Two lines meet at a point that is also the vertex of a right angle. Set up and solve an equation to find the value of. Find the measurements of ∠CAE and ∠BAG.



1: What is the value of x?



2: What is the value of ∠CAE?



3: What is the value of ∠BAG?

The speed of the roller coaster car when it is 10 m up the second hill is approximately 12.17 m/s.

To determine the speed of the roller coaster car when it is 10 m up the second hill, we can use the principle of conservation of mechanical energy.

The total mechanical energy of the car remains constant throughout the motion, neglecting any energy losses due to friction or air resistance.

The total mechanical energy (E) of the car can be expressed as the sum of its kinetic energy (KE) and potential energy (PE):

E = KE + PE

Initially, when the car crests the first hill at a height of 20 m, all of its energy is in the form of potential energy since its velocity is zero at the crest. Therefore, at the crest of the first hill:

E1 = PE1

When the car rolls down to the ground level, all of its potential energy is converted into kinetic energy since its height is zero. Therefore, at the bottom of the first hill:

E2 = KE2

Finally, when the car climbs the second hill to a height of 10 m, its mechanical energy will be the sum of kinetic and potential energy. Therefore, at a height of 10 m on the second hill:

E3 = KE3 + PE3

According to the principle of conservation of mechanical energy, the total mechanical energy at each point remains the same:

E1 = E2 = E3

Now let's calculate the speeds of the car at the different points:

At the crest of the first hill (20 m high), the potential energy is given by:

PE1 = m * g * h1

where:

m = mass of the car (500 kg)

g = acceleration due to gravity (approximately 9.8 m/s^2)

h1 = height of the crest (20 m)

PE1 = 500 kg * 9.8 m/s^2 * 20 m

PE1 = 98,000 J

At the bottom of the first hill (ground level), the kinetic energy is given by:

KE2 = (1/2) * m * v2^2

where:

v2 = speed of the car at the bottom of the first hill (10 m/s)

KE2 = (1/2) * 500 kg * (10 m/s)^2

KE2 = 25,000 J

At a height of 10 m on the second hill, the potential energy is given by:

PE3 = m * g * h3

where:

h3 = height of the second hill (10 m)

PE3 = 500 kg * 9.8 m/s^2 * 10 m

PE3 = 49,000 J

Since the total mechanical energy is conserved:

E1 = E2 = E3

PE1 = KE2 = KE3 + PE3

Solving for KE3:

KE3 = PE1 - PE3 + KE2

KE3 = 98,000 J - 49,000 J + 25,000 J

KE3 = 74,000 J

Now, we can find the speed of the car at a height of 10 m on the second hill using the kinetic energy formula:

KE3 = (1/2) * m * v3^2

Solving for v3:

v3^2 = (2 * KE3) / m

v3^2 = (2 * 74,000 J) / 500 kg

v3^2 = 148 J / kg

v3 = sqrt(148 J / kg)

v3 ≈ 12.17 m/s

Therefore, the speed of the roller coaster car when it is 10 m up the second hill is approximately 12.17 m/s.

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Answer:

March 21 = Vernal Equinox

Artic = North Pole

December 21 = Winter Solstice

Meridians = Longitude

September 23 = Autumnal Equinox

Greenwich, England = Prime Meridian

Antarctic = South Pole

Marianas Trench = Lowest point on earth

Parallels = Latitude

International Date Line = 180th Meridian

Explanation:

Answer:

what data table?

i can help if you attach a picture of the data :)

Answer:

equation average velocity = total distance

equation average velocity = total distance

Explanation:

1. The deceleration of the aeroplane in the 35s is -1.6m/s²

2. The force acting on the aeroplane is 4.0× 10⁵N

3. The momentum of the aeroplane when its speed is 6.0m/s is 15 ×10⁶kgm/s

The equation of motion are used in solving problems related to motion. The equations of motion are

1. v = u+ at

2 S = ut + 1/2at²

3. v² = u²+2as

where v is the final velocity

u is the initial velocity

S is the distance

t is time

a is the acceleration

The deceleration of the plane after 35s can be calculated as;

v = u+at

v= 6m/s, u= 62m/s , t = 35s

6 = 62+35a

35a = 6-62

35a =- 56

a = - 56/35

a = -1.6m/s²

the negative sign shows that the plane decelerates.

