The type of member function that may be called from a statement outside the class is a public function. Public functions are accessible from outside the class and can be called by any part of the program.
This is in contrast to private functions, which are only accessible from within the class and cannot be called from outside the class. In addition, there is another term that is related to public and private functions, which is "global".
Global functions are functions that are not part of a class and can be accessed from anywhere in the program. They are similar to public functions in that they are accessible from outside the class, but they are not part of any specific class.
It is important to use public and private functions to control the access to the members of a class. Public functions are used to provide an interface to the class that can be accessed from outside the class, while private functions are used to encapsulate the implementation details of the class and are not accessible from outside the class. This helps to prevent the accidental modification of the internal state of the class by external code, which can lead to unexpected behavior and bugs in the program.
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To determine what type of member function can be called from a statement outside class:
The type of member function that may be called from a statement outside the class is a "public" function.
Public member functions can be accessed from outside the class, allowing other parts of the code to interact with the class and use its functionality.
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where does the efficienty occur maximum? what will be a condition of maximum efficienty?
Answer:
The transformer will give the maximum efficiency when their copper loss is equal to the iron loss.
trevor moves a magnetic toy train away from a magnet that cannot move. what happens to the potential energy in the system of magnets during the movement?
Answer:a
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An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
If you deposit $ 1000 per month into an investment account that pays interest at a rate of 9% per year compounded quarterly.how much will be in your account at the end of 5 years ?assume no interpèriod compounding
Answer:
5,465.4165939453
Explanation:
formula
A=P(1+r/n)^n(t)
p=1000
r=0.09
n=4
t=5
a pwm signal has a pwm frequency of 50 hz and a 20% duty cycle. how long (in milliseconds) is the signal high during each period?
Therefore, the signal is high for 4 milliseconds during each period.
In this problem, we are given a PWM signal with a frequency of 50 Hz and a duty cycle of 20%. The duty cycle represents the percentage of time the signal is high (on) during each period.
To determine how long the signal is high during each period, we need to calculate 20% of the period duration.
First, let's find the period duration. The period is the time it takes for the signal to complete one full cycle. In this case, the PWM frequency is given as 50 Hz. The frequency is the number of cycles per second, so the period can be calculated as the reciprocal of the frequency:
Period = 1 / Frequency = 1 / 50 Hz = 0.02 seconds
Now that we have the period duration, we can calculate the duration of the high state.
To do this, we multiply the period duration by the duty cycle percentage:
High state duration = Duty cycle * Period duration
High state duration = 0.20 * 0.02 seconds
High state duration = 0.004 seconds
To convert the duration to milliseconds, we can multiply by 1000:
High state duration = 0.004 seconds * 1000 = 4 milliseconds
Therefore, the signal is high for 4 milliseconds during each period.
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Identify this instrument.
Refracting telescope
Reflecting telescope
Microscope
Radio Telescope
When an object is made of the plastic polyester (PET), it uses antimony as a catalyst. After production, antimony can leach into food and drink stored in PET containers. Usually, if stored correctly for a short amount of time, the amount of antimony found in liquids is well below the safety limits. However, there have been reports of as much as 44.7 micrograms per liter [µg/L] of antimony found in fruit juice concentrates. How much antimony, in units of moles [mol], could be found in one gallon [gal] of fruit juice concentrate at this level of contamination? The molecular mass of antimony is 121.76 grams per mole [g/mol].
Answer:
1.39 µmol
Explanation:
(1 gal) × (44.7 µg/L)/(121.76 g/mol)(3.785411784 L/gal) = 1.39 µmol
Running ropes must be taken out of service if they have _____ broken wires in one strad in one lay
Answer:
3
Explanation:
3 broken wires in one strand in one lay are cause for removal from service.
Answer:
3Running ropes must be taken out o service if they have 3 broken wires in one strand in one lay.Refrigerant 134a is the working fluid of a refrigeration cycle with a flow rate of 0.05kg/s. The refrigerant enters the evaporator at 120kPa with a quality of 0.3 and leaves the evaporator as a saturated vapor. It also enters the condenser at 0.8MPa and leaves as saturated liquid. If the compressor consumes 2.3kW of power, determine the isentropic efficiency of the compressor and the COP of the cycle.
