The pipe carrying feed water to a boiler in a thermal power plant has been found to vibrate violently at a pump speed of 800 rpm. in order to reduce the vibrations, an absorber consisting of a spring of stiffness k, and a trial m, mass of 1 kg is attached to the pipe. this arrangement is found to give the natural frequency of the system as 750 rpm. it is desired to keep the natural frequencies of the system outside the operating speed range of the pump, which is 700 rpm to 1040 rpm. determine the new values ka, and ma, that satisfy this requirement.​

Answers

Answer 1

The new stiffness required to achieve a natural frequency outside the pump speed range is 6171 N/m, and the mass of the absorber remains constant at 1 kg.

To solve this problem, we need to use the equation for the natural frequency of a system:

f = (1/2π) * √(k/m)

where f is the natural frequency, k is the spring stiffness, and m is the mass.

We know that the natural frequency of the system with the absorber attached is 750 rpm. We need to find the new values of k and m that will give us a natural frequency outside of the operating speed range of the pump.

First, we need to convert the pump speed range from rpm to Hz:

700 rpm = 11.67 Hz
1040 rpm = 17.33 Hz

Next, we need to find the frequency range that we want to avoid:

fmin = 11.67 Hz
fmax = 17.33 Hz

Now, we can use the equation for the natural frequency to solve for the new values of k and m:

750 rpm = 12.5 Hz

f = (1/2π) * √(k/m)

12.5 Hz = (1/2π) * √(ka/ma)

Squaring both sides, we get:

156.25 = (1/4π^2) * ka/ma

Multiplying both sides by 4π^2, we get:

ka/ma = 625π^2

So, the new values of ka and ma that satisfy the requirement are:

ka = 625π^2 * ma

We don't know the exact value of ma, but we know that the absorber has a mass of 1 kg. So, we can use this value to find ka:

ka = 625π^2 * 1 kg

ka = 6171 N/m

Therefore, the new value of ka that satisfies the requirement is 6171 N/m.

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Related Questions

The solid cylindrical bar shown is subjected to a bending force F = 55kN, an axial load P = 8 kN, and a torsional load T = 30 kN-mm. The bar is made of AISI 1060 CD steel (Sy = 280 MPa, Sut = 330 MPa). Find the factor of safety based on Maximum Distortion Energy Theory.

Answers

The factor of Safety by Maximum Distortion Energy Theory is given as: N = 6.04

What is Maximum Distortion Energy Theory?

According to this idea, failure by yielding happens when the distortion energy per unit volume in a condition of combined stress equals that associated with yielding in a basic tension test at any location in the body.

What is the calculation for the above value?

Note that we are given the following:

A solid Steel bar subjected to a bending force of F = 55kN

Torsional load T = 30 kN-mm; and

Yield Strength (sy) = 280Mpa

Sut = 330 Mpa

The formula for Normal Stress is given as:

\(\alpha _{x}\) = [UP/πd²] + [ (32* f * L)/πd³]

= [(4 * 8 * 10³)/π * (0.02)²] + [(32 * 55 *10³ * 0.1)/ π * (0.02)³]

= 25.46 + 7.003

\(\alpha _{x}\)= 32.5 Mpa

Tyz = (16T)/πd³

= (16 * 30)/ π * (0.02)³

= 19.098

Tyz = 19.098

Following from the above, sate of stress, we have:

α₁ = αₓ = 32.46 Mpa; and

α₂ = Tyz = 19.098 Mpa;

α₃ = -Tyz = -p19.098 Mpa;

Utilizing the formula given by the Maximum Distortion Energy Theory:

α₁² + α₂² + α₃² - (α₁α₂ + α₂α₃ + α₃α₁)

= Sy²/N²

→ 32.46² + 19.098² + 19.098² - ( 32.46* 19.098 - 19.098² -32.46 *  19.098)

= 280/N²

N = 6.04

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Which premise is the foundation of threat hunting?

a. Cybercrime will only increase.
b. Threat actors have already infiltrated our network.
c. Attacks are becoming more difficult.
d. Pivoting is more difficult to detect than ever before.

Answers

The foundation of threat hunting is the premise that threat actors have already infiltrated our network. Threat hunting is a proactive approach to cybersecurity that involves actively searching for and identifying potential threats or security incidents that may have gone undetected by traditional security measures.

