Two small, identical metal balls with charges 7.0 µC and 14.0 µC are held in place 1.9 m apart. In an experiment, they are connected for a short time by a conducting wire.


(a) What will be the charge on each ball after this experiment?

1. new charge on 7.0 µC ball = ? µC

2. ew charge on 14.0 µC ball = ? µC


(b) By what factor will the magnitude of the electrostatic force on either ball change after this experiment is performed?


= ?

Answer:

The acceleration is 2.448 meters per square second and is vertically upward.

Explanation:

The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:

\(\Sigma F = F - m\cdot g = m\cdot a\) (1)

Where:

\(F\) - Buoyant force, measured in newtons.

\(m\) - Mass of the plastic ball, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(a\) - Net acceleration, measured in meters per square second.

If we know that \(F = 5\,N\), \(m = 0.408\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the net acceleration of the plastic ball is:

\(a = \frac{F}{m} - g\)

\(a= 2.448\,\frac{m}{s^{2}}\)

The acceleration is 2.448 meters per square second and is vertically upward.

The speed of the artillery shell when it hits its target is 100 m/s.

Given:

Initial vertical displacement (y) = 200 m

Vertical displacement at 100 m in the air (y') = 100 m

Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)

Using the equation for vertical displacement in projectile motion:

y' = vy^2 / (2g),

where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).

100 m = vy^2 / (2 * 9.8 m/s^2),

vy^2 = 100 m * 2 * 9.8 m/s^2,

vy^2 = 1960 m^2/s^2,

vy = sqrt(1960) m/s,

vy ≈ 44.27 m/s.

Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.

Hence, the speed of the artillery shell when it hits its target is 100 m/s.

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The Young's modulus is of a material is the ratio of its stress to strain. Here, the original length of femur bone is 0.49 m. Then, change in length ΔL by the stress of 1.59 × 10⁸ Pa is 0.0043 m or 4 mm.

The young's modulus is the measure of stress by strain. Stress is the force per unit area and strain be the ratio of change in length by compression or elongation to the original length.

Strain = ΔL/L

Young's modulus = stress/strain

Y= F/a / ΔL/L

Given that, Y = 1.8 × 10¹⁰ Pa

stress = 1.59 × 10⁸ Pa

then 1.59 × 10⁸ Pa /1.8 × 10¹⁰ Pa =  ΔL/L

L = 0.49 m

ΔL =  1.59 × 10⁸ Pa × 0.49 m/1.8 × 10¹⁰ Pa

      = 0.0043 m = 4 mm.

Therefore, the amount of compression that the bone can withstand before breaking is up to 4 mm.

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Explanation:

The velocity is not needed. (its needed to find kinetic energy but its irrelevant to the question)

Potential energy = Mgh

Mass=5kg, height=10meters, g=9.8

P.e=5×9.8×10

=5×98

=490 joules

Hope it helps

:)

An object with a massive 5 kg is thrown with an initial velocity of 6 m/s. If the object has an initial height of 10 meters above the ground, then the magnitude of the initial potential energy of the object would be

490 Joules.  

As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.

ME = KE + PE

As given in the problem An object with a massive 5 kg is thrown with an initial velocity of 6 m/s. If the object has an initial height of 10 meters above the ground,

PE = mgh

PE = 5*9.8*10

     = 490 Joules

Thus, the initial gravitational potential energy of the object would be 490 Joules.

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Answer:

Light can act as a wave or a particle. This is called light wave-particle duality, simply that the light has both the characteristics of fluctuations, but also has the characteristics of particles. Light can propagate forward like a wave, and sometimes show the characteristics of particles.

Metal is not heat resistant and therefore it is not a good heat shield. For example pots are made out of metal because they are good conductors of heat.

