The length of a rectangle is 7cm longer than the width of the rectangle. 4 of these rectangles are used to make this 8-sided shape. The perimeter of the 8-sided shape is 70cm. Work out the area of the 8-sided shape

Answer:

a = 29

b = 20

Step-by-step explanation:

2a - 1 = 57

    + 1     + 1

2a = 58

/ 2    / 2

a = 29

2a - 1 + 7b - 17 = 180

2 (29) - 1 + 7b - 17 = 180

58 - 1 + 7b - 17 = 180

57 + 7b - 17 = 180

7b + 40 = 180

      - 40     - 40

7b = 140

/ 7      / 7

b = 20

Answer:

10.

Step-by-step explanation:

If you're subtraction a negative number, you are basically adding a positive number. 5-(-5) = 5+5.

Hey there!

GUIDE:

2 negatives = positive

2 positives = positive

1 negative & 1 positive = negative

1 positive & 1 negative = negative

Negatives are BELOW 0 and they are to the LEFT of 0

Positives are ABOVE 0 and they are to the RIGHT of 0

ANSWERING the QUESTION

5 - (-5)

= 5 + 5

= 10

Therefore, your answer is: 10

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

9%

Step-by-step explanation:

We can start by changing this number to a fraction.

\(\frac{9}{100}\)

We know that 100 is a whole percentage

Therfore, we would get 9%

The z-score would be most useful if you want to know how many standard deviations from the mean a single score in a data set falls. So, the answer to the given question is option B) Az score.

The z-score is a standard score that indicates how many standard deviations an observation is from the mean. A z-score expresses the difference between a measurement and the mean in units of standard deviation. It is calculated as follows: Z-score= (score – mean) / standard deviation

The z-score is frequently utilized in statistics as an index of the likelihood that a result will occur. It is often utilized to determine whether a value is significantly different from the average. It is also known as a standard score or a normal deviate.

The z-score indicates how many standard deviations an observation is from the mean. A positive z-score indicates that the measurement is above the mean, whereas a negative z-score indicates that the measurement is below the mean. A z-score of zero indicates that the score is equal to the mean.

Hence, the answer to the given question is option B) Az score.

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ANSWER

81 people

EXPLANATION

Let p be the number of people that attend the party.

Under plan A, the inn charges $30 for each person, so the value y of a party for p people is,

Then, under plan B, the cost is $1300 for a maximum of 25 people - this means that if 1 to 25 people attend the party, the cost is the same, $1300. For each person in excess of the first 25 - this means for 26, 27, 28, etc, the inn charges $20 each. The cost for plan B is,

The last part, (p - 25), is the part of the equation that separates the first 25 attendees. This equation works for 25 people or more, but it is okay to solve this problem. Note that for p = 25, the cost for plan A is,

Which is less than the cost of plan B ($1300).

We have to find for what number of people attending the party, the cost of plan B is less than the cost of plan A,

We have to solve this for p. First, apply the distributive property of multiplication over addition/subtract4ion to the 20,

Add like terms,

Now, subtract 20p from both sides,

And divide both sides by 10,

For 80 people, the costs of the plans are,

Both have the same cost. The solution to the inequation was the number of people, p, is more than 80. This means that for 81 people the cost of plan B should be less than the cost of plan A,

For 81 people, plan B costs $10 less than plan A.

We move all terms to the left.

We add all the numbers and all the variables.

We move all terms containing x to the left hand side, all other terms to the right hand side.

Answer:

180 - 70 = 110 degrees

Step-by-step explanation:

180 is half a circle, so the half minus 70 is 110

Answer:

What is the question? It is incomplete

Step-by-step explanation:

Please mark as brainliest !!!!!

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Answer:

heres ur answer x=2

heres what i used to solve it PEMDAS

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer: It's false.

I believe you would do (5-3) first.

Answer:

false

Step-by-step explanation:

Answer:

Quadrant 2

Step-by-step explanation:

-8 - 9 = -17

5 - (-1) = 6

(-17, 6) = second quadrant

Answer:

(-9, 0), (-8, 1), (-7, 2), (-6, 3) and (-5, 4)

Step-by-step explanation:

From the graph attached,

Ordered pairs which lie on the given line (-9, 0), (0, 3), (3, 4), (6, 5) and (9, 6).

Since all the points lie on the same line, rate of change of the linear function will be defined by the slope of the given line.

Slope of the line passing through (0, 3) and (3, 4) = \(\frac{y_2-y_1}{x_2-x_1}\)

                                                                                  = \(\frac{4-3}{3-0}\)

                                                                             \(m_1\) = \(\frac{1}{3}\)

Now we have to find the ordered pairs which represent a linear function having slope greater than \(\frac{1}{3}\).

So the points will be (-9, 0), (-8, 1), (-7, 2), (-6, 3) and (-5, 4).

Slope of the linear function passing through (-9, 0) and (-8, 1)

\(m_2\) = \(\frac{y_2-y_1}{x_2-x_1}\)

    = \(\frac{1-0}{-8+9}\)

    = 1

Here \(m_2>m_1\)

Answer: 14

Step-by-step explanation: 175 divided by 12.5 is 14

Answer:

a = 2x - b

Step-by-step explanation:

\(x = \frac{a + b}{2}\)

Use the reciprocal of 1/2 to get rid of the fraction by multiplying both sides of the equation by 2/1:

\((\frac{2}{1})x = \frac{a + b}{2} (\frac{2}{1})\)

2x = a + b

finally, subtract b from both sides of the equation to isolate a:

2x - b = a + b - b

2x - b = a

Answer:

x>=9

Step-by-step explanation:

so, we can plot this on a number line

the point at 9 is a solid dot, since brackets (not parenthasis) indicates that we including the number. the shaded part of the line extends all the way to positive infinity. the shaded part means that it is a solution, while the un-shaded parts aren't solutions to [9,infinity) it is x>=9 and not x>9 because 9 is included.

x>=9 is the answer

Given the length of the pencil, the length of the marker is 130.8 millimeters.

Percentage can be described as a fraction of an amount expressed as a number out of hundred. Percentages are represented %.

Length of the marker = (1 + percentage) x length of the pencil

(1.09) x 120 = 130.8 millimeters

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okay so since the area is 22cm^2 , you will need to simplify it.

Which you will get 22*22 and the total would be 484. Which u will divide by 4 ( Square) to get each of the side your looking for.

So your answer is... 121

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path. This is formalized by using the →(if-then) and ∧(logical and) operators.

Given information and corresponding atomic propositions:

We need to formalize the given statements in terms of atomic propositions r, b, and w, which are defined as follows:

r: Rabbits have been seen in the area.

b: Berries are ripe along the path.

w: Walking on the path is safe.

Now, let us formalize each of the given statements in terms of these atomic propositions:

a) Berries are ripe along the path, but rabbits have not been seen in the area.

b: Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.

c: If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.

d: It is not safe to walk along the path, but rabbits have not been seen in the area, and the berries along the path are ripe.

e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path.

The formalizations in terms of atomic propositions are:

a) b ∧ ¬r.b) ¬r ∧ w ∧

b.c) (b → w) ∧ (¬r → w).

d) ¬w ∧ ¬r ∧

b.e) (¬r ∧ ¬b) → w.b ∧

Berries are ripe along the path, but rabbits have not been seen in the area.

This is formalized by using the ∧(logical and) operator.

(¬r ∧ ¬b) → w: It means For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

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The given function is:

The theorem states that the factors are p/q where p is the factors of the last term (constant term) and q is the factors of the leading coefficient.

Here the leading coefficient is -25 and the constant term is -1.

The factors are listed below:

So the value of p/q can be the values shown below:

Hence the possible zeroes of the given function are:

9514 1404 393

Answer:

Step-by-step explanation:

Half the widgets sold were $35 widgets, so the revenue from them was ...

  (70/2)($35) = $1225

This means the remaining $1735 -1225 = $510 in revenue came from the sale of a total of 35 A and B widgets.

If we let 'b' represent the number of B widgets sold, then the revenue is ...

  12(35 -b) + 18b = 510

  6b +420 = 510

  6b = 90

  b = 15 . . . . . . . number of B widgets sold

  35 -b = 20 . . . number of A widgets sold

20 A widgets, 15 B widgets, and 35 C widgets were sold.

__

Check

Total revenue was 20(12) +15(18) +35(35) = 240 +270 +1225 = 1735.

Total widgets were 20 +15 +35 = 70.

The total of A and B was 20 +15 = 35, the same as the number of C.

Mr. Sanchez's class sold 45 fruit pies, and Mr. Kelly's class sold 37 bottles of fruit juice.

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

To solve this question, we use the following representations:

x represents the fruit pies

y represents the fruit juice

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

1.89x + 1.56y = 140.13 ---- the total cost

x + y = 82 --- the number of sales

Make x the subject in x + y = 82

So, we have

x = 82 - y

Substitute x = 82 - y in 1.89x + 1.56y = 140.13

1.89(82 - y) + 1.56y = 140.13

Expand

154.98 - 1.89y + 1.56y = 140.13

Evaluate the like terms

-0.33y = -14.85

Divide by -0.33

y = 45

So, we have

x = 82 - y

x = 82 - 45

Evaluate

x = 37

Hence, Mr. Sanchez's class sold 45 fruit pies, and Mr. Kelly's class sold 37 bottles of fruit juice.

