The registered nurse (RN) is orienting a new RN assigned to the care of a client with a cardiac disorder and is told that the client has an alteration in cardiac output. After educating the new RN about cardiac output, which statement made by the new RN indicates the need for further instruction?
1. "A cardiac output of 2 L/min is normal."
2. "A cardiac output of 4 L/min is normal."
3. "A cardiac output of 6 L/min is normal."
4. "A cardiac output of 7 L/min is normal."

The speed of the boat relative to the water is 9.08 m/s, when the boat takes 14 minutes to cross the river.

We can decompose the velocity of the boat into two components: one parallel to the river, and one perpendicular to it. Let's call the parallel component \(v_p_a_r\) and the perpendicular component \(v_p_e_r_p\):-

\(v_p_a_r = v_b_o_a_t cos\theta\)

\(v_p_e_r_p = v_b_o_a_t sin\theta\)

The boat will travel a distance of 102 m across the river, which will take 14 minutes or 840 seconds. Therefore, the distance traveled parallel to the river will be:

\(d_p_a_r = v_p_a_r * t = v_b_o_a_t cos\theta * 840 s\)

The distance traveled perpendicular to the river will be:

\(d_p_e_r_p = v_p_e_r_p * t = v_b_o_a_t sin\theta * 840 s\)

The boat will end up at a point directly north of its departure point on the south bank, which means that \(d_p_e_r_p = 102 m\). Therefore, we can solve for \(v_b_o_a_t\) as follows:

\(v_b_o_a_t sin\theta * 840 s = 102 m\)

\(v_b_o_a_t sin\theta = 102 m / 840 s\)

\(v_b_o_a_t sin\theta = 0.1214 m/s\)

To solve for \(v_b_o_a_t\):-

\(tan\theta = d_p_a_r / d_p_e_r_p\)

\(tan\theta = (v_p_a_r * t) / (v_p_e_r_p * t)\)

\(tan\theta = v_p_a_r / v_p_e_r_p\\tan\theta = v_b_o_a_t cos\theta / (v_b_o_a_t sin(\theta))\\\)

Reserving the value of \(d_p_e_r_p\) and solving for \(\theta\):-

\(\theta = arctan(v_p_a_r / (102 m / 840 s))\\\theta = arctan(v_b_o_a_t cos(\theta) / 0.1214 m/s)\)

\(v_p_a_r^2 + v_p_e_r_p^2 = v_b_o_a_t^2\\(v_b_o_a_t cos(\theta))^2 + (v_b_o_a_t sin(\theta))^2 = v_b_o_a_t^2\)

\(v_b_o_a_t^2 (cos^2(\theta) + sin^2(\theta)) = v_b_o_a_t^2\\v_b_o_a_t^2 = 102^2 / (cos^2(\theta) + sin^2(\theta))\\v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]}\)

Reserving the value of \(\theta\):-

\(v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]} \\v_b_o_a_t = 9.08 m/s\)

Therefore, the speed of the boat relative to the water is 9.08 m/s.

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The statement that is true concerning a substance with high specific heat is as follows: the substance cools down slowly after heating. an example substance is aluminum metal (option A)

Specific heat or specific heat capacity refers to the heat capacity per unit mass of a pure substance.

In other words, specific heat is defined as the amount of heat needed to increase the temperature of 1kg of a material by 1K and is expressed in terms of J/kg·K or equivalently J/kg·°C.

The specific heat capacity of a material is a physical property. It is also an example of an extensive property since its value is proportional to size.

Water is an example of a substance that has an extremely high specific heat capacity, which makes it good for temperature regulation.

Therefore, a substance with high specific heat cools down slowly after heating and an example is aluminum metal.

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The magnitude of the force on the charge at the center of the cube is 4.8 × 10^-4 N.

To calculate the magnitude of the force on the charge at the center of the cube, we need to consider the forces exerted by each of the four charges on the center charge and then calculate their vector sum.

Given:

Charge on each corner = q = 2.0 × 10^-6 C

Charge at the center = q_c = -4.7 × 10^-6 C

Edge length of the cube = a = 6.0 cm = 0.06 m

First, we need to calculate the distance between the charges. The distance between the charge at each corner and the charge at the center is equal to half the diagonal of a face of the cube. Using the Pythagorean theorem, the diagonal length can be calculated as follows:

Diagonal length = √(a^2 + a^2) = √(2a^2) = √2a

The distance between the charges is then:

Distance = (√2a)/2 = (√2 × 0.06)/2 = 0.03√2 m

Now we can calculate the force between each corner charge and the charge at the center using Coulomb's Law:

Force = k(q*q_c)/r^2

where k is the electrostatic constant, q is the charge on the corner, q_c is the charge at the center, and r is the distance between the charges.

