The International Space Station is in a 300-mile-high orbit.Part AWhat is the station's orbital speed? The radius of Earth is 6.37×106m, its mass is 5.98×1024kg.Express your answer with the appropriate units.Part BWhat is the station's orbital period?Express your answer in minutes.

Answer:

Read a stroy and drink milk and relax

Explanation:

Answer:

If Mica sends both waves through a vacuum instead of air, water, and glass, then she would find that the waves travel at the same speed. This is because a vacuum is a completely empty space with no matter or medium to interact with, and the speed of light is constant in a vacuum. Therefore, any electromagnetic waves, including light waves, radio waves, and microwaves, would travel at the same speed in a vacuum.

The formula for centripetal acceleration within the spacecraft is: ac =The outside radius of a spacecraft's doughnut-shaped body is 440 metres. The people are standing with thier feet on an outer rim and their heads .

Earth's crust is made of igneous, metamorphic, or sedimentary rocks, which range in composition from mud or clay to diamonds or coal. Igneous rocks, which are created as magma cools, are the most prevalent types of rocks in the crust. Igneous rocks like granite and basalt are abundant in the crust of the Earth.

The distance between any two places on a circle's circumference is in fact its radius. R or r are frequently used to denote it. Almost all calculations involving circles take this quantity into account. The radius of a circle can be used to determine a circle's circumference and surface area.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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The child pushes the merry-go-round, which causes it to rotate by an angle of around 85.5 radians.

The sum of the moments of inertia of the toddler and the merry-go-round (both about the same axis) represents the total moment of inertia: I=(28.13kg⋅m2)+(56.25kg⋅m2)=84.38kg⋅m2. When known values are substituted into the equation.

ω1 = 0 rad/s (initially at rest)

ω2 = (20.0 rpm) * (2π rad/rev) / (60 s/min) ≈ 4.19 rad/s

The average angular acceleration is given by the equation:

αavg = (ω2 - ω1) / t

where t is the time interval. Substituting the given values, we get:

αavg = (4.19 rad/s - 0 rad/s) / 41.0 s

αavg ≈ 0.102 rad/s²

Therefore, the average angular acceleration of the merry-go-round is approximately 0.102 rad/s².

To find the angular displacement of the merry-go-round, we can use the equation:

Δθ = ω1*t + (1/2)αt²

where ω1 is the initial angular speed, α is the average angular acceleration, and t is the time interval.

Substituting the given values, we get:

Δθ = 0 rad/s * 41.0 s + (1/2) * (0.102 rad/s²) * (41.0 s)²

Δθ ≈ 85.5 rad

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idrk but good luck on this very hard question

Answer: hii

Explanation:

Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

Answer:

μ = tanθ = tan30 = 0.58

Explanation:

μ = force parallel/force perpendicular = mgsinθ/mgcosθ = tanθ

Answer:

A. 5.03 solar mass.

B. the masses of Star A and B are 1.01 solar mass and 4.02 solar mass respectively.

Explanation:

A. The sum of their two masses can be found using Kepler's third law:

\(\frac{P^{2}}{a^{3}} = \frac{4\pi^{2}}{G(m_{A} + m_{B})}\)

Where:

P: is the period = 5 y = 1.58x10⁸ s

a: is the separation between the stars = 5 AU = 7.5x10¹¹ m

G: is the gravitational constant = 6.67x10⁻¹¹ m³kg⁻¹s⁻²

\(m_{A}\) and \(m_{B}\) are the masses of Star A and Star B respectively.    

\(m_{A} + m_{B} = \frac{4\pi^{2}a^{3}}{P^{2}G} = \frac{4\pi^{2}(5 AU*\frac{1.5\cdot 10^{11} m}{1 AU})^{3}}{(1.58 \cdot 10^{8} s)^{2}6.67 \cdot 10^{-11} m^{3}*kg^{-1}*s^{-2}} = 1.00 \cdot 10^{31} kg*\frac{1 M_{\bigodot}}{1.989\cdot 10^{30} kg} = 5.03 M_{\bigodot}\)    

Hence, the sum of their two masses is 5.03 solar mass.  

