(True or False) To effectively use Gauss's Law to find an electric field, I must choose my Gaussian surface such that E is perpendicular to dA.

Answer: i am not sure

Explanation: i am not sure

Answer:

The participants who were given the coffee

Explanation:

This is the group which the experiment is centered or focused around in order to achieve a result of derive informations regarding their exposure to some things.

Dr. Sampson is studying the effects of caffeine on hunger which means he hypothesizes that people who ingest more caffeine experience less hunger pangs throughout the day. He designs a study where one group of participants is given caffeine throughout the day, and the other group is not allowed to have any caffeine. All this talks about The participants who were given the coffee being the experimental group

When using a schematic for troubleshooting, the best property to follow is the meter and is denoted as option B.

This is referred to as any type of device which is built to accurately detect and display an electrical quantity in a form which is readable by a human being.

Examples of meters which are used by people include voltmeter, ohmeter etc which are used to read voltage and current respectively. It is used to troubleshoot when schematics are used as certain parameters are detected and analyzed so as to detect the issue and solve it appropriately.

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Answer:

A and B is common to both of

A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . The amount of work done is 140 joule.

When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement.

By multiplying the length of the path by the component of the force acting along the path, work can be calculated if the force is constant. The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.

The work is W = fd cos if the force is applied at an angle of to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as.

Therefore, A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . The amount of work done is 140 joule.

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By substituting the values into the given function, we can verify that f(1) - f(2) = f(1) - f(2). We can find the time by determining when the derivative of the function, which represents velocity, equals zero.

(a) To verify f(1) - f(2) = f(1) - f(2), we substitute the values into the given function f(t) = -16t² + 48t. We have f(1) = -16(1)² + 48(1) and f(2) = -16(2)² + 48(2). Evaluating these expressions, we get f(1) = 32 and f(2) = 0. Therefore, f(1) - f(2) = 32 - 0 = 32, and f(1) - f(2) = 32 - 0 = 32. The two expressions are indeed equal.

(b) According to Rolle's Theorem, if a function is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), and the function values at the endpoints are equal, then there exists at least one point c in the interval (a, b) where the derivative of the function is zero.

In this case, the given function f(t) represents the height of the ball. To find the time at which the velocity is zero, we need to determine when the derivative of f(t) equals zero. Taking the derivative of f(t), we get f'(t) = -32t + 48. Setting f'(t) = 0 and solving for t, we have -32t + 48 = 0, which gives t = 1.5.

Therefore, according to Rolle's Theorem, there must be a time t = 1.5 seconds in the interval (1, 2) where the velocity of the ball is zero.

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The height of ball seconds after it is thrown upward from height of 6 feet and with an initial velocity of 48 feet per second is f (t) -16t²+ 48t (a) Verify that f(1) f(2)- f (1) f(2) (b) According to Rolle's Theorem_ what must be the velocity at some time in the interval (1, 2)? ft{sec Find that time

Answer:

Snell's law of refraction also known as the second law of refraction which states:

The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant or given pair of Media .

Answer:

the electric energy travels through the plug or wire or whatever is connecting the energy source to the lightbulb, which conducts electricity, and to the light bulb. the electric energy is transfered into light energy and thermal energy

Explanation:

i hope i understood this question and answered it correctly XD

Answer:

they would fall at different speeds

Explanation:

The speed at which each falls is dependent on air resistance

Option a is correct.

F=GMm/R²

where F is the gravitational force or weight

G is the universal constant of gravitation

M is the mass of Earth

m is the mass of the object

R is the distance between the center of the earth and the object

Given,

initial distance R =4000miles

weight at surface of the earth F=400lb

Let the force be F' for a distance R' from earth's center.

Here R' = radius+ height of the tower = R+4000 miles = 4000 + 4000 = 8000 miles.

Since the other terms in the formula remain constant, the new weight F' can be calculated as follows:

F'/F = R²/R'(otherwise the inverse square law in gravitation)

F'/400=(4000)²/(8000)²

F' = 100 lb

Thus option a is correct.

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The weight of the body on a 4000-mile high tower would still be 400 lbs.

The weight of an object depends on the gravitational acceleration at its location. On the surface of the Earth, the gravitational acceleration is approximately 32 ft/s2. Therefore, a 400 lb body on the Earth's surface would weigh 400 lbs. If the body were placed on a 4000-mile high tower, it would be much farther from the center of the Earth and experience a weaker gravitational pull. The weight of the body would decrease as the square of the ratio of the radii of the tower and the Earth. So, the weight on the tower would be:

Weight on the tower = (400 lb) * (4000 mi/4000 mi)2 = 400 lb * 1 = 400 lb

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Answer:

v_squid = - 2,286 m / s

Explanation:

This exercise can be solved using conservation of the moment, the system is made up of the squid plus the water inside, therefore the force to expel the water is an internal force and the moment is conserved.

