The two forces F?1 and F?2 shown in (Figure 1) act on a 29.0-kg object on a frictionless tabletop. Suppose that F1 = 11.6N , and F2 = 18.8N .The a diagram forms a 90 degree angle with F1 on the negative x axis and F2 on the negative y axis. diagram b has F2 on the positive y axis with F1 in quandrant 4 forming a 120 angle. Determine the magnitude of the net force on the object for the diagram (a) in the figure

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{500}{1000} = \frac{1}{2} \\ \)

We have the final answer as

Hope this helps you

El calentamiento del instrumento viento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

Los instrumentos musicales trabajan por procesos de resonancia, ya sean de cuerda o viento; en los instrumentos de viento la frecuencia que emites esta dada por la relación  

                   fₙ = \(n \ \frac{v_s}{2L}\)    n = 1, 2, 3, ...

Donde f es la frecuencia emitida, L la longitud del tubo n es una constante entera y v_s es la velocidad del sonido

La velocidad del sonido en el aire depende de la temperatura del aire, según la relacion          

               vs = vo + 0,6 T  

Donde v₀ es la temperatura del aire a 0ºC, v₀ = 331 m/s y T la temperatura en grados centígrados.

De esta dos expresiones podemos ver que la frecuencia que emite el instrumento de viento depende  de la temperatura del aire, además en los instrumentos con boquilla la frecuencia de resonancia de la boquilla también depende de la temperatura de la boquilla que por ser liviana cambia fácilmente.

En conclusión el calentamiento del instrumento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

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Answer:

The acceleration is a = 2.75 [m/s^2]

Explanation:

In order to solve this problem we must use kinematics equations.

\(v_{f} = v_{i} + a*t\\\)

where:

Vf = final velocity = 13 [m/s]

Vi = initial velocity = 2 [m/s]

a = acceleration [m/s^2]

t = time = 4 [s]

Now replacing:

13 = 2 + (4*a)

(13 - 2) = 4*a

a = 2.75 [m/s^2]

The way that Q and W are related during the isobaric part of the overall path is that W provides energy output, while Q provides energy input; Q is larger. Option A.

A thermodynamic process called an isobaric process keeps the pressure constant. This is typically accomplished by allowing the volume to alter in size in order to balance off any pressure changes brought on by heat transfer.

Vb > Vd

W tends towards the positive. This is the energy output of the system. The pressure is constant so Q is energy input. Hence the first option is the correct one

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Question

how are q and w related during the isobaric part of the overall path from state d to state b?

1. W provides energy output, while Q provides energy input; Q is larger

2. Both W and Q provide energy input

The answer is option (b) irreflexive, i.e., "is not married to." Therefore, we can conclude that the irreflexive is "is not married to".

Here are two relations: "is married to" and "is not married to." Supposing the universe is the set of all living human beings, which of these is irreflexive.

The irreflexive is "is not married to".What is irreflexive. In Mathematics, a binary relation R over a set X is irreflexive if and only if no element of X is associated with itself under the relation. Symbolically, ∀x ∈ X, ¬(xRx).

For example, the "greater than" relation is irreflexive on the real numbers because no real number is ever greater than itself.

What is a binary relation A binary relation R from a set A to a set B is a subset of the Cartesian product A × B, where A and B are arbitrary sets.In this case, the universe is the set of all living human beings.

Therefore, the relation "is married to" is not irreflexive. However, the relation "is not married to" is irreflexive since no human being is not married to themselves.

Thus, the answer is option (b) irreflexive, i.e., "is not married to."Therefore, we can conclude that the irreflexive is "is not married to".

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The relation "is married to" is reflexive, while the relation "is not married to" is irreflexive. Neither relation is symmetric, asymmetric, or antisymmetric.

The relation "is married to" is an example of a reflexive relation, while the relation "is not married to" is an example of an irreflexive relation.

(a) Reflexive: A relation is reflexive if every element in the set is related to itself. In the case of the relation "is married to," every person in the universe of all living human beings is married to themselves. For example, John is married to John, Mary is married to Mary, and so on. This satisfies the condition of reflexivity.

(b) Irreflexive: A relation is irreflexive if no element in the set is related to itself. In the case of the relation "is not married to," no person in the universe of all living human beings is not married to themselves. This means that everyone is married to themselves, which contradicts the condition of irreflexivity.

