Three blocks are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box of mass M. There is friction between the surfaces of blocks 2M and 3M so the three blocks accelerate together to the right.
Which block has the smallest net force acting on it?
A) M
B) 2M
C) 3M
D) The net force is the same for all three blocks Submit
Answers
Answer:
A) M
Explanation:
The three blocks are set in series on a horizontal frictionless surface, whose mutual contact accelerates all system to the same value due to internal forces as response to external force exerted on the box of mass M (Newton's Third Law). Let be F the external force, and F' and F'' the internal forces between boxes of masses M and 2M, as well as between boxes of masses 2M and 3M. The equations of equilibrium of each box are described below:
Box with mass M
\(\Sigma F = F - F' = M\cdot a\)
Box with mass 2M
\(\Sigma F = F' - F'' = 2\cdot M \cdot a\)
Box with mass 3M
\(\Sigma F = F'' = 3\cdot M \cdot a\)
On the third equation, acceleration can be modelled in terms of F'':
\(a = \frac{F''}{3\cdot M}\)
An expression for F' can be deducted from the second equation by replacing F'' and clearing the respective variable.
\(F' = 2\cdot M \cdot a + F''\)
\(F' = 2\cdot M \cdot \left(\frac{F''}{3\cdot M} \right) + F''\)
\(F' = \frac{5}{3}\cdot F''\)
Finally, F'' can be calculated in terms of the external force by replacing F' on the first equation:
\(F - \frac{5}{3}\cdot F'' = M \cdot \left(\frac{F''}{3\cdot M} \right)\)
\(F = \frac{5}{3} \cdot F'' + \frac{1}{3}\cdot F''\)
\(F = 2\cdot F''\)
\(F'' = \frac{1}{2}\cdot F\)
Afterwards, F' as function of the external force can be obtained by direct substitution:
\(F' = \frac{5}{6}\cdot F\)
The net forces of each block are now calculated:
Box with mass M
\(M\cdot a = F - \frac{5}{6}\cdot F\)
\(M\cdot a = \frac{1}{6}\cdot F\)
Box with mass 2M
\(2\cdot M\cdot a = \frac{5}{6}\cdot F - \frac{1}{2}\cdot F\)
\(2\cdot M \cdot a = \frac{1}{3}\cdot F\)
Box with mass 3M
\(3\cdot M \cdot a = \frac{1}{2}\cdot F\)
As a conclusion, the box with mass M experiments the smallest net force acting on it, which corresponds with answer A.
Related Questions
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Answers
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg.m/s of
momentum?
Answers
Answer:
The product of the mass and the volume is known as momentum.
According to the law of momentum, it is stated that the two or more bodies remain in a constant state unless an external force is applied in an isolated room.
Momentum depends on the following:-
Mass
Velocity
Momentum = MASS \ X \ VOLUMEMomentum=MASS X VOLUME
\begin{gathered}momentum = 3000kgm/s\\\\mass = 2000kg\\\\velocity =\frac{momentum}{mass}\\\\v= \frac{3000}{2000} \\\\v= 1.5m/s\end{gathered}
momentum=3000kgm/s
mass=2000kg
velocity=
mass
momentum
v=
2000
3000
v=1.5m/s
juptiter's moon io has a mass of 8.94x10^22 kg and a radius of 1815 km. What is the acceleration due to gravity on the surface of io?
a. 4.33 m/s^2
b. 1.81 m/s^2
c. 2.51 m/s^2
d. 9.81 m/s^2
Answers
Answer:
\(g=1.81\ m/s^2\)
Explanation:
Mass of Jupiter's moon, \(M=8.94\times 10^{22}\ kg\)
Radius, R = 1815 km
We need to find the acceleration due to gravity on the surface of Juptiter's moon. The formula for the acceleration due to gravity is given by :
\(g=\dfrac{GM}{R^2}\)
G is universal gravitational constant
\(g=\dfrac{6.67\times 10^{-11}\times 8.94\times 10^{22}}{(1815\times 10^3)^2}\\\\g=1.81\ m/s^2\)
So, the acceleration due to gravity on the Jupiter's moon is \(1.81\ m/s^2\).
A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?
Answers
Answer:
The velocity of the box is related to the angular velocity of the spool, which is given by the equation:
v = r * ω
where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:
τ = I * α
where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.
