true/false. a circular field may be induced into a specimen by: passing current directly through the part.
Answers
True. A circular field may be induced into a specimen by passing current directly through the part.
The specimen is often formed in a circular or annular geometry in order to introduce a circular magnetic field into it. The specimen is in close proximity to or in contact with a current-carrying coil or conductor. A magnetic field is created around a conductor or coil as current flows through it, and the magnetic field lines within the specimen take the shape of a circle.
In several applications, circular magnetic field generating is frequently used. Magnetic particle inspection, a non-destructive testing technique used to find surface or near-surface flaws in materials, is one such use. Magnetic particles can be put to the surface of an item by applying a circular magnetic field to it. Any flaws or discontinuities will cause the particles to align or cluster, making them obvious in the right lighting.
In conclusion, it is possible to create a circular magnetic field inside a specimen by directly applying current to it. The non-destructive testing and inspection techniques in particular can use this phenomenon in a variety of industries.
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Related Questions
Which of the following objects
would have the greatest
gravitational force?
A A table
B The moon
C The Earth
D The sun
Answers
the fireman wishes to direct the flow of water from his hose to the fire at b. determine two possible angles u1 and u2 at which this can be done. water flows from the hose at va
Answers
The two possible angles obtained by using the qudratic equation are;
θ\(_{1}\) = 15.10° and θ2 = 73.51°
Given, speed of water = \(v_{A}\) = 50ft/s
For the motion along x direction, time period can be calculated as follows:
\(s_{x} = (v_{A}) _x_{} } t\)
35 = (50 × cosθ) t
t = 0.64 / cosθ
For the motion in y direction, an equation can be obtained as follows:
\(s_{y} = (v_{A})_{y} t +\frac{1}{2} (a_{y} )t^{2}\)
\(s_{y} = (-v_{A}\)\(sin\)θ) \(} t +\frac{1}{2} (a_{y} )t^{2}\)
Plugging in the values we get:
\(-20 = (-50_\)\(sin\)θ) \(} t +\frac{1}{2} (-32.2} )t^{2}\)
-20 = -32tanθ - 10.304\(sec^{2}\)θ
Upon solving the above quadratic equation, we get,
tanθ = 0.27 , -3.38
Therefore,
tanθ\(_{1}\) = 0.27
θ\(_{1}\) = 15.10°
and, tanθ\(_{2}\) = -3.38
θ\(_{2}\) = 73.51
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Calculating Force ^F=? air Fballoon=-3 N The action force is the balloon pushing the air out. What is the magnitude of the reaction force of the air pushing on the balloon? IN.
Answers
According to Newton's third law of motion, the reaction force exerted by the air on the balloon is equal in magnitude but opposite in direction to the action force exerted by the balloon on the air.
Given that the magnitude of the action force (F_balloon) is -3 N, the magnitude of the reaction force (F_air) will also be 3 N. The negative sign indicates that the forces are in opposite directions, but when considering magnitudes, we ignore the negative sign.
Therefore, the magnitude of the reaction force of the air pushing on the balloon is 3 N.
\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)
♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
the earth takes almost exactly 24 h to make a complete turn on its axis, so we might expect each high tide to occur 12 h after the one before. however, the actual time between high tides is 12 h 25 min. what can account for this
Answers
The time between high tides being slightly longer than 12 hours is due to the gravitational pull of the moon and the sun on the Earth's oceans. As the Earth rotates, the moon's gravity causes a bulge in the ocean on the side of the Earth facing the moon, which creates a high tide.
As the Earth continues to rotate, the bulge moves along with the moon's position, causing another high tide on the opposite side of the Earth. However, the Earth is also affected by the sun's gravitational pull, which can either add to or counteract the moon's pull depending on the positions of the sun, moon, and Earth. This complex interplay of gravitational forces causes the time between high tides to vary slightly from the expected 12 hours.
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1.-Sean los siguientes vectores A=3i + 2j - 7 k B=3J + 6 K + 5 i Hallar a) |A| b) A+B c) |A+B| d) A-B e) 2A+3B
Answers
Answer:
A = 2,
Explanation:
(3 + 2) - 7
2 - A: 2
3 + 6 + 5
14 - B: 14
YOUR WELCOME
A 0.57 kg rubber ball has a speed of 2.2 m/sat point A and kinetic energy 8.0 J at pointB. Finda) the ball’s kinetic energy at A.Answer in units of J.015 (part 2 of 3) 10.0 pointsb) the ball’s speed at B.Answer in units of m/s.016 (part 3 of 3) 10.0 pointsc) the total work done on the ball as it movesfrom A to B.Answer in units of J.
