We have the next formula
\(\text{distance}=\text{rate}\times\text{ time}\)In this case x is the faster speed and x-4 is the slower speed, we have the next equation
\(180=5x+5(x-4)\)We simplify
\(180=5x+5x-20\)\(180=10x-20\)Then we need to isolate the x
\(10x=200\)\(x=\frac{200}{10}=20\)Then for x-4
20-4=16
The rates of the cyclists are
16 km/hr
20 km/hr
Please solve and show the mathematical steps.
Answer:
Explanation:
W = Fd = 310(210) = 65,100 J
W = KE = ½mv²
v = √(2KE/m) = √(2(65100)/132) = 31.40642... = 31.4 m/s
W = PE = mgh = mgdsinθ
d = W/mgsinθ = 65100/(132(9.81)sin23) = 128.66488... = 129 m
Answer:
a. WD = 65100 J
b. v = 31.4 m/s
c. 129 m
Explanation:
WD = work done (Nm or J)
F = force (N) = 310
d = distance (m) = 210
P = power (W or J/s)
m = mass (kg) = 132
a = acceleration (m/s²)
v = final velocity (m/s)
u = initial velocity (m/s)
s = displacement (m) = 210
\(d_{i}\) = distance up incline (m)
Θ = angle of incline (°) = 23
g = gravity (m/s²) = 9.81
O = opposite
H = hypotenuse
Formulas:
WD = F.d
F (or net F) = ma
v² = u² + 2as
sin(Θ) = O/H
a.
WD = F.d
WD = 310 × 210
WD = 65100 J
b.
Ignoring friction and air resistance:
net F = 310
F = ma:
310 = 132a
a = 2.34848485
v² = u² + 2as:
v² = (0)² + 2(2.348...)(210)
v² = 986.363637
v = 31.4064267 → 31.4 m/s
c.
Coasting means no cycling by cyclist so no F produced up the incline
On incline:
F parallel to incline due to gravity = -132g.sin(23)
F parallel to incline due to gravity = -132(9.81)(0.390731128)
F parallel to incline due to gravity = -505.965552
F = ma:
net F parallel to incline = -505.965552
\(-505.965552 = 132a_{i}\)
\(a_{i} = -3.83307236\)
\((v_{i}) ^{2} = (u_{i})^{2} + 2(a_{i})(d_{i}):\)
\(u_{i} = 31.4064267\)
\(v_{i} = 0\)
\((0)^{2} = (31.4064267)^{2} + 2(-3.83307236)(d_{i}) \\\\ 0 = 986.363638 - 7.66614472(d_{i}) \\\\ 7.66614472(d_{i}) = 986.363638 \\\\ d_{i} = \frac{986.363638}{7.66614472} \\\\ d_{i} = 128.664886\) → 129 m
HELP PLEASEEEEEE HELP PLEASE
The letter that represents the various descriptions is as follows:
5.) Angle of incidence: B
6.) Object: D
7.) Plain mirror:A
8.) Reflection: E
9.) Angle of reflection: C
10.) Normal: F
How does the diagram explain the law of reflection?The law of reflection in a plain mirror states that the angle of reflection is equal to the angle of incidence.
The diagram explains the law of reflection on a plain mirror because it shows the reflection of the object D as E after creating an angle of incidence B on the plane mirror surface A which is equal to the angle of reflection C.
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Using conservation of energy, how fast would a rollercoaster be traveling at a point half way above the ground where it started from, assuming that is started at rest and 95.7 m above the ground?
Given,
The initial height of the rollercoaster, h₁=95.7 m
The height at which the speed of the rollercoaster is required, h₂=h₁/2=47.85 m
From the law of conservation of energy, the total energy of a system will always remain constant. That is, the potential energy lost by the rollercoaster as it descends will be equal to the kinetic energy gained by it.
Thus the kinetic energy of the rollercoaster halfway above the ground is given by,
\(\begin{gathered} \frac{1}{2}mv^2=mg\Delta h \\ =mg(h_1-h_2) \\ =mg(h_1-\frac{h_1}{2}) \\ =mg\frac{h_1}{2}_{} \end{gathered}\)Where m is the mass of the rollercoaster, v is the speed of the rollercoaster halfway above the ground, and g is the acceleration due to gravity.
On further simplifying the above equation,
\(\begin{gathered} \frac{1}{2}v^2=g\frac{h_1}{2} \\ \Rightarrow v=\sqrt[]{gh_1} \end{gathered}\)On substituting the known values,
\(\begin{gathered} v=\sqrt[]{9.8\times95.7} \\ =30.62\text{ m/s} \end{gathered}\)Thus the speed of the rollercoaster halfway above the ground from where it started is 30.62 m/s
The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
numner 5 part a and b and c and d
5)
a)
In order to calculate the force acting on the masses, we can use the formula below:
\(F=\frac{G\cdot M\cdot m}{d^2}\)Where G is the gravitational constant (G = 6.674 * 10^-11), M is the greater mass, m is the smaller mass and d is the distance between the masses.