This approach recognizes that the traditional "defense in depth" approach is not always sufficient to protect against increasingly sophisticated and targeted attacks.

While the other options listed - cybercrime will only increase, attacks are becoming more difficult, and pivoting is more difficult to detect than ever before - are certain factors that contribute to the need for threat hunting, they are not the primary premise upon which it is based. Rather, the foundation of threat hunting is the recognition that attackers are already inside the network and may be hiding in plain sight and that proactive measures are necessary to identify and remediate these threats before they can cause damage. By actively searching for threats and anomalies within the network, organizations can take a more proactive and effective approach to cybersecurity.

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234567891234567891234567891

Answers

Answer:

234567891234567891234567891 what is this?????

Explanation:

234567891234567891234567891

IS THIS IS A QUESTION

OH DON'T MIND JUST ASKING

BTW

GOOD MORNING/AFTERNOON/EVENING/NIGHT

HOW ARE YOU

HAVE A GREAT DAY AHEAD

PLS MARK ME AS BRAINLIEST

Which of the following is not a step in the database design process?A) Create tables and columns from entities and attributesB) Select primary keysC) Represent relationshipsD) Create constraints and triggers

Answers

The other three options - creating tables and columns from entities and attributes, selecting primary keys, and representing relationships - are all important steps in the process. D) Create constraints and triggers is not a step in the database design process.

Constraints and triggers are typically added after the initial design to enforce rules and ensure data integrity.
Based on the given options:

A) Create tables and columns from entities and attributes
B) Select primary keys
C) Represent relationships
D) Create constraints and triggers

All these steps (A, B, C, and D) are essential components in the database design process.

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A 1-ft rod with a diameter of 0.5 in. is subjected to a tensile force of 1,300 lb and has an elongation of 0.009 in. The modulus of elasticity of the material is most nearly:

Answers

Answer:

E = 8.83 kips

Explanation:

First, we determine the stress on the rod:

\(\sigma = \frac{F}{A}\\\\\)

where,

σ = stress = ?

F = Force Applied = 1300 lb

A = Cross-sectional Area of rod = 0.5\(\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2\)

Therefore,

\(\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips\)

Now, we determine the strain:

\(strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon = 7.5\ x\ 10^{-4}\)

Now, the modulus of elasticity (E) is given as:

\(E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}\)

E = 8.83 kips

PLS HELP ME
Caterpillars eat the milkweed plant. The milkweed plant is a weed that takes over other plants. Based on these two things, are milkweed plants helpful or harmful to the environment?

Helpful
Harmful
Both helpful and harmful
Neither helpful nor harmful ITS Science

Answers

Answer:

Both helpful and harmful

Explanation:

The milkweed plant is helpful, because it is the host pant for monarch butterflies and helps provide nectar and pollen for many other pollinators.

It is harmful for many reasons, including it's toxic, poisonous, it produces a type of steroid that is able to stop the heart, and they cause many other sicknesses.

Based on the two things above, milkweed plants are both helpful and harmful to the environment.

It is helpful because the milkweed plants acts as source of food for the caterpillar while it is harmful because it kills other plants around it.

What are Milkweed Plants?

This plant is known to belong to the genus  of herbaceous plant. It is called Asclepias as it is a perennial, flowering plants.

It is said to derive its name from latex, that is a milky substance that comes out of it when cells are damaged. monarch caterpillars needs to eat milkweed so that they can survive.

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2. a wheel tractor-scraper is operating on a level grade. assume no power derating is required for equipment condition, altitude, and temperature. use equipment data from figure 6.10. a) disregarding traction limitations, what is the maximum value of rolling resistance (in lb/ton) over which the fully loaded unit can maintain a speed of 15 mph? b) what minimum value of coefficient of traction between the tractor wheels and the traveling surface is needed to satisfy the requirements of part a? for the fully loaded condition, 52% of the weight is distributed to the drive axle. the operating weight of the empty scraper is 74,946 lb.

Answers

We can see here that the maximum value of rolling resistance over which a loaded scraper can maintain is: 780 lb/ton

What is a maximum rolling resistance?

Rolling resistance is the force that resists the motion of a rolling object on a surface. Maximum rolling resistance refers to the highest level of resistance that an object can encounter while rolling on a particular surface.

