Answer:
In economics, the marginal cost of production is the change in total production cost that comes from making or producing one additional unit.
Explanation:
This is the right answer bc i did it!!
Marginal cost is the correct answer.
What is marginal cost?"The marginal cost of production is the change in total production cost that comes from making or producing one additional unit. To calculate marginal cost, divide the change in production costs by the change in quantity".
For the given question,
The increase in total costs required to produce one additional unit of output is referred to as marginal cost.
Hence we can conclude that marginal cost is the correct answer.
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Infrared radiation from the center of our Galaxy with a wavelength of about 2 µm (2 ✕ 10−6 m) comes mainly from cool stars. What is the surface temperature (in K) of those stars?
The surface temperature of the stars whose infrared radiation have a wavelength of 2 µm is 1.45×10³ K.
What is temperature?Temperature is the measure of hotness or coldness of a thing or place.
To calculate the temperature of the stars, we use the formula below.
Formula:
T = b/λ.......... Equation 1Where:
T = Temperature of the starsλ = Wavelength of the starsb = Wein's constantFrom the question,
Given:
λ = 2×10⁻⁶ mb = 2.9×10⁻³ m⋅KSubstitute these values into equation 1
T = 2.9×10⁻³ / 2×10⁻⁶T = 1.45×10³ KHence, the surface temperature of the stars is 1.45×10³ K.
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Describe briefy the production of soud in of the following instruments. √ Trumpet
To produce its distinct sound a trumpet relies on the dynamic interplay between airflow, vibration, and resonance.
What are the process by which produces it sound?To create sound on a trumpet, one must blow air into its mouthpiece which generates a high-speed airstream causing changes in both volume and pitch. The airstream then meets with vibrating lips on the mouthpiece that function either as reeds or double reeds per player preference.
When these parted lips vibrate against each other due to passing airflow, they produce sound waves inside the long tube of Trumpet with bell widening towards downstream direction at play's end. This reverberates with vibrating lips' oscillations resulting in shaping and amplifying unique tone and timbre of Trumpet notes. Players can get different pitches by utilizing three valves located on their Trumpet.
As an accomplished trumpeter, one can utilize various valve combinations and modify their embouchure to produce a diverse range of notes and melodies.
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b
3.5 Press
The seesaw will balance when the moments on both sides are equal.
Zara weighs 400 N.
Calculate the distance from the pivot to where Zara should sit to
balance the seesaw.
Show your working and give the unit.
Because Newton as Pressure = Thrust/Area, the answer will be 7.5.
What happens when two kids of different weights balance on a seesaw and each generates an equal amount of torque in the opposing direction?The rotating equivalent of Newton's first law is this. When each child's weight exerts an equal amount of torque about the pivot in opposing directions, two kids can balance on a seesaw (clockwise and counter clockwise).
Can two people of different weights balance on a seesaw?The idea of the seesaw You are probably aware that any two people, regardless of their weights, can balance each other while seated on opposite sides of a seesaw. All that is required is for each individual to contribute an equal moment, which is determined by multiplying the person's weight by the distance from the fulcrum.
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Explain why the bottom of the ship is deeper below the surface of the sea
when the ship is fully loaded with cargo
Answer:
uhh more mass = more pull by gravity = ship go sinky more
Explanation:
1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B
(More in the photo provided)
For the roller coaster on a frictionless track:
a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.How to solve speed and height?a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.
Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.
Answer: A. 5.0 m/s
b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.
At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:
Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A
At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."
Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B
Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.
Equating the mechanical energy at Point A to the mechanical energy at Point B:
Initial mechanical energy at Point A = Mechanical energy at Point B
Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B
Since the kinetic energy is the same at both points, simplify the equation:
Potential energy at Point A = Potential energy at Point B
The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:
mgh = mghA
Since the mass and acceleration due to gravity are the same, cancel them out:
h = hA
This means that the height where kinetic energy equals potential energy is the same as the height at Point A.
Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.
c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.
Potential energy at Point B = mghB
Potential energy at Point C = mghC
Given that the height at Point C is 8.0 m, compare the potential energies:
Potential energy at Point B ≥ Potential energy at Point C
mghB ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hB ≥ hC
Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.
d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.
Potential energy at Point A = mghA
Potential energy at Point C = mghC
Given that the height at Point A is 5.0 m, compare the potential energies:
Potential energy at Point A ≥ Potential energy at Point C
mghA ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hA ≥ hC
Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.