So, for M = 6 * 10^24 kg, m = 1 kg and d = 6.4 * 10^6 m, we have:
\(\begin{gathered} F=\frac{6.674\cdot10^{-11}\cdot6\cdot10^{24}\cdot1}{(6.4\cdot10^6)^2} \\ F=\frac{40.044\cdot10^{13}}{40.96\cdot10^{12}} \\ F=9.78\text{ N} \end{gathered}\)b)
The force calculated in item a) will act on both masses, therefore the force acting on the larger object is also F = 9.78 N.
c)
The acceleration can be calculated using the second law of Newton:
\(\begin{gathered} F=m\cdot a \\ 9.78=1\cdot a \\ a=9.78\text{ m/s2} \end{gathered}\)d)
Using the second law of Newton again, we have:
\(\begin{gathered} F=M\cdot a \\ 9.78=6\cdot10^{24}\cdot a \\ a=1.63\cdot10^{-24}\text{ m/s2} \end{gathered}\)What happens when a negatively charged object A is brought near a neutral object B?
A. Object B gets a negative charge.
B. Object B gets a positive charge.
C. Object B stays neutral but becomes polarized.
D. Object A gets a positive charge.
E. Object A loses all its charge.
Answer: Option B
Explanation : When a negatively charged object A gets in contact with the neutral object B, the negative charge of object will induce the opposite charges on object B. Hence, there will be a positive charge on object B
Explain the energy transformation occuring when shooting a rubber band across the room.
The rubber band has potential energy stored. When it is released the potential energy is converted to kinetic energy.
Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A 500 N employee decides to catch a ride by sitting on a 1,000 N box for a 50 m trip as shown below:
What is the work done by the employee on the box?
Answer:
0 j
Explanation:
The work done by the employee on the box at the given zero displacement is 0 J.
The given parameters;
Constant velocity of the conveyor, v = 4 m/sWeight of the employee, W = 500 NWeight of the box, W = 1,000 NDistance of the trip, h = 50 mThe work done by the employee on the box is calculated as follows;
W = Fd
where;
F is the applied force on the box by employee = weight of the employeed is the distance through which the box is movedSince the employee sits on the box without moving it, the distance moved by the box = 0
W = 500 x 0
W = 0 J
Thus, the work done by the employee on the box is 0 J.
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URGENT HELP PLS
(a) Find the frequency ratio between the two frequencies f1 = 320 Hz and
½2 = 576 Hz.
S) If we go down from / by an interval of a fourth, find the frequency ratio filfi.
(c) Find the frequency of f3.
The frequency of f3 is approximately 716 Hz.
What is frequency?The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.
a. Given two frequencies, f1 and f2, the frequency ratio is as follows:
frequency ratio= \(\frac{f2}{f1}\)
Inputting the values provided yields:
frequency ratio = \(\frac{576}{320Hz}\) =1.8.
As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.
b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:
frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)= \(\frac{f}{ (f1 / 1.3348) }\)
By dividing the numerator and denominator by 1.3348, we may make this more straightforward:
frequency ratio= (f × 1.33348)/f1
As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.
c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831
Therefore, the frequency of f3 is:
f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz
Therefore, the frequency of f3 is approximately 716 Hz.
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two identical balls are rolling down a hill ball 2 is rolling faster than ball 1 which ball has more kinetic energy
Label each of these as either tranverse or longitudinal. And either mechanical, or electromagnetic.
1. microwave radiation
2.sound through air
3.vibrations of an ear drum
4. sound through water
5.radiant heat
6. radio broadcasts
7.visible light
a positively-charged particle ( q) is at rest in the plane between two fixed bar magnets, as shown. the magnet on the left is three times as strong as the magnet on the right. which choice below best represents the resultant magnetic force exerted by the magnets on the charge?
The resultant force exerted by the magnets on the charge will be zero.
According to the Lorentz force equation, only moving charges experience magnetic forces. Therefore, a charge at rest experiences no force and does not move. Only moving charges can experience a magnetic force, so the force on a stationary charge is zero. The magnetic force is always perpendicular to the velocity of the charged particles, so the particles move in a circular motion. The positive charges above move vertically through the magnetic field and are deflected. The correct rule below predicts the direction in which positive charges are deflected. A similar left-hand rule predicts the deflection of negative charges.
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differences between
hor
rse
and horse
solenoid is .3 m long and is wound with 2 layers of wire. the inner layer consists of 300 turns, the outer alyter of 250 turns. if the current in both layers are 3 A and in the same direction what is the magnetic field at the center of the solonoid?