For a fully loaded condition:

15mph speed, 52% resistanceGrade resistance = 0%

The total resistance = (gross + rolling) resistance

52% = 0% - rolling resistance

rolling resistance = 52%

The maximum rolling resistance = rolling resistance percentage × speed

The maximum rolling resistance = 52% (15 lb/ton)/(1% resistance)

The maximum rolling resistance = 780 lb/ton

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When the normally open ______________________________ input is closed, the sequencer instruction resets to the first output pattern.

Answers

When the normally open reset input is closed, the sequencer instruction resets to the first output pattern.

In a sequencer or programmable logic controller (PLC), the reset input is a control signal that, when activated by closing a normally open switch or contact, causes the sequencer to return to its initial state. This reset action clears any previous outputs and sets the sequencer to start executing from the beginning, typically the first output pattern. It allows for the reinitialization of the sequencer's operation, ensuring consistent and predictable behavior. By opening and closing the reset input, the sequencer can be reset and restarted as needed during the control process.

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will give brainliest and 10 points

what are 5 good wood working projects that are easy.

Answers

Answer:

a bowl, plate,

Explanation:

Please select the Strengthening Mechanisms for Metals: Solid Solution Strengthening Hot Working Annealing Grain Size Growth Precipitation Hardening Grain Size Reduction Cold Working Recrystallization

Answers

The strengthening mechanisms for metals include Solid Solution Strengthening, Hot Working, Precipitation Hardening, Grain Size Reduction, and Cold Working. These processes help improve the mechanical properties of metals, making them stronger and more resistant to deformation.

.The Strengthening Mechanisms for Metals include Solid Solution Strengthening, Precipitation Hardening, Grain Size Reduction, and Cold Working. Solid Solution Strengthening occurs when small atoms are added to the metal matrix to distort the crystal lattice and increase its strength. Precipitation Hardening is a process where a metal alloy is heated and then quenched, causing small particles to form within the metal and harden it. Grain Size Reduction is achieved by reducing the size of the grains in the metal, which leads to an increase in strength. Cold Working involves deforming the metal at room temperature, which increases its strength but also makes it more brittle. Recrystallization is a process where the metal is annealed and then cooled, which causes new grains to form and increases its strength. Hot Working involves heating the metal and then deforming it, which also increases its strength. Annealing is a heat treatment process where the metal is heated and then cooled slowly, which reduces its hardness and increases its ductility. Grain Size Growth occurs when the metal is heated and the grains grow larger, which decreases its strength.

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Discuss two (2) points related to the importance of Health and
Safety Standards in the wood processing industry.

Answers

Health and safety standards in the wood processing industry are crucial for the safety and protection of workers in the industry. They must follow strict procedures to ensure that they are not exposed to harmful elements, and that their health and well-being are not compromised.

Following are the two points related to the importance of Health and Safety Standards in the wood processing industry.

Employee Safety: Wood processing can be dangerous work, and the workers involved are at risk of injury or illness if the proper health and safety precautions are not taken. Employee safety is a top priority in the industry, and the introduction of health and safety standards helps to ensure that workers are protected from potential hazards such as chemical exposure, dust inhalation, and fire hazards. By following these standards, employers can reduce the likelihood of accidents occurring and minimize the risk of injuries or illnesses to their workers.Compliance: Another important aspect of health and safety standards is compliance. Employers who do not follow these standards can face legal action, fines, and even criminal charges in some cases. Compliance ensures that companies are held accountable for their actions and that they take the necessary steps to protect their workers. In addition, companies that follow health and safety standards are seen as more reputable and trustworthy, which can help to attract and retain employees, and maintain good relationships with clients and customers.

In conclusion, health and safety standards in the wood processing industry are essential for the protection of workers and the success of companies in the industry. By prioritizing employee safety and compliance with regulations, employers can minimize the risks associated with wood processing and maintain a safe and healthy work environment.

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An insulated piston-cylinder device initially contains 300 L of air at 120 kPa and 17°C. Air is now heated for 15 min by a 200 W resistance heater placed inside the cylinder. The pressure of air is maintained constant during this process. Determine the entropy change of air, assuming (a) constant specific heats and (b) variable specific heats.
a) AS sys= ____ kJ/k
b) As sys=____ kJ/K

Answers

The entropy changes in the system when there are constant specific heats and variable specific heats are found out to be

a) ASsys= 2.20 kJ/K

b) ASsys= 1.56 kJ/K respectively.