The isentropic efficiency of the compressor is 75% and the coefficient of performance (COP) of the refrigeration cycle is 3.08.
In a refrigeration cycle, the isentropic efficiency of the compressor represents how well the compressor performs compared to an ideal, reversible process. It is defined as the ratio of the actual work done by the compressor to the work done in an isentropic process with the same inlet and outlet conditions.
To determine the isentropic efficiency, we can start by calculating the actual work done by the compressor. The power consumed by the compressor is given as 2.3 kW. Since power is the rate at which work is done, we can equate the power consumed to the work done per unit time.
Work done = Power consumed = 2.3 kW
Next, we need to determine the work done in an isentropic process. The isentropic efficiency is defined as:
Isentropic efficiency = Actual work done / Isentropic work done
Since the refrigerant enters the evaporator as a saturated vapor and leaves the evaporator as a saturated vapor, we can assume that the evaporation process is isentropic. Therefore, the isentropic work done is the difference in enthalpy between the inlet and outlet conditions in the evaporator.
Similarly, since the refrigerant enters the condenser as saturated liquid and leaves as saturated liquid, we can assume that the condensation process is isentropic. Hence, the isentropic work done is the difference in enthalpy between the inlet and outlet conditions in the condenser.
By using the properties of the refrigerant at the given pressures, we can calculate the specific enthalpies at the evaporator and condenser inlet conditions. The difference between these values gives us the isentropic work done.
Now, we can use the given power consumed and the calculated isentropic work done to determine the actual work done by the compressor. Dividing the actual work done by the isentropic work done and multiplying by 100 will give us the isentropic efficiency of the compressor.
The coefficient of performance (COP) of the refrigeration cycle is defined as the ratio of the desired effect (refrigeration) to the required input (work done by the compressor). The COP can be calculated as:
COP = Refrigeration effect / Work done by the compressor
The refrigeration effect is given by the difference in enthalpy between the evaporator inlet and outlet conditions, multiplied by the mass flow rate of the refrigerant.
By substituting the known values into the equation, we can calculate the COP of the cycle.
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provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its working fluid. The turbine and pump operate adiabatically. The rate of energy input to the collectors from solar radiation is 0.3 kW per m2 of collector surface area, with 60% of the solar input to the collectors absorbed by the refrigerant as it passes through the collectors. Determine the solar collector surface area, in m2 per kW of power developed by the plant. Discuss possible operational improvements that could reduce the required collector surface area
Answer:
hello some parts of your question is missing attached below is the missing part ( the required fig and table )
answer : The solar collector surface area = 7133 m^2
Explanation:
Given data :
Rate of energy input to the collectors from solar radiation = 0.3 kW/m^2
percentage of solar power absorbed by refrigerant = 60%
Determine the solar collector surface area
The solar collector surface area = 7133 m^2
attached below is a detailed solution of the problem
One of the testing equipments used for inspection is? Test tubes Measuring jar Strain gauges None of the mentioned
Answer:
The answer is the strain gauges.
Explanation:
Inspection systems work or are performed to measure the characteristics of a product, to verify if it meets specified requirements, all using benchmarks and test equipment.
The strain gauges are part of the test equipment used for inspection. These are sensors that measure deformation, pressure and load in resistance tests of materials.
The passing of outside air into a building through doors, cracks around windows, and other openings is _____.
Answer:
Infiltration
Explanation:
Chad owned an office building that was destroyed in a tornado. The adjusted basis of the building at the time was $890,000. After the deductible, Chad received an insurance check for $950,000. He used $900,000 of the insurance proceeds to purchase a new building that same year. How much is Chad's recognized gain, and what is his basis in the new building?
The correct answer is $900,000.
The excess of insurance recovery over the cost of the new building,
that is 950000-900000 = $50000 would be recognized gain.
The basis of the new building would be the basis of the old building
plus the gain not recognized = 890000+(900000-890000) = $900,000.
What is insurance?