To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.
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A ball is Thrown straight up with a speed of 30 M/S, and air resistance is negligible what is its velocity after 4.2s
Answer:
11.2 m/s
Explanation:
We need to first figure out how long it took to reach the ball's max height:
Vf = 0
Vi = 30 m/s
a = -9.81 m/s^2
t = ?
---------------
Vf = Vi + at
0 = 30 + (-9.81)t ---> -30 = -9.81t ---> 3.058 = t
t = 3.058 s
---------------
We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:
Vi = 0
a = 9.81 m/s^2
t = (4.2s - 3.058s) = 1.142 s
Vf = ?
---------------
Vf = Vi + at
Vf = 0 + (9.81)*(1.142) ---> Vf = 11.203
---------------
The velocity of the ball after 4.2s is 11.2 m/s
Which one of these formulas are used to find T (time)?
Answer:
Below
Explanation:
You can actually use ALL EXCEPT THE LAST ONE of these equations to find t, time! It really just depends on what values you are given in the question! Basically what you want to do is plug in everything you have, and solve for t! For example :
Let's say that a car begins from rest and accelerates at 4.2 m/s^2 [ forward ] until it reaches a speed of 62 m/s.
vi = 0m/s, vf = 62 m/s, a = 4.2 m/s^2
We can use the 3rd equation to solve :
vf = vi + at
62 = 0 + 4.2(t)
62 = 4.2t
14.76 = t
15 seconds = t
Hope this helps!
After an unfortunate accident occurred at a local warehouse, you were contracted to determine the cause. A jib crane collapsed and injured a worker. An image of this type of crane is shown in the figure. The horizontal steel beam had a mass of 86.80 kg per meter of length, and the tension in the cable was =12170 N. The crane was rated for a maximum load of 500 kg. The acceleration due to gravity is =9.810 m/s2.
B) If =6.160 m, =0.450 m, =1.500 m, and ℎ=1.980 m, what was the magnitude of L (the load on the crane) before the collapse?
C) What was the magnitude of force p at the attachment point P?
The load of the crane before collapse is 3942.8 N.
Mass per meter of length of the beam, m = 86.80 kg
Tension in the cable, T = 12170 N
Maximum load of the crane, M = 500 kg
Length of the beam, d = 6.16 m
Distance between the end point of beam and attachment end, s = 0.45m
Distance between the end point of the beam and point of inclination,
x = 1.5 m
Height between point P and top of attachment, h = 1.98 m
The moment about the point P,
[T(d - s) sinθ] - [W(L) (d - x)] - mg(d/2) = 0
So,
W(L) = [T(d - s) sinθ - mg(d/2)] / (d - x)
where θ is the angle made by the connecting line with the beam.
tanθ = h/(d - s)
tanθ = 1.98/(6.16 - 0.45)
tanθ = 0.3467
So, θ = 19.12°
Therefore, the load of the crane before collapse,
W(L) = [12170 (6.16 - 0.45)sin19.12°- 86.8 x 9.8(0.45/2) / (6.16 - 1.5)
W(L) = (18565.1 - 191.394) / 4.66
W(L) = 3942.8 N
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If you mix 2 grams of any solid and 6 grams of any liquid, how many grams
should there be when they were combined and did NOT react?
no mass because there was no reaction
8.
12
3
Answer:
8
Explanation:
The mass is always equal to the amount of reactants, 6+2=8
12. An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb
inclined slopes of 35°. What is the minimum coefficient of static friction needed for
this claim to be possible?
The minimum coefficient of static friction required for this claim to be made possible is 0.7
In an inclined plane system, the coefficient of static friction is the angle at which an object slide over another.
The gravitational force component exceeds the static friction force when the angle rises. Hence, the object begins to slide.
According to Newton second law;
\(\sum F_x = \sum F_y = 0\)
\(\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }\)
On the L.H.S\(\mathbf{mg sin \theta =f_s}\)
\(\mathbf{mg sin \theta =\mu_s N}\)
On the R.H.SN = mg cos θ
Equating both force components on the L.H.S and R.H.S, we have the following
\(\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}\)
\(\mathbf{sin \theta =\mu_s \ \ cos \theta}\)
\(\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}\)
According to the trigonometry rule:
\(\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}\)
∴
\(\mathbf{\mu_s =\tan \theta}}\)
\(\mathbf{\mu_s =\tan 35^0}}\)
\(\mathbf{\mu_s = 0.700}}\)
Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7
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Calculate the velocity on a roller coaster that has a mass of 2,131.2 kg and the kinetic energy is 2,799,287 Joules of energy.
