The spring of a spring gun has force constant k = 400 N/m and negligible mass. The spring is compressed 6.00 cm and a ball with mass 0.0300 kg is placed in the horizontal barrel against the compressed spring. The spring is then released, and the ball is propelled out the barrel of the gun. The barrel is 6.00 cm long, so the ball leaves the barrel at the same point that it loses contact with the spring. The gun is held so the barrel is horizontal.(a) Calculate the speed with which the ball leaves the barrel if you can ignore friction. (b) Calculate the speed of the ball as it leaves the barrel if a constant resisting force of 6.00 N acts on the ball as it moves along the barrel. (c) For the situation in part (b), at what position along the barrel does the ball have the greatest speed, and what is that speed? (In this case, the maximum speed does not occur at the end of the barrel.)

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer:

Distance and Mass

Explanation:

The maximum capillary rise of water to be expected  in the vertical glass tube is 15 mm.

The process of a liquid flowing in a small area without the aid of, or even in opposition to, any outside forces like gravity is known as capillary rise.

The effect can be observed in a biological cell, in a thin tube, in porous materials like paper and plaster, in some non-porous materials like sand, liquid carbon fiber, and some other porous materials.

The maximum capillary rise of water = 4σcosθ/ρgd

= ( 4 × 0.0733 × cos0°)/(10³ × 9.81 × 2 × 10⁻³) meter

= 0.015 meter

= 15 mm.

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The initial temperature of the water was 0°C and the original temperature of the ice was -78.8°C.

First, we need to determine how much heat was transferred from the water to the ice to melt the ice and raise its temperature to 0°C.

The heat is required to melt the ice will be;

Q₁ = m_ice x Lf

where m_ice is the mass of the ice and\(L_{f}\) is the latent heat of fusion of ice.

Q₁ = 1.0 kg x 3.3 x 10⁵ J/kg

= 3.3 x 10⁵ J

The heat required to raise the temperature of the melted ice from -x°C to 0°C is;

Q₂ = m_ice x c_ice x ΔT

where c_ice is the specific heat capacity of ice and ΔT is the change in temperature.

Q₂ = 1.0 kg x 2093 J/kg.°C x (0 - (-x))°C

= 2093x J

The heat lost by the water will be equal to the heat gained by the ice;

Q₁ + Q₂ = m_water x Cw x ΔT

where m_water is the mass of the water and Cw is the specific heat capacity of water.

3.3 x 10⁵ J + 2093x J = 1.0 kg x 4186 J/kg.°C x (0 - T)°C

Solving for T, we get;

T = -[(3.3 x 10⁵ J + 2093x J)/(4186 J/kg.°C)]

= -78.8°C

Therefore, the original temperature of the ice was -78.8°C.

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The area under the curve for the histogram in this problem is given by the following option:

B. 97.

The histogram is composed by rectangular bins, hence the total area under the histogram is given by the sum of the areas of each bin.

The area of a rectangle of base b and height h is given by the multiplication of these dimensions, as follows:

Area = b x h.

From the histogram given in this image, all the bins have a base of 1, hence the total area is given by the sum of the heights of the histogram.

Thus the total area is calculated as follows:

Area = 5 + 7 + 11 + 15 + 17 + 14 + 12 + 9 + 4 + 3 = 97.

Meaning that option B is correct.

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ANSWER:

A. It requires no work.

STEP-BY-STEP EXPLANATION:

The heat pump is a thermal machine that takes heat from a cold space and transfers it to a warmer one thanks to a work provided from the outside.

Which means it requires work, so the correct answer is A. It requires no work.

The magnitude of the induced electric field is (RdB/dt)/4

The induced electric field is gotten from

-∫E.dl = dФ/dt where E = induced electric field, dl = path length vector, Ф = magnetic flux through cylindrical region = AB where A = area of magnetic flux = πR² where R = radius of cylindrical region and B = magnetic field.

So, -∫E.dl = dФ/dt

-∫E.dl = dAB/dt

-∫Edlcos0 = AdB/dt (where E.dl = Edlcos0 = Edl since E and dl are parallel to each other.)

So -∫Edl = πR²dB/dt

-E∫dl = πR²dB/dt (∫dl = 2πr since the integral is the circumference of the path)

-E(2πr) = πR²dB/dt (we integrate dl from r = 0 to 2R)

-E2π(2R - 0) = πR²dB/dt

-E4πR= πR²dB/dt

E = πR²dB/dt ÷ 4πR

E = -(RdB/dt)/4

So, the magnitude of the induced electric field is (RdB/dt)/4

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The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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Answer: A velocity-time graph shows how velocity changes over time

Explanation:

Answer:velocity

Explanation:

Usually, we use sampling when a population is hard to study, for some reason.

