Thermal energy at room temperature is about 25 meV.You're designing an electronic device to operate at room temperature, and you want the kinetic energy associated with the uncertainty principle not to exceed the thermal energy. What's the minimum width in which your device can confine an electron?

Answers

Answer 1

The minimum width in which your device can confine an electron to ensure that the kinetic energy associated with the uncertainty principle does not exceed the thermal energy at room temperature is approximately 1.86 nanometers.

To determine the minimum width in which your device can confine an electron, we can make use of the Heisenberg uncertainty principle. The uncertainty principle states that there is a fundamental limit to the precision with which certain pairs of physical properties of a particle, such as position and momentum, can be known simultaneously.

In the case of confinement of an electron, we are interested in the uncertainty in position and momentum. The uncertainty principle can be written as:

Δx * Δp ≥ h/4π

Where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is the reduced Planck's constant (approximately 6.626 × 10^(-34) J·s).

We can relate momentum to kinetic energy using the equation:

p = sqrt(2mE)

Where p is momentum, m is the mass of the electron (approximately 9.10938356 × 10^(-31) kg), and E is the kinetic energy.

Since we want the kinetic energy associated with the uncertainty principle not to exceed the thermal energy (25 meV), we can equate the two:

Δp = sqrt(2mE) = sqrt(2m * 25 * 10^(-3) eV)

Now, we can rearrange the uncertainty principle equation to solve for the minimum width (Δx):

Δx = h/(4πΔp)

Substituting the value of Δp, we can calculate the minimum width:

Δx = h/(4π * sqrt(2m * 25 * 10^(-3) eV))

Plugging in the values and performing the calculation:

Δx = (6.626 × 10^(-34) J·s)/(4π * sqrt(2 * 9.10938356 × 10^(-31) kg * 25 * 10^(-3) eV))

Δx ≈ 1.86 × 10^(-9) meters

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Related Questions

If velocity of the car is given as v(t)= 10+3t+512. Determine the acceleration at t=2s.

Answers

Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

\(\begin{gathered} a(t)=\frac{d}{dt}(v(t)) \\ =\frac{d}{dt}(10+3t+512) \\ =3m/s^2 \end{gathered}\)

Thus, the acceleration of the car at t = 2 s is 3 m/s^2

34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again. ​

Answers

Answer and Explaination:

To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.

1. Gravitational force:

The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.

2. Force exerted by the spring:

The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Given:

Mass (m) = 5.0 kg

Compression of the spring (x) = 20.0 cm = 0.20 m

Angle of the inclined plane (θ) = 30°

First, let's find the force exerted by the spring (F_spring):

F_spring = -kx

To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.

Next, let's calculate the gravitational force components:

Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ

Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ

Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.

At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).

Therefore, we have:

F_perpendicular = F_spring

mg * cosθ = -kx

Now, let's substitute the known values and solve for k:

(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m

49.0 N * 0.866 = -k * 0.20 m

42.426 N = -0.20 k

k = -42.426 N / (-0.20 m)

k = 212.13 N/m

Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:

PE_spring = (1/2) * k * x^2

PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2

PE_spring = 4.243 J

The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.

KE_max = PE_spring = 4.243 J

Next, we can calculate the height (h) the mass reaches on the inclined plane:

KE_max = m * g * h

4.243 J = 5.0 kg * 9.8 m/s^2 * h

h = 4.243 J / (5.0 kg * 9.8 m/s^2)

h = 0.086 m

The height the mass reaches on the inclined plane is 0.086 m.

Now, we can calculate the distance traveled.

A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.

Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.

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c. is what percent of 125?​

Answers

Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

Four capacitors with capacitance 3.0 pF, 2.0 pF, 5.0 pF and X pF are connected in series to each other. If the equivalent capacitance of the circuit is 0.83 pF, what is the value of the X capacitor? (A). 6.0 pF (B). 5.0 pF (C). 3.0 pF (D). 2.0 pF (E). 0.83 pF

Answers

Answer:

A. 6pF

Explanation:

If unknown capacitance C1, C2, C3 and C4 are connected in series to one another, their equivalent capacitance of the circuit will be expressed as shown

\(\frac{1}{C_t} = \frac{1}{C_1} +\frac{1}{C_2} +\frac{1}{C_3} +\frac{1}{C_4} \\\)