(a) Constant Specific Heat

To solve the problem, use the following formula:

ASsys = Cv ln(T₂/T₁)+R ln(V₂/V₁)

ASsys = [Cv ln(T₂/T₁)] + [R ln(V₂/V₁)]

where: ASsys= system entropy change

R = 0.287 kJ/kg.K

Cv = 0.717 kJ/kg.K

T₁ = 17 + 273 = 290 K (initial temperature)

P₁ = 120 kPa (constant pressure)

P₂ = 120 kPa (constant pressure)

V₁ = 300 L

= 0.3 m³ (initial volume)

V₂ = V₁ [since V is constant]

= 0.3 m³

T₂ = T₁ + q/Cp

where q= amount of heat added

Cp= specific heat of air at constant pressure

From the given data,

Q= P x V

= 120 kPa x 0.3 m³

= 36 kJ

Q/Δt = 200 W

= 200 J/s

Cp= 1.005 kJ/kg.K

[Table A-2, at 17°C, for air]

T₂ = (q/Cp) Δt + T₁

= (200/1.005) x 900 + 290

= 692 K

Now apply the formula for system entropy change.

ASsys = Cv ln(T₂/T₁)+R ln(V₂/V₁)

= 0.717 x ln(692/290) + 0.287 x ln(0.3/0.3)

= 2.20 kJ/K

(b) Variable Specific Heat

To solve the problem, use the following formula:

ASsys = ∫(Cp/T)dT- R ln(V₂/V₁)

whereASsys= system entropy change

ΔT= T₂ - T₁

= (692-290)

= 402 K

R= 0.287 kJ/kg.K

V₁ = V₂

= 0.3 m³

Using the data from Table A-2, Cps and T can be tabulated as:

Cp (kJ/kg.K)T (K)1.0052731.005284.16 (Note: T₂)1.005692

Apply the trapezoidal rule for the integral to get:

ASsys = ∫(Cp/T)dT- R ln(V₂/V₁)

= 0.287[(1.005273/290) + (1.005284.16/273) + (1.005692/692)]- 0.287 ln(0.3/0.3)

= 1.56 kJ/K

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which other factors do you need to consider when preparing to move gondolas?

Answers

The factors that  you need to consider when preparing to move gondolas are:

Heightwidthlength color.

How do you move a gondola?

In choosing gondola one need to look at some  factor in decisions such as height.

Know that it is good to  consider the construction material and also the center wall configuration for its building also.

The factors that  you need to consider when preparing to move gondolas are:

Heightwidthlength color.

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Determine the voltages at all nodes and the currents through all branches. Assume that the transistor B is 100,
VEB=0.7V and VA=0.​

Determine the voltages at all nodes and the currents through all branches. Assume that the transistor

Answers

Answer:

The voltages of all nodes are, IE = 4.65 mA, IB =46.039μA,  IC=4.6039 mA, VB = 10v, VE =10.7, Vc =4.6039 v

Explanation:

Solution

Given that:

V+ = 20v

Re = 2kΩ

Rc = 1kΩ

Now we will amke use of the method KVL in the loop.

= - Ve + IE . Re + VEB + VB = 0

Thus

IE = V+ -VEB -VB/Re

Which gives us the following:

IE = 20-0.7 - 10/2k

= 9.3/2k

so, IE = 4.65 mA

IB = IE/β +1 = 4.65 m /101

Thus,

IB = 0.046039 mA

IB = 46.039μA

IC =βIB

Now,

IC = 100 * 0.046039

IC is 4.6039 mA

Now,

VB = 10v

VE = VB + VEB

= 10 +0.7 = 10.7 v

So,

Vc =Ic . Rc = 4.6039 * 1k

=4.6039 v

Finally, this is the table summary from calculations carried out.

Summary Table

Parameters          IE       IC           IB            VE       VB         Vc

Unit                     mA     mA          μA            V           V          V

Value                  4.65    4.6039   46.039    10.7      10     4.6039

If the driver gear has 10 teeth and is moving at 10 RPMs (revolutions per minute), at what speed would the driven gear move if it has 20 teeth?

Answers

Answer:

  5 rpm

Explanation:

Each turn of the driver gear moves 10 teeth past the point of engagement with the driven gear. That is half of the 20 teeth on the driven gear, so it makes 1/2 turn for each turn of the driver.

In 1 minute, the driver makes 10 turns, so the driven gear makes 5 turns. Its speed is 5 rpm.

