The SPH3U class designs a cannon able to shoot a human being out of it. If the human is launched at a velocity of 40 m/s, 37° from the ground, how far from the cannon should you place a mattress to catch the human if the muzzle of the cannon is 0.75 m from the ground? Hello I need to use kinematic equations and the variables vfvitda

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Explanation:

for part A:

work done is equal to change in potential energy which is

MgH

so the answer is 1.9 × 1 × 9.81

ANSWER FOR PART A: 18.639

FOR PART B:

power = flow rate x gh

= 5×9.81×1.9

93.195 watts

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

The answer is Non contract force

Answer:

0.1707 N

Explanation:

From the question,

Applying Coulombs law

F = kqq'/r²................... Equation 1

Where F = Electric Force, q = First charge, q' = second charge, r = distance between the charges, k = coulomb's constant

Given: q = -6.67×10⁻⁶ C, q' = -5.27×10⁻⁸C, r = 0.43 m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

F = [(-6.67×10⁻⁶)(-5.27×10⁻⁸)(8.98×10⁹)]/(0.43)²

F = (315.655×10⁻⁵)/(0.1849)

F = 1707.17×10⁻⁵

F = 1.7072×10⁻²

F = 0.1707 N

Answer:

a the chess peice

Explanation:

my head

Answer:

a

Explanation:

100 waves in 10 seconds would create the highest frequency.

Frequency is defined as the number of oscillation per seconds. It is usually

measured in Hertz which is denoted as Hz.

100 waves in 10 seconds means the frequency is

= 100 waves/ 10 seconds

= 10 Hz

This is the highest derived when compared with the remaining options

which makes it the most appropriate.

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Answer:

Assumption: there is no object between this point charge and the observer.

Explanation:

The electric field of a point charge is inversely proportional to the square of the distance from that point charge.

Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:

\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).

Convert the magnitude of the point charge in this question to standard units:

\(q = 1\; \rm nC = 10^{-9}\; \rm C\).

Apply that equation to find the magnitude of the electric field due to this point charge:

\(r = 1\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 2\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 3\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).

The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.

Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.

Answer:

F = 695.25 N

Explanation:

The force between Mars and Rover can be given by Newton's Law of Gravitation can be written as follows:

F = Gm₁m₂/r²

where,

F = Force of Gravity = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of rover = 74 kg

m₂ = mass of mars = 6.39 x 10²³ kg

r = distance between the centers of mars and rover = 2.1299 x 10⁶ m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(74 kg)(6.39 x 10²³ kg)/(2.1299 x 10⁶ m)²

F = 695.25 N

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Answer:

A)

The Big Bang is the earliest known event in the observable Universe, its earliest known phase of evolution, and the name of the model for this process. According to this scenario, the Big Bang took place around 13.800 million years ago, when the known Universe emerged from very dense and hot matter. This theory is based on observations showing that space is expanding from an initial state where all the matter in the universe had a very high density and temperature, to a more cold and stable one.

B)

A. Closed. The universe will stop expanding and then collapse back to its point of origin.

B. Flat. The universe will stop expanding but will not collapse.

C. Open. The universe will continue to expand forever.

Answer:

the energy in the oscillations between the blocks is 3.025 J

Explanation:

Given the data in the question;

Force f = 138 N

stiffness of spring k = 605 kg/s²

mass of block = 202 g = 0.202 kg

pushing the block a distance 15 cm, the rightmost block has moved a distance 5 cm

i.e

x₁ = 15 cm

x₂ = 5cm

the energy in the oscillations between the blocks will be;

E\(_A\) = E\(_B\) = \(\frac{1}{2}\)k( Δx )²

we substitute

= \(\frac{1}{2}\) × k( 15 - 5 )² × 10⁻⁴

= \(\frac{1}{2}\) × 605 × ( 10 )² × 10⁻⁴

= \(\frac{1}{2}\) × 605 × 100 × 10⁻⁴

= 3.025 J

Therefore, the energy in the oscillations between the blocks is 3.025 J

A color.......................................................................yeah the color of your socks is a color :}

Answer:

a

e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

b

G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

    The  velocity  of transverse waves in a crystal of atomic separation is  

                  \(b_y  = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }\)

Generally the dispersion relation is mathematically represented as

            \(e(k) =  b_y  *  k\)

=>    \(e(k) = c  \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} }  *  k\)

=>    \(e(k) =   c *  \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }\)

=>    \(e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )\)

Generally the group velocity is mathematically represented as

          \(G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} ) \)

The frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

The observed frequency is determined by applying Doppler effect;

f' = f₀(v + v₀)/(v)

where;

f' = 342(6 + 336)/(336)

f' = 348.1 Hz

Thus, the frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

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Using SOH,CAH,TOA, we can calculate the height of the building by taking the sine of the launch angle (60°) and the distance traveled (65 m). The height of the building is 56.9 m.

SOH,CAH,TOA stands for Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse and Tangent = Opposite/Adjacent. This is a set of trigonometric ratios that can be used to solve for angles and lengths of sides of a right triangle. It is used when the angle and length of two sides of a right triangle are known, but the length of the third side needs to be calculated.