Given the capacitance's 3.0 pF, 2.0 pF, 5.0 pF and X pF connected in series to each other. If the equivalent capacitance of the circuit is 0.83 pF, then to get X, we will apply the formula above;

\(\frac{1}{0.83} = \frac{1}{3.0} +\frac{1}{2.0} +\frac{1}{5.0} +\frac{1}{C_4} \\\\\\1.205 = 0.333+0.5+0.2+\frac{1}{C_4} \\\\1.205 = 1.033 + \frac{1}{C_4} \\\\\frac{1}{C_4} = 1.205-1.033\\\\\frac{1}{C_4} = 0.172\\\\C_4 = \frac{1}{0.172}\\ \\C_4 = 5.8pF\\\\\)

C₄ ≈ 6pF

Hence the value of the X capacitor is approximately 6pF

PLEASE HELP!!

To conclude, how would you explain
electromagnetic induction to a 5 year old?
words to include: magnets, electricity, and
change.

Answers

Answer:

fgdyauqushxhxxgxggxgxgxgsgsysysy

sysydyydydysysysysyxhxyt56fys7w727ueudu

The following equation shows the position of a particle in time t, x=at²i + btj where t is in second and x is in meter. A=2m/s², b=1m/s. Find
A, the average velocity of the particle in the time interval t₁=2sec and t₂=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)​

Answers

The average velocity is 4i m/sec ,  the average acceleration is 4i

What is a Vector ?

A vector is an object that has both magnitude and direction.

It is given that

x=at²i + btj

where t is in second and x is in meter.

The average velocity is given by dx/dt

dx/dt = 2at i + b j

dx/dt = 2 * 2 * t i +1 j

dx/dt = 4t i +j

dx/dt in the time interval of 2 to 3 sec is

at 2 sec,

dx/dt = 4 * 2 i +j = 8i +j

at 3 sec ,

dx/dt = 4 * 3 i + j = 12i+j

Therefore the average velocity is

(12i +j - 8i -j)/ (3-2) = 4i

The velocity at any given time is dx/dt = 4t i +j

The acceleration at any given time is d²x/dt²

d²x/dt² = 4 i

the average acceleration in the time interval  t₁=2sec and t₂=3sec

Average Acceleration =  4i

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Which two components must a vector quantity
have?
a. Magnitude and velocity
b. Acceleration and direction
c. Force and speed
d. Direction and magnitude

Answers

Answer:

d. Direction and magnitude

Explanation:

The two components of a vector are its magnitude and direction.

Magnitude is the quantity of the substance

Direction is the path.

Other quantities are called scalar quantities. Scalar quantities have only magnitude but no direction.

Examples of vector quantities are velocity, displacement, acceleration.

How much force is needed accelerate a 35 kg sled from 30 m/s to 65 m/s in 0.4 seconds?

Answers

Answer:

F = 3062.5  N

Explanation:

Given that,

The mass of a sled, m = 35 kg

The speed increase from 30 m/s to 65 m/s in 0.4 seconds.

We need to find the force needed to accelerate the car.

Net force is given by :

F = ma

where

a is acceleration of the car.

\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{35\times (65-30)}{0.4}\\\\F=3062.5\ N\)

So, the net force is 3062.5  N.

A spring is resting vertically on a table. A small box is dropped onto the top of the spring and compresses it. Suppose the spring has a
spring constant of 300 N/m and the box has a mass of 1.9 kg. The speed of the box just before it makes contact with the spring is 0.39
m/s.
(a) Determine the magnitude of the spring's displacement at an instant when the acceleration of the box is zero.
(b) What is the magnitude of the spring's displacement when the spring is fully compressed?

Answers

(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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If the distance between two objects is cut in half, what happens to the
gravitational force between them?
A. It decreases to 1/2 its original magnitude.
B. It decreases to 1/4 its original magnitude.
O
C. It increases to 4 times its original magnitude.
D. It increases to 2 times its original magnitude.

Answers

C. Increase to 4 times its original magnitude

How the government can ensure basic human dignity is maintained in relation to safe and healthy living

Answers

To ensure basic human dignity in relation to safe and healthy living, governments can implement various measures such as accessible healthcare, adequate housing, and sanitation and clean water.

How government can ensure basic human dignity is maintained

Governments should place a high priority on ensuring that everyone has access to healthcare services, enabling them to receive the essential medical care without suffering financial difficulty. This entails providing access to necessary pharmaceuticals, cheap healthcare, and a strong healthcare system.

