The key to successfully solving two-dimensional relative velocity problems is drawing the proper triangle to represent all three velocity vectors. Is this true or false?

Answer:

Nicolaus Copernicus

Explanation:

Nevertheless, Copernicus began to work on astronomy on his own. Sometime between 1510 and 1514 he wrote an essay that has come to be known as the Commentariolus (MW 75–126) that introduced his new cosmological idea, the heliocentric universe, and he sent copies to various astronomers

Answer:

75.0 cm

Explanation:

becouse i don,t no the right answer

Answer:

If the car travels 150 kilometers to the Southeast, and then 50 kilometers to the North, it is understood that the car does not travel the same way out as it does back. Therefore, the car's displacement will be the sum of both distances traveled, that is, 150 + 50, which is equal to 200. Therefore, the car traveled about 200 kilometers from its starting point.

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Answer:

hello your question lacks the required diagram attached below is the complete question with the required diagram

answer : Qtotal = 807.4 Mw

Explanation:

Given Data :

disk properties :

∈ = 0.65

D = 200 mm

Ts = 400⁰c

attached below is the detailed solution

The total rate of Heat transferred from the disk

Qtotal = 807.4 Mw

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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Answer:

The answer is C

Pls mark as brainliest

(a) The angular speed of the system at the instant the beads reach the end of the rod is 9.26 rad/s.

(b) The angular speed of the rod after the after the beads fly off the rod's ends is 25.71 rad/s.

I = ¹/₁₂ML²

I =  ¹/₁₂ (0.1)(0.5)²

I = 0.0021 kgm²

For the beads, I = 2Mr² = 2(0.03 x 0.1²) = 0.0006 kgm²

Total initial moment of inertia, Ii = 0.0021 kgm² + 0.0006 kgm²

I(i)= 0.0027 kgm²

When the beads reach the end, I = 2Mr² = 2(0.03)(0.25)² = 0.00373 kgm²

Total final moment of inertia, I(f) = 0.0021 kgm²  +  0.00373 kgm²

I(f) = 0.00583 kgm²

The speed of the system at the moment the beads reach the end of the rod is calculated as follows;

\(I_i \omega_i = I_f\omega _f\\\\\omega _f = \frac{I_i \omega_i}{I_f}\)

\(\omega_f = \frac{0.0027 \times 20}{0.00583} \\\\\omega _f = 9.26 \ rad/s\)

\(\omega_f = \frac{0.0027 \times 20}{0.0021} \\\\\omega _f = 25.71 \ rad/s\)

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Answer:

24g/225cm^3

Explanation:

Density = mass/volume.

Calculate volume first so u do 5cm x 3cm x 15cm.

Volume is 225cm^3.

Then divide mass by volume.

The density of the object is 24g/225cm^3.

Answer:

The object in motion is deaccelerating in the negative direction.

Explanation:

Interpret the given position-time graph.

Observing the graph we can determine the slope is negative and is gradually flattening out. Thus, we can conclude the object in motion is deaccelerating in the negative direction.

Answer:

Explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

\(E_{k} =1/2mv^{2}\)

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1

A balanced force is referred to as when all the applied forces create an equilibrium which is therefore denoted as option A.

This is referred to as an influence that can change the motion of an object and the formulas is F= ma where m is the mass and a is acceleration of the body involved with its unit being Newton.

Equilibrium on the other hand  is referred to as as a state in which all the individual forces and torques exerted upon an object are balanced and there is no movement of the body in any type of direction in this type of scenario.

Balanced force is referred to as a situation in which all the applied forces which creates an equilibrium as denoted above which is therefore the reason why option A was chosen as the correct choice.

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Answer:

S = Vo t + 1/2 a t^2 = 1/2 a t^2       V0 = 0 for a standing start

t = (2 S / a)^1.2

t = (2 * 30 / (2.0) =  (30)^1/2 = 5.5 sec

Answer: that guy

Explanation:

The height of the cliff is approximately 248.5 meters. It's important to note that this estimate assumes that air resistance is negligible and that the stone is dropped vertically.

We can use the kinematic equation for the vertical motion of the stone to estimate the height of the cliff:

h = 1/2 * g * t^2

where h is the height of the cliff, g is the acceleration due to gravity (9.81 m/s^2), and t is the time taken for the stone to hit the water.

In this case, the time taken for the stone to drop is 7.1 seconds, so we have:

h = 1/2 * (9.81 m/s^2) * (7.1 s)^2

h = 248.5 meters (rounded to one decimal place)

Therefore, the height of the cliff is approximately 248.5 meters. It's important to note that this estimate assumes that air resistance is negligible and that the stone is dropped vertically. In reality, these assumptions may not hold true, so the actual height of the cliff may be slightly different.

One way to estimate the height of a cliff is to use the fact that sound travels at a fixed speed, which is approximately 343 meters per second at room temperature and standard atmospheric pressure. By measuring the time it takes for a sound to travel from the top of the cliff to the bottom and back up, we can estimate the distance between the top of the cliff and the ground.

However, it can be difficult to produce a sound that is loud enough to be heard at the bottom of a cliff, especially in outdoor settings with a lot of ambient noise. A simple alternative is to use the time it takes for a stone to fall from the top of the cliff to the bottom, and then use the kinematic equations of motion to estimate the height of the cliff.