Answers
Given that the mass of the ball is m = 0.57 kg.
The speed of the ball is
\(v_A=2.2\text{ m/s}\)A) The kinetic energy at point A will be
\(\begin{gathered} K\mathrm{}E._A\text{ =}\frac{1}{2}m(v_A)^2 \\ =\frac{1}{2}\times0.57\times(2.2)^2 \\ =1.38\text{ J} \end{gathered}\)B) Given that the kinetic energy,
\(K\mathrm{}E._B=\text{ 8 J}\)The ball's speed at point B will be
\(\begin{gathered} K\mathrm{}E._B=\frac{1}{2}m(v_B)^2 \\ v_B=\sqrt[]{\frac{2K.E._B}{m}} \\ =\sqrt[]{\frac{2\times8}{0.57}} \\ =5.298\text{ m/s} \end{gathered}\)C) The total work done on the ball to move from point A to B is
\(\begin{gathered} W=K\mathrm{}E._B-K.E._A \\ =8-1.38\text{ } \\ =6.62\text{ J} \end{gathered}\)an electromagnetic wave with a wave length about the same as the diameter of an apple would be
Answers
An electromagnetic wave with a wavelength about the same as the diameter of an apple, which is approximately 10 centimeters, would be a radio wave.
Radio waves are part of the electromagnetic spectrum, which includes a wide range of wavelengths and frequencies. The spectrum is divided into different categories, such as radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. Radio waves have the longest wavelengths and lowest frequencies among the categories of the electromagnetic spectrum. They are used for various purposes, such as communication, broadcasting, and navigation.
Radio waves with a wavelength of about 10 centimeters fall into the Ultra High Frequency (UHF) band, which ranges from 300 MHz to 3 GHz. UHF radio waves are utilized in television broadcasting, cell phone communication, and satellite systems. In summary, an electromagnetic wave with a wavelength comparable to the diameter of an apple would be classified as a radio wave, specifically within the UHF band. This type of radio wave is commonly used in modern communication and broadcasting technologies.
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A 5.00-kg sphere is moving at a speed of 4.00 m/s. An identical sphere is at rest. The two spheres collide. The first sphere moves off at a 60.0° angle to the left of its original path. The second sphere moves off in a direction 90.0° to the right of the first sphere’s final path. Assuming no friction, what are the speeds of the two spheres as they separate?
Answers
The final speeds of the spheres are 3.47 m/s and 3.08 m/s.
We can use conservation of momentum to solve this problem since there are no external forces acting on the system.
The initial momentum of the system is:
p_initial = m₁ * v₁ + m₂ * v₂
where m₁ and m₂ are the masses of the spheres, and v₁ and v₂ are their initial velocities (4.00 m/s and 0 m/s, respectively).
After the collision, the momentum of the system is:
p_final = m₁ * v1' + m₂ * v₂'
where v₁' and v₂' are the final velocities of the spheres. We also know that the angle between the first sphere's final path and its initial path is 60 degrees, which means that the angle between the two spheres after the collision is 150 degrees (90 + 60).
Using conservation of momentum, we can set the initial and final momenta equal to each other:
m₁ * v₁ + m₂ * v₂ = m₁ * v₁' + m₂ * v₂'
We can also break down the final velocities into their x and y components using trigonometry. Let's define the angle between the first sphere's final path and the x-axis as theta. Now we can use conservation of momentum to solve for the final velocities:
m₁ * v₁ + m₂ * v₂ = m₁ * v₁' * cos(theta) + m₂ * v₂' * cos(150 degrees)
0 = m₁ * v₁' * sin(theta) + m₂ * v₂' * sin(150 degrees)
Solving the first equation for v₂', we get:
v₂' = (m₁ * v₁ + m₂ * v₂ - m₁ * v₁' * cos(theta)) / (m₂ * cos(150 degrees))
Substituting this expression into the second equation and solving for v₁', we get:
v₁' = (m₂ * sin(150 degrees) * v₁ + m₂ * sin(150 degrees) * v₂ + m₁ * sin(theta) * v₁' - m₁ * sin(theta) * m₂ * v₁ * cos(theta) / cos(150 degrees)) / (m₁ * sin(theta))
Plugging in the given values and solving, we get:
v₁' = 3.47 m/s
v₂' = 3.08 m/s
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A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration
a
=(5.0
i
^
+7.0
j
^
)m/s
2
. At time t=0 the velocity is (5.0
i
^
)m/s. What are the (a) magnitude and (b) angle of its velocity when it has been displaced by 11.0 m parallel to the x axis? (a) Number Units (b) Number Units
Answers
The magnitude of the velocity, when the pebble is displaced by 11.0 m parallel to the x-axis, is 9.21 m/s and the angle of the velocity is 27.7°.
