Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and was approaching at 6.00 m/s due south. The second car has a mass of 900 kg and was approaching at 25.0 m/s due west. (a) Calculate the final velocity (magnitude in m/s and direction in degrees counterclockwise from the west) of the cars. (Note that since both cars have an initial velocity, you cannot use the equations for conservation of momentum along the x-axis and y-axis; instead, you must look for other simplifying aspects.) magnitude m/s direction ° counterclockwise from west (b) How much kinetic energy (in J) is lost in the collision? (This energy goes into deformation of the cars.) J

Answers

Answer 1

Answer:

a) v = 11.24 m / s ,    θ = 17.76º   b) Kf / K₀ = 0.4380

Explanation:

a) This is an exercise in collisions, therefore the conservation of the moment must be used

Let's define the system as formed by the two cars, therefore the forces during the crash are internal and the moment is conserved

Recall that moment is a vector quantity so it must be kept on each axis

X axis

initial moment. Before the crash

     p₀ₓ = m₁ v₁

where v₁ = -25.00 me / s

the negative sign is because it is moving west and m₁ = 900 kg

final moment. After the crash

      \(p_{x f}\)= (m₁ + m₂) vx

       p₀ₓ =  p_{x f}

       m₁ v₁ = (m₁ + m₂) vₓ

     vₓ = m1 / (m₁ + m₂) v₁

let's calculate

       vₓ = - 900 / (900 + 1200) 25

       vₓ = - 10.7 m / s

Axis y

initial moment

      \(p_{oy}\)= m₂ v₂

where v₂ = - 6.00 m / s

the sign indicates that it is moving to the South

final moment

     p_{fy}= (m₁ + m₂) \(v_{y}\)

     p_{oy} = p_{fy}

     m₂ v₂ = (m₁ + m₂) v_{y}

     v_{y} = m₂ / (m₁ + m₂) v₂

we calculate

    \(v_{y}\) = 1200 / (900+ 1200) 6

    \(v_{y}\)  = - 3,428 m / s

for the velocity module we use the Pythagorean theorem

      v = √ (vₓ² + v_{y}²)

      v = RA (10.7²2 + 3,428²2)

      v = 11.24 m / s

now let's use trigonometry to encode the angle measured in the west clockwise (negative of the x axis)

      tan θ = \(v_{y}\) / Vₓ

      θ = tan-1 v_{y} / vₓ)

      θ = tan -1 (3,428 / 10.7)

       θ = 17.76º

This angle is from the west to the south, that is, in the third quadrant.

b) To search for loss of the kinetic flow, calculate the kinetic enegy and then look for its relationship

      Kf = 1/2 (m1 + m2) v2

      K₀ = ½ m₁ v₁² + ½ m₂ v₂²

      Kf = ½ (900 + 1200) 11.24 2

      Kf = 1.3265 105 J

      K₀ = ½ 900 25²  + ½ 1200 6²

      K₀ = 2,8125 10⁵ + 2,16 10₅4

        K₀ = 3.0285 105J

the wasted energy is

        Kf / K₀ = 1.3265 105 / 3.0285 105

        Kf / K₀ = 0.4380

         

this is the fraction of kinetic energy that is conserved, transforming heat and transforming potential energy


Related Questions

A ball is dropped from a height of 10m. At the same time, another ball is thrown
vertically upwards at an initial speed of 10m/sec. How high above the ground will the two balls
collide?

Answers

5.1 m

Explanation:

Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by

\(y_1 = 10 - \frac{1}{2}gt^2\) (1)

where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground \(y_2,\) is given by

\(y_2 = v_0t - \frac{1}{2}gt^2\) (2)

At the instant the two balls collide, they will have the same displacement, therefore

\(y_1 = y_2 \Rightarrow 10 - \frac{1}{2}gt^2 = v_0t - \frac{1}{2}gt^2\)

or

\(v_0t = 10\:\text{m}\)

Solving for t, we get

\(t = \dfrac{10\:\text{m}}{v_0} = \dfrac{10\:\text{m}}{10\:\text{m/s}} = 1\:\text{s}\)

We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):

\(y_1 = 10\:\text{m} - \frac{1}{2}(9.8\:\text{m/s}^2)(1\:\text{s})^2\)

\(\:\:\:\:\:\:\:= 5.1\:\text{m}\)

A block of wood is 4 cm wide, 5 cm long, and 10 cm high. It weighs 100 grams. Calculate its volume. Calculate its density. Will the block sink or float in water? Explain. (Remember, the density of water is 1.0 g/cm3.)

