Two rocket ships are racing toward Earth. Ship A is in the lead, approaching the Earth at v1 = 0.84c and separating from ship B with a relative speed of 0.50c.
(a) As seen from Earth, what is the speed, v, of ship B?
(b) If ship A increases its speed by 0.10c relative to the Earth, does the relative speed between ship A and ship B increase by 0.10c, by more than 0.10c, or by less than 0.10c?
Explain
(c) Find the relative speed between ships A and B for the situation described in part (b).

Answer:

Newton's First Law of Motion.

Explanation:

Newton's First Law of Motion states that a body continues its state of motion untill and unless an external force acts on it. Here, the truck moves forward even after the breaks are applied in order to maintain its State of motion.

The comparison of the larger intensity earthquake is 2 times that of a smaller intensity earthquake from the given data.

When two ground slabs abruptly move past one another, an earthquake occurs. The region where they slip is the fault or fault plane. The movement creates seismic waves, which travel through the Earth and cause the ground to tremble. These seismic waves are made up of elastic strain energy that has been built up.

The given larger intensity earthquake has 8.4 magnitude.

The given smaller intensity earthquake has 3.7 magnitude.

So, the ratio of intensity is,

⇒ (larger intensity)/(smaller intensity)

⇒ 8.4/3.7 = 2.27 ≈ 2.3 ≈ 2

Hence, we can conclude that larger earthquake's intensity is 2 times as great as the smaller earthquake's intensity.

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Answer:

2. 1.85

Explanation:

the equations weight * distance / other persons weight = distance from fulcrum. so 66.4*2.35/84.2=1.8532 round down to 1.85

Frequency of Simple pendulum = 0.61 Hz. The pendulum oscillates with a frequency of v = ω/2π, cycles per second, and its period, T, is equal to 2π(l/g).

As a result, the pendulum's frequency determines how frequently it swings back and forth during a certain length of time. How many times the pendulum swings back and forth in 60 seconds, for instance. The length of pendulum will affect its frequency. It implies that the swing rate will be higher and the pendulum shorter.

Number of oscillations that were completed in the given unit of time. f = 1/T = ω/2π 4. Period of time (T) T = 2 π/ω.

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The ideal gas equation is needed here. Since PV=nRT, we see that the volume is directly proportional to the temperature. We must, however use Kelvin temperatures in this equation. Since you want the volume tripled, you have to triple the temperature.initial temp is 273 K final temp should be 819 K819 K - 273 K = 546 degrees CRemember to get the Kelvin temperature one adds 273 to the Celsius number

The potential difference ∆V = V(r₂) -V(r₁) between points at radial distances r₂ = 2 cm and r₁ = 1 cm is 78.9 V/m.

The potential difference ∆V = V(r₂) -V(r₁) between points at radial distances r₂ = 2 cm and r₁ = 1 cm can be calculated using the formula:

                                ∆V = (λ/2πεο) ln(r₂/r₁)

where λ is the linear charge density, εο is the permittivity of free space, r₁ and r₂ are the radial distances, and ln is the natural logarithm. Plugging in the given values, we get:

∆V = (2x10⁻⁹ C/m/2π(8.85x10⁻¹² C/V⁻¹m⁻¹)) ln(2 cm/1 cm)
∆V = (2x10⁻⁹  C/m/ 2π(8.85x10⁻¹² C/V⁻¹m⁻¹)) ln(2)
∆V = (1.14x10⁻² V⁻¹m⁻¹)) ln(2)
∆V = (1.14x10⁻² V⁻¹m⁻¹) (0.693)
∆V = 78.9 V⁻¹m⁻¹
∆V = 78.9 V/m

Therefore, the potential difference ∆V=V(r2) -V(r1) between points at radial distances r₂ = 2 cm and r₁ = 1 cm is 78.9 V/m.

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The focal length of the power lens is 54.05 mm.

