Answer:
Explanation:
From the case of well-stirred oil bath:
\(51=l+50m+n(50^{2})\rightarrow 51=l+50m+2500n\)
At the ice point, both of the thermometers show the same scale:
\(0 = l + m(0) + n(0^{2}) \rightarrow l = 0\)
At the steam point, again, both of the thermometers show the same scale:
\(100 = 0 + m(100)+n(100^{2}) \rightarrow 100 = 100m + 10000n \rightarrow 1 = m + 100n\)
By eliminating those equations, we find:
\(51=50(1-100n)+2500n \rightarrow 51=50-500n+2500n \rightarrow 1 = 2000n\)
so we can obtain that: \(n=\frac{1}{2000}=0.0005\) and \(m=1-100(0.0005)=1-0.05=0.95\)
Now, we have the complete description of the relation between A and B scale as: \(t_{A}=0.95t_{B}+0.0005t_{B}^{2}\)
So, for \(t_{A}=25^{0}C\):
\(25 = 0.95t_{B}+0.0005t_{B}^{2} \rightarrow 0.0005t_{B}^{2}+0.95t_{B}-25=0\)
\(t_{B}_{1,2}=\frac{-0.95\pm\sqrt{0.95^{2}-4(0.0005)(-25)}}{2(0.0005)}\approx-950\pm975\)
\(t_{B}_{1}=25^{0}C \vee t_{B}_{2}=-1925^{0}C\)
Your sprayer has a 60-foot wide boom with 36 nozzles along this 60-foot length. Your spray speed is 4.5 miles per hour and you want 25 GPA. How much should you catch per nozzle in 15 seconds to be properly calibrated?
Answer:
358.52 m/s
Explanation:
From the information given:
The required amount you should catch per nozzle in 15 secs. can be determined by using the formula:
\(Gallons/Min = \dfrac{(Gallons/Acre \times Miles/Hour \times nozzle \ spacing )}{5940}\)
where;
Gallons/Acre = 25 GPA
\(= \dfrac{(25 \times 4.5 \times 60 \times \dfrac{12}{ 36})}{5940} \times \dfrac{15}{60}\)
\(= \dfrac{(25 \times 4.5 \times 60 \times0.333)}{5940} \times 0.25\)
\(= \dfrac{(2247.75)}{5940} \times 0.25\)
= 0.0946 gps
= 358.52 m/s
Why does the ceramic made from Thorium and Oxygen have the chemical ratio of 2 oxygen atoms to every thorium atom (ThO2)
Which of the following best describes the form in which chemical energy exists?
a.) The heat that is generated when friction occurs
b.) The chemical composition of a substance
c.) The chemical bonds that hold atoms together in chemicals
d.) The random movement of particles in a system
c.) The chemical bonds that hold atoms together in chemicals. Chemical energy is stored in the chemical bonds between atoms in a molecule.
Define the term Chemical Bond?
Chemical bonds between atoms in a molecule store chemical energy. When these bonds are broken, energy is released, and this energy can take many forms, such as heat, light, or movement.
For example, when gasoline is burned in a car engine, the energy stored in the chemical bonds between the atoms in the gasoline molecules is released, producing heat and powering the engine.
Chemical bonds between atoms in a molecule store chemical energy. It is the energy that holds the atoms together and is released when the bonds are broken. This energy can be transformed into other forms of energy, such as heat, light, or motion, and is an important source of energy for many biological and industrial processes.
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A food warmer made of thermo-plastic material is at 40°C and the surrounding environment is at 20°C. Calculate the rate of heat transfer per unit area of the surface,provided the surface is 20mm thick and the thermal conductivity of the material is 29W/m
Answer: 870 W/m²
Explanation:
Using Fourier's Law of Heat Conduction, the rate of heat transfer per unit area (q) can be calculated as:
q = k × (T1 - T2) / L
where k is the thermal conductivity of the material, T1 is the temperature of the warmer, T2 is the temperature of the surrounding environment, and L is the thickness of the material.
Plugging in the given values, we get:
q = 29 W/m·K × (40°C - 20°C) / (20 mm / 1000)
q = 870 W/m²
Therefore, the rate of heat transfer per unit area of the surface is 870 W/m².
what type of heating system uses a boiler to produce steam, which is transferred to rooms through a pipe?