ANSWER
\(51.3m\/s\)EXPLANATION
Parameters given:
Mass, m = 2131.2 kg
Kinetic energy, E = 2799287 J
To find the velocity of the roller coaster, we have to apply the formula for kinetic energy:
\(E=\frac{1}{2}mv^2\)Substitute the given values into the equation and solve for velocity, v:
\(\begin{gathered} 2799287=\frac{1}{2}\cdot2131.2\cdot v^2 \\ v^2=2\cdot\frac{2799287}{2131.2}=2626.96 \\ v=\sqrt[]{2626.96} \\ v=51.3m\/s \end{gathered}\)That is the velocity of the roller coaster.
A 297 kg sled travels at a speed of 8.2 m/s, how much kinetic energy does it have?
A 297 kg sled travels at a speed of 8.2 m/s, so the sled has a kinetic energy of approximately 9971.61 joules, and this result is formed by using the kinetic energy formula of the object.
What is the calculation of the kinetic energy ?KE = (1/2) × m × \(v^2\)
(where m= is the mass of the object ,KE= kinetic energy, and v =is its velocity)
Putting in the given values, one get:
KE = (1/2) ×297 kg × \((8.2 m/s)^2\)
KE= (1/2) × 297 kg × \(67.24 m^2/s^2\)
KE= 9971.61 J
Hence, a 297 kg sled travels at a speed of 8.2 m/s, so the sled has a kinetic energy of approximately 9971.61 joules.
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The pressure of a gas at the triple point of water is 1.50 atm. If its volume remains unchanged, what will its pressure be at the temperature at which CO2 solidifies?
The pressure of a gas at the triple point of water is 1.50 atm, which means it is at the temperature and pressure where water can exist as a solid, liquid, and gas simultaneously.
To find the pressure of the gas at the temperature at which CO2 solidifies, we need to know the triple point of CO2. The triple point of CO2 is -56.6°C and 5.1 atm.
If the volume of the gas remains unchanged, then its pressure will change with a change in temperature. Using the ideal gas law, PV = nRT, we can find the new pressure of the gas:
P1V1 = P2V2
At the triple point of water:
P1 = 1.50 atm
V1 = V (unchanged)
T1 = 0.01°C (triple point of water)
At the triple point of CO2:
P2 = 5.1 atm
V2 = V1 (unchanged)
T2 = -56.6°C
Using the ideal gas law and solving for P2:
P2 = P1(T2/T1)
P2 = 1.5 x (-56.6+273.15) / (0.01+273.15)
P2 = 0.818 atm
Therefore, the pressure of the gas at the temperature at which CO2 solidifies is 0.818 atm.
HELP PLEASE I need to finish this asap
Answer:
I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.
Explanation:
pls vote brainliest
SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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b. Density and relative density.
Explanation:
density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC
Which image shows an object or objects moving with accelerated motion?
.
im
5m.
1m
5m.
Answer:
5m
Explanation:
Answer: The answer is A with 0m
Explanation:
77. A drag racing vehicle travels from 0 to 100 mph in 5 seconds north. What is the acceleration?
a).004
s2
b).0056 m/s2 c).0079"
d).01 m/s2
M
m
Answer:
a
Explanation:
i just took the test
Which statements accurately describe mechanical waves? Check all that apply.
The accurate statements that describe mechanical waves are: Mechanical waves require a medium , Mechanical waves transfer energy, Mechanical waves can be longitudinal or transverse, Mechanical waves can be categorized as compressional or shear waves, Mechanical waves obey the principles of reflection, refraction, and interference, Mechanical waves have measurable properties such as wavelength, frequency, and amplitude.
Mechanical waves are a type of wave that require a medium, such as a solid, liquid, or gas, to propagate. They are characterized by the transfer of energy through the oscillation or vibration of particles in the medium. Here are the accurate statements that describe mechanical waves:
1. Mechanical waves require a medium: This statement is true. Mechanical waves cannot propagate in a vacuum because they rely on the interaction of particles in a medium to transfer energy.
2. Mechanical waves transfer energy: This statement is true. Mechanical waves transport energy from one location to another as the particles of the medium vibrate or oscillate.
3. Mechanical waves can be longitudinal or transverse: This statement is true. Mechanical waves can exhibit different types of motion. In longitudinal waves, the particles of the medium oscillate parallel to the direction of wave propagation. In transverse waves, the particles oscillate perpendicular to the direction of wave propagation.
4. Mechanical waves can be categorized as compressional or shear waves: This statement is true. In a compressional wave, the particles of the medium undergo compression and rarefaction as the wave passes through. In shear waves, the particles move perpendicular to the direction of wave propagation, resulting in a sideways displacement.
5. Mechanical waves obey the principles of reflection, refraction, and interference: This statement is true. Mechanical waves can reflect off surfaces, change direction when passing through different media (refraction), and exhibit interference patterns when two or more waves interact.
6. Mechanical waves have measurable properties such as wavelength, frequency, and amplitude: This statement is true. Mechanical waves can be described by various properties. Wavelength represents the distance between two consecutive points in the wave, frequency is the number of wave cycles per unit of time, and amplitude is the maximum displacement of particles from their equilibrium position.
These statements accurately describe mechanical waves and their properties, highlighting the key characteristics of this type of wave propagation.
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A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
⠀⠀⠀
Next
cm³. A cubic box with a volume of [
m on each side.
The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.
Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.
Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.
So the filled cubic box has a side length of approximately 0.141 m.
a microwave operates at a frequency of 2400 MHZ. the height of the oven cavity is 25 cm and the base measures 30 cm by 30 cm. assume that microwave energy is generated uniformly on the uipper surface. What is the power output of the oven
Complete question is;
A microwave oven operates at a frequency of 2400 MHz. The height of the oven cavity is 25 cm and the base measures 30 cm by 30 cm. Assume that microwave energy is generated uniformly on the upper surface of the cavity and propagates directly
downward toward the base. The base is lined with a material that completely absorbs microwave energy. The total microwave energy content of the cavity is 0.50 mJ.
Answer:
Power ≈ 600,000 W
Explanation:
We are given;
Frequency; f = 2400 Hz
height of the oven cavity; h = 25 cm = 0.25 m
base area; A = 30 cm by 30 cm = 0.3m × 0.3m = 0.09 m²
total microwave energy content of the cavity; E = 0.50 mJ = 0.5 × 10^(-3) J
We want to find the power output and we know that formula for power is;
P = workdone/time taken
Formula for time here is;
t = h/c
Where c is speed of light = 3 × 10^(8) m/s
Thus;
t = 0.25/(3 × 10^(8))
t = 8.333 × 10^(-10) s
Thus;
Power = (0.5 × 10^(-3))/(8.333 × 10^(-10))
Power ≈ 600,000 W
Describe the relationship between frequency and wavelength of the visible light spectrum?
Which is an SI base unit that makes up part of the unit of energy?
candela
ampere
kelvin
kilogram
The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole
The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²
Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
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Find 5 Galaxies With Redshifts Less Than 0.001 And 10 Galaxies With Redshifts Greater Than 0.001. Record The Redshift And Distance And Calculate The Radial Velocity (Using The Method From Question 3) For Each Of These Galaxies. Make Sure You're Recoding The Distance In Mpc, If The Distance Is Given In Kpc Rather Than Mpc You Can Convert It Into Mpc Using TheThis question hasn't been solved yetAsk an expertFind 5 galaxies with redshifts less than 0.001 and 10 galaxies with redshifts greater than 0.001. Record the redshift and distance and calculate the radial velocity (using the method from Question 3) for each of these galaxies. Make sure you're recoding the distance in Mpc, if the distance is given in kpc rather than Mpc you can convert it into Mpc using the converstion 1000 kpc = 1 Mpc. You can use the tables on the second page of the lab for this if you want, but you can use normal paper as well, just make sure you don't reuse galaxies on accident.Graph all the galaxies with positive redshifts (don't use galaxies with negative redshifts) in excel or a similar spread sheet program with distance in Mpc on the x-axis and radial velocity in km/s on the y-axis (make sure you label the axis as such). Create a line of best fit for this graph and display the equation on the graph. If you're not sure how to do this, see the Excel Tutorial video.
The 5 galaxies with redshifts less than 0.001 are Ages, cosmos , hypernova , Gama , VVDS and greater than 0.001 are Devils, achne, simar , vipers, MGC, 2SLAQ,QCD, SAPM,AARS and ESP.
A more tricky task is determining the distance to the galaxy. For nearby galaxies, standard candlesticks such as Cepheid variables and Type I supernovae can be used. But in very distant galaxies, we have to resort to more indirect methods. The main assumption of this lab is that similar Hubble-type galaxies are actually similar true sizes no matter how far apart they are. This is known for adopting the "standard ruler". First, we need to adjust the actual size using a galaxy whose actual distance is known. Find the galaxies in the sample that are Sb galaxies to calibrate the distance using the nearby Sb galaxy M31, the Andromeda galaxy. The distance to the Andromeda Galaxy is known from observations of Cepheid variable stars. Then, to determine the distances to more distant similar galaxies, we only need to measure their apparent (angular) magnitudes and use the small-angle approximation: a=s/dTo study more about Andromeda galaxy -
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How long does it take to drive at 8 m/s for 30 km (answer in seconds)
Answer:
60/80 x 30 = 1800/80 = 22.5 minutes. 22.5 minutes would be required to drive 30 km
Explanation:
1350 seconds
The table shows the relationship between the masses of two objects, the distance between the two objects, and the gravitational force between the objects. A 4-column table with 5 rows. The first column labeled Mass of Object 1 (kilograms) has entries 1, 2, 2, 3, 9. The second column labeled Mass of Object 2 (kilograms) has entries 1, 1, 2, 3, 3. The third column labeled Distance between Objects 1 and 2 (meters) has entries 1, 1, 2, 1, 3. The fourth column labeled Gravitational Force Objects 1 and 2 (Newtons) has entries 1 G, 2 G, 1 G, 9 G, 3G. Which conclusion is supported by the data in the table? An increase in the mass of an object causes the same decrease in the gravitational force. An increase in the distance between the objects causes the same decrease in the gravitational force. An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. An increase in the mass causes a greater change in the gravitational force than the same increase in the distance between the objects. Brainlyest for correct answer!
Answer:
C
Explanation:
edge 2020... Using elimination it's the only one that makes sense.
The statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
What is gravitational force?The gravitational force is a force that attracts all mass-bearing objects. The gravitational force is referred to as attractive because it always strives to pull masses together rather than pushing them apart.
As we know, the gravitational force is given by:
\(\rm F = \dfrac{Gm_1m_2}{r^2}\)
Where, G is the gravitational constant.
m1 and m2 are masses.
r is the distance between the masses.
From the data given in the table, shows that:
The gravitational force is indirectly proportional to the square of the distance.
Thus, the statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.
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How are work and power different
Work is defined as the process of energy transfer to the motion of an object through the application of force. Power is defined as the amount of energy transferred in unit time.
Which of the following best explains how earth is heated through radiation
Answer:
The sun touches earth during daytime and the suns rays heat our earth giving us heat. The sun heating the earth is also considered radiation.
Explanation:
How can i balance this Erick
Answer:
Option a. The baton's center of mass is closer to the larger sphere, making the lever arm distance between your hand and the center of mass longer in option a than in option b. The longer lever arm distance gives you finer control.
find the coefficient of kinetic friction between the child and the slide if the slide is inclined at an angle of 28° below the horizontal
Given:
The acceleration of the child, a=1.26 m/s²
The angle of inclination, θ=28°
To find:
The coefficient of kinetic friction between the child and the slide.
Explanation:
The net force acting on the child when it is sliding down the slide is given by,
\(\begin{gathered} ma=mg\sin\theta-f \\ =mg\sin\theta-N\mu \\ =mg\sin\theta-mg\cos\theta\text{ }\times\mu \end{gathered}\)Where f is the frictional force, N is the normal force acting on the child, g is the acceleration due to gravity, and μ is the coefficient of kinetic friction.
On simplifying the above equation,
\(\begin{gathered} a=g\sin\theta-g\mu\cos\theta \\ \implies g\mu\cos\theta=g\sin\theta-a \\ \implies\mu=\frac{g\sin\theta-a}{g\cos\theta} \end{gathered}\)On substituting the known values,
\(\begin{gathered} \mu=\frac{9.8\sin28\degree-1.26}{g\cos28\degree} \\ =0.386 \end{gathered}\)Final answer:
The coefficient of kinetic friction between the child and the slide is 0.386