The recommended welding lens shade number for use in each of the following or cutting processes

Tillage can result in the degradation of soil, water, and air quality. Of all farm management practices, tillage may have the greatest impact on the environment. A wide variety of tillage equipment, practices and systems are available to farmers, providing opportunities to enhance environmental performance.

Answer:

Wmax =  750 kw  < power developed ( 1000kw ) for a reversible    the cycle is Impossible

Explanation:

Hot reservoir Temperature = 1000 K

Cold reservoir Temperature = 500 K

Heat transfer ( energy received by Hot reservoir ) ( Q ) = 1500 kW

Heat transfer ( energy received by Cold reservoir via Hot reservoir ) = 1000 Kw

Calculate the rate of entropy production

The higher the entropy production the less efficient the system

Δs = Cp In ( T2 / T1 )

power developed = 1000 kW

considering that the cycle is reversible and the constant volume or constant pressure of the substance in the thermodynamic cycle is not given we will use the efficiency to determine if the cycle is possible or not

Л = efficiency

∴Л = 1 - T2 / T1 = 1 - ( 500 / 1000 ) = 0.5

note as well that;  Л = work output / work input = Wmax / Q

                                  = 0.5 = Wmax / Q

∴ rate of entropy production = Q ( 0.5 ) = 1500 * 0.5 = 750 kw

Given that Wmax =  750 kw  < power developed ( 1000kw ) for a reversible    the cycle is Impossible

Answer:

both

Explanation:

Tech A says that most electric fuel pumps are now mounted inside of the fuel tank. Tech B says that fuel flows through the center of the electric pump and is used to cool the pump. Who is correct? quizlet said so  

In this case, both Technicians are right.

In conclusion, both Technicians are right.

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Cold Reading is the name of the technique, commonly used by stage performers, that involves using visible information about a person to make high-probability guesses about them.

What is high-probability?

High-probability is the likelihood that something will occur or that a certain outcome will be achieved. It is usually expressed as a percentage or a probability range. For example, if a coin is flipped, there is a 50% chance of heads and a 50% chance of tails, meaning that the probability of either outcome is high. High-probability can be used to describe events, predictions, and decisions that are more likely to happen or be correct than other possibilities. High-probability can also be used to describe investments that have a higher likelihood of producing positive returns.

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A system is a linear system if all equations inside the system can be simplified into the form,

\(y=mx+n\)

aka linear form of a linear equation.

So to sum up, a system is linear if all equations are linear equations.

Hope this helps :)

Both Technician A and Technician B are correct. An analog oscilloscope can store the waveform for viewing later, and the trigger level must be set on most scopes to be able to view a changing waveform.

An oscilloscope is a device used to measure and analyze electrical signals in oscillatory form. It consists of a display, vertical and horizontal amplifiers, and a trigger. The trigger is used to capture a specific point of the waveform and synchronize it with the display. It is important to set the trigger level correctly in order to get an accurate reading of the waveform.

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Answer:

  0.42 kg

Explanation:

Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.

  \(\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}\)

The mass of the liquid is about 0.42 kg.

Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

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Answer:

“Patience is bitter, but its fruit is sweet. With patience you can bear up under any adversity and survive any defeat. With patience you can control your destiny and have what you will. Patience is the key to contentment, for you and for those who must live with you. To be brave without patience can kill you.

Explanation:

Aristotle’s Ethical Doctrine of the Mean. According to Aristotle’s ethical rule about the Golden Mean, to use a thing with virtue is a kind of moderation, as it leads the particular thing being in a good condition, and allows for its functions to be performed in a proper manner.

When resistors are put in parallel with apiece other, their overall opposition is larger than the resistance of any individual resistor.

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The following is an asynchronously resettable D latch using logic gates:  1. Create an AND gate with one input connected to the D latch, and the other connected to a NOT gate which is fed a reset signal.

2. Create an OR gate with one input connected to the AND gate, and the other connected to the D latch.

3. Create a NOT gate, with the output connected to one of the AND gate inputs and the input connected to the OR gate output.

4. Finally, the output of the OR gate is connected to the input of the D latch.

This configuration allows for the D latch to be reset by the reset signal asynchronously.

