Two 5.0-cm-diameter metal disks separated by a0.61-mm-thick piece of Pyrex glass are charged to a potential difference of 1300V . (Dielectric constant of the Pyrex glass is Pkpyrex=4.7.)
A) What is the surface charge density on the disks?
B) What is the surface charge density on the glass?
Answers
The surface charge density on the disks is, \(4.3910^{-5} C/m^2\). The surface charge density on the glass is, σ = \(-4.39\times 10^{-5} C/m^2\).
We can solve this problem using the capacitance equation for a parallel plate capacitor with a dielectric material between the plates:
C = εA/d
where C is the capacitance, ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates.
The potential difference V between the plates is related to the charge Q on the plates and the capacitance C by:
V = Q/C
The capacitance of the parallel plate capacitor is:
C = εA/d = \((4.78.85\times 10^{-12} \text{ F/m})\times \dfrac{\pi (0.025 m)^2}{0.00061 m}\)
\(= 4.22 \times 10^{-11} F\)
The charge on each plate is:
Q = CV
\(= (4.22\times 10^{-11} F)(1300 V)\\\\ = 5.48\times10^{-8} C\)
The surface charge density on each disk is:
\(\sigma = Q/A\\\\ = 2\dfrac{Q}{\pi r^2}\\\\ = \dfrac{2(5.4810^{-8} C)}{\pi (0.025 m)^2}\\\\ = 4.3910^{-5} C/m^2\)
The surface charge density on the Pyrex glass is equal and opposite to the surface charge density on the disks. This is because the total charge on the system must be conserved. Therefore, the surface charge density on the Pyrex glass is:
σ = \(-4.39\times 10^{-5} C/m^2\)
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Related Questions
A simple 15.2 cm reflecting telescope can achieve 1 second of arc resolution for visible light. Many radio telescopes study a particular radio wavelength of 21 cm. Complete parts a −d using the above information. a. Use the Raleigh criteron to determine how large a radio telescope aperature must be to achieve this resolution at 21 cm. b. Why must the aperture of a radio telescope be much larger than that of an optical telescope? c. Why is it possible to resolve two predominantly blue stars when the same telescope can not resolve two simarily separated red stars? d. In the galaxy pictures of 5 b, which photograph corresponds to the largest aperture?
Answers
a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.
a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:
δθ = 1.22 * (λ / D)
Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.
Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:
D = 1.22 * (λ / δθ)
D = 1.22 * (0.21 m / 1 second of arc)
Calculating the result:
D ≈ 0.27 m
Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.
b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.
Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.
c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).
Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.
Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.
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draw the vectors starting from the tip of the object making use of the crosshair to locate the tip. the location and orientation of the vectors will be graded.
Answers
Drawing vectors starting from the tip of an object using a crosshair can help visually represent quantities associated with the object. It allows you to accurately locate the tip and draw vectors with the correct orientation. This method helps in understanding the location and orientation of the vectors in relation to the object being analyzed.
The instructions ask you to draw vectors starting from the tip of an object using a crosshair to locate the tip.
Here is a step-by-step explanation:
1. Start by identifying the object you want to draw vectors for.
2. Use a crosshair to locate the tip of the object accurately.
A crosshair is a set of perpendicular lines that intersect at a common point, which can help you pinpoint a specific location.
3. Once you have located the tip, draw a vector that represents a quantity associated with the object.
Vectors are arrows that have both magnitude (size) and direction.
For example, if you are drawing vectors to represent forces acting on the object, you would draw an arrow pointing in the direction of the force and with a length proportional to the magnitude of the force.
4. Repeat the process for each vector you need to draw, starting from the tip of the object and using the crosshair to locate it accurately.
5. Pay attention to the orientation of the vectors.
The orientation refers to the direction in which the vector points.
Make sure you draw the vectors in the correct direction based on the context of the problem.
6. Once you have drawn all the vectors, you can analyze their locations and orientations.
This analysis can help you understand the relationships between the different quantities represented by the vectors.
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what causes wind to flow ?
Answers
Answer:
hi
Explanation:
as a result of the collision of hot and cold air
hope it helps
have a nice day
Answer:
Hey mate.....
Explanation:
This is ur answer.....
Wind is the movement of air caused by the uneven heating of the Earth by the sun. ... Warm equatorial air rises higher into the atmosphere and migrates toward the poles. This is a low-pressure system. At the same time, cooler, denser air moves over Earth's surface toward the Equator to replace the heated air.
Hope it helps!
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The relationship between temperature measured on the Celsius scale and on the Fahrenheit scale is linear. The freezing point of water is 0°C and 32°F, and the boiling point is 100°C and 212°F.
(a) Find an equation giving the relationship between the temperature F measured on the Fahrenheit scale and the temperature C measured on the Celsius scale.
F =
(b) Find F as a function of C, and use this formula to determine the temperature in Fahrenheit corresponding to a temperature of 30°C. (Round your answer to one decimal place. )
°F
(c) Find C as a function of F, and use this formula to determine the temperature in Celsius corresponding to a temperature of 90°F. (Round your answer to one decimal place. )
°C
Answers
a) The equation giving the relationship between F and C is:
F = (9/5)C + 32
b) A temperature of 30°C corresponds to a temperature of 86°F.
c) A temperature of 90°F corresponds to a temperature of 32.2°C.
(a) To find the equation giving the relationship between the temperature F measured on the Fahrenheit scale and the temperature C measured on the Celsius scale, we can use the formula for a linear relationship:
F = aC + b
where a and b are constants that we need to determine. We know that the freezing point of water is 0°C and 32°F, so we can plug these values in to get two equations:
32 = a(0) + b
212 = a(100) + b
The first equation simplifies to b = 32, and the second equation simplifies to 100a + 32 = 212, or 100a = 180. Solving for a, we get a = 9/5.
Therefore, the equation giving the relationship between F and C is:
F = (9/5)C + 32
(b) To find F as a function of C, we can simply use the equation we found in part (a) and plug in the value of 30°C:
F = (9/5)(30) + 32
F = 86°F
Therefore, a temperature of 30°C corresponds to a temperature of 86°F.
(c) To find C as a function of F, we can rearrange the equation we found in part (a) to solve for C:
F = (9/5)C + 32
(5/9)(F - 32) = C
Plugging in the value of 90°F, we get:
C = (5/9)(90 - 32)
C = 32.2°C
Therefore, a temperature of 90°F corresponds to a temperature of 32.2°C.
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A wheel on an indoor exercise bike (a spinning bike) accelerates steadily from 130 rpm to 280 rpm in 5.0 s . The radius of the wheel is 47 cm.
Determine the tangential component of the linear acceleration of a point on the edge of the wheel 2.0 s after it has started accelerating.
Answers
The tangential component of the linear acceleration of a point on the edge of the wheel 2.0 s after it has started accelerating is approximately \(1.48 m/s^2.\)
First, let's convert the initial and final speeds from revolutions per minute (rpm) to radians per second:
ω1 = 130 rpm = 130(2π/60) rad/s ≈ 13.6 rad/s
ω2 = 280 rpm = 280(2π/60) rad/s ≈ 29.3 rad/s
The angular acceleration can be calculated as:
α = (ω2 - ω1)/t = (29.3 - 13.6)/5.0 ≈ \(3.14 rad/s^2\)
At time t = 2.0 s, the angular velocity is:
ω = ω1 + αt = 13.6 + 3.14(2.0) ≈ 20.9 rad/s
The tangential component of the linear acceleration can be calculated as:
aT = rα
where r is the radius of the wheel. Substituting r = 0.47 m and α = \(3.14 rad/s^2\), we get:
aT = (0.47)(3.14) ≈ \(1.48 m/s^2\)
Therefore, the tangential component of the linear acceleration of a point on the edge of the wheel 2.0 s after it has started accelerating is approximately \(1.48 m/s^2.\)
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A 20 N force is necessary to stretch a spring 0.5 m. What is the spring constant of this spring?
Answers
Answer: The spring constant of a given spring is \(40 N/m\).
Explanation:
Given,
Force (F) = 20N
The displacement of the spring\(= x = 0.5 m\)
To find: Spring constant (k) = ?
As we know that,
Hook's law states that,
\(F = k\) · \(x\)
Therefore, \(k = \frac{F}{x}\)
\(k = \frac{20}{0.5}\)
\(k = \frac{(20)(10)}{5}\)
\(k = 40 N/m\)
Hence, The spring constant of a given spring is \(40 N/m\).
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please help i need it fast
Answers
12. An 12 kg block is being pulled by a horizontal force over a horizontal surface with which it has coefficient of friction μ=0.50. The block is slowing down at a rate of 2.5 m/s
2
. What is the magnitude of the force of friction on the block? (a) 15 N (c) 45 N (e) 75 N (b) 30 N (d) 60 N (f) 90 N
Answers
The magnitude of the force of friction on the block is 30 N, Option (b).
