two 8.0 ω lightbulbs are connected in a 12 v series circuit. at what rate does the circuit use electric energy?

Answer:

All above!

Explanation:

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Answer:

The cosmological  constant accounts for the effects of dark energy.

Explanation:

The cosmological constant was first introduced by Albert Einstein, in 1917.

It was defined in the general relativity and it is used to represent a repulsive force in the expansion of the universe.

Vacuum Energy causes the cosmological constant.

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The claim that acceleration may be represented by the displacement time graph's y-axis change divided by x-axis change is untrue.

Displacement versus time graphs show how the displacement of a moving item changes over time. A sloping line on a displacement-time graph depicts the object's velocity. The velocity of the item is equal to the slope or gradient of the line on a displacement-time graph.

On a distance-time graph, speed is represented by the gradient. The vertical axis used to display a journey frequently shows the distance from a certain location rather than the actual distance travelled. Displacement-time graphs are those kind of graphs.

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Answer:

Its angular acceleration is zero.

Explanation:

If the angular velocity of an object (in this case the toy) is constant, then its angular acceleration will be zero. Why? Because angular acceleration is the time rate change of angular velocity. Since there is no change, this brings the answer to zero.

Answer:

The formula for force according to Newton's second law of motion is F=ma or force for an object to move is equal to mass times acceleration.

Acceleration or average acceleration defined as change in velocity per time.

F=ma

F=1.2x10³kg*(20m/s)(1/5s)=4.8x10³  Newtons

Explanation:

fthat's not the answer then i'm sorry

There are certainly times when someone's actions can cause others to dislike them. For example, if someone consistently behaves rudely or disrespectfully towards others, this can quickly turn people off.  we can build positive physical relationships and avoid causing unnecessary conflicts or hurt feelings.

The Similarly, if someone is frequently dishonest or unreliable, this can also cause others to lose trust and respect for them. It's also worth noting that some actions may be more egregious than others and may cause stronger negative reactions. For example, if someone engages in bullying behavior or is openly discriminatory towards certain groups, this is likely to be viewed very negatively by most people. Ultimately, the key to avoiding negative reactions from others is to be mindful of how our actions impact those around us, and to strive to treat others with kindness, respect, and honesty. By doing so, we can build positive physical relationships and avoid causing unnecessary conflicts or hurt feelings.

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Answer:

C. Exothermic Reaction

Explanation:

Let's go through the choices

A. Combustion - Combustion is a highly exothermic / redox reaction which produces light and heat (i.e basically it bursts into flames). In the description, the only reaction is that it feels warm, hence this is not the answer.

B. Endothermic - Recall that endothermic reactions absorbs heat and thus cools the surroundings thereby making test tube feel cooler. this is obviously not the case so this is not the answer.

C. Exothermic - Recall that exothermic reactions releases heat and thus causes the surroundings thereby making the test tube feel warmer (or hotter in some cases). This describes our situation so THIS IS THE ANSWER.

D. Endergonic reactions require an input of energy from an external source that is adsorbed by the reaction (for example if heat was applied by an external source). In this case, there is no mention of additional energy sources. Hence this is probably not the answer.

(a) The angular speed of Allen is 0.628 rad/s.

(b) The angular speed of Beth is 0.628 rad/s.

(c) The linear speed of Allen is 2.512 m/s.

(d) The linear speed of Beth is 1.256 m/s.

The given parameters;

The angular speed of Allen is calculated as follows;

\(\omega = \frac{1 \ rev}{10 \ s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 0.628 \ rad/s\)

The angular speed of Beth is calculated as follows;

\(\omega = \frac{1 \ rev}{10 \ s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 0.628 \ rad/s\)

Allen and Beth make the same number of revolutions every 10 seconds, hence their angular speed is the same.

The linear speed of Allen is calculated as follows;

\(v = \omega r\\\\v = 0.628 \ rad/s \times 4 \ m\\\\v = 2.512 \ m/s\)

The linear speed of Beth is calculated as follows;

\(v = \omega r\\\\v = 0.628 \ rad/s \times 2 \ m\\\\v = 1.256 \ m/s\)

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Answer:0.1

Explanation:

Seeds typically weigh the same.

