Answer:
An image of the cosmic microwave background radiation, taken by the European Space Agency (ESA)'s Planck satellite in 2013, shows the small variations across the sky (Image credit: ESA/Planck Collaboration) The cosmic microwave background (CMB) is thought to be leftover radiation from the Big Bang, or the time when the universe began
Explanation:
Which excited electron has the lowest energy? a green dot in the middle of 5 concentric circles. the first away from the green dot is labeled n = 1. the second circle away from the green dot is labeled n = 2. the third circle away from the green dot is labeled n = 3. the fourth away from the green dot is labeled n = 4 and the last is labeled n = 5. there is an orange dot on the n = 5 circle. a green dot in the middle of 5 concentric circles. the first away from the green dot is labeled n = 1. the second circle away from the green dot is labeled n = 2. the third circle away from the green dot is labeled n = 3. the fourth away from the green dot is labeled n = 4 and the last is labeled n = 5. there is an orange dot on the n = 4 circle. a green dot in the middle of 5 concentric circles. the first away from the green dot is labeled n = 1. the second circle away from the green dot is labeled n = 2. the third circle away from the green dot is labeled n = 3. the fourth away from the green dot is labeled n = 4 and the last is labeled n = 5. there is an orange dot on the n = 3 circle. a green dot in the middle of 5 concentric circles. the first away from the green dot is labeled n = 1. the second circle away from the green dot is labeled n = 2. the third circle away from the green dot is labeled n = 3. the fourth away from the green dot is labeled n = 4 and the last is labeled n = 5. there is an orange dot on the n = 2 circle.
An excited electron with the lowest energy is the second circle away from the nucleus (green dot) labeled n = 2.
What is an excited state?In Chemistry, an electron is considered to be in an excited state when it temporarily occupies an energy state that is greater than its ground state. Also, an electron becomes excited when it gains extra energy by:
Absorbing a photon of lightColliding with a nearby atom.Based on the diagram shown in the image attached below, an excited electron with the lowest energy is the second circle away from the nucleus (green dot) labeled n = 2.
Read more on electrons here: https://brainly.com/question/12682510
#SPJ1
a) The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as: 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.
Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.
Given:
Voltage input (V) = 30V
Initial speed (w) = 0
Step size (h) = 0.4s
Time at which speed is to be determined (t) = 0.8s
We need to determine the speed (w) at t = 0.8s using Heun's method.
We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)
At t = 0 and w = 0 (initial conditions), we have:
k₁ = 0.02 + 0.06(0) = 0.02
We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)
So, at t = 0.4s and w = 0 (initial conditions), we have:
k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048
So, W₂ = w₁ + (k₁ + k₂)(h/2)
= 0 + (0.02 + 0.02048)(0.4/2)
= 0.04048(0.2)
= 0.008096
Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.
Learn more about the Runge-Kutta method here:
https://brainly.com/question/32093981
#SPJ4
The complete question is:
The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.
A series RLC circuit has a resistance of 20 , a capacitance of 10-2 F, an inductance of 10 H and an applied voltage E(t) = 200 cos 5t Volts. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system.
The subsequent current in the series RLC circuit is given by the equation: i(t) = I * cos(5t - Φ), where I is the amplitude of the current and Φ is the phase angle.
To find the subsequent current, we need to calculate the amplitude (I) and the phase angle (Φ) of the current.
First, let's calculate the resonant frequency (ω) of the circuit:
ω = 1 / √(LC) = 1 / √(10 * 10^(-2)) = 1 / √1 = 1 rad/s.
The applied voltage can be written as E(t) = E * cos(ωt), where E is the amplitude of the voltage.
Comparing this with the given voltage E(t) = 200 * cos(5t), we can equate the angular frequencies: ω = 5.
Now, let's find the impedance (Z) of the circuit:
Z = √(R^2 + (Xl - Xc)^2),
where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.