Answer:
Explanation:
Magnetic field due to a solenoid
B = μ₀ nI where n is no of turns per unit length and I is current
for outer layer of turns
B = μ₀ x (250 / .3) x 3
= 4π x 10⁻⁷ x (250 / .3) x 3
= 3.14 x 10⁻³ T
for inner layer of turns
B = μ₀ x (300 / .3) x 3
= 4π x 10⁻⁷ x (300 / .3) x 3
= 3.77 x 10⁻³ T
Total magnetic field
= (3.14 + 3.77 ) x 10⁻³ T
= 6.91 x 10⁻³ T .
how is the law of conservation of energy different to the first law of thermodynamics
The law of conservation of energy is a general principle that applies to all closed systems, while the first law of thermodynamics is a specific application of this principle to thermodynamic systems.
How is the law of conservation of energy different to the first law of thermodynamics
The law of conservation of energy and the first law of thermodynamics are related, but they are not exactly the same thing.
The law of conservation of energy states that the total energy of a closed system remains constant over time. Energy can be transformed from one form to another (such as from potential to kinetic energy), but the total amount of energy in the system remains constant. This is a fundamental law of physics and applies to all systems, not just thermodynamic ones.
The first law of thermodynamics is a specific application of the law of conservation of energy to thermodynamic systems. It states that the total energy of a thermodynamic system (including its internal energy, potential energy, and kinetic energy) is constant, but energy can be transferred into or out of the system in the form of heat or work. In other words, the first law of thermodynamics is a statement about the relationship between energy and work in thermodynamic processes.
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You are a musician and want to know the frequency of a guitar string. You measure the length of the string to be 0.6 meters and the tension in the string to be 60 Newtons. If the mass of the string is 0.01 kg, what is the frequency of the string? (Units: frequency -hertz (Hz), length -meters (m), tension -newtons (N), mass -kilograms (kg))
Answer:
Explanation:
I frequency = 278 Hz
Use the force diagrams below to determine whether the cart is not moving, moving at a constant speed speeding up or slowing down
a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.
What do you understand by force and friction?Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.
Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.
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What is the atomic number of this element?
A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How long was the stone in the air before hitting the ground? How far did the rock land from the edge of the cliff?
Answer:
Substitute the numbers for YOUR problem this is NOT the answer.
Explanation:
A spring scale hung from the ceiling stretches by 5.9 cm
when a 1.6 kg
mass is hung from it. The 1.6 kg
mass is removed and replaced with a 2.1 kg
mass.
Part A
What is the stretch of the spring?
Express your answer with the appropriate units.
The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.
The stretch of the spring is given by:
stretch = (mass x gravity x length) / (spring constant)
where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).
We can rearrange this equation to solve for the stretch of the spring:
stretch = (mass x gravity x length) / (spring constant)
length = (spring constant x stretch) / (mass x gravity)
Substituting the given values, we get:
length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)
Simplifying, we get:
length = 0.236 m
Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.
A small car with mass 0.610 kg
travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m
If the normal force exerted by the track on the car when it is at the top of the track (point B
) is 6.00 N
, what is the normal force on the car when it is at the bottom of the track (point A
)?
Express your answer with the appropriate units.
The normal force on the car when it is at the bottom of the track is 8.84 N.
At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:
N = mg + mv²/r
where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.
Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:
N = mg
Substituting the given values, we get:
6.00 N = (0.610 kg)(9.81 m/s²)
Solving for g, we get:
g = 9.68 m/s²
At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:
N = mg - mv²/r
Substituting the known values, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)
Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:
mg(2r) = (1/2)mv²
where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:
v = sqrt(2gr)
Substituting the known values, we get:
v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s
Substituting this value of v into the equation for N, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N
Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.
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Which statement is supported by the graph?
From the graph it is clear that, as the concentration of carbon dioxide emitted increases, the global temperature increases. Hence, option B is correct.
What is global warming ?Global warming is the rising of temperature of earth surface allover the world by some environmental imbalance. The most contributing factors to the rise in global temperature is greenhouse gas effect.
Gases such as carbon dioxide, methane oxides of nitrogen etc. are intensely absorbing the heat radiating back from earth and keep the heat in earth surface itself.
Therefore, emission of carbon dioxide definitely increases the temperature of the globe. It is very clear from graph that, global temperature is rising with carbon dioxide concentration. Thus, option b is correct.
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Your complete question is attached below:
A tennis ball thrown at a velocity of 25.0 m/s at 53.1° lands exactly 3.00s later on the top of a building. Calculate the horizontal distance it traveled and the height of the building.