Given:
Acceleration (a) = 5.0i + 7.0j m/s²
Initial velocity (v₀) = 5.0i m/s
Displacement (Δx) = 11.0 m
X-component:
Using the equation of motion:
\(\Delta x = v_ox \times t + \frac{1}{2} \times ax \times t^2\)
Since the pebble is moving only in the x-direction, the y-components do not contribute to the displacement. Therefore, the y-component equation simplifies to:
\(0 = v_oy \times t + \frac{1}{2} \times ay \times t^2\)
From the given information,
v₀x = 5.0 m/s
v₀y = 0 m/s
Simplifying the x-component equation:
\(11.0 = 5.0 \times t + \frac{1}{2} \times 5.0 \times t^2\)
Simplifying the equation:
\(5t^2 + 5t - 11 = 0\)
Using the quadratic formula:
\(t = -b +- \sqrt{\frac{(b^2 - 4ac)}{2a}}\)
Applying the values:
\(t = -5 +- \sqrt{\frac{5^2 - 45\times -11 }{2\times5}\)
t = 0.61 s
Velocity components:
\(v_x = v_ox + a_x \times t\\v_y = v_oy + a_y \times t\)
From the given information:
\(a_x = 5.0 m/s^2\\a_y = 7.0 m/s^2\)
Calculating the velocity components:
\(v_x = 5.0 + 5.0 \times 0.61\)
= 8.05 m/s
\(v_y = 0 + 7.0 \times 0.61\)
=4.27 m/s
(a) Magnitude of the velocity:
The magnitude of the velocity is given by the Pythagorean theorem:
\(|v| = \sqrt{(v_x^2 + v_y^2)}\\\)
\(|v| = \sqrt{((8.05 m/s)^2 + (4.27 m/s)^2)}\\|v| = 9.21 m/s\)
(b) Angle of the velocity:
The angle of the velocity can be found using the inverse tangent function:
\(\theta = \frac{1}{tan}\times \frac{v_y}{v_x}\\\theta = \frac{1}{tan}\times \frac{4.27}{8.05}\\\theta = 27.7^o\)
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3. Two fans blow at 5 ms^-1 in a easterly direction and 8ms^-1 in a Northerly
direction. What is the total wind speed of both fans combined?
Answers
Addition of vectors is done by adding the components of the vectors
The total speed of the fan is approximately 9.43 m/s,
Direction of total wind 58° counterclockwise from the positive x-axis
The reason the value is correct is as follows:
The given parameters are:
The direction at which the fan blowing at 5 m/s is blowing = Easterly
The direction in which the fan blowing 8 m/s is blowing = Northerly
The total speed of the van, |v| ≈ 9.43 m/s
Required:
To find the total wind speed of the fans
Solution:
Taken the easterly direction as the ith component, and the northerly direction as the jth component, the vector representing the speed of the fan is presented as follows
v = 5·i + 8·j
The magnitude of the total wind speed of the fan, |v| = √(5² + 8²) = √(89) ≈ 9.43
The total wind speed of the fan , |v| ≈ 9.43 m/s
The direction of the total speed with respect to the x-axis, θ, is given as follows;
θ = arctan(8/5) ≈ 58°
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. 8 quarts = ________ pints 12 pints 10 pints 4 pints 16 pints
Answers
Answer:
According to my calculations it equals to 16 pints
Explanation:
You know that there is a calculator online for this stuff right?
It is required to design a zener shunt regulator to provide a regulated voltage of about 10 V. The available 10-V, 1-W zener of type 1N4740 is specified to have a 10-V drop at a test current of 25 mA. At this current, its r z is 7 . The raw supply, V S , available has a nominal value of 20 V but can vary by as much as ±25%. The regulator is required to supply a load current of 0 mA to 20 mA. Design for a minimum zener current of 5 mA.
Answers
Answer:
jgfsdghjjuk
Explanation:
khhnghjj
2 QUESTIONS!! PLEASE HELP QUICK
1. true or false: Balanced forces acting on an object result in constant velocity
2. If one of the cars starts and ends at the same point in the race (making a loop around the track), what is the car's displacement?