R = 20 Ω
Xl = ωL = 1 * 10 = 10 Ω
Xc = 1 / (ωC) = 1 / (5 * 10^(-2)) = 20 Ω
Plugging in these values, we get:
Z = √(20^2 + (10 - 20)^2) = √(400 + 100) = √500 ≈ 22.36 Ω.
The amplitude of the current (I) can be calculated using Ohm's Law:
I = E / Z = 200 / 22.36 ≈ 8.94 A.
The phase angle (Φ) can be found using the relationship between resistance, inductive reactance, and capacitive reactance:
tan(Φ) = (Xl - Xc) / R = (10 - 20) / 20 = -0.5.
Therefore, Φ ≈ -0.464 rad.
The subsequent current in the series RLC circuit is given by i(t) = 8.94 * cos(5t + 0.464) A.
To know more about amplitude visit :
https://brainly.com/question/3613222
#SPJ11
a train of length 200m passes over a bridge of length 600m how long does it take to cross the bridge with a uniform speed of 36kmph?
80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.
Given data,
length of bridge = 600m
length of train = 200m
Length of bridge + Length of train is the total distance travelled by train to cross the bridge.
So, 600+200 = 800m = 0.8km
Now, applying the formula for time,
\(time =\frac{distance}{speed}\)
\(time = \frac{0.8}{36}\)
time = 0.022hours
time in seconds= 0.022×60×60
time in seconds= 1.33×60
time in seconds= 80seconds
Therefore, 80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.
Learn more about time here:
https://brainly.com/question/10566304
#SPJ9
Where would the net force acting on a charge placed in a system of like charges be zero?
Answer:
If an object is electrically neutral it has no net charge becuase it has the same number of protons as it does electrons, which are opposite charges that offset each other. No, that just means that the sum of all its positive and negative amounts of charge equals zero.
Which option lists a form of potential energy followed by a form of kinetic
energy?
A. Magnetic energy | electromagnetic energy
O B. Electromagnetic energy electrical energy
O C. Gravitational energy elastic energy
O D. Sound energy | nuclear energy
Answer:
D)Sound Energy/magnetic energy
Explanation:
Got it right on Apex!
Answer:
Magnetic and Electromagnetic Energy
Explanation:
F
A student has been assigned to measure the density of an irregularly shaped piece of metal.which apparatus would be more appropriate to carry out this task
Complete Question:
A student has been assigned to measure the density of an irregularly shaped piece of metal.
Which apparatus would be most appropriate to carry out this task?
Group of answer choices
A. ruler, balance
B. beaker, crucible
C. flask, Bunsen burner
D. graduated cylinder, balance
Answer:
D. graduated cylinder, balance
Explanation:
In this scenario, A student has been assigned to measure the density of an irregularly shaped piece of metal.
The apparatus which would be most appropriate to carry out this task is a graduated cylinder and balance.
A graduated cylinder can be defined as a measuring cylinder used for the measurement of the volume of an irregularly shaped piece of metal or liquids. It is typically marked with horizontal lines on its side as units of measurement for volume. The balance is then used to weigh the metals mass.
Consider a Carnot heat engine that operates between 500
∘
C and 30
∘
C. If the engine does 2.2 J of work per cycle, how much heat per cycle does it absorb from the high temperature reservoir? Express your answer with one decimal place.
The Carnot heat engine absorbs 8.3 J of heat per cycle from the high-temperature reservoir.
The efficiency of a Carnot heat engine is given by the equation:
Efficiency = 1 - (Tc/Th)
where Tc is the temperature of the cold reservoir and Th is the temperature of the hot reservoir.