Answers

Answer:

\(V=200cm^3\\\\\rho =0.500g/cm^3\)

It will float.

Explanation:

Hello.

In this case, given the width, length and height, we can compute the volume as follows:

\(V=W*L*H\\\\V=4cm*5cm*10cm\\\\V=200cm^3\)

Moreover, since the density is computed via the division of the mass by the volume:

\(\rho =\frac{m}{V}\)

We obtain:

\(\rho =\frac{100g}{200cm^3} \\\\\rho =0.500g/cm^3\)

In such a way, since the solid has a lower density than the water, we infer it will float.

Best regards.

PLS HELP!! This question was never fully solved!

An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg

Answers

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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A 10 kg rock falls 5 meters and hits the ground. Did the rock have any energy just
before it hit the ground? If so, how much? What force did it require, to get the rock to start
moving?

Answers

Answer:

495.5 Joules

Explanation:

Given data

Mass= 10kg

Height= 5meters

g= 9.81m/s^2

Yes the rock will possess potential energy before it hits the ground

The potential energy is expressed as

PE=mgh

substitute

PE= 10*9.91*5

PE= 495.5 Joules

The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.2 m above the ground, how steep a slope can the truck be parked on without tipping over

Answers

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

The maximum steepness of the slope where the truck can be parked without tipping over is approximately 54.55 %.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, C represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

\(tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}\)

The steepness of the slope is therefore;

\(\mathrm{The \ steepness \ of \ the \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100\)

Where;

\(\overline{AM}\) = Half the width of the truck = \(\dfrac{2.4 \, m}{2}\) = 1.2 m

\(\overline{CM}\) = The elevation of the center of gravity above the ground = 2.2 m

\(\mathrm{The \ steepness \ of \ the \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%\)

\(tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}\)

\(Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right) \approx 28.6 ^{\circ}\)

The maximum steepness of the slope where the truck can be parked is 54.55 %.

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The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4

In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject, John Stapp, had a mass of 84.0 kg: a) what is the amount of Work done to stop the John Stapp? b) how much Force was applied to John Stapp?

Answers

84.0 was applied by John Stapp

What is the mass of a block of lead that is 30cm by 80cm by 60cm?

Answers

To calculate the mass of the block, we need to use the formula:

mass = density x volume

The density of lead is approximately 11.34 grams per cubic centimeter.

The volume of the block is:

30cm x 80cm x 60cm = 144,000 cubic centimeters

Therefore, the mass of the block of lead is:

11.34 g/cm3 x 144,000 cm3 = 1,632,960 grams

So the mass of the block of lead is 1,632,960 grams.

The mass of the block of lead is 1632.96 kg.

To find the mass of a block of lead with dimensions 30 cm by 80 cm by 60 cm, we need to know the density of lead. The density of lead is 11.34 g/cm³. The formula for mass is

mass = density x volume.

The volume of the lead block is 30 cm x 80 cm x 60 cm = 144000 cm³.

Therefore, mass = 11.34 g/cm³ x 144000 cm³ = 1632960 g.

The mass of the block of lead is 1632.96 kg.The mass of a block of lead is determined by the formula

mass = density x volume.

The density of lead is 11.34 g/cm³. The block of lead has dimensions of 30 cm by 80 cm by 60 cm, therefore its volume can be calculated as 30 cm x 80 cm x 60 cm = 144000 cm³.The formula for the mass of an object is

mass = density x volume.