0
1
2
7.5
Answers
Answer:
1. True 2.0
Explanation:
1. When balanced forces are acting on an object, they have a constant velocity, meaning that the velocity remains the same.
2. When an object begins at a starting point and returns back to that same starting point, its displacement would be 0.
I'm pretty confident in these answers, however, you must have studied this more than me, so let me know if you have any questions or concerns at all, I'll be glad to help. :)
no files.
Please hurry I’m not trynna fail
Answers
Answer:
Larger, because both the Sun and Moon are pulling it.
Explanation:
can velocity be negative with respect to the direction?
Answers
Answer: Yes!
Explanation: Think of a number graph. If we go right it will be positive and if we go left it'll be negative. Like this the velocity can me negative or positive based on the direction.
2.
Hussein is mowing the lawn with an applied force of 8 N but there is a little elf pushing back with a force of 6 N.
Is it balanced or unbalanced
Answers
Answer:
Explanation:
lll
Answer:
Unbalanced
Explanation:
Hussein is pushing 2 N harder.
If you wanted to see the EM wave produced by the iclicker with your eyes, which of the following would work? (Note: Your eyes are sensitive to EM waves with frequency around 1014 Hz) Run away from the iclicker when it is voting. Run toward the iclicker when it is voting. Neither will work, moving relative to the iclicker won't change the frequency reaching your eyes. Suomiteo submisons for this question. Only You currently have O submissions for this question. Only 5 submission are allowed You can make 5 more submissions for this question
Answers
Neither will work, moving relative to the iclicker won't change the frequency reaching your eyes enough to make it visible.
To determine if you can see the EM wave produced by the iclicker with your eyes, let's consider the given options:
1. Run away from the iclicker when it is voting.
2. Run toward the iclicker when it is voting.
3. Neither will work, moving relative to the iclicker won't change the frequency reaching your eyes.
Your eyes are sensitive to EM waves with a frequency of around 10^14 Hz. Moving toward or away from the iclicker will cause a Doppler effect on the perceived frequency. However, the frequency of the EM waves produced by the iclicker is likely to be significantly lower than 10^14 Hz, so any change due to the Doppler effect will still not bring the frequency into the visible range for your eyes.
Therefore, the correct answer is: Neither will work, moving relative to the iclicker won't change the frequency reaching your eyes enough to make it visible.
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How does temperature change from planets to planets in our solar system?
Answers
The further a planet is from the Sun, the colder its surface temperatures tend to be. Venus is an exception, since it has the highest surface temperature in our solar system due to its close closeness to the Sun and its thick atmosphere.
What was the temperature of the solar system when the planets first formed?The inner planets are rocky, whereas the outer planets are gaseous, which can be attributed to the early solar system's temperature. The solar system's temperature increased as the gases came together to create a protosun. Temperatures in the inner solar system reached 2000 K, whilst in the outer solar system, it was only 50 K.
The quantity of heat received is just one of many intricate aspects that go into determining the temperature.
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what is the wavelength of such a wave? the speed of sound in air is 340 m/s.
Answers
Answer:
wavelength is λ=fv=440340=0. 77m.
If Styrofoam has a specific heat of 1131 J/kg°C, how much energy would it take to change a 0.5 kg Styrofoam cooler from 15°C to 2°C?
Answers
Answer:
.
Explanation:
6. A student placed a cardboard box at the
bottom of a hill. The student then released a
ball from a point on the hill. The ball collided
with the box, and the box moved a distance
of 2 meters before both the box and the ball
came to rest. Which change to the initial
conditions would be most likfly to result in
the box moving a greater distance?
A. Decreasing the mass of both the ball and the
box
B. Decreasing the mass of the ball and
increasing the mass of the box
C. Increasing the mass of the ball and
releasing it from a lower point on the hill
D. Decreasing the mass of the box and
releasing the ball from a higher point on
the hill
Answers
The correct option for the given question is D. Decreasing the mass of the box and releasing the ball from a higher point on the hill.
A cardboard box was placed at the bottom of a hill, and a ball was released from a point on the hill. The box moved a distance of 2 meters before coming to rest, along with the ball. To move the box a greater distance, a change in the initial conditions is required. It can be achieved by decreasing the mass of the box and releasing the ball from a higher point on the hill.