Initial moment. Before expelling the water

          p₀ = 0

the squid is at rest

Final moment. After expelling the water

         \(p_{f}\) = M V_squid + m v_water

         p₀ = p_{f}

          0 = M V_squid + m v_water

           c_squid = -m v_water / M

The mass of the squid without water is

            M = 9 -2 = 7 kg

let's calculate

           v_squid = 2 8/7

           v_squid = - 2,286 m / s

The negative sign indicates that the squid is moving in the opposite direction of the water

To calculate the distance between the ships by formulas.

What constitutes speed?

The speed at which a position of an object changes in any direction. Speed is defined as the ratio of distance travelled to the amount of time needed to cover that distance. Because it only has a direction and no magnitude, speed is a scalar quantity.

What is distance?

Distance is an object's overall movement, independent of direction. Distance can be described as the amount of ground that an object has covered, regardless of its starting or ending points.

Known dx/dt= 35km/h

dy/dt= 25km/h

dz/dt when x=(4.35)= 140km and

y=(4.25) = 100 km

( then =\(\sqrt{100^2 + 240^2}\) = 260 km)

∴ 100^2 ( x+y)^2 = Z²

0+∂(x+y)(dx/dt+dy/dt)=∂z(dz/dt)

=∂(140+100)(35+25)=∂(260)(dz/dt)

dz/dt= 55.4km/h

Therefore, the distance between the ships is55.4km/h.

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Water is more dense in its solid state.

This statement is true.

Answer: what is it asking

Explanation:

A key prerequisite for adaptive radiations that is shared among just about all examples of adaptive radiations is the availability of ecological opportunities or vacant ecological niches.

Adaptive radiation refers to the rapid diversification of a single ancestral lineage into a variety of species that occupy different ecological niches. It occurs when a group of organisms encounters new and vacant ecological opportunities, allowing them to exploit different resources or habitats.

The availability of ecological opportunities is crucial for adaptive radiations because it provides the necessary conditions for evolutionary divergence and speciation.

When new ecological niches become available, organisms that possess adaptations enabling them to exploit these niches can undergo rapid diversification and give rise to multiple new species.

This prerequisite of ecological opportunities is observed in various examples of adaptive radiations, such as Darwin's finches in the Galápagos Islands, Hawaiian honeycreepers, cichlid fish in African lakes, and many others.

In each case, the colonization of new habitats or the opening of new ecological niches has facilitated the adaptive radiation and subsequent diversification of species.

The key prerequisite for adaptive radiations that is shared among just about all examples is the availability of ecological opportunities or vacant ecological niches. This provides the necessary conditions for organisms to diversify and occupy different niches, leading to the rapid evolution of multiple new species.

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The energy stored in the inductor is 0.036 J.

To calculate this, we need to use the formula E = (1/2) * L * I^2, where E is the energy stored in the inductor, L is the inductance in henries, and I is the current in amps. First, we need to find the current flowing through the circuit by calculating the total resistance (R = 4.0 Ω + 2.0 Ω = 6.0 Ω) and using Ohm's Law (I = V/R). Thus, I = 12 V / 6.0 Ω = 2.0 A. Plugging in the values, we get E = (1/2) * 0.1 H * (2.0 A)^2 = 0.036 J. Therefore, the energy stored in the inductor is 0.036 J.

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Given :

A rectangular solid box of aluminum is heated.

To Find :

Which of the following is not true.

A) Its mass remains constant

C) its density increase

B) Its volume increase

D) none of the above​

Solution :

We know, when an object is heated it expands.

Objects expands means that the volume increases but mass remains same by conservation of mass.

Since mass remains constant and volume increases.

So, density will decrease.

Hence, this is the required solution.

Answer:

MgO relative atomic mass is 40

Explanation:

Mg=24

O=16

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

Answer:

B

Explanation:

Two cars X and Y start from two points separated by 75 m. Y which is ahead of X. starts from rest with acceleration of 10 m/s2 and X starts with uniform velocity of 40 m/s . The time gap between the two meetings would be approximately 1.44 seconds.

Let's assume that the two cars meet for the first time after time t₁, and then they meet for the second time after time t₂.

We can start by finding the time it takes for car Y to catch up to car X for the first time. We can use the following kinematic equation:

d = ut + (1/2)at²

where d is the distance between the two cars, u is the initial velocity of car X, a is the acceleration of car Y, and t is the time it takes for car Y to catch up to car X.

Plugging in the values, we get:

75 = 40t₁ + (1/2)(10)t₁²

Simplifying the equation, we get:

5t₁² + 8t₁ - 15 = 0

Solving for t1 using the quadratic formula, we get:

-t₁ = 1.5 seconds or -1 seconds

Since time cannot be negative, we discard the negative solution and conclude that the two cars meet for the first time after 1.5 seconds.

Now, let's find the time it takes for the two cars to meet for the second time. We can use the fact that the two cars have covered the same distance between their first and second meetings.