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Answer:

Explanation:

To find the discharge carried by the river, we need to use the cross-sectional area of the river and the velocity of the water. The cross-sectional area can be found by integrating the width of the river across the depth.If the side slope of the river is 1:1, that means that for every 1 meter of horizontal distance from the centerline, the depth of the water decreases by 1 meter. Using this information, we can set up the following integral to find the cross-sectional area:A = ∫[0,b] (b - x) dxWhere b is the width of the river at the base, and x is the distance from the centerline.Solving this integral, we find that the cross-sectional area is:A = (b^2)/2Now that we have the cross-sectional area, we can use the equation for discharge:Q = VAWhere Q is the discharge, V is the velocity of the water, and A is the cross-sectional area. If S is equal to 210^-4 for all sections, that means that the slope of the river is 210^-4. The velocity of the water can be found using the equation:V = √(SgD)Where S is the slope of the river, g is the acceleration due to gravity (9.81 m/s^2), and D is the depth of the water.If we plug in the values for S, g, and D, we can find the velocity of the water and then use the equation for discharge to find the total discharge carried by the river.For example, if the width of the river at the base is 10 meters and the depth of the water is 5 meters, the cross-sectional area would be:A = (10^2)/2 = 50 m^2The velocity of the water would be:V = √(2*10^-4 * 9.81 * 5) = 1.99 m/sAnd the discharge would be:Q = VA = 50 m^2 * 1.99 m/s = 99.5 m^3/sThis is the total discharge carried by the river.

Answer:

(a) 0.0064 kg/s

(b) 800 KPa

(c) 2.03

Explanation:

The ideal vapor compression cycle consists of following processes:

Process  1-2 Isentropic compression in a compressor

Process 2-3 Constant-pressure heat rejection in a condenser

Process 3-4 Throttling in an expansion device

Process 4-1 Constant-pressure heat absorption in an evaporator

For state 4 (while entering compressor):

x₄ = 34% = 0.34

P₄ = 120 KPa

from saturated table:

h₄ = hf + x hfg = 22.4 KJ/kg + (0.34)(214.52 KJ/kg)

h₄ = 95.34 KJ/kg

For State 1 (Entering Compressor):

h₁ = hg at 120 KPa

h₁ = 236.99 KJ/kg

s₁ = sg at 120 KPa = 0.94789 KJ/kg.k

For State 3 (Entering Expansion Valve)

Since 3 - 4 is an isenthalpic process.

Therefore,

h₃ = h₄ = 95.34 KJ/kg

Since this state lies at liquid side of saturation line, therefore, h₃ must be hf. Hence from saturation table we find the pressure by interpolation.

P₃ = 800 KPa

For State 2 (Leaving Compressor)

Since, process 2-3 is at constant pressure. Therefore,

P₂ = P₃ = 800 KPa

T₂ = 70°C (given)

Saturation temperature at 800 KPa is 31.31°C, which is less than T₂. Thus, this is super heated state. From super heated property table:

h₂ = 306.9 KJ/kg

(a)

Compressor Power = m(h₂ - h₁)

where,

m = mass flow rate of refrigerant.

m = Compressor Power/(h₂ - h₁)

m = (0.450 KJ/s)/(306.9 KJ/kg - 236.99 KJ/kg)

m = 0.0064 kg/s

(b)

Condenser Pressure = P₂ = P₃ = 800 KPa

(c)

The COP of ideal vapor compression cycle is given as:

COP = (h₁ - h₄)/(h₂ - h₁)

COP = (236.99 - 95.34)/(306.9 - 236.99)

COP = 2.03

The Ph diagram is attached

Answer:

"Physical" would be the right approach.

Explanation:

So the answer here is just the perfect one.

Answer:

i play it

Explanation:

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

........

....... False

ANSWER:

1) The car is not accelerating, because for the the car to turn while accelerating down the street, it has to deaccelerate (reduce speed) due to CENTRIPETAL FORCE that is acting on the car during the turn. This force acts to bring the car in the direction where it has turned to.

2) You will feel the movement as everyone in the car will tend to fall to the left, while the car makes a right turn. This is because of CENTRIFUGAL FORCE, which is acting to take the car to a left direction, while the car is turning to the right direction.

a) Call Setup Process on PSTN with SS7 Signaling: John initiates a call to Adam. John's local exchange (LE) routes the call to Adam's LE using SS7 signaling. SS7 network establishes a connection between the exchanges.