There is an AC series circuit that is constructed of a 150.0-ohm resistor along with 300.0 ohm inductive reactance and 200.0 ohm capacitive reactance. What is the difference in phase between the current and resistor voltage of the circuit

Answers

Answer:

  0°

Explanation:

The resistor voltage has the same phase as the circuit current. There is no phase difference.

Answer:

0° (zero degree)

Explanation:

the difference in pjase between the current and resistor voltage of the given 150.0 ohm, 300.0 ohm and 200.0 ohm

How is the foundation for a skyscraper different from a house?

Answers

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

pjm, the regional grid operator that includes peco, has asked for consumers to look for ways to safely conserve electricity until 10 a.m. tomorrow. if your health permits, please consider reducing the use of your electricity.

Answers

PJM Interconnection, the electricity grid operator for 65 million people in 13 states and the District of Columbia, has requested the public in its region to conserve electricity.

What is grid?GRID is a user-friendly data tool for the average person in a world full of sophisticated software created for experts. Our goal is to enable contemporary knowledge teams to investigate, clarify, and work together on numbers. Spreadsheet data is made simple to understand and use by GRID, enabling your team to operate at peak efficiency and perform like the champions they are.Build stunning interactive models with your spreadsheet data, enrich your analyses with narratives, and much more. In just a few minutes, you can edit, update, and work on GRID documents with your team.  Make a new GRID document, add a spreadsheet from your computer or from a cloud drive, and then connect it. Data will be necessary for your work.

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what are advantages of using sinusoidal Voltages​

Answers

Answer:

The advantages of using a pure sine wave for your appliances and machinery are as follows: Reduces electrical noise in your machinery.

translates to no TV lines and no sound system hum.

Cooking in microwaves is quicker.

Explanation:

The smoothest signal is a sine wave, and sine waves are the basis of all functions.

Every other continuous periodic function is a basis function, which means that it can be described in terms of sines and cosines.

For instance, using the Fourier series, I can describe the fundamental Sinusoidal frequency and its multiples in terms of the triangle and square waves.

Segments ab and cd of the assembly are solid circular rods, and segment bc is a tube. If the assembly is made of 6061-t6 aluminum, determine the displacement of end d with respect to end a.

Answers

The displacement of end D with respect to end A is \(-0.488 \times 10^{-3}\;m\)

Given the following data:

Length = 435 mm to m = 0.435 meter.Modulus of elasticity = 68.9 GPa.Radius A = 20 mm to m = 0.03 meter.Inner radius BC = 30 mm to m = 0.03 meter.Outer radius BC = 40 mm to m = 0.04 meter.Force A = 10 kN.Force B = 15 kN.

To determine the displacement of end D with respect to end A:

How to calculate the displacement.

First of all, we would do a sectional cut of the circular rods at point A and then determine the sum of forces acting on it:

\(\sum F=0\\\\ 10000+N_1=0\\\\N_1 = -10000\;N\)

Mathematically, the displacement of a circular rod is given by this formula:

\(d = \frac{NL}{AE}\)

Where:

N is the normal force.L is the length.A is the area.E is the modulus of elasticity.

Substituting the given parameters into the formula, we have;

\(d_1 = \frac{-10000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_1 = \frac{-4350}{0.0003142 \times 68.9 \times 10^9}\\\\d_1 =-0.201 \times 10^{-3}\;meter\)

For section cut BC:

\(\sum F=0\\\\ 10000-20000+N_2=0\\\\N_2 = 10000\;N\)

\(radius = outer\;radius^2 - inner\;radius^2\\\\radius = 0.04^2 -0.03^2=0.0007\;m\)

\(d_2 = \frac{10000 \times 0.435}{\frac{3.142 \times 0.0007^2}{4} \times 68.9 \times 10^9} \\\\d_2 = \frac{4350}{0.00054985 \times 68.9 \times 10^9}\\\\d_2 =0.115 \times 10^{-3}\;meter\)

For section cut D:

\(\sum F=0\\\\ -20000-N_3=0\\\\N_3 =- 20000\;N\)

\(d_3 = \frac{-20000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_3 = \frac{-8700}{0.0003142 \times 68.9 \times 10^9}\\\\d_3 =-0.402 \times 10^{-3}\;meter\)

For the total displacement:

The total displacement is equal to the displacement of end D with respect to end A.