All citizens should have access to affordable and good housing, according to governments. Policies may include restrictions on rental costs, programs to expand the supply of affordable housing, and efforts to combat homelessness. Basic hygienic and safety criteria should be met by housing.

Governments must make sure that everyone has access to clean, safe drinking water and adequate sanitary facilities. The spread of diseases and the maintenance of sanitary living circumstances can be aided by investments in sewage systems, water treatment facilities, and public hygiene education.

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An objects position can be graphed as a function of time as seen on the right (Answer each question)

1. What is the net displacement of the object from t = 0s to t = 8s?


2. What is the initial velocity of the object?


3. What is the final velocity of the object?


4. What is the average velocity of the object from t = 0s to t = 8s?


5. How far does the object travel in the first 8 seconds?

An objects position can be graphed as a function of time as seen on the right (Answer each question)

Answers

The net displacement of the object from t = 0s to t = 8s is 2 m.

The initial velocity of the object is 1 m/s.

The  final velocity of the object is 0 m/s.

The average velocity of the object from t = 0s to t = 8s is 0.25 m/s.

The distance traveled by the object in the first 8 seconds is 6 m.

What is the displacement of the object?

The displacement of the object is the change in the position of the object.

d = Δx

d = x(0) = x(8)

d = 2 m - 0 m = 2m

Initial velocity of the object

v = x/t

v = 2m / 2 s

v = 1 m/s

Final velocity of the object

v = x/t

v = 0/8 s = 0 m/s

Average velocity of the object

v(avg) = Δx/Δt = 2 m/8 s = 0.25 m/s

Distance traveled by the object in the first 8 seconds

in the first 2 seconds = 2 m

in the first 6 seconds = 4 m

in the first 8 seconds = 2 m + 4 m + 0 = 6 m

Thus, the net displacement of the object from t = 0s to t = 8s is 2 m.

The initial velocity of the object is 1 m/s.

The  final velocity of the object is 0 m/s.

The average velocity of the object from t = 0s to t = 8s is 0.25 m/s.

The distance traveled by the object in the first 8 seconds is 6 m.

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How often does the World Cup happen?
Your answer

Answers

Answer:

every 4 years

Explanation:

Answer:

Every four years

Explanation:

What shows a major change form early settlements to complex societies?

Answers

Answer: Specialized skilled workers became obsolete as complex societies grew and traded with neighbors.

Explanation:

Which change(s) of state require an increase in energy?

Answers

Answer: Melting, evaporation and sublimation.

Melting, evaporation and sublimation require an increase in energy.

To determine the changes of state that require an increase in energy, we need to know about changes of state.

What are the changes of state of a substance?

Melting, evaporation and sublimation are the changes of state of a substance.

How do melting, evaporation and sublimation require an increase in energy?In melting process, substance goes from solid to liquid state. In evaporation state, it goes from liquid to vapour state and in sublimation, it goes from solid to vapour state.In each of the above case, the bonds between molecules of the substance  become weak due to getting of heat energy. And the heat energy is appeared as kinetic energy of the molecules.So the molecules vibrate rapidly which leads to the change of state.

Thus, we can conclude that melting, evaporation and sublimation require an increase in energy.

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What is the shape of a line graph that shows the temperature change over time of the liquid before it starts to boil.

Answers

The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.

In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.

This is because as heat is applied to the liquid, its temperature increases at a consistent rate.

During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.

Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.

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A thin rod extends from
x = 0
to
x = 15.0 cm.
It has a cross-sectional area
A = 8.00 cm2,
and its density increases uniformly in the positive x-direction from 2.50 g/cm3 at one endpoint to 19.5 g/cm3 at the other.
(a)
The density as a function of distance for the rod is given by
= B + Cx,
where B and C are constants. What are the values of B (in g/cm3) and C (in g/cm4)?
B =
g/cm3
C =
g/cm4
(b)
Finding the total mass of the rod requires integrating the density function over the entire length of the rod. The integral is written as follows.
m =


allmaterial
dv =


all x
A dx =
15.0 cm

0
(B + Cx)(8.00 cm2) dx
What is the total mass of the rod (in kg)?
kg

Answers

(a) For the density function, the value of B is 2.5 g/cm³   and the value of C is 1.3 g/cm⁴

(b) The total mass of the rod is 1470 g.

What is the density function?