The force acting on the plane is calculated as;

F = ma

F = 2.5×10⁵× 1.6

F = 4× 10⁵N

The momentum of the plane at 6m/s is ;

p = mv

p = 2.5×10⁵ × 6

p = 1.5× 10⁶ kgm/s

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The pressure at a point in a fluid depends on its weight.

Weight is the product of mass of the object and the acceleration due to gravity.

Fluid pressure is the pressure at a point inside a fluid due to the weight of the fluid.

The pressure in liquids can be calculated using the following relationship,

\(P_{fluid}\) = P + ρgh

where,

\(P_{fluid}\) = pressure at a point in the fluid

P = pressure at reference point

ρ = Density of liquid

g = gravitational acceleration (relative to the ground g = 9.8 m/s)

h = Height from reference point

Two factors affect fluid pressure.

These two elements are the depth and density of the fluid.

Therefore the fluid pressure depends on the weight at a point.

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When shooting a bow and arrow, the archer pulls back the string and flexes the bow, storing potential energy.

Potential energy is the energy stored in an object due to its position or configuration. This type of energy is the stored energy of an object, which can be released and transformed into other forms of energy, such as kinetic energy. Potential energy is associated with forces such as gravity, electrical, and chemical, which can cause a change in an object’s energy state. Examples of potential energy include a stretched bow and arrow, a roller coaster at the top of a hill, and a compressed spring.

This potential energy is then transferred to the arrow in the form of kinetic energy. The arrow is then put in motion by the archer and due to the force of the bowstring, work is done in the form of acceleration. The arrow is then released and the kinetic energy propels it towards the target.

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Answer:

it was Ernest Rutherford

The work done by the applied force is 21.23 J.

The work done by the gravity is 29.4 J.

The magnitude of the normal force between the block and the wall is 9.8 N.

The work done on the block include the following;

where;

The applied force on the block is calculated as follows;

Fsinθ - μmgsin(90) = ma

at a constant velocity, the acceleration of the block = 0

Fsinθ - μmg = 0

Fsinθ = μmgsinθ

F =  μmg/sinθ

F = (0.4 x 1 x 9.8)/sin(29)

F = 8.09 N

The work done by the applied force is calculated as;

W = Fcosθ x d

W = (8.09 x cos29) x 3

W = 21.23 J

The work done by the gravity is calculated as follows;

W = Fn cosθ x d

where;

W = mg cosθ x d

W = 1 x 9.8 x cos(0) x 3

W = 29.4 J

The magnitude of the normal force between the block and the wall is calculated as follows;

Fn = mg cosθ

where;

Fn = 1 x 9.8 x cos(0)

Fn = 9.8 N

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1 meter per second squared is equivalent to 0.001 kilometer per second squared.

To convert 1 meter per second squared (m/s²) into kilometer per second squared (km/s²), we need to consider the conversion factor between meters and kilometers.

1 kilometer is equal to 1000 meters, so we can use this conversion factor to convert the units.

First, let's convert the acceleration from meters per second squared to kilometers per second squared:

1 m/s² = (1/1000) km/s²

Therefore, 1 meter per second squared is equal to 0.001 kilometer per second squared.

So, 1 m/s² = 0.001 km/s².

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The primary indicator of an object's position and speed is its velocity.It is the distance that an object travels in one unit of time.The displacement of the item in one unit of time is the definition of velocity.

