Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smaller sphere. If the electric field just outside of the smaller sphere is E0, then the electric field just outside of the larger sphere is

The speed of the ball have in falling 3.6 s is 35.5 m/s.

The speed of the ball is calculated using the equation of a body falling under the influence of gravity or velocity of free fall.

The equation of the motion of the body is given as follows:

v = u - gt

where;

u is the initial velocity

g = acceleration due to gravity

t = time

v = final velocity

Assuming u = 0 m/s, g = 9.8 m/s², t = 3.6 s

v = 0 - 9.8 * 3.6

v = 35.5 m/s

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Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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According to the given Statement the average force is 235.824

The following assumptions are made - The wind is blowing perpendicular to the face of the building. The wind speed is constant and does not change with height. The drag coefficient of 1.0 is a rough estimate. This calculation assumes the wind is laminar and does not take into account any turbulence or vortex shedding that may occur in reality.

The drag coefficient (C) is a dimensionless number that depends on the shape of the object. For a tall building with a flat face, such as the Willis Tower, the drag coefficient is approximately 1.0.

F \(=0.5*1.0*1.3*35840*10^{2}\)

F = 235.824 N (approximately 53,000 pounds).

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Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.

Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.

As the Heat of vaporization for methyl alcohol  (1100) is almost half as that of Heat of vaporization for water (2257) , it means  Methyl alcohol requires less than half as much energy per kg to evaporate than water does.

Answer:

i think its the top one

Explanation:

pls tell me if im wrong  

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

It's c I think ( 4 , 2 , 6 , )

Answer:

320 J

Explanation:

From the question,

KE = 1/2mv².................. Equation 1

Where KE = Kinetic Energy, m = mass of the rock, v = velocity of the rock

Given: m = 40 kg, v = 4m/s

Substitute these values into equation 1

KE = 1/2(40)(4²)

KE = 20×16

KE = 320 J

Hence the kinetic energy of the rock is 320 J

SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.

SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.

SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.

Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.

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Answer:

The order of maximum is   \(n = 5\)

Explanation:

From the question we are told that

  The  diffraction grating is  k  =  300 lines per mm  =  300000 lines per m

   The wavelength is  \(\lambda  =  630 \  nm  =  630 *10^{-9} \  m\)

   Generally the condition for constructive interference is mathematically represented as

      \(dsin \theta = n  * \lambda\)

Here n is the order maximum

d is the distance the grating which is mathematically represented as

    \(d =  \frac{1}{k}\)

=>   \(d =  \frac{1}{300000}\)

=>    \(d =  3.3*10^{-6}\  m \)

So

   \(n  = \frac{dsin \theta}{ \lambda}\)

at maximum  \(sin\theta  =  1\)

     \(n  = \frac{d}{\lambda}\)

=>   \(n  = \frac{3.3*10^{-6}}{630 *10^{-9}}\)

=>   \(n = 5\)

The magnitude and direction of the current "I" so that the magnetic field at the center of the square is zero is equals to 2 Ampere and downward(-y) respectively.

We have a four very long, current-carrying wires in the same plane intersect to form square.

Side of square = 40.0 cm

Magnetic field at the centre of square= 0

We have to determine the current value and direction so that the magnetic field at the center of the square is zero. Let us consider I1, I2, I3 and I respreesnts the current magnitude in first, second, third and fourth wires respectively. So,

I₁ = 8.0 A

I₂ = 20.0 A

I₃ = 10.0 A

Distance between central point of square to any of wire, r = 20 cm or 0.2 m.

From right hand side rule, I has drawn magnetic fields \(\vec B_1 , \vec B_2, \vec B_3 , \vec B_4\) for I₁, I₂, I₃ and I respe respectively. Now, total magetic field at centre of square = 0

\(\vec B_1 + \vec B_2 + \vec B_3 + \vec B_4 = 0\)

=> \( \frac{ \mu_0}{2π} \frac{I_1}{r}(-\hat k) + \frac{ \mu_0}{2π} \frac{I_2}{r}(\hat k) + \frac{ \mu_0}{2π} \frac{I_3}{r}(-\hat k) + \frac{ \mu_0}{2π} \frac{I}{r}(\hat k) = 0 \\ \)

=> I₁ + I₃ = I₂ + I

=> 10 + 8 = 20 + I4

=> I4= 18 - 20 = - 2 Ampere

Here, negative sign indicates that direction of current is opposite to what we assumed.