John and Adam's LEs establish a connection over the PSTN. The call is connected between John and Adam. Call termination occurs when either party hangs up.

b) Components of a GSM Network:

The main components are Mobile Station: User's mobile device. Base Transceiver Station: Wireless communication with the mobile station. Base Station Manages multiple base transceiver stations and handles tasks like call setup and handoff.

Mobile Switching Center (MSC): Central hub for call switching and routing. Home Location Register (HLR): Stores subscriber information for call routing and authentication.

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2.1) The support reactions are calculated now: \(A_{x} = 10\,kN\), \(A_{y} = -10\,kN\), \(B_{y} = 30\,kN\).

2.2) The member CD is on tensile load and the member BC is on compressive load. \(F_{BC} \approx 28.284\,kN\), \(F_{CD} = 20\,kN\)

The dynamic situation of a mechanical system whose geometry cannot be neglected is described by Newton's laws and D'Alembert's principle. A planar system in equilibrium is described by the following formulae:

\(\sum F_{x} = 0\)     (1)

\(\sum F_{y} = 0\)     (2)

\(\sum M = 0\)     (3)

2.1) The support reactions can be found by assuming that the truss is a rigid solid:

\(\sum F_{x} = A_{x} - F = 0\)    (4)

\(A_{x} = F\)

\(A_{x} = 10\,kN\)

\(\sum M_{A} = F\cdot r_{BD} - G \cdot (r_{AB}+r_{CD}) + B_{y}\cdot r_{AB} = 0\)     (5)

\(B_{y} = \frac{G\cdot (r_{AB}+r_{CD})-F\cdot r_{BD}}{r_{AB}}\)

\(B_{y} =\frac{(20\,kN)\cdot (8\,m)-(10\,kN)\cdot (4\,m)}{4 \,m}\)

\(B_{y} = 30\,kN\)

\(\sum F_{y} = A_{y} + B_{y} - G = 0\)     (6)

\(A_{y} = G - B_{y}\)

\(A_{y} = 20\,kN - 30\,kN\)

\(A_{y} = -10\,kN\)

Note - The negative sign means that the real direction of the component is antiparallel to the assumed one.

2.2) If the entire system is at equilibrium, then every part of the system must be also at equilibrium. The joint is considered a particle and thus the D'Alembert's principle is not necessary. The member CD is on tensile load and the member BC is on compressive load.

\(\sum F_{x} = F_{BC} \cdot \cos 45^{\circ} - F_{CD} = 0\)     (7)

\(\sum F_{y} = -G + F_{BC}\cdot \sin 45^{\circ} = 0\)     (8)

By (8):

\(F_{BC} = \frac{G}{\sin 45^{\circ}}\)

\(F_{BC} \approx 28.284\,kN\)

By (7):

\(F_{CD} = F_{BC}\cdot \cos 45^{\circ}\)

\(F_{CD} = 20\,kN\)

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Answer:

the answer is false

Explanation:

i took the advice of the other person and found a Quizlet that said false :)

i hope this helps :D

Answer:

I think it's the no 3rd

Explanation:

hope this helps

Answer:

No, the velocity profile does not change in the flow direction.

Explanation:

In a fluid flow in a circular pipe, the boundary layer thickness increases in the direction of flow, until it reaches the center of the pipe, and fill the whole pipe. If the density, and other properties of the fluid does not change either by heating or cooling of the pipe, then the velocity profile downstream becomes fully developed, and constant, and does not change in the direction of flow.

Here is an example document outlining the design of an interactive online personal assistant for mobile devices:

**Interactive Online Personal Assistant Design**

**Product Description:**

The interactive online personal assistant is a mobile application designed to provide users with personalized assistance and streamline their daily activities. The assistant utilizes artificial intelligence and natural language processing to understand and respond to user queries, perform tasks, and provide relevant information and recommendations.

**Key Features:**

1. Voice Recognition: The assistant can process voice commands, allowing users to interact with the application using their voice. It employs advanced speech recognition algorithms to accurately understand and interpret user queries.

2. Natural Language Processing: The assistant utilizes natural language processing techniques to analyze and understand the meaning behind user inputs. It can interpret complex queries, extract relevant information, and generate appropriate responses.

3. Task Management: The assistant helps users manage their tasks and schedules. It can create to-do lists, set reminders, and send notifications to ensure users stay organized and productive.

4. Personalized Recommendations: Based on user preferences, browsing history, and past interactions, the assistant provides personalized recommendations for various activities such as restaurants, events, movies, and more. It learns from user feedback and continuously refines its recommendations.

5. Information Retrieval: The assistant retrieves information from various sources such as the internet, databases, and user profiles to provide accurate and up-to-date information on a wide range of topics including weather, news, sports, and general knowledge.

6. Integration with External Services: The assistant seamlessly integrates with external services and applications such as calendars, email, navigation, and social media platforms. It can schedule appointments, send emails, provide directions, and interact with social media accounts on behalf of the user.

7. Multilingual Support: The assistant supports multiple languages, allowing users from different regions to interact with the application in their preferred language.

8. User Profiles and Preferences: The assistant creates user profiles to store individual preferences, settings, and personal information securely. It uses this information to personalize the user experience and provide tailored recommendations.

9. Continuous Learning: The assistant employs machine learning techniques to improve its performance over time. It learns from user interactions, feedback, and user-provided ratings to enhance its understanding, accuracy, and responsiveness.

**User Interface:**

The user interface of the assistant is designed to be intuitive and user-friendly, with a clean and modern look. It features a chat-like interface for text-based interactions and a voice input/output interface for voice-based interactions. The interface includes buttons and icons for easy access to various features and services.

**Conclusion:**

The interactive online personal assistant is a powerful tool that enhances user productivity, provides personalized assistance, and simplifies daily tasks. With its advanced capabilities, seamless integration with external services, and continuous learning, it aims to become an indispensable companion for users on their mobile devices.

Note: This is just an example design document, and the actual design may vary depending on specific requirements, target audience, and technical considerations.

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From a safety perspective, the most serious lift truck defect is faulty or malfunctioning brakes.

From a safety perspective, the most serious lift truck defect can vary depending on the specific situation and context. However, some commonly identified serious lift truck defects from a safety standpoint may include:

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The complete question is:

Fill in the blanks,

From a safety perspective, the most serious lift truck defect is ________________.

The e = (λz. z (λx. x)) (λx. x z), Not typeable because the second argument is a λ-term with an unbound variable 'z'.

A variable is a symbolic name that refers to a data value or set of values. In programming, a variable is a container that stores a specific value that can be changed throughout the program. Variables are used to store data such as numbers, words, objects and other information. In programming languages, variables are declared to indicate the type of data they store and to provide a reference to that data. For example, a variable might be declared to store a person’s name, or a list of numbers. Variables are essential for making programs dynamic and customizable, as they allow for data to be changed and used in different ways.

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Answer:

A. A only

Explanation:

Airbags are safety features added to vehicles to prevent or reduce the shock impact during a collision.

Disconnecting the negative battery cable would prevent power from reaching the airbag system, but the airbag system has a capacitor that stores charges at initial incidents and would deploy the bags. After a collision, the airbag leads are shot off preventing the airbag system power.

Answer:

I can help but I need to know what it looking for

Maintenance refers to detection and treatment of equipment or facilities. In simple terms, it refers to taking care of things. Whether it is about your house, car, or any other equipment that you possess, maintenance plays a vital role in keeping things operational and working efficiently.

The same is true when it comes to industrial equipment or facilities. Maintenance is essential for the smooth running of operations and prolonging the life of assets.Maintenance can be categorized into three different types; preventive, corrective, and predictive maintenance. Preventive maintenance is a strategy for maintaining equipment that is done on a set schedule. This helps to avoid any unscheduled breakdowns and downtime, which can be costly. Corrective maintenance is the type of maintenance done after a failure has occurred.

It includes any repairs and replacement of faulty parts. Predictive maintenance uses data analytics and condition-based monitoring to predict when maintenance will be needed before failure occurs. This type of maintenance is useful in minimizing downtime, increasing efficiency, and reducing repair costs.In conclusion, maintenance is essential in keeping equipment and facilities operational, efficient, and cost-effective. It is a preventative measure that can be done in different ways, depending on the nature of the equipment and facility. Preventive, corrective, and predictive maintenance strategies are all necessary to ensure that operations run smoothly and to minimize downtime.

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