The density of the rod is a function of distance and it is given as;

ρ = B + Cx

where;

B and C are constants

ρ = 2.5 g/cm³  +  (19.5 g/cm³ ) / ( 15 cm ) x

ρ = 2.5 g/cm³  +  1.3 g/cm⁴  x

The total mass of the rod is calculated by integrating the function;

dm = ( B + Cx)(8 cm² ) dx

m = 8B + 8Cx

m = 8Bx  +  8Cx² / 2

m = ( 8 x 2.5 x 15 )  +  ( 8 x 1.3 x 15² ) / 2

m = 1470 g

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Heat transfer by convection occurs when...

Answers

Answer:

Convection occurs when particles with a lot of heat energy in a liquid or gas move and take the place of particles with less heat energy.

Explanation:

Heat energy is transferred from hot places to cooler places by convection.

Find the final velocity if the initial velocity of 8 m/s with an acceleration of 7 m/s2 over a 3 second interval?

Answers

I don't know about it your answer will give another people

Answer: Let the final velocity be v.

Given,

Initial velocity(u)=8m/s

Acceleration(a)=7m/s2

Time(t)=3 sec

Then,

v=u+at

  =8+7*3 m/s

  =29m/s

Therefore, the final velocity is 29m/s.

What is the acceleration

Answers

Speed going faster or going slower from a constant speed

If you in a car and you slowing down to turn a corner your accelerating
But if your speeding up to make a light your also accelerating

It’s more common knowledge that going faster is acceleration but going slower is also accelerating
Hope this helps you :>
- Pam Pam

\({\tt{\red{\underline{\underline{\huge{Answer:}}}}}}\)

\(\longrightarrow\) The rate of change of velocity per unit time is called acceleration.

\(\longrightarrow\) Its SI unit is m/s².

\(\huge\boxed{\fcolorbox{blue}{red}{Thank you}} \)

Polaris has a fixed position in the sky as it lies directly over the celestial North Pole. Therefore, it is useful to be able to identify Polaris, to help you get your bearings. First identify the two stars in the Great Dipper that point to Polaris. Then identify the position of Polaris in this image of the night sky.

Polaris has a fixed position in the sky as it lies directly over the celestial North Pole. Therefore,

Answers

Answer:

Explanation:

Unfortunately, as an AI text-based model, I cannot directly view or interpret images. However, I can still provide you with the information you need to identify Polaris and its position in the night sky.

To locate Polaris using the stars of the Big Dipper (also known as the Great Dipper or Ursa Major), you can follow these steps:

1. Locate the Big Dipper: The Big Dipper is a prominent asterism, or a recognizable pattern of stars, within the constellation Ursa Major (the Great Bear). It is visible in the northern hemisphere during most of the year.

2. Identify the pointer stars: The two stars on the outer edge of the Big Dipper's bowl, farthest from the handle, are called the pointer stars. These stars are named Dubhe and Merak.

3. Extend the line between the pointer stars: Mentally extend an imaginary line that passes through Dubhe and Merak, extending it for approximately five times the distance between the pointer stars.

4. Locate Polaris: The extended line will lead you to Polaris, also known as the North Star. Polaris is relatively bright and appears as the last star in the handle of the Little Dipper (Ursa Minor constellation). It lies almost directly above the North Pole of the Earth and remains nearly fixed in the sky while other stars appear to rotate around it as the Earth rotates.

By following these steps, you should be able to identify Polaris and its position in the night sky, even without an image.

Final answer:

Polaris is positioned directly above the celestial North Pole in the sky, making it a useful navigation tool. The easiest way to locate it is by identifying the Great Dipper constellation and using its two pointer stars, Dubhe and Merak, to lead to the North Star.

Explanation:

The star Polaris, also known as the North Star, is beneficial for navigation due to its fixed position in the sky above the celestial North Pole. The best way to locate it is by first finding the Great Dipper constellation. Two stars in the bowl of this Dipper, named Dubhe and Merak, form a line that leads directly to Polaris.

In the given image, without the benefit of visual reference, it is difficult to identify the specific position of Polaris. However, remember that in actual practice, you would find the two pointer stars of the Great Dipper and follow a line from these stars to locate Polaris.

