The ratio of an objects weight on earth to its weight on the moon is 6:1 the first person to walk on the moon was neil armstrong. he weighed 165 pounds on earth. what would be the proportion of this word problem?

Answer:

The last one please.

Answer:

\(-\frac{22}{91} = x\)

Step-by-step explanation:

To solve the equation \(3x - 23 = 94x - 1\), we'll follow these steps:

Start by simplifying the equation by combining like terms. In this case, we have terms with x on both sides, as well as constants:

\(3x - 23 = 94x - 1\)

To isolate the x terms, we can subtract 3x from both sides of the equation:

\(3x - 3x - 23 = 94x - 3x - 1\)

Simplifying further, we get:

\(-23 = 91x - 1\)

Next, we want to isolate the constant term on one side of the equation. We can do this by adding 1 to both sides:

\(-23 + 1 = 91x - 1 + 1\)

Simplifying further:

\(-22 = 91x\)

Finally, we can solve for x by dividing both sides of the equation by 91:

\(-\frac{22}{91}=\frac{91x}{91}\)

Simplifying further:

\(-\frac{22}{91} = x\)

Therefore, the solution to the equation \(3x - 23 = 94x - 1\) is \(-\frac{22}{91} = x\)

Answer: the answer is b or 6.48

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Use scale factor

6/q=8/4

The maximum angle of the incline for the car to be at rest using only friction is 38.7° if, for the car on the incline, the coefficient of static friction is 0.8 and the coefficient of kinetic friction is 0.6.

If the car is at rest on the incline, the force of gravity acting on the car down the incline is balanced by the force of static friction acting up the incline. The maximum angle \($\theta$\) of the incline is the angle at which the force of static friction is at its maximum, which is given by the product of the coefficient of static friction and the normal force.

Let's assume that the mass of the car is m and the incline makes an angle of \($\theta$\) with the horizontal. Then, the force of gravity acting on the car down the incline is given by \($mg\sin(\theta)$\), where g is the acceleration due to gravity. The normal force acting on the car perpendicular to the incline is given by \($mg\cos(\theta)$\).

For the car to be at rest on the incline, the force of static friction acting up the incline must be equal in magnitude to the force of gravity down the incline. Therefore, we have:

\($$\mu_s mg\cos(\theta) = mg\sin(\theta)$$\)

here \($\mu_s$\) is the coefficient of static friction. Simplifying this equation,

we get:

\($$\tan(\theta) \leq \mu_s$$\)

Therefore, the maximum angle \($\theta$\) of the incline is:

\($$\theta \leq \tan^{-1}(\mu_s)$$\)

Substituting the value of \($\mu_s = 0.8$\), we get:

\($$\theta \leq \tan^{-1}(0.8) \approx 38.7^{\circ}$$\)

Therefore, the maximum angle of the incline for the car to be at rest using only friction is approximately 38.7°.

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An ordered pair is a solution of an equation in two variables if replacing the variables by the coordinates of the ordered pair results in a true statement.

In mathematics, an equation in two variables represents a relationship between two quantities. An ordered pair consists of two values, typically denoted as (x, y), that represent the coordinates of a point in a two-dimensional plane.

When these values are substituted into the equation, if the equation holds true, then the ordered pair is considered a solution or a solution set to the equation. This means that the relationship described by the equation is satisfied by the values of the ordered pair. In other words, the equation is true when evaluated with the values of the ordered pair.

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Answer:

Median might be the answer or maybe the height?

The rate of change of the area of the triangle is not constant and will depend on the angle between the ladder and the ground.

The area of the triangle formed by the ladder wall and ground is dependent on the angle between the ladder and the ground. The area of a triangle is equal to half the product of the length of the base and the corresponding height. Therefore, if the angle between the ladder and the ground changes, the corresponding height of the triangle will also change, resulting in a change of the area of the triangle. As the angle between the ladder and the ground changes, the rate of change of the area of the triangle will also change.