Plugging in the values, we get:

Force = (9 × 10^9 Nm^2/C^2) * (2.0 × 10^-6 C * -4.7 × 10^-6 C) / (0.03√2 m)^2

Calculating this expression, we find:

Force = 4.8 × 10^-4 N

The magnitude of the force on the charge at the center of the cube is 4.8 × 10^-4 N. This force is the vector sum of the forces exerted by each of the four charges at the corners of the cube.

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Answer:

2 seconds

Explanation:

Since the velocities during the initial five seconds and the return journey are not given, a comparison cannot be drawn.

The rate at which an object's location changes in a specific direction is measured by its velocity. It has both a direction and a magnitude because it is a vector quantity. Meters per second (m/s) is the standard unit of measurement for speed. Acceleration, which is a change in velocity per unit of time, can cause an object's velocity to alter over time. The difference between an object's position change and time change can be used to compute an object's average velocity over a period of time. A measurement of an object's rate of change in location at a specific moment in time is its instantaneous velocity.

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Iron oxide cement produces bright-red and yellow colors in some sandstones.

The coloration in sandstones is often influenced by the presence of different minerals and pigments in the cement that binds the sediment grains together. Iron oxide, specifically hematite (Fe2O3) and goethite (FeO(OH)), is a common cementing material found in sandstones. When present in higher concentrations, these iron oxide minerals can impart bright-red and yellow hues to the sandstone.

The colors of iron oxide cement in sandstones are a result of the selective absorption and reflection of light. Hematite and goethite have specific light absorption properties that allow them to absorb certain wavelengths of light, particularly in the blue and green regions of the visible spectrum. As a result, the sandstone appears red or yellow, as these colors are the wavelengths of light that are not absorbed and are instead reflected or transmitted.

The specific shades and intensity of red and yellow colors in sandstones can vary depending on factors such as the concentration of iron oxide minerals, grain size, and the presence of other minerals or impurities. Different geological processes and environmental conditions during the formation of sandstones can contribute to the variation in coloration.

The bright-red and yellow colors observed in some sandstones are typically caused by the presence of iron oxide cement, specifically hematite and goethite. The selective absorption and reflection of light by these minerals result in the sandstone appearing red or yellow. The exact coloration may vary based on factors such as the concentration of iron oxide, grain size, and geological processes involved in the sandstone's formation.

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Answer: 24 cm

Explanation:

F = 15 cm; d = 40 cm;

f - ?

\( \frac{1}{f} = \frac{1}{15} - \frac{1}{40} = \frac{1}{24} \)

f = 24 cm (according to the proportion)

"The term used for the distance between corresponding points of adjacent waves is wavelength."

The peak of the wave is the location where displacement is at its greatest in a wave motion, while the trough of the wave is the location where displacement is at its lowest.

The wavelength of a wave is the distance between its two consecutive crests and troughs.

The relationship between a wave's frequency and velocity can be used to describe wavelength.

We can quantify certain aspects of any wave called wave properties. Amplitude, wavelength, frequency, time, and velocity are some of these characteristics. It is the distance, typically measured in metres, between two equivalent points on adjacent waves. The distance between two consecutive crests can be used to calculate a transverse wave's wavelength.

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Answer:

0.1 A

Explanation:

From the question,

V = IR............ Equation 1

Where V = Voltage, I = current, R = Resistance.

Given: I = 0.2 A, R = 10 ohms.

Substitute into equation 1

V = 0.2(10)

V = 2 volt,

If the resistor is replaced with a 20 resistor, The nwe current is

I = V/R................ Equation 2

I = 2/20

I = 0.1 A

Answer:

7.5 × 10^-11 m

Explanation:

Hope this helps !

Work = force x distance

Work = 5500 x 1.8

Work = 9900 N

The work measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

Work = force x distance

Work = 5500 x 1.8

Work = 9900 N

therefore, work does 9900 N

Work is force applied over distance. Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon. Work is a mechanical manifestation of energy. The standard unit of work is the joule (J), equivalent to a newton - meter (N · m).

Work is defined as transferring energy into an object so that there is some displacement. Energy is defined as the ability to do work. Work done is always the same. Energy can be of different types such as kinetic and potential energy.

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The formula to calculate speed is distance/time and the speed for the approach is 6m/s.

This refers to the rate of movement of an object in relation to time.

Hence, we can see that given a sample data:

Hence, to find the speed for the sample data:

Distance/Time

36/6

= 6m/s

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The mass attached to a 1,460 N/m spring will have a period of oscillation of 0.80 seconds. The period of oscillation of this system will be 0.80 seconds.

The mass attached to a 1,460 N/m spring will have a period of oscillation of 0.80 seconds.What is an oscillation?Oscillation is the repetitive variation of a variable around an equilibrium value. The motion of a body or system that varies between two points is called oscillation. A spring attached to a mass will make it oscillate when compressed and released.What is the formula to find the period of oscillation of a spring mass system?The formula for finding the period of oscillation of a spring-mass system is as follows:T = 2π√m/kwhere:T is the period of oscillationk is the spring constantm is the mass attached to the springSubstituting the values in the formula:T = 2π√m/kT = 2π√2.3/1460T = 2π√0.00158T = 0.80 seconds.

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Answer: Speed increases

Explanation:

A streamlined shape reduces the surface area making contact with the fluid (in this case, water).  Less surface area making contact with the fluid means friction is reduced.  The lower the force of friction, the lower the "drag" on the object in motion, hence the faster it can go.  The force of friction is always in the opposite direction of the motion of the object.

The energy of a photon in joule with a given frequency of 8.73 × 10⁸ Hz is *4.59 × 10⁻¹⁹ J*.

The energy of a photon can be calculated using the formula: E = h * f, where E represents energy, h is Planck's constant (6.626 × 10⁻³⁴ J • s), and f is the frequency of the photon. By substituting the given values into the formula, we can calculate the energy as follows: E = (6.626 × 10⁻³⁴ J • s) * (8.73 × 10⁸ Hz) E = 5.77 × 10⁻²⁵ J • Hz  E ≈ 4.59 × 10⁻¹⁹ J Therefore, the energy of the photon is approximately 4.59 × 10⁻¹⁹ J.

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A hydraulic press may be utilized to tear down and reassemble the transmission for service.

A hydraulic press is a powerful tool that uses hydraulic pressure to apply force to an object. It can be used to press bearings and other components out of the transmission housing, as well as to press them back in during reassembly. A hydraulic press may be utilized to tear down and reassemble the transmission for service.

Dial indicators, bearing splitters, and snap ring pliers are also common tools used in transmission service, but they are typically used for specific tasks such as measuring clearances, removing bearings, or removing snap rings.

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If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is C. Inelastic.

In this scenario, the supply of the good is considered inelastic. The elasticity of supply measures the responsiveness of the quantity supplied to changes in price. When the price of a good decreases, and the quantity supplied decreases by a larger percentage, it indicates that the supply is relatively unresponsive to price changes.

To determine the elasticity of supply, we compare the percentage change in quantity supplied to the percentage change in price. In this case, a 0.3% decrease in price results in a 1% decrease in the quantity supplied. Since the percentage change in quantity supplied (1%) is greater than the percentage change in price (0.3%), the supply is considered inelastic.

Inelastic supply means that producers are less responsive to price changes, and a small change in price leads to a proportionally smaller change in quantity supplied. In such cases, producers may find it challenging to adjust their output levels quickly in response to price fluctuations.

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Answer:

The correct option is D 18

We know that when an unpolarized light passes through a polarizer its intensity gets halved.

Now according to Malu's law-

I=I0

So the intensity after passing through 1st polarizer will be

I1=I0 cos2 θ=I0 cos2 45∘=I02

After passing through 2nd polarizer

I2=I1 cos2 θ=I02×12=I04

After passing through 3rd polarizer

I3=I2 cos2 θ=I04×12

I3=I08

The intensity of the emerging beam is 0 W/m².

In other words, no light is transmitted through the stack of polarizers because the third polarizing sheet blocks all of the partially polarized light that passes through the second polarizing sheet.

When unpolarized light passes through a polarizer, half of the light is absorbed and the other half is transmitted in a plane perpendicular to the polarization axis of the polarizer.

In this case, we have three polarizing sheets arranged as follows:

Polarizer 1: |         | (vertical)

                  |____|      

Polarizer 2: /         / (at an angle of 0.833 rad with respect to Polarizer 1)

                 /____/            

Polarizer 3: |         | (horizontal)

                   |____|

The unpolarized beam of light passes through Polarizer 1 and half of its intensity is transmitted. Then, this partially polarized light passes through Polarizer 2, which is at an angle of 0.833 rad with respect to Polarizer 1.

The intensity of the light transmitted through Polarizer 2 is given by:

\(I_2\) = \(I_1\) cos²θ

where \(I_1\) is the intensity of the partially polarized light incident on Polarizer 2 and θ is the angle between the polarization axis of Polarizer 2 and the polarization axis of Polarizer 1.

