Answer:
T₁ = 418.9 k = 145.9° C
T₂ = 167.6 k = - 105.4° C
W = - 522 KJ
Here negative sign indicates that work is being done on the gas.
Explanation:
For the temperature of Helium, we use the general gas equation:
PV = mRT
For initial state:
PV₁ = mRT₁ (Constant Pressure)
where,
P = constant pressure = 174 KPa
V₁ = Initial Volume = 5 m³
m = mass = 1 kg
R = Gas Constant of Helium = 2.0769 KJ/kg.k
T₁ = initial temperature of helium = ?
Therefore,
(174 KPa)(5 m³) = (1 kg)(2.0769 KJ/kg.k)T₁
T₁ = (870 KJ)/(2.0769 KJ/k)
T₁ = 418.9 k = 145.9° C
For final state:
PV₂ = mRT₂ (Constant Pressure)
where,
P = constant pressure = 174 KPa
V₂ = Final Volume = 2 m³
m = mass = 1 kg
R = Gas Constant of Helium = 2.0769 KJ/kg.k
T₂ = Final temperature of helium = ?
Therefore,
(174 KPa)(2 m³) = (1 kg)(2.0769 KJ/kg.k)T₂
T₂ = (348 KJ)/(2.0769 KJ/k)
T₂ = 167.6 k = - 105.4° C
The work done on a gas in a constant pressure process (isobaric) is given as:
W = P(V₂ - V₁)
W = (174 KPa)(5 m³ - 2 m³)
W = - 522 KJ
Here negative sign indicates that work is being done on the gas.
How is the A He related to the A Hof a reaction?
Answer:
by giving a person to person
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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The principle of cross-cutting relationships states that certain features, such as faults, are than the rock layers they cut through. These features are breaks in Earth’s surface where rock has moved sideways, upward, or downward. formations are made of molten rock that has cooled. Those on Earth’s surface are called . Those beneath Earth’s surface are called .
______________________________
A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.
N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________
A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.
In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²
according to kinematics,
s = ut + 1/2 at²
s = 1/2 ×9.8×3.4²
s = 56.6 m
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If a 1.5-Kg physics book measures 0.260 m x 0.210 m x 0.040 m, calculate the pressure applied by the standing book on the table. (Round off answer to two sig figs)
*
Answer choices:
P = 1,600 N/m^2
P = 1,800 N/m^2
P = 1,500 N/m^2
P = 1,700 N/m^2
The pressure applied by the standing book on the table is 1,800 N/m².
option B is the correct answer.
What is the pressure applied by the book?
The pressure applied by the standing book on the table is determined from the ratio of weight of the book and the area of the standing book.
Mathematically, the formula for the pressure of a material is given as;
P = F / A
where;
F is the applied force or weight of the object standing on another surfaceA is the area of the object in contact with another surfaceThe weight of the book , F = mg
where;
m is the mass of the bookg is acceleration due to gravityF = 1.5 kg x 9.8 m/s²
F = 14.7 N
The dimension of the book include;
height of the book, h = 0.26 mwidth of the book, w = 0.21 mthickness of the book, b = 0.04 mThe height of the book is not in contact with the surface of the table, so the area of the book in contact with the table becomes;
A = w x b
W = 0.21 m x 0.04 m
W = 8.4 X 10⁻³ m²
P = F / A
P = ( 14.7 N ) / ( 8.4 X 10⁻³ m² )
P = 1,750 N/m² ≈ 1,800 N/m²
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what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k
The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.
To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:
C = A × B
Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.
Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:
C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)
Now, let's expand the cross product using the properties of vector products:
C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +
(3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +
(1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)
Now, let's calculate each of these cross products:
C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +
(3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +
(1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)
Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:
C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k
Combining like terms, we get:
C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)
Simplifying further:
C = 6.00i - 12.00j + k
Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.
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The vector product of A and B is -3i - 5j - 9k.
Explanation:The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.
In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.