\(d_T = d_1 +d_2+d_3\\\\d_T = -0.201 \times 10^{-3} + 0.115 \times 10^{-3}-0.402 \times 10^{-3}\\\\d_T = -0.488 \times 10^{-3}\;m\)

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Segments ab and cd of the assembly are solid circular rods, and segment bc is a tube. If the assembly

a technician suspects that a power supply is faulty. how can it be checked?

Answers

To check if a power supply is faulty, a technician can use a multimeter to measure the voltage output from the power supply. If the voltage is lower than the specified output voltage, it may indicate a faulty power supply. Another way to check is by using a power supply tester, which can determine if the power supply is providing power to all the necessary components.

Use a multimeter to measure voltage output: Set the multimeter to measure DC voltage and connect the red probe to the positive terminal and the black probe to the negative terminal of the power supply. Compare the reading to the specified output voltage, which can be found on the label of the power supply or in the manual.Use a power supply tester: A power supply tester can check if the power supply is providing power to all the necessary components. It will check for proper voltage levels on the various power connectors (such as the 24-pin ATX connector) and check if there are any voltage fluctuations.

If either of these tests indicates a faulty power supply, it should be replaced. It's important to note that power supply issues can also be caused by other factors, such as a short circuit in a component or a faulty motherboard.

Therefore, it's important to conduct further troubleshooting if needed to identify the root cause of the problem.

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How much does 1 gallon of water weigh in pound given that the density of water is 1gram/ cm3

Answers

Explanation:

There are 8.35 pounds in a gallon of water. Water weighs 1 gram per cubic centimeter or 1 000 kilogram per cubic meter, i.e. density of water is equal to 1 000 kg/m³; at 25°C (77°F or 298.15K) at standard atmospheric pressure.

Compare the output of full-wave rectifier with and without filter

Answers

Answer:

Full wave rectification flips the negative half cycle of the sine wave to positive so the result is two positive half cycles.

Explanation:

hope it helps a lil

4. a. A family purchased a 3 acre piece of land in Limuru for Kshs.30,000,000.00 fifteen years ago. They planted trees at a cost of Kshs.250,000.00 per acre. Each year they have been spending on average Kshs.25,000.00 per acre per month to take care of the trees and also to secure the property. They are now considering selling it. What is the minimum amount they should accept so as not to incur a loss bearing in mind that comparable properties have been yielding a rate of 6.5% interest per annum? (8 marks)

b. “Compulsory acquisition is the power of government to acquire private rights in land for public good without the willing consent of the owner but; in exchange for compensation”. Discuss this statement with special reference to the main considerations that ought to be made in conducting a valuation for compulsory acquisition. (12 marks)

Answers

The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.

Why should they accept this amount and why?

To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.

Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.

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me that both a triaxial shear test and a direct shear test were performed on a sample of dry sand. When the triaxial test is performed, the specimen was observed to fail when the major and minor principal stresses were 100 lb/in2 and 20 lb/in2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 3000 lb/ft2

Answers

Answer:

shear strength = 2682.31 Ib/ft^2

Explanation:

major principal stress = 100 Ib / in2

minor principal stress = 20 Ib/in2

Normal stress = 3000 Ib/ft2

Determine the shear strength when direct shear test is performed

To resolve this we will apply the coulomb failure criteria relationship between major and minor principal stress a

for direct shear test

use Mohr Coulomb criteria relation between normal stress and shear stress

Shear strength when normal strength is 3000 Ib/ft  = 2682.31 Ib/ft^2

attached below is the detailed solution

me that both a triaxial shear test and a direct shear test were performed on a sample of dry sand. When

Competence refers to speakers' tacit, unconscious knowledge of grammar.
True
False

Answers

False, competence refers to speakers' tacit, unconscious knowledge of grammar.

How to determine the statement

Competence refers to speakers' underlying knowledge and ability to use a language, which includes both conscious and unconscious knowledge of grammar.

Even if the speaker is unable to explicitly state the rules, it includes their innate sense of what is or is not grammatically correct.

This ingrained understanding is frequently referred to as "linguistic competence," which is separate from "performance," which refers to the actual use of language in settings that might be influenced by things including memory impairment, speech impediments, and situational considerations.