Light is said to be the fastest, it is because we have not discovered anything faster than light. If someone discover's something faster than light then that will become the fastest. It is not that we have tried hard enough, it is just that our technology, research and veiw of outer space is limited. Implementing good research and technology requires a lot of money, time and expertise. We have much better things to do than to discover something faster then light because even if it's discovered what can we do with it, with our severe lacking research and technology, it's practically useless and good as updating some newspaper articles. When even light can give us a headache.

Dark matter, antimatter, dark energy and degenerate matter can be said to be different. I'm not sure about the intricasies but all have different energy frequencies and effects. Not sure but please do research about it.

Hope this helps you.

Answer:

Canva. Although Canva's free storyboard app for iOS and Android is targeted more at video production, it still provides animators and UX designers everything they need.

Explanation:

The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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In order to increase the temperature of an ideal gas in a cylinder that is initially at room temperature, the statement that correctly indicates the appropriate action is to push the piston in rapidly. The temperature of the gas will increase because no energy will be transferred to the surrounding by cooling. (Option C)

An ideal gas refers to a theoretical gas which is composed of many randomly moving point particles that are not subject to interparticle interactions. The concept is useful as it obeys the ideal gas law, which is a simplified equation of state, and is amenable to analysis under statistical mechanics. For an ideal gas, as the temperature increases, the average kinetic energy increases as does the velocity of the gas particles hitting the walls of the container. The force exerted by the particles per unit of area on the container is the pressure, so as the temperature increases the pressure must also increase. Hence, when the piston is compressed so quickly that there is no time to exchange heat to the surrounding, the temperature of the gas increases rapidly.

Note: The question is incomplete. The complete question probably is: A student wants to increase the temperature of an ideal gas in a cylinder that is initially at room temperature. The cylinder has a movable piston with negligible friction. Which of the following correctly indicates an action the student could take to increase the temperature of the gas and why does the temperature increases? A) Pull the piston out rapidly. The gas will expand violently and increase in temperature B) Pull the piston out slowly. The gas will have time to absorb energy from the surroundings by heating as it expands. C) Push the piston in rapidly. The temperature of the gas will increase because no energy will be transferred to the surrounding by cooling. D) Push the piston in slowly. The gas will have time to absorb energy from the surroundings by heating as it is compressed

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The required, it experiences a downward force due to gravity and a force due to air resistance.

Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Here,

When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.

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Answer:

D

Explanation:

Answer:Probably because we've been so dependent on them,and we took to long to find new reusable resources.

Explanation:

Answer:

0.0003

Explanation:

In the rules of Sig Figs, all zeros before with decimals are not sigificant. I.E. 0.00000000000000009. Despite how many 0's there are, only the 9 is significant. Zeros before a number is not significant. In 100, only the one is signficant in 100. with a dot at the end, the one and the two zeros are significant. hope this helps.

Answers:

the second option

Explanation:

Answer:

r = 1.07 m

Explanation:

The maximum radius of the propeller that can be allowed is given by the following formula:

\(v = r\omega\\\\r = \frac{v}{\omega}\)

where,

r = maximum possible radius of the propeller = ?

v = maximum possible linear speed of the propeller = 270 m/s

ω = angular speed of the propeller = (2400 rpm)(2π rad/1 rev)(1 min/60 s)

ω = 251.33 rad/s

Therefore,

\(r = \frac{270\ m/s}{251.33\ rad/s}\)

r = 1.07 m

The time it will take for the horse to go 20m is 2.92 seconds.

The time it will take for a moving body to accelerate can be calculated using one of the equations of motion as follows:

s = ut + ½at²

Where;

Acceleration refers to the amount by which a speed or velocity increases. According to this question, a race horse starts from rest and accelerates at a rate of 4.7m/s². The time it will take can be calculated as follows:

20 = (0 × t) + ½ × 4.7 × t²

20 = 2.35t²

t² = 8.511

t = ✓8.511

t = 2.92 seconds

Therefore, 2.92 seconds is the time it will take the horse to race 20m..

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Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

Graph of area under force vs displacement shows work done. Thus A. is 30J, B. is -12J, C. 18J.