The focal length of reading glasses found on the rack in a pharmacy depends on its lens power. Lens power can be defined as the ability of the optical device to see. It can be represented by a dioptre unit. The relaxed power formula is

P = 100/f

where P is the power of the lens in dioptre, and f is the focal length.

From the question above, the given parameter is

P = 1.85 d

By substituting the given parameters, we can calculate the focal length

P = 100/f

1.85 = 100/f

f = 54.05 mm

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Answer:

Electromagnetic waves have crests and troughs similar to those of ocean waves.

Explanation:

The distance between crests is the wavelength. hope this helps you :)

The following does not increase as mass increases for main sequence stars is D) Main sequence lifetime. As mass increases, the temperature, radius, and luminosity of main sequence stars all increase.

As mass increases for main sequence stars:
A) Temperature increases because more massive stars have stronger gravitational forces, causing higher pressure and temperature in their cores.
B) Radius increases since more massive stars have larger volumes.
C) Luminosity increases due to the higher temperature and larger surface area, resulting in more energy output.

However, D) Main sequence lifetime does not increase as mass increases. In fact, it decreases because more massive stars consume their nuclear fuel at a faster rate, leading to shorter lifetimes on the main sequence.

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The mass of a ball is 3.5 kg. It moves down a slope that is inclined at 40 degrees with respect to the horizontal. The base of the slope has a length of 4.8 meters.the ball loses 106.2 Joules of gravitational potential energy when it rolls down the slope.

It is required to determine how much gravitational potential energy the ball loses when it rolls down the slope.For this, we need to use the following formula:ΔPE = mghwhere m = mass of the ball = 3.5 kgg = acceleration due to gravity = 9.81 m/s2h = height from which the ball rolls downLet's analyze the situation. The ball moves down a slope. The potential energy (PE) of the ball at the top of the slope is converted into kinetic energy (KE) as it moves down the slope. The ball gains KE, and it loses PE.The height from which the ball rolls down the slope is given by the following expression:h = length of slope × sin θh = 4.8 × sin 40°h = 3.086 metersSubstitute the given values into the formula for ΔPE.ΔPE = mghΔPE = 3.5 × 9.81 × 3.086ΔPE = 106.2 JoulesTherefore, the ball loses 106.2 Joules of gravitational potential energy when it rolls down the slope.

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You push on a 2-kg block initially at rest on a frictionless surface with 10n of force horizontal for 5m on level ground before letting go. the block slides into a loop with a radius of 0.5 m. The velocity will the block have at the top of the loop is determined as 7.071 m/s.

To find the velocity, the given values are,

Mass m = 2 Kg

Force F = 10 N

Displacement = 5m

Radius = 0.5 m

The work-energy theorem states that the change in the kinetic energy is equal to the amount of work done.

Energy is ability to do work. To perform work, energy has to be spent. Work is said to be done whenever the force is applied to an object then the object is moved to a certain distance.

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

Force × Displacement = 1/2 mv²

Thus, the velocity can be determined as

velocity v = √(2×Force×Displacement/m)

Substituting all the given values,

Velocity, v = \(\sqrt{\frac{2*10*5}{2} }\)

v = √50

v = 7.071 m/s.

So, the block's velocity is determined as 7.071 m/s.

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Take your car as soon as possible to a service facility if the brakes pulse when ABS is engaged. On gravel or recently fallen snow, stopping time may be increased while utilizing ABS.

How do you figure out time in physics?

The Physics Formula for Time. The following are some basic formulas: 1) To calculate speed, use the formula Speed = (frac Distance Time). 2) How to calculate distance: Speed divided by time equals distance. 3. To determine the time: Time equals (frac) Distance x Speed. The following mathematical formulas are available: S equals (frac dt). d = s + t, and t = (frac ds + d) Where,

What is the time theory?

Although the concept of time seems simple, physicists concur that it is a difficult topic to fully comprehend. The most common definition of time in sciences is that it is measured in milliseconds, minutes, hours, etc. Yet, defining "time" is a more challenging topic for physics to discuss.