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Complete question:

Four very long, current-carrying wires in the same plane intersect to form a square 40.0 cm on each side, as shown in Fig. E28.26. Find the magnitude and direction of the current "I" so that the magnetic field at the center of the square is zero.

Answer: 0.715

Explanation: from grams to newtons

In order to solve this, we will use the formula

where n is the index of infraction, c is the speed of light (3x10^8), and v is the medium in which the velocity is measured

solving for n,

n = (3x10^8)/(2.75x10^8) = 1.09

Before the bus starts moving, the bus and the skater are both standing still.

When the bus starts moving and pulls away from the bus-stop, the skater stays right where she is.  

The people outside on the sidewalk see her standing still, and they see the bus moving out from under her.  

The other passengers on the bus see her rolling backwards down the aisle, toward the back of the bus.

Answer:

I KNOW THE ANSWER IT WILL COST 30$

Explanation:

Answer:

The gravitational force Asteroid A experiences is greater than the gravitational force Asteroid C experiences

9\(\^{i}\)+8\(\^{j}\)/\(\sqrt{136}\)

F=(9.00i-8.00j)N

we are now to find the unit vector

according to formula

unit vector = \(\frac{vector of F}{Magnitude of F}\)

Now :

vector form of F = 9\(\^{i}\)+8\(\^{j}\)

magnitude of F =\(\sqrt{9^2+8^2}\)

magnitude of F=\(\sqrt{136}\)

now put that in formual

unit vector = 9\(\^{i}\)+8\(\^{j}\)/\(\sqrt{136}\)

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D. if I increases, R must decrease

Explanation

Ohm's Law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit.it says

the triangle states the 3 formulas:

so

Step 1

if we let V constant

now, as the product of R and I must be constant:

if you increase the resistance, the current must decrease, or if yuo increase the current, the resistance must decrease to maintain the same voltage ( constant)

therefore, the correct answer is

D. if I increases, R must decrease

I hope this helps you

Graphical analysis of motion gives the graphical the relationships between position, velocity, and acceleration, versus time

2. Please find attached the required position versus time and acceleration versus time graphs

3. Please find attached the required velocity versus time and position versus time graphs

The reasons the attached graphs are correct are given as follows:

2. The given coordinates of the vertex points obtainable from the graph is first written as follows:

\(\begin{array}{|c|c|c|c|c|}\underline {Time, \ t}&\underline {Velocity, \ v}&Acceleration, a&\underline {Distance , \ s =v\cdot \Delta t+\dfrac{1}{2} \cdot a \cdot (\Delta t)^2}&Position\\0&-1&0&0&0\\2&1&1&0&0\\4&-1&-1&0&0\\6&1&1&0&0\\10&1&0&4&4\\12&0&-0.5&1&5\end{array}\)The distance covered between time intervals of time, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Other values on the graph obtained by calculation on a spreadsheet are;

\(\begin{array}{|l|cl|}Time \ (s)&&Position \ (m)\\0.5&&-0.375\\1&&-0.5\\1.5&&-0.375\\2.5&&0.375\\3&&0.5\\3.5&&0.375\\4.5&&-0.375\\5&&-0.5\\5.5&&-0.375\\6.5&&0.5\\7&&1\\7.5&&1.5\\8&&2\\8.5&&2.5\\9&&3\\10&&4\\10.5&&4.4375\\11&&4.75\\11.5&&4.9375\\12&&5\end{array}\right]\)

Please find attached the acceleration versus time graph

3. The coordinates of the points are presented as follows:

\(\begin{array}{|c|cc|}\underline{Time\ (s)}&&\underline{Acceleration\ (m/s^2)}\\0&&0.5\\2&&0.5\\2&&0\\4&&0\\4&&-0.5\\6&&-0.5\\6&&0\\8&&0\\8&&0.5\\10&&0.5\\10&&-0.5\\12&&-0.5\end{array}\right]\)

The distance covered between time intervals, s, is given as follows;

\(s = v \cdot \Delta t + (1/2) \cdot a \cdot ( \Delta t)^2\)

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Using a spreadsheet application, more detailed values of the position can be found as shown in the graph created with MS Excel

0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6, 6.5, 7, 7.5, 8, 8.5, 9, 9.5, 10, 10.5, 11, 11.5, 12

0, 0.06, 0.25, 0.56, 1.00, 1.50, 2, 2.5, 3, 3.5, 3.81, 4.00, 4.06, 4.06, 4.06, 4.06, 4.06, 4.13, 4.31, 4.63, 5.06, 5.50, 5.81, 6, 6.06

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Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer:

e^-4t e^-5t

Explanation:

solving s²+9s+20 quadratically we have (s+4)(s+5)

x(s) can be written as x(s) =(1/s+4)(1/s+5)

if we take the laplace inversve

L-¹ (s)=L-1(1/s+4) L-1(1/s+5)

we have e^-4t e^-5t

Work done by gravity when it moves from A to C will be 288.6 joule

Applying conservation of energy between point A and B,

7.4xgx5.9 = 1/2x7.4xv2 + 7.4xgx3.2

873.2 = 7.4v2 + 473.6

v = 7.34 m/s

It should be noted that to find velocity at C, which has come down to a height of 2 meter, it means it has travelled by 5.9-2 =3.9 m

so, v2 = 2gh = 20x3.9 =

v = 8.83 m/s

Work done by gravity when it moves from A to C = mxgx(5.9-2) = 288.6 joule

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Answer:

A

Explanation:

F = m * a

100 = 5 * a

a = 100/5 = 20 m/s^2

(PLEASE GIVE BRIANLIEST)

The average speed is not equal to the sum of the speeds divided by 2 because the car takes different times to cover the distance while going up and coming down the hill.

The average speed can be calculated as the total distance covered divided by the total time taken. As the speeds are constant, we can use the formula:

distance = speed * time

Let the distance traveled be "d". The time taken to go up the hill is "t1" and the time taken to come down is "t2".

d = 35 * t1 = 69 * t2

The total time taken for the round trip is t1 + t2.

The average speed is given by:

average speed = d / (t1 + t2) = d / (d/35 + d/69)

So the average speed can be calculated as follows:

average speed = d / (d/35 + d/69) = d * (35 + 69) / (35 * 69) = 104 / 2445 = 8 / 205 km/h

Without lenses, his near point is at 66.7 cm. In order to read a material at 50 cm, he needs a lens of 2.0D.

The near point is the closest distance of distinct vision. We can obtain the focal length from the power as in; f = 100/2.5 = 40cm

1/40 = -1/v + 1/25

1/v = 1/25 - 1/40

1/v = 0.04 - 0.025

v = 66.7 cm

Now if he wants to read at 50 cm

1/f = -1/50 + 1/25

1/f = 1/25 - 1/50

1/f =  0.04 - 0.02

f = 50cm

Power = 100/50 cm = 2 D

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A block of wood resting on a steel desk experiences a force of friction that opposes the applied force. The force of friction depends on the coefficients of friction and the normal force acting on the block.

At time t=0, the force applied on the block is 15.8 N. Since the block is at rest, the frictional force must be equal and opposite to the applied force to maintain static equilibrium. Therefore, the force of friction acting on the block at t=0 is:

Ffriction = Fapplied = 15.8 N

Now, when the applied force is greater than the maximum static frictional force (i.e., Fs > μsN), the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force is given by:

Ffriction = μkN

where μk is the coefficient of kinetic friction and N is the normal force acting on the block.

The normal force N acting on the block can be calculated using Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:

ΣF = ma

Since the block is moving horizontally, its acceleration in the vertical direction is zero, and the normal force N is equal to the weight of the block:

N = mg

where m is the mass of the block and g is the acceleration due to gravity.

Substituting the given values, we get:

N = 5.760 kg × 9.81 m/s^2 = 56.47 N

The maximum static frictional force Fs can be calculated using:

Fs = μsN

Substituting the given values, we get:

Fs = 0.455 × 56.47 N = 25.68 N

Since the applied force is greater than the maximum static frictional force, the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force can be calculated using:

Ffriction = μkN

Substituting the given values, we get:

Ffriction = 0.205 × 56.47 N = 11.56 N

Therefore, the force of friction acting on the block at t=0 is 15.8 N, and the force of friction acting on the block when it starts to move is 11.56 N.

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Answer:

carbon.

Explanation:

the reaction would then create c02 as a product

The speed at the top of the loop is √gR.

Let the starting point be A, the lower point of loop be B and the top of loop be C.

So, at A the car is having only potential energy.

PE = mgh

At B, the kinetic energy,

KE = 1/2 mv²

a) At point C,

mv²/R = mg

The velocity at the top point, v(C)

v(top) = √gR

b) According to Conservation of energy, at B and C,

1/2 mv(B)² = 1/2 mv(C)² + mg(2R)

v(B)² = gR + 4gR

Therefore, v(B) = √5gR

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