Sampling is a technique commonly employed in research and statistics when it is impractical or impossible to study an entire population directly. It involves selecting a subset, or sample, from the population and using the information gathered from the sample to make inferences about the entire population. This is done with the assumption that the sample is representative of the population and that the findings from the sample can be generalized to the larger population.

There are several reasons why a population might be difficult to study comprehensively. One reason is the size of the population. For example, if the population of interest is the entire world or a country, it would be practically impossible to study each individual in the population due to logistical constraints and limited resources. In such cases, sampling allows researchers to gather information from a smaller, manageable subset of the population.

Another reason for using sampling is when the population is dispersed or geographically scattered. If the population is spread out across a wide area, it can be challenging and costly to reach and collect data from every individual. Sampling allows researchers to select representative individuals or clusters from different regions, making data collection more feasible.

Additionally, there are cases where the population is inaccessible or hard to reach due to privacy concerns or ethical considerations. For example, if the population consists of individuals with certain medical conditions or sensitive personal information, it may be challenging to obtain consent or access to the entire population. In such cases, researchers can use sampling methods to obtain data from a subset of individuals who are willing to participate and meet the necessary criteria.

In summary, sampling is a valuable tool when studying populations that are hard to access, too large, or dispersed. It allows researchers to gather relevant data from a representative subset of the population and make valid inferences about the larger population, despite the challenges posed by studying the population as a whole.

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The question probable may be:

Usually, we use                  when a population is hard to study, for some reason.

The motion of the particles in this kind of wave is that the particles will move up and down over small areas.

In physics, mathematics, and related fields, a wave is described as a propagating dynamic disturbance of one or more particles or quantities that can be periodic, in which case those particles or quantities oscillate repeatedly about an equilibrium value at some frequency.

The type of the wave that has been discussed in the scenario above is called the transverse wave.

The transverse wave are known to be the waves where the particle motion is the perpendicular to the motion of the wave.

In the transverse waves that is a moving kind of a wave where the oscillations are perpendicular to the direction of the movement of the wave.

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Answer:

Explanation:

Given:

D = 1.80 m

h = 65.0 cm =0.65 m

m = 3.70 g = 0.0037 kg

___________________

ρ - ?

S = π·D²  / 4 = 3.14·1.8² / 4 ≈ 2.54 m²

V = S·h = 2.54·0.65 ≈  1.65 м³

ρ = m / V =  0.0037 /1.65 ≈ 0,0022 kg / m³

Answer:

5 m/s

Explanation:

Total distance = 300 + 100 = 400m

Total time = 60 + 20 = 80s

Velocity = 400/80 = 5m/s

Average velocity of man is 5 meter per second.

To find the average speed of an object we divide the total distance travelled by the total time time taken by object.

Total distance travelled by man = 300 + 100 = 400 m

Total time taken by man = 60 + 20 = 80 seconds

Average velocity,\(=\frac{400}{80} =5m/s\)

Thus, Average velocity of man is 5 meter per second.

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The magnitude of the charge is 0.82 * 10-7 C, that can be calculated using the formula for the same.

Electric charge is available in types, which we pick to name high-quality charge and bad charge. This is the importance of the pressure which every fee exerts on the opposite fee (recollect Newton's third law).

Let the charge on each of them be "Q"

Now, electrostatic force of attraction on each of them = (1/4πε)(Q2/0.022)

Also, this force is being acted on each of the spheres, hence,

(1/4πε)(Q2/0.022)  = M*a

9 * 109 * Q2 * 104 / 4 = 10-3 * 150

Q = 0.82 * 10-7 C

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Using the formula for the charge, it can be determined that the charge has a magnitude of 0.92 x \(10^{-7}\) C.

There are many kinds of electric charge, which we will refer to as good charge and poor charge. This highlights the significance of the pressure one fee puts on the opposite fee remember Newton's third law.

Let "Q" be the charge on each of them.

Currently, the electrostatic force of attraction between each of them is equal to (1/4)(Q2/0.022).

Additionally, each of the spheres is being affected by this force, so

(1/4πε)(Q2/0.022) = M*a

9 x 109 x Q2 x 104 / 4 = \(10^{-3}\) x130

Q = 0.92 x \(10^{-7}\) C

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1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

Explanation:

We can use Hooke's law to solve this problem. Hooke's law states that the force required to extend or compress a spring by some distance x is proportional to that distance. Mathematically, this can be written as:

F = kx

where F is the force applied to the spring, x is the distance the spring is stretched or compressed, and k is the spring constant, a measure of the stiffness of the spring.

To find the spring constant, we can use the given information that a 20g weight causes an extension of 0.72cm in the spring. We can convert the weight to force using the acceleration due to gravity, g:

F = mg = (0.02 kg)(9.8 m/s^2) = 0.196 N

Now we can solve for the spring constant:

k = F/x = 0.196 N / 0.0072 m = 27.2 N/m

Finally, we can use this spring constant to find the extension caused by an 80g weight:

F = mg = (0.08 kg)(9.8 m/s^2) = 0.784 N

x = F/k = 0.784 N / 27.2 N/m = 0.0288 m

So the extension caused by an 80g weight is 0.0288 m or 2.88 cm.