Smax = 400 feet.

c) v = 32 ft/s

c) v = - 32 ft/s

(a)

The following is the function provided for ball height:

s = 160 t - 16 t²

Therefore, we must take the derivative with respect to t and make it equal to zero in order to get the time to reach maximum height (in-flexion point):

So, 160 - 32 t = 0, 32 t = 160 t, and 160/32 t = 5 sec.

As a result, the maximum distance is covered every 5 seconds.

Smax = (160)(5) - (16)(5)²

Smax = 800 - 400

Smax=400 feet

b)First, we determine the speed at which the ball travels 384 feet.

384 = 160 t - 16 t

16 t² - 160 t + 384 = 0

Quadratic Equation Solving:

Either:

t = 6 sec

or t = 4 seconds

Since it takes 5 seconds to reach the highest point,

t then equals 5 seconds.

t then equals 4 seconds.

Now, by taking a derivative of ods with respect to t at 4 sec, we can find velocity:

v = 160 - 32 t

v = 160 - (32)(4)

v = 32 ft/s

c,Because t = 6 s > 5 s

The second number of t = 6 sec must represent the point in the ball's downward motion when it is 384 feet above the earth.

So, at that moment, velocity will be:

v = 160 - (32)(6)

v = -32 ft/s

downward motion is a bad sign.

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Answer:

ω = 0.1 rad/s

v = 0.002 m/s

Explanation:

The angular velcoity of the second hand of the clock can be found by:

ω = θ/t

where,

ω = Angular Speed

θ = Angular Displacement

t = time taken

Now, for one complete revolution of second hand of the clock:

θ = 2π rad

t = 60 s

Therefore,

ω = 2π rad/60 s

ω = 0.1 rad/s

Now, for the linear speed (V):

V = rω

where,

V = Linear Speed of Second Hand = ?

r = radius = length of second hand = 0.02 m

Therefore,

V = (0.02 m)(0.1 rad/s)

V = 0.002 m/s

The installation of baghouse filters in exhaust systems is Particulate matter.

The exhaust system gathers the cylinder exhaust gases, filters out dangerous materials, lowers the noise level, and then releases the cleaned exhaust gases to an appropriate location of the vehicle away from the occupants. Depending on the engine, the exhaust system may have one or two channels.

The majority of people are aware that an exhaust system eliminates the dangerous gases your engine produces, however exhaust systems also perform a lot more functions! The four primary purposes of your vehicle's exhaust system are to reduce fuel consumption, move gases away, reduce noise, and increase engine performance.

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Answer:

1,1 m

Explanation:

Dado que;

coeficiente de fricción = 0,6

sabemos que W = R = mgcos 37 = 3.5Kg * 10m / s ^ 2 * cos37 = 27.95 N

coeficiente de fricción = fuerza / reacción normal (R)

Fuerza = 0.6 * 27.95 N

Fuerza (F) = 16.77 N

Recuerda que F = Ke

dónde;

K = constante de fuerza (15N / m)

e = extensión (lo desconocido)

e = F / K

e = 16,77 N / 15 N / m

e = 1,1 m

The volume of the balloon increased by a factor of 20 or increased by 20 times.

We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional, as long as the temperature remains constant.

Boyle's Law: P1V1 = P2V2

Where P1 and V1 are the initial pressure and volume, and

P2 and V2 are the final pressure and volume.

Also we know that  P1 = 300 torr, P2 = 15 torr, and V1 = V

Therefore, after substituting

300 V = 15 (V2)

V2 = 300/15

V2 = 20 V1

Therefore, the volume changed by a factor of 20 or increased by 20 times.

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If the person is weighing 120 N and the tension in the right part of the string is 200 N then the tension in the left part of the string is also 200 N.

Based on the given information, we know that the person weighing 120 N is sitting on a swing that is in rotary motion. The tension on the right part of the swing is 200 N.

In order for the swing to stay in motion, the tension on both sides of the swing needs to be equal. Therefore, the tension on the left part of the swing must also be 200 N.

So, the tension on the left part of the swing is 200 N.