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Answer:

1/8^2, 1/2^4 and 1/3^5

Step-by-step explanation:

Answer:

∠5 = 70°

∠8 = 130°

Step-by-step explanation:

Since ∠5 and ∠1 are equal they will both equal 70°

Since ∠6 and ∠8 are also equal they will both equal 130°

Hope this helps

Plz mark brainliest

The answer is in the image. If you convert them to improper fractions, the division is easier. Like 2/3 + 1 = 5/3

Step-by-step explanation:

Simply graph the two equations....the intersection of the two graphs is the solution

Over the weekend she walked a total distance of (4 + 5/8) miles

We know that on Saturday she walked a total of (3 + 7/10) miles (so we need to work with mixed numbers), and on Sunday she walked 0.25 of that distance.

Then the  distance that she walked on Sunday is:

D = 0.25*(3 + 7/10) miles

We can rewrite: 0.25 = 1/4

replacing that:

D = (1/4)*(3 + 7/10) mi = (3/4 + 7/40) mi

   = (30/40 + 7/40)mi = (37/40)mi

Then the total distance that she walked over the weekend is:

d = (3 + 7/10) mi +  (37/40)mi

  = (120/40 + 28/40) mi + (37/40) mi

  = (185/40)mi = (160/40 + 25/40) mi = (4  + 5/8) mi

Over the weekend she walked a total distance of (4 + 5/8) miles

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Step-by-step explanation:

\( {17}^{2} = {8}^{2} + {b}^{2} \\ {b}^{2} = {17}^{2} - {8}^{2} \\ {b }^{2} = 225 \\ b = \sqrt{225} = 15\)

Use Pythagorean theorem

\(\\ \sf\longmapsto b^2=h^2-p^2\)

\(\\ \sf\longmapsto b^2=17^2-8^2\)

\(\\ \sf\longmapsto b^2=289-64\)

\(\\ \sf\longmapsto b^2=225\)

\(\\ \sf\longmapsto b=15ft\)

Answer:

Step-by-step explanation:

Note that the absolute value of the difference in the two estimates of Q with an uncertainty range at a 95% confidence interval is 1.052.

To find the average value of Q, we simply add up all the values and divide by the number of trials:

Average value of Q = (41.314 + 40.087 + 41.248 + 40.196 + 40.284 + 41.152 + 38.852 + 36.401 + 37.941 + 39.221 + 39.035 + 38.404 + 40.683 + 41.568 + 42.175 + 42.319)/16

= 39.976

Next, to find the uncertainty range where we can be 95% sure that the true value of Q lies within, we need to find the standard error of the mean. The formula gives this:

Standard error of the mean = standard deviation / √(n)

where n is the number of trials. We can find the standard deviation using the formula:

Standard deviation = √(Σ(Qi - Q_avg)² / (n-1))

where Qi is the value of Q for the ith trial.

Using these formulas, we find:

Standard deviation = 1.549

Standard error of the mean = 0.387

To find the uncertainty range, we say:

Uncertainty range = t-value * standard error of the mean

= 2.131 * 0.387

= 0.826

Therefore, we can be 95% sure that the true value of Q lies within the range:

39.976 ± 0.826

Now, to calculate the absolute value of the difference in the two estimates of Q with an uncertainty range at a 95% confidence interval, we can simply add the uncertainty ranges of the two estimates and take the absolute value of the difference:

|Q1 - Q2| = |39.976 ± 0.826 - 40| + |39.976 ± 0.826 - 39.8|

= 0.826 + 0.226

= 1.052

Therefore, the absolute value of the difference in the two estimates of Q with an uncertainty range at a 95% confidence interval is 1.052.

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Rose curve equations have two forms: r = a cos(nθ) and r = a sin(nθ) where a ≠ 0 and n is a positive integer. Petals have length determined by a. If n is odd, the number of petals is n. However, if n is even, the number of petals is 2n.

hope it helps aaa ^^'

Answer:

Step-by-step explanation:

Given

As per segment addition postulate

Substituting values

Answer: x = -7

Step-by-step explanation:

7 (x + 4) = -21

7x + 28 = -21

Subtract 28 from both sides

7x = -49

Divide both sides by 7

x = -7

Answer:

x = -7

Step-by-step explanation:

first distribute he 7 to get 7x + 28 = -21

then subtract 28 from both sides to get 7x = -49

lastly divide 7 from both sides to get x = -7

Answer:

Well, 6.94 - 4.99 = 1.95 also that divided by 0.65 = 3 So it is 3  pounds of bananas

Step-by-step explanation:

P.S can I have brainliest?

