true/false. The gravitational force between the two objects is weak because they are 1 m apart. No gravitational force exists between the two objects because their masses are small.

Answers

Answer 1

The given statement "The gravitational force between the two objects is weak because they are 1 m apart. No gravitational force exists between the two objects because their masses are small." is False.

The gravitational force between the two objects is not weak because they are 1 m apart. The strength of the gravitational force depends on the masses of the objects and the distance between them.
Additionally, it is not true that no gravitational force exists between the two objects because their masses are small. Every object in the universe exerts a gravitational force on every other object, regardless of their masses. However, the strength of the gravitational force will be weaker if the masses are smaller.

So. The gravitational force between the two objects is weak because they are 1 m apart. No gravitational force exists between the two objects because their masses are small is False.

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Related Questions

What is the impact of age on flexibility? A. Younger people tend to develop flexibility more slowly. B. Younger people tend to be more flexible. C. Older people tend to be more flexible. D. Older people cannot maintain their flexibility.

Answers

The answer is B. Younger people tend to be more flexible.

Answer:

the answer is b

Explanation:

a circuit has three resistors connected in series. resistor r2 has a resistance of 200 ohms and a voltage drop of 30 volts. what is the current in resistor r3?

Answers

The current through resistor R3 is 0.33 A. A circuit with three resistors connected in series is shown below: Circuit diagram of three resistors connected in series As per the given information, R2 has a resistance of 200 ohms and a voltage drop of 30 volts.

Therefore, the voltage drop across R1 is V1 = V - V2 - V3V = voltage supplied to the circuit = voltage drop across R1 + voltage drop across R2 + voltage drop across R3R1 = Resistance of resistor R1.R2 = Resistance of resistor R2 = 200 Ω.V3 = Voltage drop across resistor R3.I3 = Current through resistor R3.To calculate the current in resistor R3, let's follow the steps given below.Step 1: Find the voltage drop across R1.Using Ohm's Law, the voltage drop across R2 is V2 = IR2Substitute the values of V2 and R2 to get the value of current I.I = V2/R2I = 30/200I = 0.15 A

Using Kirchhoff's voltage law, the voltage drop across R1 isV1 = V - V2 - V3V = V1 + V2 + V3Substitute the values of V, V2, and V3 to get the value of V1.V1 = V - V2 - V3V1 = 100 - 30 - V1V1 = 70 VStep 2: Find the current through R3.Using Ohm's Law, the voltage drop across R3 is V3 = I3R3.Substitute the values of V3 and R3 to get the value of current I3.I3 = V3/R3I3 = (V - V1 - V2)/R3I3 = (100 - 70 - 30)/R3I3 = 0.33 A

Therefore, the current through resistor R3 is 0.33 A.

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A block is accelerated by a single force. If the magnitude of the force is doubled, what happens to the magnitude of the acceleration

Answers

If the magnitude of a force acting on a block is doubled, what happens to the magnitude of the acceleration? Let's find out. Here's the main answer:If the magnitude of the force acting on the block is doubled, then the magnitude of the acceleration of the block will be doubled as well

.Let's see the explanation below:Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass. The equation is as follows:F = maWhere F is force, m is mass, and a is acceleration. Therefore, if the force applied to an object is doubled, then the acceleration will also double, assuming the mass remains the same.For example, let's say a block has a mass of 2 kg and is being accelerated by a force of 10 N.

Using the equation F = ma, we can calculate its acceleration:a = F/m = 10/2 = 5 m/s²Now, if the magnitude of the force is doubled to 20 N, the acceleration can be calculated as follows:a = F/m = 20/2 = 10 m/s²As you can see, the acceleration has doubled as well because the force was doubled. This is consistent with Newton's second law of motion.

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According to Newton’s first law of motion, when will an object at rest begin to move?

when its inertia decreases to zero
when an unbalanced force acts upon it
when the action and reaction forces are equal
when two equal and opposite forces act upon it

Answers

According to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

option B is the correct answer.

What is Newton's first law of motion?

Newton's first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will continue in motion with a constant velocity unless acted upon by an external force.

In other words, an object will maintain its state of motion (whether it is at rest or moving in a straight line at a constant speed) unless a force acts upon it.

Thus, according to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

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Answer:

its B

Explanation:

Suppose a cheetah running at a velocity of 5 m/s east slows down. After 15 seconds, the cheetah has reached a velocity of 25 m/s. What is the
cheetah's acceleration?

Answers

Answer:

1.33m/s²

Explanation:

Given parameters:

Initial velocity  = 5m/s

Final velocity  = 25m/s

Time taken  = 15seconds

Unknown:

Acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

  Acceleration  = \(\frac{v - u}{t}\)  

  v is the final velocity

  u is the initial velocity

  t is the time taken

 So;

    Acceleration  = \(\frac{25 - 5}{15}\)    = 1.33m/s²

Which of the following statements about independent and dependent variables is accurate? (Choose all that apply)

a. The independent variable is manipulated by the scientist.

b. Both the independent and dependent variables are mentioned in the hypothesis.

c. Experiments test for a relationship between the independent and dependent variable.

d. The independent variables are held constant during an experiment.

e. The dependent variable will never change during the experiment.

Answers

The independent variables are held constant during an experiment. Hence, option (d) is correct.

What are  independent and dependent variables ?

In mathematical modelling, statistical modelling, and experimental sciences, there are dependent and independent variables.

Dependent variables get their name because, during an experiment, their values are examined under the assumption or requirement that they are dependent on the values of other variables due to some law or rule (for example, a mathematical function).

In the context of the experiment under consideration, independent variables are those that are not perceived as dependent on any other factors.

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Turn on the timer and click the green circular button to start a wave pulse. Stop the timer when the wave pulse first hits the end of the string (when the final bead first starts to move). Do this a couple times to get a precise measurement of the time it took the wave pulse to cross the string. What is the wave velocity

Answers

The wave velocity is calculated by dividing the wave pulse's total distance travelled by the length of time it takes to cross the string.

What is Wave velocity?

Wave velocity is the speed at which a wave travels through a medium. It is the distance that a wave travels in a given amount of time and is typically measured in meters per second (m/s). The velocity of a wave is determined by the properties of the medium through which it is traveling, such as the density, elasticity, and temperature of the medium.

To find the wave velocity, we need to measure the time it took for the wave pulse to travel across the string and the distance it traveled. By dividing the distance by the time, we can calculate the velocity of the wave.

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Two charges are aligned with a -2.5x10-6 C charge 0.50 m directly below a 3.0x10-6 C charge. Calculate the force acting on both charges, including direction.

Show work please.

Answers

The force on the -2.5x10-6 C charge is given by Coulomb's Law:

F = k*(q1*q2)/r^2

where k is the Coulomb's constant (8.99x10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between them.

F = 8.99x10^9 Nm^2/C^2 * (-2.5x10^-6 C) * (3.0x10^-6 C) / (0.50 m)^2

F = -7.49x10^-5 N

The force on the 3.0x10-6 C charge is the same magnitude but in the opposite direction:

F = 7.49x10^-5 N

Can someone help me find the which direction is north and which is south on this solenoid?

Can someone help me find the which direction is north and which is south on this solenoid?

Answers

Explanation:

Now, looking down the solenoid tube determine what direction is the winding. If clockwise in relation to the positive wire then is the south pole, if anti-clockwise then is the north pole. So, to summarize the magnetic south pole is always clockwise in relation to the positive wire.

A kettle was tested for its energy efficiency. Its power rating was 900 W. Over the course of 4 minutes and 30 seconds, its useful energy output was 0.05 kWh. How do I answer this ?

Answers

A kettle was tested for its energy efficiency. Its power rating was 900 W. Over the course of 4 minutes and 30 seconds, its useful energy output was 0.05 kWh

Energy is referred to by scientists as the capacity for work. People have figured out how to transform energy from one form to another and then use it to accomplish tasks, making modern civilization possible.

Thermal energy, radiant energy, chemical energy, nuclear energy, electrical energy, motion energy, sound energy, elastic energy, and gravitational energy are among the several types of energy.

The ability to perform tasks is referred to as energy. Formula. Potential energy is the energy that an object has stored because of its position and height, and it may be calculated using the following formula: P.E. equals mgh.

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can someone please help i will name brainliest

Answers

Answer:

dang it its so long :(

Explanation:

Wave 1

a) How many waves are there in this wave train?
b) Wavelength cm c) Amplitude
cm

Wave 1a) How many waves are there in this wave train?b) Wavelength cm c) Amplitudecm

Answers

Answer:

see below

Explanation:

a wave means one complete wave which is 1 period

so a) 5 complete waves

wavelength is the shortest distance between any two points in phase

so wavelength = 1 CM

amplitude of a wave is the maximum displacement of a particle from its rest position

so amplitude = 3 CM

hope this helps

By moving her arms outward, an ice skater speeds up a spin, while moving her arms inward slows down a spin. Question options: True False

false

Answers

ITS TURE.When there is no torque acting on a body, its angular momentum is constant. Net force changes momentum, while net torque changes angular momentum.