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An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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Answer:

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Answer:

true

Explanation:

this is because potienal energy is energy that is stored, and kinetic is energy being used, as kinetic is used, potential is also being used.

Flute, Clarinet, Saxophone, Piccolo, Tenor Sax oboe

Piccolo

Flute

Clarinet

Saxophone (all registers)

Oboe

English Horn

Bassoon

Answer:

it is the physics that explains how everything works. The best description we have of the. nature of the particles that make up matters and the forces with which they interact. It underlines how atoms work, and so why chemistry and biology work as they do

Answer: the focal length of the CCl4-glass combination is 102.31 cm

Explanation:

Given that;

Index of refraction n1 = 1.55

carbon tetrachloride (CCl4), which has n2 = 1.46

radii of curvature for its surfaces R1 = 4.6cm and R2 = 9.20 cm

the focal length of the CCl4-glass combination = ?

we can determine the focal length using the Formula;

1/f = ( n1 - n2) ( 1/R1 - 1/R)

so we substitute in our values

1/f = ( 1.55 - 1.46 ( 1/4.6 - 1/9.20)

1/f = 0.09 × 0.1086

1/f = 0.009774

f = 1 / 0.009774

f = 102.31 cm

Therefore the focal length of the CCl4-glass combination is 102.31 cm

Answer:

the area is 0.0196 m^2

Explanation:

Recall that pressure is defined as the force over the surface area:

Pressure = Force / Area

Therefore, Area =  Force / Pressure

in our case, the acting force is the gravitational force Fg = m * g = 100 * 9.8 N = 980 N

and the pressure is 50000 N/m^2

Then the acting area is:

980 / 50000 m^2 = 0.0196 m^2

The lens strength or lens power of contact lenses that m should be prescribed to correct the nearsightedness is 59.9 diopters.

The focal length of a lens is the distance from a lens to the focal point of that lens.

It is a measure of how strongly a lens converses or diverges light.

The power of a lens is the inverse of the focal length when given in metres.

Power of a lens = 1/focal length (m)

The focal length = 16.7 mm = 0.0167 M

Power of lens required = 1/0.0167 = 59.9 diopters

Therefore, the lens strength or lens power of contact lenses that m should be prescribed to correct the nearsightedness is 59.9 diopters.

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All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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Answer:

-Positively charged nucleus

-Empty spaced

-Dense core

Explanation:

Answer:

Ocean Liner because its mass is 5000 times more and the bullet's velocity squared is only 1600 times more. This means that the kinetic energy of the ocean liner will be roughly 3 times greater.

Explanation:

The kinetic energy of an object is dependent on mass and velocity.

E = ( 1 / 2 )mv²;

Energy is measured in Joules which is equal to kilogram metres squared per second squared.

1J = ( kg )( m² )( s⁻² ) or 1J = ( kg )( m² ) / ( s² )

We can substitute the mass and velocity directly into the equation because the question gives the values in metres and kilograms.

BULLET:

E = ( 1 / 2 )( 0.0014kg )( 397m / s )²;

E = ( 0.0007kg )( 157609m² )( s⁻² );

E = 110.3263kgm²s⁻²;

E = 110.3263J;

I will just skip some steps because you get the idea.

OCEAN LINER:

E = ( 1 / 2 )( 5.9107kg )( 13m / s )²;

E = 499.45415J;

To calculate the weight of the block, we can use the formula:

Weight = Mass x Gravity

Where gravity is approximately 9.8 m/s^2.

First, we need to find the mass of the block. We can use the formula:

Density = Mass / Volume

The volume of the block is:

Volume = Length x Width x Height

Volume = 10 cm x 3 cm x 2 cm

Volume = 60 cm^3

We don't know the density of the metal, so we can't calculate the mass directly. However, we can use the spring balance reading to find the weight of the block.

The spring balance has a maximum reading of 10 Newtons, which corresponds to a length of 20 cm. When the block is hung on the balance, it stretches the string by 15 cm. The extension of the spring is proportional to the weight of the block, so we can use the following proportion:

Extension of spring / Total length of spring = Weight of block / Maximum weight of spring balance

Substituting the values we have:

15 cm / 20 cm = Weight of block / 10 N

Solving for the weight of the block:

Weight of block = 7.5 N

Now we can find the mass of the block:

Mass = Weight / Gravity

Mass = 7.5 N / 9.8 m/s^2

Mass = 0.765 kg

Finally, we can calculate the density of the metal:

Density = Mass / Volume

Density = 0.765 kg / 60 cm^3

Density = 0.01275 kg/cm^3

So the weight of the block is 7.5 N, the mass of the block is 0.765 kg, and the density of the metal is 0.01275 kg/cm^3.

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Explanation:

Finger bones have joints.

Answer: true , finger bones have joints

Explanation:

The correct answer is "c. horizontal component of the normal force." When a railroad train rounds a banked track, the centripetal force needed comes from friction, but from the horizontal component of the normal force.

It is the component of the normal force that acts perpendicular to the direction of motion. The normal force is the force exerted by a surface on an object that is in contact with it. It acts perpendicular to the surface and helps to support the weight of the object. In the case of a train rounding a banked track, the normal force acts perpendicular to the surface of the track and helps to keep the train from sliding off the track.

The horizontal component of the normal force is the component of the normal force that acts in the direction of motion. It acts parallel to the surface of the track and helps to provide the centripetal force needed to keep the train moving in a circular path.

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