it with it. This sand is then deposited on the right side of the image, where the water slows down and loses energy. It's important to note that longshore currents can change direction depending on the direction of the incoming waves and the shape of the shoreline. But based on the image provided and the location of deposition and erosion, it seems that the longshore current is moving towards the right.

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The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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Answer:

The magnitude of the acceleration is \(a_r = 1.50 \ m/s^2\)

The direction is  \(\theta = 32.5 6^o\) north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  \(F_{sail} = (330 ) \ N \ north\)

   The force exerted by water is  \(F_{keel} = (210 ) \ N \ east\)

      The mass of the boat(+ crew) is  \(m_b = 260 \ kg\)

Now Force is mathematically represented as

      \(F = ma\)

Now the acceleration towards the north is mathematically represented as

      \(a_n = \frac{F_{sail}}{m_b}\)

substituting values

       \(a_n = \frac{330 }{260}\)

      \(a_n = 1.269 \ m/s^2\)

Now the acceleration towards the east is mathematically represented as

       \(a_e = \frac{F_{keel}}{m_b }\)

substituting values

      \(a_e = \frac{210}{260}\)

      \(a_e =0.808 \ m/s^2\)

The resultant acceleration is  

      \(a_r = \sqrt{a_e^2 + a_n^2}\)

substituting values

     \(a_r = \sqrt{(0.808)^2 + (1.269)^2}\)

      \(a_r = 1.50 \ m/s^2\)

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

        \(tan \theta = \frac{a_e}{a_n}\)

       \(\theta = tan ^{-1} [\frac{a_e}{a_n } ]\)

substituting values

     \(\theta = tan ^{-1} [\frac{0.808}{1.269 } ]\)

    \(\theta = tan ^{-1} [0.636 ]\)

   \(\theta = 32.5 6^o\)

The pulleys will reduce the mechanical force (effort) required to lift the block and will change the mechanical advantage.

The pulley system is a type of simple machine which makes our work easier and faster by overcoming a large load when a small force (effort) is applied to it.

The efficiency of a machine is calculated as follows;

\(Eff = \frac{M.A}{V.R} \times 100\%\)

where;

\(M.A = \frac{load}{effort}\)

The velocity ratio of a pulley system = number of pulleys

The velocity ratio of a pulley system increases with increase in the number of pulleys.

Thus, we can conclude that the pulleys will reduce the mechanical force (effort) required to lift the block and will change the mechanical advantage.

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Answer: At such high frequencies it is very difficult for a sound wave to propagate efficiently; indeed, above a frequency of about 1.25 × 1013 hertz it is impossible for longitudinal waves to propagate at all, even in a liquid or a solid

(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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It takes 30 s from launch to the top of the rocket's trajectory.

The total time of flight is calculated to be equal to 45 s.

Trajectory is the path that any object with mass in motion follows through space as function of time.

As we know, Vf = Vi + at

d = Vi × t + (1/2) × \(\mathrm{at^2}\)

Vf = final velocity  ; Vi = initial velocity  ; a = acceleration  ; t = time  d = distance

As, F = ma

So, F = mg

ma = mg

a = g

Vf = Vi + at

Vf = 0 + (\(\mathrm{9.81 m/s^2}\)) × 15 s

Vf = 147.15 m/s

So the velocity of the rocket at the instant the rocket motor shuts down is 147.15 m/s.

Vf = Vi + at

0 = 147.15 m/s + (\(\mathrm{-9.81 m/s^2}\)) × t

t = 15 s - (147.15 m/s)/(\(\mathrm{-9.81 m/s^2}\))

t = 30 s

So it takes 30 s from launch to the top of the rocket's trajectory.

total time of flight = 15 s (accelerating upwards) + 30 s (reaching maximum height and falling back to ground)

Total time of flight = 45 s

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Explanation:

temperature o temperatura

Answer:

on Earth: 500 N; on distant planet: 200 N

the weight of the object on Earth and on a distant planet is 500 N and 200 N respectively

Weight is the gravitational pull on an object.

To calculate the weight of the object on Earth, we apply the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Also, to calculate the weight in a distant planet, we use the formula below.

Where

From the question,

Given:

Substitute into equation 2

Hence, the weight of the object on Earth and on a distant planet is 500 N and 200 N respectively.

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Answer:

1. v = 6.67 m/s

2. d = 9.54 m

Explanation:

1. To find the horizontal velocity of the rock we need to use the following equation:

\( d = v*t \rightarrow v = \frac{d}{t} \)    

Where:

d: is the distance traveled by the rock

t: is the time

The time can be calculated as follows:

\( t = \sqrt{\frac{2d}{g}} \)

Where:

g: is gravity = 9.8 m/s²

\( t = \sqrt{\frac{2d}{g}} = \sqrt{\frac{2*7 m}{9.8 m/s^{2}}} = 1.20 s \)

Now, the horizontal velocity of the rock is:

\( v = \frac{d}{t} = \frac{8 m}{1.20 s} = 6.67 m/s \)      

Hence, the initial velocity required to barely reach the edge of the shell below you is 6.67 m/s.          