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To calculate work, we need to know both the magnitude of the force applied and the distance over which it is applied. The formula for work is W = F × d × cosθ.

We measure both the force acting on an object and the distance through which the force acts, known as displacement.

Work is defined as the product of force and displacement in the direction of the force. Therefore, to calculate work, we need to know both the magnitude of the force applied and the distance over which it is applied.

The formula for work is W = F × d × cosθ, where W is the work done, F is the force applied, d is the displacement, and θ is the angle between the force and displacement vectors.

The unit of work is joule (J), which is equivalent to the product of newton (N) and meter (m).

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An unbalanced force acting on an object results in the object's motion changing. The object may change its speed (speed up or slow down), or it may change its direction. Friction is a force that resists the motion or the tendency toward motion between two objects in contact with each other.

motion

Answer:

motion. FILLER FILLER FILLER

Answer:

Weight is a force.

Explanation:

Force acting on an object is defined in terms of mass and its acceleration. Its mathematical force is given by

F = ma

Weight of an object is force that the Earth exerts on an object. It can be given by the formula as follows :

W = mg

g is acceleration due to gravity on the surface of earth

Hence, the correct option is (d).

Answer:

Explanation:

For A to become positively charged, a + charge must transfer from B to A.

The charge that must transfer for object A to become positively charged is the negative charge in object A.

Charging by conduction occurs when a charged object causes the flow of electron when it comes in contact with an uncharged object.

An object can either be negatively or positively charged. An object is said to be positively charged when it contains more protons than electron.

Therefore, for object A to be positively charged, the charge that must transfer for object A to become positively charged is the negative charge.

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The correct response is D. There is insufficient information to answer this question.

Luminosity measures the total amount of energy a star emits in a unit of time whereas, surface temperature measures the average kinetic energy of the particles in the star's atmosphere. Hence, it is not possible to estimate the relative diameters of two stars based solely on the knowledge that they have the same luminosity and that one has a greater surface temperature than the other.

Many factors, including as a star's mass, brightness, and surface temperature, affect its size. It is hard to tell which star is bigger or if they are the same size without knowing more about the masses and other characteristics of the two stars.

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The net electrostatic force acting on the charged particle q₂ is 28.7 N.

Charge on the first particle, q₁ = 8 μC

Charge on the second particle, q₂ = 3.5 μC

Charge on the third particle, q₃ = - 2.5 μC

Distance between the charges q₁ and q₂, r₁ = 0.1 m

Distance between the charges, q₂ and q₃, r₂ = 0.15 m

Electrostatic force exerted on the charged particle q₂ and q₁,

F₁ = 1/4πε₀ (q₁q₂/r₁²)

F₁ = 9 x 10⁹ x (8 x 10⁻⁶ x 3.5 x 10⁻⁶)/(0.1)²

F₁ = 25.2 N

Electrostatic force exerted on the charged particle q₂ by q₃,

F₂ = 1/4πε₀ (q₂q₃/r₂²)

F₂ = 9 x 10⁹ x (3.5 x 10⁻⁶x -2.5 x 10⁻⁶)/(0.15)²

F₂ = -78.75 x 10⁻³/22.5 x 10⁻³

F₂ = -3.5 N

The net electrostatic force acting on the charged particle q₂ is,

F = F₁ - F₂

F = 25.2 - -3.5

F = 25.2 + 3.5

F = 28.7 N

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The auxiliary equation is given by d^2x/dt^2 + (c/m) dx/dt + (k/m) x = 0. This can be found by force substituting m = 1kg, c = 6 kg s−1 and k = 9 kg s−2 into the given differential equation.

The general solution for equation (2.1) is given by:$$x(t) = c_1 e^{r_1 t} + c_2 e^{r_2 t}$$where r1 and r2 are the roots of the auxiliary equation and c1 and c2 are arbitrary constants. We can find the roots of the auxiliary equation by solving the characteristic equation:$$r^2 + (c/m)r + (k/m) = 0$$Using the quadratic formula, we get:$$r_{1,2} = \frac{-p \pm \sqrt{p^2 - 4q}}{2}$$where p = c/m and q = k/m. Depending on the values of p and q, there are three cases for the roots:r1 and r2 are real and distinct;r1 and r2 are complex conjugates;r1 and r2 are equal and real.