Answer:

y=1/5x+5

Step-by-step explanation:

Slope-intercept form is written y=mx+b.

y- needs to be by itself in this form.

m- the slope.

x- always to the right side of the slope, or m.

b- y-intercept.

Now that we know this, all we have to do is plug in the numbers we have. So when we plug this in, the equation looks like this:

y=1/5x+5

Hope this helps you and have a great day :3

Answer:

The answer is below

Step-by-step explanation:

Trigonometric ratios shows the relationship between the sides of a right angled triangle and its angles. Some trigonometric ratios are:

sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse; tanθ = opposite / adjacent.

In triangle PQR:

tanθ = QR / PQ

substituting gives:

3/4 = 9 / PQ

PQ = 9 * 4 / 3 = 12 cm

Applying Pythagoras in triangle PQR gives:

PR² = PQ² + QR²

PR² = 12² + 9²

PR² = 144 + 81 = 225

PR = 15 cm

Also in triangle PRS:

PS = (5/3)PR = (5/3)*15 = 25 cm

PS² = PR² + RS²

25² = 15² + RS²

625 = 225 + RS²

RS² = 400

RS = 20 cm

Answer:

midpoint of chord ab is (-2, 12) slope of chord ab is 1/2

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

the greatest common factor of 16 and 48 is 16

Factors for 16: 1, 2, 4, 8, and 16.

Factors for 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

The solution to the differential equation is: r(t) = ⟨1/100 e10t - t2 + 119/10 t + 49/100, 1/12 t4 - 1/2 t2 - 13/3 t - 1/3, 1/2 t2 - 12 t + 26/5 ⟩, for t ≥ 0.

The differential equation for r′′(t) = ⟨e10t − 10, t2 − 1, 1⟩ with the initial conditions r(1) = ⟨0, 0, 5⟩, r′(1) = ⟨12, 0, 0⟩ can be solved using the following method:

Solve for the position vector r(t) using the acceleration vector a(t).

Then solve for the velocity vector r′(t) using the initial velocity. Finally, solve for r(t) using the initial position vector.1.

Solve for r(t) using a(t)

Integrate a(t) with respect to t two times to get r(t):a(t) = ⟨e10t − 10, t2 − 1, 1⟩

Integrating once will give the velocity: v(t) = ∫a(t) dt = ⟨ 1/10 e10t - 10t + C1 , 1/3 t3 - t + C2, t + C3 ⟩

Integrating again will give the position: r(t) = ∫v(t) dt = ⟨ 1/100 e10t - t2 + C1t + C4 , 1/12 t4 - 1/2 t2 + C2t + C5, 1/2 t2 + C3t + C6 ⟩2.

Solve for C1, C2, and C3 using initial velocity r′(1) = ⟨12, 0, 0⟩ = v(1)C1 = 119/10, C2 = -13/3, C3 = -12.3.

Solve for C4, C5, and C6 using initial position r(1) = ⟨0, 0, 5⟩ = r(1)C4 = 49/100, C5 = -1/3, C6 = 26/5

Therefore, the solution to the differential equation is: r(t) = ⟨1/100 e10t - t2 + 119/10 t + 49/100, 1/12 t4 - 1/2 t2 - 13/3 t - 1/3, 1/2 t2 - 12 t + 26/5 ⟩, for t ≥ 0.

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Answer:

8

Step-by-step explanation:

Replace the variables with numbers.

1+7=8

Answer:

8

Step-by-step explanation:

Since z equals 1 and k equals 7, we do 1 + 7 which is equal to 8. Therefore, the answer would be 8.

Answer:

1. 61

2. -8

3. 731

4. -16

5. -5

Step-by-step explanation: