Two ropes support a load of 478 kg. The two ropes are perpendicular to each other, and the tension in the first rope is 2. 2 times that of the second rope. Find the tension in the second rope. The acceleration of gravity is 9. 8 m/s 2. Answer in units of N

Answer:

F = 6.12 10⁻¹⁵ N,    a = 3.66 10¹² m / s²

Explanation:

The magnetic force is

            F = q v x B

bold letters indicate vectors, the modulus of this expression is

            F = q v B sin θ

as they indicate that the magnetic field is vertical the proton moves horizontally the angle is 90º

suppose that the energy of the proton is totally kinetic

        E = 5.3 MeV (10⁶ 1.6 10⁻¹⁹J / 1 eV) = 8.48 10⁻¹³ J

       E = K = ½ m v²

       v = \(\sqrt{2E/m}\)\(\sqrt{2 \ 8.48 \ 10^{-13} / 1.67 \ 10^{-27}}\)

       v = \(\sqrt{2 \ 8.48 \ 10^{-13} / 1.67 \ 10^{-27}}\)

       v = \(\sqrt{10.155 \ 10^{14}}\)

       v = 3.19 10⁷ m / s

we calculate

        F = 1.6 10⁻¹⁹  3.19 10⁷  1.2 10⁻³

        F = 6.12 10⁻¹⁵ N

The direction of this out is given by the right hand rule,

thumb in the direction of speed, south to north

fingers extended in the direction of the magnetic field, vertical

the probe points in the direction of the force for a positive charge,  East

To calculate the acceleration we use Newton's second law

        F = ma

        a = F / m

        a = 6.12 10⁻¹⁵ / 1.67 10⁻²⁷

        a = 3.66 10¹² m / s²

the direction of the acceleration is the same as the direction of the force

Answer:

160J OR 140J

Explanation:

Depends on teacher which formula your teacher uses.

U=Q+W OR U=Q-W

Method 1:

U=150+10J=160

U=150-10=140J

ANSWER:

The current always choose low resistor to flow in circuit

STEP-BY-STEP EXPLANATION:

Gven:

V = 10 V

R1 = 250 Ω

R2 = 800 Ω

Apply Ohm's law:

We calculate the current in each case:

That means current always choose low resistor to flow in circuit

The maximum height achieved by the cannonball above the ground is approximately 24.14 meters.

To find the maximum height achieved by the cannonball, we can analyze its motion using the principles of projectile motion.

Given:

Initial velocity (v₀) = 35 m/s

Launch angle (θ) = 50 degrees

Acceleration due to gravity (g) = 9.8 m/s²

The motion of the cannonball can be divided into horizontal and vertical components.

Vertical motion:

The initial vertical velocity (v₀y) can be calculated using the launch angle:

v₀y = v₀ * sin(θ)

The time taken to reach the maximum height (t_max) can be determined using the equation:

t_max = v₀y / g

Using this time, we can find the maximum height (h_max) reached by the cannonball above the ground using the equation:

h_max = (v₀y)² / (2 * g)

Substituting the given values:

v₀y = 35 m/s * sin(50°)

t_max = (35 m/s * sin(50°)) / 9.8 m/s²

h_max = [(35 m/s * sin(50°))^2] / (2 * 9.8 m/s²)

Calculating these expressions gives us:

v₀y ≈ 27.01 m/s

t_max ≈ 1.46 s

h_max ≈ 24.14 m

Therefore, the maximum height achieved by the cannonball above the ground is approximately 24.14 meters.

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Answer:

Explanation:

The gravitational force between two objects can be calculated using the formula:

F = G * (m1 * m2) / r^2

Where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 is the mass of one object (60 kg), m2 is the mass of the other object (5.67 x 10^26 kg), and r is the distance between the two objects (the radius of Saturn, 6.3 x 10^7 m).

F = 6.67 x 10^-11 * (60 * 5.67 x 10^26) / (6.3 x 10^7)^2

F = 6.67 x 10^-11 * 3.402 x 10^33 / 3.969 x 10^14

F = 2.30 x 10^19 N

So the gravitational force on a 60 kg man on Saturn would be approximately 2.30 x 10^19 N.