A steam heating system is a type of heating system that uses a boiler to produce steam, which is then distributed through a network of pipes to various rooms in a building. The steam is typically generated by heating water to its boiling point, and the resulting steam is used to transfer heat to the rooms through the pipes. The steam can be used to heat the air in the rooms directly, or it can be used to heat water or other fluids in a radiator or other heat exchanger, which can then be used to transfer heat to the air in the room.
IF YOUR DRIVING PRIVILEGE HAS BEEN REVOKED, YOU MAY:
A. Drive only in an emergency
B. Still drive to and from work or school
C. Not drive in this state with any license or permit
D. Drive only in the presence of a licensed parent or guardian
HELP ME !!
Answer:
correct me if im wrong but A. drive only in an emergency
If your driving privilege has been revoked, you may not drive in this state with any license or permit. Thus, the correct option is C.
What is Driving privilege?The Driving privilege may be characterized as the bounty of authority by a jurisdiction to a person that permits a specific person is able to drive a vehicle on highways within that jurisdiction. It is offered to the individual who wants to drive the vehicle, but not the vehicle.
Once the driving privilege of any individual has been revoked, he/she now does not have the authority or jurisdiction to drive any form of vehicle officially in any terms or circumstances. This represents your sincerity and activeness in front of others.
Therefore, if your driving privilege has been revoked, you may not drive in this state with any license or permit. Thus, the correct option is C.
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I need help with this ASAP please. This is basic carpentry, I just missed the first half of the year so I am a little behind. Can somebody answer the two questions?
Answer:
the half answer is pretty easy just look at it really really good hope this helps..
Explanation:
A site is underlain by a 10 meter layer of saturated gravel with unit weight = 20 kN/m3. Point A is located 5 meters below the ground surface. The horizontal effective stress at point A is 30 kPa. Determine the lateral stress ratio of the soil at point A.
Answer:
The lateral stress ratio of the soil at point A is 0.3
Explanation:
given that; Unit weight = 20 kNm⁻³ at point A 5m below the ground surface,
vertical stress (\(V_{stress}\)) = 20 kNm⁻³ × 5m ⇒ 100 kNm⁻²
vertical stress (\(V_{stress}\)) = 100kPa
note that; Horizontal Stress (\(H_{stress}\)) is given by k(\(V_{stress}\))
where "k" is the lateral stress ratio
\(H_{stress}\) = k(\(V_{stress}\))
k = \(H_{stress}\) ÷ \(V_{stress}\)
k = 30 kPa ÷ 100 kPa
k = 0.3
Which of these adhesives will glue mdf to acrylic?
Bondtite Wood Adhesives is the best glue for pasting Acrylic Sheet to any wooden surface like Plywood , MDF, or WPC.
1. Make sure both surfaces are clear of dirt and other impurities (Oil, grease, dust, etc.).
2. Using a spreader, evenly apply Bondtite Acrylicfix on the plywood (base surface). Let the surface 8 to 10 minutes to dry.
3. Use a wet cloth to rub the acrylic sheet's backside on the second surface. Make sure there are no water droplets on the area that the adhesive will be sticking to. Avoid rubbing with wet towel during the rainy season.
4. To ensure a strong binding, bring the two surfaces together and apply uniform pressure using a roller, press machine, or dry cloth.
5. Use clamps, nails, tape, etc. to firmly hold the bonded surface together. Handling Strength can be attained in two to four hours.
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9. what is the cause of thrashing? how does the system detect thrashing? once it detects thrashing, what can the system do to eliminate this problem?
Thrashing occurs when a computer system spends excessive time and resources on paging due to a high demand for virtual memory.
It leads to frequent page faults and a decline in system performance. The system detects thrashing by monitoring the page fault rate and resource utilization. Once thrashing is detected, the system can take actions such as increasing available memory, adjusting process scheduling, or optimizing the page replacement strategy to resolve the issue.
Thrashing is primarily caused by a shortage of physical memory relative to the demand for virtual memory. When the working set of active pages required by running processes exceeds the available physical memory, the system starts swapping pages between RAM and the disk excessively. This leads to a high page fault rate and an increase in disk I/O, resulting in a significant degradation of system performance.