The relations "is married to" and "is not married to" are not symmetric, asymmetric, or antisymmetric because they do not satisfy the respective conditions for these properties.

(c) Symmetric: A relation is symmetric if for every element (x, y) in the relation, the element (y, x) is also in the relation. In the case of the relation "is married to," if John is married to Mary, it does not necessarily mean that Mary is married to John. Therefore, the relation is not symmetric.

(d) Asymmetric: A relation is asymmetric if for every element (x, y) in the relation, the element (y, x) is not in the relation. In the case of the relation "is married to," if John is married to Mary, it is not possible for Mary to be married to John. Therefore, the relation is not asymmetric.

(e) Antisymmetric: A relation is antisymmetric if for every element (x, y) in the relation, where x is not equal to y, if (x, y) is in the relation, then (y, x) is not in the relation. In the case of the relation "is married to," if John is married to Mary, it is not possible for Mary to be married to John. Therefore, the relation is antisymmetric.

In summary, the relation "is married to" is reflexive, while the relation "is not married to" is irreflexive. Neither relation is symmetric, asymmetric, or antisymmetric.

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The radius of the cylinder with uncertainty is found to be 0.488 ± 0.01 cm. This can be understood by propagation of errors.

Volume of the cylinder, V = 15.0 ± 0.5 cm³

Length of the cylinder, L = 20 ± 0.1 cm.

Circular cross-section radius, r =?

We know, Volume of the cylinder = πr²L

`V=π r²L`

r²= V/(πL)

Taking the square root of both the sides, `r = √(V/(πL))`

Let's calculate the uncertainty of the radius,

`r = √(V/(πL))` = √15/(π×20) = 0.488 cm

`Δ(r)/r = 1/2 × [Δ(V)/V + Δ(L)/L]`

`Δ(r) = r/2 × [Δ(V)/V + Δ(L)/L]`

Substitute the values of V, L, and Δ(V) and Δ(L)

`Δ(r) = r/2 × [0.5/15 + 0.1/20]`=`r/2 × (0.033 + 0.005)`=`r/2 × 0.038`=`0.019r`

Now substitute the value of r,

`Δ(r) = 0.019 × 0.488 = 0.0092 ≈ 0.01` (rounded to 2 significant figures)Therefore, the radius of the cylinder with uncertainty is `0.488 ± 0.01 cm`.

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Answer:

V = E * d    

E = (200 J/C) / .024 m =   8330 J / C-m  

1/2 m v^2 = V q      potential energy of electron

v^2 = 2 * 200 J/C * 1.6E-19 C / 9.11 E-31 kg

v^2 = 400 * 1.6E-19 / 9.11 E-31   N-m  / kg

v = 8.4E6 m/s

The winds aloft chart for the Great Lakes (Michigan is fine) region displays the wind direction and speed at several altitudes. At 3000 feet, the wind speed is approximately 17 knots.

At 12,000 feet, the wind speed is about 44 knots. The wind speed at FL350 is approximately 67 knots.Surface friction has an effect on the winds close to the ground, slowing them down due to the frictional force exerted on the ground by air molecules. The winds shift direction with altitude, veering to the right of the direction of travel in the northern hemisphere. The approximate location of the Jetstream can be obtained by examining the wind/temperature plot chart. The fastest wind speed at FL360 appears to be approximately 145 knots, traveling towards the northeast. Flight to the east or southeast would benefit from this wind speed.Seasonally, winds aloft change depending on the position of the jet stream, which moves towards the poles during the summer months and towards the equator during the winter months.

The current surface analysis chart (Prog chart) shows the major frontal activity passing through the Midwest states. Precipitation is what leads the frontal passage in general, with both temperature and wind speed/direction changing from behind to ahead of the front.

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Answer:

If you hear thunder and then see lightning at almost the same time, this means that the lightning was likely close by. Thunder is the sound created by lightning, which is the discharge of energy between two clouds or between a cloud and the ground. Because sound travels much slower than light, it takes longer for the thunder to be heard, which is why we usually hear thunder after seeing a flash of lightning. This indicates that the lightning was very close in proximity and that you should be aware of the potential danger of an impending thunderstorm.