In this case, the temperatures are given as 500°C and 30°C, respectively. We can calculate the efficiency of the engine using these values:
Efficiency = 1 - (30 + 273.15)/(500 + 273.15) ≈ 0.8208
The efficiency of a Carnot heat engine is also defined as the ratio of the work done by the engine to the heat absorbed from the high-temperature reservoir:
Efficiency = Work/Heat absorbed from high-temperature reservoir
We know that the engine does 2.2 J of work per cycle, so we can rearrange the equation to solve for the heat absorbed from the high-temperature reservoir:
Heat absorbed from high-temperature reservoir = Work/Efficiency
Heat absorbed from high-temperature reservoir = 2.2 J / 0.8208 ≈ 2.68 J
Therefore, the Carnot heat engine absorbs approximately 2.68 J of heat per cycle from the high-temperature reservoir.
Learn more about the heat engine
brainly.com/question/13155544
#SPJ11
How much energy (in kWh) can you get from a 72 cell solar panel in one year?
a cd, initially turning at 100 rpm, speeds up to 300 rpm in 10 seconds, what is the cd’s average rotational acceleration?
The CD's average rotational acceleration is 20 rpm/s. In this case, the final angular velocity is 300 rpm, the initial angular velocity is 100 rpm, and the time is 10 seconds.
To find the CD's average rotational acceleration, we use the formula: average rotational acceleration = (change in angular velocity) / (change in time). In this case, the change in angular velocity is 300 rpm - 100 rpm = 200 rpm, and the change in time is 10 seconds. Dividing the change in angular velocity by the change in time gives us 200 rpm / 10 s = 20 rpm/s. Therefore, the CD's average rotational acceleration is 20 rpm/s. This means that, on average, the CD's rotational velocity increases by 20 revolutions per minute every second.
learn more about velocity here:
https://brainly.com/question/19979064
#SPJ11
which of the following statements is a valid conclusion to this experiment? explain your reasoning for choosing a certain statement
The statement that is said to be the a valid conclusion based on the results of this experiment is that: option c; Cattails grow the fastest when they receive maximal volumes of water
Do cattails need a lot of water?Cattails is known to be a plant that is said to possess “wet feet” in almost all of the growing season.
Note that when a person want to control the plant cattails, you will be required to distort the root system via the use of cutting, hand-pulling, dredging, flooding, and others.
Hence, The statement that is said to be the a valid conclusion based on the results of this experiment is that: option c; Cattails grow the fastest when they receive maximal volumes of water
Learn more about cattails from
https://brainly.com/question/26371981
#SPJ1
See full question below
Which of the following statements is a valid conclusion based on the results of this experiment?
a. Cattails grow the fastest when they receive minimal volumes of water
d. All plants grow fastest when they receive maximal volumes of water
b. Cattails grow the fastest when they receive intermediate volumes of water
e. Both c and d
c. Cattails grow the fastest when they receive maximal volumes of water
La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el piso. NOTA: Se debe encontrar la fuerza, para lo cual, se debe obtener el peso utilizando la fórmula de masa por gravedad que es 9.8 m / s2
Answer:
11025 N / m²
Explanation:
Los siguientes datos se obtuvieron de la pregunta:
Área (A) = 400 cm²
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Presión (P) =?
A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Fuerza (F) =.?
F = m × g
F = 45 × 9,8
F = 441 N
A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:
1 cm² = 0,0001 m²
Por lo tanto,
400 cm² = 400 cm² × 0,0001 m² / 1 cm²
400 cm² = 0,04 m²
Por tanto, 400 cm² equivalen a 0,04 m².
Finalmente, determinaremos la presión ejercida de la siguiente manera:
Área (A) = 0.04 m².
Fuerza (F) = 441 N
Presión (P) =?
P = F / A
P = 441 / 0,04
P = 11025 N / m²
Por tanto, la presión ejercida es 11025 M / m²
a ball is held at rest at the top of a hill. the ball is then released and starts rolling down the hill. at the bottom, it reaches level ground and keeps rolling along the ground. consider the level ground at the bottom of the hill as zero height. select the type or types of energy the ball has at the top of the hill.
Gravitational Potential Energy is the type of energy the ball has at the top of the hill.