Answer:
horizontal distance it traveled is 45 m
the height of the building is 15 m
Explanation:
X = Vo cos 53.1 . t = 25 x 0.6 x 3
X = 45 m
Y = Vo sin 53.1 t - 1/2 g t²
Y = 25 x 0.8 x 3 - 1/2 x 10 x 9
Y = 60 - 45
Y = 15 m
The the figure shows a famous roller coaster ride. You can ignore friction. If the roller coaster leaves Point Q from rest, what is its speed at the top of 25 m peak(Point s
Answer:
22 m/s
Explanation:
PEf +KEf =PE0 +KE0 →PE0 −PEf =KEf
−mgΔy= 1 mv2 →v= −2gΔy = −2(9.8 m/s2)(−25 m)=22 m/s
Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation
F = {G m_1 m_2}/{r^2},
where F is the magnitude of the gravitational attraction on either body, m_1 and m_2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In SI units, the units of force are kg x m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?
The units of G must be C. m³ / ( kg s² )
What is Newton's gravitational law?
Every particle in the universe is pulled to every other particle with a force that is directly proportional to the product of their masses and inversely proportional to their separation from one another, according to Newton's Law of Universal Gravitation.
In the equation above, the constant proportionality is the universal gravitational constant (G). Henry Cavendish conducted an experiment to determine G's precise value. The equation for G is G = 6.673 x 10-11 N m2/kg2.
The Universal Gravitational Law may explain everything, from how an apple falls off a tree to why the moon revolves around the earth. To understand the beauty of the universal gravitational law, watch the video.
F = Gravitational Force ( Newton )
G = Gravitational Constant ( 6.67 × 10⁻¹¹ Nm² / kg² )
m = Object's Mass ( kg )
R = Distance Between Objects ( m )
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if a certain car, going with speed v1, rounds a level curve with a radius r1, it is just on the verge of skidding. if its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:
Answer:
The correct answer is 4R1
Explanation:
According to the given scenario ,the radius of the tightest curve on the same road without skidding is as follows:
As we know that
Centeripetal Acceleration is
= v^2 ÷ r
In the case when velocity becomes 2 times so the r would be 4 times
So, the radius of the tightest curve on the same road without skidding is 4R1
5. What occurs when an enzyme and a substrate interact at an
active site?
a. Activation energy is reduced.
b. The products are bound irreversibly.
c. The enzyme is changed by the reaction.
d. Activation energy is increased.
Answer:
B
Explanation:
The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex
When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.
What are enzymes?Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.
All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.
Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.
Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.
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Now think creatively about who you might have been had you been raised by other parents. Prepare three brief descriptions of how you might have developed using any three to four styles of parenting .
by using all the four type of parenting here is the descriptive answer which include 4 types of parenting by parents.
When a child queries the justification for a regulation, authoritarian parents are infamous for responding, "Because I said so," They are more concerned with obeying than they are with negotiating. Parental authority figures may substitute punishment for instruction. So instead of instructing a child on how to make better decisions
Parents who are authoritative put time and effort into avoiding behavioral issues before they arise. Additionally, they employ positive discipline techniques like reward and praise systems to reinforce good conduct.
Parents that are liberal with their children typically act more like friends than parents. They frequently encourage their kids to talk to them about their issues, but they typically don't make an attempt to discourage poor decisions or misbehavior because they are either uninvolved parents who don't understand how kids develop, or they are unaware of it.
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When you think about and describe the characteristics of a giraffe, what type of model are you using?
Answer:
The giraffe is the tallest of all mammals. It reaches an overall height of 18 ft (5.5 m) or more. The legs and neck are extremely long. The giraffe has a short body, a tufted tail, a short mane, and short skin-covered horns
10. In a laboratory experiment, students recorded the
following length data: 12.2 cm, 12.1 cm, 12 cm,
11.9 cm, and 12.20 cm. (a) Determine the average
length and express the answer using the correct
number of significant figures. (b) Based on your
average length calculation in part (a), discuss the
importance of recording measurements to the
appropriate number of significant figures.
a) 12.1 Average.
B) It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.
What does the average?A data set's mean (average) is calculated by summing all of the numbers in the set, then dividing by the total number of values in the set. When a data collection is ranked from least to greatest, the median is the midpoint.The mean, median, and mode are the three primary varieties of average. Each of these methods operates slightly differently and frequently yields values typically a little off. The average that is most frequently used is the mean. You add all the values and divide this sum by the total number of values to obtain the mean value.Averages are mostly used to track changes over time within a sample group or cohort.Since averages can be used to compare different quantities of the same category, we employ them. The calculation of averages has limits since it cannot reveal how something is distributed among individuals. For instance, the distribution of income is not shown by per capita income.A) Determine the average length and express the answer using the correct number of significant figures:
12.2+12.1+12=36.3/3 = 12.1 Average.
B) Based on your average length calculation in part a, discuss the importance of recording measurements to the appropriate number of significant figures:
It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.
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