Answer:

La materia y energía interactúa entre sí de forma continua. De hecho, la materia estaría en un estado estático de forma estable si no fuera por la energía. De esta forma, materia y energía están interactuando entre sí constantemente, donde la materia sería el sujeto pasivo que padece la acción de la energía, mientras que la energía sería el sujeto activo que modificaría el estado de reposo o movimiento de la materia.

Explanation:

Answer:

The moon rotates around the earth but the earth revolves around its own axis

Explanation:

A.) The speed of Tarzan at the bottom of the swing when he starts from rest is 10.8 m/s.

B.) The speed of Tarzan at the bottom of the swing when he starts with 4 m/s is 11.6 m/s.

Let us solve this problem using law of conservation of energy. The kinetic energy at the bottom of the swing will be equal to the gravitational potential energy at the start of the motion.

U = K

m g h = 1/2 m v²

where,

m is Tarzan's mass

g is acceleration due to gravity

h is initial height

Tarzan's speed at the bottom is v

Re-arranging the equation for making v as subject, we have

v = √ (2 g h + u²)

Initial velocity u = 0.

Therefore, we must determine h, Tarzan's starting height. We know that the length of the swing is L= 30 m and it is initially inclined at θ = 37° with respect to the vertical, so the initial height of Tarzan is given by

h = L - L cosθ = L(1 - cosθ) = 30 ×(1 - cos 37 ) = 6 m

Tarzan's speed, then, at the swing's bottom is

v = √ ( 2 × 9.8 × 6) = 10.8 m/s

B.) If u = 4 m/s,

v = √ 2 g h + u² = √ [2 g L(1 - cosθ) + u²] = √ [ 2 × 9.81× 30 × (1 - cos 37 ) + 4²] = 11.6 m/s

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To determine the first date when Copernicus will be lit up by the sun and show good shadow detail, we need to consider the position of the sun and its relationship with Copernicus.

Copernicus is a lunar impact crater located on the Moon's surface. It receives sunlight when the angle between the sun, Copernicus, and the observer on Earth is appropriate.

To find this date, we can use an astronomical software or website that provides lunar data. One such resource is the NASA Moon Phases website. By entering the date of 3/5/2022 and selecting the 7th hour (7:00 UT), we can obtain the moon phase information for that time.

Checking the data, we observe that on this specific date, the moon is in the first quarter phase. During the first quarter, Copernicus is not in direct sunlight and thus would not show good shadow detail. Therefore, the first date when Copernicus will be lit up by the sun and show good shadow detail will be a different date.


To determine the first date when Copernicus will be lit up by the sun and show good shadow detail, we need to consider the position of the sun and its relationship with Copernicus. Copernicus is a lunar impact crater located on the Moon's surface. It receives sunlight when the angle between the sun, Copernicus, and the observer on Earth is appropriate.

To find this date, we can use an astronomical software or website that provides lunar data. One such resource is the NASA Moon Phases website. By entering the date of 3/5/2022 and selecting the 7th hour (7:00 UT), we can obtain the moon phase information for that time.

Checking the data, we observe that on this specific date, the moon is in the first quarter phase. During the first quarter, only half of the moon's face is illuminated, and Copernicus is not in direct sunlight. As a result, it would not show good shadow detail. Therefore, the first date when Copernicus will be lit up by the sun and show good shadow detail will be a different date.

To find the specific date, we can use the same resource and check the moon phase for each day. We will be looking for a phase where the moon is approaching the full moon phase. During the days leading up to the full moon, the sun's angle with respect to Copernicus will increase, resulting in better illumination and shadow detail.

For example, if we find that the full moon occurs on 3/15/2022, we can conclude that the first date when Copernicus will be lit up by the sun and show good shadow detail is likely to be around 3/13/2022 or 3/14/2022. However, the specific date will depend on the precise angles and positions of the sun, Earth, and the moon during that time.

To determine the first date when Copernicus will be lit up by the sun and show good shadow detail, we need to consider the moon phase and its relationship with the sun and Earth. By using astronomical resources like the NASA Moon Phases website, we can find the date when the moon is approaching the full moon phase, indicating better illumination and shadow detail for Copernicus.

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Answer:

4 ohms

Explanation:

Current = Voltage/resistance

2 = 8/R

2R = 8

R = 4

Answer:

B

Explanation:

The speed of the plane and pilot before the pilot jumps is 17.8 m/s.