From the provided values, we can calculate the mass of the block of lead as follows:

mass = 11.34 g/cm³ x 144000 cm³ = 1632960 g.Since 1 kg = 1000 g,

we can convert the mass from grams to kilograms by dividing the answer by 1000:

mass = 1632960 g / 1000 = 1632.96 kg.

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Drag each label to the correct location on the chart.
Based on Newton's law of universal gravitation, complete the following table.
tum. All rights reserved.
distance increases
mass increases
Gravity Increases When:
distance decreases mass decreases
Reset
Gravity Decreases When:
Next

Answers

When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.

Which Newtonian principle is universal?

Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.

Is there a universal rule governing gravity?

What exactly does the Law of Gravitation apply to  According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.

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When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.

Which Newtonian principle is universal?

Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.

Is there a universal rule governing gravity?

What exactly does the Law of Gravitation apply to  According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.

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It takes the elevator in a skyscraper 4.0 s to reach its cruising speed of 10 m/s. A 60 kg passenger gets aboard on the ground floor.
1. What is the passenger's apparent weight before the elevator starts moving?
2. What is the passenger's apparent weight whilethe elevator is speeding up?
3. What is the passenger's apparent weight afterthe elevator reaches its cruising speed?

Answers

Answer:

1. 588 N

2. 738 N

3. 588 N

Explanation:

time, t = 4 s

initial velocity, u = 0

final velocity, v = 10 m/s

mass, m= 60 kg

1.

Weight of passenger before starts

W =m g = 60 x 9.8 = 588 N

2.

When the elevator is speeding up

v = u + a t

10 = 0 + a x 4

a = 2.5 m/s2

Now the weight is

W' = m (a + g) = 60 (9.8 + 2.5) = 738 N

3.

When he reaches the cruising speed, the weight is

W = 588 N

an air conditioner is label 1500-watt 240v If it is used for 8 hours, calculate the electrical energy that has been used.Required to answer. Single choice.​

Answers

Answer:

Energy = 12000 [kw*h]

Explanation:

In order to solve this problem, we must multiply the power used by the amount of time in use.

\(Energy = Power*time\\Energy = 1500*8\\Energy = 12000 [kW*h]\)

Which of the following objects requires the MOST power to lift?

A. A 2 kg box lifted 1 m in 1 s.
B. A 2 kg box lifted 2m in 1 s.
C. A 2 kg box lifted 1 m in 2 s.
D. A 2 kg box lifted 2 m in 2 s.

Answers

The object requires the MOST power to lift  a 2 kg box 2 m in 1 s. Hence, option (B) is correct.

What is power?

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Power required for lifting a 2 kg box 1 m in 1 s = (2×9.8×1)/1 watt = 19.6 watt.

Power required for lifting a 2 kg box 2 m in 1 s = (2×9.8×2)/1 watt = 39.2 watt.

Power required for lifting a 2 kg box 1 m in 2 s = (2×9.8×1)/2watt =9.8 watt.

Power required for lifting a 2 kg box 2 m in 2 s = (2×9.8×2)/2watt =19.6 watt.

So, The most power required in  lifting a 2 kg box 2 m in 1 s.

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A 1.2 kg ball drops vertically onto a floor hitting with a speed of 15 m/s

Answers

The magnitude of the change in momentum is 36 kg m/s.

The momentum of an object is defined as the product of its mass and velocity.

The symbol for momentum is p. Its unit is kilogram meters per second (kg m/s). When a ball falls vertically onto a surface, the momentum is said to change.

The magnitude of the change in momentum can be found by calculating the difference between the initial momentum and the final momentum.

We can use the equation below to find the change in momentum.Δp = pf - pi

Where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.The initial momentum of the ball can be found using the equation:

p = mv

where p is momentum, m is mass and v is velocity.

Therefore, the initial momentum of the ball is:

p = mv= 1.2 kg × 15 m/s= 18 kg m/s

The final momentum can be found using the same equation, but with a negative velocity since the ball is bouncing back with the same speed but opposite direction.