When the partial pressure of water equals the saturated vapor pressure, this is commonly called "equilibrium."

In the context of water vapor, equilibrium occurs when the rate of evaporation and the rate of condensation are in balance. At equilibrium, the amount of water molecules transitioning from the liquid phase to the vapor phase (evaporation) is equal to the amount of water molecules transitioning from the vapor phase to the liquid phase (condensation). This equilibrium state results in a constant concentration of water vapor in the air. The saturated vapor pressure refers to the maximum pressure that water vapor can exert when it is in equilibrium with its liquid phase at a particular temperature. It represents the point at which the air is holding as much moisture as it can at that specific temperature.

When the partial pressure of water vapor in the air matches the saturated vapor pressure at a given temperature, the air is holding the maximum amount of water vapor it can at that temperature. Any additional increase in water vapor would result in condensation, where water molecules transition from the vapor phase to the liquid phase.This state is commonly referred to as "saturation" because the air is saturated with moisture, and any further increase in water vapor would lead to the formation of liquid water.

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Answer: \((a)10.812\ m/s\ (b)\ 0.75\ m/s\ \text{left}\)

Explanation:

Given

Mass of hockey puck \(m=0.160\ kg\)

Initial velocity of hockey puck is \(u=3\ m/s\)

First a horizontal force of \(25\ N\) is applied to the right for \(0.05\ s\)

acceleration associated with it is

\(\Rightarrow a=\dfrac{25}{0.160}\\\\\Rightarrow a=156.5\ m/s^2\)

Using equation of motion i.e.

\(\Rightarrow v=u+at\\\Rightarrow v=3+156.25\times 0.05\\\Rightarrow v=3+7.812\\\Rightarrow v=10.812\ m/s\)

(b) When a force of \(12\ N\) is applied for 0.05s

Using equation of motion i.e.

\(\Rightarrow v=3-\dfrac{12}{0.160}\times 0.05\\\\\Rightarrow v=3-75\times 0.05\\\Rightarrow v=3-3.75\\\Rightarrow v=-0.75\ m/s\\\Rightarrow v=0.75\ \text{towards left}\)

Answer: E = 5.004*10^(20) joules

Explanation:

We do not have a lot of information about the impact, so we can assume that the energy released on the impact was the kinetic energy of the large fragment.

Remember that the kinetic energy of an object of mass M that moves at a velocity V is:

K = (M/2)*V^2

in this case, we know that the speed (that is equivalent to the velocity) is:

V = 60,000 m/s

And the mass is:

M = 1.39*10^(11) kg

Then the kinetic energy of the large fragment was:

K = (1.39*10^(11) kg/2)*( 60,000 m/s)^2 = 5.004*10^(20) joules.

Then we could conclude that the energy released on the impact was:

E = 5.004*10^(20) joules

Answer:

d

Explanation:

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Answer:

A few of the positive particles aimed at a gold foil seemed to bounce back.

Explanation:

Answer:

The answer is A: A few of the positive particles aimed at a gold foil seemed to bounce back.

Explanation:

This is Bohr's model, and this is what his discovery was: that, when he conducted several experiments, he found that the positive particles bounced off of the gold foil.

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The maximum EMF induced in the coil by the Earth's magnetic field is zero.

We can use Faraday's law of electromagnetic induction to calculate the maximum EMF induced in the coil by the Earth's magnetic field. Faraday's law states that the EMF induced in a coil is equal to the rate of change of the magnetic flux through the coil.

Assuming the loop is a circle of radius r, the magnetic flux through the loop due to the Earth's magnetic field is given by:

Φ = B * A * cosθ

where B is the horizontal component of the Earth's magnetic field, A is the area of the loop, and θ is the angle between the normal to the loop and the direction of the magnetic field. Since the loop is lying flat on the ground, θ = 0, and cosθ = 1.