Answer: false

Explanation:

how mny hours does it takes you to travel by foot from australia to fiji

Answers

Answer:

About 22 hours in flight time.

Explanation:

It wouldn't give me the walking time.

Hope I helped ya.

< Sarah >

Answer:

Hmm idk u was tryna take the trip or sum

Explanation:

Draw a diagram to represent conical pendulum in a non inertial frame of reference and state the equation of centrifugal force on the Bob

Answers

As the pendulum moves around the circle, the centripetal acceleration remains constant in magnitude but changes in direction. This is because the tangential velocity of the bob changes direction as it moves around the circle, but its speed remains constant.

The centripetal acceleration experienced by the bob of the conical pendulum is given by the formula \(a = v^2/r\),

Since the pendulum is rotating with a constant angular velocity, the tangential velocity is also constant, given by:

v = 2πr/T,

where T is the period of one revolution. The period is 60/20 = 3 seconds since the pendulum makes 20 revolutions per minute.

Thus, v = 2π*2/3 = 4.19 m/s.

Therefore, the centripetal acceleration is \(a = 4.19^2/2 = 8.77 m/s^2.\)

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--The complete Question is, A conical pendulum is set up in a non-inertial frame of reference that is rotating with a constant angular velocity. The length of the string is 2 meters, and the mass of the bob at the end of the string is 0.5 kg. The pendulum makes 20 revolutions per minute. What is the centripetal acceleration experienced by the bob, and how does this acceleration change as the pendulum moves around the circle?--

WHAT IS THE NET FORCE (CENTRIPETAL FORCE) FOR A 1500 KG
CAR DRIVING 5 M/S AROUND A CURVE, 10 M IN RADIUS?

Answers

A :-) Given - m = 1500 kg
v = 5 m/s
r = 10 m
Solution -
F = mv^2 by r
F = 1500 x 5 x 5 by 10
( cut 5 and 10 because 5 x 2 = 10 )
F = 1500 x 5 by 2
( cut 2 and 1500 because
2 x 750 = 1500 )
F = 750 x 5
F = 3750 N
.:. The centripetal force is 3750 N.

Anyone know the answer ——————————

Anyone know the answer

Answers

You got it right two m/s

If we increase the duration of a collision (i.e., we make the collision time longer), while keeping everything else about the collision the same, which of the following will be true? Select the correct answer O The compressive pressure on the colliding objects due to the collision will increase. O The compressive pressure on the colliding objects due to the collision will decrease.

Answers

If we increase the duration of a collision while keeping everything else about the collision the same, the compressive pressure on the colliding objects due to the collision will decrease.

The compressive pressure is the force per unit area applied to the objects during the collision. When the collision duration is increased, it allows for a longer period of time for the objects to interact and exchange momentum. As a result, the force applied to the objects can be spread over a longer duration, reducing the compressive pressure. Therefore, the correct answer is: The compressive pressure on the colliding objects due to the collision will decrease.

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If X = 5 and Y = 3, what does Z equal?

Answers

Answer:

What is the figure? please provide

electrons are accelerated by a 1000-v potential drop. (a) calculate the de broglie wavelength. (b) calculate the wave- length of the x-rays that could be produced when these elec- trons strike a solid.

Answers

The de Broglie wavelength of the electron is 2.212 x 10-11 m.

What is Broglie wavelength?

The de Broglie wavelength is a concept in quantum mechanics which states that all matter has a wave-like nature, and can thus be described as a wave.

(a) The de Broglie wavelength (λ) of a particle is given by the equation: λ = h/p, where h is Planck's constant (6.626 x 10-34 J.s) and p is the momentum of the particle.
The momentum of an electron with a 1000-V potential drop is given by the equation p = eV/c,
where e is the electron charge (1.602 x 10-19 C) and c is the speed of light (2.998 x 108 m/s).
Therefore, the de Broglie wavelength of the electron is:
λ = h/(eV/c) = (6.626 x 10-34 J.s) / (1.602 x 10-19 C x 1000 V/2.998 x 108 m/s) = 2.212 x 10-11 m.

(b) X-rays are produced when high-energy electrons strike a solid.
The wavelength of the x-ray is inversely proportional to the energy of the electron.
The energy of the electron is equal to the potential drop, i.e. 1000 eV. Therefore,
the wavelength of the x-ray produced is: λ = hc/eV = (6.626 x 10-34 J.s x 2.998 x 108 m/s)/(1.602 x 10-19 C x 1000 eV) = 1.246 x 10-10 m.

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Please help although I think I have the awnser but correct me if I’m wrong

Please help although I think I have the awnser but correct me if Im wrong

Answers

I believe you got it correct already

What is the momentum of a 110kg fullback running at 860 m/s?*

Answers

Answer:

94600kgm/s

Explanation:

Linear momentum of a body can be calculated using the formula;

P = mv

Where;

P = linear momentum (Kgm/s)

m = mass of body (kg)

v = speed of the moving body (m/s)

According to the provided information in the question, m = 110kg, v = 860m/s

P = 110 × 860

P = 94600kgm/s

8. A satellite weighs 200 newtons on the surface of

Earth. What is its weight at a distance of one Earth

radius above the surface of Earth?

1) 800 N

3) 100 N

2) 400 N

4) 50 N

Answers

The weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

The given parameters:

Weight of the satellite, F = 200 NOne Earth radius above the surface of Earth = 2R

The gravitational force on the satellite is calculated by applying Newton's law of universal gravitation is calculated as;

\(F = \frac{Gm_1m_2}{R^2} \\\\F_1 R_1^2 = F_2R_2^2\\\\F_2 = \frac{F_1 R_1^2 }{R_2^2} \\\\F_2 =\frac{200 \times R_1^2}{(2R_1)^2} \\\\F_2 = \frac{200 \times R_1^2 }{4R_1} \\\\F_2 = 40 \ N\)

Thus, the weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

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The lifecycle of a star, including the sun, is controlled by the blank of the star. A. Ending mass B. Ending density C. Initial density D. Initial mass

Answers

A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available…so initial mass I think

Which of the following is NOT an example of acceleration?
A car is traveling 33 km/h and slows down to 25 km/h.
B.
A car is driving straight at 50 mi/h.
A car is traveling 33 km/h and speeds up to 45 km/h.
A car is traveling 33 km/h north and turns east.

Answers

Answer:

B

explanation:

The car is not making a change in speed.

incandescent light bulbs are quite inecient, emitting only about 5% of their power in visible light. imagine a spherical, 100 w incandescent bulb with a 6.0 cm diameter. a. what is the intensity of the visible light at the surface of the bulb?

Answers

The intensity of the visible light at the surface of the 100 W spherical incandescent bulb of 6.0 cm in diameter is approximately 0.044 W/cm^2.

The intensity of the visible light at the surface of a 100 W incandescent bulb with a 6.0 cm diameter can be calculated as follows:

First, we need to determine the total power emitted as visible light by the bulb. Since incandescent bulbs are only 5% efficient in emitting visible light, the power in visible light can be calculated as:

Power in visible light = Total power × Efficiency
Power in visible light = 100 W × 0.05
Power in visible light = 5 W

Next, we need to calculate the surface area of the spherical bulb. The surface area of a sphere can be calculated using the formula:

Surface area = 4 × π × r^2

Given the diameter of the bulb is 6.0 cm, the radius (r) is 3.0 cm. Therefore, the surface area of the bulb is:

Surface area = 4 × π × (3.0 cm)^2
Surface area ≈ 113.1 cm^2

Now, we can calculate the intensity of the visible light at the surface of the bulb using the formula:

Intensity = Power in visible light / Surface area
Intensity = 5 W / 113.1 cm^2
Intensity ≈ 0.044 W/cm^2

So, the intensity of the visible light at the surface of the 100 W incandescent bulb is approximately 0.044 W/cm^2.

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please write with good handwriting.
Given the following triangle, find the angle A using the appropriate sine or cosine 5.3 7 A=? law: 8.2 Given the following triangle, find the length of side x using the appropriate sine X 101° 38° o

Answers

The angle A using the appropriate sine or cosine law is 43.29 degrees.

To find angle A, we can use the cosine law, which states that $a^2 = b^2 + c^2 - 2bc \cos{A}$. We have $b=5.3$, $c=7$, and $a=8.2$, so we can plug in and solve for $\cos{A}$:$$8.2^2 = 5.3^2 + 7^2 - 2(5.3)(7) \cos{A}$$$$\cos{A} = \frac{8.2^2 - 5.3^2 - 7^2}{-2(5.3)(7)} = 0.509$$$$A = \cos^{-1}{(0.509)} \approx 43.29^\circ$$The length of side x using the appropriate sine X is 61.32 units.

We can use the sine law, which states that $\frac{a}{\sin{A}} = \frac{b}{\sin{B}} = \frac{c}{\sin{C}}$. We know that $A=101^\circ$ and $a=x$, so we can use the ratio $\frac{a}{\sin{A}}$ to solve for $x$:$$\frac{x}{\sin{101}} = \frac{c}{\sin{38}}$$$$x = \sin{101} \cdot \frac{c}{\sin{38}} \approx 61.32$$Therefore, the length of side x is approximately 61.32 units.

In geometry, the Cosine Decide says that the square of the length of any side of a given triangle is equivalent to the amount of the squares of the length of different sides short two times the result of the other different sides duplicated by the cosine of point included between them.

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A typical value for intrapleural pressure is ________ mm Hg. A) -3 B) -6 C) 0 D) +3 E) +6

Answers

option A, which is -3 The typical value for intrapleural pressure is -3 mm Hg.

Intrapleural pressure (IPP) is the pressure in the space between the lung and chest wall, known as the pleural space. option A, which is -3. The other options given are not the typical value for intrapleural pressure.

Here are some additional details about intrapleural pressure: Intrapleural pressure is always negative in relation to atmospheric pressure. The typical intrapleural pressure during breathing is around -3 mm Hg. During inhalation, the intrapleural pressure becomes more negative as the diaphragm moves downward, causing the lungs to expand. During exhalation, the intrapleural pressure becomes less negative as the diaphragm relaxes and moves upward, causing the lungs to decrease in size.

Intrapleural pressure is a negative pressure that exists within the pleural space between the lung and chest wall. The typical value for intrapleural pressure during breathing is -3 mm Hg.

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A horizontal wire of length 0.19 m, carrying a current of 7.6 A, is placed in a uniform external magnetic field. When the wire is horizontal, it experiences no magnetic force. When the wire is tilted upward at an angle of 17°, it experiences a magnetic force of 6.2 x 10-³ N. Determine the magnitude of the external magnetic field.

Answers

The magnitude of the external magnetic field is approximately 0.194 Tesla.

To solve this problem, we can use the equation for the magnetic force on a current-carrying wire:

F = BILsinθ

where F is the magnetic force, B is the magnitude of the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

Given:

Length of the wire, L = 0.19 m

Current, I = 7.6 A

Angle, θ = 17°

Force, F = 6.2 x \(10^{-3}\)N

Substituting the given values into the equation, we have:

6.2 x \(10^{-3}\) N = B * 0.19 m * 7.6 A * sin(17°)

Simplifying the equation, we can solve for B:

B = (6.2 x \(10^{-3}\) N) / (0.19 m * 7.6 A * sin(17°))

Calculating this expression, we find:

B ≈ 0.194 T

Therefore, the magnitude of the external magnetic field is approximately 0.194 Tesla.

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Roller coasters are popular attractions at amusement parks. A cart on a roller coasterapproaches the highest point on the coaster. As the cart reaches the top, it slows down.Which statement best describes the energy of the roller coaster as it slows down whiletraveling to the top of the coaster?A The cart gains both kinetic and potential energy.B The cart gains kinetic energy and loses potential energy.C The cart loses kinetic energy and gains potential energy.D The cart loses both kinetic and potential energy.

Answers

The statement that describes energy of the roller coaster as it slows down while travelling to the top of the coaster is 'The cart loses kinetic energy and gains potential energy.'

Consider three roller coaster points that are each at a different height from the ground. If we disregard all frictional and drag forces and focus just on the conservative forces acting on the roller coaster car, we may assume that all kinetic and potential energy is conserved. As a result, energy only transforms from one form to another.

When the roller coaster vehicle hits the bottom, it will have reached its maximum level of kinetic energy since all of the gravitational potential energy has been transformed into kinetic energy.

At the top of the roller coaster, the object has its maximum gravitational potential energy and none at all (assumed there is no velocity). As the object begins to fall to the bottom, its gravitational potential energy falls and its kinetic energy increases.

Hence, as the cart reaches the top, it slows down because it loses kinetic energy and gains potential energy.

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