Calculation using SOH, CAH, TOA

The distance from the ground to the top of the building is 65 m and the angle is 60 degrees. the height (h) of the building.has to be found

Using the trigonometric ratio of Sine,  calculate the height of the building:

Sin(60°) = Opposite/Hypotenuse

h/65 = sin(60°)

h = 65sin(60°)

h = 65(0.866)

h = 56.59 m

Therefore, the height of the building the projectile was launched to from the ground is 56.59 m.

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Answer:

Nuclear power plant.

Gas stove.

Dam.

Gas pump.

Geothermal heat pump.

Power lines.

Solar panels.

Windmills.

Explanation:

Hope this helps :))

Answer:

gasoline,solar panels,geothermal heat pump,windmills

Explanation:

F = 19.62 N

The mass of the ball = 2 kg

m = 2 kg

The force of the weight is given by the formula:

F = mg

where m is the mass

and g is the acceleration due to gravity

g = 9.81 m/s²

F = 2(9.81)

F = 19.62 N

The final speed is 58.8 m/s.

We have to note that if we are to solve the problem that we have here, we have to look at the equations of motion and this is how we can be able to get the final velocity of the object.

Thus we are going to have that;

v = u + gt

v = final speed

u =- initial speed

g = acceleration

t = time

v = gt

v = 9.8 * 6

= 58.8 m/s

The object is going to have a final speed of about 58.8 m/s when we look at the calculations above here.

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Some energy in a body is unavailable to do useful work. According to second law of thermodynamic, unavailable energy is quantified as the . the increase in entropy.

According to second law of thermodynamics, the heat is flowing from a hot body to colder body. This heat transfer from hot to cold, for instance, is related to nature's tendency for disorganized systems and a lack of energy available for labor.

It has been demonstrated that a system's entropy is a measurement of its disorder and the lack of energy for work.Entropy is a measurement of the amount of energy that cannot be used for labor.

Even if all kinds of energy are interconvertible and all of them can be utilized to do work, it is not always feasible to employ all of the available energy for labor, even in theory.

The study of thermodynamics is interested in this unusable energy because efforts to turn heat into work gave rise to the discipline.

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The average speed of the whole journey is 54 mph.

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Answer:

a.A

Explanation:

when x=0, the power becomes 0 and the exponent becomes 1

anything to the power of 0 is 1

in addition, the exponent only applies to the 'e' term, hence the e term will become 1 and multiply A to give you A

The mass of ice required at 0oc that 10 grams of 100oc steam will melt completely is 80.07 g.

The amount of energy that must be supplied to a solid substance (typically in the form of heat) in order to cause a change in its physical state and convert it to a liquid is known as latent heat of fusion (when the pressure of the environment is kept constant). The latent heat of fusion of one kilogramme of water, for example, is 333.55 kilojoules, which is the amount of heat energy that must be supplied to convert one kilogramme of ice without changing the temperature of the environment (which is kept at zero degrees Celsius).

Given,

mass of steam, \(m_s\) = 10g = 0.01 kg

Latent heat of fusion of ice ,\(L_f= 334kj/kg\)

Latent heat of vaporization of water, \(L_v=2256kj/kg\)

change of temperature, \(\delta T=100-0=100\textdegree\ C\)

The amount of heat cooling can be determined by.

\(m_{ice}L_f=m_sL_v+m_sS \delta T\)

Here, S= specific heat constant i.e \(4.184 kj/kg\)

\(m_{ice}L_f=(0.01*2256)+(0.01*4.184*100)\\\\m_{ice}*334=22.56+4.184\\\\m_{ice}*334=26.744\\\\m_{ice}=\frac{26.744}{334}=0.0807kg=80.07 g\)

Thus, the mass of quantity of ice is 80.07 g.

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Heya!!

For calculate velocity, lets applicate formula

                                                 \(\boxed{d = v * t}\)

                                               Δ   Being   Δ

                                         d = Distance = 3790 m

                                             t = Time = 249 s

                                             v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

\(\boxed{v= 3790\ m / 249\ s}\)

⇒ Resolving

\(\boxed{ v = 15,22 \ m/s }\)

Result:

The velocity is 15,22 meters per second.

Good Luck!!

Answer:

I think it's A

Explanation:

he shouldn't have changed the amount of sugar, because the whole point is to see which temperature dissolves sugar more quickly.

Answer:

C

Explanation:

The thermal energy from her hand will go up into the smoothie.

Answer:

C bois

Explanation:

Answer: \(f=3.125 Hz\)

Explanation:

frequency = 1 / period

\(f=\frac{1}{T}\)

\(f=\frac{1}{0.32}=3.125Hz\)

Therefore, the frequency of the wave is 3.125 Hz.

The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns

This is defined as the change in momentum of an object.

Impulse = change in momentum

Impulse = final moment – Initial momentum

Impulse = force × time

h = ½gt²

6.02 = ½ × 9.8 × t²

6.02 = 4.9 × t²

Divide both side by 4.9

t² = 6.02 / 4.9

Take the square root of both side

t = √(6.02 / 4.9)

t = 1.1 s

Impulse = Force × time

Impulse = 66.052 × 1.1

Impulse = 72.66 Ns

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