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an amplifier with 40 db of small-signal, open-circuit voltage gain, an input resistance of 1 m, and an output resistance of 100 , drives a load of 500 . what voltage and power gains (expressed in db) would you expect with the load connected? if the amplifier has a peak output-current limitation of 20 ma, what is the rms value of the largest sine-wave input for which an undistorted output is possible? what is the corresponding output power available?

Answers

14.14 V is the RMS value of the largest sine-wave input for which an undistorted output is possible. 100 mW is the corresponding output power available.

Voltage gain with load: Using the equation

\(A_{v} = A_{voc} \times \frac{R_l}{(R_i + R_l)}\)

where

\(A_{voc}\) is the open-circuit voltage gain,

Ri is the input resistance, and

Rl is the load resistance, one may determine the voltage gain when a load of 500 ohms is connected.

The formula for calculating the maximum undistorted rms input voltage is: Calculating the highest undistorted output power is as follows:

Imax = 20 mA

        = 20 × 10⁻³ A

In this case,

\(A_{voc} = 10^{\frac{40}{20}}\)

        = 100, Ri

        = 1 M Ohm,

and Rl = 500 Ohms,

so,

\(A_{v} = 100 \times \frac{500}{(1 + 500)}\)

    = 100 × (500/1.5)

    = 33.33

The voltage gain in dB can be calculated as

20 × log(Av)

= 20 × log (33.33)

= 32.2 dB.

Ap = (33.33)² / 500

    = 11.1

The power gain in dB can be calculated as

10 × log(Ap)

= 10 × log(11.1)

= 9.54 dB.

Vmax = Imax × Ri

         = 20 × 10⁻³ × 1 × 10⁶

         = 20 V

\(V_{rms} = \frac{V_{max}}{\sqrt{2}}\)

        \(= \frac{20}{\sqrt 2}\)

        = 14.14 V

Pmax = (Vrms)² / Rl

         = (14.14)² / 500

         = 0.1 W

         = 100 mW

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An intake manifold gasket has been replaced due to a vacuum leak. Which of the following steps uses a scan tool to complete the job? O A. Torquing the manifold bolts B. Idle relearn O C. Refilling the cooling system O D. Air cleaner check​

Answers

Answer: B.Idle relearn

Explanation:

When replacing an intake manifold gasket due to a vacuum leak, using a scan tool for idle relearn is a crucial step to complete the job. The Option B.

How does a scan tool help complete the job when replacing an intake manifold gasket?

The scan tool is used to reset the idle control system and allow the engine's computer to relearn the correct idle speed and air/fuel mixture. This is important because the replacement of the intake manifold gasket can affect the engine's idle characteristics.

By using the scan tool to perform an idle relearn procedure, the engine management system can recalibrate and optimize the idle control parameters, ensuring smooth and stable idle operation. This step helps to restore the engine's performance and maintain proper combustion efficiency after the intake manifold gasket replacement.

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Find the resultant of the force system on the body OABC as shown .find the points where the resultant will cut the X and Y axis?

Answers

Explanation:

the resultant force =

\( \sqrt{} {x}^{2} + {y}^{2} \)

A resultant force is the single force and corresponding torque that are produced when adding vectors to a system of forces and torques acting on a rigid body.

What are the resultant of the force system on the body?

R = A + B. Instance 2 To create the resulting vector, two vectors facing the opposite direction are subtracted from one another. Here, the vector B is pointing in the opposite direction of the vector A, and the resulting vector is called R.

A force system is a group of forces that interact at specific locations (may also include couples). Therefore, the collection of forces shown on any free body diagram is a force system. A group of forces is simply referred to as a force system.

Therefore, When an item is under the influence of two or more forces, the combined force can be calculated by adding up the separate forces.

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Which of the following statements best describes the first priority of public works during the initial response?

Answers

The statement that best describes the first priority of public works during the initial response is: B. Provide an initial assessment of the damages to all community services

How to describe public works?

Public works are defined as a broad category of infrastructure projects, that are financed and constructed by the government, for recreational, employment, and health and safety uses in the greater community.

They include works (such as schools, highways, docks) constructed for public use or enjoyment especially when financed and owned by the government.

Looking at the given options, the one that best describes the first priority of public works is Option B

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The missing options are:

A. Review reports and other data to provide a preliminary damage assessment

B. Provide an initial assessment of the damages to all community services

C. Restore solid waste management services, repair facilities, and clear streets

D. Assist with life safety activity by providing equipment and technical expertise

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