The main scale of a vernier callipers has n divisions/cm. n divisions of the vernier scale coincide with (n - 1) divisions of main scale. The least count of the vernier callipers is?​

The best shows ax and ay when the object reaches the highest point in its trajectory is aₓ = 0 and \(a_y\) acting downwards. So the 2nd potion is correct.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

A projectile is an object or particle that is launched toward the surface of the earth and moves along a curved route solely due to the force of gravity. In order to evaluate this type of motion, the acceleration and velocity components are split into separate analyses for the horizontal and vertical directions.

At the highest point in object's trajectory;

Acceleration due to gravity acts along negative y axis and no acceleration acts long x axis. so accelerations along x and y axis can be represented by    aₓ = 0 and \(a_y\) acting downwards. So the 2nd potion is correct.

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Answer:

See below

Explanation:

For a right triangle, remember that tan = opposite leg / adjacent leg:

The angle will be found by using the inverse tangent function

arctan ( .3/1.4)  = 12°

The measure of the angle, in degrees, between the resultant and the 1.40-kilometer displacement vector is 12.

In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.

Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed (the amount of velocity), time, and mass are scalars, displacement, velocity, and acceleration are vector quantities.

Therefore, The measure of the angle, in degrees, between the resultant and the 1.40-kilometer displacement vector is 12.

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To make a shadow that appears as a clear shadow and not a blurry shadow, the light source must be small and the object creating the shadow should be placed closer to the light source.

A light source is any object or device that emits light.

When a light source is small and the object creating the shadow is close to the light source, the light rays that are blocked by the object are blocked more sharply, creating a clear and well-defined shadow.

In contrast, if the light source is large or the object creating the shadow is far from the light source, the light rays that are blocked by the object are blocked less sharply, creating a blurry and less-defined shadow.

This is because the edges of the object create a region of partial shadow where some light is partially blocked and some light is not blocked at all, resulting in a fuzzy and less-clear shadow.

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An object floats in water with 5/8 of its volume submerged. The ratio of the density of the obkect to that of water is 5/8.

What is meant by density ?

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The area under the velocity time graph is 125 m and the meaning of the area is displacement.

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

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Answer: 10%

Explanation:

n this case, if the earth' mass goes up by 10%, then the force of gravity on you, or your weight, will increase by the same amount, that is 10%

Answer:

Work done  = 4,998 J

Explanation:

Given:

Mass m = 102 kg

Height h = 5 m

Find:

Work done

Computation:

Work done  = mgh

g = gravitational acceleration = 9.8m/s²

Work done  = (102)(9.8)(5)

Work done  = 4,998 J

Answer:

The water pressure on the upper pipe is 92.5 kPa.

Explanation:

Given that,

Pressure in lower pipe= 120 kPa

Speed of water in lower pipe= 1 m/s

Acceleration due to gravity = 10 m/s²

Density of water = 1000 kg/m³

Radius of lower pipe = 12 m

Radius of uppes pipe = 6 m

Height of upper pipe = 2 m

We need to calculate the velocity in upper pipe

Using continuity equation

\(A_{1}v_{1}=A_{2}v_{1}\)

\(\pi r_{1}^2\times v_{1}=\pi r_{2}^2\times v_{2}\)

\(v_{2}=\dfrac{r_{1}^2\times v_{1}}{r_{2}^2}\)

Put the value into the formula

\(v_{2}=\dfrac{12^2\times1}{6^2}\)

\(v_{2}=4\ m/s\)

We need to calculate the water pressure on the upper pipe

Using bernoulli equation

\(P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho gh_{2}\)

Put the value into the formula

\(120\times10^{3}+\dfrac{1}{2}\times1000\times1^2+1000\times10\times0=P_{2}+\dfrac{1}{2}\times1000\times(4)^2+1000\times10\times2\)

\(120500=P_{2}+28000\)

\(P_{2}=120500-28000\)

\(P_{2}=92500\ Pa\)

\(P_{2}=92.5\ kPa\)

Hence, The water pressure on the upper pipe is 92.5 kPa.

Answer:

D.  resistance increases

Explanation:

The relationship between resistance and wire length is directly proportional, meaning the longer the wire the greater the resistance.  

Answer: The resistance increases.

Explanation: A wire's resistance is directly proportional to its length. This implies that as a wire's length increases, so does its resistance. The following formula describes this relationship:

R = ρ (L/A)

where L is the wire's length, A is its cross-sectional area, R is the wire's resistance, and ρ is the wire material's resistivity.

This formula shows that the resistance will rise when the wire's length is extended while its cross-sectional area remains the same. On the other hand, if we shorten the wire, the resistance will rise. As a result, choice D is the right response.

Answer:

The electric potential energy of the system is 7.87x10⁻²⁰ J.