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a 0.2 kg vase has a potential energy of 100j
The height above the ground in which the vase is raised is 51.02 m.
What is the height of the vase?
The height above the ground in which the vase is raised is calculated by applying the formula for gravitational potential energy.
Gravitational potential energy of an object is the energy possessed by the object due to the object's position above the ground.
Mathematically, the formula for gravitational potential energy is given as;
P.E = mgh
where;
m is the mass of the objectg is acceleration due to gravityh is the height above the ground in which the object is raisedThe given parameters include;
mass of the vase = 0.2 kg
potential energy of the vase = 100 J
acceleration due to gravity = 9.8 m/s²
h = P.E / mg
h = (100) / (0.2 x 9.8)
h = 51.02 m
Thus, the height of the vase is a function of the potential energy and mass of the vase.
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The complete question is below:
a 0.2 kg vase has a potential energy of 100j. What is the height of the vase?
A person driving a car suddenly applies the brakes. The car takes four seconds to come to rest while traveling 20 m at constant acceleration.Can the speed of the car immediately before the brakes are applied be determined without first determining the car’s acceleration?a. Yes, by dividing the distance (20m) by the time (4s).b. Yes, by determining the average speed while braking and doubling it. c. No, because the acceleration is needed to use equations such as change in position=initial velocity + 1/2 acceleration • time^2d. No, because the fundamental relationship that defines velocity contains acceleration. Explain why choice A is wrong.Explain why the correct choice is correct. Use words like “average speed (or velocity)”, “initial speed (or velocity)”, “final speed (or velocity)”, “total distance”, and “total time.” Refer to appropriate basic motion equations.
ANSWER:
b. Yes, by determining the average speed while braking and doubling it.
STEP-BY-STEP EXPLANATION:
Option A is not correct because both speeds, the final and the initial, are not taken into account.
To determine the correct answer, the first thing to do is to do it mathematically. Just like this:
\(\begin{gathered} v=u+at\rightarrow a=\frac{v-u}{t} \\ \\ s=ut+\frac{1}{2}at^2 \end{gathered}\)We replacing
\(\begin{gathered} s=ut+\frac{1}{2}(\frac{v-u}{t})t^2 \\ \\ s=ut+\frac{1}{2}vt-\frac{1}{2}ut \\ \\ s=\frac{1}{2}t(u+v) \\ \\ v=0 \\ \\ s=\frac{1}{2}tu\rightarrow u=\frac{2s}{t} \end{gathered}\)The average speed, that is, the average between the initial speed and the final speed, is determined since the final speed is 0, because it ends up braking. We can calculate the initial start since we know the total braking time (4 seconds) and the total distance we also know to be 20 meters, using the previous equations.
Therefore, the correct answer is: b. Yes, by determining the average speed while braking and doubling it.
A particle with mass 3×10−2 kg
k
g
and charge +3 μC
μ
C
enters a region of space where there is a magnetic field of 1 T
T
that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 12 m/s2
m
/
s
2
. What is the speed of the particle when it enters the magnetic-field region?
The speed of the particle when it enters the magnetic-field region is 120,000 m/s.
Speed of the particle
Magnetic force on the particle is given as;
F = qvB
where;
q is magnitude of the chargev is speed of the particleB is magnetic field strengthFrom Newton's second law, force on an object is given as;
F = ma
where;
m is mass of the particlea is accelerationma = qvB
v = ma/qB
v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)
v = 120,000 m/s
Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.
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cheese is made of cheese
Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.
What is a dairy product?
Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.
Hence, cheese is made up of casein proteins that are present in the milk.
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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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Construct a graph of position versus time for the motion of a dog, using the data in the table below. Explain how the graph indicates that the dog is moving at a constant speed.
Answer:
The dog is moving at a constant speed
Explanation:
Given that,
Position : 5, 10, 15, 20, 25
Time = 5. 10, 15, 20, 25
We need to draw a position time graph
Using given data
A graph of position and time shows the speed.