What is meant by Gravitational Potential Energy ?The energy that an item has due to its location in a gravitational field is known as gravitational potential energy. For an object close to the surface of the Earth, when the gravitational acceleration may be considered to remain constant at around 9.8 m/s, gravitational potential energy is most frequently used.Gravitational potential energy may be defined as an energy that has a connection to gravitational force or gravity.If an item is placed at a height above (or below) the zero height, it has gravitational potential energy. If an item is not in its equilibrium position on an elastic material, it has elastic potential energy.Learn more about Gravitational Potential Energy refer to :
https://brainly.com/question/15896499
#SPJ4
A secant-secant angle intercepts arcs that are 3/5 and 3/8 of the circle. if a chord-chord angle and its vertical angle intercept the same arc, what is the measure of the chord-chord angle?
The measure of the chord-chord angle is 175.5.
What is a chord in a circle?A circle's chord is the line segment that connects any two locations on the circle's circumference. It should be remembered that a circle's diameter is defined as the lengthiest chord that runs across the center of the circle.
What is an angle in math?An angle is a figure created by two rays or lines that have the same termination in plane geometry. The Latin word "angulus," which meaning "corner," is where the term "angle" originates. The common terminal of the two rays—known as the vertex—is referred to as an angle's sides.
To learn more about angle visit:
https://brainly.com/question/13954458
#SPJ4
Exam
You push on a shovel then the
shovel pushes on dirt. The force
you apply to the shovel is the
input force. The shovel then
pushing on the dirt is known as
what?
A. Output work
B. Input work
C. Input force
D. Output force
A ball is dropped from the top of a tower 40 m high. What is its velocity when it has covered 20 m? What would be its velocity when it hits the ground? Take g= 10 m/s²
Given :
Height from which ball is dropped , h = 40 m .
Acceleration due to gravity , g= 10 m/s² .
Initial velocity , u = 0 m/s .
To Find :
Velocity when ball covered 20 m and velocity when it hit the ground .
Solution :
Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .
By equation of motion :
\(v^2=u^2+2gh\\\\v=\sqrt{2\times 10\times 20}\ m/s\\\\v=20\ m/s\)
Now , distance covered when body reaches ground is , 40 m .
Putting value h = 40 m in above equation , we get :
\(v=\sqrt{2\times 10\times 40}\ m/s\\\\v=20\sqrt{2}\ m/s\)
Hence , this is the required solution .
2. A block of mass 1.2 kg lies on a frictionless surface. A man slides the block
against a spring, compressing it .15m. When the man lets go of the spring, the
block moves at 5 m/s. What is the spring constant of the spring?
mm
.
Answer:
The spring constant will be "1333.33 N/m".
Explanation:
The given values are:
Mass,
m = 1.2 kg
Displacement compression,
x = 0.15 m
Block's velocity,
\(v_i=5 \ m/s\)
As we know,
⇒ \(E_i=E_f\)
or,
⇒ \(K_i+v_i=K_f+v_f\)
⇒ \(\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2\)
So,
⇒ \(K=\frac{mv_i^2}{x_2}\)
On substituting the values, we get
⇒ \(=\frac{1.2\times 5\times 5}{0.15\times 0.15}\)
⇒ \(=\frac{30}{0.0225}\)
⇒ \(=1333.33 \ N/m\)
a roller coaster starts at rest at the top of a 51-meter-high frictionless track. at the bottom of the track, what is the approximate speed of the roller coaster?
The approximate speed of the roller coaster is 32m/s.
Considering that the earth and the roller coaster are both parts of one system.
We can use the law of conservation of energy,
This law states that in a system, the sum of total energy is always conserved.
So we can say that the energy at the top of roller coaster will be equal to the energy at the bottom of the roller coaster.