To detect thrashing, the system continuously monitors the page fault rate and resource utilization. A high page fault rate, indicating frequent page swaps, combined with low CPU and disk utilization may indicate thrashing. The system may also analyze patterns of page faults and examine the working set sizes of processes to identify thrashing conditions accurately.
Once thrashing is detected, the system can employ several strategies to mitigate the problem. Increasing the available physical memory, either by adding more RAM or implementing memory management techniques like virtual memory expansion, can provide more space for active pages, reducing the need for excessive swapping.
The system can also adjust its process scheduling algorithm to prioritize processes causing thrashing. For instance, it may employ priority-based algorithms or aging techniques to allocate more resources to processes with high page fault rates, allowing them to complete their work more efficiently.
Furthermore, optimizing the page replacement strategy can help alleviate thrashing. By using efficient algorithms like the Least Recently Used (LRU) or Not Recently Used (NRU), the system can ensure that the most relevant and frequently accessed pages remain in the physical memory, reducing the number of page faults and the likelihood of thrashing.
By employing these measures, the system can effectively eliminate or minimize thrashing, improving overall system performance and resource utilization.
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LOLOLOLOKOLLOLLOLOLOO STRIKER KID THINKS HES SO GOOD LLOLOLOLOLOLOLOLOLOLOOLOLOLOLOLOLOL
Answer:
UUUUUUMMMM do you mean in soccer ????????????????
Explanation:
Which of the following is NOT a line used on blueprints?
Answer: Photo lines
Explanation: made more sense
An article gave a scatter plot along with the least squares line of x = rainfall volume (m3) and y = runoff volume (m3) for a particular location. The accompanying values were read from the plot.
c) Calculate a point estimate of the true average runoff volume when rainfall volume is 51. (Round your answer to four decimal places.)
(d) Calculate a point estimate of the standard deviation . (Round your answer to two decimal places.)
(e) What proportion of the observed variation in runoff volume can be attributed to the simple linear regression relationship between runoff and rainfall? (Round your answer to four decimal places.)
x 6 12 14 16 23 30 40 52 55 67 72 81 96 112 127
y 4 10 13 14 15 25 27 48 38 46 53 72 82 99 100
Answer:
y = 0.834X - 1.58015
Slope = 0.8340 ; Intercept = - 1.5802
y = 40.9539
19.93
0.9765
Explanation:
X: Rainfall volume
6
12
14
16
23
30
40
52
55
67
72
81
96
112
127
Y : Runoff
4
10
13
14
15
25
27
48
38
46
53
72
82
99
100
The scatterplot shows a reasonable linear trend between the Rainfall volume and run off.
The estimated regression equation obtained using a linear regression calculator is :
y = 0.834X - 1.58015
y = Runoff ; x = Rainfall volume
Slope = 0.8340 ; Intercept = - 1.5802
Point estimate for Runoff, when, x = 51
y = 0.834X - 1.58015
y = 0.834(51) - 1.58015
y = 40.95385
y = 40.9539
d.)
Point estimate for standard deviation :
s = 5.145
σ = s * √n
σ = √15 * 5.145
= 19.93
e.)
r² = Coefficient of determination gives the proportion of explained variance in Runoff due to the regression line. From the model output, the r² value = 0.9765. Which means That about 97.65% Runoff is due to Rainfall volume.
The * key is used for ____.
All of the questions in this problem are based on the circuit below. R=10Ω,L=5mH,C=500μF. The source voltage is 10cos(200t+45LaTeX: ^{^\circ}∘). Round all of your answers to two decimal places if necessary. Omit the units. What is the inductor impedance value in ohms? First, what is the REAL part.