The distance covered by car Y during the time t₁ is:

d₁ = (1/2)(10)(1.5)² = 11.25 m

The distance remaining between the two cars is:

75 - 2d₂ = 52.5 m

To find the time it takes for car Y to cover this distance, we can use the same kinematic equation as before:

52.5 = 0t₂ + (1/2)(10)t₂²

Simplifying the equation, we get:

t₂ = (21)

Therefore, the time gap between the two meetings is:

t₂ - t₁ = √(21) - 1.5 seconds

So, the time gap between the two meetings is approximately 1.44 seconds.

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Answer:

Yes

Explanation:

The world responsible for saying or wonder the world from this country's government.

If a 5.0 kg hollow disk of radius 2.2 m rolls down a large ramp, then the moment of inertia of the hollow disk is 13.1 kg m^2.

Moment of inertia is a measure of an object's resistance to rotational motion about a particular axis. It is similar to mass in linear motion, as it describes the object's tendency to resist changes in its rotational motion. The moment of inertia of an object depends on its mass distribution, shape, and axis of rotation.

The moment of inertia of a hollow disk is given by

I = (1/2)mr^2,

where m is the mass of the disk and r is the radius.

Substituting the given values, we get:

I = (1/2)(5.0 kg)(2.2 m)^2 = 13.1 kg m^2

Therefore, the moment of inertia of the hollow disk is 13.1 kg m^2.

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Answer:

0.18

Explanation:

The force by effort on the lever is 5.5 N and the load is 1 N. Them actual mechanical advantage of the lever is 0.18.

The lever's mechanical advantage is determined by the output force to input force ratio. This connection demonstrates that, assuming no losses from friction, flexibility, or wear, the mechanical advantage can be calculated from the ratio of the distances from the fulcrum to where the input and output forces are applied to the lever.

The ideal mechanical advantage is calculated as ratio of the distance from the load and the effort from the fulcrum. If we know the actual force acting on both side, we can calculate the actual mechanical advantage (AMA).

The force of effort  = 5.5 N

force by the load on the lever = 1 N

AMA    = load / effort

           = 1 /5.5 = 1.8

Therefore, the mechanical advantage of the lever is 0.18.

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Answer:C

Explanation:

You should just have to do the math and will get you C

The general manager target bonus plan includes financial incentives based on achieving specific performance goals.

The general manager target bonus plan is a type of incentive program that rewards managers for achieving specific performance goals. The plan typically includes financial incentives, such as bonuses or profit sharing, that are tied to the achievement of predetermined goals, such as revenue growth, cost reduction, or customer satisfaction.

The plan may also include other performance metrics, such as employee engagement or operational efficiency. By linking financial incentives to specific performance goals, the plan encourages managers to focus their efforts on areas that are critical to the success of the organization and helps align their interests with those of the company. Overall, the general manager target bonus plan is a key tool for motivating and rewarding managers and driving performance improvement within an organization.

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The gravitational potential energy of the bike racer after climbing a 1500 m long road at 4.3 degrees is 83,851.7 Joules.

To calculate the change in gravitational potential energy during the climb, we can use the formula:

Gravitational Potential Energy (GPE) = m * g * h

Where:
m = mass (76 kg)
g = gravitational acceleration (approximately 9.81 m/s²)
h = vertical height gained

First, we need to find the vertical height gained (h). We can use trigonometry to do this. Since we have the length of the road (1500 m) and the slope (4.3°), we can find the height using the sine function:

sin(slope) = height / length

height = sin(4.3°) * 1500 m

Now, let's calculate the height:

height = 0.0749 * 1500
height = 112.46 m

Now that we have the height, we can calculate the change in gravitational potential energy:

GPE = 76 kg * 9.81 m/s² * 112.46 m
GPE = 83851.7 J (Joules)

The gravitational potential energy changes by 83,851.7 Joules during the climb.

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The gravitational potential energy of the bike racer after climbing a 1500 m long road at 4.3 degrees is 83,851.7 Joules.

To calculate the change in gravitational potential energy during the climb, we can use the formula:

Gravitational Potential Energy (GPE) = m * g * h

Where:
m = mass (76 kg)
g = gravitational acceleration (approximately 9.81 m/s²)
h = vertical height gained

First, we need to find the vertical height gained (h). We can use trigonometry to do this. Since we have the length of the road (1500 m) and the slope (4.3°), we can find the height using the sine function:

sin(slope) = height / length

height = sin(4.3°) * 1500 m

Now, let's calculate the height:

height = 0.0749 * 1500
height = 112.46 m

Now that we have the height, we can calculate the change in gravitational potential energy:

GPE = 76 kg * 9.81 m/s² * 112.46 m
GPE = 83851.7 J (Joules)

The gravitational potential energy changes by 83,851.7 Joules during the climb.

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The distance traveled by the box along the ramp is 0.51 m.

Apply the principle of conservation of energy;

Potential energy of the box at top of incline = Elastic potential energy at bottom

mgh = ¹/₂kx²

where;

h = L sinθ

where;

mg(L sinθ) = ¹/₂kx²

(18)(9.8)(L sin25) = ¹/₂(740)(0.32)²

74.55 L = 37.89

L = 37.89 / 74.55

L = 0.51 m

Thus, the distance traveled by the box along the ramp is 0.51 m.

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