Amount of energy required for the displacement of an object at certain distance, is called work done.

Given,

along y(m) axis, each unit is 2m.

along Fy(N) axis, each unit is 2N.

A. Distance between y = A to y = B

W(AB) = 1/2×base×height

W(AB) = 1/2×10m×6N

W(AB) = 30J

B. Distance between y = B to y = C

W(BC) = 1/2×base×height

W(BC) = 1/2×6m×-4N

W(BC) = -12J

C. Distance between y = A to y = C

W(AC) =  W(AB)+W(BC)

W(AC) = 30J+(-12J)

W(AC) = 18J.

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The question is incomplete, but most probably the complete question is, attached in image:

Answer:

The correct option 50.0 m (the units of the answers are wrong, they should be in meters and not in millimeters).  

Explanation:

From the first second we can find the acceleration of the object:

\( X_{f} = X_{0} + V_{0}t + \frac{1}{2}at^{2} \)

Where:

\(X_{f}\): is the final position = 2.00 m

\(X_{0}\): is the initial position = 0

\(V_{0}\): is the initial speed = 0 (starts from rest)

t: is the time = 1 s

The acceleration is:

\( a = \frac{2X_{f}}{t^{2}} = \frac{4.00 m}{(1 s)^{2}} = 4.00 m/s^{2} \)      

Now, we can find the distance after 5 seconds:

\(X_{f} = X_{0} + V_{0}t + \frac{1}{2}at^{2} = \frac{1}{2}*4.00 m/s^{2}*(5 s)^{2} = 50.0 m\)                  

Therefore, the correct answer is 50.0 m. All the options have the units in millimeters and not in meters hence, the units of the options are wrong.

I hope it helps you!        

The final position of the object after 5 seconds is 50 m.

Option D is the correct answer.

Given that the object starts from rest and accelerates uniformly. It moves 2.00m during the first second.

Let us consider that the initial velocity is v and the initial position is x and the final position is x' for time interval t.

Hence for the given condition, t = 1 s, x' = 2 m, v = 0 m/s and x = 0 m. The acceleration can be calculated as given below.

\(a = \dfrac {2x'}{t^2}\)

\(a = \dfrac {2\times 2}{1}\)

\(a = 4 \;\rm m/s^2\)

The final position of the object after 5 seconds is given below.

\(x (\rm final) = x + vt + \dfrac {1}{2}at^2\)

Substituting the values in the above equation.

\(x(\rm final) = 0 + 0 + \dfrac {1}{2}\times 4 \times 5^2\)

\(x (\rm final) = 50 \;\rm m\)

Hence we can conclude that the final position of the object after 5 seconds is 50 m. Option D is the correct answer.

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Answer:

Explanation:

a) 1.00 - 0.12 = 0.88

m = 1200(0.88)^t

b) t = ln(m/1200) / ln(0.88)

c) m = 1200(0.88)^10 = 334.20 g

d) t = ln(10/1200) / ln(0.88) = 37.451... = 37 s

e) t = ln(1/1200) / ln(0.88) = 55.463... = 55 s

Answer:

Patellar region

Plantar region

Crural region

Answer:

B, C, D

Patellar, Plantar, Crural regions

Explanation:

Legs are the lower limbs of the body, consisting of all these parts. Just did assignment too.

Answer:

it is d that my answer to the question

a. The momentum of the clay before the collision is 0.12m/s

b. The momentum of the clay-bob system after the collision is 0.12m/s

c. The velocity of the clay-bob system after the collision is 2m/s

d. The kinetic energy of the clay-bob system after the collision is 0.12m/s

e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m

f. The velocity  clay should have  before the collision in order for the clay-bob system to complete one circle is 35.13m/s

Momentum is the product of mass and velocity

It is given by ,

p= mv

where, p = momentum

m = mass

v = velocity

velocity is the rate of change of displacement.