Answer:
1) The real part of the inductor impedance is 0 Ω and
2) the imaginary part of the inductor impedance 1 Ω
3) The real part of the impedance of the capacitor is 0 Ω and
4) the imaginary part of impedance of the capacitor is -10 Ω
5) The real part of total impedance is 10Ω
6) The Imaginary part of total impedance is -9j Ω
Explanation:
Given that R=10Ω,L=5mH,C=500μF and The source voltage is 10cos(200t+45°)
The voltage in an AC circuit is given by:
\(V=V_mcos(wt+\theta)\)
Comparing \(V=V_mcos(wt+\theta)\) with 10cos(200t+45°), we get that the angular frequency w = 200 rad/s
A complex number given by x + jy has a real part of x and an imaginary part of y
The inductor impedance (Z) is given by: \(Z_L=jwl = j*200*5*10^{-3}=j = 0 \ \Omega \ + \ j\ \Omega\)
1) The real part of the inductor impedance is 0 Ω and
2) the imaginary part of the inductor impedance 1 Ω
The impedance of the capacitor is given by:
\(Z_c=\frac{1}{jwC} =-j*\frac{1}{wC}=-j*\frac{1}{200*500*10^{-6}} =0\ \Omega \ - j10 \ \Omega\)
3) The real part of the impedance of the capacitor is 0 Ω and
4) the imaginary part of impedance of the capacitor is -10 Ω
The total impedance of the circuit is the sum of the resistance, capacitive impedance and inductive impedance. It is given by:
\(Z=R+Z_L+Z_C=10+(0+j)+(0-j10)=10+j-j10=10\ \Omega - \ j9\ \Omega\)
5) The real part of total impedance is 10Ω
6) The Imaginary part of total impedance is -9j Ω
Generators must be oversized when supplying ________ loads to reduce heating and voltage waveform distortion
Generators must be oversized when supplying non-linear loads to reduce heating and voltage waveform distortion.An oversized generator is an electrical generator that is larger than the anticipated electrical load.
The need for an oversized generator may arise if the original electrical load changes, if the system's future expansion is expected, or if the generator must run at low loads.Overloading a generator can result in system overloads, poor power quality, and device failures.
When a generator is oversized, its electrical power output capability is greater than the load that it will supply, and it will not be loaded to its full potential.
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Student A says that wires on a screw-type terminal connection should be installed as shown in Figure A - 5 . Student 8 says that wire nut connections are a type of soldere connection. Which of the following statements is correct?
Answer:
Student A
Explanation:
There is no reason to solder a wire nut connection because the nut already makes a mechanical connection.
Oil refineries separate crude oil into fractions by boiling point in a distillation tower. Rank these crude oil fractions in order from lowest to highest boiling point.Refinery Gases Gasoline Diesel Lubricating Oils AsphaltLower boiling point < ___ < ___ < ____< ____ < Highest boiling point
Rank these crude oil fractions in order from lowest to highest boiling point are: Refinery Gases < Gasoline < Diesel < Lubricating Oils < Asphalt.
What is crude oil?Crude oil is a naturally occurring, unrefined petroleum product composed of hydrocarbon deposits and other organic materials. It is a non-renewable energy source, and is usually black or dark brown in color. Crude oil is highly flammable, and is composed of a complex mixture of hydrocarbons of various molecular weights, plus other organic compounds. It is used to produce a variety of petroleum products, including gasoline, diesel fuel, heating oil, jet fuel, and many types of petrochemicals. Crude oil is also used as a feedstock for the petrochemical industry, which uses it to produce a variety of products, including plastics, synthetic fabrics, paints, fertilizers, and detergents. Crude oil is a major source of energy, and its production and consumption have a significant environmental impact due to its high levels of air pollutants.
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Rank these crude oil fractions in order from lowest to highest boiling point are: Refinery Gases < Gasoline < Diesel < Lubricating Oils < Asphalt.
What is crude oil?Crude oil is an organic substance made up of hydrocarbon deposits and other organic elements that is a naturally occurring, unrefined petroleum product. Its typical colour is black or dark brown, and it is a non-renewable energy source. Crude oil contains a complex mixture of hydrocarbons with different molecular weights as well as other organic compounds, making it extremely flammable. Numerous petroleum products, including aviation fuel, heating oil, diesel, gasoline, and numerous varieties of petrochemicals, are produced using it.
The petrochemical industry, which uses crude oil as a feedstock to make a variety of goods like polymers, synthetic textiles, paints, fertilizers, and detergents, also uses it to make crude oil. Due to its high levels of air pollutants, crude oil is a significant source of energy and its production and consumption have a significant negative effect on the environment.
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Should you prefer rooftop solar panels?
The rooftop solar is a form of solar energy that can be installed on the roof of a home or business. It is cost-effective, environmentally friendly, and provides many benefits to homeowners and businesses.
The rooftop solar has many advantages over other forms of solar energy. One of the main advantages is that it provides 100% clean electricity from renewable sources. In addition, it can be combined with other sources such as wind power and geothermal power for even more benefits.
There are also many uses for rooftop solar panels in homes and businesses. One example is using it to heat water for hot water systems or heating swimming pools.
For me Bluebird Solar Private Limited is the best website in India for rooftop solar panels in India.
A receiver has a dynamic range of 65 dB. It has a sensitivity of 0.88 nW. The maximum allowable input signal is approximately:
Answer:
2.783 * 10^-3 watts
Explanation:
calculate the maximum allowable input signal
= Dynamic range * sensitivity
Dynamic range is in decibels hence we have to take log
∴ 65 db. = \(10log_{10} (DR)\)
= \(10 \frac{65}{10}\) = \(10^{6.5}\)\(10^{6.5}\)
therefore DR ( dynamic range ) = 31.6223 * 10^5
sensitivity = 0.88 nW = 0.88 * 10 ^-9 watts
therefore the maximum allowable input signal = ( 0.88 * 10^-9 ) * ( 31.6223 * 10^5 ) = 2.783 * 10^-3 watts
Un material determinado tiene un espesor de 30 cm y una conductividad térmica (K) de 0,04 w/m°C. En un instante dado la distribución de temperatura en función de "x" el cual es la distancia desde la cara izquierda de una pared, está dado por la siguiente función: T(x) = 150x2 -30x, donde x está en metros. Calcúlese el flujo de calor por unidad de área cuando x=0 y x=30, para cada caso menciones si se está enfriando o calentando el sólido.
Answer:
Para x=0:
\(\phi=1.2 W/m^{2}\)
Para x=30 cm:
\(\phi=-2.4 W/m^{2}\)
Explanation
Podemos utilizar la ley de Fourier par determinar el flujo de calor:
\(\phi=-k\frac{dT}{dx}\)(1)
Por lo tanto debemos encontrar la derivada de T(x) con respecto a x primero.
Usando la ley de potencia para la derivda, tenemos:
\(\frac{dT(x)}{dx}=300x-30\)
Remplezando esta derivada en (1):
\(\phi=-0.04(300x-30)\)
Para x=0:
\(\phi=0.04(30)\)
\(\phi=1.2 W/m^{2}\)
Para x=30 cm:
\(\phi=-0.04(300*0.3-30)\)
\(\phi=-2.4 W/m^{2}\)
Espero que te haya ayudado!
In a vehicle with front disc brakes, the vehicle pulls to the left when braking. What causes this?
A. Seized left brake caliper piston
B. Collapsed left brake line hose
Define the limitations in the operation conditions of a P-N junction
Answer:
1. Maximum forward current
2. Peak inverse voltage
3. Maximum power rating
Explanation:
The limitations in the operations of a P-N junction are as stated below.
Every P-N junction has limiting values and will give better performance if operated within this values, and if this values are exceeded the P-N junction may be destroyed
1. Maximum forward current: the highest instantaneous current the P-N junction can conduct without being destroyed
2. Peak inverse voltage: the maximum reserve voltage that can be applied without destroying the P-N junction
3. Maximum power rating: the maximum power that can be dissipated at the junction without damaging it
When the process is in control but does not meet specification which type of error is it?
When the process is in control but does not meet specification, it is referred to as a special cause error.
What is the term for a process in control but not meeting specification?In statistical process control, a process is considered to be in control when it operates within the defined limits and shows only random variations. However, when a process is in control but does not meet the desired specifications, it indicates the presence of a special cause error.
Special cause errors are attributed to specific factors or events that cause the process to deviate from the expected outcome. These errors are typically unpredictable and require investigation and corrective action to bring the process back within the desired specifications.
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superposition theorem
Answer:
mark me brainliest
Explanation:
Superposition theorem is one of those strokes of genius that takes a complex subject and simplifies it in a way that makes perfect sense. A theorem like Millman’s certainly works well, but it is not quite obvious why it works so well. Superposition, on the other hand, is obvious.
gasoline volatility is being discussed. technician a says gasoline blended for summer use is more volatile than winter gasoline. technician b says in high altitude areas, fuels must be blended to have higher volatility.
Both technician a and technician b are correct that gasoline volatility is being discussed and it have higher volatility.