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The Proof for ABD is congruent to CBD is shown below.

The triangles are said to be congruent when two angles and a non-included side of one triangle match the corresponding angles and sides of another triangle.

Two triangles are congruent by side-side-side (SSS), side-angle-side (SAS), angle-side-angle (ASA), angle-angle-side (AAS) and right angle-hypotenuse-side (RHS).

Given:

AB || CD, <CBD = <ADB

In ΔABD and ΔCDB

<CBD = <ADB {Given}

BD= BD {Common}

<ABD = <CDB {Alternate Interior Angle}

So, By ASA Congruence Rule  ΔABD ≅ ΔCDB

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Answer:

6/11 * 5/10

3/11 or 0.27 repeating

Step-by-step explanation:

Answer:

84

Step-by-step explanation:

x/2=3*28/2=3*14 = 42

x=84

Answer:

(6⁴ * 8⁻⁷) ⁻⁹

equivalent expressión is:

1 / (6⁴ * 8⁻⁷)⁹

Step-by-step explanation:

(6⁴ * 8⁻⁷) ⁻⁹

= 1 / (6⁴ * 8⁻⁷)⁹

The critical numbers of the function h(p) = (p - 1) / (p^2 - 5) are "dne" (does not exist).

To find the derivative of h(p), we can apply the quotient rule. Taking the derivative, we have:

h'(p) = \([(p^2 - 5)(1) - (p - 1)(2p)] / (p^2 - 5)^2\)

Simplifying this expression, we get:

h'(p) = \((p^2 - 5 - 2p^2 + 2p) / (p^2 - 5)^2\)

= \((-p^2 + 2p - 5) / (p^2 - 5)^2\)

To find the critical numbers, we set h'(p) equal to zero and solve for p:

\(-p^2 + 2p - 5 = 0\)

However, this quadratic equation does not factor easily. We can use the quadratic formula to find the solutions:

p = (-2 ± √\((2^2 - 4(-1)(-5))) / (-1)\)

p = (-2 ± √(4 - 20)) / (-1)

p = (-2 ± √(-16)) / (-1)

Since the discriminant is negative, the equation has no real solutions. Therefore, the critical numbers of the function h(p) = (p - 1) / (\(p^2\) - 5) are "dne" (does not exist).

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The coordinates of the point M' is (-6,2) when the point M was reflected across x =-2.

Here, assume that there is a point A(a, b). This point is reflected across the line x = -2. When reflected across this line, the value of the y coordinate of this point A will not change, only the value of the x coordinates of the point A will change.

Here, the point M(1,2) is reflected across the line x = -2.

The coordinates of the reflected point M' are (a, b).

The value of will b will remains same as that of the point M.

Now, the location of a,

the distance between the line x = -2 and a will be same as that of the distance between 2 and x =-2 which is 4 units,

So, the location of a will be fours units away from x =-2 and in the opposite direction so, a = -6

So, the Point M' is (-6,2)

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Answer: 182 report cards

Step-by-step explanation:

The ratio of the number of report cards Mrs. Thomas folded to the number of report cards Mrs. Maas folded is 2:3.

Mrs. Maas folded 273 report cards so the number of report cards folded by Mrs. Johnson can be found using direct proportion. Assume Mrs. Johnson folded x report cards:

2             :            3

x              :         273

Cross multiply to get:

3x = 546

x = 546 / 3

x = 182 report cards

The expression for the area under the graph of the function \(f(x) = 4 + sin^2(x)\), where 0 ≤ x ≤ A, using right endpoints as a limit is given by the sum of the areas of rectangles with width A/n and height \(f(x_i)\), where  \(x_i = i(A/n)\)  for i = 1 to n.

To find the expression for the area under the graph of f(x), we divide the interval [0, A] into n subintervals of equal width A/n. We use right endpoints to determine the height of each rectangle. In this case, the height of each rectangle is given by \(f(x_i)\), where \(x_i = i(A/n)\) for i = 1 to n. The width of each rectangle is A/n. Therefore, the area of each rectangle is \([(A/n) * f(x_i)]\)

To find the total area, we sum up the areas of all the rectangles. This can be expressed as the limit as n approaches infinity of the sum from

i = 1 to n of \([(A/n) * f(x_i)]\). Taking the limit as n goes to infinity ensures that we have an infinite number of rectangles and that the width of each rectangle approaches zero. This limit expression represents the area under the graph of f(x) using right endpoints.

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