Explanation:

The electric potential energy is given by:

\(E = \int{Fdr} = \frac{Kq_{1}q_{2}}{r}\)

Where:

q₁ = q₂ is the charge of the protons = 1.62x10⁻¹⁹ C

r is the distance = 3x10⁻⁹ m

K: is the electrostatic constant = 9x10⁹ Nm²/C²

\( E = \frac{Kq_{1}q_{2}}{r} = \frac{9\cdot 10^{9} Nm^{2}/C^{2}*(1.62 \cdot 10^{-19} C)^{2}}{3\cdot 10^{-9} m} = 7.87 \cdot 10^{-20} J \)

Therefore, the electric potential energy of the system is 7.87x10⁻²⁰ J.

I hope it helps you!

The electric potential energy of the system should be 7.87x10⁻²⁰ J.

SInce We know that

fdr = kq1q2/r

Here

q₁ = q₂ i.e. is the charge of the protons = 1.62x10⁻¹⁹ C

r should be the distance = 3x10⁻⁹ m

K should be the electrostatic constant = 9x10⁹ Nm²/C²

Now electric potential energy should be

= (9x10⁹ Nm²/C² * 1.62x10⁻¹⁹ C) /  3x10⁻⁹ m

=  7.87x10⁻²⁰ J.

hence, The electric potential energy of the system should be 7.87x10⁻²⁰ J.

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Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

The moon orbits Earth due to a gravitational field. This  observations provides the best evidence for the claim that gravity acts between objects across a distance.

According to Newton's Law of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is directly proportional to the product of their masses and inversely proportional to their distance from one another.

The moon orbits Earth due to a gravitational field of the earth. Gravity, an attraction force that acts on all objects, keeps the Moon in its orbit. Satellites can orbit a body and fall around it rather than into it if the speed and gravity are just right. Hence, option (B) is correct.

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Phrases in this set (10) 5.0 seconds after observing the flash, You should be 2.7 kilometers away. In an unidentified medium, the wavelength of a sound wave at 2280 Hz is 0.655 m.

The distance between two identical locations (adjacent crests) as in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted across wires or space. In wireless systems, its length is commonly specified in meters (m), centimetres (cm), or micrometer (mm) (mm).

illustrations of wavelengths. All visible light has a wavelength between 400 and 700 nanometers (nm). Yellow light has a wavelength of about 570 nanometers. Infrared energy is defined as being "redder than red" but having a wavelength that's too long to be seen.

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The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.

A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.

The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.

Hence option B is correct.

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Answer:

445

Explanation:

In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or

1/18 × 2π (0.25 m) ≈ 0.087 m

The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:

2/3 × 2π (0.31 m) ≈ 1.3 m

The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of

40 × 2π (0.34 m) ≈ 85 m

The distances traveled by the tips of the hour hand, minute hand and second hand in a 40-min interval are 0.087 m, 1.3 m and 85 m respectively.

In a clock, there are three hands of the clock. One is hour hand, second is minute hand and third one is second hand.

The hour hand of the clock is 0.25 m long. The hour hand sweep 1/12 of the clock face each hour (as there are 12 hours in a clock). Thus, in a 40-minute interval, it will travel the distance of,

\(d=2\pi\times\dfrac{40}{12\times60}(0.25)\\d\approx0.087\rm\; m\)

The minute hand of the clock is 0.25 m long. In a 40-minute interval, it will travel the distance of,

\(d=2\pi\times\dfrac{40}{60}(0.31)\\d\approx1.3\rm\; m\)

The second hand of the clock is 0.25 m long. In a 40-minute interval, it will travel the distance of,

\(d=2\pi\times\dfrac{40\times60}{60}(0.34)\\d\approx85\rm\; m\)

Thus, the distances traveled by the tips of the hour hand, minute hand and second hand in a 40 min interval are 0.087 m, 1.3 m and 85 m respectively

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The equation E = F/q can be used to determine the strength of the electric field (E) at the location denoted by the dot.

The force applied per unit of positive charge is referred to as the electric field's strength, or E. It may be shown from the equation E = F/q. Volts per meter (V/M) or Newton per Coulomb are its SI units.

You should be aware that an electric field is strongest where the lines are close and weakest when the lines are far apart.

The technique above can be used to determine the answer even though the whole question is not given.

The equation E = F/q where gives the magnitude of the electric field (E) at the location denoted by the dot: E = F/q where;

F = Force exerted per unit and

q = The electric charge there is positive.

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Answer:

The answer is 6.

90 - (3+9) • 7

90 - (12) • 7

90 - 12 • 7

90 - 84

6

The mass of the wheel is 0.38 kg. It is related to weight, which is the force exerted on an object due to gravity and is proportional to the object's mass.

What is Mass?