The system described by equation (2.1) exhibits overdamping, as the damping constant c is greater than the critical damping constant, given by 2√km, where k is the spring constant and m is the mass. Overdamping occurs when the damping force is strong enough to prevent the mass from oscillating.(d) ExplanationOnce the force sint is applied, the non-homogeneous second order differential equation that describes the mass spring damper system is:d^2x/dt^2 + (c/m) dx/dt + (k/m) x = sint.(e).

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Answer:

product

Explanation: it's the product of chlorine and sodium

Answer:

y

Explanation:

Answer:

Zeros that follow non-zero numbers and are also to the right of a decimal point are significant.

Explanation:

For example:

0.300 has 3 significant figures.

5.400 has 4 significant figures.

Answer:B, They preform experiments.

Explanation:

your welcome :)

Answer: FRANCE

Explanation:

Answer:

France

Explanation:

UK has 15 nuclear power plants and 2 under construction whereas France has 56 in operation and 1 under construction  

Answer: A basketball is something that can have a physical or chemical change done to it.

Explanation:

A basketball is made of matter. The fire itself is not a matter however, the wood that burns is matter. A basketball is very different from a fire because a basketball has some mass in it on the other hand fire does not contain any mass

Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

For any substance to be considered as matter it must have to contain some mass and occupies some space.

As given in the problem statement a basketball is made of matter. The fire itself is not a matter however, the wood that burns is matter. A basketball is very different from a fire because a basketball has some mass in it on the other hand fire does not contain any mass.

For any substance to be considered as matter it must have to contain some mass and occupies some space.

Thus, a basketball is considered a matter but fire is not considered a form of matter.

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Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

Sunlight will take 8 minutes to reach the Earth.

Sunlight is part of the electromagnetic radiation emitted by the Sun, especially infrared, visible and ultraviolet light.

Light is travelling with the speed of \(3 * 10^{8}\) m/s

Distance between Sun and Earth is 144 million km

1 km = 1000 m

1 million km = \(10^{6}\) km

\(10^{6}\) km = \(10^{9}\) m

144 million km = 144 * \(10^{9}\) m

According to the speed, distance and time relationship, speed is directly proportional to the ration of distance and time.

\(3 * 10^{8} = \frac{144 * 10^{9} }{Time}\)

Time = \(\frac{144 * 10^{9} }{3* 10^{8} }\)

Time = 480 sec

Time = 8 minutes

Time taken by the sunlight to reach the Earth's surface is 8 minutes.

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The temperature is a chilly 3.1 k, and there are only 106 atoms per cubic meter of air in the deep vacuum between galaxies. 3.86*10⁻¹⁷ pa is the pressure.

Density of atoms,\(\rho= 10^6 atoms/m^3\)

Temperature, T= 2.8K

using Ideal Gas Equation,

                         PV= nRT

   where n= number of moles,

              R= Universal Gas Constant

              P= Pressure

  Number of atoms in 1 mole, \(N_A= 6.022 \times 10^{23}\)

  Then given number of atoms will have following number of moles, \(n= \frac{10^6}{N_A}\)

  where NA= Avogadro's number which is constant

  Or we can write,

                      \(\frac{n}{V}= \frac{\rho}{N_A}\)

  Thus Pressure will be

                   \(P= \frac{nRT}{V}= \frac{\rho RT}{N_A}\)

  using given and known values in above,

                      \(P= \frac{10^6 \times 8.314 \times 2.8}{6.022 \times 10^{23}}= 3.86 \times10^{-17} Pa\)

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Answer:

mass m = 17.2 kg.

Explanation:

Use potential energy =m*g*h,

so,

m=potential energy/(g*h)

m=96000 J/(9.8*568) = 17.2 kg