At top, whole energy is potential energy and the bottom whole energy is kinetic energy,
So we can write,
PE = KE
Mgh = 1/2Mv²
Where M is mass of roller coaster,
v is the speed of roller coaster,
g is acceleration due to gravity and,
h is the height of the roller coaster,
Putting all the values,
gh = 1/2v²
v² = 2gh
v² = 2×9.8×51
v² = 999.6
v = 31.61 m/s.
The speed of roller coaster at the end is 32 m/s approx.
To know more about law of energy conservation, visit,
https://brainly.com/question/24772394
#SPJ1
a motorcycle covers a distance of 8.5 km in 15 minutes. Calculate the distance covered by the motorcycle in per second
bert and ernie are pushing on opposite sides of the box. if they can both push with the same amount of force, what is true about the motion of the box?
The box will be in rest due to net force applied on it is zero.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given that Bert and Ernie are pushing on opposite sides of the box with force of same magnitude, let it be F.
So, net force acting om the force = F-F = 0.
As that net force acting on the box is zero, the box will be in rest.
Learn more about force here:
https://brainly.com/question/13191643
#SPJ1
what term is used to describe the sliding motion within the layers of an object
The term used to describe the sliding motion within the layers of an object is "shear."
Shear refers to the deformation that occurs when layers of a material slide or move in relation to each other, parallel to their planes. This type of motion can happen in various materials, including solids, fluids, and even gases.
In the context of solids, shear can occur when a force is applied parallel to a surface or when there is a difference in movement between adjacent layers.
This can lead to the layers sliding past one another, resulting in a shearing or shearing deformation. Shear can cause changes in shape, stress distribution, and material properties within the object.
Shear is an essential concept in fields such as materials science, engineering, and physics.
Understanding shear behavior is crucial for designing structures, analyzing material properties, and predicting the response of materials under different loads and conditions.
Various mathematical models and equations, such as the shear stress and shear strain relationship, are used to quantify and describe shear deformation in materials.
To know more about shear refer here:
https://brainly.com/question/31611830#
#SPJ11
Please answer ASAP!
According to Newton's First Law (the Law of Inertia) -
Group of answer choices
when you kick a soccer ball, the ball pushes back against your foot.
when you hit a baseball, the bat can vibrate your hands.
when you push a shopping cart that is still, or at rest, it rolls forward.
when you lean back against a chair, the chair pushes back against your back.
Answer:
Letter C
Explanation:
That is newton's first law
25. Calculating
A triathlete enters a race in which
he swims 500 meters, runs 3000 meters, and
cycles 10.0 kilometers. What is the total distance
of the race in kilometers?
-I NEED HELP PLEASE! I BEGGGGG
Answer:
3,510 po yung sagot pa brainliest po
Explanation:
By adding the distances for cycling, running, and swimming, the total race distance can be determined. The distance covered by him is 13.5 km.
Converting all the distances to the same unit before combining them because the triathlete swims 500 meters, runs 3000 meters, and cycles 10.0 kilometers.
Divide 500 meters by 1000 to get kilometers: 500 meters divided by 1000 equals 0.5 kilometers.
Divide 3000 meters by 1000 to get 3 kilometers: 3000 meters divided by 1000.
The triathlete completes a 0.5-kilometer swim, a 3-kilometer run, and a 10.0-kilometer bike ride.
Now that the distances have been added, the total is 13.5 kilometers: 0.5 kilometers for swimming, 3 kilometers for running, and 10.0 kilometers for cycling.
Consequently, the race's overall length is 13.5 kilometers.
Learn more about distance here:
https://brainly.com/question/34779919
#SPJ7
You are pulling on a rope attached to the outer radius of a pulley with a moment of inertia I = 2.85 kg-m^2 as shown. The tension force of you on the pulley is 266.3 N. A pack of mass 23.4 kg is attached to the pulley's inner radius as shown. If the inner radius of the pulley is 0.43 m and the outer radius is 0.66 m, what is the magnitude of the linear acceleration of the pack? If instead of using a pulley with two radii, you were to replace the two radii pulley with a simple pulley of one radius: how would using the simple pulley instead of the two radii pulley affect the difficulty of holding the pack at rest over the edge? It will be easier to hold the pack. Not enough information to tell. There will be no difference. It will be harder to hold the pack.