According to graph,
The graph indicates that the dog is moving at a constant speed because the graph is straight line.
Hence, The dog is moving at a constant speed
A ball is moving up a hill at 20 meters per second, and is decelerating at a uniform rate of 2 meters per second squared. What is its velocity after 5 seconds? Assume the direction up the hill is positive.
Answer:
-12meters per secondExplanation:
2^5=32-20=-12 meters per sec (going backwards).
If this is correct pls mark me. brainly to let me know, tyy C:
A beam of electrons with a speed of is incident on a slit of width 200. nm. The distance to the detector plane is chosen such that the distance between the central maximum of the diffraction pattern and the first diffraction minimum is 0.300 cm. How far is the detector plane from the slit?
Answer:
L =( 5.17 10⁻⁶ v) m
Explanation:
This is a diffraction exercise, which is described by the equation
a sin θ = n λ
where a is the width of the slit a = 200 nm = 200 10⁻⁹ m, n is the order of diffraction n = 1 and lan the wavelength in this case we use the DeBroglie relation to find the wavelength
λ = h´ / p = h´ / mv
with h´ = h / 2π
let's use trigonometry for distance,
sin θ = y / L
tan θ = sin θ / cos θ
since these experiments the angle is very small, we approximate
tan θ = sin θ = y / L
we substitute
a y / L = n λ
L = a y / n λ
L = a y 2π mv / n h
we calculate
L = 200 10⁻⁹ 0.300 10⁻² 2π 9.1 10⁻³¹ v / (1 6.63 10⁻³⁴)
L = 517.44 10⁻⁸ v m
L =( 5.17 10⁻⁶ v) m
for a specific value we must know the speed of the electrons
The density of blood is 2kg/m.convert to g/cm
Explanation:
if we convert it into g/cm it'll be
2000 grams
relationship between angular acceleration and. angle
A friend of yours who is traveling the world reports that she recently experienced a day on which the surface wind blew from the southeast while simultaneously the clouds overhead were moving from east to west. Independently, she is made aware of the fact that on that day the PGF was the same at the surface and at the cloud height. What hemisphere was she in at the time
Answer:
At that time, she was in the southern hemisphere
Explanation:
She is witnessing the southeastern trade breeze because the cloud is passing from east to west and she is also witnessing a storm from the southeast.
Because of the Coriolis effect, which deviates the atmosphere in the left-hand side of the southern hemisphere and generates a southeastern wind, this wind did not blow directly from south to east.
A racecar going around a circular track of radius r begins at rest and then accelerates with a constant linear acceleration a. Find how long it takes the car to complete one full lap around the track.
You inject your patient with 2.5-mL of medicine. If the inside diameter of the 31-gauge needle is 0.114 mm and the
injection lasts 0.90 s.
1) Determine the speed of the fluid as it leaves the needle. (Express your answer to two significant figures.)
Answer:
270 m/s
Explanation:
The cylinder of medicine has to exit in .9s
Find 'height' of the fluid cyinder pi r^2 h = 2.5 cc
2.5 cc = .0000025 m^3
.114 mm = .000114 m radius = .000057 m
pi (.000057)^2 h = .0000025
solve for h = 244.9 meters
in .9 s
=~ 270 m/s ( Yikes.....seems correct though)
Q12. How big is a Moon? How big is a Mars? What is therefore the weight of the person from Q11 on the Moon? What is the person's weight on Mars?
Answer:
The moon is 1,079.4 mi.
Mars is 2,106.1 mi
Multiply your weight by the moon's gravity relative to earth's, which is 0.165. Solve the equation. In the example, you would obtain the product 22.28 lbs. So a person weighing 135 pounds on Earth would weigh just over 22 pounds on the moon
Being that Mars has a gravitational force of 3.711m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on mars. So an object or person on Mars would weigh 37.83% its weight on earth.
Explanation:
~Hope this helps
A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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Why is physics used to study the heat absorbed by the ocean?