We know that the principle of conservation of linear momentum states that the total momentum of a system is constant. This means that the momentum "before" and "after" must be equal.

Thus;

Momentum before = (114 Kg + 60.0 kg) v

Momentum after = (60.0 kg × -5.32 m/s) + (114 Kg × 3.40 m/s)

Hence;

(114 Kg + 60.0 kg) v = 3100.8

v = 3100.8/(114 + 60.0)

v = 17.8 m/s

The speed of the plane and pilot before the pilot jumps is 17.8 m/s.

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Answer:

The correct answer is Positive

Explanation:

Put the word POSITIVE

Answer:

8/9 parts

Explanation:

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The work per unit mass done by the piston is 300 \(\frac{kJ}{kg}\).

At state 1 for steam

\(P_{1}\)= 101. 325 kpa

\(T_{1}\)= 400K = 127 °C

Now, see from the property table

\(u_{1}\)= 2550 \(\frac{kJ}{kg}\)

Now, at State 2

\(P_{2}=101.325\times 4=405.3\)kpa

\(T_{2}\)=600K= 327 °C

Now, see from the property table

\(u_{2}\)=2850 \(\frac{kJ}{kg}\)

Now, the work done is W which is given by

The definition of work done includes both the forces applied to the body and the total displacement of the body.

A constant force F is present before to this block. The goal of this force is to move the body d meters in a straight line in the force's direction.

W=\(u_{2}-u_{1}\)

W=2850-2550

W=300 \(\frac{kJ}{kg}\)

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The strength of the magnetic field at the centrer of coil is calculated to be 1.97× 10⁻⁷ Tesla

A magnetic field is a vector field that explains the magnetic impact on moving charges, currents, and magnetic materials. A moving charge in a magnetic field is subjected to a force that is perpendicular to both its own velocity and the magnetic field.

We know that for a circular wire the magnetic field at the center is given by

B= μI/2r

Here, μ= 4π×10⁻⁷

I= current flowing= 0.15A

r= radius of the circular wire

In the given question the wire of length 3m is bent into a circular coil of one turn.

So, the circumference of coil will be equal to the length of the coil.

Length= circumference= 2πr

2πr= 3m        (π≅3.14)

r=  \(\frac{3}{2* 3.14}\)= 0.477 m

Now putting the value of r= 0.477 m in magnetic field formula we get

B= \(\frac{4\pi }{2* 0.477}\)×10⁻⁷

B= 1.97× 10⁻⁷ Tesla

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The car will move fast with the velocity of 32.03 m/s

Calculation

Initial velocity(u) = 5.9 m/s

Distance traveled = 3.3 km = 3300 m

Time = 2.9 min = 2.9×60 = 174 seconds

Formula,

\(s=\frac{1}{2} (u+v)t\)

\(3300=\frac{1}{2} (5.9+v)*174\)

\(v= (\frac{6600}{174} -5.9)m/s\)

v = 37.93–5.9 = 32.03 m/s

Hence, the car will move fast with velocity = 32.03 m/s

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1H81Br at 382 K, the values of Erot/kBT for J = 5, 10, and 20 are 2.47, 9.88, and 39.71, respectively.

To calculate the rotational energy of a diatomic molecule, the following equation can be used:

E_rot = J(J+1) * h^2 / (8 * pi^2 * I)

where J is the quantum number, h is Planck's constant, pi is the mathematical constant pi, and I is the moment of inertia of the molecule. The moment of inertia can be calculated using the following equation:

I = mu * r^2

where mu is the reduced mass of the molecule and r is the bond length.

The quantity Erot/kBT represents the rotational energy of the molecule relative to the thermal energy of the molecule at a given temperature. This can be calculated using the following equation:

Erot/kBT = E_rot / (k_B * T)

where k_B is the Boltzmann constant and T is the temperature in Kelvin.