The magnitude of the linear acceleration of the pack can be calculated using the following equation:a = (T - Fr) /m where a is the magnitude of the linear acceleration of the pack,T is the tension force of you on the pulley,Fr is the frictional force, and m is the mass of the pack.Substitute the given values to the formula:a = (T - Fr) / ma = (266.3 - Fr) / 23.4.
The frictional force can be determined using the moment of inertia of the pulley.I = mr²I = 2.85 kg-m²m = I / r²m = 2.85 / 0.43²m = 15.57 kgFr = maFr = 15.57 × aa = (266.3 - 15.57a) / 23.4Solve for a by multiplying both sides by 23.4:23.4a = 266.3 - 15.57a23.4a + 15.57a = 266.3a = 266.3 / 39.97a = 6.66 m/s².
Therefore, the magnitude of the linear acceleration of the pack is 6.66 m/s².If instead of using a pulley with two radii, you were to replace the two radii pulley with a simple pulley of one radius, it will be harder to hold the pack.
Learn more about magnitude:
https://brainly.com/question/24468862
#SPJ11
A car is traveling at a speed of 50 m/sec when it suddenly accelerates at a rate of 5 m/sec2. How fast will the car be going (final velocity) if it maintains that acceleration for 30 seconds?
Answer:
200 ms-1
Explanation:
v = u+ at
v = 50+ 5×30
v = 200 ms-1
Heat energy has to do with the energy contained within a system
true or false
science
Answer: The statement is false.
Explanation:
Although adding heat energy to a system raises its temperature, that isn't always the scenario. When you heat water, for example, the temperature rises, but when you heat it to 100 degrees Celsius, the state of the water changes while the temperature stays the same.
The weight shift forward and backwards in your vehicle is referred to as....
Pitch
Roll
Yaw.
x Methane, has a molar mass of 16.03 grams per mole. How many particles o of methane are present in 120 grams?
In order to determine the number of particles of methane, use the following expression:
number of particles = (mass /molar mass ) x Avogadro's number
in this case, you have:
molar mass = 16.03 grams/mole
mass = 120 grams
Avogadro's number = 6.02*10²³ particles/mol
replace the previos values of the parameters into the formula for the number of particles:
number of particles=(120 grams/ 16.03 grams/ mol)x(6.02*10²³particles/mol)
= (7.46 mol) x (6.02*10²³ particles/mol)
= 4.50*10²⁴ particles
Hence, the number of particles of methane, in 120 grams, is 4.50*10²⁴
an aluminum flagpole is 39.4 m high. by how much does its length increase as the temperature increases by 15
The length of the aluminum flagpole will increase by 0.00881 m as the temperature increases by 15.
The length of an aluminum flagpole may not change with temperature. While thermal expansion can cause materials to change in size when heated or cooled, aluminium, as a metal, is not significantly affected by temperature changes. As such, the length of an aluminium flagpole is unlikely to be significantly affected by changes in temperature.
Calculate the Coefficient of Linear Expansion for Aluminum
The coefficient of Linear Expansion for aluminum is about 0.000023 per degree Celsius
Calculate the change in length
Change in length = (Coefficient of Linear Expansion x Original Length x Change in Temperature)
Change in length = (0.000023 x 39.4 m x 15) = 0.00881 m
For more questions like Aluminum click the link below:
https://brainly.com/question/14617544
#SPJ4
Heart Rate During Aerobic Activity?
Answer:
It is recommended that you exercise within 55 to 85 percent of your maximum heart rate for at least 20 to 30 minutes to get the best results from aerobic exercise. The MHR (roughly calculated as 220 minus your age) is the upper limit of what your cardiovascular system can handle during physical activity.
(I think) ¯\_(ツ)_/¯