Insurance is a means of protection against financial loss in which a party, in exchange for a fee, undertakes to indemnify another party in the event of certain loss, damage or injury. IIIt is a form of risk management that is primarily used to hedge against the risk of contingent or uncertain loss.To know more about insurance, click the link given below:
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All of these are part of the seat belt assembly EXCEPT the:
O latch plate
O D-ring
O retractor.
O cushion
g assume the double sideband suppressed modulation is used the complex envelope of the modulated signal is
If we assume the double sideband suppressed modulation is used, the complex envelope of the modulated signal can be expressed as follows:
s(t) = Ac [1 + m(t)] cos(2πfct).
where s(t) is the modulated signal, Ac is the carrier amplitude, m(t) is the message signal, fc is the carrier frequency, and cos(2πfct) represents the carrier wave. This equation can be simplified using trigonometric identities to obtain:
s(t) = Ac cos(2πfct) + Ac m(t) cos(2πfct)
Here, the first term represents the unmodulated carrier wave, and the second term represents the modulation sidebands. As the name suggests, the double sideband suppressed carrier (DSB-SC) modulation scheme suppresses the carrier wave, leaving only the modulation sidebands. This can be achieved by multiplying the modulated signal by a carrier wave with a phase shift of 90 degrees (i.e., sin(2πfct)). The resulting signal is then passed through a bandpass filter that removes the unwanted sideband and the carrier frequency, leaving only the desired modulated signal.
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Therefore, the complex envelope of the modulated signal is a function of the message signal and the carrier frequency, and contains both the upper and lower sidebands.
In double sideband suppressed carrier (DSB-SC) modulation, the carrier frequency is suppressed, resulting in a modulated signal with no frequency content at the carrier frequency. The complex envelope of the modulated signal can be expressed as:
s(t) = m(t) * cos(2πfct)
where s(t) is the modulated signal, m(t) is the message signal, fc is the carrier frequency, and cos(2πfct) represents the carrier wave.
Using trigonometric identities, this can be rewritten as:
\(s(t) = 0.5[m(t) * e^{(j2πfct)} + m*(t) * e^{(-j2πfct)]}\)
where j is the imaginary unit, and m*(t) represents the complex conjugate of the message signal.
The expression shows that the modulated signal consists of two complex exponentials with frequencies of fc + fm and fc - fm, where fm is the frequency of the message signal. These frequencies are called the upper and lower sidebands, respectively.
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a commercial refrigerator with r-134a as the working fluid is used to keep the refrigerated space at -35 c by rejecting waste heat to cooling water that enters the condenser at 18 c at a rate of 0.25 kg/s and leaves at 26 c. the refrigerant enters the condenser at 1.2 mpa and 50 c and leaves at the same pressure subcooled by 6 c. if the compressor consumes 3.3 kw of power , determine (a) the mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
At 1.2mpa pressure and 50c
What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).
a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser
T2 = 46.29C - 5
T2 = 41.29C
Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg
(COP)r = 238/53
(Cop) = 4.490
Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.
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An electron is accelerated by a constant electric field of magnitude 300 N/C.(a) Find the acceleration of the electron.(b) Find the electron's speed after 1.00×10−71.00×10−7s, assuming it starts from rest
The electron's speed after 1.00×10⁻⁷s , after assuming it starts from rest is 5.27 × 10⁶ m/s and acceleration is 5.27 × 10¹³ m/s².
If an electron is accelerated by a constant electric field of magnitude 300N/C then:
(a) The acceleration of the electron is given by:
a = F/m
where F is the force on the electron and
m is the mass of the electron.
But The force on the electron is given by:
F = qE
where q is the charge of the electron and
E is the electric field.
Substituting the given values to find the values of force we get:
F = (1.602 × 10⁻¹⁹ C)(300 N/C) = 4.806 × 10⁻¹⁷ N
F=4.806 × 10⁻¹⁷ N
Now we know that the mass of the electron is:
m = 9.109 × 10⁻³¹ kg
Therefore, the acceleration of the electron is:
a = F/m = (4.806 × 10⁻¹⁷N) / (9.109 × 10⁻³¹ kg) = 5.27 × 10¹³ m/s²
a = 5.27 × 10¹³ m/s²
(b) The final speed of the electron after a time t can be found using the following kinematic equation:
v = v_0 + at
where v_0 is the initial velocity (which is zero in this case),
a is the acceleration found in part (a), and
t is the time elapsed.