B. Their individual masses can be found using the center of the mass equation:

\( a_{B} = (\frac{m_{A}}{m_{A} + m_{B}})a \)

Where:

\(a_{B}\) is the distance of Star B from the center of the mass

Since, \(a_{A}\) is four times \(a_{B}\) and a = 5 AU we have:

\( a_{A} = 4a_{B} \)

\( a = a_{A} + a_{B} \)

\( a_{B} = a - a_{A} = a - 4a_{B} \rightarrow a_{B} = \frac{a}{5} \)      

Then, their individual masses are:

\(\frac{a}{5} = (\frac{m_{A}}{5.03 M_{\bigodot}})a\)  

\(m_{A} = \frac{5.03 M_{\bigodot}}{5} = 1.01 M_{\bigodot}\)

Now, the mass of Star B is:

\(m_{B} = m_{T} - m_{A} = 5.03 M_{\bigodot} - 1.01 M_{\bigodot} = 4.02 M_{\bigodot}\)

Therefore, the masses of Star A and B are \(1.01 M_{\bigodot}\) and \(4.02 M_{\bigodot}\) respectively.

I hope it helps you!                              

Answer:

The acceleration of the object occurred at 2.95 s

Explanation:

Given;

initial angular velocity of the object, ω = 0

angular acceleration, α = 2.3 rad/s²

angular displacement of the object, θ = 10 radians

The time of the motion is given by the following kinematic equation;

θ = ω + ¹/₂αt²

θ = 0 + ¹/₂αt²

θ = ¹/₂αt²

\(t^2 = \frac{2 \theta}{\alpha}\\\\t = \sqrt{\frac{2 \theta}{\alpha}}\\\\t = \sqrt{\frac{2 *10}{2.3}}\\\\t = 2.95 \ s\)

Therefore, the acceleration of the object occurred at 2.95 s

Since the beginning of the industrial revolution, human activity has been responsible for a substantial alteration in the chemical makeup of the atmosphere as well as a large rise in the concentration of greenhouse gases. These gases enable the atmosphere to retain more heat, similar to how a greenhouse works, which ultimately results in long-term changes to our climate.

This is further explained below.

Generally, The molecules of the many gases that make up our atmosphere make up the air that we breathe.

Nitrogen makes up roughly 78 percent of the atmosphere, followed by oxygen (about 21 percent), and argon (nearly 1 percent). There are also, but in much lower concentrations, other chemicals that may be found in the air we breathe.

In conclusion, gases enable the atmosphere to retain more heat, similar to how a greenhouse works, which ultimately results in long-term changes to our climate.

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Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Explanation:

The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Answer:

8,345,925 lb-f

Explanation:

We know pressure P = F/A = ρgh ⇒ F = ρghA = ρgV

F = ρgV where F = force, ρ = density of water = 1000 kg/m³ , g = acceleration due to gravity = 9.8 m/s² and V = 1 × 10⁶ gallons = 1 × 10⁶ gallons × 1m³/264.2 gallons = 3785 m³

So, F = ρgV = 1000 kg/m³ × 9.8 m/s² × 3785 m³ = 37,093,000 N

We now convert Newtons to pound-force.

1 N = 0.225 lb-f

So, F = 37,093,000 N = 37,093,000 N × 0.225 lb-f/1 N = 8,345,925 lb-f

So, the tower must be able to withstand 8,345,925 lb-f

One revolution is equal to 360 degrees, so the disk has completed 1/4 of a revolution or 0.25 revolutions.

We can use the fact that the angle rotated during the entire 1.0 s period is 90 degrees to calculate the number of revolutions completed. Disk accelerates at a rate of:

\(600 rad/s^2 for 1/2 s\)

ω = ω0 + αt,(ω is the final angular velocity, ω0 is initial angular velocity, α is angular acceleration, t is the time). The angular velocity remains constant at 300 rad/s. Using the equation

θ = ω0t + 1/2 αt^2,

Now, v = rω, ( v is linear speed of dot, r is radius of  disk (which is half its diameter, or 4.0 cm), and ω is the angular velocity.