This is because in the summer, gasoline must be able to evaporate quickly in order to create the proper air/fuel mixture for combustion. In contrast, winter gasoline is blended to be less volatile to prevent vapor lock, which occurs when gasoline vaporizes too quickly and creates air pockets in the fuel line. The lower air pressure at high altitudes can cause gasoline to vaporize more slowly, which can result in poor engine performance. By blending fuels with a higher volatility, gasoline is able to vaporize more quickly, ensuring proper combustion in high altitude environments.
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What can be used as a tracing powder when checking for small oil leaks
Answer:
Talcum powder!
Explanation:
How to find the source of an oil leak:
This method simply involves using Talcum Powder as a visual aid to help pinpoint the location of an oil leak,
so you use Talcum powder for small oil leak :]
Have a wonderful day!
Select the best alternative about the red-light shift ____
a. Red light shift bring lights from the infrared to the visible spectrum due to the doppler effect. b. It is used to observe the expandable universe and one expression of the doppler effect. c. The doppler effect induces the red light shift observed in sound waves. d. Objects approaching the observer close to the light speed are subject to the red light shift.
The best alternative about the red-light shift is It is used to observe the expandable universe and one expression of the Doppler effect.
The red-light shift refers to a phenomenon observed in light waves where the wavelength of the light is stretched, causing a shift towards the red end of the spectrum. Option B correctly states that the red-light shift is used to observe the expanding universe and is an expression of the Doppler effect.
When light waves from distant galaxies or celestial objects travel through space, the expansion of the universe causes the wavelength of the light to stretch. This stretching leads to a shift towards longer wavelengths, which appear as a red shift when observed from Earth. This phenomenon is an essential tool in studying the expansion and evolution of the universe.
The Doppler effect is the change in frequency or wavelength of a wave as perceived by an observer when there is relative motion between the source of the wave and the observer. In the context of the red-light shift, the motion of distant galaxies away from us causes the observed wavelength of their light to increase, resulting in a red shift.
By observing the red-light shift, scientists can gather valuable information about the distance, speed, and behavior of celestial objects. It provides evidence for the expansion of the universe and helps in understanding its dynamics and history.
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Show that these statements about the real number x are equivalent: (i) x is rational, (i) x/2 is rational, (iii) 3x - 1 is rational
The only case in which 3x+1 is rational is when x is reasonable. Rational numbers can be stated as fractions with integral numerator and denominator, according to the definition of a rational number.
As an integer, as p and q are also integers. For this reason, 3x+1 is rational if x is reasonable.
For p and q to be integers, let x be pqL
3x=3pq
3x+1=3p+qq
Three times p plus q is an integer since p and q are also integers. For this reason, 3x+1 is rational if x is reasonable.
To demonstrate why 3x+1 is irrational when x is irrational, simply subscript x = pi.
Finite numbers cannot adequately represent 3pi, and adding one does not make the problem any better. 3pi+1 is therefore illogical.
Applying the two ideas mentioned above, I draw a conclusion.
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Wind blows on the side of a fully enclosed hospital located on open flat terrain where V= 120 mi/h. Determine the external pressure acting on the leeward wall, if the length and width of the building are 200 ft and the height is 30 ft. Take Ke 1.0.
Answer:
The external pressure is p = -21.9 psf or p = -8.85 psf
Explanation:
Given :
Velocity of wind, v = 120 mi / hr
\($k_d = k_c =1 $\) (wind direction factor)
\($k _{zt} = 1 $\) = topographical factor (for flat terrain)
\($ q_n$\) = velocity pressure at height h
\($ \therefore q_n = 0.00256 k_z k_{zt} k_d v^2 $\)
\($ q_n = 0.00256 \times k_z (1)(1)(120)^2 $\)
\($ = 36.86 k_z$\)
But for height h = 30 ft, \($ k_z$\) = 0.98 (from table)
\($ \therefore q_n = 36.86 \times 0.98 $\)
= 36.16
Now, \($ \frac{L}{B}= \frac{200}{200} =1$\) , so \($C_p=-0.5 $\) (from table)
\($p = q(G)(C_p)-q_n(GC_{pi})$\)
where, p = external pressure
G = 0.85 = gust factor (for typical rigid building)
\($GC_{pi} = \pm 0.18 $\) (internal pressure co efficient)
Therefore putting the values,
\($p = (36.13)(0.85)(-0.5)-(36.13)(\pm 0.18)$\)
p = -21.9 psf or p = -8.85 psf