Given that the bond length of 1H81Br is 141.4 pm, we can calculate the reduced mass of the molecule as follows:

mu = m1 * m2 / (m1 + m2)

where m1 and m2 are the masses of hydrogen and bromine, respectively. The atomic masses of hydrogen and bromine are approximately 1.008 u and 79.904 u, respectively. Converting these values to kilograms and using the above formula, we get:

mu = 1.008 * 79.904 / (1.008 + 79.904) * 1.66054 * 10^-27 kg/u = 1.629 * 10^-26 kg

Using the bond length and reduced mass, we can calculate the moment of inertia of the molecule as follows:

I = mu * r^2 = 1.629 * 10^-26 kg * (141.4 pm / 100 pm)^2 * (1 m / 10^12 pm)^2 = 1.131 * 10^-46 kg m^2

For J = 5, plugging in the values into the equation for rotational energy, we get:

E_rot = 5(5+1) * h^2 / (8 * pi^2 * 1.131 * 10^-46 kg m^2) = 1.270 * 10^-20 J

Plugging in this value and the temperature into the equation for Erot/kBT, we get:

Erot/kBT = (1.270 * 10^-20 J) / (1.38 * 10^-23 J/K * 382 K) = 2.47

For J = 10, using the same process, we get:

E_rot = 10(10+1) * h^2 / (8 * pi^2 * 1.131 * 10^-46 kg m^2) = 5.079 * 10^-20 J

Erot/kBT = (5.079 * 10^-20 J) / (1.38 * 10^-23 J/K * 382 K) = 9.88

For J = 20:

E_rot = 20(20+1) * h^2 / (8 * pi^2 * 1.131 * 10^-46 kg m^2) = 2.032 * 10^-19 J

Erot/kBT = (2.032 * 10^-19 J) / (1.38 * 10^-23 J/K * 382 K) = 39.71

Therefore, for 1H81Br at 382 K, the values of Erot/kBT for J = 5, 10, and 20 are 2.47, 9.88, and 39.71, respectively.

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The velocity of the second ball that was hit by a ball of mass 2.5 kg moving with an initial velocity of 5 m/s is 5 m/s.

Velocity can be defined as the rate of change of displacement.

To calculate the velocity of the second ball after collision, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for V

Hence, the velocity of the second ball is 5 m/s.

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70 N force will the ball apply to a car if it hits a parked car at the bottom of the hill.

Push or pull on an object is called force and is unit is kg/ms⁻² or newton and is shown as N.

Force, F = ma

m = mass of an object, given = 10 kg

a = acceleration of an object, given = 7 ms⁻²

Put these values in the formula, F = ma

F = 10 × 7

F = 70 N

Hence, 70 N force will the ball apply to a car if it hits a parked car at the bottom of the hill.

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Answer:

E = h ν = h c / λ

E = (6.63E-34 J-s * 3.00E8 m/s) / 757.7E-9 m

E = 2.62E-19 J

Note 1 eV = 1.60E-19 J

ν = c / λ = 3.00E8 / 110.9E-9 = 2.71E15 / sec

How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Substituting the given values, we get: E = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(757.7 x 10^-9 m)E = 2.61 x 10^-19 JTherefore, the energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. What is the frequency (in Hz) of light that has a wavelength of 110.9 nm  The frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. The frequency of light is given by the formula:f = c/λwhere f is the frequency, c is the speed of light, and λ is the wavelength of the light.

Substituting the given values, we get:f = (3.00 x 10^8 m/s)/(110.9 x 10^-9 m)f = 2.70 x 10^15 Hz Therefore, the frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

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Answer:

i. + 22.5 m ii. 4.0 m

Explanation:

i. Image distance

Using the lens formula

1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown

So, we find v

1/v = 1/f - 1/u

= 1/+18 - 1/+90

= (5 - 1)/90

= 4/90

v = 90/4

= + 22.5 m

So the image is real and formed 22.5 m away on the other side of the lens.

ii Length of Shark

Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.

m = image distance/object distance

= v/u

= +22.5/+90

= 0.25

0.25 = image height/object height

So,

object height = image height/0.25

= 1.0 m/0.25

= 4.0 m

So, the length of the shark is 4.0 m

Answer:

the words

Explanation:

Answer:

Pressing the brake pedal

Explanation:

Decelerate sounds a lot like the word accelerate, but we know that the speed is decreasing, so it would have to be going down, getting slower, so whichever sounds like a good example of speed decreasing should be a good answer!

The measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

Option C.

The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.

To find the median: Arrange the data points from smallest to largest. If the number of data points is odd, the median is the middle data point in the list.

So from the given data of the 100 meter dash, the measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

The median will help to separate half of the data points that are smaller than the cutoff time and half of the data points are larger than the cutoff time.

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