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Answer:

75%(TT,Tt,tt) Hope that helps

Answer:

\(v = \frac{1}{5}\cdot s\)

Explanation:

If the distance (\(s\)) and speed (\(v\)), measured in centimeters and centimeters per hour, respectively, are directly proportional to each other, then each set of values must observe the following relationship:

\(k = \frac{v}{s}\) (Eq. 1)

Where \(k\) is the proportionality constant, measured in \(\frac{1}{h}\).

If we know that \(s_{1} = 10\,cm\), \(v_{1} = 1\,\frac{cm}{h}\), \(s_{2} = 15\,cm\), \(v_{2} = 2\,\frac{cm}{h}\), \(s_{3} = 15\,cm\) and \(v_{3} = 3\,\frac{cm}{h}\), then the constant of proportionality for each pair is:

\(k_{1} = \frac{v_{1}}{s_{1}}\)

\(k_{1} = \frac{1\,\frac{cm}{h} }{5\,cm}\)

\(k_{1} = \frac{1}{5}\,\frac{1}{h}\)

\(k_{2} = \frac{v_{2}}{s_{2}}\)

\(k_{2} = \frac{2\,\frac{cm}{h} }{10\,cm}\)

\(k_{2} = \frac{1}{5}\,\frac{1}{h}\)

\(k_{3} = \frac{v_{3}}{s_{3}}\)

\(k_{3} = \frac{3\,\frac{cm}{h} }{15\,cm}\)

\(k_{3} = \frac{1}{5}\,\frac{1}{h}\)

As \(k_{1} = k_{2} = k_{3}\), we conclude that correct equation is \(v = \frac{1}{5}\cdot s\).

The correct equation that correctly state the relationship between the dot distances and speeds is ;  S = 5 * V   or   \(V = 1 / 5 * s\)

Although some data related to your question is missing a general answer within the scope of your question is provided

From the given data

The distance of the dot  is directly proportional to the speed ( v ) of the dot

i.e. S ∝ V

∴ S = kV

K = S / V . -------- ( 1 )

where ;

S = distance of dot , V = speed of dot  and K = proportionality constant.

Applying equation ( 1 ) to all three dot distances

       K = 5 cm / 1 cm/hr  = 5

       K = 10 cm / 2 cm/hr = 5

      K = 15 cm / 3 cm/hr = 5  

Therefore we can conclude that the equation that will currently state the relationship between the dot distances and their speeds is \(V = 1 / 5 * s\)

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The pressure measured at the bottom of a 20-foot high tank filled with water is 46.2 psi. Therefore, option (a) is the correct answer.

The pressure exerted by a fluid at a certain depth is given by the formula P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the fluid.

For water, the density (ρ) is approximately 62.4 lb/ft³, and the acceleration due to gravity (g) is approximately 32.2 ft/s².

Plugging in these values and the depth of 20 feet into the formula, we get:

P = (62.4 lb/ft³) * (32.2 ft/s²) * (20 ft)

P ≈ 40,115.2 lb/ft²

Converting the pressure from lb/ft² to psi (pounds per square inch), we divide by 144:

P ≈ 40,115.2 lb/ft² / 144 in²/ft²

P ≈ 278.43 psi

Rounding this value to the nearest tenth, the pressure measured at the bottom of the tank filled with water is approximately 46.2 psi. Therefore, option (a) is the correct answer.

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Answer:

Nikola Tesla was a Serbian-American inventor, electrical engineer, mechanical engineer, and futurist best known for his contributions to the design of the modern alternating current electricity supply system.

The magnitude of the impulse that the plate gives to the bullet is  6.7 N, Option a.

The formula for impulse is given as m*deltav

convert 20 grams to kg

= 20 x 1000

= 0.020kg

We would have to find the paralle; impulse and also solve for the perpendicular impulse.