Mass, m = 12 kg
Coefficient of friction, μ = 0.5
Acceleration, a = -2.5 m/s²
The force of friction can be calculated as follows:
f = ma
Where,
f = force of friction
m = mass
a = acceleration
Since the block is slowing down, the acceleration is negative.
So, the magnitude of acceleration = |a| = 2.5 m/s²
Therefore, the force of friction, f = m|a|
f = 12 × 2.5f = 30 N
Therefore, the magnitude of the force of friction on the block is 30 N.
Option (b) is the correct answer.
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How do you find the magnitude of the electric field at the origin?
Answers
In order to find the magnitude of the electric field at the origin, you need to use the equation E = q/4πεr², where q is the charge, ε is the permittivity of space, and r is the distance from the origin.
To calculate the electric field, you must first determine the charge of the particle, then determine the distance to the origin, and finally, use the equation to calculate the magnitude of the electric field.
Once you have the magnitude of the electric field at the origin, you can then use it to explore the behavior of other electric fields in the area.
To calculate the magnitude, you must first determine the values of k, q, and r, then plug them into the equation and solve. The resulting answer will be the magnitude of the electric field at the origin.
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an egg drops from a second-story window, taking 1.12 s to fall and reaching 11.0 m/s just before hitting the ground. on contact, the egg stops completely in 0.131 s. calculate the magnitudes of its average acceleration (a) while falling and (b) while stopping
Answers
The average acceleration of the egg while falling can be calculated using the equation a = (v - u)/t, where v is the final velocity, u is the initial velocity and t is time.
The average accelerationa) A = (11.0 m/s) / (1.12 s) = 9.82 m/s^2
b) A = (0 m/s) / (0.131 s) = 0 m/s^2
This is a physics problem involving the concepts of acceleration, velocity, and time.Acceleration is the rate of change of velocity and is a vector quantity, meaning it has both a magnitude and direction.In this case, v = 11.0 m/s, u = 0 m/s and t = 1.12 s.This gives an acceleration of 9.82 m/s^2 downwards, the same value as the acceleration due to gravity.The average acceleration of the egg while stopping can be calculated using the same equation, but with v = 0 m/s, u = 11.0 m/s and t = 0.131 s.This gives an acceleration of -84.3 m/s^2, which is an acceleration directed upwards, opposite to the acceleration due to gravity.In summary, the egg experienced an average acceleration of 9.82 m/s^2 downwards while falling, and an average acceleration of -84.3 m/s^2 upwards while stopping.To learn more about The average acceleration refer to:
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a car accelerates from 20 m/s to 40 m/s in 10 s and its forward thrust is equal to 3 kN, what is the mass of
Answers
A car that has a forward thrust of 3kN and accelerates from 20 m/s to 40 m/s in 10 s has a mass of 1500 kg. Thus, the mass of the car is the 1500 kg
Newton's 2nd law of motionFrom the question, we are to calculate the mass of the car.
From Newton's second law of motion, we have that
F = ma
Where F is the Net force
m is the mass
and a is the acceleration
Also, from one of the equations of linear motion, we have that
v = u + at
Then, we can write that
\(a = \frac{v-u}{t}\)
Where v is the final velocity
u is the initial velocity
a is the acceleration
and t is the time taken
Therefore,
\(F = m\frac{(v-u)}{t}\)
From the given information,
u = 20 m/s
v = 40 m/s
t = 10 s
F = 3 kN = 3000 N
Putting the parameters into the equation, we get
\(3000 = m \frac{(40-20)}{10}\)
\(3000 = m \times \frac{20}{10}\)
3000 = 2m
Then,
m = 3000 ÷ 2
m = 1500 kg
Hence, the mass of the car is the 1500 kg.
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The momentum of a 3000 kg truck is 6.36 x 104 kg·m/s. At what speed is the truck traveling? m/s
472
19,080
2.1
21.2
19.6
24.5
Answers
Answer:
21.2m/s
Explanation
Given data
P=6.36 x 10⁴kg·m/s.
M=3000kg
From the momentum expression
P=mv
v=p/m
Substitute
v=63600/3000
v=21.2m/s
Hence the Velocity is 21.2m/s
The speed of the truck is 21.2 m /s
Momentum is the product of the mass of the object and the velocity of the object. Therefore,
p = mv
where
m = mass
v = velocity
m = 3000 kg
p = 6.36 x 104 kg·m/s.
lets find the velocity
6.36 x 10⁴ = 3000 × v
v = 6.36 x 10⁴ / 3000
v = 21.2 m / s
The speed of the truck is 21.2 m /s
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The celestial sphere turns once around each day because.
Answers
Answer:
The celestial sphere turns once around each day because...
the planet on which we live is rotating
Explanation:
Earth is constantly rotating which causes the celestial sphere to rotate as well.
How are coal types classified?
color and texture
carbon content and heat value
depth from the surface
sulfur content
Answers
Answer:
I believe its B...."Carbon Content and Heat Value"
Explanation:
Coal is classified into four main types, or ranks: anthracite, bituminous, subbituminous, and lignite. The ranking depends on the types and amounts of carbon the coal contains and on the amount of heat energy the coal can produce.
To serve a single load that will not operate more than 3 hours, 1 awg conductors are installed. These branch circuit conductors can be protected by a circuit breaker with a rating no greater than ___ amps.
Answers
The correct answer of branch circuit conductors can be protected by a circuit breaker with a rating no greater than should be 125 amps.
What Size Wire Do We Need for My Breaker?
The accepted system for this measurement is AWG. A smaller wire size is indicated by a greater number in the wire gauge scale, which runs from high to low.
The circuit conductors between the outlet and the final overcurrent device protecting the circuit are referred to as branch circuits (s).
The circuit conductors between the outlet and the final overcurrent device protecting the circuit are referred to as branch circuits (s). If the conductors are on the load side of the final branch circuit overcurrent device, even conductors for a circuit rated at 1000 amps are a branch circuit.
The branch-circuit conductors that supply loads other than those listed in 210.3 and other than the cooking appliances covered by 210.19 must have an ampacity sufficient for the loads served and must not be lower than 14 AWG.
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a primary difference between the asteroid belt and the kuiper belt is that group of answer choices the kuiper belt is significantly more dense than the asteroid belt. objects in the asteroid belt tend to be larger than those in the kuiper belt. objects in the asteroid belt are mostly rocky while objects in the kuiper belt are mostly icy. the astroid belt was formed from debris left over from the formation of the solar system while the kuiper belt was formed from the collision of several large planets very early in the solar system's formation.
Answers
The primary difference between the asteroid belt and the Kuiper belt is that objects in the asteroid belt are mostly rocky, while objects in the Kuiper belt are mostly icy.
The asteroid belt is a region located between the orbits of Mars and Jupiter, consisting of numerous small rocky objects called asteroids. These asteroids are primarily composed of rock and metal. They are remnants from the early formation of the solar system when planetesimals failed to form a planet due to the gravitational influence of Jupiter's strong gravity.
On the other hand, the Kuiper belt is a region beyond the orbit of Neptune, extending from around 30 to 55 astronomical units from the Sun. It is home to a large number of icy bodies, including dwarf planets such as Pluto and Eris. The Kuiper belt objects (KBOs) are predominantly composed of volatile materials like water ice, methane, and ammonia, making them distinct from the rocky asteroids in the asteroid belt.
Therefore, the primary difference lies in the composition of the objects, with the asteroid belt containing mostly rocky objects and the Kuiper belt consisting mainly of icy bodies.
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Calculate the electric potential at point P
Answers
Answer:
The potential energy at point 'P' due to the first charge can be found as follows:
V1=kq1r1V1=(9.0×109N.m2/C2)(+1.0×10−5C)1.0mV1=9.0×104VV1=kq1r1V1=(9.0×109N.m2/C2)(+1.0×10−5C)1.0mV1=9.0×104V
The potential energy at point 'P' due to the second charge can be found as follows:
V2=kq2r2V2=(9.0×109N.m2/C2)(−5.0×10−6C)1.0mV2=−4.5×104VV2=kq2r2V2=(9.0×109N.m2/C2)(−5.0×10−6C)1.0mV2=−4.5×104V
Since the electric potential is the scalar quantity, therefore,
The electric petential at point 'P' due to the two given charges:
VP=V1+V2VP=9.0×104V+(−4.5×104V)VP=4.5×104VVP=V1+V2VP=9.0×104V+(−4.5×104V)VP=4.5×104V
When third charge q3=+2μC=+2.0×10−6Cq3=+2μC=+2.0×10−6C is placed at point 'P', then
The electric potential energy of the charge q3q3 can be expressed as follows:
U3=q3VPU3=q3VP
After plugging in the values, we have:
U3=(+2.0×10−6C)(−4.5
Explanation:
hope this helps
The acceleration of an object would increase if there was an increase in:
A.mass of the object
B.force on the object
C.inertia of the object
D.friction in the object
Answers
Answer:
Its either B or A
Explanation:
What is 102 Fahrenheit fever in Celcius?
Answers
Answer:
102°F fever in Celsius is equivalent to 38.9°C.
When your hand presses
down on scissors, what is your
force called?
a. input force
b. output force
c. buoyant force
Answers
Answer:
INPUT force
Explanation:
You are putting force into a machine of levers to have the output of cutting something.
When your hand presses down on scissors, the force is called input force because are applying a force into an object. Thus, option a is correct.
What is force ?Force is an external agent acting on a body to deform it or to change its state from rest or motion. There are various kinds of force such as magnetic force, nuclear force, gravitational force etc.
Force is a vector quantity thus, it is characterised by a magnitude and direction. According to second law of motion, the force acting on a body is the product of mass and acceleration.
Hence, the force acting on a body is directly proportional to the mass. Greater the mass, greater will be the force needed to accelerate the body. When we press down on an object we are applying an input force to the object.
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What is the dewpoint in radiation fog at a temperature of 10 °C
(50 °F)?
Answers
Assuming 100% relative humidity, the dewpoint temperature in radiation fog at a temperature of 10 °C (50 °F) is approximately 10 °C.
To find the dewpoint in radiation fog at a temperature of 10 °C (50 °F), we need to consider the saturation point of air, which is the temperature at which the air becomes saturated and condensation occurs.
The dewpoint temperature is the temperature at which the air must be cooled for it to reach saturation and for condensation to occur. When the dewpoint temperature is reached, fog or dew will form.
The relationship between temperature, relative humidity, and dewpoint temperature is complex and depends on various factors such as air pressure and moisture content. However, we can estimate the dewpoint using empirical formulas or tables.
One commonly used approximation is the Magnus formula:
Td = (T × Arctan[0.151977 × (RH + 8.313659)^0.5]) + Arctan(T + RH) - Arctan(RH - 1.676331) + 0.00391838 × (RH^(3/2)) × Arctan(0.023101 × RH) - 4.686035
Where:
Td = Dewpoint temperature in degrees Celsius
T = Temperature in degrees Celsius
RH = Relative humidity (expressed as a decimal)
Assuming a relative humidity of 100%, which represents saturated air, we can estimate the dewpoint temperature at a temperature of 10 °C (50 °F).
Substituting the values:
T = 10 °C
For simplicity, we assume RH = 1 (100% relative humidity).
Td = (10 × Arctan[0.151977 × (1 + 8.313659)^0.5]) + Arctan(10 + 1) - Arctan(1 - 1.676331) + 0.00391838 × (1^(3/2)) × Arctan(0.023101 × 1) - 4.686035
Simplifying the equation, we find that the estimated dewpoint temperature (Td) is approximately equal to 10 °C.
Therefore, assuming 100% relative humidity, the dewpoint temperature in radiation fog at a temperature of 10 °C (50 °F) is approximately 10 °C.
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the amount of a good or service a
producer wants to sell
scarcity
O supply
demand
O capital
entrepreneurshipb
Answers
Answer:
I can't understand you're que... plzz write in a correct way..
A container of gas is held at a constant volume. Which will most likely happen to the temperature if the pressure of the gas increases?
The temperature will increase at the same rate as the pressure increases.
The temperature will decrease at the same rate as the pressure increases.
The temperature will increase at half the same rate as the increase in pressure.
The temperature will decrease at half the same rate as the increase in pressure.
Answers
Answer:
With more particles there will be more collisions and so a greater pressure. The number of particles is proportional to pressure, if the volume of the container and the temperature remain constant. ... This happens when the temperature is increased.
Explanation:
Assuming the gas to be an ideal gas, the temperature will increase at the same rate as the pressure increases.
Ideal gas:Let us assume that the gas in the container is an ideal gas. Then from the ideal gas equation, we get that:
PV = nRT
where P is the pressure of the gas
V is the volume
T is the temperature
n is the number of moles of the gas
R is the universal gas constant
Now, it is given that V is constant, R is already a constant, and n will also be constant, since the number of moles of gas in the container is not changing, so:
P = nRT/V
P = constant × T
P/T = constant
This means that the temperature will increase at the same rate as the pressure increases.
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what is the angular momentum L of the block-bullet system with respect to the pivot point immediately after the collision
Answers
Angular momentum of a block-bullet system with respect to the pivot point immediately after the collision is given below:The angular momentum L of the block-bullet system with respect to the pivot point immediately after the collision is: `L = (I + mr²)ω′`.
Here,I = Moment of inertia of the bullet block system about its center of mass. `I = (1/2)mr²`m = Mass of the bullet block system.r = Distance of the pivot point from the center of mass of the bullet block system.ω′ = Angular velocity of the bullet block system immediately after the collision.
In this case, the bullet is completely embedded in the block after the collision. Hence, they move as a single unit. So the angular velocity of the bullet-block system is the same as that of the center of mass.Using the law of conservation of momentum along with the angular momentum of the system just before and after the collision, we can determine the angular velocity of the bullet-block system immediately after the collision.
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If this collision occurs during a time of 0.012 seconds, what is the average force exerted on the ball
Answers
(a) The change in momentum is -12.04 kg-m/s
(b) The force exerted by the bat is 1003.33 N
How to calculate?The given values are :
The mass of a ball, m = 0.14 kg
Initial speed of the ball, u = 40 m/s
Final speed of the ball, v = -46 m/s
(a) The change in momentum of the ball during the collision with the bat is given by :
Change in P = m(v-u )
Change in P = 0.14(-46-40)
Change in P = - 12.04 kg-m/s
(b) Time for collision, t = 0.012 s
the force can be calculated as follows :
force = Change in P/ t
force = 1003.33 N
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Complete question:
An official major league baseball has a mass of 0.14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
a) What is the change in momentum of the ball during the collision with the bat?
b) If this collision occurs during a time of 0.012 seconds, what is the average force exerted by the bat on the ball?
What local group of galaxies is the Milky Way part of?
Quasar Cluster
Andromeda Mini-Cluster
Virgo Supercluster
Hubble Open Cluster
Answers
The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C
What are Virgo Supercluster?The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.
Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.
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At any given time in space, how much of
the moon is lit by the sun?
PLEASE ANSWER QUICKLY!!!
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Answer: 50%
Explanation: The sun and the moon go around Earth and The sun is way bigger than the moon so 50% of the sun lights up the moon at night
Answer:
50%
Explanation:
prominences hanging off the limb of the sun are the same as filaments seen in front of the disk.T/F
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The statement "prominences hanging off the limb of the sun are the same as filaments seen in front of the disk" is True.
Prominences and filaments are essentially the same solar feature observed from different perspectives. When viewed from Earth, they appear as dark, thread-like structures called filaments against the bright solar disk.
However, when observed from the edge or limb of the Sun during a solar eclipse or with specialized telescopes, they are seen as bright, arching structures called prominences extending outward from the Sun's surface.
Prominences and filaments are both composed of cooler plasma suspended in the Sun's hot and highly ionized outer atmosphere, known as the corona. They are formed by complex magnetic field interactions and can extend for thousands of kilometers above the Sun's surface.
Prominences/filaments can be stable, lasting for days or even weeks, or they can become unstable and erupt, releasing a significant amount of plasma and energy into space in what is known as a solar eruption or coronal mass ejection.
In conclusion, while their appearance may differ depending on the observer's perspective, prominences hanging off the limb of the Sun are indeed the same as the filaments seen in front of the solar disk.
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can someone please help me?? i’ll give brainilist
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A block with the mass of 14.26kg is on a ramp with an incline of 41 degrees. If the block is stationary, what is the minimum value of the coefficient of static friction? [Please explain to me how you did it, I'm giving you 30 points lol the last two times I've asked ive gotten either no explanation or a link to a calculator...]
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The minimum value of the coefficient of static friction between the surface and the stationary block is 0.87.
What is the coefficient of static friction?The coefficient of static friction is equal to the tangent of the angle at which the objects slide.
Mathematically,
μs = tan(θ)where;
μs is the coefficient of static frictionθ is the angle of inclination just before the object begins to slide.Since the block is stationary, the minimum value of the coefficient of static friction will be:
μs = tan(41°)
μs = 0.87
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