The mass of an avocado seed can't directly be estimated based on the mass of a watermelon seed. Generally, an avocado seed is larger and heavier than a watermelon seed, often weighing around 15 grams.

The estimated mass of the avocado seed can't be directly determined based on the mass of a watermelon seed. The mass of a seed depends on the size, type, and species of the fruit, which varies considerably between a watermelon and an avocado. For example, an avocado seed typically weighs around 15 grams, which is significantly heavier than a watermelon seed.

However, if you are trying to compare or learn about the relative sizes and masses of different seeds, it might be helpful to know that an avocado seed is generally larger and heavier than a watermelon seed due to the size and nature of the fruit.

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Answer:

Yea what he said I think

Explanation:

A state function does not depend on the path between the initial and final configurations.

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The person's average force on the box is equal to F = 20 N.

The force applied by an object moving over a defined period of time at a defined rate of speed is known as the average force. Here, the word "average" is used to denote that the velocity is not instantaneous or precisely measured.

Given,

I = 5kg.m/s

t = 0.25s

We are aware that force is the same as the change in momentum over time. The impulse is equal to the change in momentum.

F = dP/dt

F = I/t

F = 5/0.25

F = 20N.

The person's average force on the box is equal to F = 20 N.

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explanation

the general form of wave equation is

       y=Asin(kx-wt)

we have

      y=5sin(3x-4t)

hence the angular frequency

     w= 4s^-1

the frequency

  f=w/2 pi

  f=4/2 pi

  f=4/2*3.14

  f=0.64 hz

the period

T=1/f

T=1/0.64

T=1.5625=1.6

the wavelength

k=2 pi/lambda

lambda=2 pi/k

k=3

so

lambda=2*3.14/3

lambda=2.09

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Answer:

V = 0.01(R₁ + R₂)

Explanation:

From Ohm's law, the voltage V across a resistor with resistance R and a current I passing through it is given by

V = IR

If we have two resistances, R₁ and R₂ in series, the total resistance R is the sum of their resistances.

So, R = R₁ + R₂

Now, if the current in the circuit is 0.01 A, the voltage V is

V = IR

V = 0.01R

Substituting R = R₁ + R₂ into the equation for V, we have

V = 0.01(R₁ + R₂)

So, the voltage in two series resistors with current 0.01 A is

V = 0.01(R₁ + R₂)

20 - 5 = 15

total displacement = 15 meters

Answer:

214.4 hz

Explanation:

fundamental frequency

An object of uniform density applies its gravitational force at its center of mass.

An object of uniform density applies its gravitational force at its center of mass. This is because the force of gravity is a result of the object's mass being concentrated at a single point, and the center of mass is the point where the object's mass is evenly distributed in all directions. Therefore, any object with uniform density will apply its gravitational force at its center of mass.

The centre of mass of an object with homogeneous density is where gravitational force acts. This is so because the centre of mass is where the object's mass is evenly distributed in all directions and the force of gravity results from the object's mass being concentrated at a single location. As a result, the centre of mass of any object with uniform density will experience gravitational pull.

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Answer:

Explanation:

The formula for kinetic energy  Ke=1/2mv^2 where Ke is kinetic energy, m=mass, and v= velocity.

If the kinetic energy is increased that means that there must be an increase in mass or velocity. However, since the velocity is squared that means that velocity affects the kinetic energy of the object more than the mass does.

The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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The kinetic energy of another body having three times the mass of the given object will be 108 J

Kinetic energy-In physics, the kinetic energy of an object is the energy  it has due to  motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.

The kinetic energy of a body is given by \(K.E= \frac{1}{2}Mv^{2}\) (first equation)

Given K.E= 36J

Now the mass of second body is m=3M

also the second body is moving with the same speed v

So kinetic energy of second body K.E₂= \(\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}\)=36×3

=108J (from first equation)

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Answer:

-24.2487113m/s

Explanation:

vi=0, x=30, a=9.8, t=?, vf=?

x=vi*t+.5*a*t^2

30=.5*9.8*t^2

30=4.9*t^2

t=2.4743583s

vf=vi+a*t

vf=0+9.8*2.4743583

vf=24.2487113m/s

Then change it to negative because you are going down.

Answer:

Below

Explanation:

Here are all the values that we are given :

Initial velocity Vi = 0 m/s

Vertical distance Dy = 30 m

All objects accelerate towards earth at a rate of 9.8 m/s^2, this is our acceleration

We can use this formula to find the rocks final velocity as it hits the water :

     finalvelocity^2 = initialvelocity^2 + 2(acceleration)(distance)

Plug in our values :

     Vf^2 = 0^2 + 2(9.8m/s^2)(30m)

     Vf^2 = 588

Square this number to get Vf

     Vf = 24.2487 m/s

Now we have to round this number to significant figures. In this case we have to round it to 1 sig fig as the the only number we are given, 30, has 1 sig fig :

     Vf = 20 m/s

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Answer:(d) mass

Explanation: The kilogram is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogram weighs 9.8 Newtons under normal conditions on the surface of the Earth, and Newton is the corresponding SI unit of force and weight.

A) The velocity of Cart B after the collision is 0.8 m/s.

B) The initial kinetic energy of Cart A is 0.176 J.

C) The initial kinetic energy of Cart B is 0 J.

D) The final kinetic energy of Cart A is 0 J.

E) The final kinetic energy of Cart B is 0.176 J.

To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy during an elastic collision.

A) Using conservation of momentum,

m_A × v_Ai = m_A × v_Af + m_B × v_Bf

where

m_A = 0.550 kg (mass of cart A)

m_B = 0.550 kg (mass of cart B)

v_Ai = 0.8 m/s (initial velocity of cart A)

v_Af = 0 m/s (final velocity of cart A, since it stops)

v_Bf = velocity of cart B after the collision (what we want to find)

Plugging in the values

0.550 kg × 0.8 m/s = 0.550 kg × 0 m/s + 0.550 kg × v_Bf

v_Bf = 0.8 m/s

So the velocity of Cart B after the collision is 0.8 m/s.

B) Using the kinetic energy equation

K = 1/2 × m × v^2

where

m = 0.550 kg (mass of cart A)

v = 0.8 m/s (initial velocity of cart A)

Plugging in the values

K = 1/2 × 0.550 kg × (0.8 m/s)^2

K = 0.176 J

So the initial kinetic energy of Cart A is 0.176 J.

C) Since Cart B is initially at rest, its initial kinetic energy is 0.

D) Using the kinetic energy equation

K = 1/2 × m × v^2

where

m = 0.550 kg (mass of cart A)

v = 0 m/s (final velocity of cart A, since it stops)

Plugging in the values

K = 1/2 × 0.550 kg × (0 m/s)^2

K = 0 J

So the final kinetic energy of Cart A is 0 J.

E) Using the kinetic energy equation

K = 1/2 × m × v^2

where

m = 0.550 kg (mass of cart B)

v = 0.8 m/s (velocity of cart B after the collision)

Plugging in the values

K = 1/2 × 0.550 kg × (0.8 m/s)^2

K = 0.176 J

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The law that describes the relationship between the pressure and volume of a gas in a sealed container is Boyle's law.

Boyle's Law, formulated by the Irish scientist Robert Boyle in the 17th century, describes the relationship between the pressure and volume of a gas at a constant temperature. It states that the pressure of a gas is inversely proportional to its volume when the temperature remains constant.

According to Boyle's law, when the pressure of a gas is cut in half, the volume of the gas will double, as long as the temperature remains constant. This means that if you decrease the pressure exerted on a gas by half, the volume of the gas will increase by a factor of two.

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Applying Newton's third law, these two impulsive forces are equal and opposite i.e. If the time of contact is t, the impulse of the force F21 is equal to the change in momentum of the first object. The impulse of force F12 is equal to the change in momentum of the second object.