The tension in the string is equal to the weight of the box, which is given by:
T = m * g
Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:
First, we can find the angular acceleration of the spool using the torque equation:
τ = I * α
T = m * g = τ
m * g = I * α
α = (m * g) / I
α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2
α = 86.53 rad/s^2
Next, we can find the angular velocity of the spool using the kinematic equation:
ω^2 = ω_0^2 + 2 * α * θ
where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:
ω^2 = 2 * α * θ
ω = sqrt(2 * α * θ)
ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))
ω = 166.6 rad/s
Finally, we can find the time it takes for the box to reach the floor using the equation:
v = r * ω
v = 0.10 m * 166.6 rad/s
v = 16.66 m/s
t = d / v
t = 3.50 m / 16.66 m/s
t = 0.21 s
Question 4 of 10
Which of the following describes the reactants of a chemical reaction?
OA. The chemicals on the right side of a chemical equation
B. The substances that are formed
OC. The substances that are made
O D. The chemicals on the left side of a chemical equation
Answers
The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.
Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.
On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.
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The power of a wave comes from the wave's ..
Answers
Answer:
waves energy i think
Explanation:
HELP I DEPEND ON THIS
Answers
Answer:
D. A force within a fluid that pushes upward
Explanation:
Buoyancy is the ability of something floating in water, so it's probably not about the attraction between molecules and is about a force within a fluid. If a force within a fluid is pushing downwards on an object, that would make the object go downwards (sink), which is not buoyancy. If a force within a fluid is pushing upwards on an object, the object would be floating.
Answer:
Option D
Explanation:
When you put any object and push it inwards water .
According to Newton's third law every action has equal and opposite reaction
So the water hits back with opposite force which is known as buoyant force.
Archimedies law is applicable in these cases
An ecosystem with one dominant type of plant growing in it is a healthy, stable ecosystem. True or false?
Answers
Show that time period of revolution an electron beam in uniform magnetic field is independent of velocity and radius of path
Answers
Since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path
How to show that time period of revolution an electron beam in uniform magnetic field is independent of velocity and radius of path?For an electron moving in a uniform magnetic field, the force on the electron is given by
F = Bev where
B = magnetic field, e = electron charge and v = speed of electronAlso, this magnetic force equals the centripetal force on the electron, F'
F' = mv²/r where
m = mass of electron, v = speed of electron and r = radius of pathSince both forces are equal,
F = F'
Bev = mv²/r
Be = mv/r
We know that angular speed, ω = v/r. So,
Be = mω
Also, angular speed, ω = 2π/T where T = period of revolution of electron
So, Be = m2π/T
Making T subject of the formula, we have
T = 2πm/Be
so, since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answers
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
How can we show that air can do work?
Answers
Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.
Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.
To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.
The work done by the air can be calculated using the equation:
Work = Force * Distance * cos(θ)
Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.
In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:
Work = Force * Distance * 0
Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.
However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.
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Answer #49 please and thank you
Answers
when Force (N) is 10.0 Length (m) is 0.60
when Force (N) is 8.0 Length (m) is 0.40
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 2.0 Length (m) is 0.10
chatgpt
49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:
Period (T) = 2π√(Length (L) / g)
Substituting the given values:
2.3 = 2π√(L / 1.6)
To solve for L, we can rearrange the formula:
L = (2.3 / (2π))^2 * 1.6
L ≈ 0.781 meters (or 78.1 centimeters)
So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.
50. Ranking Task:
To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.
Ranking from least to greatest period:
1. A: 10 cm long, mass = 0.25 kg
2. C: 20 cm long, mass = 0.25 kg
3. B: 10 cm long, mass = 0.35 kg
There is a tie between pendulums A and C, as they have the same length but different masses.
What is true about the foci of a planet in elliptical orbit?
A:The sun is located at one focus.
B: Earth is located at one focus.
C: Earth is located in the center of the orbit.
D: The sun is located in the center of the orbit
Answers
Statement A. The sun is located at one focus is true about the foci of a planet in an elliptical orbit (option A).
What is an elliptical orbit?An elliptical orbit can be defined as any movement of a celestial body in which the attained object (for example a planet around its star) moves in an eccentric manner or oval-shaped way, which is a feature of the planets in the solar systems including the Earth planet.
The movement of a planet in an elliptical orbit is called an ellipse, while two points that are selected chosen at the start site are known as foci in such orbits.
Therefore, with this data, we can see that an elliptical orbit is an excentric movement of a celestial body such as the earth's planet around the sun, and foci are called to fixed points located inside this orbit.
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Two identical metallic spheres A and
B, each carrying a charge of q C, are fixed.
They repel each other with a force of
2x10-5 N. Another identical uncharged
sphere C is made to touch A, moved to
touch B, and placed halfway between A
and B. What is then the electric charge
and the electric force (in N) on each
sphere in terms of q?