\(t = 1.0 s = 120 cm/s.\)

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Answer:

\(\huge\boxed{\sf P = 10\ Watts}\)

Explanation:

Given:

Energy = E = 200 J

Time = t = 20 s

Required:

Power = P = ?

Formula:

P = E / t

Solution:

P = 200 J / 20 s

P = 10 Watts

\(\rule[225]{225}{2}\)

Hope this helped!

Jared will go up the ramp 2.5 meters.

Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.

The work done by Jared on the ramp can be calculated as follows:

W = mgh

where m is the mass of Jared and his skateboard, g is the acceleration due to gravity (9.8 m/s²), and h is the change in height.

The work done by Jared on the ramp is equal to the initial increase in kinetic energy:

W = (1/2)mv²

Setting these two equations equal to each other, we get:

mgh = (1/2)mv²

Solving for h, we get:

h = (1/2)v²/g

Plugging in the known values, we get:

h = (1/2)(7 m/s)²/9.8 m/s² = 2.5 m

Thus, he will go up the ramp 2.5 m.

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Answer:

Although there are only 118 elements that have been discovered and entered in the Periodic Table, there is an almost infinite multiplicity of things, materials, resources and other objects in the universe.

This is so because each of these elements can be combined with the others, varying its proportion and the inclusion of different elements, forming different things according to the proportion in which each element has been used.

Answer:

1.Lactose

I Hope its help for you

Have a good day

h= height = 19 m

g.e = gravity on earth = 9.8 m/s^2

g.u = gravity on Uranus = 9.8 x (88.9/100) = 8.71 m/s^2

Apply :

h = vot + 1/2 gt^2

h= 1/2 g t^2

t = √(2h/g)

Earth:

t= √(2(19)/9.8) = 1.97 s

Uranus

t= √(2(19)/8.71) = 2.09 s

Tu - Te = 2.09 - 1.97 = 0.12 s

Answer : 0.12 s

Answer:

The group that remains unaltered is called the control group.

With a 25.1 m/s2 acceleration, 2,946.19 N of horizontal force is required to push the trunk across the floor to the left.

Usually, the Greek letter mu is used to indicate it (). is mathematically equivalent to F/N, where F denotes frictional force and N is normal force. Due to the fact that F and N are both measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds).

An object's mass times its acceleration equals the object's net force:

F_net = m * a

The applied force less the frictional force equals the net force acting on the trunk:

F_net = F_applied - F_friction

The force of friction is given by:

F_friction = μ * N

As there is no vertical acceleration of the trunk, its weight is equal to the normal force:

N = m * g

where g is the gravitational acceleration.

When you combine everything, you get:

F_net = F_applied - μ * m * g = m * a

With the applied force factored in, we obtain:

F_applied = m * (a + μ * g)

Plugging in the given values, we get:

F_applied = 105 N * (25.1 m/s^2 + 0.63 * 9.81 m/s^2) = 2,946.19 N

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The equation for the magnitude of the system's acceleration is a = g + (2M/m), where g is the acceleration due to gravity and M and m are the masses of the two objects.

Acceleration is the rate of change of velocity in an object over time. It is the rate of change of the speed of an object, and is defined as the change in velocity divided by the change in time. In other words, it is the rate at which an object's speed changes. Acceleration can be caused by a change in the speed of an object, or by a change in its direction. It is usually measured in meters per second squared (m/s2). Acceleration can be either positive or negative, depending on the direction of the change in velocity.

a = g + (2M/m)

a = 9.81 m/s^2 + (2(8 kg)/(3 kg)) = 13.87 m/s^2

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When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

We have

\(a = \frac{40}{20} = \frac{4}{2} \\ \)

We have the final answer as

Hope this helps you