Substituting the given values, we have:
v = 0 + (5.27 × 10¹³ m/s²)(1.00 × 10⁻⁷ s) = 5.27 × 10⁶ m/s
Therefore, the electron's speed after 1.00 × 10⁻⁷seconds is 5.27 × 10⁶ m/s.
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Prove that line current is equal to phase current in induction motor using ac voltage controller fed drives
In AC voltage controller-fed drives, the line current is equal to the phase current due to the balanced nature of the three-phase system. Therefore, in AC voltage controller-fed drives, the line current is equal to the phase current in the induction motor.
In AC voltage controller-fed drives, the induction motor operates with a balanced three-phase supply. Each phase of the motor is connected to a separate output of the AC voltage controller. The voltage controller regulates the voltage supplied to each phase. In a balanced three-phase system, the line current is the current flowing through the supply lines, while the phase current is the current flowing through each motor phase. Due to the balanced nature of the three-phase system, where the voltages and impedances are equal in magnitude and phase, the line current is equal to the phase current. This is known as the principle of balanced loads in three-phase systems.
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What is the linear distance traveled in one revolution of a 36-inch wheel
Answer:
36π inches ≈ 113.0973 inches
Explanation:
The circumference of the wheel is pi times its diameter.
C = πd
C = π(36 in) = 36π in ≈ 113.0973 in
The distance around the wheel is 36π inches, about 113.0973 inches.
La Patrulla Fronteriza de los Estados Unidos analiza la compra de un helicóptero nuevo para la vigilancia aérea de la frontera de Nuevo México y Texas con la República Mexicana. Hace 4 años se adquirió un helicóptero similar con un costo de $ 140,000.00. con una tasa de interés de 7% anual. Calcula el factor de pago único y el factor valor presente con los datos anteriores con la tabla y fórmula. Dibuja el diagrama de flujo.
Answer:
The Border Patrol of the United States analyzes the purchase of a new helicopter for the aerial surveillance of the border of New Mexico and Texas with the Mexican Republic. 4 years ago a similar helicopter was purchased at a cost of $ 140,000.00. with an interest rate of 7% per year. Calculate the single payment factor and the present value factor with the above data with the table and formula. Draw the flow chart.
Explanation:
A 20 mm diameter rod made of ductile material with a yield strength of 350 MN/m2 is subjected to a torque of 100 N.m, and a bending moment of 150 N.m. An axial tensile force is then gradually applied. What is the value of the axial force when yielding of the rod occurs using: a. The maximum-shear-stress theory b. The maximum-distortional-energy theory.
Answer:
a) 42.422 KN
b) 44.356 KN
Explanation:
Given data :
Diameter = 20 mm
yield strength = 350 MN/m^2
Torque ( T ) = 100 N.m
Bending moment = 150 N.m
Determine the value of the applied axial tensile force when yielding of rod occurs
first we will calculate the shear stress and normal stress
shear stress ( г ) = Tr / J = [( 100 * 10^3) * 10 ] / \(\pi /32\) * ( 20)^4
= 63.662 MPa
Normal stress( Гb + Гa ) = MY/ I + P/A
= [( 150 * 10^3) * 10 ] / \(\pi /32\) * ( 20)^4 + 4P / \(\pi * 20^2\)
= 190.9859 + 4P / \(\pi * 20^2\) MPa
a) Using MSS theory
value of axial force = 42.422 KN
solution attached below
b) Using MDE theory
value of axial force = 44.356 KN
solution attached below
8. Find the volume of the figure shown below: * V=L x W x H 7 cm 2 cm 2 cm
Need help fast 50 points Project: Creating a Morphological Matrix
Assignment Directions
A systematic way to view common functionality of an object's structure and components is through a morphological matrix. You are going to utilize this method to analyze a common household device (from the list below or your own idea). First, create the left-hand column by deciding on the parameters that allow the object to function normally. For example, a pencil sharpener has a blade and a housing unit to support the system. Use the parameters to describe the system. If the pencil sharpener is hand operated, list the parameter of hand turning (either the pencil itself in a small unit or a handle in a wall-mounted device). The parameter column can include specific structures in the device, power sources, or any other information you learned in the lesson. The right-hand columns will include the current methods used by the device to complete the parameter, as well as any other options that would satisfy the parameter. You must create at least two other options for each parameter.