Answer:

5.68*10^-5 °C

Explanation:

ADC is an acronym that means analog to digital conversion.

The numbers of bit in any ADC is the level of Voltage it possess.

The question states 32 bits, this means that it's total voltage levels is 2^32

Also, the question gives us a range of 10 V for the ADC. Now we can evaluate the resolution of the voltage as:

Δv = 10 / (2^32)

Δv = 10 / 4.29^9

Δv = 2.33*10^-9

The thermocouple sensitivity is 41 micro volts/°C

Thermocouple sensitivity = Δv/ΔT, where ΔT is the temperature change

ΔT = Δv/thermocouple sensitivity

ΔT = 2.33*10^-9 / 41*10^-6

ΔT = 5.68*10^-5 °C

Thus, the smallest temperature change is 5.68*10^-5 °C

4th paths out of 1 - 5 would the bowling ball most closely follow as it falls to the ground

The bowling ball moves due to the resultant force of the vertical and horizontal direction.

The overall force operating on the item or body as well as the direction in which the body is moving are referred to as the resultant force. When the object is stationary or moving at the same speed as it, there is no consequent force.

The outcome is what is produced when vectors are added together. The biggest (maximum) consequent when adding two vectors is equal to their sum when forces are acting in the same direction.

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All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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Answer:

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

Explanation:

By law of conservation of momentum  

momentum before collision = momentum after collision

\(m_1u_1+m_2u_2 = m_1v_1+m_2v_2\\plugging/values\\1520\times16+ 0= 1520\times v_1 + 663\times v_2\\24320= 1520v_1+663v_2\)

Since, collision is elastic

\(16 = v_2-v_1///v_2 = v_1+16 ....(b)\)

solving the above two equations we get

v_1 = 6.28 m/s and v_2 = 22.28 m/s

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

Answer:

the intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

Answer:

Explanation:

Since no external force acts on the system , centre of mass of two players will remain the same throughout the movement .

Distance of centre of mass is inversely proportional to mass . So centre of mass of the system will be nearer to 60 kg player

Distance of cetre of mass from 60 kg player

= 10 x 40 / (60+40 )

= 4 m

They will meet at centre of mass .

So, 60 kg player will be moving by a distance of 4 m , 40 kg player will be moving by 6 m before they meet .

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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The momentum of the bullet before and after the collision must be equal, and the velocity of the bullet after the collision must be one-half of its initial velocity.

Velocity is the change in an object position is typical Excel in unit of m/s velocity is equal to the distance travelled by the time it takes for velocity is also related to which is the rate of change of velocity.

The ratio of the velocity of the system after collision to the initial velocity of the bullet is equal to the inverse of the ratio of the masses of the bullet and the wooden block. In other words, it is equal to m/(m+m) = 1/2. This means that the velocity of the system after the collision is one-half the initial velocity of the bullet.

This result follows from the law of conservation of momentum, which states that the total momentum of the system before collision must equal the total momentum of the system after collision. If we assume that the bullet and the wooden block are the only objects involved in the collision, then the total momentum of the system before the collision is equal to the momentum of the bullet, and the total momentum of the system after the collision is equal to the momentum of the wooden block plus the momentum of the bullet. Since the wooden block is initially at rest, its momentum is zero before and after the collision. The momentum of the bullet before the collision is equal to its mass times its velocity, and the momentum of the bullet after the collision is equal to its mass times its velocity after the collision. Therefore, the momentum of the bullet before and after the collision must be equal, and the velocity of the bullet after the collision must be one-half of its initial velocity.


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Answer:

It's the Second one Endocrine Cells

Answer:

Shown by explanation;

Explanation:

The heat of the sample = mass ×specific heat capacity of the sample × temperature change(∆T)

Assumption;I assume the mass of the samples are : 109g and 192g

∆T= 30.1-21=8.9°c.

The heat of the samples are for 109g are:

0.109 × 4186 × 8.9 =4060.84J

For 0.192g are;

∆T= 67-30.1-=36.9°c

0.192 × 4186×36.9=29656.97J

The minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is  140km.

Telescope is device through which we can see the distant objects very clearly as it seems like they are some meters away.

Distance of the Mars from the Earth D = 1.99 x 10¹¹ m

Diameter of telescope's objective lens d = 0.977 m

The wavelength of light λ in m, λ = 563nm = 563 x 10⁻⁹ m

The distance y or the minimum feature size  =1.22λD/d

Substitute the value, we get

y = 1.22 x 563 x 10⁻⁹ x 1.99 x 10¹¹ /0.977

y = 140 km (approximately)

Thus, the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is  140km.

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To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.

In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:

Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians

To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:

Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians

Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.

Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.

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