The area of a circle is A = π\(r^2\), so we have:

Φ = B * π\(r^2\)

The rate of change of the magnetic flux through the loop is given by the time derivative of Φ:

dΦ/dt = d(B * π\(r^2\))/dt = π\(r^2\) * dB/dt

Since the horizontal component of the Earth's magnetic field is constant, dB/dt = 0, so the rate of change of the magnetic flux is zero.

Therefore, the maximum EMF induced in the coil by the Earth's magnetic field is zero.

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The period of y for two satellites that are being watched as they orbit the planet is 22.63 times, and if the period of rotation of satellite x is T, satellite y.

Is four times as far from the Centre of the earth as satellite x. A satellite, often known as an artificial satellite, is a spacecraft that has been put into orbit on purpose. With the exception of passive satellites, most spacecraft have a method for producing electricity for the electronics they carry, such as solar cells or radioisotope thermoelectric generators. From above the Northern Hemisphere, Earth circles the Sun in a counterclockwise manner at an average distance of 149.60 million kilometres. It takes 365.256 days to complete one orbit.

Tx/Ty = (rx/ry) 3/2 = (8/1) 3/2 = 8 3/2 where Tx/Ty = (rx/ry) 3/2 =

X's revolution lasts for 8/3 = 22.63 times as long as Y does

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The condition for the first dark fringe through a single slit of width w is when the path difference between the rays passing through the top and bottom edges of the slit is half a wavelength, which causes destructive interference and results in a dark band on the screen.

This can be expressed mathematically as sin θ = λ/w, where θ is the angle between the direction of the incoming light and the direction of the diffracted light, λ is the wavelength of the light, and w is the width of the slit.

The condition for the first dark fringe in a single-slit diffraction pattern occurs when the path difference between adjacent rays is equal to half the wavelength (λ/2). This can be represented by the equation:

sin(θ) = λ/(2w)

where θ is the angle of the first dark fringe, λ is the wavelength of the light, and w is the width of the slit.

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Answer:

This is because the protons have more mass and are harder to get moving. Although electrons are very small, their negative electrical charges are still quite strong. Remember, the negative charge of an electron is the same as the positive electrical charge of the much larger in size proton.~Tori

Explanation:

The equation to determine the maximum distance the spring will be compressed when the car hits it is x = \(\sqrt{(2mgh)/k}\).

When the car rolls down the hill, it gains kinetic energy equal to its potential energy at the top of the hill: mgh. This kinetic energy will be transferred to the spring upon impact with the crash barrier. The spring will compress until all the kinetic energy is stored as potential energy in the spring.

Using the conservation of energy principle, we can equate the initial potential energy of the car with the potential energy stored in the compressed spring:
mgh = (1/2)kx²

where x is the maximum distance the spring will be compressed. Solving for x, we get:
x = \(\sqrt{(2mgh)/k}\)

So, the maximum distance the spring will be compressed is dependent on the mass of the car (m), the height of the hill (h), the spring constant (k), and the acceleration due to gravity (g).

In summary, the equation to determine the maximum distance the spring will be compressed when the car hits it is x = \(\sqrt{(2mgh)/k}\).

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True. The Hubble constant derived by the cosmic distance ladder method is indeed smaller than the one derived by the cosmic microwave background (CMB) method.

The Hubble constant represents the rate at which the universe is expanding. There are two primary methods used to estimate the value of the Hubble constant: the cosmic distance ladder method and the CMB method.

The cosmic distance ladder method involves a step-by-step process of measuring distances to nearby objects, such as Cepheid variable stars and supernovae, and then using their known properties to estimate distances to more distant objects. This method relies on a chain of measurements and assumptions, which can introduce uncertainties.

On the other hand, the CMB method utilizes measurements of the cosmic microwave background radiation, which is the leftover radiation from the early universe. By studying the patterns in the CMB, scientists can infer the expansion rate of the universe. This method relies on the precise measurements of the CMB and the assumptions based on the standard model of cosmology.

In recent years, there have been some discrepancies between the results obtained from these two methods. The cosmic distance ladder method tends to yield a smaller value for the Hubble constant, while the CMB method suggests a larger value. This discrepancy is known as the Hubble tension and has sparked significant interest and ongoing research in the field of cosmology.

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In circular motion at a constant speed, the velocity and acceleration of a body point perpendicular to each other and in opposite directions.

In circular motion at a constant speed, the velocity and acceleration of a body have specific relationships:

Therefore, the correct answers are:

It is important to note that the acceleration is not zero in circular motion at a constant speed. The acceleration is directed towards the center of the circle and is responsible for continuously changing the direction of the velocity.

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The velocity and acceleration point perpendicular to each other, and the acceleration is zero.

In circular motion at a constant speed, the direction of the velocity and acceleration vectors have specific relationships.

The correct statements are:

- The velocity and acceleration point perpendicular to each other: In circular motion, the velocity vector is tangent to the circular path, while the acceleration vector is directed toward the center of the circle. Therefore, the velocity and acceleration vectors are perpendicular to each other.

- The acceleration is zero: In circular motion at a constant speed, the magnitude of the velocity remains constant, indicating that there is no change in speed. Since acceleration is the rate of change of velocity, and the velocity is not changing, the acceleration is zero.

The incorrect statements are:

- The velocity and acceleration point in the same direction: This is not true in circular motion at a constant speed. The velocity and acceleration vectors are perpendicular to each other.

- Centripetal force and acceleration point in perpendicular direction: This is incorrect. Centripetal force and acceleration have the same direction, both directed toward the center of the circle.

Understanding the relationships between velocity, acceleration, and centripetal force is essential in analyzing circular motion and determining the forces acting on objects moving in a circular path.

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Answer:

Yes

Explanation:

The world responsible for saying or wonder the world from this country's government.

Answer:

do explain what u need help with?

Answer:

Only circuit A will contain to lit bulbs

a) The magnetic field around a wire carrying current can be represented using concentric circles centered on the wire. The direction of the magnetic field lines can be determined using the right-hand rule: if you wrap your right hand around the wire with your thumb pointing in the direction of the current, your curled fingers will indicate the direction of the magnetic field.

b) To calculate the strength of the magnetic field, we can use the equation:

Force = Magnetic field strength × Current × Length

Plugging in the given values, we have:

0.55 N = Magnetic field strength × 6.8 A × 0.15 m

Solving for the magnetic field strength, we find:

Magnetic field strength = 0.55 N / (6.8 A × 0.15 m)

Calculating the numerical value, we can determine the strength of the magnetic field.

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Mercury has the largest core relative to its total diameter of any planet in the solar system.

The planet's core is estimated to be about 2,200 kilometers (1,367 miles) in radius, making up about 85% of its total diameter. This large core is thought to be the result of a massive impact that stripped away much of the planet's outer layers early in its history.

The core is also much denser than the planet's mantle and crust, with a density of about 10.6 grams per cubic centimeter, which is nearly twice that of the mantle and crust. The core is believed to be largely composed of iron and nickel, and its high density suggests that it may contain a small amount of sulfur as well.

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Answer:

Drums, harps, recorders, and bagpipes.

Explanation:

The time it takes to stop is 2.5 seconds (in seconds), and the distance it takes to stop is 25 meters (in meters).

Given,

The initial velocity (u) of the car is 10 m/s.

The acceleration (a) of the car is 4 m/s².

Distance (S) covered by the car will be zero as it is coming to a halt.

Now we have to find the time taken and the distance covered by the car to come to a halt using the given data.1- To find the time taken, we can use the formula of time to stop.

It is given by:t = (v - u) / a

Where,t is the time taken,v is the final velocityu is the initial velocity,a is the acceleration

Let us substitute the given values in the above equation,t = (0 - 10) / -4= 2.5 s

Hence, it takes 2.5 seconds to stop the car.2-

To find the distance covered by the car, we can use the formula of distance.

It is given by: S = ut + 1/2 at²

Where,S is the distance covered by the car, u is the initial velocity, t is the time taken, and a is the acceleration.

Let us substitute the given values in the above equation,

S = 10(2.5) + 1/2 (4) (2.5)²= 25 m

Hence, it takes 25 meters to stop the car.

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The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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