According to the law of conservation of momentum, the total momentum before and after the collision is conserved. If the mass of the box is decreased, its momentum will be less after the collision. Therefore, the momentum of the ball will be greater than the momentum of the box, allowing it to move the box to a greater distance. Thus the correct option is Option D.
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what is the surface temperature of a star that has a peak wavelength of 400 nm? choose the answer that is closest to the calculated value.
Answers
The surface temperature of a star that has a peak wavelength of 400 nm is approximately 7245 K.
It can be calculated using Wien's Law, which states that the peak wavelength of a black body radiation curve is inversely proportional to the surface temperature of the object. The formula for Wien's Law is:
λmax = b/T
where λmax is the peak wavelength, b is a constant (2.898 x 10^-3 mK), and T is the surface temperature in Kelvin.
Rearranging the formula to solve for T, we get:
T = b/λmax
Substituting λmax = 400 nm = 4 x 10^-7 m, we get:
T = (2.898 x 10^-3 mK) / (4 x 10^-7 m) = 7245 K
Therefore, the surface temperature of a star that has a peak wavelength of 400 nm is approximately 7245 K.
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A particle of mass 16kg travelling with a velocity of 10m/s is acted upon by a steady force of friction in a direction opposite that of its motion. Find the speed of the particle after 10 seconds if the force of friction is 25N.
Answers
The speed of the particle after 10 seconds is, 25.88m/s.
To find the answer, we have to know more about the equations of motion.
How to find the speed of the particle after 10s?It is given that,\(m=16kg\\u=10m/s\\t=10s\\f=25N\)
It is clear from the question that, the motion is balanced by the frictional force. Thus, the acceleration will be,\(ma=f\\a=\frac{f}{m} =\frac{25}{16}=1.6m/s^2\)
We have the equation of motion for the distance travelled as,\(S=ut+\frac{1}{2}at^2=(10*10)+(\frac{1.6*10^2}{2})=178.13m\)
Thus, by another equation of motion connecting a, S, and u, we get the final speed after 10s as,\(v=\sqrt{u^2+2aS} =\sqrt{10^2+(2*1.6*178.13)} =25.88m/s\)
Thus, we can conclude that, the speed of the particle after 10 seconds is, 25.88m/s.
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The driver of a car slams on the brakes, causing the car to slow down at a rate of
20.0ft/s as the car skids 295ft to a stop.
How long does the car take to stop?
What was the car’s initial speed?
Answers
Answer:
The time taken for the car to stop is 5.43 s.
The initial velocity of the car is 108.6 ft/s
Explanation:
The following data were obtained from the question:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Distance travalled (s) = 295 ft
Final velocity (v) = 0 ft/s
Time taken (t) =?
Initial velocity (u) =?
Next, we shall determine the initial velocity of the car as shown below:
v² = u² + 2as
0² = u² + (2 × –20 × 295)
0 = u² + (–11800)
0 = u² – 11800
Collect like terms
0 + 11800 = u²
11800 = u²
Take the square root of both side
u = √11800
u = 108.6 ft/s
Therefore, the initial velocity of the car is 108.6 ft/s.
Finally, we shall determine the time taken for the car to stop as shown below:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Final velocity (v) = 0 ft/s
Initial velocity (u) = 108.6 ft/s
Time taken (t) =?
v = u + at
0 = 108.6 + (–20 × t)
0 = 108.6 + (–20t)
0 = 108.6 – 20t
Collect like terms
0 – 108.6 = – 20t
– 108.6 = – 20t
Divide both side by –20
t = – 108.6 / –20
t = 5.43 s
Therefore, the time taken for the car to stop is 5.43 s.
a boat has a velocity of 8.0 m/s, east. it is crossing a river that is 20.0 m wide. the current in the river flows south at 5.0 m/s. how long will it take the boat to cross the river? how far downstream does it land from its starting point?
Answers
2.5 seconds long will it take the boat to cross the river and 2m far downstream does it land from its starting point.
How do velocity and speed differ?Velocity is the pace and direction of an item's motion, whereas speed is really the time rate at which a object is travelling somewhere along route. In other words, velocity is a vector, whereas speed is a numerical number.
Briefing:We may simply utilize the boat's velocity along the vector perpendicular to the river in this section of the issue, which is
\($v_x=8.0 \mathrm{~m} / \mathrm{s}$\)
The distance d between the river's two sides is 20.0 meters.
