True or False:Datums assure repeatability for location of the part for inspection.

Answers

Answer 1

True, datums play a crucial role in assuring repeatability for the location of a part during inspection. Datums are reference points or surfaces that serve as the basis for measuring and inspecting parts in manufacturing.

They establish a standardized framework that ensures consistent positioning and alignment of parts. During inspection, datums help to maintain accuracy and precision by providing a stable reference point from which measurements can be taken. This ensures that parts are measured and compared in a consistent manner, enabling accurate assessment of whether a part meets its specifications. In summary, datums are essential for guaranteeing repeatability and reliability in the location of parts during inspection. By providing a standardized reference framework, they ensure that measurements and comparisons are conducted accurately and consistently, leading to improved quality control and reduced variation in manufactured parts.

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Related Questions

HELPPPPP Which option identifies the government agency responsible for monitoring the situation in the following scenario? A salmonella outbreak in 2012 was caused by frozen raw yellowfin tuna. More than 100 people became sick from eating the contaminated tuna. Food and Drug Administration Environmental Protection Agency Forest Service Department of Agriculture

Answers

Answer:

Food and drug admin

Explanation:

forty gal/min of a hydrocarbon fuel having a spesific gravity of 0.91 flow into a tank truck with load limit of 40,000 lb of fuel. How long will it takee to fill the tank in the truck?

Answers

Answer: 131.75minutes

Explanation:

First if all, we've to find the density of liquid which will be:

= Specific gravity × Density to pure water

= 0.91 × 8.34lb/gallon

= 7.59lb/gallon

Then, the volume that's required to fill the tank will be:

= Load limit/Density of fluid

= 40000/7.59

= 5270.1gallon

Now, the time taken will be:

= V/F

= 5270.1/40

= 131.75min

It'll take 131.75 minutes to fill the tank in the truck.

observation that r2 and /?3 in effect are in parallel (because the ideal op amp forces a virtual ground at the inverting input terminal). use this observation to derive an expression for the gain (v()/vt) by first finding (vx/vz) and (v0/vx). for the latter use the voltage-divider rule applied to /?4 and (/?21| /?3)

Answers

Rx is the individual resistor across which the output voltage drop is being measured, and VRx is the voltage divider formula for a circuit with many resistors.

The distribution of the input voltage among the divider's parts produces voltage division. Two resistors linked in series with the input voltage applied across them and the output voltage emerging from the connection between them serve as a straightforward example of a voltage divider. The currents flowing through the resistors R1 and R2 are I1 and I2, respectively, while the voltage across each element is VS. At node P, the KCL equation will be. IS=I1+I2. Replace I1=VSR1 and I2=VSR2 in the equation above.

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Computers designed using the von Neumann Architectures have two buses: one for data and one for instructions

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It should be noted that the computers designed using the von Neumann Architectures do not have two buses. Therefore, the statement is false.

Von-Neumann Architecture

It should be noted that Von-Neumann Architecture is made of three major bus systems for data transfer.

The Address Bus carries the address of data between the processor and the memory.

The Data Bus carries data between the processor, the memory unit, and the input or output devices.

The Control Bus carries signals from the central processing unit.

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A printers display shows no reading the problem might be

Answers

Put your printer through a hard reset. Try turning off both the printer and your computer, then restarting both if that doesn't fix the problem. Then try to remove and reinstall your printer's driver.

What causes printing errors?

A problem with the printer itself may exist if the status of your printer reads "Printer in error state." Check to see if the printer is on and wired or wirelessly linked to your computer. Make sure the cover is closed and the paper isn't jammed, and check if there isn't enough paper or ink.

Of all printer errors, paper jams are arguably the most dreadful. There are a few problems that might be present when it comes to smudges, faded lettering, and poor image quality.

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This might count as engineering, I'm not sure as this is IT



An ordered collection of data elements stored and accessed in a program is called what?
Group of answer choices

Variables

List

Locale

Parameters

Answers

Answer:

10.5

Explanation:

Convert to an equation for example P%* X=Y

P is 7.5% X is 140, so the equation Is 7.5 percent * 14= Y

convert 7.5% Into a decimal by removing the percent sign and deviding by 7.5/100= 0.075

Substitute 0.075 for 7.5% in the equation: 7.5%*140=Y becomes 0.075*140= 10.5

In 1984, General Motors (GM) and Toyota opened NUMMI as a joint venture in California. The venture was
dissolved and the NUMMI plant was finally closed after GM declared bankruptcy in 2009. After listening to the Podcast NUMMI Case Study (approx 60 min), write essay regarding causes of GM's failure to introduce the lessons learnt from the NUMMI venture across other factories in the GM network. The report should be focused onthe examination and analysis of the specific issues presented in the case study/podcast.