To solve , we use Law of conservation of momentum and Law of conservation of  mechanical energy

Law of conservation of momentum states that  in absence of any external forces , the momentum of a system always remains conserved.

i.e,

The momentum  of the system before collision = momentum of the system after collision.

\(m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}\)

Where,

m₁ = mass of first body.

m₂ = mass of the second body.

u₁ = velocity of first body before collision,

u₂ = velocity of the second body before collision

v₁ = velocity of first body after collision

v₂ = velocity of first body after collision.

v₂ = velocity of second body after collision.

The Law states that the total mechanical energy of a system remains conserved and energy can be converted from one form to another form.

The sum of kinetic energy an potential energy is equal to total mechanical energy which is a constant.

So, K.E + P.E = constant

a, Here mass of clay m₁ = 10g = 0.01kg,

velocity of the clay = 12m/s.

therefore, momentum  p = mv.

p = 0.01 x 12 = 0.12kg m/s.

Hence momentum of clay is 0-12kg m/s.

b. The momentum of clay - bob system after collision is

From law of conservation of momentum ,

final momentum = initial momentum

since initial momentum  = 0.12kg m/s

therefore momentum of the clay-bob system after collision is 0.12kg m/s

c. To find the velocity of the body we apply law of conservation of momentum

\(m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}\)

Here  m₁u₁ = 0.12kgm/s

m₂u₂ = 0 (since bob is at rest initally)

m₁ = 10g = 0.01kg

m₂ =  50g = 0.05kg

after collision the system moves with a common velocity v

So,

m₁u₁ = (m₁ + m₂)v

0.12 = (0.01 + 0.05 ) v

So, v = 0.12/0.06 = 2m/s

Hence velocity of clay -bob system after collision is = 2m/s.

d. The kinetic energy of the clay-bob system after the collision.

kinetic energy = 1/2 mv²

Here. m = 0.06kg

v = 2m/s

therefore K.E = (1/2)x 0.06 x 2²

K.E = 0.12J

Hence Kinetic energy of the clay-bob system after collision is 0.12J

e. The maximum height of the clay-bob system that they deflect after the collision.

From Law of Conservation of mechanical energy we have,

The kinetic energy = The potential energy

so, 1/2 mv² = mgh

Here, m = 0.06kg

g= 9,8m/s²

h = height.

So,  h =  2/9.8 = 0.204m

Hence height to which the clay-bob system will rise after collision is 0.204m

e.  To find the velocity that clay should possess  before collision in order for the clay- bob   system to gain the velocity so that it completes the circle -

The velocity that the particle should have at the bottom of the circle in order to complete the circle is v = \(\sqrt{5rg\\}\)

Where, r = radius of the circle

g = acceleration due to gravity

Here,

r = 0.7m

g = 9.8m/s

So, v = \(\sqrt{5 X0.7 X 9.8 }\) = 5.85m

So clay-bob system should have a velocity of 5.85m at the bottom of the circle so that it can complete the circle

Now,  applying Law of conservation of momentum

m₁u₁ = (m₁ + m₂)v

Here, m₁ = 0.01kg

m₂ = 0.05kg

v = 5.85m/s

So, 0.01u₁ = 0.06 x 5.85  

Hence u₁ = 35.13m/s

So velocity that clay should have is 35.13m/s.

Therefore  the solution of the question is

. The momentum of the clay before the collision is 0.12m/s

b. The momentum of the clay-bob system after the collision is 0.12m/s

c. The velocity of the clay-bob system after the collision is 2m/s

d. The kinetic energy of the clay-bob system after the collision is 0.12m/s

e. The maximum height of the clay-bob system that they deflect after the collision is 0.204m

f. The velocity  clay should have  before the collision in order for the clay-bob system to complete one circle is 35.13m/s

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The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

The angular velocity of the propeller in rad/s is given as follows:

1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.

b. The linear velocity, v = radius * angular velocity

Linear velocity, v = 2.25/2 * 136.1

v = 153.1 m/s

c. Centripetal acceleration, \(a = \frac{v^{2}}{r}\)

\(a = \frac{(153.1)^{2}}{1.125} = 20835.2\:ms^{2}\)

Centripetal acceleration in terms of g; \(g = \frac{20835.2}{9.81} = 2123.8 g\)

Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

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An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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These relationships are referred to as the equation of motion.

s = ut + ½at². and v = u + at.

length of the Run way = 1350m

Take of speed of the plane is 90 m/s.

The three equations of motion are as follows:

from equation of motion

s = ut + ½at².

here u =0 a =3 m/s^2 t= 30s

put these values on the above equation

s= 1/2x 3x 30x30= 1350 m

length of the Run way = 1350m

from equation of motion ,

v = u + at.

= 0+ 3x 30 = 90m/s.

Take of speed of the plane is 90 m/s.

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Distance = 1350m, speed = 90m/s

Given:

Initially the Aero plane is at rest. Therefore, initial velocity:

u = 0m/s

Acceleration = 3m/\(s^{2}\)

Time taken = 30 seconds

So according to question, we have to find distance & speed

we know that

s = ut + 1/2a\(t^{2}\)

Putting all the values, we get S = 1350 m

Now to find speed, we know,

\(v^{2} = u^{2} + 2aS\)

Putting all the values,

v = \(\sqrt{8100}\)

v = 90m/s

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Answer:

D. will decrease slightly in volume when heated to 6° C

Explanation:

A gram of distilled water at 4° C  will increase slightly in volume when heated to 6 C. Hence option C is correct.

Water has the chemical formula H2O, making it an inorganic substance. It is the primary chemical component of the Earth's hydrosphere and the fluids of all known living things (in which it serves as a solvent[1]). It is translucent, flavourless, odourless, and almost colourless. In spite of not supplying food, energy, or organic micronutrients, it is essential for all known forms of life. Its molecules are made up of two hydrogen atoms joined by covalent bonds and have the chemical formula H2O. The angle at which the hydrogen atoms are joined to the oxygen atom is 104.45°.[2] The liquid condition of H2O at normal pressure and temperature is known as "water" as well.

Water occurs because the environment on Earth is pretty near to the triple point of water.

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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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A collision that is elastic occurs when there is no net loss of kinetic energy in the system as a result of the collision. Kinetic energy and momentum are both conserved in elastic collisions.

When two balls collide at a pool table, that is an instance of an elastic collision. When you throw a ball on the ground and it bounces back into your hand, there is no net change in the kinetic energy, making it an elastic collision.

Two balls colliding at a pool table is an example of an elastic collision. When a ball is tossed to the ground and subsequently returns to your hand, there is no net change in the kinetic energy, making it an elastic collision.

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Stress refers to a state of mental or emotional strain resulting from adverse or demanding circumstances. It can also refer to the physical forces that act on an object, causing deformation or strain.

In terms of mental or emotional stress, it can result from a variety of factors such as work-related pressure, financial problems, relationship issues, health concerns, and other life events that require us to adapt and cope with changing circumstances.

Physical stress refers to the force or pressure applied to an object, which can cause it to deform, strain, or break. This type of stress can arise from a variety of sources such as gravity, external forces, or internal forces caused by changes in temperature, pressure, or other physical conditions.

Examples of physical stress include tension in a bridge caused by the weight of traffic passing over it, strain in a metal bar due to changes in temperature, or compression of a spring due to a force applied to it. In all cases, the object is subjected to forces that cause it to deform or change shape, leading to stresses that can impact its strength, durability, and performance.

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1302200J

Explanation:

To bring water at 70°C to water at 0°C, we use MC∆T.

To convert water at 0°C to ice at 0°C, ML is applicable, where L is the latent heat of fusion and M equals mass. NB: Temperature is constant during fusion.

Again, to raise the temperature of ice to -11°c, we use MC∆T.

Total heat = MCw∆T + ML + MCi∆T

2 ×4200× 70 + 2×334000 + 2× 2100× 11 = 1302200J