Mass is a measure of the amount of matter in an object. It is a scalar quantity and is usually measured in kilograms (kg) in the SI system of units. Mass is a fundamental property of an object and does not change with its location or motion.

Let's start by finding the tension in the wire using the motion of the object. We can use the kinematic equation:

y = (1/2)at^2

where y is the distance the object moves, a is the acceleration, and t is the time. Substituting the given values:

2.95 m = (1/2)a(1.85 s)^2

Solving for the acceleration:

a = 2.47 m/s^2

Now, we can find the tension in the wire using the rotational dynamics of the wheel. The torque due to the tension is equal to the moment of inertia times the angular acceleration:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Since the wheel is rotating without friction, the torque due to the tension is the only torque acting on the wheel, so:

Tension * radius = (1/2)mr^2 * α

where m is the mass of the wheel and r is its radius. We can rearrange this equation to solve for the tension:

Tension = (1/2)ma

Substituting the values we found:

Tension = (1/2)(4.3 kg)(2.47 m/s^2) = 5.31 N

Now we can use the torque equation again to solve for the moment of inertia of the wheel:

Tension * radius = (1/2)mr^2 * α

Substituting the values we found and solving for the moment of inertia:

I = 2(Tension * radius) / α = 0.033 kg·m²

Finally, we can use the moment of inertia to find the mass of the wheel using the formula:

I = (1/2)mr^2

Substituting the values we found:

0.033 kg·m² = (1/2)m(0.288 m)^2

Solving for the mass:

m = 2I / r^2 = 0.38 kg

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Answer:

c

Explanation:

Answer: The novel focused on human emotions (C.)

Explanation:

Answer:

Object with the mass 14g

Explanation:

First object-K.E=1/2mv²

1/2×11×3.6²

=71.28J

Second object- K.E=1/2×0.45×22²

K.E=108.90J

Third object- K.E=1/2×0.014×42²

K.E=12.35J

So second object has the highest kinetic energy

F - f = ma

The sum of forces on the x-axis = ma (since it is not stated that the forces are in equilibrium)

By resolving the Free Body

Simplifying the equation above, we have:

F - f = ma

The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N

The following data were obtained from the question:

The centripetal force can be obtained as illustrated below:

F = mv²/r

= (50 × 7²) / 5

= (50 × 49) / 5

= 2450 / 5

= 490 N

Thus, we can concluded that the centripetal force is 490 N

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Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer:

Wind

Explanation:

Answer:

94,5 x 3,17 = 299,565 m/s

Explanation:

To find the speed of waves (V), you just need to multiply wavelength with frequency. That's all.

The speed of the given electromagnetic waves is equal to 3 × 10⁸ m/s.

The frequency can be described as the number of oscillations of a wave in 1 second. The S.I. units of the frequency can be represented as per second or hertz.

The wavelength can be described as the distance between the two points in phase on the wave w.r.t. each other. The separation between two crests or two troughs on a wave is known as wavelength.

The relation between the wavelength (λ) of the wave, frequency (ν), and speed of the wave (V) can be written as:

V = νλ

Given, the frequency of the wave, ν = 94.5 MHz = 94.5 ×10⁶ s⁻¹

The wavelength of the waves, λ  = 3.17 m

The speed of the waves can determine from the above-mentioned relationship:

V = λν = 3.17 × 94.5 ×10⁶ =  3 × 10⁸ m/s

Therefore, the speed of the wave is equal to 3 × 10⁸ m.

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Answer:

Explanation:

We need the power equation here:

P = W/t where W is work and is defined as

W = F*displacement.

Force is a measure in Newtons, which is also weight. We have the mass of the piano, but we need to find the weight:

w = mg so

w = 166(9.8) so

w = 1600N, rounded to the correct number of sig dig. We use that now in the power equation:

\(4560=\frac{(1600)(15)}{t}\) and isolating the unknown:

\(t=\frac{(1600)(15)}{4560}\) so

t = 5.3 seconds

The particles that are considered nucleons are neutrons and protons. Option B.

Nucleons are particles found in the nucleus of an atom, specifically protons and neutrons.

Protons have a positive charge, while neutrons have no charge, and together they make up the majority of the mass of an atom.

Electrons, on the other hand, are much smaller than protons and neutrons, and they orbit around the nucleus in shells. Since they are not found in the nucleus, electrons are not considered nucleons.

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Answer:

Option A

Explanation:

N is Chloroplast, P is a large centralized vacuole and R is the cell wall which are found only in plant cells. Hence, the given cell is a plant cell.

S = Rough Endoplasmic Reticulum

P = Vacuole

O = Nucleus

T = Smooth Endoplasmic Reticulum

U = Golgi Apparatus

N = Chloroplast

U = Cell Membrane

M = Mitochondria

R = Cell wall

\(\rule[225]{225}{2}\)

Hope this helped!