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What must the charge (sign and magnitude) of a particle of mass 1.44 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 680 N/C

Answers

Answer:

Q E = m g      electric and gravitational forces balance - both E and g are taken as positive in the downward direction

Q = m g / E = .00144 kg * 9.8 m/s^2 / 680 N/C = 2.08E-5 coul

This is the charge required for the specified force

Therefore Q = -2.08-5 C      for the charge to remain stationary

The word lithosphere is broken into many small and large slabs of rock called?

Answers

Answer:

The lithosphere is divided into huge slabs called tectonic plates. The heat from the mantle makes the rocks at the bottom of lithosphere slightly soft.

Explanation:

The Earth's lithosphere is broken into many small and large slabs of rock that are known as tectonic plates.

What are earth layers?

Earth is divided into four parts :

The crustThe mantleThe outer core and,The inner core.

Lithosphere is the rigid and rocky outer portion of earth's surface. It consists of crust and upper mantle.

Asthenosphere is mostly found in the uppermost mantle of earth. It is weak in nature. Hot molten magma comes out from here.

Our earth is broken into 7 major and some minor plates.

7 Major Plates are :

Pacific PlateNorth American PlateSouth American PlateEurasian PlateAfrican PlateAntarctic Plate Indo- Australia Plate

Minor Plates are :

Cocos PlateNazca PlateArabian Plate Philippine plate Caroline plate Fuji Plate

Hence, our lithosphere is divided into many small and large slabs of rock, and they are known as tectonic plates.

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If a 1.5-Kg physics book measures 0.260 m x 0.210 m x 0.040 m, calculate the pressure applied by the standing book on the table. (Round off answer to two sig figs)
*

Answer choices:
P = 1,600 N/m^2
P = 1,800 N/m^2
P = 1,500 N/m^2
P = 1,700 N/m^2

Answers

The pressure applied by the standing book on the table is 1,800 N/m².

option B is the correct answer.

What is the pressure applied by the book?

The pressure applied by the standing book on the table is determined from the ratio of weight of the book and the area of the standing book.

Mathematically, the formula for the pressure of a material is given as;

P = F / A

where;

F is the applied force or weight of the object standing on another surfaceA is the area of the object in contact with another surface

The weight of the book , F = mg

where;

m is the mass of the bookg is acceleration due to gravity

F = 1.5 kg  x  9.8 m/s²

F = 14.7 N

The dimension of the book include;

height of the book, h = 0.26 mwidth of the book, w = 0.21 mthickness of the book, b = 0.04 m

The height of the book is not in contact with the surface of the table, so the area of the book in contact with the table becomes;

A = w x b

W = 0.21 m  x  0.04 m

W = 8.4 X 10⁻³ m²

P = F / A

P = ( 14.7 N ) / ( 8.4 X 10⁻³ m² )

P = 1,750 N/m² ≈ 1,800 N/m²

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One car travels 56 meters due east in 2.0 seconds, and a second car travels 84 meters due west in 3.0 seconds. During their periods of travel, the cars definitely had the same

They have narrowed down to two answer choices. Using your knowledge, help them decide which answer choice is correct. Explain your reasoning.

average speed
average velocity

Answers

Answer:

  average speed

Explanation:

The directions were different, so the velocities could not be the same.

However, the magnitude of the velocity (speed) was 56/2 = 28 m/s for the first car, and 84/3 = 28 m/s for the second car. These average speeds are the same.

A family made the observation that more expensive brands of popcorn seem to produce more popped kernels than cheaper brands of popcorn. In order to test this hypothesis, the family conducted an experiment in which they followed the procedures below: The family bought 2 differing brands of popcorn to test: Wilbur Bockenreder Popcorn and PopWhisper. They measured 1 cup of kernels and popped 5 bowls of each type of popcorn. They ensured they popped the popcorn for the same amount of time, used the same wattage microwave, and did not have any other ingredients added to the kernels (butter, etc). They counted and recorded the number of unpopped kernels in each of the 10 bowls. As they analyzed the data collected, they were able to conclude that their initial hypothesis was supported. They formed the conclusion that the more expensive brand of popcorn popped more kernels than the cheaper brand of popcorn. From this experiment, let's answer some questions. Identify the independent variable.

Answers

Answer:

The different types of corn used.

Explanation:

Independent variable: In research methods, the term "independent variable" is determined as a variable that is being manipulated, changed, or altered in an experiment by the experimenter in order to see its effect on the dependent variable. The changes in the dependent variable in an experiment depends on the independent variable directly.

The independent variable in the popcorn experiment is brand of popcorn used.

INDEPENDENT VARIABLE:Independent variable in an experiment is the variable that the experimenter changes or manipulates in order to bring about a response.

According to this question, a family is conducting an experiment to test which brand of popcorn seem to produce more popped kernels. They used two brands of popcorn as follows: Wilbur Bockenreder Popcorn and PopWhisper.

However, the brand of popcorn was changed in this experiment, hence, the brand of the popcorn is the independent variable.

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What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter

Answers

Energy is that which has the ability to cause change in matter.

What is energy?

Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.

So in simple definition we can say that energy is that which has the ability to cause change in matter.

Based on the given statements we can classify them as;

anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.

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Compare the time it
takes the light to travel from your
teacher to your eye with the time
it takes sound to travel the same
distance.

Answers

Answer:

Light takes less time than sound.

Explanation:

Let's say, the teacher and the student are at a distance "d" from each other.

The medium around them would be air.

And,

The speed of light in air is approx. 3× 10 m/s

while, the speed of sound in air is approx. 330 m/s

We have a formula that establishes the relation between speed, distance and time.

\( \boxed{ \mathsf{speed = \frac{distance}{time} }}\)

Our hunt for time — Speed in both the scenarios is known to us whereas the distance is same.

Sound

\( \mathsf{330 = \frac{d}{time_{s}} }\)

\( \underline{\mathsf{time _{s} = \frac{d}{330} }}\)

Light

\( \mathsf{3 \times {10}^{8} = \frac{d}{time _{l} } }\)

\( \underline{ \mathsf{ time _{l} = \frac{d}{3 \times {10}^{8}} }}\)

The best way of comparison is finding their ratio.

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ \frac{d}{330} }{ \frac{d}{3 \times {10}^{8} } } }\)

simplifying the fraction

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{d \times (3 \times {10}^{8} )}{330 \times d}}\)

d gets canceled and we're left with the following expression

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ (3 \times10 \times {10}^{7} )}{330}}\)

30, being a common factor in the numerator as well as denominator, gets canceled out. and in its place remains 1/ 11

(why?

=> 30÷330 = 1÷11)

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ 1\times {10}^{7} }{11}}\)

taking time to the numerator on the other side.

\( \implies \mathsf{time_{s} = \frac{ 1\times {10}^{7} }{11}\times time_{l}}\)

Therefore, we get timeₛ is approx. 10⁶ times the timeₗ.

That's a big difference, no wonder light's way much faster than sound.

As lesser the time taken to cover a distance, faster is the wave.

The sound takes about 874,000 times MORE time than the light takes.

The Moon and the Earth are attracted to each other by gravity. Which celestial body exerts a greater force on the other?

Answers

ANSWER

The earth

EXPLANATION

We want to know the celestial body that exerts a greater force on the other.

The gravitational force is a non-contact force of attraction is a force that acts between any two bodies that have mass. This means that once two objects have mass, they are attracted to one another by the force of gravity.

Because the force of gravity is a force that depends on the mass of the objects, a body with greater mass can exert a greater force of gravity on another body.

This implies that the greater the mass of the body, the greater the force it exerts on the other body.

Hence, the earth exerts a greater force.

An autographed baseball rolls off of a 1.2 m

high desk and strikes the floor 0.76 m away

from the desk. How fast was it rolling on the desk before

it fell off? The acceleration of gravity is 9.81 m/s2.

Answers

The autographed baseball rolled off at 0.3762m/s before it fell off.

What is acceleration?

Acceleration is the rate of change of the velocity of an object with respect to time.

Given the following data:

Initial velocity = 0 m/s (assuming it started from rest).

Vertical distance = 1.2 meters

Horizontal distance = 0.76 meters

Acceleration due to gravity = 9.81

To find how fast the autographed baseball was rolling on the desk before it fell off:

we will use the second equation of motion to determine the time required:

S = ut + 1/2at²

Where:

S is the displacement or distance covered.

u is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting the given values into the formula, we have;

S = ut + 1/2at²

=0*t + 1/2 * 9.81 * t²

t = 2.02 seconds

Next, we would determine the horizontal speed:

horizontal speed= horizontal distance/time

horizontal speed=0.76/2.02

horizontal speed=0.3762m

Horizontal speed = 0.3762m/s

Therefore, the autographed baseball rolled off at 0.3762m/s before it fell off.

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