Consequently, the duration of the river crossing is
\($t=\frac{d}{v_x}=\frac{20.0 \mathrm{~m}}{8.0 \mathrm{~m} / \mathrm{s}}=2.5\mathrm{~s}$\)
We must take into account the boat's motion along the direction of the stream, which happens at a velocity of to determine how far the boat will land downstream.
\($v_y=5.0 \mathrm{~m} / \mathrm{s}$\)
According to a prior calculation, it takes 2.5 seconds to traverse the river.
Consequently, the boat will land a distance of
\($d=v_y t=(5.0 \mathrm{~m} / \mathrm{s})(2.5 \mathrm{~s})=2 \mathrm{~m}$\)
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Magnetism is due to the motion of electrons as they _____.
Answers
Spin-based electron motion is what causes magnetism. The spins of electron pairs produce a magnetic moment.
What alters electrons due to magnetism?A weak magnetic field is produced by the electrons of an atom rotating around its nucleus. Most objects' electrons spin randomly, and the magnetic forces acting on them cancel each other out. Because the molecules in magnets are structured so that their electrons spin in the same direction, magnets are unique.
Are electrons responsible for magnetic force?The movement of the electrons within the material's atoms produces these magnetic fields. A characteristic of electrons called the magnetic dipole moment, which is connected to the intrinsic spin of each individual electron, also contributes to them.
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which of the following statement(s) is/are correct? i) stars like the sun generate energy through nuclear fusion.ii) the most stable nucleus in terms of binding energy per nucleon is 56fe.iii) the core of nuclear fission reactors consists of uranium enriched in 235u surrounded by a moderator which slows down the neutrons from the 235u.
Answers
The statements which are correct include the following:
i) Stars like the sun generate energy through nuclear fusion.
ii)The most stable nucleus in terms of binding energy per nucleon is 56fe.
iii) The core of nuclear fission reactors consists of uranium enriched in 235u surrounded by a moderator which slows down the neutrons from the 235u.
What is Nucleus?This is referred to as the dense part which is present at the center of the atom and it comprises of particles such as proton and neutron. Iron -56 is referred to as the most stable nucleus because it has the lowest mass per nucleon of all nuclides.
Nuclear fusion is the process in which two light nuclei merge to form a single heavier nucleus and energy is generated as a result which is used by stars.
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A prize wheel is spinning in a vertical circle when an acceleration of 2.0 rad/s^2 is applied to the edge of the wheel as it spins through 5.0 rad. If the final velocity of the wheel was measured to be 9.0 rad/s, what was the initial velocity of the wheel?
Answers
The initial velocity of the prize wheel from the givens is calculated by using the equation of motion. The initial velocity of the wheel is 7.8 m/s.
From the equation of motion, the initial velocity, final velocity, distance, acceleration, and time was taken are calculated by choosing the appropriate equation. From the given, the final velocity (v) is 9 rad/s, distance(s) is 5 rad, and acceleration (a) is 2.0 rad/s^2.
The equation is
v² = u² + 2as
v²₋ 2as = u²
9² - 2(2)(5) =u²
u² = 61
u = √61
= 7.8 m/s
Thus the initial velocity of the wheel is 7.8 m/s.
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what is the giant impact hypothesis for the origin of the moon?
Answers
The big impact theory is the most widely accepted scientific theory to explain the formation of the moon, which it posits that it originated as a result of a collision between the young earth and a protoplanet the size of Mars, which is called Tea or occasionally orphheus. or orpheus
Please i need the answers now. a) Explain why i) More thermal energy is required to raise the temperature of 2 Kg of a substance by 10°C than is required to raise the temperature of 1 Kg of the same substance by 10°C. ii) A solid expand when heated.
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Answer: find the answer in the explanation
Explanation:
1.) More thermal energy will be required to raise the temperature of 2 Kg of a substance by 10°C than is required to raise the temperature of 1 Kg of the same substance by 10°C.
Because the thermal energy depends on the mass of an object.
If the two materials are the same, then they will have the same specific heat capacity. Thermal energy can be expressed as:
H = MCØ
Where
M = mass of the body
C = specific heat capacity
Ø = change in temperature
H = thermal energy
If u substitute the two values of masses into the formula above, then, the mass of 2kg will produce higher thermal energy .
Il.) Heat causes expansion. Using kinetic theory to explain this, the molecules of solid material are in a fixed pattern, held together with strong bonds. When heat is applied to the solid, the molecules will start vibrating in their fixed position. As a result of this, the bond between the molecules begins to loss. This eventually lead to expansion of solid.