While the matrix provides valuable information for an engineer, it is typically more technological than a client or decision team needs. Therefore, you will also need to complete a one- or two-page analysis of the device, including the current parameter solutions and any recommended alterations to a design. Each recommendation must be supported by information in the morphological matrix.
Here are some ideas of household devices that you can analyze:
can opener
bathroom or kitchen scale
doorknob assembly
stapler
Assignment Guidelines
a completed morphological matrix
each parameter must have at least three solutions
a written analysis of the device with supporting details from the matrix
Submission Requirements
One to two pages double spaced
Proper grammar and vocabulary is required.
Answer:
The fundamental difference between effective and less effective matrix organizations is whether the tension between different perspectives is creative or destructive. While various processes, systems and tools can help, what matters most is what top leadership says and does and how that flows through the organization in shared targets, clear accountabilities, live team interactions and team-building transparency and behaviors.
Getting matrix management right is linked inextricably to an organization’s culture - the only sustainable competitive advantage. Key components of a culture can be grouped into behaviors, relationships, attitudes, values and the environment.
Environment and values: Each organization has its own environment, context and bedrock values. Everyone needs to know what matters and why. Don’t try to do anything else until you’ve got that set.
Attitude is about choices: An organization’s overall strategy drives choices about which of its parts will be best in class (superior), world class (parity), strong (above average), or simplified/outsourced to be good enough. These choices help determine the need for a matrix and how best to design it.
Relationships and behaviors: This is why organizations have matrices. The most effective of them best balance focus and collaboration. They allow leaders and teams to build differential strengths and then work together to make the best possible decisions and scale enterprises with a creative tension that they could not do on their own.
My colleague Joe Durrett has worked all sides of matrix organizations in marketing at Procter & Gamble, sales and general management at Kraft General Foods and CEO of Information Resources, Broderbund Software and Advo. He has seen matrices at their best and at their worst and offered his perspective for this article along with his partners John Lawler and Linda Hlavac. The 12 ways to make matrix organizations more effective were built on their ideas.
Explanation:
Technician A says ABS systems provide superior directional stability when the brakes are applied while turning a corner. Technician B says ABS systems provide superior braking when driving on loose snow. Who is correct
Both technicians A and B are partially correct, because it's important to note that ABS is not a foolproof solution in all driving situations and should not be relied upon as a substitute for proper driving techniques and caution.Technician A is partially correct in that ABS (Anti-lock Braking System) can improve directional stability. Technician B is also partially correct in that ABS can improve braking performance on loose snow.
Both technicians are partially correct, but neither is entirely accurate.
Technician A is partially correct in that ABS (Anti-lock Braking System) can improve directional stability when the brakes are applied while turning a corner, especially on slippery or uneven road surfaces. The system can prevent the wheels from locking up and skidding, which can cause the vehicle to lose control. However, it's important to note that ABS does not necessarily guarantee superior directional stability in all situations, and the driver should still exercise caution and proper driving techniques when turning.
Technician B is also partially correct in that ABS can improve braking performance on loose snow, as the system can help prevent the wheels from locking up and losing traction. However, other factors such as tire type and condition, road gradient, and vehicle weight distribution can also impact braking performance on loose snow.
Therefore, both technicians are partially correct, but it's important to note that ABS is not a foolproof solution in all driving situations and should not be relied upon as a substitute for proper driving techniques and caution.
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What is the relationship between green building and self-interest? (Select all that apply.)
Green building is burdensome but has advantages in terms of public image.
Green building should be considered when necessary resources are in short supply.
Green building practices can lead to planning and budget efficiencies in general.
Green building is attractive because of its long-term growth potential as a market.
The relationship between green building and self-interest include the following:
Green building is burdensome but has advantages in terms of public imageGreen building is attractive because of its long-term growth potential as a market.What is Green building?This is the process of reducing the environmental impact of buildings. This therefore leads to enhancement of the health of people.
Its relationship with self interest can seen listed above as the most appropriate choice.
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FOR BRAINLIST ITS A DCP
The Battle of Sabine Pass
The Battle of Galveston
The Battle of Palmito Ranch
The Battle of Vicksburg
Answer:
I think The Battle of Sabine Pass
For the figure shown below, assume that Vs = 10 sin(333t + 45o )V, (a) find the total impedance of the circuit and is in phasors form [15 marks] (b) find the currents iR and iL in phasor form [10 marks] (c) obtain the expressions for is, iL, and iR as single sinusoids [10 marks] (d) determine the instantenous values of is, iL and iR at t=0 s.
Answer:
see bold numbers below
Explanation:
Given the attached series-parallel circuit, you want to know ...
the total impedance (phasor)the source current (phasor and sinusoid)the branch currents (phasor and sinusoids)the currents at t=0Total impedanceThe circuit impedance is the sum of the series resistance and the parallel combination of the 1Ω resistor and the 3 mH inductor. For ω = 333, the inductor's impedance is Xl = jωL = j(333)(.003)Ω = j0.999Ω.
The total impedance is the sum ...
Ztot = 10 + 1/(1/1 +1/j0.999) = 10.51∠2.73°
Circuit currentsThe total current in the circuit is ...
Is = Vs/Ztot = 10∠45°/10.51∠2.73° = 0.9513∠42.27°
The branch currents are in reverse proportion to the branch impedance
Ir = Is(Xl/(1+Xl)) = 0.6724∠87.30°
Il = Is(1/(1+Xl)) = 0.6730∠-2.70°
Sine functionExpressed as a sine function, these have the magnitude and phase angle indicated by the phasor:
Is(t) = 0.9513·sin(333t +42.27°)
Ir(t) = 0.6724·sin(333t +87.30°)
Il(t) = 0.6730·sin(333t -2.70°)
Current at t=0At t=0, each of these current values is the magnitude of the current multiplied by the sine of the phase angle. In effect, it is the imaginary part of the current when it is expressed in complex form.
Is(0) = 0.9513·sin(42.27°) = 0.6399 A
Ir(0) = 0.6724·sin(87.30°) = 0.6716 A
Il(0) = 0.6730·sin(-2.70°) = -.0317 A
__
Additional comment
Solving these problems is immensely aided by a calculator that easily handles complex numbers. The one shown in the attachments does not thread polar conversions over a list, but otherwise works nicely for this problem. Angle mode is set to degrees. The value of x is 0.999i.
Find and write the mathematical problem formulation of shortest path problem
Technician A says that a magnetic field is created in the alternator rotor. Technician B says that alternator output is increased if the speed of the alternator is decreased. Who is right
Alternators are devices used to convert mechanical energy into electrical energy. They are widely used in vehicles to recharge the battery and power the electrical systems of the vehicle. Alternators operate based on the principle of electromagnetic induction, which involves the creation of a magnetic field in the rotor to generate electrical energy.
Technician A is correct in stating that a magnetic field is created in the alternator rotor. The rotor is the rotating part of the alternator that contains a series of windings. When an electrical current flows through these windings, a magnetic field is created in the rotor. This magnetic field interacts with the stator, which is a stationary part of the alternator that contains a series of windings, to generate an electrical output.
Technician B is incorrect in stating that alternator output is increased if the speed of the alternator is decreased. The output of an alternator is directly proportional to the speed of the rotor. The faster the rotor spins, the higher the output of the alternator. Therefore, if the speed of the alternator is decreased, the output will also decrease.
In conclusion, both technicians are partially correct, but Technician A is more accurate. A magnetic field is created in the alternator rotor, and the output of the alternator is directly proportional to the speed of the rotor.
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