The parallel impulse is given as:

0.020kg * (320 - 350)m/s * cos30

= 0.020 * -30 * 0.8660

= -0.5196

Next we have to solve for the perpendicular impulse

0.020kg * (320 + 350)m/s * cos30

0.020 * 670 * 0.8660

= 6.7

the mag impulse is given as;

\(\sqrt{6.7^2 + 0.52^2}\)

= 6.7 N/S

Option A is correct

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Answer:

The major difference between Motor and Generator is that a motor converts electrical energy into mechanical energy, whereas the generator does the exact opposite. The motor uses electricity whereas the generator produces electricity.

Answer:motor converts electrical energy into mechanical energy and a generator does the opposite.

Explanation:

A) The linear model relating altitude a (in feet) and time in the air t (in seconds) is a = 0.0625t + 1593.75.

B) The rate of change of the parachutist in the air is 0.0625 feet per second.

C) The speed of the parachutist at landing is 0.0625 feet per second.

A) To find a linear model relating altitude a (in feet) and time in the air t (in seconds), we can use the formula for a linear equation: y = mx + b, where y represents the altitude (a) and x represents the time in the air (t).

Given that the jump at 1,600 feet lasts 100 seconds, we have the following data points: (1600, 100).

We can use these data points to determine the slope (m) and the y-intercept (b) of the linear equation.

Using the formula for slope (m):

m = (y2 - y1) / (x2 - x1)

m = (100 - 0) / (1600 - 0)

m = 0.0625

Now we can substitute the slope value and one of the data points into the linear equation to solve for the y-intercept (b).

Using the point-slope form: y - y1 = m(x - x1):

a - 1600 = 0.0625(t - 100)

Simplifying the equation:

a - 1600 = 0.0625t - 6.25

a = 0.0625t + 1593.75

Therefore, the linear model relating altitude a (in feet) and time in the air t (in seconds) is: a = 0.0625t + 1593.75.

B) The rate of change of the parachutist in the air is equal to the slope of the linear equation. Therefore, the rate of change is 0.0625 feet per second.

C) To find the speed of the parachutist at landing, we can use the fact that speed is equal to the rate of change of distance with respect to time. In this case, it is equal to the rate of change of altitude with respect to time.

Since the rate of change of altitude is 0.0625 feet per second, the speed of the parachutist at landing is 0.0625 feet per second.

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Answer:

A. stronger prevailing winds and more hurricane activity

Explanation:

edg2020

Answer:A

Explanation:

According to the FITT principle,  Most healthy adults ages 18 to 65 need 20 minutes of vigorous-intensity aerobic activity three to five days each week.

The FITT principle stands for Frequency, depth, Time, and type of education. every of those is a variable that may be adjusted to be able to create a schooling application or training to goal cardio or anaerobic education. aerobic schooling is training that objectives to improve an athlete's cardio electricity or VO2max.

FITT is one manner to preserve in thoughts the overall pointers for what need to be blanketed in a fitness plan. maintain in mind, it is essential to understand that each member of the family's health intensity may be exclusive based on age, intercourse, modern fitness degree, and available assets.

Frequency. This refers to how regularly you exercising. The element is to fulfill your goals with out overtraining the frame. in terms of cardio: As a present day rule of thumb, aim for a minimum of three cardio sessions in line with week. if you're trying to shed pounds, you would probably increase this range to five to six intervals

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Answer:

w = 7.5 [J]

Explanation:

We must remember the definition of mechanical work, which tells us that work is equal to the product of force by distance. This force must be applied in the direction of movement. So we have the following equation:

w = F*d

where:

w = work [J]

F = force [N]

d = distance [m]

Now replacing we have:

w = 5*1.5

w = 7.5 [J]

Answer:

An object in motion will remain in motion until it experiences an unbalanced force.

Explanation:

This is part of Newton's first law. An unbalanced force is there to offset the object in motion, such as a ball versus a wall. A wall will stop the ball from moving.

Servicing MVAC (Mobile Air Conditioning) systems on hybrid and electric vehicles typically requires specialized knowledge and equipment due to the unique characteristics of these vehicles.

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