2. To calculate the distance at which the projectile will land, first, we need to find the time:

\( t = \sqrt{\frac{2d}{g}} = \sqrt{\frac{2*(7 m + 3 m)}{9.8 m/s^{2}}} = 1.43 s \)

So, the distance is:

\( d = v*t = 6.67 m/s*1.43 s = 9.54 m \)    

Therefore, the projectile will land at 9.54 m of the second cliff.

I hope it helps you!        

Answer:

55 degrees

Explanation:

Given that an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s.

From the question above, we can get the below parameters

Object speed (V) = 1500 km/h

Sound speed ( v) = 342 m/s

Convert km/h to m/s

(1500 × 1000)/3600

Jet speed V = 416.67 m/s

Let's first calculate the mash number M.

M = V/v

M = 416.67 / 342

M = 1.2183

Formula for the angle of the shock cone is reciprocal of mash number. That is,

Sin Ø = 1 / M

Sin Ø = 1 / 1.2183

Sin Ø = 0.8208

Ø = sin^-1(0.8208)

Ø = 55 degree

Therefore, the angle of the shock cone is approximately 55 degrees

Answer:

An element is made of only one type of atom. (Oxygen or sulphur) A compound is two or more elements that are chemically combined. (Iron oxide or Carbon monoxide)

Explanation:

Explanation:

where I is the current, L is the length of the wire, and B is the magnetic field.

If we point our right-hand thumb in the direction of the current (to the right), and our fingers in the direction of the magnetic field (away from us), then our palm will point in the direction of the force.

The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Answer:

Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.

Answer:

the work done by him is 2,340 joules

Explanation:

The computation of the work done by him is shown below:

= Weight of man × height

= 450 N × 5.2 meters

= 2,340 joules

Hence, the work done by him is 2,340 joules

We simply multiply the man weight with the height

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Hooke's Law states that when a spring is extended, the force is proportional to the length increase above the equilibrium length.

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Answer:

The images produced by a convex mirror are smaller than the object it reflects. The image produced by a concave lens is always virtual. The image in a convex mirror is always upright and is smaller than the object.

Explanation:

:)

Explanation:

The WORK required to stop the truck is equal to the initial Kinetic Energy of the truck  ( 1/2 m v^2)

1/2 mv^2   = 1/2 * 2000 * 30^2  = 900 000 J

Distance travelled in 10 seconds is

  d = vot  - 1/2 at^2      where a = 30 m/s / 10 s = 3 m/s^2

     = 30 (10) - 1/2 ( 3)(10^2) = 150 meters

Work = F * d

900 000 = F * 150

   F = 6000 N

The ecological methods allows to find the correct answer to the question of how to prevent river pollution is:

   b)  Maintain zones of grass at least wide on the sides of streams in the area.

Stream pollution from human activities can occur in a number of ways:

Let's analyze the different claims.

a) False. It is too expensive and the slopes cannot be changed due to possible flooding problems.

b) True. Maintaining a protective zone with grass on the sides of the rivers, prevents the waste of the frarmer from reaching the river, and the problems of the debris reaching the river bank. This un  ecological methods.

c) False. The dam controls flooding but does not eliminate the problems of river pollution.

d) False. Many lands are not acts for agriculture, but for livestock.

In conclusion we can find the correct answer to the question of how to prevent river pollution is:

   b) Maintain zones of grass at least wide on the sides of streams in the area.

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The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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With a horizontal velocity of 3.04 m/s and a horizontal displacement of 1.68 m from the end of the diving board, the swimmer enters the water 1.70 metres below the diving board.

The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.

We can use the kinematic equations of motion to solve this issue.

Use the swimmer's horizontal travel distance as the displacement in the x-direction. Given that the swimmer enters the water 1.68 metres from the board's end, the following is the answer:

x=1.68 m and v0x=3.04 m/s

Δx = v0x * t

calculating t:

t = 1.68 m / 3.04 m/s because x / v0x.

t = 0.5526 s

Thus, the swimmer enters the water in 0.5526 seconds.

"y" equals "v0y*t" plus "(1/2)*a*t2"

replacing the values with:

Δy = 0 + (1/2) * (-9.81 m/s²) * (0.5526 s)²

Δy = -1.70 m

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Answer:

The correct answer is - B ≠ 0, E = 0.

Explanation:

A force q E is exerted by the electric field on the charged particle that accelerates always, that is, it increases the speed of the particle. The particle can never be rotated in a rotation in the circle in an electric field.

The magnitude of the velocity cannot be changed by the magnetic field but changes only the velocity of the direction.

If the particle moves in a circle it means that the speed should begin for a year. The only direct velocity is constant and only the change be b can be achieved. So, B ≠ 0 and E = 0.

Answer:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.

Explanation: