Two 90.0-kilogram people are separated by 3.00 meters. What is the magnitude of the gravitational force that one person exerts on the other?

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer:

the answer to this is letter b

Answer:

B) Technology helps scientists study things that are very small, far away, or hard to reach.

Answer:

organizing

Explanation:

thinking about where things should go, to make it so that everybody has an easy experience when inside of my store.

Answer:

Force is 2 × 10^-4 N

Explanation:

\({ \bf{F = \frac{ \gamma_{o} I _{1} I _{2} l}{2\pi r} }}\)

F is force

I is current

r is separation distance

gamma is a constant

l is wire length

\(F = \frac{(4\pi \times {10}^{ - 7}) \times (20) \times (10) \times 1 }{2\pi \times 0.2} \\ \\ F = 2 \times {10}^{ - 4} \: \: newtons\)

The magnitude of the force on 1m length of the 20A wire is 2×10⁻⁴N.

To determine the answer, we need to know about magnetic field due to a current carrying wire and magnetic force.

The magnetic field due to a straight wire having current I₁ at a perpendicular distance (say) 'd'  is μ₀I₁ / 2\(\pi\)d.

Magnetic force on a current carrying wire of length 'L' and having current I₂ is I₂(L×B). Where B is the magnetic field at that wire.

  ( Here L and B are perpenicular to each other so L×B= L·B)    

                              = 20×1×10⁻⁵

                              =2×10⁻⁴N

Thus, we can conclude that the magnitude of the force on 1m length of the 20A wire is 2×10⁻⁴N.

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The focal length of the concave mirror is approximately option B. 8.20 cm,

To solve this problem, we can use the mirror equation, which relates the object distance (d_o), image distance (d_i), and the focal length (f) of a concave mirror. The equation is:

1/f = 1/d_o + 1/d_i

Given the object distance (d_o) is 12.2 cm and the image distance (d_i) is 25.0 cm, we can plug in these values to find the focal length (f):

1/f = 1/12.2 + 1/25.0

To solve for f, first find the common denominator and combine the fractions:

1/f = (25 + 12.2) / (12.2 * 25) = 37.2 / 305

Now, take the reciprocal of both sides to isolate f:

f = 305 / 37.2

After calculating, we get:

f ≈ 8.20 cm

Thus, the focal length of the concave mirror is approximately 8.20 cm, Therefore the correct option to option b.

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As the time elapses before the ball strikes the ground, the horizontal velocity of the ball remains the same.

The horizontal velocity of the ball remains constant because of the absence of any forces acting on it in the horizontal direction. The only force acting on the ball is gravity, which only affects the vertical direction of the ball's motion.

Is a fundamental concept in physics, as it explains why objects maintain a constant horizontal velocity when there are no forces acting upon them. This phenomenon can be observed in everyday life, such as when a ball is thrown in the air.

As the ball moves upwards, the only force acting upon it is the force of gravity, which causes the ball to slow down and eventually fall back to the ground. During this time, the ball's horizontal velocity remains constant.

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Answer:

the apparent weight of the astronaut is 81.032 N { towards moon }

Explanation:

Given that;

Mass of astronaut m = 80 kg

Distance of spaceship from the Earth's moon r = 2200 km = 2200 × 10³ m

Acceleration due to gravity of the moon = GM/r²

where M is mass of the moon( 7.34767309 × 10²² kg )

gravitational constant G = 6.67 × 10⁻¹¹

So,

Acceleration due to gravity of the moon g is;

g  = [ (6.67 × 10⁻¹¹) × (7.35 × 10²²) ] / (2200 × 10³)²

g = 4.90245 × 10¹² / 4.84  × 10¹²

g = 1.0129 m/s²

now, we take the positive direction towards the moon if the spacecraft is moving with constant velocity, a = 0

The apparent weight is measured by the normal force FN

so,

∑F = ma

-FN + mg = ma

-FN + mg = 0

FN = mg

we substitute

FN = 80 × 1.0129

FN = 81.032 N { towards moon }

Therefore, the apparent weight of the astronaut is 81.032 N { towards moon }

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Answer:

Vy = 18 sin 32 = 18 * .5 = 9.54    vertical speed

Vx = 18 cos 32 = 18 * .848 = 15.3 m/s horizontal speed

ty = Vy / 9.80 = .973 to get to top

t = 2 ty = 1.95 sec  (total time in air

Average speed up = 9.54 / 2 = 4.77 sec

Height ball rises = 4.77 * .973 = 4.64 m

Or H = Vy t - 1/2 g t^2

H = 9.54 * .973 - 4.9 * .973^2 = 4.64 m   as found above

D = Vx t = 15.3 *  1.95 = 29.8 m       for distance traveled

Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg  

assume the greatest scale reading = 78.09 kg

Determine the maximum acceleration for these elevators

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N

At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

Answer:

The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, we expect (in theory) an increase in friction when the normal force is increased.

One more thing, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force

Answer:

The units of kinetic energy are mass times the square of speed, or kg⋅m2/s2 kg ⋅ m 2 /s 2. But the units of force are mass times acceleration, kg⋅m/s2 kg ⋅ m/s 2, so the units of kinetic energy are also the units of force times distance, which are the units of work

Explanation:

EDGE 2021

Answer:

I think you are trying to ask 'what happens to the average speed (of humans or animals.) if the distance decreased and time stayed the same (the time such as what hour it is or what second?)' If that is the case then the average speed will be more since the distance decreased. And the time staying the same might affect it I am not fully sure so I will not say anything about that. I hope this helps!

Answer:

I think A is correct.

Explanation:

If it's not I'm sorry probably my fault but I hope this helps:)

Answer:

Explanation: because Keller concluded that the circular obits of the Copernican model weren't correct paths of planets were elleptical

When a 0.80 Kg block is used in place of a 0.25 Kg block, the length of the string is increased by 19.6 cm.

The formula used by the Hooke's Law Calculator is Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or the length by which the spring is being stretched

We'll start by determining the spring's string constant. Specifics below:

Extension (e) = 6.0 cm

Mass (m) = 0.25 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.25 × 9.8 = 2.45 N

Spring constant (K) =?

F = Ke

2.45 = K × 6

Divide both sides by 6

K = 2.45 / 6

K = 0.40 N/cm

The extension will be calculated after the 0.25 kg block is replaced with the 0.80 kg block. As demonstrated below:

Mass (m) = 0.80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.80 × 9.8 = 7.84 N

Spring constant (K) = 0.40 N/cm

Extension (e) = ?

F = Ke

7.84 = 0.40 × e

Divide both sides by 0.40

e = 7.84 / 0.40

e = 19.6 cm

We may thus deduce from the preceding computation that the spring will lengthen by 19.6 cm.

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The de-Broglie wavelength of a person jogging at the rate of 2.70m/s is 3.5 x 10⁻³² m.

De-Broglie wavelength is the ratio of Planck's constant  h to the momentum of the electron p.

Momentum p = mass m x velocity v

Given is the mass of a person = 70kg, the speed of person 2.70m/s, Planck's constant h= 6.63 x 10⁻³⁴J.s

De- Broglie wavelength λ= h/mv

λ = 6.63 x 10⁻³⁴/ ( 70 x 2.70)

λ = 3.5 x 10⁻³² m

Thus the wavelength is 3.5 x 10⁻³² m.

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Some ways to change the resistance in a circuit.resistance can be changed in the circuit by changing the length of the wire, area of the wire, resistivity of the wire.

steady current  means a continuous flow that has been going on forever, without change and without charge piling up anywhere.

A system (e.g. circuit) is in the steady state when the current at each point in the circuit is constant (does not change with time). –In many practical circuits, the steady state is achieved in a short time.

steady current can be produced in the circuit in which resistance is changing by varying the voltage. by increasing or decreasing the voltage  we can maintain a constant or steady current in a circuit which has varying resistance.

                        charecteristics of toasting wires:

The nichrome alloy does not oxidize when heated. Iron wire would rust very quickly at the temperatures seen in a toaster.

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When evaluated at 20 feet per second in a water tunnel, a parachute model that is one-fifth the size does have a drag of 450 pounds. When Reynolds Negligible consequences don't exist.

Something graded, especially if used as a benchmark or guideline, such as to show how far points on a map are from their corresponding real-world distances.

It was created to measure the body temperature of people. It has a mercury-filled bulb at the end of a long, narrow glass tube. The average body temperature of a person might vary between these ranges. Hence, the selection of clinical thermometers.

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Answer:

option 1

Explanation:

Answer:

flat lol, that's the answer

The girl's velocity and the force that the swing exerts on the girl as she passes through the lowest point are 15.34 m / s and 470.82 N respectively

According to law of conservation of energy,

1 / 2 m v1² + m g h1 = 1 / 2 m v2² + m g h2

m = 32 kg

g = 9.8 m / s²

h1 = 16 - 4 = 12 m

v1 = 0 ( Since the girl is released from rest )

h2 = 0 ( Taking the lowest point of the swing as ground level )

m g h1 = 1 / 2 m v2²

g h1 = 1 / 2 v2²

v2² = 2 * 9.8 * 12

v2² = 235.2

v2 = 15.34 m / s

Force acting on the girl due to the swing is the centripetal force.

Fc = m v² / r

Fc = Centripetal force

m = Mass

v = Linear / Tangential Velocity

r = Radius

m = 32 kg

r = 16 m

Fc = 32 * 15.35² / 16

Fc = 470.82 N

Therefore,

a ) The girl's velocity as she passes through the lowest point = 15.34 m / s

b ) The force that the swing exerts on the girl as she passes through the lowest point = 470.82 N

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Answer:

5 newtons

Explanation:

Just divide them

The car is moving with the linear velocity of 44.2 m/s.

We have the diameter of car wheels as 65 cm which are spinning at an angular velocity of 136 rad/s.

We have to determine how fast is the car moving or its linear velocity.

Angular velocity is defined as the rate of change of angular position of a rotating body.

\(\omega = \frac{d\theta}{dt}\)

According to question, we have -

diameter of car wheels = 65 cm

Therefore, the radius will be = 32.5 cm

Angular velocity = 136 rad/s

We know that -

v = r\(\omega\)

v = 32.5 x 136

v = 4420 cm/s

v = 44.2 m/s

Hence, the car is moving with the linear velocity of 44.2 m/s.

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The circuit is a series circuit since all of the components are connected in a single path.

The current that flows through each component is the same, and the voltage across each component is proportional to its resistance.

In this circuit, there are two resistors, R1 and R2, and a battery with an electromotive force (EMF) of E.

The voltage across each resistor can be determined using Ohm's law, which states that

V = IR,

where V is the voltage

           I is the current

           R is the resistance.
The total resistance of the circuit can be calculated using the formula:

R = R1 + R2.

Using Ohm's law, the current in the circuit can be found by dividing the voltage by the total resistance:

I = E / R
The voltage across each resistor can be found using

V1 = IR1 and V2 = IR2.

The total voltage of the circuit is equal to the sum of the voltages across each resistor

V = V1 + V2

Substituting the equations for V1 and V2 into the equation for V, we get;

V = I(R1 + R2)
Thus, we can use the following equations to solve for the different variables in the circuit:
R = R1 + R2
I = E / R
V1 = IR1
V2 = IR2
V = I(R1 + R2)
Using these equations, we can calculate the current, voltage, and power of the circuit.

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Taking the positive direction to be to the right,  the total momentum of this system is - 14kg-m/s

Option B is correct.

momentum is described as the product of the mass and velocity of an object and a vector quantity possessing a magnitude and a direction.

momentum = mass x velocity

momentum 1  = 5 x 8kg = 40 kg-m/s

momentum 2 = 4 x 15 kg = 60 kg-m/s

momentum 3 = 2 x 3kg = 6 kg-m/s

Taking the positive direction to be to the right,  the total momentum of this system is momentum 1  - momentum 2 + momentum 3

total momentum =  40 kg-m/s - 60 kg-m/s + 6 kg-m/s

total momentum  = -20kg-m/ + 6 kg-m/s

total momentum =  - 14 kg-m/s

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Meter #2 is more precise.

There's no information here that tells us which meter is more accurate.