Answers
The electric charge and the electric force on each sphere in terms of q is 2
The Electric Charge and Electric ForceThe ability of particles or objects to attract or repel one another without coming into contact is known as electric charge. Incompatiblely charged particles are drawn to one another. Like-charged particles repel one another. Electric force is the name given to the force of attraction or repulsion.
Two metallic spheres, a and b, with a charge of half and a force of two tens of five
F1=k(1/2)(1/2)/r2
Equation F1=k/4r
A and C are two metallic spheres, respectively, so
Equation F2=k/2rsquare
equ1/equ2
2×10^-5/F2=k/4r^2×2r^2/k
F2=4×10^-5
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If the Test Section area has an air speed of 10 m/s, what would be the air speed at the Air Intake area
Answers
The speed of air at the intake area is \(\frac{10A_2}{A_1} \) (m/s).
Continuity equationThe continuity equation is used to determine the flow rate at different sections of a pipe or fluid conduit.
The continuity equation is given as;
\(A_1v_1 = A_2 v_2\)
Let the intake area = A₁Let the velocity of air in intake area = v₁Let the area of the test section = A₂Velocity of air in test section, v₂ = 10 m/sThe speed of air at the intake area is calculated as follows;
\(A_1 v_1 = A_2 v_2\\\\ v_1 = \frac{A_2 v_2}{A_1} \\\\ v_1 = \frac{10A_2}{A_1} \)
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A 2kg ball is rolled along the floor for 0.8 m at a constant speed of 6 m/s. What is the work done by gravity?
A, 0
B, 16 J
C, 72 J
D, 450 J
E, 90 J
Answers
=F×s×cosa=2×g×0,8×cos90°= 0
The work done by gravity on a ball of 2 kg which is moving with a constant speed of 6 meter per second is zero. Thus, the correct option is A.
What is Work?Work is the energy transfer to or from an object through the application of force along with the displacement. For a constant force aligned with the direction of motion, the work done is equal to the product of the force strength which is applied and the distance traveled by the object.
Work = Force × Displacement
Force = Mass × Acceleration
Acceleration of the ball is zero as it is moving with a constant speed. Therefore, the work done by the gravity is zero.
Therefore, the correct option is A.
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which of the following are not units used to measure energy?
a. joules
b. newtons
c. BTU
d. calories
Answers
Answer:
The BTU, or British thermal unit, is actually a measure of heat.
Tom applied 10 000J of heat energy to four (4) metals A, B, C and D. All the metals were of the same mass and were initially at the same temperature. After heating the metals the temperature change was noted as shown in the table below. Metal 9 A.25 B.35 C.10 D.15 Which of these four (4) metals has the highest heat capacity?
Answers
The metal with the highest heat capacity between metals A.25 B.35 C.10 and D.15 is metal A.
How to determine heat capacity?Heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius. Metal A has a heat capacity of 400 J/kg°C, which means that it takes 400 joules of heat to raise the temperature of one kilogram of metal A by one degree Celsius.
Metal B has a heat capacity of 285.7 J/kg°C, metal C has a heat capacity of 1000 J/kg°C, and metal D has a heat capacity of 666.7 J/kg°C. Therefore, metal A has the highest heat capacity of the four metals.
Metal A's high heat capacity means that it can absorb a lot of heat without its temperature changing very much. This makes metal A a good material for things like heat sinks and thermal insulation.
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PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
Answers
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?
a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.
2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?
a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.
3 Which statement about the observed results of the double-slit experiment is true?
a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.
4 Which statement about the observed results of the double-slit experiment is true?
a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.
5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?
a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.
6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?
a 789 nm
b 420 nm
c 581 nm
d 591 nm
Answers
Answer:
1. Two bright bands would appear on the screen in line with the slits.
2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.
3. Waves that are in phase constructively interfere to create bright bands.
4. Waves that are out of phase destructively interfere to form dark bands.
5. The spacing between the bright fringes will decrease.
6. 581 nm
Explanation:
How much force is needed to accelerate a Kia Soul with a
mass of 1200 kg to 5 m/s2?
Answers
Answer:
\(\boxed {\boxed {\sf 6,000 \ Newtons}}\)
Explanation:
Force is the product of mass and acceleration.
\(F=ma\)
The mass of the Kia Soul is 1200 kilograms and its acceleration is 5 meters per square second.
\(m= 1200 \ kg \\a= 5 \ m/s^2\)
Substitute the values into the formula.
\(F= 1200 \ kg * 5 \ m/s^2\)
Multiply.
\(F= 6000 \ kg*m/s^2\)
1 kilgram meter per square second is equal to 1 Newton. Our answer of 6000 kg*m/s² equals 6000 N\(F= 6000 \ N\)
Answer:
Given :-Mass = 1200 kgAcceleration = 5 m/s²To Find :-Force
Solution :-We know that
F = ma
F = Force
m = mass
a = acceleration
F = 1200 × 5
F = 6000 N
\( \\ \)
Can someone answer this pls ?
Answers
It is discovered that the object, which weighs 60g and has a volume of 50cm³, has a density of 1.2 g/cm³.
Does density vary as a result of pressure?Under pressure, a liquid becomes denser. In other words, as an excessive force is given to a liquid, volume decreases and density increases, and as molecules get closer to one another, interparticle spacing decreases.
What does mass vs. density mean?A substance or object's mass is a measure of how much matter it contains. Volume (the amount of space an object or substance occupies) to mass (the amount of material present) ratio is known as density (its mass).
According to the given information:
Mass= 60g
Volume = 50cm³
Density = mass / volume
=> 60/50 =>1.2 g/cm³
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A 45.0 kg box initially at rest is pushed 6.00 m along a rough, horizontal floor with a constant applied horizontal force of 150 N. Find the work done by applied force?
Answers
Answer:
Define the capacitance of a parallel pate capacitor and state one application of in the electric circuit
In your own words, what is Newton's second law
Answers
I would say that it states that..when a force of certain magnitude is exerted to an object to a certain direction the object will accelerate to the direction of that force. When you increase the force to the object the object also increase its acceleration but when the mass of the object is increased acceleration of the object will decrease .
NOTE I USED MY OWN WORDS TO EXPLAIN HOW NEWTON'S SECOND LAW OPERATES.
GOODLUCK
How many joules of energy are required to accelerate one kilogram of mass from rest to a velocity of 0.866c?
Answers
Answer:
the amount of energy needed is 1.8 x 10¹⁷ J.
Explanation:
Given;
mass of the object, m₀ = 1 kg
velocity of the object, v = 0.866 c
By physics convection, c is the speed of light = 3 x 10⁸ m/s
The energy needed is calculated as follows;
E = Mc²
As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;
\(M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\ M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg\)
The energy required is calculated as;
E = 2 x (3 x 10⁸)²
E = 1.8 x 10¹⁷ J
Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.
When you put water in the ice tray in the freezer, water becomes ice. Ice is more ordered than water. Is this a violation of Second Law of Thermodynamics
Answers
Answer:
No because the heat that moved out of the water to make ice caused an even greater disorder in the environment around it.
Explanation:
Rahim is watching his favorite football team on television. In order to work, the television must be
plugged into an electrical outlet. When the television gets turned on, what is the main energy
transformation demonstrated by the television?
Answers
Answer:
it would be the cord will have the most energy at the moment.
Explanation:
...
A piano wire under tension has a fundamental resonance frequency of 272 hz. The length of the string is 0. 95 m and its mass is 1. 2 grams. Calculate the tension in the wire.
Answers
The tension in the wire is 105.6 N
The fundamental frequency of a stretched wire is given by:
f = (1/2L) * √(Tension/Linear density)
where L is the length of the wire, Tension is the tension in the wire, and Linear density is the mass per unit length of the wire.
In this case, we are given:
f = 272 Hz
L = 0.95 m
Linear density = 1.2 g/m = 0.0012 kg/m
Solving for Tension:
Tension = ( 4f²* L * Linear density) / 1²
Tension = (4 * 272²* 0.95 * 0.0012) / 1²
Tension = 105.6 N
Therefore, the tension in the wire is 105.6 N.
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Fernando, who has a mass of 43.0 kg, slides down
the banister at his grandparents' house. If the
banister makes an angle of 35.0° with the horizontal,
what is the normal force between Fernando and the
banister?
Answers
From the calculations, the normal force on the body is 345 N.
What is the normal force?Let us recall the theory of Newton that states that action and reaction are equal and opposite. We know that the force that is exerted on an object is equal to the reaction of that surface of the object on the source of the force.
We know that the normal force can be given by the formula;
N = mgcosθ
m = mass of the object
g = acceleration due to gravity
θ = angle involved
We would now have
N = 43.0 kg * 9.8 m/s^2 * cos 35
N = 345 N
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If an object is moving with a constant velocity then according to Newton's first law:
A- it will continue with this velocity only if a net external unbalanced force acts.
B- it will change its velocity if a net unbalanced external force is applied.
С- it will continue with its velocity as external unbalanced force acts.
D- it will continue with its velocity as friction only acts if an external unbalanced force is applied.