Substituting the given values, we get:

\(I_2\) = (1/2) cos²(0.833 rad) = 0.2586 \(I_1\)

Therefore, the intensity of the light transmitted through Polarizer 2 is 0.2586 times the intensity of the partially polarized light incident on Polarizer 2.

Finally, the partially polarized light passes through Polarizer 3, which is perpendicular to Polarizer 1. The intensity of the light transmitted through Polarizer 3 is given by:

\(I_3\) = \(I_2\) cos²(90°) = \(I_2\) (0) = 0

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The answers include the following:

This is referred to as a group of stars that form a perceived pattern or outline and are usually given names and an example is hydra.

The Zenith as the name implies is known as the overhead point in the sky which is usually hardly seen while the constellation which is closest to this point tonight is Polaris due to the position thereby making it the most appropriate choice.

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Answer:

E = 256.444 N/C

Explanation:

E = kq/r²

E = 9*10^9 * 5.77*10^-9/(0.450)²

E = 51.93/0.2025

E = 256.444 N/C

Answer:

(a). The rocket's velocity is 117.6 m/s.

(b). The rocket can reach at maximum height is 940.8 m.

(c). The velocity the instant before the rocket crashes on the ground is 135.7 m/s.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 4 sec

(a). We need to calculate the rocket's velocity

Using equation of motion

\(v=u+at\)

Put the value into the formula

\(v=0+29.4\times4\)

\(v=117.6\ m/s\)

We need to calculate the maximum height at the moment fuel ends

For the value of x₁

Using equation of motion

\(x_{1}=ut+\dfrac{1}{2}at^2\)

Put the value into the formula

\(x_{1}=0+\dfrac{1}{2}\times29.4\times4^2\)

\(x_{1}=235.2\ m\)

We need to calculate the value of x₂

Using equation of motion

\(v^2=u^2-2gx_{2}\)

Put the value into the formula

\(0=u^2-2gx_{2}\)

\(x_{2}=\dfrac{u^2}{2g}\)

Put the value in to the formula

\(x_{2}=\dfrac{117.6^2}{2\times9.8}\)

\(x_{2}=705.6\ m\)

(b). We need to calculate the maximum this rocket can reach

Using formula for height

\(H=x_{1}+x_{2}\)

Put the value into the formula

\(H=235.2+705.6\)

\(H=940.8\ m\)

(c). We need to calculate the velocity the instant before the rocket crashes on the ground

Using equation of motion

\(v^2=u^2+2gh\)

Put the value into the formula

\(v=\sqrt{2\times9.8\times940.8}\)

\(v=135.7\ m/s\)

Hence, (a). The rocket's velocity is 117.6 m/s.

(b). The rocket can reach at maximum height is 940.8 m.

(c). The velocity the instant before the rocket crashes on the ground is 135.7 m/s.

Question: A 2.0 kg sphere with a velocity of 6.0 m/s collides head-on and elastically with a stationary 10 kg sphere, What is thier velocities after collision.

Answer:

v = 6 m/s, v' = 0 m/s

Explanation:

From the question,

For Elastic collision,

mu+m'u' = mv+m'v'......................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, v = final veolocity of the first sphere, v' = final velocity of the second sphere.

Also,

The relative velocity before collision = relative velocity after collision

u-u' = v-v'............................ Equation 2

Given:  m = 2 kg, m' = 10 kg, u = 6 m/s, u' = 0 m/s

Substitute into equation 1 and 2

2(6)+10(0) = 2v+10v'

2v+10v' = 12.............. Equation 3

6-0 = v-v'

v-v' = 6 ................... Equation 4

Solve equation 3 and 4 simultaneously.

v = 6+v'............. Equation 5

Substitute equation 5 into equation 3

2(6+v')+10v' = 12

12+2v'+10v' = 12

12v' = 12-12

v' = 0/12

v' = 0 m/s.

Also substitute the value of v' into equation 5

v = 6+0

v = 6 m/s

Answer:

The dimensional formula for specific latent heat is L²/T²

Explanation:

The unit of specific latent heat is J/kg

Answer: I would say the answer is B.

Explanation: It looks and sounds the most correct.

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

Power sources that are connected in parallel should have the same voltage output. This statement is true.

What does it mean when we say two power sources are connected in parallel?  Power sources are connected in parallel to increase the current output. This means that the positive terminals of the power sources are connected to the other positive terminals, and the negative terminals of the power sources are connected to the other negative terminals. This results in the voltage output remaining the same, but the current output increasing. This is useful when more current is required for a particular application. To summarize, when power sources are connected in parallel, the voltage output should remain the same, and the current output should increase.

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