A. The ocean is important.
B. Heat is a form of energy.
C. The Sun gives off heat.
D. Physicists mostly study the ocean.
Answer:
B
Explanation:
It absorbs gases, but also heat energy from the atmosphere, distributes them in its depths and thus slows down changes in the entire Earth system. The amount of energy absorbed by the ocean is therefore also an indication of the total heat absorbed by the planet.
Answer:B
Explanation:
When you throw a ball into the air, its kinetic energy _
Answer:
increases
Explanation:
The ball's kinetic energy is the energy it has due to its motion. When you throw the ball into the air, it gains kinetic energy from the force of your throw.
Multiple Choice: Suppose the electric field is zero in a certain region of space. Which of the following statements best describes the electric potential in this region?
a) The electric potential is zero everywhere in this region.
b) The electric potential is zero at least one point in this region.
c) The electric potential is constant everywhere in this region.
d) There is not enough information given to distinguish which of the above answers is correct.
The correct option is C, as in a region where electric field is zero, electric potential is constant and independent region location.
Electric potential, also known as voltage, is a fundamental concept in physics and electrical engineering. It is a measure of the electrical potential energy per unit of charge that a point in an electric field possesses. Electric potential is defined as the work done per unit charge in moving a test charge from an infinitely far distance to a specific point in the electric field.
Electric potential plays a crucial role in understanding the behavior of electric fields and the flow of electric currents. It determines the direction and magnitude of electric currents, and it is essential for designing and analyzing various electrical systems and devices, such as generators, motors, and electronic circuits. Electric potential is a measure of the energy per unit charge in an electric field and is essential for understanding and designing electrical systems and devices.
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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?
Answer in kg
The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:
τ = r * F * sin(θ)
where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.
In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.
Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:
τ_M = r_M * F_M * sin(θ)
where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.
Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:
τ_M = τ_stick
r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)
Substituting the given values:
30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)
Solving for F_M:
F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)
F_M = 0.0264 kg * 9.8 m/s^2
F_M = 0.25872 N
Finally, we can convert the force into mass using the formula:
F = m * g
0.25872 N = M * 9.8 m/s^2
M = 0.0264 kg
Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
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What happens to balls dropped on opposite sides of earth
Answer:
It reaches its top speed at the very center of the globe and continues rocketing toward the other side
Explanation:
So what happens? Well, as the ball drops through the hole it picks up speed - that's the acceleration due to gravity. It reaches its top speed at the very center of the globe and continues rocketing toward the other side.
Find the Magnitude of the resultant vector (the actual
path of the boat).
The picture is a little blurry, so here are the stats:
Velocity of the boat is 0.75 m/s
Velocity of the river is 1.2 m/s
The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.
To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.
Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.
To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:
Resultant magnitude = √(boat velocity^2 + river velocity^2)
Plugging in the given values, we have:
Resultant magnitude = √(0.75^2 + 1.2^2)
= √(0.5625 + 1.44)
= √2.0025
≈ 1.42 m/s
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An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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When you stand on a bathroom scale, the scale does not measure the force of gravity (i.e., weight) acting upon your mass. What does the scale measure?
The scale reading is actually a measure of the upward force applied by the scale to balance the downward force of gravity acting upon an object
What is a bathroom scale ?Scales measure weight, which is the force acting on a mass equal to the mass times the acceleration of gravity of the object. Due to the dependence of the weighing mechanism and the weight of any given object on the local gravity, a scale cannot accurately determine mass.
Although we use a scale to determine how much we weigh, the scale reading actually represents the upward force the scale applies to an object to counteract the downward force of gravity. These two forces are balanced when an object is in an equilibrium condition (whether it is at rest or moving at a constant speed).
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To increase the energy of an electromagnetic wave, which property should
you increase?
A. Shift
B. Frequency
o
C. Wavelength
D. Speed
Answer:
B. Frequency
Explanation: