The chance of x 92 is the best option since it corresponds to the shaded area under a normal distribution with a mean of 100 and a standard deviation of 5.
Identify the mean (μ) and standard deviation (σ),
Here, mean μ = 100, standard deviation σ = 5
Recognize that x = 92 is within the shaded region of normal distribution, so the probability we're looking for is either x ≤ 92 or x ≥ 92.
Since the shaded region is to the right of 92, the best choice is the probability of x ≥ 92.
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Is it b? Am I right? Helppppp question 15
Answer:
A is correct.
Step-by-step explanation:
Since the 39 is the initial value and isn't a coefficient. 15 is a coefficient and represents the slope.
Dinner Bill- $28.15, Tax- 8%, Tip- 15% What is the final cost.
A group contains n men and n women. how many ways are there to arrange these people in a row if the men and women alternate?
A group contains n men and n women. 2n! number of ways are there to arrange these people in a row if the men and women alternate. Arrangement is known as permutation.
A permutation of a set in mathematics is, broadly speaking, the rearrangement of its elements if the set already has an ordered structure into a sequence or linear order. The act or procedure of altering the linear order of an ordered set is referred to as a "permutation."
When the order of the arrangements counts, a permutation is a mathematical technique that establishes the total number of alternative arrangements in a collection. Choosing only a few items from a collection of options in a specific sequence is a common task in arithmetic problems.
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scale factor is a to b and 1:2
Answer:
Ok the scale factor is the ratio of 1:2, but what are the two lengths? A and B? I need more information, like what numbers are A and B.
Step-by-step explanation:
. An article in the publication Consumer Reports reported the following data: * 35 of 80 randomly selected Perdue-brand chickens tested positive for campylobacter bacteria, salmonella bacteria, or both. * 66 of 80 randomly selected Tyson-brand chickens tested positive for campylobacter bacteria, salmonella bacteria, or both. From these data, would you conclude that the proportion of Tyson-brand chickens that test positive exceeds the proportion of Perdue-brand chickens that test positive
It conclude the Tyson-brand exceeds proportion of Perdue-brand chickens testing positive.
The test statistic and p-value are 2.33 and 0.0001 respectively.
The p-value < significance level, reject null hypothesis.
To test the hypothesis,
The proportion of Tyson-brand chickens testing positive exceeds the proportion of Perdue-brand chickens testing positive,
Use a two-proportion z-test. Let us state the relevant hypotheses.
Null Hypothesis (H₀), p₁ ≤ p₂
Alternative Hypothesis (H₁), p₁ > p₂
Where
p₁ = Proportion of Perdue-brand chickens testing positive
p₂ = Proportion of Tyson-brand chickens testing positive
Now, let us calculate the test statistic and p-value,
First, calculate the sample proportions,
p₁ = 35/80
= 0.4375 (proportion of Perdue-brand chickens testing positive)
p₂= 66/80
= 0.825 (proportion of Tyson-brand chickens testing positive)
Next, calculate the standard error (SE) of the difference between two proportions,
SE = √[(p₁ × (1 - p₁) / n₁) + (p₂ × (1 - p₂) / n₂)]
= √[(0.4375 × (1 - 0.4375) / 80) + (0.825 × (1 - 0.825) / 80)]
≈ 0.0844
Then, calculate the test statistic (z),
z = (p₁ - p₂) / SE
= (0.4375 - 0.825) / 0.0844
≈ -4.5821
Using a significance level of 0.01, the critical z-value for a one-tailed test is approximately 2.33 using z-calculator.
Finally, calculate the p-value associated with the test statistic.
p-value = P(Z > -4.5821)
Using a z-calculator, find that the p-value is very close to 0 (p-value < 0.0001).
Interpreting the results,
Since the p-value (0.0001) is less than the significance level (0.01), we reject the null hypothesis.
Therefore, sufficient evidence to conclude proportion of Tyson-brand chickens testing positive exceeds proportion of Perdue-brand chickens testing positive.
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The above question is incomplete, the complete question is:
An article in the publication Consumer Reports reported the following data: * 35 of 80 randomly selected Perdue-brand chickens tested positive for campylobacter bacteria, salmonella bacteria, or both. * 66 of 80 randomly selected Tyson-brand chickens tested positive for campylobacter bacteria, salmonella bacteria, or both. From these data, would you conclude that the proportion of Tyson-brand chickens that test positive exceeds the proportion of Perdue-brand chickens that test positive.
Carry out a test of hypotheses using a significance level 0.01. (Use p1 for Brand A and p2 for Brand B.)
State the relevant hypotheses.
Calculate the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
HAVING BAD DAY FREE 5o POINTS IF CORRECT
anna is x years old and her sister jane is y years old what will the sum of their ages be in 3 years
Answer:
S = x+y+9
Step-by-step explanation:
Age of Anna is x years and age of her sister is y years old.
3 years later,
Age of Anna = x+3
Age of her sister = y +3
Sum of their ages in 3 years will be :
S = x+3+y+3
S = x+y+9
Hence, this is the required solution.
what is 2+a when a=22?
Answer:
24
Step-by-step explanation:
2+a
2 + (22)
= 24
a) estimate the area under the graph of f(x) = 5 cos(x) from x = 0 to x = /2 using four approximating rectangles and right endpoints. (round your answers to four decimal places.)
The estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.
To estimate the area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints, we can use the right Riemann sum method.
The width of each rectangle, Δx, is given by the interval width divided by the number of rectangles.
In this case, Δx = (π/2 - 0)/4 = π/8.
To calculate the right endpoint values, we evaluate f(x) at the right endpoint of each rectangle.
For the first rectangle, the right endpoint is x = π/8.
For the second rectangle, the right endpoint is x = π/4.
For the third rectangle, the right endpoint is x = 3π/8.
And for the fourth rectangle, the right endpoint is x = π/2.
Now, let's calculate the area for each rectangle by multiplying the width (Δx) by the corresponding height (f(x)):
Rectangle 1: Area = f(π/8) * Δx = 5cos(π/8) * π/8
Rectangle 2: Area = f(π/4) * Δx = 5cos(π/4) * π/8
Rectangle 3: Area = f(3π/8) * Δx = 5cos(3π/8) * π/8
Rectangle 4: Area = f(π/2) * Δx = 5cos(π/2) * π/8
Now, let's calculate the values:
Rectangle 1: Area = 5cos(π/8) * π/8 ≈ 0.2887
Rectangle 2: Area = 5cos(π/4) * π/8 ≈ 0.3142
Rectangle 3: Area = 5cos(3π/8) * π/8 ≈ 0.2887
Rectangle 4: Area = 5cos(π/2) * π/8 ≈ 0
Finally, to estimate the total area, we sum up the areas of all four rectangles:
Total Area ≈ 0.2887 + 0.3142 + 0.2887 + 0 ≈ 0.8916
Therefore, the estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.
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-4K2 – 8k – 3 =-3 – 5K2
Solve by factoring
Answer:
k = 0 or 8
Step-by-step explanation:
First, get the variables and constants on their side.
-4k^2 + 5k^2 - 8k = -3 + 3 Now simplify
k^2 - 8k = 0 Factor
k(k - 8) = 0 Solve
k = [0, 8]
If you want you can double check your answer by plugging in the values you got. First, 0.
0 - 0 - 3 = -3 - 0
-3 = -3. That works, so we know 0 is correct. Now 8
-4(64) - 8(8) - 3 = -3 - 5(64)
-256 - 64 - 3 = -3 - 320
-320 - 3 = -323
-323 = -323 That also works, so we know 8 is correct.
Explain how you use a net to find the surface area of a prism.
Answer:
Nets of rectangular prisms are made up of rectangles and squares. Finding the areas of each of the rectangles and squares of the net of a rectangular prism and adding up those areas gives the surface area or total surface area of the prism.
Step-by-step explanation:
Answer:
By drawing a net, you can see each face of the prism. You can find the areas of each face and then add them together to find the total surface area.
Step-by-step explanation:
This is edges sample resopnse
=
39 newspapers in 3 piles
newspapers per pile
Answer:
there are 13 newspapers per pile
Step-by-step explanation:
to find newspapers per pile we divide 39/ 3
39/3= 13
convert 11000 milligrams into pounds. Round your answer to the nearest hundredth.
Answer:
0.02
Step-by-step explanation:
hope this is correct!!
The value of the number 11000 milligrams into pounds will be;
⇒ 24.255 × 10⁻³ pounds
What is Measurement unit?
A measurement unit is a standard quality used to express a physical quantity. Also it refers to the comparison between the unknown quantity with the known quantity.
Given that;
The number is,
⇒ 11,000 milligrams
Now,
Since, We know that;
1 milligrams = 2.205 × 10⁻⁶ pounds
Hence,
11,000 milligrams = 11,000 × 2.205 × 10⁻⁶ pounds
= 11 × 10³ × 2.205 × 10⁻⁶ pounds
= 24.255 × 10⁻⁶⁺³ pounds
= 24.255 × 10⁻³ pounds
Thus, The value of the number 11000 milligrams into pounds will be;
⇒ 24.255 × 10⁻³ pounds
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The geometry graph above is a (—)
Answer:
square
Step-by-step explanation:
Someone please help
Answer:
12
Step-by-step explanation:
12 is 40% of 30
A group of workers takes 4 1/2 days to plant 5 1/4 acres. What is the unit rate in acres per day?
Write your answer as a fraction or a mixed number in simplest form. Answer would be: 1 1/6
The unit rate for planting is 1 1/6 acres per day.
To find the unit rate, we need to divide the total area planted by the number of days taken to plant it. We can convert the mixed number of days to an improper fraction by multiplying the whole number by the denominator and adding the numerator.
Therefore, 4 1/2 days can be converted to 9/2 days.
Now we can divide the total area of 5 1/4 acres by the number of days it took to plant it, which is 9/2 days. To divide fractions, we invert the second fraction and multiply, so:
5 1/4 ÷ 9/2 = 21/4 ÷ 9/2 = 21/4 x 2/9 = 42/36
We can simplify 42/36 by dividing both the numerator and denominator by their greatest common factor, which is 6.
42/36 = 7/6
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consider the initial value problem y″ 36y=g(t),y(0)=0,y′(0)=0, where g(t)={t if 0≤t<30 if 3≤t<[infinity]. take the laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t)y(t) by Y(s)Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). == help (formulas) Solve your equation for Y(s)Y(s). Y(s)=L{y(t)}=Y(s)=L{y(t)}= Take the inverse Laplace transform of both sides of the previous equation to solve for y(t)y(t). y(t)=y(t)=
Thus, the value of the function for the given Laplace transformation is:
y(t)=(1/6)*∫[0,t]sin(6(t-u))du+30u(t-3)sin(6(t-3))
To take the Laplace transform of both sides of the given differential equation, we will use the fact that L{y''(t)}=s^2Y(s)-s*y(0)-y'(0) and L{g(t)}=G(s), where G(s) is the Laplace transform of g(t).
Thus, we have:
s^2Y(s)-s*0-0+36Y(s)=G(s)
Simplifying:
Y(s)(s^2+36)=G(s)
Solving for Y(s):
Y(s)=G(s)/(s^2+36)
To take the inverse Laplace transform of both sides, we will use the fact that L^-1{F(s)/s}=∫[0,∞]f(t)dt and L^-1{F(s)/(s^2+w^2)}=1/w*sin(wt).
Thus, we have:
y(t)=L^-1{Y(s)}=L^-1{G(s)/(s^2+36)}
Breaking up G(s) into two terms based on the definition of g(t), we have:
y(t)=L^-1{(t/(s^2+36))+(30e^(-3s)/(s^2+36))}
Taking the inverse Laplace transform of the first term:
L^-1{(t/(s^2+36))}=∫[0,t](1/6)*sin(6(t-u))du
Taking the inverse Laplace transform of the second term:
L^-1{(30e^(-3s)/(s^2+36))}=30u(t-3)sin(6(t-3))
Thus, our final solution for y(t) is:
y(t)=(1/6)*∫[0,t]sin(6(t-u))du+30u(t-3)sin(6(t-3))
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given a and b, determine the least-squares error in the least-squares solution of ax equals b.
The least-squares error in the least-squares solution of ax = b is given by the equation:
\(||b - ax||^2 = (b - ax)^T(b - ax) = b^Tb - 2a^Tbx + a^Tax\)
The least-squares solution is the value of x that minimizes this error. This occurs when the derivative of the error with respect to x is equal to zero, and the second derivative is positive.
To find the least-squares solution, we take the derivative with respect to x and set it to zero:
\(-2a^T(b - ax) = 0\\a^Tb = a^Tax\)
This gives us the normal equation, which is the equation that x must satisfy in order to minimize the error. The solution of this equation is:
\(x = (a^Ta)^-1a^Tb\)
This is the least-squares solution of the equation ax = b, and it is the value of x that minimizes the least-squares error. The least-squares error is given by the equation:
\(||b - ax||^2 = b^Tb - 2a^Tbx + a^Tax = b^Tb - a^T(a(a^Ta)^-1a^Tb) = b^Tb - a^T(a^Tb)\)
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Which is the approximate measure of angle acb? 31.0° 36.9° 53.1° 59.0°
Answer: the answer is
53.1
Please help me with my work
Answer:
16p^12 q^4
Step-by-step explanation:
Open up the parenthesis and simplify.
2^4 is 16
p^3 times ^4 is p^12
q times ^4 is q^4
So your answer is 16p^12 q^4
Answer:
16p^12 q^4
Step-by-step explanation:
This is because the power 4 will multiple with all the variables inside
hence, p^3 will become p^12
and q^1 will become q^4
the power 4 will also change 2 into 2^4 which is 16
Decrease £19064.67 by 9.5%
Give your answer rounded to 2 DP.
Answer:
£17253.53 to the nearest hundredth.
Step-by-step explanation:
Decreasing by 9,5% is equivalent to multiplying by 1 - 0.095 = 0.905.
19064.67 * 0.905
= £17253.52635.
Answer:
17253.53
Step-by-step explanation:
100%-9.5%=90.5%
100% = 19064.67
90.5% = 19064.67 ÷ 100 × 90.5
= 17253.52635
≈ 17253.53 (corrected to 2 dp)
Which pairs of polygons are similar?
Select each correct answer.
Consider the geometric sequence 1,3,9,27. If n is a integer, which of these functions generate the sequence?
a(n)= 3^n for n>0
b(n) = 3(3)^n for n>0
c(n)= 3^n for n>2
d(n) = 3^n-1 for n>2
The function d(n) = 3^n-1 for n>2 generates the given geometric sequence.
The common ratio of the given geometric sequence is 3, which means that each term is obtained by multiplying the previous term by 3.
a(n)= 3^n for n>0 generates the sequence 3^1, 3^2, 3^3, 3^4, ... = 3, 9, 27, 81, ..., which is not the same as the given sequence.
b(n) = 3(3)^n for n>0 generates the sequence 3(3)^1, 3(3)^2, 3(3)^3, 3(3)^4, ... = 9, 27, 81, 243, ..., which is not the same as the given sequence.
c(n)= 3^n for n>2 generates the sequence 3^3, 3^4, 3^5, 3^6, ... = 27, 81, 243, 729, ..., which is not the same as the given sequence.
d(n) = 3^n-1 for n>2 generates the sequence 3^2, 3^3, 3^4, 3^5, ... = 9, 27, 81, 243, ..., which is the same as the given sequence starting from the third term.
Therefore, the function d(n) = 3^n-1 for n>2 generates the given geometric sequence.
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Answer: A
a(n) = 3^n for n > 0
Step-by-step explanation: Khan
Please provide an explanation, thank you!
Answer:
angle a = angle d
50 = 2x+25
x=25/2
angle c = angle f
30 = 80 -25y
-50 = -25y
y = 2
Calculate the value of x. Make sure to include units. *
X
13°
25cm
O A-) 5.62
B-) 5.77
C-) 24.36
D-) 325
Hey! jeny.
︎⠀⠀⠀⠀⠀⠀⠀⠀⠀How are you?
Use the fundamental identities to simplify the expression. There is more than one correct form of the answer.
From the fundamental identities, we know that
\(csc\varphi=\frac{1}{sin\varphi}\)By substituting this result into the given expression, we have
\(9sin\varphi(\frac{1}{sin\varphi}-sin\varphi)\)Now, by distributing sine of phi into the parentheses, we have
\(9(\frac{sin\varphi}{sin\varphi}-sin^2\varphi)\)or equivalently,
\(9(1-sin^2\varphi)\)Now, from the Pythagorean identity:
\(cos^2\varphi+sin^2\varphi=1\)we can note that
\(cos^2\varphi=1-sin^2\varphi\)Then, by substituting this result into our last result from above, we obtain
\(9(1-sin^2\varphi)=9cos^2\varphi\)Therefore, the answer is:
\(9cos^2\varphi\)One of the legs of a right triangle measures 9 cm and its hypotenuse measures 13 cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
9.4
Step-by-step explanation:
Hopefully this explains it well enough, I can go deeper if needed :)
PLEEASE I NEED THIS RN
Cars lose value the farther they are driven. A random sample of 11 cars for sale was taken. All 11 cars were the same make and model. A line was fit to the data to model the relationship between how far each car had been driven and its selling price.
Based on this equation, estimate The price of a car that had been driven 56000 km.
Based on this equation, estimate the price of a car that had been driven 56 thousand kilometers.
Step-by-step explanation:
The flight of a javelin released six. 5 feet from the ground at an initial velocity of 68 ft./s is modeled by the function age equals 16 t^2+68t+6.5 where H is the height of the Javelin in feet after t seconds. When will the javelin hit the ground? Round to the nearest hundredth if necessary
The equation of the javelin path h(t) = -16t^2+68t+6.5 is a quadratic function
The javelin hits the ground after 4.344 seconds
How to determine when the javelin hits the ground?The equation of the javelin path is given as:
h(t) = -16t^2+68t+6.5
When it hits the ground, h(t) = 0.
So, we have:
-16t^2+68t+6.5 = 0
Using a graphing calculator, we have:
t = 4.344 and t = -0.094
Time cannot be negative.
So, we have:
t = 4.344
Hence, the javelin hits the ground after 4.344 seconds
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12. In PQR if mP is 14 less than five times x, mQ is five less than x, and mR is nine less
than twice x, find x and the measure of each angle.
Answer:
Step-by-step explanation:
mP=5x-14
mQ=x-5
mR=2x-9
we know that all the angles in a triangle= 180
that means (5x-14)+(x-5)+(2x-9)=180
5x-14+x-5+2x-9=180 we add the variables and the numbers
8x=180+28
8x=108
x=26
mP=130-14=116
mQ=26-5=21
mR=43
If f(x)=4x+10, find f(2)
Answer:
18
Step-by-step explanation:
f(2)=4x+10
f=(4)(2)+10
f=8+10
f=18