Therefore, the final momentum is:-18 kg m/s/

The change in momentum can now be calculated using the equation:

Δp = pf - piΔp = (-18 kg m/s) - (18 kg m/s)Δp = -36 kg m/s

Therefore, the magnitude of the change in momentum is 36 kg m/s.

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a plane crashes with a deceleration of 185 m/s. How many g’s is this?

Answers

Answer:

26 g's

Explanation:

Hope this helps~

Have a great day

Zero

if the wavelength of a wave is 15 mm and the speed of the wave is 18,000mm/s what is the frequency of this wave

Answers

Answer:

the frequency of the wave is 13mm

Explanation:

15mm divided by 3 = 5 x 2= 10+3= 13mm so the answer is 13

When practicing reading skills, you should focus on _______.

content recall
comprehension
speed
all of the above

Answers

Answer:

I would say the answer is All the above.

Explanation:

If this wasn't what you were looking for please don't hesitate to comment again! Have a nice day/night! :)

Answer:

all the above

Explanation:

A length of wire is connected to a 9.0 V power pack and an ammeter. The reading on the ammeter is 0.25 A.
Calculate the resistance of the wire. Give the unit.

Answers

The resistance of the wire, given that it is connected to a 9.0 V power pack and an ammeter is 36 ohms

How do I determine the resistance?

From Ohm's law, we understood that the voltage, current and resistance are related according to the following formula:

Voltage (V) = Current (I) × resistance (R)

V = IR

Using the above formula, we can obtain the resistance of the wire as follow:

Voltage (V) = 9.0 VoltsCurrent (I) = 0.25 AResistance (R) = ?

Voltage (V) = Current (I) × resistance (R)

9 = 0.25 × resistance

Divide both sides by

Resistance = 9 / 0.25

Resistance = 36 ohms

Thus, we can conclude that the resistance of the wire is 36 ohms

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Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?

Question 12 options:

Put it in the fridge where it is cold


Cover it with a blanket so it's dark


Warm it up on the stove


There is nothing you can do to change the speed of the reaction

Answers

In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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the photo shows a skateboarder applying a force against one edge of a skateboard as she rides down a hill. how does this action cause the skateboarders motion to change?

A.it applies an unbalanced sideways force that causes a change in direction.

B.it increases the net force pointing down the hill so she speeds up.

C. it applies a balanced sideways force that causes a change in direction.

D. it increases the force of friction so she slows down.

Answers

Option D. This action cause the skateboarders motion to change because it increases the force of friction so she slows down.

What is frictional force?

This is the force that opposes motion or cause a moving object to stop or slow down.

Ff = μmg

where;

Ff is frictional force

μ is coefficient of frcitionm is mass of the objectg is acceleration due to gravity

The frictional force between the skateboard and the hill increases with increase in weight of the skateboard.

As the skateboarder applies the force on one edge of the skateboard, the applied to the skateboard increases which in turn increases the frictional force between the skateboard and the hill, reducing the speed of the skateboarder.

Thus, this action cause the skateboarders motion to change because it increases the force of friction so she slows down.

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You want to double the radius of a rotating solid sphere while keeping its kinetic energy constant. (The mass does not change.) To do this, the final angular velocity of the sphere must be Group of answer choices

Answers

The Final angular velocity of the sphere is : Half of its initial value ( W/2 )

Kinetic energy of a rotating body

Given that The kinetic energy of a rotating body ( K ) = 1/2 IW² --- ( 1 )

where : I = moment of inertia,  w = angular velocity

I = \(\frac{2}{5} MR^{2}\)

Therefore equation ( 1 ) becomes

K = \(\frac{1}{5}MR^2W^2\)   ----- ( 2 )

After doubling the radius

R' = 2R

K' = K

Mass = unchanged

therefore :

  \(\frac{1}{5}MR'^2W'^2 = \frac{1}{5}MR^2W^2\)

= ( 2R )² W'² = R²W²

Resolving equation above

Hence : W' ( new angular velocity ) =  W / 2

In conclusion The Final angular velocity of the sphere is : Half of its initial value ( W / 2).

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Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another 9
km. That part of her trip takes her 2 h. What is her average speed?

Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides

Answers

Answer:

24km/h

Explanation:

go it right on ingenuity 2020

Is this statement true or false?

Tornadoes are accompanied by spinning downdrafts and updrafts that form a funnel cloud.

Answers

Answer:

true true true true true

True true true true true

Question 1

Describe the path light takes as it travels through air and into glass

Question 2

Explain the brightness of light using the wave model of light

Answers

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Question 1 :
The path light bends as it travels through air and into glass.
What is light?
The light is the ray form of energy obtained from the Sun.
The path of light will look like bended when it has crossed the interface of two medium.
As. the light ray falls on the surface of glass travelling through air, the ray appears to bend after refraction.
Thus, the path of light bends as it travels through air and into glass.
———————
Question 2 :
According to the wave theory of light, the energy of radiation depends only on the intensity or wave amplitude (brightness), not the frequency (what type of light; e.g red light or green light; visible light or gamma) According to the particle theory of light states the energy of radiation depend only on the frequency

why do some object remain hot for a long period of time and some object remain hot for short period of time ? urgent​

Answers

Some object remains hot for a long period of time because they have low thermal conductivity and some object remain hot for a short period of time because they have high thermal conductivity.

What is thermal conductivity?

Thermal conductivity is a property of a substance to allow heat to flow through it easily.

Thermal conductivity is a measure of how well a substance will conduct heat or not.

Objects that have high thermal conductivity gain heat easily and also lose heat easily. Hence, they get hot quickly and also get cold quickly.

Objects that have low thermal conductivity gain heat slowly and also lose heat slowly. Hence, they get hot slowly and also get cold slowly.

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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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A bus travels from Houston, Texas to Dallas, Texas, in 4.7 h with an average velocity of 76 km/h to the north. What is the bus’s displacement?

Answers

The bus's displacement from Houston to Texas with average velocity = -16.170 km/h

Evaluation :

average velocity = ( initial velocity -- final velocity )

                                    ( v-u )

displacement = \(\frac{v-u}{t}\)

displacement =  \(\frac{0 - 76 }{4.7}\)

                            = - 16.170 km/h

Average velocity :

Average velocity is determined  as the change in position or displacement (∆x) divided by the time period  (∆t) in which the displacement results . The average velocity could be positive or negative based upon the sign of the displacement. The SI unit of average velocity is defined as  meters per second (m/s or ms-1).

Displacement :

The displacement is commonly the difference in the position of the two marks and is independent of the path covered  when traveling between the two of the  marks. The distance covered , however, is the total length of the path chosen  between the two marks. Displacement defined  as a vector quantity that mean  to "how far out of  the place an object is"; it's the object  overall changes  in  the position.

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1. What kind of force is the force of gravity? (1 Point) contact force
non-contact force electromagnetic force imaginary force

Answers

Answer:

the answer is electromagnetic force because gravity is a force of attraction

An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou

Answers

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Give an example of how a bicycle rider would accelerate? Explain the three different ways a bicyclist could
accelerate.

Answers

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

Ways in which a cyclist can increase the speed of a bicycle

Bicycle riders could accelerate/ increase their speed in various ways

By Changing the gears and by doing so increasing the speedBy Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.By increase the rate at which they are pedalling the bicycle.

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Work of 2 Joules is done in stretching a spring from its natural length to 14 c m beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (14 c m )

Answers

Answer:

F =28.57 N

Explanation:

Assuming that the spring is ideally followed  Hooke's law, This means

F=kx

Here F is the force required to stretch or compress the spring through x distance.

the amount of the work done in the displacement of the spring would be:

W = ∫F.dx

=∫kx dx

=1/2kx^2

=1/2k×0.14^2

⇒ 0.0098k =2

⇒ k = 204.081

Therefore, the force (in Newtons) that holds the spring stretched at the same distance.

F = 204.081×0.14

F =28.57 N

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