Answers

GM's failure to introduce the lessons learned from the NUMMI venture across other factories in the GM network can be attributed to several key factors presented in the case study/podcast. These factors include:

Resistance to change: GM's corporate culture and long-established practices made it difficult for the company to embrace the new production methods and employee empowerment strategies implemented at NUMMI. The hierarchical structure and lack of open communication within GM hindered the dissemination of knowledge and best practices across other factories.

Lack of leadership alignment: The case study highlights how the top leadership at GM was not fully aligned with the principles and practices implemented at NUMMI. Without strong support and commitment from top management, it was challenging to drive the necessary changes and replicate the success of the joint venture.

Inadequate training and education: The NUMMI venture emphasized the importance of training and developing employees to build a skilled and engaged workforce. However, GM failed to invest in similar training programs and employee development initiatives across its other factories. This lack of investment in human capital resulted in a workforce that was resistant to change and unable to fully adopt the NUMMI principles.

Resistance from labor unions: The case study points out that the UAW, the main labor union representing GM workers, was skeptical of the NUMMI venture and resistant to some of the changes proposed. This resistance made it difficult for GM to implement the lessons learned from NUMMI across its unionized factories.

GM's failure to introduce the lessons learned from the NUMMI venture can be attributed to resistance to change, lack of leadership alignment, inadequate training and education, and resistance from labor unions. Overcoming these challenges would have required a fundamental shift in GM's culture, stronger leadership support, investment in training and education, and collaborative efforts with labor unions.

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The spiral grooves in a drill body are used to do all of the following except?

Answers

The spiral grooves in a drill body help to form the cutting edge of the drill point; curl chips for easier removal; and, form channels through which the chips can escape from the hole.

If a PPE doesn’t fit properly do you keep wearing them

Answers

No, cuz it wouldn’t protect u properly

to fulfill mr prerequisite storage & collection of recyclables, which item is not required to be separated out?

Answers

To fulfill the prerequisite of storage and collection of recyclables, the only item that may not need to be separated out is non-recyclable waste

To fulfill the prerequisite of storage and collection of recyclables, the only item that may not need to be separated out is non-recyclable waste. However, it is important to note that this can vary depending on local recycling regulations and guidelines. It is always best to check with your local waste management or recycling facility to ensure that you are properly separating and disposing of your items.

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Zone, n = (sum of digits of your student id)% 8 for example, if your student id is 17301283, zone = (1+7+3+0+1+2+8+3) % 8 = 25 % 8 = 1 derive midpoint line drawing algorithm for a line in zone n. if you find zone 0, i.e., then drop the last digit from sum and take % 8 again. if your student id is 16240524, zone = (1+6+2+4+0+5+2+4)%8 = 24%8 = 0 updated zone by removing last digit 4 = (1+6+2+4+0+5+2)%8 =20%8 = 4 derive midpoint circle drawing algorithm for the arc of the circle in zone n. if you find zone 1, i.e., then drop the last digit from sum and take % 8 again. if your student id is 17301283, zone = (1+7+3+0+1+2+8+3)%8 = 25%8= 1 updated zone by removing last digit 3 = (1+7+3+0+1+2+8)%8 = 22%8= 6

Answers

nick needs to take shower and shower so we could do it

A hydrogenation catalyst is prepared by soaking alumina particles (100-150 mesh size) in aqueous NiNO3 solution. After drying and reduction, the particles contain about 7 wt% NiO. This catalyst is then made into large cylindrical pellets for rate studies. The gross measurements for one pellet are: Mass, g 3.15 Diameter, mm 25 Thickness, mm 6 Volume, cm3 3.22 The alumina particles contain micropores, and the pelleting process introduces macropores surrounding the particles. If the macropore volume of the pellet is 0.645 cm3 and the micropore volume is 0.40 cm3 /g of particles, determine: i] The density of the pellet ii] The macropore volume in cm3 /g iii] The macropore void fraction in the pellet iv] The micropore void fraction in the pellet v] The solid fraction vi] The density of the particles

Answers

i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.

i] To determine the density of the pellet, we can use the formula:

Density = Mass / Volume

Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:

Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)

ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):

Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)

iii] The macropore void fraction in the pellet can be calculated using the formula:

Macropore void fraction = Macropore volume / Total volume of the pellet

Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}

Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%

iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):

Micropore volume in the pellet = Micropore volume/g x Mass

Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3

Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet

Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%

v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:

Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)

Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%

vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:

Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)

Density of the particles = Mass / Total volume of the particles

Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)

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in python, modules of statements that perform a specific task are called

Answers

Answer:

In Python, modules of statements that perform a specific task are called functions. These functions can be defined within a program or separately in libraries and can be used by many programs. A function is a group of related statements that performs a particular task and runs only when it is called . Parameters can be passed into a function, and it can be designed to return a value to the calling program. Python comes with prewritten functions in libraries, and users can also define their own functions for reuse and sharing in other programs. The def keyword is used to define a function in Python, and a function can be called using the function name followed by opening and closing parentheses. Functions are a powerful programming tool and are an essential mechanism for sharing and trading software.

Explanation:

FILL INN THE BLANK To select multiple sketch entities, press and hold down the ______ key on the keyboard while selecting multiple entities.

Answers

Press the Ctrl keys on the keyboard while choosing multiple sketch entities, holding the key down.

What is the proper click sequence for a three-point arc?

First, choose the 3 point arc tool to start drawing an arc.To set your starting point, click on the first position.To choose your second paragraph, the arc's endpoint, click inside the second place. Next, click in the third position to choose the radius.

What shortcut on the keyboard can be used to launch the sketching dimension tool?

You may access the sketch size tool from the sketching dropdown list, which is located at the bottom of this list.The letter "D," as in Delta, on the keyboard shortcuts can also be used to activate it.

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With the changing demand patterns, fewer full bins are being required and a
greater proportion of goods need to be picked at the picking stations. What
alternatives may be considered to accommodate this?
Should home shopping continue to have its own dedicated area within the
SANDC, with its own inventory and OSR equipment? How flexible is a
SANDC to such changes in demand patterns, and what are likely to be the key
implementation issues for any future operational change?
• Continuous improvement is being sought in all operations. How can the present
SANDC operation be improved still further in terms of efficiency, service levels,
ergonomics and sustainability? What areas may be worthy of examination?

Answers

The alternative that could be thought of in order to accommodate changing demand patterns is to increase the number of bins to manage the picking of orders which would accommodate a large number of orders from diverse customers.

What alternatives may be considered to accommodate this?

To accommodate changing demand patterns, the number of picking stations and number of pickers can also be increased in order to manage the orders of customers efficiently.

Home shopping should continue to have its own dedicated area within the SANDC, with its own inventory and OSR equipment as it helps for easier assemblage and storage.

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What 2 things can you never eat for breakfast?

i know the answer but lets see if you do

Answers

Answer:

you can't eat your school computer or a pencil.

u can’t eat a shoe or clock

A soil sample, taken from a borrow pit has a specific gravity of soil solids of 2.66. The sample was taken to a materials laboratory and tested. The results of a standard Proctor test are tabulated below.

Weight of Soil (lb) Moisture Content (%)
3.20 12.8
3.78 13.9
4.40 15.0
4.10 15.7
3.70 16.6
3.30 18.1

The maximum dry density in lb/ft3 is most nearly:_______

Answers

Answer:

115 Ib/ft^3

Explanation:

To determine the maximum dry density in Ib/ft3 we have to calculate :

Bulk unit weight ( yb ) ; W / v

Dry unit weight ( yd. ) :  yb / ( 1 + w )

For every set of data given

assuming  v = 1/30 ft^3

calculating for the 3 data set ( maximum dry density )

weight of soil (W) = 4.40

moisture content (%) (w) = 15.0 = 0.15

Bulk unit weight (yb) = 4.40 / (1/30)  = 132 Ib/ft^3

Dry unit weight ( yd. ) = 132 / ( 1 + 0.15 ) = 114.702 Ib/ft^3

therefore after calculations the maximum dry density in Ib/ft^3 ≈ 115 Ib/ft^3

How are concepts of risk and safety in cellular phones and
automotive industry relevant to engineers? Discuss.

Answers

The concepts of risk and safety are highly relevant to engineers in both the cellular phone and automotive industries.

Engineers play a crucial role in designing, developing, and manufacturing products that meet safety standards and minimize risks for users. Let's discuss their relevance in each industry:

1. Cellular Phones:

In the cellular phone industry, engineers are responsible for ensuring the safety of the device and its components. They need to consider various risks associated with phone usage, such as battery explosions, electromagnetic radiation, and overheating. By conducting thorough risk assessments and implementing safety measures, engineers can minimize these risks. They work on designing robust battery systems, implementing heat dissipation mechanisms, and complying with regulatory standards to ensure user safety. Engineers also focus on reducing the risk of cybersecurity threats by developing secure software and encryption protocols to protect user data.

2. Automotive Industry:

Safety is a critical concern in the automotive industry, and engineers play a vital role in designing vehicles with advanced safety features. They focus on minimizing risks related to collisions, occupant protection, and vehicle stability. Engineers work on developing innovative safety systems, such as anti-lock braking systems (ABS), electronic stability control (ESC), adaptive cruise control, and collision avoidance technologies. They also conduct extensive testing and simulation to ensure compliance with safety regulations and standards, including crash tests and impact analysis. By considering potential risks and prioritizing safety features, engineers contribute to reducing accidents and enhancing the overall safety of vehicles.

In both industries, engineers are responsible for identifying potential risks, conducting risk assessments, and implementing appropriate safety measures. They collaborate with cross-functional teams, including designers, researchers, and regulatory experts, to integrate safety considerations into the product development process. By prioritizing risk mitigation and safety, engineers help protect users and ensure the reliability and trustworthiness of cellular phones and automotive products.

Overall, engineers play a critical role in enhancing safety standards and reducing risks in the cellular phone and automotive industries. Their expertise and dedication to safety contribute to the continuous improvement of these technologies and safeguarding users' well-being.

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What sub-discipline of Mechanical Engineering focuses
heavily on vehicle design and testing?
Geothermal Engineering
Automotive Engineering
Biomedical Engineering
Architectural Engineering

Answers

Automotive I believe

Answer:

Automotive engineering

If he continues to work here for the next 10 years, how often should he reobtain informed consent? should this be done at regular time intervals? or should it be done only when something changes (for example, if he moves to a different excavation area at the site)?

Answers

It is generally recommended that informed consent should be obtained at regular intervals, such as annually or semi-annually, in order to ensure that the participant has not changed their mind about the research.

It should also be obtained whenever something changes that could affect the participant's willingness to participate, such as a change in their medical condition or a move to a different excavation area.

Furthermore, it is important to document all aspects of the informed consent process, including when and how the consent was obtained, in order to ensure that the participant's consent is valid and has been properly obtained.

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under what soil and load conditions would a caisson installation be used to support a building instead of driven piles?

Answers

When soil with sufficient bearing strength is discovered beneath weak surface materials like fill or peat, it is exploited.

It is a type of deep foundation that is built above system level, then sunk to the necessary level by removing material from inside the caisson by excavating or dredging. An anchor for a foundation is a caisson, a watertight structure. Imagine that you need to construct a pier. That pier may be stationary or floating. If it's a fixed pier, the foundation of the structure on the water's surface will be a caisson. In areas with soft ground or deep water, caisson construction is employed as a foundation.

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The following scores represent the final examination grade for an elementary statistics course:-

23 60 79 32 57 74 52 70 82 36 80 77 81 95 41 65 92 85 55 76 52 10 64 75 78 25 80 63 98 74 80
81 67 41 71 83 54 64 72 88 62 74 43 60 78 89 76 84 48 84 90 15 79 34 67 17 82 69 80 85 61 62


i.Find its Mean, Median, and Mode (Use first 10 observations)
ii.Make a grouped frequency distribution of this data and again calculate Mean, Median, and Mode.

Answers

The answer of the following statistics course will be:

i. Mean: 64.7

Median: 67

Mode: 70

ii. Mean: 69.4

Median: 72

Mode: 76

What is statistics?

Statistics is the study of data gathering, organisation, analysis, interpretation, and presentation. It is customary to begin with a statistical population or a statistical model to be researched when applying statistics to a scientific, industrial, or social problem. Populations can refer to many groupings of people or objects, such as "all people in a country" or "every atom in a crystal." Statistics is concerned with all aspects of data, including data collection planning in the form of survey and experiment design.

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A standard carbon resistor has a gold band to indicate + 5% tolerance. If its resistance is 3,500 , what are the upper and lower limits for its resistance? OA . 3495 - 3505 2 OB. 3300 Q - 3600 0 OC. 3325 N - 3675 OD 3450 - 35500​

Answers

Answer:

  C.  3325 Ω - 3675 Ω

Explanation:

5% of 3500 Ω is ...

  0.05 × 3500 = 175

The lower limit is this amount less than the nominal value:

  3500 -175 = 3325

The upper limit is the nominal value plus the tolerance:

  3500 +175 = 3675

The lower and upper limits are 3325 Ω and 3675 Ω, respectively.


If Alice wants to send Bob some Bitcoin, what information mast Bob first give to Alice?
A Transaction fees
B. Public key
C. Private key
D. Pablic and private keys, called a key pair

Answers

The information which Bob must given to Alice is B. Public Key.

Why is this?

Bob must give Alice his public key so that Alice can send the Bitcoin to Bob's public key address, which serves as the destination for the transaction.

The private key is kept secret and is used to access the Bitcoin stored at the corresponding public key address. The transaction fee is paid to the network to process the transaction and is separate from the amount being sent.

Therefore, the correct answer is B. Public key.

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what is the law of physics


10 points if you tell me the answer and your name

Answers

꧁༒Answer༒꧂

F=m•a

\(f = force\)

\(m = mass \: of \: an \: object\)

\(a = acceleration\)

Newton's second law is one of the most important in all of physics. For a body whose mass m is constant, it can be written in the form F = ma, where F (force) and a (acceleration) are both vector quantities. If a body has a net force acting on it, it is accelerated in accordance with the equation

TRUE / FALSE. once the monitor finishes processing the character on the screen, dsr[15] becomes 1

Answers

Once the monitor finishes processing the character on the screen, dsr[15] becomes 1. False. The statement is incorrect.

The DSR (Data Set Ready) signal is a hardware signal typically used in serial communication protocols. It is a handshake signal indicating the readiness of a data set or device to receive or send data. In the context of a monitor, DSR is not directly related to processing characters on the screen.

The processing of characters on a monitor typically involves the rendering of pixels based on the input data. Once the rendering process is completed, the monitor may update the screen accordingly. However, this process does not automatically trigger a change in the DSR signal. The DSR signal depends on the specific hardware and communication protocol being used and is typically controlled by the transmitting or receiving device, not the monitor itself.

Therefore, the statement that DSR[15] becomes 1 after the monitor finishes processing a character on the screen is false. The completion of character processing on the screen does not have a direct impact on the DSR signal.

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3. Suppose up to 300 cars per hour can travel between any two of the cities 1, 2, 3, and 4. Formulate a maximum flow problem that can be used to determine how many cars can be sent in the next two hours from city 1 to city 4. Give the network diagram and the LP formulation for your model.

Answers

Let $x ij$ represent the quantity of cars that will be delivered in the following two hours from city I to city j.

Create a maximum flow issue?

Network Diagram:

LP Formulation:

Maximize Z = 150x14 + 150x24

Subject to:

x11 + x12 + x13 + x14 <= 300 (flow from city 1 to other cities)

x21 + x22 + x23 + x24 <= 300 (flow from city 2 to other cities)

x31 + x32 + x33 + x34 <= 300 (flow from city 3 to other cities)

x41 + x42 + x43 + x44 <= 300 (flow from city 4 to other cities)

x11 + x21 + x31 + x41 = 150 (flow into city 1)

x12 + x22 + x32 + x42 = 150 (flow into city 2)

x13 + x23 + x33 + x43 = 150 (flow into city 3)

x14 + x24 + x34 + x44 = 150 (flow into city 4)

xij >= 0 (all variables must be positive)

Where xij represents the number of cars traveling from city i to city j in two hours.

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a storage tank contains liquid with a density of 0.0361 lbs per cubic inch. the height of liquid in the tank is 168 feet. what is the pressure of the liquid at the bottom of the tank give your answer in psi

Answers

Answer:

Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:

Float on water:  d < 0.0361 lb/in³ (where d denotes denisity)

Do not float on water:  d > 0.0361 lb/in³

Explanation:

I don't know if this works for it or not?

Which of the following would zoning ordinances not address?


how tall a skyscraper can be

how much revenue a restaurant must make

how far from a school a power plant must be

how many parking spots a mall must have

Answers

I’m pretty sure it’s how much revenue a restaurant must make

Water flows steadily through the pipe as shown below, such that the pressure at section (1) and at section (2) are 300 kPa and 100 kPa respectively. Determine the diameter of the pipe at section (2), D, if the velocity at section (1) is 20 m/sec and viscous effects are negligible.

Answers

Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

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